Gigi is planning to pursue her dream to be a successful human resource manager working for multinational company and she wants to do her full-time degree in Malaysia. You as a cousin, needs to assist Gigi to shortlist at least 4 institutions of higher learning (IHLs) which is offering human resource related degree programs. List down all the assumptions/values/methods and references used to solve the following questions. a. Identify the key variables such as duration, tuition fees, ranking of the IHL, starting pay of the fresh graduate etc for the shortlisting of the IHLs and tabulated it into a table. (7 marks) b. Show how you can apply the statistical toolpak and probability toolpak in EXCEL for the data analysis and draw meaningful conclusions based on the data that you have collected in part (a). You need to compare the EXCEL result with manual calculation. Refer to your own significant findings, suggest to Gigi which IHL is most suitable for her and justify your suggestion. Appendix A (Fill up the empty column) No Brand 1 A 2 A 3 A 4 A 5 A 6 A 7 A A A A B B B B 8 B 8 B B B C C С C C с C C C C D D 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 59 60 ه هاهاهاهاهاهاها D D D D D D D D Sugar content (g/100g) 13.5 14.7 15.7 18.0 22.5 24.2 17.0 14.0 15.0 19.0 15.2 15.5 17.8 17.0 18.0 25.0 21.2 23.4 22.0 16.0 15.0 16.0 18.0 19.0 26.5 21.5 22.5 14.0 25.0 16.5 19.0 14.5 15.5 16.8 17.5 19.5 20.5 22.0 22.5 23.0 Question 1: Ginny is working as a chemist for a food manufacturing company. She is tasked to perform a sugar content analysis on the 4 types of company products - biscuit brand A, B, C and D. She has completed the sugar content analysis in the 60 biscuits (15 for each brand) and tabulated in Table Q1 as shown in Appendix A. List down all methods/assumptions/values used to solve the following questions. a. Complete the Table Q1 which consists of 60 biscuits details and use EXCEL to draw a graph for sugar content comparison in 4 different brands and draw conclusion b. Refer to part (a) Table Q1, use EXCEL to calculate the average sugar content and standard deviation for the brand A biscuit. If the sugar contents are normally distributed, calculate the probability that a randomly selected brand A biscuit will have sugar content smaller than 19g/100g. Repeat the same calculation for brand B. Compare the answers with manual calculation and draw conclusions. c. Refer to part (a) Table Q1, the company has decided to reject any biscuit with sugar content greater than 20g/100g. Use EXCEL to calculate the probability that a randomly selected 30 biscuits will have the following: (i) Exactly 18 good biscuits. (ii) At least 20 good biscuits. Compare the answer(s) with manual calculation and draw conclusion(s).

Answer: 240.9 Kpa

Explanation:

Let first changes pressure Gage B from mm of mercury to KPa. That is,

254mm of mercury = 33.86KPa.

To calculate the pressure at C, we need to consider the atmospheric pressure and calculate the absolute pressure of the tank compartment

At gage C, the reading will read P1– P2

Where P1 = absolute pressure

Give that the pressure at B = 254 mm Hg

But (101.33/760) = 33.87 kPa

Where 101.33 = atmospheric pressure

Therefore,

P2 = 101 - 33.87 = 67.13 kPa

P2 = Pa ( pressure at A

Absolute P1 = Patm + Pa= 101 + 207 = 308 kPa abs.

Therefore, Pc = 308 - 67.13

Pc = 240.9Kpa

Therefore, gage C will read 240.9 Kpa if it is connected to compartment 1 but inside compartment 2

The business application that uses passive (no power source) electronic tags and labels to identify objects wirelessly over short distances (up to 20 feet) is radio-frequency identification (RFID).

RFID (radio-frequency identification) is a system that employs passive (no power source) electronic tags and labels to identify objects wirelessly over short distances (up to 20 feet).

The tags contain data that is transmitted by a reader that is also called a radio-frequency identification interrogator or transceiver.

An RFID tag is placed on the object to be identified, and when it comes into range of the reader, the reader sends a signal that activates the tag.

After that, the tag responds by transmitting the data encoded in its memory.

This data can include identification, status, location, and other information related to the object.

A conclusion may be that the radio-frequency identification (RFID) is an advanced technology that has been developed to improve the accuracy and efficiency of data collection and management.

It can be used in a variety of business applications, such as inventory management, supply chain management, and asset tracking.

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Answer:

actually, it was John Doe and Jane Doe, as they were created as testers on the exact same say when Roblox was created.

Explanation:

The first  player was builderman. Option C

The first player was one whose user handle was builderman.

However, the account was terminated. It was replaced with

‘Builderman’ is the account that belonged to the CEO and Co-Founder of , David Baszucki. He manages all of the admins.

When you make a new account, he's automatically your friend.

Note that ‘John Doe’ and ‘Jane Doe’ were two test accounts that were created by David.

The accounts were later rumored to hack others’

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In the radio communication system, multipath is the propagation phenomenon that causes diffusion or reflection in multiple different directions of a signal.

Multipath is a propagation mechanism that impacts the propagation of signals in radio communication. Multipath results in the transmission of data to the receiving antenna by two or more paths. Diffusion and reflection are the causes that create multiple paths for the signal to be delivered.

Diffraction occurs when a signal bends around sharp corners; while reflection occurs when a signal impinges on a smooth object. When a signal is received through more than one path because of the diffraction or reflection, it creates phase shifting and interference of the signal.

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Higher costs imposed on speculators to participate in energy markets could lead to a reduction in liquidity and trading volume.

This decline would reduce the influence that speculation has over oil and gas futures prices, as previously highlighted.

As it stands in this particular instance, buyers utilizing hedging strategies within the market for oil derivatives are net long: positioning with contracts designed to mitigate the risk of future price increases. Conversely, sellers involved in hedging activities in the gas derivatives sector maintain a net short position- offsetting prospective losses from declining prices.

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a)  The initial and final temprature are 99.61°C and T3 = 259.07°C

b)   The mass of liquid water when the piston first start moving is 0g

Using the data provided:

Initial Pressure = P1 = 125kPa

Mass of Saturated Vapor Liquid = m = 5kg

Initial Mass of Liquid water = mf = 2kg

Initial Mass of Vapor = mg = 3kg

The temperature for a mixture of liquid steam saturated with water according to the thermodynamic table is:

T₁ = 99.61°C

The specific volume is:

vf = 0.001043m³/kg

And the saturated volume is:

vg = 1.6941m³/kg

Therefore, the volume in state 1 will be equal to:

V1 = mfvf + mgvg

V1 = (2kg)(0.001043m³/kg) + (3kg)(1.6941m³/kg)

V1 = 5.084m³

In state 3 then the volume will be equal to:

V3 = 1.2V1

V3 = 1.2(5.084m³)

V3 = 6.1008m³

Then the specific volume will be equal to:

v3 = V₃/m

v3 = 6.1008m³/5kg

v3 = 1.2202m³/kg

For a pressure of 300 kPa and the previous specific volume found through the thermodynamic table, the value of the temperature is:

T3 = 259.07°C

Question b) When the piston first stats moving at P₂ = 300kPa and V₂ = V₁ = 5.084m³

v₂ =V₂/m

v₂ = 5.084m³/5kg

v2 = 1.0168m³/kg

While at 300 kPa the value of the vapor saturated vg = 0.88578m³/kg This implies that the condition is met:

v2 > vg

Therefore, no liquid is there in-cylinder when piston stats moving, mf = 0kg

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All the following methods have proven to be useful techniques to help project teams identify the risks that might impact the project, except documenting lessons learned.

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The two options are based on the "rule of thumb" that a rotor should have at least.030 inches of material left on it in order to be machined.

When a thicker area of the brake rotor rotates through the calliper, it pushes back against brake fluid, which can be felt at the brake pedal, causing brake pedal pulsation and other circumstances like steering-wheel shaking while braking.

Although metallic brake lines are also available, brake lines are often constructed of rubber or a rubber and synthetic material combination. Their length and diameter vary.

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Answer:

-Computer going blank .

-Mouse pointer freezing.

-Keyboard getting stuck.

Explanation:

Any problems with the computer related to its hardware will consist of issues directly related to the physical components of the PC or computer. So any problem involving the physical component of the computer, then it can be termed as a hardware problem.

Based on the problems given in the option, the hardware issues will be problems with the computer, mouse, and keyboard. These form the physical parts of the computer so they will be a hardware issue.

Thus, the correct answers are the third, fourth, and fifth options.

Answer:

c d e

Explanation:

The total rate of energy emission is 2786.9 W.

Radiation is a type of heat transfer where the heat energy is conveyed from photons or electromagnetic waves.  The rate of energy emission can be calculated multiplying the Stefan–Boltzmann law (σ\(*T^4\)) by area (A). Therefore, you have:

Total Rate of Energy Emission (E)= σ\(*A*T^4\), where:

σ = Stefan–Boltzmann constant = \(5.67*10^{-8}\) \(\frac{W}{m^2K^4}\)

A= area

T=temperature (K)

For solving this exercise, you should apply this formula. For your question:

σ = Stefan–Boltzmann constant = \(5.67*10^{-8}\) \(\frac{W}{m^2K^4}\)

A= 0.12 m²

T=527+273=800 K

Thus, the Total Rate of Energy Emission (E) will be:

E=σ\(*A*T^4\)

\(E=(5.67*10^{-8}\frac{W}{m^2K^4})*(0.12*m^{2} )*(800K)\\ \\ E=2786.9 W\)

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Answer:

When are resistors in series? Resistors are in series whenever the flow of charge, called the current, must flow through devices sequentially. For example, if current flows through a person holding a screwdriver and into the Earth, then  

R

1

 in Figure 1(a) could be the resistance of the screwdriver’s shaft,  

R

2

 the resistance of its handle,  

R

3

 the person’s body resistance, and  

R

4

 the resistance of her shoes.

Figure 2 shows resistors in series connected to a voltage source. It seems reasonable that the total resistance is the sum of the individual resistances, considering that the current has to pass through each resistor in sequence. (This fact would be an advantage to a person wishing to avoid an electrical shock, who could reduce the current by wearing high-resistance rubber-soled shoes. It could be a disadvantage if one of the resistances were a faulty high-resistance cord to an appliance that would reduce the operating current.)

Two electrical circuits are compared. The first one has three resistors, R sub one, R sub two, and R sub three, connected in series with a voltage source V to form a closed circuit. The first circuit is equivalent to the second circuit, which has a single resistor R sub s connected to a voltage source V. Both circuits carry a current I, which starts from the positive end of the voltage source and moves in a clockwise direction around the circuit.

Figure 2. Three resistors connected in series to a battery (left) and the equivalent single or series resistance (right).

To verify that resistances in series do indeed add, let us consider the loss of electrical power, called a voltage drop, in each resistor in Figure 2.

According to Ohm’s law, the voltage drop,  

V

, across a resistor when a current flows through it is calculated using the equation  

V

=

I

R

, where  

I

 equals the current in amps (A) and  

R

 is the resistance in ohms  

(

Ω

)

. Another way to think of this is that  

V

 is the voltage necessary to make a current  

I

 flow through a resistance  

R

.

So the voltage drop across  

R

1

 is  

V

1

=

I

R

1

, that across  

R

2

 is  

V

2

=

I

R

2

, and that across  

R

3

 is  

V

3

=

I

R

3

. The sum of these voltages equals the voltage output of the source; that is,

V

=

V

1

+

V

2

+

V

3

.

This equation is based on the conservation of energy and conservation of charge. Electrical potential energy can be described by the equation  

P

E

=

q

V

, where  

q

 is the electric charge and  

V

 is the voltage. Thus the energy supplied by the source is  

q

V

, while that dissipated by the resistors is

q

V

1

+

q

V

2

+

q

V

3

.

Explanation:

(a) The heating requirement for this process is 2.95 x 10⁶ kW

(b) The given benzene analyses are not consistent with each other.

(a) To calculate the heating requirement for this process, we need to determine the heat that must be supplied to the evaporator to vaporize the liquid stream and heat the vapor to the outlet temperature of 95.0°C. We can use the following energy balance:

Q = m(L)v + m(V)h

where Q is the heat required, m(L) and m(V) are the mass flow rates of the liquid and vapor streams, respectively, and v and h are the specific volumes and enthalpies of the liquid and vapor streams, respectively.

To convert the given mole fractions to mass fractions, we need to use the molecular weights of benzene and toluene:

MW_benzene = 78.11 g/mol

MW_toluene = 92.14 g/mol

The mass fraction of benzene in the liquid stream is:

y_B = 0.50

M_B = y_B x MW_benzene / ((1 - y_B) x MW_toluene + y_B x MW_benzene) = 0.436

Similarly, the mass fraction of benzene in the liquid outlet stream is:

x_B = 0.425

M_B = x_B (MW_benzene) / ((1 - x_B)  MW_toluene + x_B ( MW_benzene) = 0.378

And the mass fraction of benzene in the vapor stream is:

z_B = 0.735

M_B = z_B x MW_benzene / ((1 - z_B) x MW_toluene + z_B x MW_benzene) = 0.532

Now we can use Raoult's law to relate the vapor pressures of benzene and toluene in the liquid and vapor streams:

P_B = y_B x P°_B

P_T = (1 - y_B) x P°_T

P'_B = z_B x P°_B'

P'_T = (1 - z_B) x P°_T'

where P°_B and P°_T are the vapor pressures of pure benzene and toluene at 25°C, and P°_B' and P°_T' are the vapor pressures of pure benzene and toluene at 95°C. We can look up these values in a reference table:

P°_B = 12.7 kPa

P°_T = 3.8 kPa

P°_B' = 95.4 kPa

P°_T' = 12.6 kPa

Substituting these values and solving for the vapor pressure of benzene in the liquid and vapor streams, we get:

P_B = 6.35 kPa

P'_B = 50.80 kPa

Now we can calculate the mass flow rates of the liquid and vapor streams:

m(L) = 1320 / (1 + V/L)

m(V) = 1320 - m(L)

where V/L is the ratio of the vapor flow rate to the liquid flow rate, which we can calculate from the vapor-liquid equilibrium relation:

V/L = z_B / (y_B - z_B) = 1.53

Substituting these values and the specific volumes and enthalpies of benzene and toluene, which we can look up in a reference table, we get:

v_L = 0.001319 m³/mol

v_V = 0.03147 m³/mol

h_L = -15702 J/mol

h_V = -11006 J/mol

Q = m(L)v_L(h_V - h_L) + m(V)h_V

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Answer:

Please report my answer

Explanation:

I want my account deleted

Answer:

a) 0.42

b) Independent

c) 30%

d) 0.88

Explanation:

Person chooses Chicken's item : 70% = 0.7

Person chooses fish's item : 30% = 0.3

Visits in which he orders Afghani Chicken = 60% = 0.6

a) Probability that he goes to KARIM and orders Afghani Chicken:

P = 0.7 * 0.6 = 0.42

b) Two events are said to be independent when occurrence of one event does not affect the probability of the other event's occurrence. Here the person orders Afghani Chicken regardless of where he visits so the events are independent.

c)  P = 0.30 because he orders Afghani Chicken regardless of where he visits.

d)  Let A be the probability that he goes to KARIM:

P(A) = 0.7 * ( 1 - 0.6 ) = 0.28

Let A be the probability that he orders Afghani Chicken:

P(B) =  0.3 * 0.6 = 0.18

Let C be the probability that he goes to KARIM and orders Afghani chicken:

= 0.7 * 0.6 = 0.42

So probability that he goes to KARIM or orders Afghani Chicken or both:

P(A) + P(B) + P(C) = 0.28 + 0.18 + 0.42 = 0.88

The given statement "The adult population can be calculated by adding the labor force and not in the labor force together" is true because the adult population refers to the number of people in a particular region or country who are eligible for voting.

This demographic includes all individuals who are legally eligible to cast their ballot in any given election. To determine the adult population, it's important to note that not all adults are in the labor force. Some individuals may be out of work and not actively seeking employment, which means they are not included in the labor force.

Similarly, those who are not working due to disability or other reasons are also not included in the labor force. The adult population can be calculated by adding the labor force and not the labor force together. The labor force is the number of individuals who are employed or actively seeking employment. Those who are not in the labor force include retirees, stay-at-home parents, and individuals who are unable to work due to disability or other reasons.

So, adding the labor force and not in the labor force together can give us the total adult population of a particular region or country.

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Evaluation is the methodical determination of a subject's validity, worth, and relevance using standards-based criteria.

Thus, It can help an organization, program, design, project, or any other intervention or initiative evaluate any goal, realizable concept or proposal, or any alternative, to aid in decision-making; or to determine the level of achievement or value in relation to the goal and objectives, as well as the outcomes of any such action that has been taken.

In addition to providing insight into past or current projects, evaluation's main goal is to promote introspection and help identify potential areas for future improvement.

In a variety of human endeavours, such as the arts, criminal justice, and other fields, evaluation is frequently used to describe and evaluate topics of interest.

Thus, Evaluation is the methodical determination of a subject's validity, worth, and relevance using standards-based criteria.

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It's important to note that this speed difference is only noticeable for large programs. For small programs, the difference is negligible.

1. Shortcut operators are faster than the conventional arithmetic operators: This statement is true. Shortcut operators are faster because they combine arithmetic operations with variable assignments in a single statement. For example, instead of writing "a = a + 2", you can write "a += 2". This saves time and reduces the amount of code you need to write. However, it's important to note that this speed difference is only noticeable for large programs or when dealing with complex calculations. For small programs, the difference is negligible.
2. You can declare more than one variable in a single line: This statement is also true. In many programming languages, you can declare and initialize multiple variables on the same line. For example, instead of writing "int a; int b; int c;", you can write "int a, b, c;". This saves space and makes your code more concise. However, it's important to note that you should only do this if the variables are related and have the same data type.
3. You must use else after every if statement: This statement is false. It's not necessary to use else after every if statement. You can use if statements on their own if you don't need to execute any code if the condition is not true. However, if you need to execute code in both cases (true and false), then you should use else. It's also important to note that you can use else if to test for additional conditions if the first if statement is not true.

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Promotion is any form of communication that a business uses to inform, persuade, or remind potential customers about their products. The goal is to raise awareness, draw attention to, and encourage consumers to purchase the product over competing options.

All of the activities that inform consumers about a product, brand, or service are referred to as promotions.

Companies communicate about sales promotions through a variety of media, including printed materials like posters, coupons, direct mail pieces, and billboards; radio and television commercials; and digital media like text messaging, email, websites, and social media, among others.

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Huffman encoding's longest codeword is n-1 bits long. For instance, f i = 2(i-1)/2n.

The length of the longest codeword is n 1. This number is obtained by encoding n symbols, where n 2 of them have probabilities of 1/2,1/4,...,1/2n-2, and two of them have probabilities of 1/2n-1. Never can a codeword be longer than length n 1.

The longest code, or the maximum depth, is 255.ac if by "all bytes" you mean the 256 potential byte values that can be used as symbols.

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It is to be noted that all UHRS platforms are optimized for the popular kinds of internet browser applications.

The Universal Human Relevance System (UHRS) is a crowdsourcing platform that allows for data labeling for a variety of AI application situations.

Vendor partners link people referred to as "judges" to offer data labeling at scale for us. All UHRS judges are bound by an NDA, ensuring that data is kept protected.

A browser is a software tool that allows you to see and interact with all of the knowledgeon the World Wide Web. Web sites, movies, and photos are all examples of this.

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Answer:

I think it is the 2,3,5 and 1 ones

Answer:

byee byee bbbbbbbbbbbb

Answer:

a) 397.89 ohm

b) attached below

c) 0.707  as a ratio

Gain in dB = 20 log 0.707 = -3 dB

d)  0.8087

Gain in dB = 20 log \(|\frac{Vout}{Vin}|\) = -1.844 dB

Explanation:

A) Find the appropriate resistor

c = 0.01 uf

fc = 40 kHz

cut-off frequency ; fo = \(\frac{1}{2\pi RC }\)

from the above equation  R = \(\frac{1}{2\pi foC}\)  = 397.89 ohm

B) sketch of the circuit  is attached

C) The gain of the filter at the cutoff frequency

fc = 40 kHz,  

C = 0.01 uF ⇒ \(\frac{-j}{2\pi foC }\) =  -j 397.89

Vout = Vin * ( R / R- C )

Vout = Vin * ( 397.89 / (397.89 - j 397.89))

Vout = \(\frac{1}{\sqrt{2} }\)  Vin ∠45⁰

therefore gain = |\(\frac{Vout}{Vin }\)| = \(\frac{1}{\sqrt{2} }\) = 0.707  as a ratio

Gain in dB = 20 log 0.707 = -3 dB

D) Gain of filter at 55 kHz

c = 0.01 uF =  \(\frac{-J}{2\pi foC }\) =  -j 289.373 ohms

Vout = Vin * \(\frac{R}{R-C}\)  

        = Vin * ( 397.89 / ( 397.89 - j 289.373))

Gain in ratio \(|\frac{Vout}{Vin}|\) = 0.8087 ∠ 36.03⁰

therefore gain in ratio = 0.8087

Gain in dB = 20 log \(|\frac{Vout}{Vin}|\) = -1.844 dB

Answer:

E = 8.83 kips

Explanation:

First, we determine the stress on the rod:

\(\sigma = \frac{F}{A}\\\\\)

where,

σ = stress = ?

F = Force Applied = 1300 lb

A = Cross-sectional Area of rod = 0.5\(\pi \frac{d^2}{4} = \pi \frac{(0.5\ in)^2}{4} = 0.1963\ in^2\)

Therefore,

\(\sigma = \frac{1300\ lb}{0.1963\ in^2} \\\\\sigma = 6.62\ kips\)

Now, we determine the strain:

\(strain = \epsilon = \frac{elongation}{original\ length} \\\\\epsilon = \frac{0.009\ in}{12\ in}\\\\\epsilon = 7.5\ x\ 10^{-4}\)

Now, the modulus of elasticity (E) is given as:

\(E = \frac{\sigma}{\epsilon}\\\\E = \frac{6.62\ kips}{7.5\ x\ 10^{-4}}\)

E = 8.83 kips

The speed of a sound wave can be calculated using the formula:Speed (v) = Frequency (f) × Wavelength (λ)Given that the frequency of the musical tone is 410 Hz (cycles per second) and

The speed of the sound wave is 328 m/s. This is calculated by multiplying the frequency (410 Hz) by the wavelength (0.80 m) using the formula for wave speed. The frequency represents the number of cycles per second, and the wavelength is the distance between two corresponding points on the wave. Multiplying these values gives the distance traveled by the wave per second. In this case, the sound wave travels at a speed of 328 meters per second. The speed of sound in air is approximately 343 m/s, so the given value of 328 m/s falls within the expected range.

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a. When you pass a constant DC current through an inductor, the inductor will resist the change in current and create a magnetic field. This magnetic field will increase over time, causing the inductor to store energy in the form of magnetic potential energy.

b. When you pass an AC current through an inductor, the inductor will still resist the change in current and create a magnetic field. However, the direction of the current in the AC signal will alternate, causing the magnetic field to constantly increase and decrease. This will result in the inductor storing energy during one half of the AC cycle and releasing it during the other half.

c. If a current existed near the inductor, the inductor would respond by inducing a voltage in the nearby circuit. This is because the magnetic field produced by the inductor will interact with the current in the nearby circuit, causing a change in voltage.

d. One experiment you could perform to test these answers would be to set up a simple circuit with an inductor and a resistor. Then, you could pass a constant DC current through the circuit and measure the voltage across the inductor. Next, you could pass an AC current through the circuit and measure the voltage across the inductor again. Finally, you could introduce a nearby current and observe the effect on the voltage across the inductor. By comparing the results of these tests, you could confirm the behavior of the inductor in different situations.

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As the percent of theoretical air increases, the adiabatic flame temperature also increases. This is because more air means more oxygen is available for the combustion reaction, which allows the reaction to proceed more efficiently and release more heat. This increase in heat causes the temperature of the gas to rise.

An adiabatic flame temperature is the temperature reached by a gas as it undergoes a chemical reaction, such as combustion, in an insulated environment where no heat is lost to the surroundings. In this case, the adiabatic flame temperature of propane gas burning with air can be plotted versus the percent of theoretical air, which is the amount of air required for complete combustion of the fuel.

At a percent of theoretical air of 120%, the adiabatic flame temperature is 2125 K. This temperature will continue to rise as the percent of theoretical air is increased further.

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Answer: The velocity of a motor cyclist who travelled a distance of 200 m in 10 seconds is 20 m/sec.

Explanation:

Given: Distance = 200 m

Time = 10 seconds

Formula used to calculate velocity is as follows.

\(Velocity = \frac{Distance}{Time}\)

Substitute the value into above formula as follows.

\(Velocity = \frac{Distance}{Time}\\= \frac{200 m}{10 sec}\\= 20 m/sec\)

Thus, we can conclude that the velocity of a motor cyclist who travelled a distance of 200 m in 10 seconds is 20 m/sec.