Gallup conducted a poll of 492 registered Democrats and 502 registered Republicans about whether or not they think individuals are born with their sexual orientation (i.e., born straight, gay, lesbian, pansexual, asexual, bisexual, demisexual, etc.) or whether sexual orientation is something that is influenced by upbringing and other social/environmental factors. The sample proportion of registered Democrats that believed people are born with their sexual orientation was 0.6098 and the sample proportion of registered Republicans that believed people are born with their sexual orientation was 0.3606. Test the null hypothesis of no difference between the population proportions of registered Democrats and registered Republicans who believe people are born with their sexual orientation. What is the research hypothesis in this study? O There is no difference in population proportions of registered Democrats and registered Republicans who believe people are born with their sexual orientation. O There is a difference in population proportions of registered а Democrats and registered Republicans who believe people are born with their sexual orientation. The sample proportion of registered Democrats that believed people are born with their sexual orientation was and the sample proportion of registered Republicans that believed people are born with their sexual orientation was What is the combined sample proportion (P*)? What is the standard error of the difference? What is calculated z? Based on the comparison of calculated z and critical z, what must we do? O Retain the null hypothesis that there is no difference in population proportions of registered Democrats and registered Republicans who believe people are born with their sexual orientation. O Reject the null hypothesis and conclude there is a difference in population proportions of registered Democrats and registered Republicans who believe people are born with their sexual orientation.

a random variable can have any value that is possible within the range of -infinity and infinity.So a. can have any value between -infinity and infinity.

A random variable from an experiment with outcomes that are normally distributed can take on any value between -infinity and infinity. This means that it can take on any real number, including fractions and decimals. It is not limited to only a few discrete values, nor does it have to be positive.

A random variable from an experiment with outcomes that are normally distributed can take on any real value between -infinity and infinity. This means that the variable is not limited to a few discrete values, nor does it have to be positive. Instead, it can have any value, no matter how small or large, and including fractions and decimals. Such a random variable can have any value that is possible within the range of -infinity and infinity.

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Answer:

x = 4, x = -4

Step-by-step explanation:

Step-by-step explanation:

Move terms to the left side

2=16

x^{2}=16x2=16

2−16=0

Use the quadratic formula

Simplify

Evaluate the exponent

Multiply the numbers

Add the numbers

Evaluate the square root

Multiply the numbers

=0±82

2

Separate the equations

To solve for the unknown variable, separate into two equations: one with a plus and the other with a minus.

=0+82

x= 0 + 8 over 2

=0−82 over 2

Rearrange and isolate the variable to find each solution

=4

x=4x=4

ans =−4

Answer:

x = 17.6

Step-by-step explanation:

use sine

⇒ sine = \(\frac{opposite}{hypotenuse}\)

⇒ sine 62 = \(\frac{20}{x}\)

sine of 62 is 0.88

⇒ 0.88 =  \(\frac{20}{x}\)

multiply 20 on both sides

⇒ 0.88 x 20 =  \(\frac{20}{x}\) x 20

⇒ 17.6 = x

Step-by-step explanation:

The domain of a quadratic is All Reals however the function is only increasing on the interval (-2, ♾️)

Therefore the domain is (-2, ♾️). The function is also one to one since only one. x value maps to one y value.

\(y = (x + 2) {}^{2} \)

Swap x and y

\(x = (y + 2) {}^{2} \)

\( \sqrt{x} = y + 2\)

\( \sqrt{x} - 2 = y\)

Let y=f^-1(x)

\(f {}^{ - 1} (x) = \sqrt{x} - 2\)

The domain here is [0, ♾️)

It won't be all reals since we can not graph the square root of a negative number on a cartisean coordinate plane

The equation of the line that passes through the points (-8, 9) and (2, -6) is y = (-3 / 2)x - 3.Given two points (-8, 9) and (2, -6). We are supposed to find the equation of the line that passes through these two points.

We can find the equation of a line that passes through two given points, using the slope-intercept form of the equation of a line. The slope-intercept form of the equation of a line is given by, y = mx + b,Where m is the slope of the line and b is the y-intercept.To find the slope of the line passing through the given points, we can use the slope formula: m = (y2 - y1) / (x2 - x1).Here, x1 = -8, y1 = 9, x2 = 2 and y2 = -6.

Hence, we can substitute these values to find the slope.m = (-6 - 9) / (2 - (-8))m = (-6 - 9) / (2 + 8)m = -15 / 10m = -3 / 2Hence, the slope of the line passing through the points (-8, 9) and (2, -6) is -3 / 2.

Now, using the point-slope form of the equation of a line, we can find the equation of the line that passes through the point (-8, 9) and has a slope of -3 / 2.

The point-slope form of the equation of a line is given by,y - y1 = m(x - x1)Here, x1 = -8, y1 = 9 and m = -3 / 2.

Hence, we can substitute these values to find the equation of the line.y - 9 = (-3 / 2)(x - (-8))y - 9 = (-3 / 2)(x + 8)y - 9 = (-3 / 2)x - 12y = (-3 / 2)x - 12 + 9y = (-3 / 2)x - 3.

Therefore, the equation of the line that passes through the points (-8, 9) and (2, -6) is y = (-3 / 2)x - 3. Thus, the answer is (-3/2)x - 3.

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The letters corresponding to the solutions are: x = 10, x = -3/2, x = -1/9, x = -6, x = 10/3 That gives you the letters "joke"1.  5x – 7 = 4x + 3.

To solve for x, we can add 7 to both sides of the equation and subtract 4x from both sides:

5x - 7 + 7 = 4x + 3 + 7

5x = 4x + 10

x = 10

2.  6 + 2x = 7x - 9

To solve for x, we can add 9 to both sides of the equation, subtract 6 from both sides and divide both sides by -1:

6 + 2x + 9 = 7x - 9 + 9

2x = -3

x = -3/2

3. 8x + 1 = -8 - x

To solve for x, we can add x to both sides of the equation and add 8 to both sides:

8x + 1 + x = -8 - x + x + 8

9x + 1 = 0

x = -1/9

4. -5 + 12x = 18x + 7

To solve for x, we can subtract 12x from both sides of the equation and add 5 to both sides:

-5 + 12x - 12x = 18x + 7 - 12x

-5 = 6x + 7

x = -6

5.  -4x + 3 = 5x - 13 - x

To solve for x, we can add x to both sides of the equation, subtract 3 from both sides and divide both sides by -1:

-4x + 3 + x = 5x - 13 - x + x + 3

-3x = -10

x = 10/3

The letters corresponding to the solutions are: x = 10, x = -3/2, x = -1/9, x = -6, x = 10/3

That gives you the letters "joke"

Therefore, The letters corresponding to the solutions are: x = 10, x = -3/2, x = -1/9, x = -6, x = 10/3 That gives you the letters "joke"1.  5x – 7 = 4x + 3.

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Answer:

D. linear; y = –x – 1

Step-by-step explanation:

Linear; y=-x - 1

The slope is negative since it’s decreasing. So it’s not the first equation. It’s not a quadratic equation because there is no forming U shape for this data. It’s not a exponential function because the slope is not 3 and a exponential function is in the form y=a(b)^x

...............................................................................................................................................

Answer:

The correct answer is D) linear; y = –x – 1

Step-by-step explanation:

To find this, use any values in the table and it will produce a true statement. This is how we check to see if a model is correct. See the two examples below for proof.

(4, 5)

y = -x - 1

-5 = -4 - 1

- 5 = -5 (TRUE)

(0, -1)

y = -x - 1

-1 = 0 - 1

-1 = -1 (TRUE)

By the Mean Value Theorem, there exists at least one point c = 0.783 in (0, π) where f'(c) = 2c cos(cc) is equal to the average rate of change of f(x) over [0, π].

To use the Mean Value Theorem for the function f(x) = sin(xx) on the interval [0, π], we first need to check that f(x) is continuous on [0, π] and differentiable on (0, π).

f'(x) = cos(u) * d/dx (u)
      = cos(xx) * (2x)
      = 2x cos(xx)

Since 2x and cos(xx) are both continuous functions on (0, π), their product f'(x) = 2x cos(xx) is also continuous on (0, π). Therefore, f(x) is differentiable on (0, π).

Now, we can apply the Mean Value Theorem to find a point c in (0, π) where the slope of the tangent line to f(x) is equal to the average rate of change of f(x) over [0, π].

Mean Value Theorem: If f(x) is continuous on [a, b] and differentiable on (a, b), then there exists a point c in (a, b) such that f'(c) = (f(b) - f(a))/(b - a).

Using f(x) = sin(xx) on the interval [0, π], we have a = 0, b = π, and

\(f(a) = sin(0*0) = 0 f(b) = sin(π*π) ≈ -0.15\)

f'(x) = 2x cos(xx), so we need to solve for c in the equation

\(f'(c) = (f(b) - f(a))/(b - a) 2c cos(cc) = (-0.15 - 0)/(π - 0) 2c cos(cc) ≈ -0.048 c cos(cc) ≈ -0.024 c ≈ 0.783\)

Therefore, by the Mean Value Theorem, there exists at least one point c in (0, π) where f'(c) = 2c cos(cc) is equal to the average rate of change of f(x) over [0, π]. We found that one such point is approximately c = 0.783.

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In a random sample of 5 infants affected by tetanus, the probability that only two will recover is 7.29%.

In a binomial distribution, the probability of getting a success must remain the same for the trials we are investigating.

For example, when tossing a coin, the probability of flipping a coin is ½ or 0.5 for every trial we conduct, since there are only two possible outcomes.

The formula for binomial probability is;

P(X = x) = ⁿCₓ * p^(x) * (1 - p)^(n - x)

where;

p is probability of success

q = 1 - p is probability of failure

n is sample size

x is number of successes

We are given;

p = 10% = 0.1

n = 5

x = 2

Thus;

P(X = 2) = ⁵C₂ * 0.1² * (1 - 0.1)⁵ ⁻ ²

P(X = 2) = 0.0729

P(X = 2) = 7.29%

Thus, in a random sample of 5 infants affected by tetanus, the probability that only two will recover is 7.29%

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a least squares linear trend line is just a simple regression line with the years recoded  then it is a true statement

The simple linear regression model is;

y = mx + c

Where,

y = dependent variable

m is the slope

x is the independent variable

c is the y- intercept

The long-term trend only Least-Squares Regression Model also follows the same format except y becomes Yt and x becomes t.

The long-term trend only Least-Squares Regression Model is therefore the same as a simple linear regression only with different variable terms.

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The value of radius of a right circular cylinder is 1,248 in for which the minimum surface area is obtained.

Volume of the  right circular cylinder be;

v(c) = 12 in³ =  π*r²*h    

In which, h is the height of the cylinder,

Then , h  =  12 / π*r²

Surface area of a right circular cylinder is:

S = area of base and top  + lateral area

S(A)  =  2*π*r²  + 2*π*r*h  ....eq 1

Put value of 'h' in equation (1)

S(r)  =  2*π*r² +   2*π*r*  ( 12 / π*r²)

S(r)  =  2*π*r² + 24 /r

Differentiate both sides,

S´(r)  =  4*π*r -  24 /r²

Put , S´(r)  = 0 to get the critical points.

4*π*r -  24 /r²  =  0

π*r - 6/r² = 0

π*r³ - 6  = 0

r³   =  1,91    

r = 1,248 in    

Check for the minimum surface area for r = 1,248 in.

Find the second derivative,

S´´(r)  =  4*π  +  48/r³    

S´´(r)  will always be positive.

Thus,  the minimum surface area S  is for   r = 1,248 in.

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The ordered pair that can be plotted together with these four points, so that the resulting graph still represents a function is (2, -1).

option C.

The ordered pair that can be plotted together with these four points, so that the resulting graph still represents a function is determined as follows;

The four points include;

A = (1, 2)

B = (2, - 3)

C = (-2, - 2)

D = (-3,  1)

The  ordered pair that can be plotted together with these four points, must fall withing these coordinates. Going by this condition we can see that the only option that meet this criteria is;

(2, - 1)

Thus, the ordered pair that can be plotted together with these four points, so that the resulting graph still represents a function is (2, -1).

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Answer:

12 minutes

2 times 60=120

From the given function, the domain of the function is (-∞, ∞) and range of the function is (-∞, -5].

The given function is:

\(f(x) = (2/3)(x - 4)^2 - 5\)

The domain of a function is the set of all possible input values (x) for which the function is defined. In this case, there are no restrictions on the input, so the domain is all real numbers:

Domain: (-∞, ∞)

The range of a function is the set of all possible output values (y) that the function can produce. To find the range of the given function, we can complete the square:

\(f(x) = (2/3)(x - 4)^2 - 5 \\ = (2/3)(x^2 - 8x + 16) - 5\\ = (2/3)x^2 - (16/3)x + 7.33\\ = (2/3)(x - 4)^2 - 4.67\\\)

Since the term \((x - 4)^2\) is always non-negative, the smallest value of the function occurs when \((x - 4)^2 = 0\), which happens when x = 4. Substituting x = 4 into the equation gives:

\(f(4) = (2/3)(4 - 4)^2 - 5 \\ = -5\)

Therefore, the range of the function is all real numbers less than or equal to -5:

Range: (-∞, -5]

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Answer:

The table is missing in the question. The table is provided below.

Step-by-step explanation:

1. In the table, it is given the difference of high temperature. They are :

-7, -7, 2, 5, -3, -2

Now adding the differences of high temperatures and taking out its average.

-7 + (-7) + 2 + 5 + (-3) + (-2)= -12

Average : \($-\frac{12}{6}=-2$\)

Thus the answer is an integer.

2.  In the table, it is given the difference of high temperature. They are :

0, -3, -7, -1, 1, 0

Now adding the differences of high temperatures and taking out its average.

0 + (-3) + (-7 )+ (-1) + 1 + 0= -10

Average : \($-\frac{10}{6} = -1.66$\)

Thus, the answer is not an integer. The answer lies between the integers -2 to -1.

Answer:

Ok to clear some question the top guy got 6 because there are 6 numbers

Step-by-step explanation:

Answer:

400

Step-by-step explanation:

you can do 2x2 and you get 4 then add the zeros

Answer:

$47.60

Step-by-step explanation:

\(18+\frac{148}{5} =47.60\) ($)

The value of n that satisfies each equation are fractions or integers  n = 5/2, n = (log3(4/9) + 2)/(-4) and n = 7/4.

What is fraction ?

A fraction is a mathematical expression that represents a part of a whole or a ratio of two quantities. It consists of two numbers, one on top of the other, separated by a horizontal or diagonal line. The number above the line is called the numerator and the number below the line is called the denominator.

According to the question:
a. \(4\sqrt(2) = 2 ^ n\)

We can write \(4\sqrt(2)\) as \(2^2 * \sqrt(2)\). Therefore, we can rewrite the equation as:

\(2^2 * \sqrt(2) = 2^n\)

We can simplify this to:

\(2^{2 + 1/2} = 2^n\)

\(2^{5/2} = 2^n\)

To solve for n, we can take the logarithm of both sides of the equation with base 2:

\(log2(2^(5/2)) = log2(2^n)\)

5/2 = n

Therefore, n = 5/2.

b. \(1/( \sqrt[4]{9} ) = 3 ^ n\)

We can simplify root(9, 4) to:

\(\sqrt[4]{9} = (4/9) ^ {1/4}\)

Substituting this into the equation gives:

\(1/((4/9)^{1/4}) = 3^n\)

Taking the reciprocal of both sides of the equation gives:

\((4/9)^{1/4} = 3^{-n}\)

Raising both sides of the equation to the fourth power gives:

\(4/9 = 3^{-4n}\)

Multiplying both sides of the equation by 9 gives:

\(4 = 9 * 3^{-4n}\)

Dividing both sides of the equation by 9 gives:

\(4/9 = 3^{-4n-2}\)

Taking the logarithm of both sides of the equation with base 3 gives:

\(log3(4/9) = -4n - 2\)

Solving for n gives:

\(n = (log3(4/9) + 2)/(-4)\)

Therefore, n = (log3(4/9) + 2)/(-4).

c.\(\sqrt[4]{32} * \sqrt[4]{8} = 2 ^ n\)

We can simplify root(32, 4) and root(8, 4) to:

\(\sqrt[4]{32} = 2\)

\(\sqrt[4]{8} = 2^{3/4}\)

Substituting these values into the equation gives:

\(2 * 2^{3/4} = 2^n\)

Multiplying the two terms on the left-hand side of the equation gives:

\(2^{7/4} = 2^n\)

To solve for n, we can take the logarithm of both sides of the equation with base 2:

\(log2(2^{7/4}) = log2(2^n)\)

7/4 = n

Therefore, n = 7/4.


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As per the concept of simple interest, the interest amount earned after three years is $306.

To calculate the interest amount earned, we can use the formula:

I = P * r * t

Where:

I = interest earned

P = principal amount

r = interest rate per year (as a decimal)

t = time period in years

Plugging in the values from the problem, we get:

I = $1200 * 0.085 * 3

I = $306

This means that after three years, the bond will be worth the principal amount plus the interest earned, which is:

$1200 + $306 = $1506

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Answer:

One of the most common algebraic symbols is the use of x, y or another letter of the alphabet to indicate a variable or unknown quantity. Common symbols used in algebra also include those related to equality, inequality, factorials and organization, like braces, brackets and parentheses.

Give brainiest please ;-;

Answer:

different variables represent unknown numbers.

Step-by-step explanation:

For example the equation 5x = 15

X is a variable that represents an unknown number. To get the unknown number in the example you need to divide 15 by 5 and 5 by 5 to get X alone and then X will equal 3.

So 5×3=15

I hope this helps

There are 0.002 mg of Epinephrine.

The ratio shows how many times one value is contained in another value.

Example:

There are 3 apples and 2 oranges in a basket.

The ratio of apples to oranges is 3:2 or 3/2.

We have,

Epinephrine and solutions ratio is 1 : 10,000

Now,

Solutions = 20 mg

This means,

10,000 = 20

Divide both sides by 10,000.

1 = 20/10,000

1 = 0.002

This means,

Epinephrine is 0.002 mg

Thus,

Epinephrine is 0.002 mg.

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Answer:

The answer is B y=tan x

The graph y = tanx  function is not graphed correctly, the correct graph of the function is attached in the question.

Trigonometric functions are also known as Circular Functions can be simply defined as the functions of an angle of a triangle.

The trigonometric ratios can also be considered as functions of a variable which is the measure of an angle. This angle measure can either be given in degrees or radians . Here, we will use radians.

Since, tan(x)=sin(x)cos(x) the tangent function is undefined when cos(x)=0 . Therefore, the tangent function has a vertical asymptote whenever cos(x)=0 .

Similarly, the tangent and sine functions each have zeros at integer multiples of π because tan(x)=0 when sin(x)=0 .

The graph of a tangent function y=tan(x) is attched in the image.

Hence, the graph y = tanx  function is not graphed correctly, the correct graph of the function is attached in the question.

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The 1 dollars found near the table by your friend is likely the money for the tickets.

You are selling tickets at a dance. Individual tickets cost $6, and 2 tickets for a couple cost $10. After the dance, you count $1075 and 195 tickets.

let

x = number of individual ticket

y = number of couple tickets = 2x

Therefore, using equation,

2x(10) + 6x = 1075

2x + x = 195

Hence,

20x + 6x  = 1075

3x = 195

x = 195 / 3

x = 65

Hence,

26x = 1075

26(65) = 1690

Therefore, the money on the table is the ticket money because the money is short of the amount of the tickets in dollars.

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The correct answer is The logic behind the Secant method is to iteratively update two initial guesses, x0 and x1, based on the function evaluations at those points. The formula x2 = x1 - (f(x1) * (x1 - x0)) / (f(x1) - f(x0)) is used to update the guesses and obtain a new approximation, x2

Here's an example MATLAB code that implements the Secant method to find the root of a function:

% Function to find the root of

function y = myFunction(x)

\(y = x^3 - 5*x^2 + 6*x - 2;\)

end

% Secant method

x0 = 0; % Initial guess x0

x1 = 1; % Initial guess x1

approx_error = 1; % Initial approximation error

while approx_error > 0.001 % Set the desired approximation error threshold

\(x2 = x1 - (myFunction(x1) * (x1 - x0)) / (myFunction(x1) - myFunction(x0));\)

\(approx_error = abs((x2 - x1) / x2) * 100; % Calculate the approximation\)error

   x0 = x1;

   x1 = x2;

The logic behind the Secant method is to iteratively update two initial guesses, x0 and x1, based on the function evaluations at those points. The formula x2 = x1 - (f(x1) * (x1 - x0)) / (f(x1) - f(x0)) is used to update the guesses and obtain a new approximation, x2. The iteration continues until the approximation error, calculated as the absolute difference between x2 and x1 divided by x2, falls below the desired threshold (in this case, 0.001).

To compare the Secant method with the False-position method, you can apply both methods to the same function and compare their convergence and accuracy. You can also analyze the number of iterations required for each method to achieve a certain level of approximation error.

Please note that in order to generate graphs and screenshots with results, it would be best to run the code in a MATLAB environment and visualize the results directly.

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51.1% of the qualified applicants were accepted into the magnet school programs, 15.4% were waitlisted, and 33.5% were turned away due to a lack of space.

To find the relative frequency for each decision made by the school district's magnet school programs, we need to divide the number of applicants for each decision by the total number of qualified applicants.

Accepted applicants: 986 / 1928 = 0.511 or 51.1%

Waitlisted applicants: 297 / 1928 = 0.154 or 15.4%

Turned away applicants: 645 / 1928 = 0.335 or 33.5%

In summary, 51.1% of the qualified applicants were accepted into the magnet school programs, 15.4% were waitlisted, and 33.5% were turned away due to a lack of space.

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Answer:

Answer is each large drink $1.25

Answer: It costs $1.25 for one large drink

Step-by-step explanation: 17.25-13.50=3.75   3.75/3=1.25

Answer:

Mango = 0.5, Peach = 1.75

Step-by-step explanation:

Let x represent the price of mango

Let y represent the price of peach

Melanie: 8x + 6y = 14.50

Jaya: 4x + 7y = 14.25

Isolate for a variable in one of the equations (just pick a random one, you don't have to pick mine)

4x + 7y = 14.25 => x = (14.25 - 7y)/4 = 3.5625 - 7/4y

Plug into other equation

8x + 6y = 14.50

8(3.5625 - 7/4y) + 6y = 14.5

28.5 - 14y + 6y = 14.5

28.5 - 14.5 = 14y - 6y

14 = 8y

y = 1.75

4x + 7y = 14.25

4x + 7(1.75) = 14.25

4x + 12.25 = 14.25

4x = 2

x = 0.5

The probability sum of the dice is 2/11.

Let A be the event that the sum of dots is 5, then

A={(1,4), (2,3), (3,2), (4,1)}

n(A)=4

And, B is the event that one die shows a "one"

B={(1,1), (1,2), (1,3), (1,4), (1,5), (1,6), (2,1), (3,1), (4,1), (5,1), (6,1)}

n(B)=11

The Event that some of the dots are five and one of the die shows "one".

A intersection B = {(1,4), (4,1)}

Since n(A) = 36 (thirty-six possible samples of two dice)

P(A)=4/36

P(B)=11/36

P(A intersection B)=2/36

So, the required probability is

P(A|B)=P(A intersection B)/P(B) =2/11

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Answer:

A linear equation has the greatest x power at 1.

If you see an equation with only x (no x^2 or x^3 or stuff like that), you will know that it is linear.