g. Name a separating method for each of the question. (3)
I. Sodium chloride from the sodium chloride salt solution
II. Pure water from the sea water
III. Sand from the mixture of sand and salt solution

Ionic compound is defined as those which contains ion and are held together by the attractive forces among the oppositely charged ions.

The names of the ionic compounds is given above and is the most appropriate answer.

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The mass of carbon dioxide released during the reaction is 2.6 grams.

To determine the mass of carbon dioxide released during the reaction between sodium hydrogen carbonate (NaHCO3) and acetic acid (CH3COOH), we need to calculate the difference in mass before and after the reaction.

Before the reaction:

Mass of NaHCO3 = 3.8 g

Mass of acetic acid = 10.5 g

Total mass before the reaction = Mass of NaHCO3 + Mass of acetic acid = 3.8 g + 10.5 g = 14.3 g

After the reaction:

Mass of the contents of the reaction vessel = 11.7 g

To find the mass of carbon dioxide released, we calculate the difference in mass:

Mass of carbon dioxide released = Total mass before the reaction - Mass of the contents of the reaction vessel

= 14.3 g - 11.7 g

= 2.6 g

Therefore, the mass of carbon dioxide released during the reaction is 2.6 grams.

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Answer:Using a makeshift workspace, Marie Curie began, in 1897, a series of experiments that would pioneer the science of radioactivity, change the world of medicine, and increase our understanding of the structure of the atom

Explanation:

Answer: B

Explanation:

Answer:

B.electrostatic repulsion by gold nuclei

Explanation:

According to Rutherford's experiment, a thin gold foil was bombarded with alpha particles. Some of the particles passed through the foil undeviated, some were scattered through large angles while some bounced backwards.

It follows that the particles that bounced backwards must have encountered a massive particle of like charge.

The atom is composed of a nucleus which contains positively charged particles. Some of the alpha particles which are positively charged particles bounced back when they encountered the positively charged particles in the nucleus.

Answer: The correct option is B (electrostatic repulsion by gold nuclei).

Explanation:

In the Rutherford's experiment, he used positively charged particles called alpha particles to bombard an atom in order to find out what is inside the atom. Together with two other scientists, Geiger and Marsden, they used a narrow beam of alpha particles emitted from a radioactive source to bombard a thin gold foil. The scattering of the particles from the gold foil was detected by a movable zinc sulphide screen which could be rotated to various positions around the foil.

Each time an alpha particle hit the screen, a visible flash of light or scintillation was produced. This was observed by a microscope attached to the screen. It was then observed that some of the particles followed a straight path through the gold foil while a few where scattered in a backward direction. This was as a result of electrostatic repulsion by gold nuclei which occurs due to the greater part of the mass of the atom was concentrated in a minute nucleus with positive charge.

Answer:

Fraction of water that can be vaporized = 0.0961 or 9.61%

Note : The question is incomplete. The complete question is given below:

A serving of Cheez-Its releases 130 kcal (1 kcal = 4.18 kJ) when digested by your body.

If this same quantity of energy were transferred to 2.5 kg of water at its boiling point, what  fraction of the water would be vaporized?

Explanation:

Energy released by a serving of Cheeze-Its = 130 kcal

Since 1 kcal = 4.18 kJ, 130 kcal = 130 * 4.18 kJ = 543.4 kJ

Heat of vaporization (evaporating or condensing) Hv, of water = 2260 J/g

From formula, quantity of heat, Q = mass  * heat of vaporization

mass of water = 2.5 kg = 2500 g

Q = 2500 g * 2260 J/g

Q  = 5650000 J = 5650 kJ

Therefore 2.5 kg of water requires 5650 kJ of heat for complete vaporization

Fraction of water that can be vaporized by 543.4 kJ energy = 543.4/5650

Fraction of water that can be vaporized = 0.0961 or 9.61%

The molar heat capacity of a substance is the amount of heat needed to change the temperature of 1 mol of that substance by 1 degree Celsius (or Kelvin).

Molar heat capacity is termed as the amount of heat energy will be required to raise the temperature of one mole of a substance by one degree Celsius (or one Kelvin). It is typically denoted by the symbol Cₘ and has units of J/mol·K.

The molar heat capacity will be related to specific heat capacity, which is the amount of heat energy will be required to raise the temperature of one gram of the substance by one degree Celsius (or one Kelvin). The specific heat capacity can be converted to the molar heat capacity by dividing it by the molar mass of the substance.

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The pH of the buffer solution composed of 2.00 mol of acid and 8.25 mol of the conjugate base is 5.01

A buffer solution is one that is capable of resisting changes in pH, even when a strong acid or base is added to it. The pH of the buffer is determined by the amount of acid and its conjugate base present in the solution, as well as the pKa of the acid.

A buffer solution is composed of 2.00 mol of acid and 8.25 mol of the conjugate base. If the pKa of the acid is 4.40, the pH of the buffer can be calculated as follows :

First, calculate the ratio of the conjugate base to the acid, using the equation :

pH = pKa + log [base]/[acid]  where : pH = the pH of the buffer ; pKa = the acid dissociation constant ;

log = the base 10 ; logarithm[base] = the concentration of the conjugate base ; [acid] = the concentration of the acid

Substitute the given values into the equation :

pH = 4.40 + log [8.25]/[2.00]

pH = 4.40 + log 4.125

pH = 4.40 + 0.614pH = 5.01

Therefore, the pH of the buffer solution composed of 2.00 mol of acid and 8.25 mol of the conjugate base is 5.01

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Answer:follow these steps Identify the given quantity in the problem.

Identify the wanted quantity in the problem.

Establish the unit path from the given quantity to the wanted quantity using equivalents as conversion factors.

Set up the conversion factors to permit cancellation of unwanted units

Explanation:

other things that may helps

Set up each problem by writing down what you need to find with a question mark. Then set it equal to the information that you are given. The problem is solved by multiplying the given data and its units by the appropriate unit factors so that only the desired units are present at the end.

Answer:

I will answer the first one for you: 5.33

Explanation:

You can use dimensional analysis to do conversions in almost any field of math. For the first problem:

\(\frac{16 feet}{} |\frac{1 meter}{3 feet} = about 5.33\)

The quantity of sulfuric acid may not be used because sulfuric acid is excessive and aluminum is limiting.

Limiting reactants in reactions are reactants that are present in lower stoichiometric quantities in comparison with other reactants.

Thus, limited reactants determine how far the reaction can go in terms of producing products.

Thus, the percent yield of alum might have been calculated based on the starting quantity of aluminum because the latter is the limiting reactant of the reaction.

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we write the empirical formula using the mole ratios as subscripts: Empirical formula of Calcocite = Cu2STherefore, the empirical formula for Calcocite is Cu2S.

Calcocite is a mineral composed of 79.9 mass % copper and 20.1 mass % sulfur. To determine the empirical formula for Calcocite, we must first determine the mole ratios of copper and sulfur in the mineral.

Here's how: Step-by-step explanation:

We assume a 100 g sample of Calcocite.

Then, the mass of copper in the sample is 79.9 g (79.9 mass % of 100 g) and the mass of sulfur in the sample is 20.1 g (20.1 mass % of 100 g).Next, we find the moles of copper and sulfur using their atomic masses:

Moles of copper = 79.9 g / 63.55 g/mol (atomic mass of copper)

= 1.257 moles Moles of sulfur

= 20.1 g / 32.06 g/mol (atomic mass of sulfur)

= 0.626 moles

Then, we divide each mole value by the smallest mole value to get the simplest whole-number ratio of moles:

Moles of copper / Smallest mole value

= 1.257 / 0.626

= 2.007 Moles of sulfur / Smallest mole value

= 0.626 / 0.626

= 1.000 (Note that we rounded off the mole ratio of copper to two decimal places, which may introduce some errors in our calculation.

However, we will use this rounded value to make our empirical formula easier to write.)

Finally, we write the empirical formula using the mole ratios as subscripts: Empirical formula of Calcocite = Cu2STherefore, the empirical formula for Calcocite is Cu2S.

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Explanation:

H² + Br² = 2HBr

2Mg + O² = 2MgO

2H² + O² = 2H²O

hope this helps you

Answer:

H² + Br² = 2HBr

2Mg + O² = 2MgO

H² + O² = 2H2O

HOPE IT'S WORK

Answer:

d=0.4cm

t=0.25km

v=7s of 100m

i hope it helps you

this is my asnwer

correct me if im wrong

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Na2SO3 – Sodium sulfite

A  covalent bond is likely to form between two nonmetals with electron deficiency. Hence, they will share their valence electrons each other to achieve octet.

A covalent bond is formed between two non-metals through sharing of valence electrons between atoms. For example carbon and oxygen are non metals forming the covalent compound CO.

The number of shared pair of electron depends on the valence of each atoms. For example in HCl, both atoms shares one electron to each other.

In a covalent compound, if the difference in electronegativity between two atoms is significant, the shared pair of electrons attracts towards the highly electronegative atom and resulting charge separation make them polar compounds.

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Answer:i am not studying chemistry but best of luck to you

Explanation:

A central theme in chemistry is that we study Observable changes in matter to understand their Unobservable causes.

Matter is a substance made up of a variety of sorts of particles that occupies physical house and has inertia. According to the standards of current physics, the a variety of sorts of particles every have a particular mass and size. The most acquainted examples of fabric particles are the electron, the proton and the neutron.

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73.3 mL of 3.00M CH3OH solution is needed to provide 0.220 mol of CH3OH.

To determine the volume of a 3.00 M CH3OH solution needed to provide 0.220 mol of CH3OH, we can use the formula:

moles = concentration x volume

Rearranging the formula to solve for volume, we get:

volume = moles / concentration

Substituting the given values, we have:

volume = 0.220 mol / 3.00 M

Solving for volume, we get:

volume = 0.0733 L or 73.3 mL

Therefore, a volume of 73.3 mL of 3.00 M CH3OH solution is needed to provide 0.220 mol of CH3OH.

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Chemically speaking, covalent bonds are those between two or more atoms when the electrons are shared rather than transferred, as in the case of ionic bonds. Generally speaking, ionic bonding can be seen in compounds where a metal is bound to a semi or a semi-metal.

Hydrogen (H2), oxygen (O2), nitrogen (N2), water (H2O), and methane (CH4) are five instances of covalent bonding. A covalent bond is a type of chemical relationship where two atoms share electron pairs.

Covalent compounds are those whose atoms are joined together by covalent bonds. Sharing 1 or more pair of valance electrons results in the formation of a covalent bond.

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True. Polarity impacts bonding between water molecules in both liquid and solid states. Polarity arises due to the unequal sharing of electrons between oxygen and hydrogen atoms in a water molecule, leading to partial positive and negative charges.

These charges cause water molecules to form hydrogen bonds, which give water its unique properties in liquid and solid states. Water molecules have a polar covalent bond due to the unequal sharing of electrons between the hydrogen and oxygen atoms. This polarity allows water molecules to form hydrogen bonds with each other. In the liquid state, water molecules are constantly moving and forming and breaking hydrogen bonds with each other. In the solid state, the water molecules are arranged in a crystal lattice structure where each molecule is bonded to four others through hydrogen bonds. This arrangement gives ice a lower density than liquid water and allows it to float. The polarity of water also makes it a good solvent for polar and charged substances.

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Egg whites are simply made frothy by adding air during the whipping process. It's a physical shift as they are still eggs whites—a material that has not changed. Yet in a chemical transformation.

To put it another way, a chemical always consists of the same "substance." There are some substances in nature, like water. Other chemicals, including chlorine, are produced

All of these things are made of chemicals, some organic and others manmade, including air, water, iron, fuel, clothes, stones, equipment, plastics, plants, and food. Chemicals can be made up of several distinct chemicals or they might be specific chemical molecule like water. Nitrogen, carbon, water, carbon dioxide, and other substances are all present in air.

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14.7 mL of the 0.010 M sodium bromide solution is required to begin the precipitation of copper(I) bromide.

To determine the volume of 0.010 M sodium bromide solution required to begin the precipitation of copper(I) bromide, we need to calculate the number of moles of copper(I) nitrate present in the solution, as well as the number of moles of copper(I) bromide that can be formed.

First, we can calculate the number of moles of copper(I) nitrate:

moles of Cu(NO₃)₂ = mass / molar mass = 0.05135 g / (Cu: 63.55 g/mol + 2xN: 2x14.01 g/mol + 6xO: 6x16.00 g/mol) = 0.000294 mol

Since copper(I) nitrate contains one mole of copper for every two moles of nitrate, we can calculate the number of moles of copper(I) ions:

moles of Cu⁺ = 0.000294 mol / 2 = 0.000147 mol

Copper(I) bromide can be formed by mixing copper(I) ions with bromide ions in a 1:1 molar ratio. Therefore, the number of moles of sodium bromide required to react with all the copper(I) ions can be calculated as:

moles of NaBr = moles of Cu⁺ = 0.000147 mol

Finally, we can calculate the volume of the 0.010 M sodium bromide solution required to provide this amount of moles:

volume of NaBr solution = moles of NaBr / molarity of NaBr solution = 0.000147 mol / 0.010 mol/L = 0.0147 L = 14.7 mL

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Answer:

The light bends

Explanation:

When it passes through two different densities it changes directions, causing a bend

Answer:

B

Explanation:

Answer:

Yes under certain conditions

Explanation:

Although radioactivity is harmful, there are still safety precautions people can take to avoid disaster. Assuming that the radioactive waste is already in a specialized bin, workers would have to wear hazmat suits and load it onto a truck. It would be best if the truck was made out of at least 2 layers of some strong metal like titanium. Next, a route would need to be planed out with 2 factors in mind. 1. It has to be a relatively isolated road. 2. It has to be the shortest route taken. The truck must already be fueled to avoid running out of gas in the middle of the road or having to go off the assigned route to a gas station. It would help out a lot if the factories were relatively close to the pickup destination so it would be quicker to travel from point A to point B. There are more things that can be done in terms of safety but these are key.

The question asks to determine the pH at the half-equivalent point during the titration of 100.0 ml of 0.295 M HF with 50.0 ml of 0.295 M NaOH. The given Ka value is 6.8x10^-4. We need to find the pH at the point where half of the HF has reacted with NaOH.

To solve this problem, we need to use the Henderson-Hasselbalch equation, which is given by:

pH = pKa + log([A-]/[HA])

In this equation, [A-] represents the concentration of the conjugate base (F-) and [HA] represents the concentration of the acid (HF). At the half-equivalent point, the moles of HF reacted will be equal to the moles of NaOH added.

First, we need to calculate the moles of HF and NaOH. Moles can be calculated using the formula:

moles = concentration (M) * volume (L)

For HF:
moles of HF = 0.295 M * 0.100 L = 0.0295 mol

For NaOH:
moles of NaOH = 0.295 M * 0.050 L = 0.01475 mol

Since the reaction between HF and NaOH is 1:1, the moles of HF reacted at the half-equivalent point will be half of the initial moles of HF:

moles of HF reacted = 0.0295 mol / 2 = 0.01475 mol

Now, we can calculate the concentration of F- and HF at the half-equivalent point using the balanced chemical equation:

At the half-equivalent point, moles of F- will be equal to moles of HF reacted, which is 0.01475 mol.

Concentration of F- = moles of F- / total volume (L)
Concentration of F- = 0.01475 mol / (0.100 L + 0.050 L) = 0.0983 M

Concentration of HF at the half-equivalent point will be the initial concentration minus the concentration of F-:

Concentration of HF = 0.295 M - 0.0983 M = 0.1967 M

pH = -log(6.8x10^-4) + log(0.5)
pH = -(-3.17) + log(0.5)
pH = 3.17 + (-0.30)
pH = 2.87

Therefore, the pH at the half-equivalent point is 2.87 (rounded to 2 decimal places).

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Answer:

changes that dont result in the formation of new substance with new properties.

The final temperature of the glass and water mixture is 46.37°C.  

Temperature is a measure of the average kinetic energy of the particles and molecules that make up a substance. Temperature is often measured in degrees Celsius (°C), Fahrenheit (°F) or Kelvin (K). Temperature is a fundamental physical quantity that is used to describe the degree of hotness or coldness of a material. Temperature affects many physical and chemical properties of a substance, including its viscosity, melting point, boiling point, electrical resistance, and even its color. The speed of biological and chemical reactions is also impacted by temperature.

The total heat in the system (the glass + the water) is given by the following equation:
Heat = Mass x Specific Heat x Temperature Change
For the glass:
Heat = 41.0 g x 8.79 J/g °C x (T f - 95°C)
For the water:
Heat = 175 g x 4.18 J/g °C x (T f - 21°C)
Where T F is the final temperature.
We can set the two equations equal since the total heat in the system must be conserved:
41.0 g x 8.79 J/g °C x (T f - 95°C) = 175 g x 4.18 J/g °C x (T f - 21°C)
Solving for T f:
T f = (41.0 g x 8.79 J/g °C x (T f - 95°C)) / (175 g x 4.18 J/g° C) + 21°C
T f = (347.69 J/g °C x T f - 3451.05 J/g °C) / 719.5 J/g °C + 21°C
T f = (347.69 J/g °C x T f) / 719.5 J/g °C - 3451.05 J/g °C / 719.5 J/g °C + 21°C
T f = (347.69 T f) / 719.5 - 48.17 + 21°C
T f = (347.69 T f + 34278.85) / 719.5
T f = 46.37°C
The total heat in the system (the glass + the water) is given by the following equation:

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Answer: type the compound into your search bar then it should tell you what it is for 3. you should look up "what is the formula for -----" same thing for #4

Explanation:

Answer:

2.a.  germanium tetrahydride

2.b. dinitrogen tetrabromide

2.c. diphosphorus pentasulfide

2.d. selenium dioxide

2.e. nitrogen trihydride

2.f. silicon dioxide

3.a. PO3

3.b. SiCl4

3.c. N2O5

3.e. N2O4

3.f. CO

4.a CO2

4.b. SF6

4.c. N2Cl4

4.d. CI4

4.e. PF5

4.f. P2O5

****All numbers are subscripts, please do not write them as is, but to the bottom right of them like shown in the options from question 2.

Explanation:

To name covalent compounds (NM+NM), we use prefixes.

To name covalent compounds goes as follows:

First, name the first element in the formula the normal name it has (ex. Nitrogen, Oxygen). If the first element is present more than once shown by a subscript, use a prefix that will indicate how many there are present (ex. mono, di, tri).

Next, name the second element in the compound using prefixes aswell if present more than once. These elements though, will end with -ide instead of their original name (ex. monoxide, dibromide, trichloride).

The Lewis structure of AsO showing 2 lone pairs is as follows:

O

As

/

X X (where X represents a lone pair)

The molecular geometry of AsO is trigonal planar. The central As atom is hybridized with sp2 hybridization. The approximate bond angles in AsO are 120 degrees. The AsO ion is polar.

A Lewis structure, also known as a Lewis dot diagram, is a way to represent the chemical bonding in a molecule. It uses dots (also called electron dots or Lewis dots) to show the valence electrons on an atom, and lines to show the bonds between atoms. The goal of drawing a Lewis structure is to use the valence electrons of the atoms in a molecule to form the most stable arrangement of atoms, that is to say, to achieve the octet rule where each atom has 8 valence electrons in its outermost shell.

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The presence of hydrogen would be indicated by a pale blue flame that is nearly invisible in broad daylight, but the presence of carbon dioxide would be indicated by the flame going out.

A flame ignited by hydrogen gas emits a barely perceptible pale blue flame under normal lighting conditions. This is due to the flame that hydrogen gas produces mostly emitting light in the ultraviolet spectrum, which is invisible to the human eye.

On the other side, a flame is put out when carbon dioxide gas is added to it. This is because carbon dioxide is a gas that does not support burning and is not flammable.

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5) Convert molarity to percent, calculate moles of acetic acid, convert moles to grams, divide grams by volume in mL, multiply by 100 to obtain experimental percent, and calculate percent error.

6) Phenolphthalein could have been used as an alternative indicator.

7) When using barium hydroxide instead of sodium hydroxide, adjust the calculations by considering the stoichiometry of the reaction and using a molar ratio of 2:1 between acetic acid and barium hydroxide.

5. To calculate the percent error in the concentration of acetic acid, we need to convert our molarity (M) results to percent (%). Using the average molarity and the average volume (converted to liters) of acetic acid, we can calculate the number of moles of acetic acid.

Then, by converting moles to grams using the molar mass of acetic acid (CH3COOH), we can divide the grams of acetic acid by the average volume (in milliliters) of acetic acid and multiply by 100 to obtain the experimental percent.

Finally, we can calculate the percent error by comparing the experimental percent to the labeled percent (4% vinegar on the bottle).

6. An alternative indicator that could have been used is phenolphthalein. Phenolphthalein is commonly used in acid-base titrations and changes color in a specific pH range, indicating the endpoint of the reaction.

6. If barium hydroxide (Ba(OH)2) were used instead of sodium hydroxide (NaOH), the adjustment in calculations would involve the stoichiometry of the reaction. The balanced chemical equation for the reaction between acetic acid and barium hydroxide is:

2CH3COOH + Ba(OH)2 → Ba(CH3COO)2 + 2H2O

The molar ratio between acetic acid and barium hydroxide is 2:1. Therefore, the number of moles of barium hydroxide used would be half the number of moles of acetic acid in the calculation.

The rest of the procedure, including converting moles to grams and calculating the percent, would remain the same.

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