For this question you will be designing an investigation Carefully read the information below and respond to the prompt
Does the temperature of a liquid affect the amount of sugar it will dissolve? In other words, if you change the temperature of a liquid, is there a
relationship between the temperature and how much sugar can dissolve at that specific temperature?
Tell how you would test this question, being as scientific as possible (including the different variables, constants, hypothesis, safety considerations, data
tables, etc.) when you write about your test. Write down the steps you would take to find out if the temperature of a liquid affects the amount of sugar it
can dissolve

Answer:

Gravitational force

Explanation:

Gravitational force is obviously one of the biggest obstacles in climbing. You are essentially going against this very strong force to pull your body mass up the beautiful terrain. Gravity is defined as the force of attraction between all masses in the universe, gravity is what allows the sport of climbing.

Answer:

Gravity, low oxygen, and rock slides.

Explanation:

Some rock climbers train for years but are hardly prepared for some situations.

Answer:

A) v = √[(rg(tan θ - µ_s))/(1 + (µ_s•tan θ))]

B)√[(rg(tan θ - µ_s))/(1 + (µ_s•tan θ))] ≤ v ≤ v = √[(rg(tan θ + µ_s))/(1 - (µ_s•tan θ))]

C) µ_s = tan θ

D) µ_s = 0.4663

Explanation:

A) The forces acting on the car will be;

Force due to friction; F_f

Force due to Gravity; F_g

Normal Force; F_n

Now, let us take the vertical direction to be j^ and the direction approaching the centre to be i^ downwards and parallel to the road surface by k^.

Also, we will assume that initially, F_n is in the negative k^ direction and that it will have a maximum possible value of; F_f = µ_s × F_n

Thus, sum of forces about the vertical j^ direction gives;

ΣF_j^ = F_n•cos θ − mg + F_f•sin θ = 0

Since F_f = µ_s × F_n ;

F_n•cos θ − mg + (µ_s × F_n × sin θ) =0

F_n = mg/[cos θ + (µ_s•sin θ)]

Also, sum of forces about the centre i^ direction gives;

ΣF_i^ = F_n(sin θ + (µ_s•cos θ)) = mv²/r

Plugging in formula for F_n gives;

ΣF_i^ = [mg/[cos θ + (µ_s•sin θ)]] × (sin θ + (µ_s•cos θ)) = mv²/r

Making v the subject gives;

v = √[(rg(tan θ - µ_s))/(1 + (µ_s•tan θ))]

B) What we got in a above is the minimum speed the car can have while going round the turn.

The maximum speed will be gotten by making the frictional force(F_f) to point in the positive k^ direction. This means that F_f will be negative.

Now, if we change the sign in front of F_f in the equation in part a that led to the minimum velocity, we will have the maximum as;

v = √[(rg(tan θ + µ_s))/(1 - (µ_s•tan θ))]

Thus the range is;

√[(rg(tan θ - µ_s))/(1 + (µ_s•tan θ))] ≤ v ≤ v = √[(rg(tan θ + µ_s))/(1 - (µ_s•tan θ))]

C) For the minimum speed to be 0, it implies that F_f will be in the negative k^ direction. Thus, Sum of the forces in the k^ direction gives;

ΣF_k^ = mg(sin θ - µ_s•cos θ) = 0

Thus;

mg(sin θ - µ_s•cos θ) = 0

Making µ_s the subject gives;

µ_s = sin θ/cos θ

µ_s = tan θ

D) If θ = 25.0°;

Thus;

µ_s = tan 25

µ_s = 0.4663

Answer:

Explanation:

Out of the given options, A would not describe a physical property of a substance. How a substance reacts with another substance is a chemical property, whereas physical properties are intrinsic characteristics that can be observed or measured without changing the substance's identity. B, C, and D are examples of physical properties - shininess, color, and mass respectively.

Hi there!

To solve, we can begin by doing a summation of torques. We can place the fulcrum at the point at which the strut and wall make contact to make solving easier.

Recall that:
\(\tau = r \times F\) (Cross Product)

τ = Torque (Nm)

r = distance from lever arm (m)

F = Force (N)

This can also be written as:
\(\tau = rFsin\theta\)

For a system to be in rotational equilibrium:
\(\tau _{cw} = \tau_{ccw}\)

In this instance, we only have the torques of the force of gravity and the vertical component of the cable's tension that are in opposite directions. Additionally, these torques are PERPENDICULAR to the strut, so sin(θ) = 1.

Let 'r' represent the length of the bar.

\(rTsin\theta = rF_g\\\\Tsin\theta = F_g\\\\T = \frac{F_g}{sin\theta} = \frac{9.8 \times 160.9}{sin(25.3)} = \boxed{3689.695 N}\)

To find the compression force exerted by the wall on the strut, we can do a summation of forces in the horizontal direction.

Let F(W) represent the force on the strut by the wall, and Tx represent the horizontal component of the tension. These two sum up to zero since the system is in equilibrium.

\(\Sigma F_x = T_x - F_W\)

\(0 = T_x - F_W\\\\F_W = T_x\\\\F_W = Tcos\theta = 3689.695cos(25.3) = \boxed{3335.789 N}\)

**This is assuming the strut has no mass.

Answer:

Explanation:

1)  ½(0.8)t² = 4t

        0.4t² = 4t

         0.4t = 4

              t = 10 s

2)           d = vt = 4(10) = 40 m

d =  ½atⁿ = ½(0.8)10² = 40 m

3)    v = at = 0.8(10) = 8 m/s

Answer: The mass of an object can be calculated in a number of different ways: mass=density×volume (m=ρV). Density is a measure of mass per unit of volume, so the mass of an object can be determined by multiplying density by volume. mass=force÷acceleration (m=F/a).

As temperature increases, molecules of liquid become more active and they move more rapidly.

Answer:

The initial Velocity IS 3.53 cm

Explanation:

The initial velocity is required so that the football just clears the goalpost crossbar that is 3.1 m above the ground is 13.7 m/s.

Projectile is the curved motion experienced by an object which is thrown in space.

Given an angle (θ) = 35°, acceleration due to gravity (g) = 10 m/s². u is initial velocity

The maximum height (h) is:

For the ball to reach 3.1 m above the ground:

\(3.1=\frac{u^2sin^2(35)}{2(10)} \\\\u=13.7 \ m/s\)

The initial velocity is required so that the football just clears the goalpost crossbar that is 3.1 m above the ground is 13.7 m/s.

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The speed of the puck is 3.67 m/s.

To find the speed of the puck, we can use the concept of centripetal force. The tension in the string provides the necessary centripetal force to keep the puck moving in a circle. At the same time, the tension in the string also supports the weight of the suspended mass.

Using Newton's second law, we can write two equations of motion: one for the puck and one for the suspended mass. For the puck, the net force acting on it is the tension in the string, which is equal to the centripetal force required to keep it moving in a circle. Thus, we can write:

= m1 * v^2 / R

where T is the tension in the string, v is the speed of the puck, and R is the radius of the circle.

For the suspended mass, the net force acting on it is its weight minus the tension in the string, which must be zero since the mass is in equilibrium. Thus, we can write:

T = m2 * g

where g is the acceleration due to gravity.

Combining these two equations, we can solve for the speed of the puck:

v = sqrt(T * R / m1) = sqrt(m2 * g * R / m1)

Substituting the given values, we get:

v = sqrt(1.0 kg * 9.81 m/s^2 * 0.9 m / 0.21 kg) = 3.67 m/s

Therefore, the speed of the puck is 3.67 m/s.

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Answer:

Explanation:

Let's just have our reference frame travel along with the original un broken mass. This way the original velocity is not relevant.

Each half will have a mass of 770/2 = 385 kg

Each half will have the same magnitude of velocity (conservation of momentum) which will be 2.6 x 10³/2 = 1.30 x 10³ m/s

Now add back the reference frame velocity to get velocity relative to earth.

Section one will have velocity 6.90 x 10³ + 1.30 x 10³ = 8.2 x 10³ m/s

Section two will have velocity 6.90 x 10³ - 1.30 x 10³ = 5.6 x 10³ m/s

In the moving reference frame, each half will have kinetic energy which could only come from the explosion

KE = ½(385)(1.3 x 10³)² = 325,325,000 J

2(325,325,000) = 650,650,000 J released in the explosion.

Rounding to the three significant figures of the problem numerals

E = 6.50 x 10⁸ J or 650 MJ released

Answer:

Explanation:

The diagram showing the illustration of the question is shown on the first uploaded image

Here G represents the base

So the displacement in the x -axis is mathematically represented as

\(X = 11200 + 8400 = 19600 \ m\)

The displacement in the y -axis is mathematically represented as

\(Y 3200 + 1700 = 4900 \ m\)

Generally the resultant displacement is

\(R = \sqrt{ X^2 + Y^2}\)

\(R = \sqrt{ 19600^2 + 4900^2}\)

\(R = 20200\ m \)

Generally the direction of this resultant displacement is mathematically represented as

\(\theta = tan ^{-1} [\frac{Y}{X} ]\)

=>       \(\theta  =  tan ^{-1} [\frac{4900}{19600} ]\)

=>            \(\theta  = 14.03 ^o  \)

Hence the direction is  \(14.03 ^o[\tex] from the horizontal axis

Answer:

density = mass/volume

so . . .  

density = (36 g)/(15 cm³) = 2.4 g/cm³

Explanation:

The mass of M₂ = 12kg.

Newton's second law of motion states that an object's acceleration is equal to its mass divided by the net force acting on it, or a = F m. When an object's mass and the net force acting on it are known, this equation for acceleration can be used to determine the object's acceleration.

The formal formulation of Newton's second law is as follows: The acceleration of an object caused by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.

F = ma

F = 6×4.9

F = 29.4N.

F = (M₂ - M₁)a

29.4 = (M₂- 6) 4.9

29.4/ 4.9 = M₂- 6

M₂ = 6+6

M₂ = 12kg.

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Answer:

The temperature of the final equilibrium temperature of the system is 19.7⁰C

Explanation:

Given;

mass of the ice, m₁ = 25 kg

temperature of the ice =  0°C

mass of the steam, m₂ = 4 kg

temperature of the steam, = 100 ⁰C

Let the temperature of the resulting mixture = t

Apply the principle of conservation of energy.

Heat required to melt the ice + Heat gained by the mixture = Heat required to convert the water to steam + Heat lost by the mixture

\(m_1L_f + m_1c (t - 0) = m_2L_v + m_2c(100 - t)\)

where;

Lf is the latent heat of fusion of ice =  3.33 x 10⁵ J/kg.

Lv is the latent heat of vaporization of water, = 2.260 x 10⁶ J/kg

c is the specific heat capacity of water = 4,200 J/kg

\(m_1L_f + m_1c (t - 0) = m_2L_v + m_2c(100 - t)\\\\25 \times 3.33\times 10^5 + 25\times 4,200 (t ) = 4\times 2.26\times 10^6 + 4\times 4,200(100 - t)\\\\8,325,000 + 105,000t = 9,040,000 + 1,680,000 - 16,800t\\\\105,000t + 16,800t = 10,720,000 - 8,325,000\\\\121,800t = 2,395,000\\\\t = \frac{2,395,000}{121,800} \\\\t = 19.7 \ ^0 C\)

The temperature of the final equilibrium temperature of the system is 19.7⁰C

Answer:

Explanation:

C

Answer:

Explanation:

Alcohol use C

The terminal velocity of the sphere is approximately 22.68 mph.

The terminal velocity of a sphere is the constant speed at which the gravitational force pulling the sphere down is balanced by the drag force pushing the sphere up. The drag force is proportional to the velocity of the sphere, and can be calculated using the following formula:

Fd = (1/2) * rho * Cd * A * v²

where Fd is the drag force, rho is the density of the fluid (air in this case), Cd is the drag coefficient (which depends on the shape of the object), A is the cross-sectional area of the object perpendicular to the direction of motion, and v is the velocity of the object.

The gravitational force pulling the sphere down is given by:

Fg = m * g

where m is the mass of the sphere and g is the acceleration due to gravity.

At terminal velocity, the drag force is equal in magnitude to the gravitational force, so:

Fd = Fg

Substituting the expressions for Fd and Fg and solving for v, we get:

v = √((2 * m * g) / (rho * Cd * A))

where A = pi * r² is the cross-sectional area of the sphere, and r is the radius of the sphere.

Plugging in the given values, we get:

v = sqrt((2 * 0.6 * 9.81) / (1.2 * 0.47 * pi * 0.3²)) ≈ 10.13 m/s

To convert this to mph, we multiply by 2.23694:

v ≈ 22.68 mph

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Answer:

A high EQ (emotional intelligence)

In today's transitioning workplace, having a high EQ is the most important trait of a good boss. Bosses must be able to discern between their own personal beliefs and the thoughts and beliefs of others, and other generations (boomers, Gen X, xennials, millennials and now Gen Z).

Explanation:

hope it helps you

Answer:

it has to be b contact forces

Explanation: because the two objects are next to each other but they still have force

Answer:

c

Explanation:

Answer:

A. Physics has changed the course of the world.

Explanation:

If the human were fully made of neutron star matter, his mass would be roughly 1.8 x 10¹⁶ kg, to two significant numbers.

As most protons and electrons will have merged to become neutrons under the extremely dense conditions, neutron stars get their name because they are largely made of neutrons.

Assume the individual has a volume of 59,000 cm3, or about the same as someone with a density of 1000 kg/m3. When we convert this volume to m3, we obtain:

V = 59,000 cm³

V = 0.059 m³

If the individual were made entirely of matter from neutron stars, his mass would be:

m = ρV

m = (3 x 10¹⁷ kg/m³) (0.059 m³)

m = 1.77 x 10¹⁶ kg

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Answer:

a = 1.55m/s²

Explanation:

a = (v_f-v_0)/t

a = (12.4m/s-3.22m/s)/5.94s

a = 1.55m/s²

When the teacher asked the student to make words out of the jumbled word gzeysktqix, the student was being tested on his ability to unscramble words. Unscrambling words is the process of taking a word or series of letters that are out of order and rearranging them to form a word that makes sense.

When trying to unscramble a word, it is important to look for any patterns that can help identify smaller words within the jumbled letters. This can help make the process easier and quicker. For example, in the jumbled word gzeysktqix, one might notice that the letters "sktqix" appear together.

This could indicate that these letters could potentially form a word. By looking at the remaining letters, one could notice that the letters "g", "z", "e", and "y" could also form smaller words. After some rearranging, the letters can be unscrambled to form the words "sky", "zig", "sex", and "yet". These are just a few examples, as there are likely many other words that can be formed from this jumbled word.

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Answer:

true

Explanation:

because it has magnitude

1.00 kg of ice at -24.0°C is placed in contact with a 1.00 kg block of a metal at 5.00°C. They come to equilibrium at -8.88°C.

We can use the principle of conservation of heat to solve this problem. The heat lost by the metal must equal the heat gained by the ice.

The heat lost by the metal is given by

Q1 = m1c1ΔT1

Where m1 is the mass of the metal, c1 is its specific heat, and ΔT1 is the change in temperature.

The heat gained by the ice is given by

Q2 = m2c2ΔT2

Where m2 is the mass of the ice, c2 is its specific heat, and ΔT2 is the change in temperature.

Since the two objects come to thermal equilibrium, we can set Q1 equal to Q2

m1c1ΔT1 = m2c2ΔT2

Solving for c1, we get

c1 = m2c2ΔT2 / (m1ΔT1)

By putting these values we get

c1 = (1.00 kg)(2.06 kJ/kg·K)(-24.0°C - (-8.88°C)) / [(1.00 kg)(5.00°C - (-8.88°C))]

c1 = 0.902 kJ/kg·K

Hence, the specific heat of the metal is 0.902 kJ/kg·K.

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Answer:

Explanation:

Mass of disk = 0.14 kgSpring constant = 155 N/mLength = 4 cmWe need to calculate the speed Using energy conservationWhere, k = spring constantx = compressed lengthm = mass of the discPut the value into the formulaHence, The speed with which the disk slides across the surface is 1.33095 m/s.

The total distance is 105 kilometers and the total displacement is 15 kilometers east. Option C

To calculate the total distance, we add the distances traveled in each leg of the journey: 60 kilometers (from A to B) + 45 kilometers (from B back to A) = 105 kilometers.

However, displacement refers to the change in position of an object in a straight line from its starting point to its ending point. In this case, since the boat starts and ends at the same point (A), the total displacement is zero.

Hence The total distance is 105 kilometers and the total displacement is 15 kilometers east.

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Answer:

920000

Explanation:

Each kg contains 1,000 grams

The speed of the wind is 20 miles per hour.

To solve this problem, we can use the formula:

Speed = Distance/Time

Let's assume that the speed of the wind is x miles per hour.

With the wind, the plane travels at a speed of 460 miles per hour. This means that its speed relative to the ground is the sum of its airspeed and the speed of the wind:

460 = Airspeed + x

Against the wind, the plane travels at a speed of 420 miles per hour. This means that its speed relative to the ground is the difference between its airspeed and the speed of the wind:

420 = Airspeed - x

We can solve this system of equations to find the airspeed of the plane:

460 = Airspeed + x

420 = Airspeed - x

Adding the two equations gives:

880 = 2Airspeed

Dividing both sides by 2 gives:

Airspeed = 440 miles per hour

Now that we know the airspeed of the plane, we can find the speed of the wind by substituting this value into one of the equations we obtained earlier:

460 = Airspeed + x

460 = 440 + x

x = 20

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Answer:

Winds are caused by differences in air pressure. Unequal heating of Earth’s surface creates areas of different pressure. Cooler areas have higher air pressure. Warmer areas have lower pressure. This causes air to move from high pressure to low pressure. This movement is the wind we feel.

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