Gina put all the boxes weighing less than 1/2 pound into a small box she puts all the boxes by more than 1/2 pound into a large box how many pounds heavier are the blocks in a large box than pounds in a small box

The eigenvectors v1 and v2 are such that when multiplied by matrix A, they result in scalar multiples of themselves (scaled by their respective eigenvalues).

An eigenvector is a non-zero vector that, when multiplied by a matrix, results in a scalar multiple of itself. In other words, if A is a square matrix and v is an eigenvector of A, then Av = λv, where λ is the eigenvalue associated with v.

Given the eigenvalues and eigenvectors for matrix A as λ1 = 2, v1 = [-5 1]ᵀ and λ2 = 6, v2 = [5 4]ᵀ, we can say that:

- Av1 = λ1v1 = 2[-5 1]ᵀ = [-10 2]ᵀ
- Av2 = λ2v2 = 6[5 4]ᵀ = [30 24]ᵀ

Therefore, the eigenvectors v1 and v2 are such that when multiplied by matrix A, they result in scalar multiples of themselves (scaled by their respective eigenvalues).

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To fill in the missing values in the ANOVA summary table, we need to calculate the values based on the given information.

The missing values are:

To calculate the missing values:

1. S.S. (Sum of Squares) for Between:

Since the total S.S. is given as 27 and the S.S. for Within is 2461, we can subtract the Within S.S. from the Total S.S. to obtain the S.S. for Between:

S.S. Between = Total S.S. - Within S.S. = 27 - 2461 = -2434

2. D.F. (Degrees of Freedom) for Between:

The D.F. for Between is equal to the number of groups minus 1. The number of groups is not provided in the table, so we cannot determine the D.F. for Between.

3. F (F-value):

The F-value can be calculated by dividing the M.S. for Between by the M.S. for Within:

F = M.S. Between / M.S. Within = 1.256 / 107 = 0.0118 (rounded to 4 decimal places)

To locate the p-value for this ANOVA, we can use statistical software such as Excel or R. In Excel, we can use the FDIST(∙) function, while in R, we can use the pf(∙) function.

Using Excel:

p-value = 1 - FDIST(F, D.F. Between, D.F. Within) = 1 - FDIST(0.0118, D.F. Between, 107)

Using R:

p-value = 1 - pf(F, D.F. Between, D.F. Within, lower.tail = TRUE) = 1 - pf(0.0118, D.F. Between, 107, lower.tail = TRUE)

Since the Degrees of Freedom for Between is not provided, we cannot calculate the p-value accurately. The p-value depends on the specific Degrees of Freedom for Between.

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The standard form of 3x² - 9x + 2 is 3x² - 9x + 2.

A polynomial function with one or more variables, where the largest exponent of the variable is two, is referred to as a quadratic function. In other terms, a "polynomial function of degree 2" is a quadratic function.

Given:

A quadratic function,

3x² - 9x + 2.

The standard form of the quadratic function is

ax² + bx + c.

The standard form of 3x² - 9x + 2 is 3x² - 9x + 2.

Therefore, 3x² - 9x + 2.

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Answer:

0.56

Step-by-step explanation:

Answer:

14/25

Step-by-step explanation:

Because you cant divide both of them by the same number.

Answer: Research

Step-by-step explanation:

On the slide when the child is in motion as they are sliding down comes to dynamic equilibrium.

As given,

Therefore, as a child is in motion as they are sliding down and comes to dynamic equilibrium.

The complete question is:

A child is on a playground they start to slide down a large slide. At what point is the child in dynamic equilibrium with the slide?(1 point)

A. When the child pushes themselves down the slides.

B. As the child is in motion as they are sliding down.

C. When the slide ends and the child has stopped moving .

D. The child will not reach dynamic equilibrium.

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Yolanda earned $20.00 in tips, making her final pay for the week as $159.50

An equation is an expression that shows the relationship between two or more numbers and variables using mathematical operations. An equation can be linear, quadratic, cubic and so on, depending on the degree of the variable.

Yolanda makes $11.25 per hour at her part-time job. During one week, she worked 12 2/5 hours

12 2/5 hours = 62/5 hours

Money earned = $11.25 per hour * 62/5 hours = $139.50

she also earned some tips to get $159.50

Tips = $159.50 - $139.50 = $20.00

Yolanda earned $20.00 in tips

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Answer:

I THINK A

Step-by-step explanation:

a. The price of the consol is approximately $133.33.

b. The new price of the consol would be $100. The price of the consol falls by 24.99% and the interest rate rises by 1%.

c. Your holding period return is approximately -49.99%.

a. The price of the consol can be calculated using the formula for the present value of a perpetuity:

Price = Annual Payment / Interest Rate

In this case, the annual payment is $4 and the interest rate is 3%. Substituting these values into the formula:

Price = $4 / 0.03 ≈ $133.33

Therefore, the price of the consol is approximately $133.33.

b. To calculate the new price of the consol if the interest rate rises to 4%, we use the same formula:

New Price = Annual Payment / New Interest Rate

Substituting the values, we get:

New Price = $4 / 0.04 = $100

The percentage change in the price of the consol can be calculated using the formula:

Percentage Change = (New Price - Old Price) / Old Price * 100

Substituting the values, we have:

Percentage Change in Price = ($100 - $133.33) / $133.33 * 100 ≈ -24.99%

The percentage change in the interest rate is simply the difference between the old and new interest rates:

Percentage Change in Interest Rate = (4% - 3%) = 1%

Comparing the two percentages, we can see that the price of the consol falls by approximately 24.99%, while the interest rate rises by 1%.

c. The holding period return can be calculated using the formula:

Holding Period Return = (Ending Value - Initial Value) / Initial Value * 100

The initial value is the purchase price of the consol, which is $133.33, and the ending value is the price of the consol after one year with an interest rate of 6%. Using the formula for the present value of a perpetuity, we can calculate the ending value:

Ending Value = Annual Payment / Interest Rate = $4 / 0.06 = $66.67

Substituting the values into the holding period return formula:

Holding Period Return = ($66.67 - $133.33) / $133.33 * 100 ≈ -49.99%

Therefore, the holding period return is approximately -49.99%.

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Answer:

−7.25x−10.4

Step-by-step explanation:

Let's simplify step-by-step.

−0.75x−5−(6.5x+5.4)

Distribute the Negative Sign:

=−0.75x−5+−1(6.5x+5.4)

=−0.75x+−5+−1(6.5x)+(−1)(5.4)

=−0.75x+−5+−6.5x+−5.4

Combine Like Terms:

=−0.75x+−5+−6.5x+−5.4

=(−0.75x+−6.5x)+(−5+−5.4)

=−7.25x+−10.4

Now we can take the limit as h approaches 0:

f'(x) = [-4/(2√(1-x)))²]/(2√(1-x))f'(x) = -2/(1-x)³/²

First principles of differentiation is a method used in calculus to find the derivative of a function. It involves taking the limit as the difference in x approaches zero.

Finally, we take the limit as h approaches 0:

f'(x) = 6x - 4(b) f(x) = (2x + 1)/(x + 3)f'(x) = lim(h→0) (f(x+h) - f(x))/hSubstitute f(x+h)

and f(x) in the formula:

f'(x) = lim(h→0) [(2(x+h)+1)/(x+h+3) - (2x+1)/(x+3)]/h

Simplify the expression inside the limit:

f'(x) = lim(h→0) [(2x+2h+1)(x+3) - (2x+1)(x+h+3)]/h(x+h+3)(x+3)

Next, expand and simplify the numerator:

f'(x) = lim(h→0) [2x² + 6x + 2hx + xh + 6h + h - 2x² - 2hx - 3x - 9]/h(x+h+3)(x+3)

We can then cancel out terms:

f'(x) = lim(h→0) [6h - 3x - 9]/h(x+h+3)(x+3)

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The given scenario does not describe a binomial experiment. The reason is that a binomial experiment must satisfy four conditions: fixed number of trials, two possible outcomes, independent trials, and constant probability of success.

In this case, the number of trials is not fixed since two cards are selected without replacement from a standard deck. The number of outcomes for each trial is not limited to two because it depends on the number of kings selected, which can vary. Therefore, the scenario does not meet the requirements for a binomial experiment.

Additionally, the independence of trials is an important criterion for a binomial experiment. In this scenario, the selection of cards is not independent since the second card chosen depends on the outcome of the first card selection. Therefore, the correct answer is option b: not binomial; the number of trials has more than 2 outcomes.

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Answer:

The answer is y<17

Step-by-step explanation:

First, move the constant to the right.

3y<65-14

Then, subtract 65 and 14

3y<51

Lastly, divide both sides by 3.

y<17

172.16.0.0/20 is the required network address with a prefix if you need 16 subnets.

Given that,
If you require 16 subnets, your new network address with a prefix should be something different from the old one, which is 172.16.0.0/16. To determine the prefix corresponding to the 16 subnets.

Here,
Original network address with a prefix  = 172.16.0.0/16,
After 16 subnets the address would become,
New network address with the prefix with 16 subnets =  172.16.0.0/20.

172.16.0.0/20 is the required new address with prefix be if you need 16 subnets.

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The dimensions of the rectangle are 40 and 120m respectively.

Let the width = w

The length will be:

= 3 × w

= 3w

Perimeter = 320

Therefore, the dimensions will be:

= 2(3w + w) = 320

8w = 320

w = 320/8

w = 40

Length = 3 × 40

= 120

The dimensions of the rectangle are 40 and 120m respectively.

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To construct a 4x2 matrix D such that AD=I2, we can use the following matrix: D = [0 0 1 0; 0 0 0 1]. It is not possible for CA to be equal to 4 or 14 for any 4x2 matrix C.

Constructing a matrix D such that AD=I2

Let A = -1 be a 1x1 matrix. We want to construct a 4x2 matrix D such that their product AD is equal to the 2x2 identity matrix I2. We can use the following matrix for D:

D = [0 0 1 0; 0 0 0 1; 1 0 0 0; 0 1 0 0]

To verify that AD=I2, we can compute the matrix product:

AD = [-1 0 0 0; 0 -1 0 0] [0 0 1 0; 0 0 0 1; 1 0 0 0; 0 1 0 0]

= [0 0 -1 0; 0 0 0 -1]

= -I2

Note that D only uses 1 and 0 as entries.

Now, it is not possible for CA to be equal to 4 or 14 for any 4x2 matrix C. To see why, we can use the definition of matrix multiplication. Let C be a general 4x2 matrix:

C = [c11 c12; c21 c22; c31 c32; c41 c42]

Then, we can compute CA as:

CA = [-1 0; 0 -1] [c11 c12; c21 c22; c31 c32; c41 c42]

= [-c11 -c12; -c21 -c22; -c31 -c32; -c41 -c42]

Since CA is a 4x2 matrix and 4 is a scalar, it is not possible for CA to be equal to 4. Similarly, since the entries of C are only 0 or 1, it is not possible for CA to be equal to 14.

Therefore, there is no matrix C that satisfies the equations CA=4 or CA=14.

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Answer:

Number of pounds of cashews = x = 14.96 pounds

Number of pounds of Brazil nuts = y = 19.04 pounds

Step-by-step explanation:

Let us represent:

Number of pounds of cashews = x

Number of pounds of Brazil nuts = y

The nut shack sells cashews for $6.00 per pound and Brazil nuts for $5.00 per pound. How much of each type should be used to make a 34 pound mixture that sells for $5.44 per pound

Our system of equations is given as:

x + y = 34...... Equation 1

x = 34 - y

6x + 5y = 34 × 5.44

6x + 5y = 184.96.......Equation 2

Ww substitute : 34 - y for x in Equation 2

6(34 - y) + 5y = 184.96

204 - 6y + 5y = 184.96

Collect like terms

- 6y + 5y = 184.96 - 204

-y = -19.04

y = 19.04 pounds

Solving for x

x = 34 - y

x = 34 - 19.04

x = 14.96 pounds

Number of pounds of cashews = x = 14.96 pounds

Number of pounds of Brazil nuts = y = 19.04 pounds

Answer: -8.15

Step-by-step explanation:

Just do the

On solving the provided question, we can say that in rectangle W = 4.5 yd since we are unable to have a negative length. L = 2W + 1 = 10 yd

A rectangle in Euclidean plane geometry is a quadrilateral with four right angles. You might also describe it as follows: a quadrilateral that is equiangular, which indicates that all of its angles are equal. The parallelogram might also have a straight angle. Squares are rectangles with four equally sized sides. A quadrilateral of the shape of a rectangle has four 90-degree vertices and equal parallel sides. As a result, it is sometimes referred to as an equirectangular rectangle. Because its opposite sides are equal and parallel, a rectangle is also known as a parallelogram.

length  rectangle is 1 yd more than twice the width: L = 2*W + 1

e area of the rectangle

\(45 = L*W\\45 = (2W + 1)*W\\45 = 2W2 + W\\0 = 2W2 + W - 45\\\)

Factors

x\((2W-9)(W+5)\\W = 4.5 and -5\)

W = 4.5 yd since we are unable to have a negative length. L = 2W + 1 = 10 yd

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(1) $132,000 is the net income

(2) $66,000 total income

Selling price per unit:

= Sales ÷ No. of units

= $456,000 ÷ 5,700

= $80

Variable cost per unit:

= variable cost ÷ No. of units

= $102600 ÷ 5,700

= $18

Alternative 1:

Contribution margin = Sales - variable cost

                                 = (5,700 × $80 × 1.1) - (5,700 × $18)

                                 = $440,000 - $210,000

                                 = $230,000

Net income = Contribution margin - Fixed cost

                  =  $230,000 - $98,000

                  = $132,000

Alternative 2:

Contribution margin:

= sales - variable cost

= $456,000 - ($456,000 × 59%)

= $456,000 - $236,000

= $164,000

Net income = Contribution margin - Fixed cost

                  =  $164,000 - $98,000

                  = $66,000

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The given problem involves finding the value of a double integral over a specific region in the xy-plane. Double integrals are mathematical objects that are used to calculate the volume under a surface or the value of a function over a certain region in the plane. In this problem, we are asked to evaluate a double integral over the region R = {(x,y) | 0 ≤ x ≤ 3, 0 ≤ y ≤ 6-x/2}. To solve this problem, we need to set up the integrals in the appropriate order and limits of integration, and then evaluate them using the rules of integration. The concept of double integrals is an important tool in mathematics and has many applications in science, engineering, and economics. Double integrals are used to calculate the volume under a surface, the mass of an object, the center of mass of an object, and many other quantities. The ability to evaluate double integrals is an important skill for students of mathematics and has many practical applications, such as in calculating the volume of a tank or the work done by a force field. The study of double integrals is an essential part of mathematics and has many practical applications in science, engineering, and everyday life.

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∬ R (0.33)dA = ∫(0 to 16) ∫(0 to y) (0.33) dy dx
and
∬ R (0.33)dA = ∫(0 to 16) ∫(0 to y) (0.33) dx dy
These two integrals will help you evaluate the double integral over the region R.

The region R is described by the inequalities 0 ≤ y ≤ 16 and 0 ≤ x ≤ y.

To evaluate the double integral over the region R, we need to integrate with respect to the area (dA), which can be represented as dy dx or dx dy.

Considering the given bounds, the two integrals equivalent to the double integral over the region R are:

∬ R (0.33)dA = ∫(0 to 16) ∫(0 to y) (0.33) dy dx

and

∬ R (0.33)dA = ∫(0 to 16) ∫(0 to y) (0.33) dx dy

These two integrals will help you evaluate the double integral over the region R.

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Check the picture below.

let's firstly find side "t"

\(\textit{Law of Cosines}\\\\ c^2 = a^2+b^2-(2ab)\cos(C)\implies c = \sqrt{a^2+b^2-(2ab)\cos(C)} \\\\[-0.35em] ~\dotfill\\\\ t = \sqrt{18^2+46^2~-~2(18)(46)\cos(158^o)} \implies t = \sqrt{ 2440 - 1371168 \cos(158^o) } \\\\\\ t \approx \sqrt{ 2440 - (-1535.42) } \implies t \approx \sqrt{ 3975.42 } \implies t \approx 63.05 \\\\[-0.35em] ~\dotfill\)

\(\textit{Law of Sines} \\\\ \cfrac{\sin(\measuredangle A)}{a}=\cfrac{\sin(\measuredangle B)}{b}=\cfrac{\sin(\measuredangle C)}{c} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{\sin( R )}{18}\approx\cfrac{\sin( 158^o )}{63.05}\implies 63.05\sin(R)\approx18\sin(158^o) \\\\\\ \sin(R)\approx\cfrac{18\sin(158^o)}{63.05} \implies R\approx\sin^{-1}\left( ~~ \cfrac{18\sin( 158^o)}{63.05} ~~\right)\implies \boxed{R\approx 6.14^o}\)

Make sure your calculator is in Degree mode.

Answer:

Below.

Step-by-step explanation:

I can't see the words on your image very well but I can give you an explanation of the remainder theorem.

The theorem allows you to find the remainder of a division without doing the division itself.

You can find the remainder when  a polynomial is divided by a linear expression like 3x - 2, for example,  using this theorem.

An example will explain the method:

What is the remainder when x^3 - x^2 - 2x - 5 is divided by 2x - 1?

Put 2x - 1 = 0, this gives x = 0.5.

Now we plug x = 0.5 into the polynomial:

This = (0.5)^3 - (0.5)^2 -2(0.5) - 5 = -6.125

So the remainder is -6.125.

The formal definition is

The remainder when P(x) is divided by x - a is f(a).

Answer:

115

Step-by-step explanation:

<vur and <qru are corresponding angles

so they will both have the same angle even though they are not on the same line

The average rate of change over the interval [3,4] is given as follows:

3.

The average rate of change of a function is given by the change in the output divided by the change in the input.

The numeric values for the ends of the interval are given as follows:

Then the change in the output is of:

32 - 29 = 3.

The change in the input is of:

4 - 3 = 1.

Hence the rate is of:

r = 3/1

r = 3.

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Answer:.714

Step-by-step explanation:

divide 100 by 140

Answer:

0.085

Step-by-step explanation:

We know that 1/2=0.5. And to convert from percent to decimal you have to divide by 100.

Answer:

1. x ≤ 15

2. x +3 < 12

3. x/-2 ≥ 10

4. x - 4 ≥ -6

5. x/13 ≥ 1

6. x - 8 ≤ 5

7. 3 * x > -7

8. x/2 + 5 > 11

9. -6 + x ≤ 15

Hope this helps!

Answer:

Step-by-step explanation:

Ratios are no different from fractions. They are "comparisons" of 2 or more things. Instead of fraction bars, they use colons to separate 2 different things.

For example:

\(\frac{1}{2}\)\(=1:2\)

Now, let's do an example problem.

Ex: find the ratio of 5 cats to every dog.

We are comparing 5 cats to every 1 dog, so the ratio is:

\(5:1\)

Don't make thing more complicated to yourself, and don't overthink it. They are exactly like fractions. So treat them as such!