g Suppose a uniform slender rod has length L and mass m. The moment of inertia of the rod about about an axis that is perpendicular to the rod and that passes through its center of mass is given by Icm=112mL2. Find Iend, the moment of inertia of the rod with respect to a parallel axis through one end of the rod.

Answer:

1. The density of the cube is 1.03 g/mL.

2. Dish soap

Explanation:

1. Determination of the density of the cube.

From the question given above, the following data were obtained:

Mass (m) of cube = 21.7 g

Volume (V) of cube = 21 mL

Density (D) of cube =?

The density of a substance is simply defined as the mass of the substance per unit volume of the substance. Thus, density can be expressed mathematically as:

Density (D) = mass (m) / volume (V)

D = m / V

With the above formula, we can obtain the density of the cube as follow:

Mass (m) of cube = 21.7 g

Volume (V) of cube = 21 mL

Density (D) of cube =?

D = m / V

D = 21.7 / 21

D = 1.03 g/mL

Thus, the density of the cube is 1.03 g/mL.

2. Determination of the layer of density the cube will settle in.

From the question given above,

Subtance >>>>>>>> Density

Vegetable oil >>>>> 0.91 g/mL

Grape juice >>>>>> 0.97 m/L

Water >>>>>>>>>>> 1 g/mL

Dish soap >>>>>>>> 1.03 g/mL

Maple syrup >>>>>> 1.37 g/mL

Comparing the density of the cube (i.e 1.03 g/mL) with those in the table able, we can conclude that the cube will settle in the DISH SOAP layer since they both have the same density.

The hiker made it to a safe landing on the other side of the gap after travelling horizontally at 2.49 m.

The time taken for the hiker to fall from the given height is calculated as follows;

h = vt + ¹/₂gt²

where;

h = ¹/₂gt²

t = √(2h/g)

t = √[(2 x 0.6) / (9.8)]

t = 0.35 seconds

The horizontal velocity of the hiker during the period of acceleration is calculated as follows;

Vₓ = at

Vₓ = (5.92 m/s²) x (1.2 s)

Vₓ = 7.104 m/s

The horizontal distance travelled during the time period of 0.35 seconds;

X = Vₓt

X = 7.104 x 0.35

X = 2.49 m

Thus, the hiker made it to a safe landing on the other side of the gap which is 2.3 m wide and smaller to his horizontal displacement of 2.49 m.

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Answer:

8.0 rad/s

Explanation:

I₁ = 1.0 kgm², ω₁ = -20.0 rad/s (clockwise is positive direction)

I₂ = 4.0 kgm², ω₂ = 15.0 rad/s

Angular momentum conservation:

I₁ω₁ + I₂ω₂ = (I₁ + I₂)ω

1.0 x (-20.0) + 4.0 * 15.0 = (1.0 + 4.0)ω

40.0 = 5.0ω

so ω = 8.0 rad/s

Answer:

none of the above

Explanation:

im pretty positive this is the answer tell me if i am wrong please

Answer:

M = 0.31 kg

Explanation:

This exercise must be done in parts, let's start by finding the speed of the set arrow plus apple, for this we define a system formed by the arrow and the apple, therefore the forces during the collision are internal and the moment is conserved

let's use m for the mass of the arrow with velocity v₁ = 20.4 m / s and M for the mass of the apple

initial instant. Just before the crash

          p₀ = m v₁ + M 0

instant fianl. Right after the crash

          p_f = (m + M) v

          p₀ = p_f

          m v₁ = (m + M) v

          v =\(\frac{m}{m+M} \ v_1\)                          (1)

now we can work the arrow plus apple set when it leaves the child's head with horizontal speed and reaches the floor at x = 8 m. We can use kinematics to find the velocity of the set

          x = v t

          y = y₀ + \(v_{oy}\) t - ½ g t²

when it reaches the ground, its height is y = 0 and as it comes out horizontally, \(v_{oy} = 0\)

          0 = h - ½ g t²

          t² = 2h / g

For the solution of the exercise, the height of the child must be known, suppose that h = 1 m

            t = \(\sqrt{ \frac{ 2 \ 1}{9.8} }\)

            t = 0.452 s

let's find the initial velocity

             v = v / t

             v = 8 / 0.452

             v = 17.7 m / s

From equation 1

              v = m / (m + M) v₁

              m + M = \(m \ \frac{v_1}{v}\)

              M = m + m \  \frac{v_1}{v}

we calculate

              M = 0.144 + 0.144  \(\frac{20.4}{17.7}\)

              M = 0.31 kg

Knowing the exits are exactly 7 km apart, the cars pass each other at 9:29 and 15 seconds a.m.

The relative velocity of the cars is 30 m/s - 26 m/s = 4 m/s.

The distance between the cars is 7 km = 7000 m.

The time it takes for the cars to pass each other is 7000 m / 4 m/s = 1750 seconds.

1750 seconds is 29 minutes and 15 seconds.

To calculate the time in minutes;

Let:

v_p = the speed of car P (m/s)

v_q = the speed of car Q (m/s)

d = the distance between the cars (m)

t = the time it takes for the cars to pass each other (s)

Given that:

v_p = 30 m/s

v_q = 26 m/s

d = 7000 m

Use the equation for relative velocity to find the velocity of the cars relative to each other:

v_r = v_p - v_q

v_r = 30 m/s - 26 m/s = 4 m/s

Use the equation for distance to find the time it takes for the cars to pass each other:

d = v_r × t

7000 m = 4 m/s × t

t = 7000 m / 4 m/s = 1750 s

Convert 1750 seconds to minutes and seconds:

1750 s = 29 minutes and 15 seconds

Therefore, the cars pass each other at 9:29 and 15 seconds a.m.

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Answer:

In the formula, F = m×a, where a represents acceleration.

Answer:

Force=mass times acceleration

Explanation:

Answer:a vertical expanse of water stretching between the surface and the floor of a body of water

Explanation:

Answer:

MA=Fo/Fi

Explanation:

The interval between the first and second echo is 7 seconds. This means that after the initial sound wave reaches the first cliff, it takes a total of 7 seconds for the sound to travel to the second cliff and then return to the student as the second echo.

To determine the interval between the first and second echo, we need to consider the time it takes for sound to travel from the student to the first cliff, and then from the first cliff to the second cliff, and finally back to the student.

Let's break down the distances and calculate the time for each part of the journey:

Distance from the student to the first cliff: 330 meters

Time taken: t₁ = distance / speed = 330 m / 330 m/s = 1 second

Distance from the first cliff to the second cliff: 990 meters

Time taken: t₂ = distance / speed = 990 m / 330 m/s = 3 seconds

Distance from the second cliff back to the student: 990 meters

Time taken: t₃ = distance / speed = 990 m / 330 m/s = 3 seconds

Now, we can calculate the total interval between the first and second echo by adding up the individual times:

Interval between first and second echo = t₁ + t₂ + t₃ = 1 s + 3 s + 3 s = 7 seconds

Therefore, the interval between the first and second echo is 7 seconds. This means that after the initial sound wave reaches the first cliff, it takes a total of 7 seconds for the sound to travel to the second cliff and then return to the student as the second echo.

It's important to note that this calculation assumes a straight path for the sound waves and neglects factors such as air temperature and wind that can affect the speed of sound. Additionally, it assumes perfect reflection of sound waves off the cliffs, which may not be the case in real-world scenarios.

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Note the complete questions is:

A student stands 330m from a tall cliff which is 990m from another tall cliff. If the speed of sound between the cliffs is 330m/s.What is the interval between the first and second echo?

The two kinds of energy associated with flames are light and heat.

To burn something in contact with air it must be heated to its ignition temperature. Iron has a strong molecular force of attraction. So, when heated it doesn't burn. But iron fillings when sprinkled in flames attain the in=gnition temperature quickly.

The same reason is valid for the twigs and the logs. Kindling or smaller pieces have a lot of surface area and therefore have more contact with oxygen, making them easier to burn.

Answer:

configuration of string:

Node - Antinode - Node    or N-A-N

This is 1/2 wavelength since a full wavelength is N-A-N-A-N

f (fundamental) = V / wavelength

F0 = 300 m/s / 1 m = 100 / sec

F1 = 300 m/s / .5 m = 600 / sec

Each increase is a multiple of the fundamental since the wavelength

increases by 1/2 wavelength to keep nodes at both ends of the string

Answer:

4.3 g/cm³ or 4.3g/cc

Explanation:

Volume(V) = Height × Length × Width

= 5cm × 3cm × 2cm

= 30cm³

Mass(m) = 129gram

So,

Density = m/V

= 129g/30cm³

= 4.3g/cc or 4.3g/cm³

Answer:

false

Explanation:

if an object is accelerating the object will not travel the same distance every time interval

Answer: part a) both the tension and gravity vectors will be pointing downwards.

part b) the tension vector will be pointing upwards and the gravity will be pointing downwards.

Explanation:

part a) Since you are looking at the FBD for the steel cable here, the tension will be pointing downwards because the girder is hung from the cable which creates a downwards tension. Gravity will always point downwards, to the ground.

part b) Since you are looking at the FBD for the girder here, the tension will be pulled upwards because the cable is weighted which creates an upwards tension. Gravity will always point downwards, to the ground.

Sorry for the poor explanation, but hopefully this makes sense.

(a)Both the tension and gravity vectors will be pointing downwards in the component.

(b) The tension vector will point upwards, whereas the gravity vector will point downwards.

A free-body diagram is a diagrammatic representation of a single body or a subsystem of bodies that have been isolated from their surroundings and depicts all of the forces acting on it.

(a) Both the tension and gravity vectors will be pointing downwards in the component.

Because the girder is suspended from the cable, creating downward tension. Gravity will constantly pull you down, toward the ground.

(b) The tension vector will point upwards, whereas the gravity vector will point downwards.

The tension will be lifted upwards due to the cable's weight, which causes upwards tension. Gravity will constantly pull you down toward the ground.

Hence the tension and gravity is shown with the help of FBD in both cases

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\(\displaystyle U_s = 0.6 \ J\)

Math

Pre-Algebra

Order of Operations: BPEMDAS

Physics

Energy

Elastic Potential Energy: \(\displaystyle U_s = \frac{1}{2} k \triangle x^2\)

Step 1: Define

k  = 7.50 N/m

Δx = 0.40 m

Step 2: Find Potential Energy

a student rises their 15 kg back pack from the floor at a constant velocity of 5.0 m/s then they apply of 37.5 N of force.

Force is responsible for the motion of an object. it produces acceleration in the body. According to newton's second law force is mass times acceleration i.e. F =ma. Its SI unit is N which is equivalent to kg.m/s². There are two types of forces, balanced force and unbalanced force.

In this problem student rises 15 kg of backpack at constant velocity and it happens in 2s, so consider time t = 2s.

Force is change in velocity with respect to time multiplied by mass.

F = m dv/dt

F = 15 kg × 5.0 m/s/2s

F = 37.5 N

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Answer:

d) The box’s initial potential energy is transformed into kinetic energy and

thermal energy.

Explanation:

Let us analyze the situation first. Initially we have a box at rest placed at some height on a ramp. So, the three energies associated with the box will be:

Kinetic Energy = 0 (due to zero velocity)

Thermal Energy = 0 (due to not temperature change)

Potential Energy = Greater than zero value (due to height)

Now, when the box is released to slide down the ramp with friction, the energies become:

Kinetic Energy = Increasing (due to increase in velocity)

Thermal Energy = Increasing (due to increase in temperature, because of friction)

Potential Energy = Decreasing (due to decrease in height)

So, from Law of Conservation of Energy, we can write:

Loss of Potential Energy = Gain in Kinetic Energy + Gain in Thermal Energy

So, the correct option is:

d) The box’s initial potential energy is transformed into kinetic energy and  thermal energy.

If the distance between them is tripled, the gravitational force is F2= 36/9=4N. The force of attraction between any two bodies is proportional to the product of their masses and inversely proportional to the square of their distance.

WHAT IS GRAVITATIONAL FORCE?

The formula for Gravitational force:

F=G m1*m2/r² ,

G: gravitational constant = 6.67x10⁻¹¹ N*m²/kg²

m1: is the mass of the first object

m2: is the mass of the second object

r: is the distance between the center of the masses of the objects

F∝1/r²

so F1/F2=( r2/r1)².......(1)

Given F1= 36N F2=?

let r1=r, r2= 3r

putting all this value in equation (1)

36/F2= (3r/r)²

⇒F2= 36/9=4N

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The object's speed shortly before it lands on the earth is 40 m/s.

The speed at which something moves in a specific direction is known as its velocity. as the speed of a car driving north on a highway or the pace at which a rocket takes off. Because the velocity vector is scalar, its absolute value magnitude will always equal the motion's speed.

The parameters are as follows: the pebble's time, t = 4 s; the object's velocity right before impact;

The kinematic equation is as follows;

v = in which

v = 0+10 (4)

The object's speed right before impact with the earth is v = 40 m/s2, where g is the acceleration caused by gravity and an is a constant of 10 m/s2. As a result,

the object's final velocity before impact is 40 m/s.

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Answer:

D

Explanation:

Mass is the amount of matter your body has ....does not change on the Moon.

there is less gravity .....so your WEIGHT would decrease

The input to the power station is 5x10^9 W. This means that the power station requires an input of 5x10^9 watts to produce an electrical power output of 1.9x10^9 watts with an efficiency of 38%.

The efficiency of a power station is defined as the ratio of its output power to input power. Therefore, we can use the efficiency and the electrical power output of the power station to calculate its input power as follows:

Efficiency = Output power / Input power

Solving for input power, we get:

Input power = Output power / Efficiency

Substituting the given values, we get:

Input power = 1.9x10^9 W / 0.38

Input power = 5x10^9 W (to two significant figures)

The rest of the input power is lost as heat due to inefficiencies in the power generation process.

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The potential energy of the student standing on the building floor, 15 m above the ground, is 30,000 Joules.

To calculate the potential energy (P.E) of the student standing on a building floor, use the formula P.E = mgh, where m = mass of the student, g = acceleration due to gravity, and h = height above the ground.

Given:

Mass of the student (m) = 200 kg

Acceleration due to gravity (g) = 10 m/s^2

Height above the ground (h) = 15 m

Using the formula, calculate the potential energy as follows:

P.E = mgh

= 200 kg x 10 m/s² x 15 m

= 30,000 kg·m²/s²

= 30,000 J (Joules)

Therefore, the potential energy of the student standing on the building floor, 15 m above the ground, is 30,000 Joules.

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Answer:

speed and velocity or direction.

The boat must have moved, despite not being seen to move, because its relative position to the dock has changed. This phenomenon is known as relative motion .

Everything is always in motion, but the way we perceive it depends on our frame of reference.

In this scenario, the dock was the frame of reference for the initial position of the boat. When the boat moved to the cove, its position relative to the dock changed, and the dock was no longer an appropriate frame of reference. The boat's motion is now relative to the cove instead.

It is important to note that relative motion depends on the chosen frame of reference. If we were to choose the boat as the frame of reference, then it would be the dock that appears to move, not the boat. This is because motion is always relative to a chosen frame of reference.

In conclusion, the boat must have moved because its position relative to the dock changed. The concept of relative motion reminds us that motion is always relative to a chosen frame of reference, and that the way we perceive motion depends on our chosen frame of reference.

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The best, most helpful observation you can make is to LOOK steadily and squarely at the PICTURE of the stack.

For some nefarious reason, you decided to prevent us from doing that.

Answer: The scenario violates the second law of thermodynamics.

Explanation: The second law states that heat cannot be converted into work without some loss of usable energy, and that the amount of usable energy in a closed system will always decrease over time. Therefore, the machine described in the scenario cannot exist because it would violate the second law by converting all of the heat into electricity without any loss of usable energy.

Answer:

A. 1.4 m/s to the left

Explanation:

To solve this problem we must use the principle of conservation of momentum. Let's define the velocity signs according to the direction, if the velocity is to the right, a positive sign will be introduced into the equation, if the velocity is to the left, a negative sign will be introduced into the equation. Two moments will be analyzed in this equation. The moment before the collision and the moment after the collision. The moment before the collision is taken to the left of the equation and the moment after the collision to the right, so we have:

\(M_{before} = M_{after}\)

where:

M = momentum [kg*m/s]

M = m*v

where:

m = mass [kg]

v = velocity [m/s]

\((m_{1} *v_{1} )-(m_{2} *v_{2})=(m_{1} *v_{3} )+(m_{2} *v_{4})\)

where:

m1 = mass of the basketball = 0.5 [kg]

v1 = velocity of the basketball before the collision = 5 [m/s]

m2 = mass of the tennis ball = 0.05 [kg]

v2 = velocity of the tennis ball before the collision = - 30 [m/s]

v3 =  velocity of the basketball after the collision [m/s]

v4 = velocity of the tennis ball after the collision = 34 [m/s]

Now replacing and solving:

(0.5*5) - (0.05*30) = (0.5*v3) + (0.05*34)

1 - (0.05*34) = 0.5*v3

- 0.7 = 0.5*v

v = - 1.4 [m/s]

The negative sign means that the movement is towards left

Answer:

A. 1.4 m/s to the left

Explanation: