Frank is drawing a treasure map using a scale of 1 cm to 10 m. He wants to show that the treasure is buried 40 meters from a tree. How many centimeters should he show for this distance on the map?

Answer:

Let me give you an example of a segment addition problem that uses three points that asks the student to solve for x but has a solution x = 20.

First, I assumed values for each x, y and z and then manipulated their coefficients to get the total at the end of each equation.

20 + 10 +30 = 60

40 + 0 + 40 = 80

40 + 10 = 50

Then exchangeing these numbers into values and we have the following equation.

x + 2y + 3z = 60

2x + 4z = 80

2x + z = 50

If you will solve them manually by substituting their variables into these equations, you can get

x = 20

y = 5

z = 10

Step-by-step explanation:

This is based on a survey conducted by the American Customer Satisfaction Index (ACSI) in 2020 that surveyed 1,097 passengers who had flown on U.S. airlines in the past 12 months.

A survey is a research method used to collect quantitative and qualitative data from a specific population. Surveys are often used to assess attitudes, opinions, and behaviors of a given group of people. They are typically administered in the form of a questionnaire, which can be administered in person, over the phone, or online. Surveys are often used in market research, political polling, social science research, and other types of research.

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Answer: 14 percent

Step-by-step explanation:

Not really needed.

Answer:

Step-by-step explanation:

9y-4 = 50

9y = 54

y= 6

9y-4+7x+xy = 180

9(6)-4+7x+6x= 180

54-4+13x = 180

13x+50 = 180

13x = 130

x = 10

Answer:

A

Step-by-step explanation:

The Talia should place the cell tower at the cicumcenter of triangle which is made with three locations of elementary school, shopping mall, and starbucks.

The circumcenter of a triangle is the point which lies in the center of the triangle and at the equidistant from all the three vertex of the triangle.

Taliya gets a summer job. She was in charge of placing a cell tower which should be equidistant to an elementary school, shopping mall, and starbucks.

The three locations form a triangular pattern on the map.  Now the Taliya were to use a center of triangle.

Thus, the Talia should place the cell tower at the cicumcenter of triangle which is made with three locations of elementary school, shopping mall, and starbucks.

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The Java program Factorial.java implements a recursive method to compute the factorial of a nonnegative integer less than 11.

The Factorial.java program in Java utilizes a recursive method to calculate the factorial of a given number. The recursive method follows the mathematical definition of factorial, where the factorial of a number n is n multiplied by the factorial of (n-1). The program first checks if the input number is within the valid range (0 to 10). If it is, the program calls the recursive method to calculate the factorial. The base case of the recursive method is when the input number is 0 or 1, where the factorial is defined as 1. For any other number, the method recursively calls itself with the number decreased by 1 until it reaches the base case. The factorial value is calculated by multiplying the current number with the factorial of the decreased number. Finally, the program displays the computed factorial as output.

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Answer:\(\frac{-5}{4}, \frac{3}{4}\)

Step-by-step explanation:

Given

\(\theta\) is in the third quadrant and

\(\Rightarrow \cos \theta=\frac{-3}{5}\)

tan and cot is positive in the third quadrant and the rest are negative

using identity

\(\sin^2 \theta+\cos^2 \theta=1\\\Rightarrow \sin \theta=-\sqrt{1-\cos^2 \theta}\\\Rightarrow \sin \theta =-\sqrt{1-(-\frac{3}{5}^2)}\\\Rightarrow \sin \theta =-\frac{4}{5}\\\Rightarrow\text{cosec} \theta=-\frac{5}{4}\\\Rightarrow \cot \theta=\frac{\cos \theta}{\sin \theta}=\frac{\frac{-3}{5}}{\frac{-4}{5}}=\frac{3}{4}\)

Using average to predict the population in 1820, the population is 10 million people

From the question, we have the following parameters that can be used in our computation:

Population in 1810 = 7 million people

Population in 1830 = 13 million people

Using average, we have

Population in 1820 = 1/2 * (7 million people + 13 million people )

Evaluate

Population in 1820 = 10 million people

Hence, the population in 1820 is 10 million people

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Answer:

first one (2*2*2*3*3)

Step-by-step explanation:

2*2*2*3*3=72

Answer:

K=40

Step-by-step explanation:

240/6=40 grams and egg

check 6x40=240

Answer:  K= 40

Step-by-step explanation: divide 240 by 6 :)

240/6=40

The value of determinant of the matrix det (AB) is 15.

Given matrices A and B are 3 by 3 matrices with

det (A) = 3 and

det (b) = 5.

We need to find the value of det (AB).

Writing the given matrices into the augmented matrix form gives [A | I] and [B | I] respectively.

By multiplying A and B, we get AB. Similarly, by multiplying I and I, we get I. We can then write AB into an augmented matrix form as [AB | I].

Therefore, we can solve the augmented matrix [AB | I] by row reducing [A | I] and [B | I] simultaneously using elementary row operations as shown below.


The determinant of AB can be calculated as det(AB) = det(A) × det(B)

= 3 × 5

= 15.

Conclusion: The value of det (AB) is 15.

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We need to find the value of determinant det(AB), using the formula: det(AB) = det(A)det(B)

=> det(AB) = 3 × 5

=> det(AB) = 15.

Hence, the value of det(AB) is 15.

The given matrices are A and B. Here, we need to determine the value of det(AB). To calculate the determinant of the product of two matrices, we can follow this rule:

det(AB) = det(A)det(B).

Given that: det(A) = 3

det(B) = 5

Now, let C = AB be the matrix product. Then,

det(C) = det(AB).

To evaluate det(C), we have to compute C first. We can use the following method to solve the augmented matrix by elementary row operations.

Given matrices A and B are: Matrix A and B:

[A|B] = [3 0 0|1 0 1] [0 3 0|0 1 1] [0 0 3|1 1 0][A|B]

= [3 0 0|1 0 1] [0 3 0|0 1 1] [0 0 3|1 1 0].

We can see that the coefficient matrix is an identity matrix. So, we can directly evaluate the determinant of A to be 3.

det(A) = 3.

Therefore, det(AB) = det(A)det(B)

= 3 × 5

= 15.

Conclusion: Therefore, the value of det(AB) is 15.

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The distance between the two cities is 2240.23 miles

As per the data given:

City A and City B are on the same meridian.

City A has a latitude of 64.2 degrees to the North.

City B has a latitude of 31.9 degrees to the North.

Here we have to determine the value of the distance between the two cities to the decimal to the nearest hundredth.

\(\theta & =64.2^{\circ}-31.9^{\circ} \\\)

\(& =32.4^{\circ} \\\)

\(& =32.4 \times \frac{\pi}{180}\) radians

\(& =\frac{10.8 \pi}{60}\) radians

Radius of the Earth is equal to 3960 miles. Consider the formula for the arc-length of a circle, s = r\(\theta\)

Substitute r = 3960 miles and \(\theta\) \(& =\frac{10.8 \pi}{60}\) radians the arc length between A and B will be,

s = \((3960 ) \times\left(\frac{10.8 \pi}{60})\) radians

\(& =712.8 \pi\) miles

= 2240.228 miles

\(& \approx 2240.23\) miles

Therefore, the distance between two cities A and B is approximately 2240.23 miles

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Answer: Your answer would be  y = 17/4 x - 12

Step-by-step explanation:

I hope this helps!

Answer:

y=17/4x-12

Step-by-step explanation:

0.8 is greater than 0.3 an image is attached to show the plotting on the number line.

A number line is a one-dimensional horizontal line where we can represent any real number. The origin of the number line is represented by zero left to it are all negative real numbers and right to it are all positive real numbers.

Given, are two decimals 0.3 and 0.8.

We know 0.3 lies between 0 and 0.5 and 0.8 lies between 0.5 and 1.

∴ 0.8 > 0.3.

The plotting of the numbers is attached in the image.

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Answer:

Step-by-step explanation:

Find the diagram attached

Area of a parallelogram = Base * Height

Given

Area = 120ft^2

BAse = 20ft

Required

Height

From the formula;

Height = Area/Base

Height = 120/20

Height = 6ft

Hence the value of h is 6ft

Answer:

x = 9

Step-by-step explanation:

5+ 2/3x= -x+20.

Add x to each side

5+ 2/3x +x= -x+x+20

5 + 2/3x+3/3x = 20

5 + 5/3x = 20

Subtract 5 from each side

5+5/3x -5 = 20-5

5/3x = 15

Multiply each side by 3/5

3/5 * 5/3x = 15*3/5

x = 9

Answer:

Step-by-step explanation: 5+2/3x= -x+20

-5. -5

2/3x= -x +15

+x +x

1 2/3x/1 2/3 = 15/1 2/3

X=9

Answer:

The answer is a

Step-by-step explanation:

hope this helps :}

Answer:

A

Step-by-step explanation:

l

v

The lines L1 and L2 are parallel. Since their direction vectors are identical, the lines do not intersect and are not skew. The lines have the same direction in space and are thus parallel.

To determine the relationship between the lines L1 and L2, we need to analyze their direction vectors. The direction vector of a line is a vector that points in the direction of the line. If the direction vectors are parallel, the lines are parallel. If they are not parallel and do not intersect, the lines are skew. If they are not parallel and intersect, we can find the point of intersection.

Let's find the direction vectors of L1 and L2:

For L1:

The direction vector d1 = <1, 1, 1> as the coefficients of x, y, and z in the line equation are all 1.

For L2:

The direction vector d2 = <1, 1, 1> as well, since the coefficients of x, y, and z in the line equation are all 1.

Since the direction vectors d1 and d2 are the same, we can conclude that the lines L1 and L2 are parallel.

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Answer:

4 × (7 - 3)

Step-by-step explanation:

You first subtarct 3 from 7 and then multiply that answer by 4

Answer:

4 × (7 - 3)

Step-by-step explanation:

Answer:

to my beliefs it is 18. I THINKKKKK I LIKE ALELI THINKS ITS 18

it displays the computed sum and product of the diagonal elements.

Here's a MATLAB code to find the sum and product of the diagonal elements of a given matrix `A`, as well as an example execution for `A = ones(5)`:

```matlab

% Define the matrix A

A = ones(5);

% Get the size of the matrix

[n, ~] = size(A);

% Initialize variables for sum and product

diagonal_sum = 0;

diagonal_product = 1;

% Calculate the sum and product of diagonal elements

for i = 1:n

   diagonal_sum = diagonal_sum + A(i, i);

   diagonal_product = diagonal_product * A(i, i);

end

% Display the results

disp("Sum of diagonal elements: " + diagonal_sum);

disp("Product of diagonal elements: " + diagonal_product);

```

Example execution for `A = ones(5)`:

```

Sum of diagonal elements: 5

Product of diagonal elements: 1

```

In this example, `A = ones(5)` creates a 5x5 matrix filled with ones. The code then iterates over the diagonal elements (i.e., elements where the row index equals the column index) and accumulates the sum and product. Finally, it displays the computed sum and product of the diagonal elements.

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Answer: More than one

Step-by-step explanation: You can do the two side lengths then add the angle any corner giving you a minimum of 3 triangles.

Answer:

Step-by-step explanation:

Answer:

50

Step-by-step explanation:

The sum of interior angles in a triangle is equal to 180 degrees

since one of the angle is given as 80 the remaining is 100

The given is an isosceles triangle which means two of its side length and so its angles are equal in measure so 100/2 = 50

Answer:

4/5 t

Step-by-step explanation:

why?

80%xt by definition of p%=p/100

80/100t

80/100t reduce the fraction with 20

so the answer is;

4/5 t

Hope it helps

The 95% confidence interval for the true proportion of all auto accidents involving teenage drivers is approximately (0.1205, 0.1927).

To find the 95% confidence interval for the true proportion of all auto accidents involving teenage drivers, we can use the formula for the confidence interval for a proportion.

The formula for the confidence interval is:

CI = p1 ± Z * √((p1 * (1 - p1)) / n)

Where:

CI is the confidence interval,

p1 is the sample proportion (proportion of accidents involving teenage drivers),

Z is the Z-score corresponding to the desired confidence level (95% confidence level corresponds to Z ≈ 1.96),

n is the sample size (number of accidents checked).

Given:

Number of accidents checked (sample size), n = 582

Number of accidents involving teenage drivers, x = 91

First, we calculate the sample proportion:

p1 = x / n = 91 / 582 ≈ 0.1566

Now we can calculate the confidence interval:

CI = 0.1566 ± 1.96 * √((0.1566 * (1 - 0.1566)) / 582)

Calculating the standard error of the proportion:

SE = √((p1 * (1 - p1)) / n) = √((0.1566 * (1 - 0.1566)) / 582) ≈ 0.0184

Substituting the values into the formula:

CI = 0.1566 ± 1.96 * 0.0184

Calculating the values:

CI = 0.1566 ± 0.0361

Finally, we can simplify the confidence interval:

CI = (0.1205, 0.1927)

Therefore, the 95% confidence interval for the true proportion of all auto accidents involving teenage drivers is approximately (0.1205, 0.1927).

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