The conversion factor from electrino to coulombs is 1.60×10−19.
What is charge?The term charge refers to a particle that is positively or negatively charged. The electron is a particle that is negatively charged. One of the popular units that could be used when dealing with electrons is the electrinos.
We know that;
1 electrino = 1.60×10−19 C
It then follows that the conversion factor from electrino to coulombs is 1.60×10−19.
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zinc + hydrogen arsenate—>
What type of reaction is this? (Synthesis, Decomposition, or Single Replacement?
Answer:
Single Replacement
Explanation:
im just smart lol
Which plants have a fibrous root system? (Select all that apply.) grass dandelion carrot corn
The plants which have a fibrous root system are
GrassCornWhat is a fibrous root?A fibrous root system is a root system which consists of large mass of roots of nearly equal size
Some few examples of plants with fibrous roots system are as follows:
Rice plantsSugarcane plantsOnionsPinesAsparagusMaizeIn conclusion; the plants which have a fibrous root system are grasses and corns.
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How did Buddhism become a formal religion after the death of the Buddha?
Followers continued to share the Buddha's teachings.
Buddhism was replaced with Jainism.
The Buddha had written down his teachings in laws.
Asoka's religious intolerance allowed only one religion.
After the death of the Buddha, Buddhism became a formal religion through the efforts of his followers, who continued to spread his teachings and organized into communities known as sanghas. Over time, these sanghas developed a system of governance, with monastic councils, hierarchical structures, and formalized practices and rituals.
One key factor in the formalization of Buddhism was the development of the Tripitaka, a collection of the Buddha's teachings, which were written down in the Pali language and preserved by monastic communities. The Tripitaka contains three major sections: the Vinaya Pitaka, which outlines the rules and guidelines for monastic life; the Sutta Pitaka, which contains the Buddha's discourses on a wide range of topics; and the Abhidhamma Pitaka, which provides a detailed analysis of Buddhist psychology and philosophy.
The spread of Buddhism was also facilitated by the patronage of rulers such as Asoka, who supported the religion and helped to spread it throughout his empire. However, this support was not always consistent, and Buddhism faced periods of persecution and decline in various parts of the world. Despite these challenges, Buddhism has continued to evolve and adapt over the centuries, with different schools and traditions emerging in different regions. Today, Buddhism is practiced by millions of people around the world, and continues to offer a unique and powerful perspective on the nature of reality, the human condition, and the path to liberation.
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An empty graduated cylinder weighs 82.450 g. When filled to 50.0 mL with an
unknown liquid it weighs 110.810 g. What is the density of the unknown liquid?
Answer:
0.567 g/mL
Explanation:
First, we will find the mass of the liquid. Subtract the weight of the empty cylinder from the weight of the filled cylinder
110.81 - 82.45 = 28.36
The mass of the liquid is 28.36 g.
Now, we find the density by dividing the mass by volume
28.36/50 = 0.5672
The density of the unknown liquid is approximately 0.5672 grams per cubic centimeter.
Given that:
Weighs of empty graduated cylinder = 82.450 g
Mass of the graduated cylinder + unknown liquid = 110.810 g
Volume of the unknown liquid = 50.0 mL
The mass of the unknown liquid can be calculated as:
Mass of unknown liquid = Mass of graduated cylinder + unknown liquid - Initial mass of graduated cylinder
Mass of unknown liquid = 110.810 g - 82.450 g
Mass of unknown liquid = 28.360 g
The density formula can be obtained as:
\(Density = \dfrac{Mass}{Volume}\)
Substitute the values in the formula:
\(Density = \dfrac{28.360 g}{50.0 mL}\)
The volume is given in milliliters (mL)
1 mL = 1 cm³,
\(Density = \dfrac{28.360 g}{50.0 cm^3 }\)
Density = 0.5672 \(\dfrac {g}{cm^3}\)
So, the density of the unknown liquid is approximately 0.5672 grams per cubic centimeter (g/cm³).
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TNT has relatively small energy per pound. However, it is a very effective explosive. Why?
TNT (Trinitrotoluene) has relatively small energy per pound, but it is a very effective explosive due to the following reasons:
1. It is an insensitive explosive: TNT has a high ignition temperature, making it less prone to accidental detonation. TNT can also resist shock and friction, making it a stable explosive.
2. High detonation velocity: TNT is capable of detonating at a speed of 6,900 m/s. This high velocity allows TNT to produce a supersonic shockwave that can cause significant damage to its surroundings.
3. High gas yield: When TNT explodes, it produces a large amount of gases, which further increases the pressure exerted on its surroundings. This high-pressure shockwave causes significant damage to buildings and structures.
4. Easy to manufacture: TNT is relatively easy and cheap to manufacture, making it a popular explosive for military and industrial applications.
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One of the scientists interviewed for the article said, "Almost certainly this
effect has already ended." If he is correct, what evidence would you expect to
see to support his statement?
Answer:
The scientist is referring to the unusually slow growth rate of carbon dioxide occurring recently. As that slow growth rate ends, the rate of increase of carbon dioxide in the atmosphere should go up soon.
Explanation:This is the exact answer so switch it up.
How many milliliters of a 2. 99 M solution of glucose, C6H12O6 , molar mass = 180. 155 g/mol , do you need to obtain 25. 0 g of glucose?
For 25.0 g of glucose, 138.9 ml of the 2.99 M glucose solution are needed.
The most common monosaccharide, or kind of carbohydrate, is often glucose.
Molar mass of glucose = 180.155 g/mol
Molarity of glucose = 2.99 M
Mass of glucose = 25.0 g
The formula for calculating the volume of a solution required to obtain a given mass of the solute is given by,
\(Volume of solution (V) =\frac{ Mass of solute (m) }{ Molar mass of solute (M)}* 1000\)
Therefore, the volume of the 2.99 M glucose solution required to obtain 25.0 g of glucose is given by,
\(V = (\frac{25.0 }{ 180.155}) * 1000 V = 138.9 ml\)
Hence, 138.9 ml of the 2.99 M glucose solution is required to obtain 25.0 g of glucose.
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How is it possible for light to change genetic material? include evidence from the Sim in your answer and use the
vocabulary terms light, energy, and absorb.
Answer:When light hits CRY2, it changes shape and binds to its natural partner protein, known as CIB1. ... When light shines on the cells, the CRY2 protein binds to CIB1, which is floating in the cell. CIB1 brings along a gene activator, which initiates transcription, or the copying of DNA into mRNA.
Explanation:
Answer: Is to eat
Explanation: getting fatter
A file ____ shows the location of a file or folder.A)matrixB)pathC)runD)circuit
The correct term to complete your question is "path." A file path shows the location of a file or folder.
File path literally denotes the location of a specific file.
In other words, this indicates that a file's path determines or specifies location of a file or a folder.
Consider a text file named abc that is located on the desktop. Its file location might be C:UsersHPDesktopabc.txt.
Other options are file type, which refers to the kind of file—it might be a text file, an image, etc.—and file extension, which is a suffix that tells what kind of file it is (like jpg, txt, or png).
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What is the classification of igneous rock which forms from lava on the earths surface?(Why is there no option for Geology for the subject thing btw)
Answer:
Extrusive and intrusive are the two major types of igneous rocks. On the Earth's surface, extrusive rocks are created from lava, which is magma that has erupted from the underground. Intrusive rocks are formed from magma within the planet's crust that cools and solidifies.
Explanation:
Yeet
Calculate the mass defect and nuclear binding energy per nucleon ofthe each of the nuclides indicated below.Part A) Li-7 (atomic mass = 7.016003 )Express your answer using five decimal places.Mass Defect=
the mass defect of Li-7 is -0.035279 u and the nuclear binding energy per nucleon is 5.60553 × 10⁻¹² J/nuclide.
Given data:
Atomic mass of Li-7, A = 7.016003
The atomic mass of Li-7 is the sum of the number of protons and neutrons in it. Therefore, the number of neutrons in Li-7 is:
Neutrons = Atomic mass - Protons= 7.016003 - 3= 4.016003The mass of 3 protons and 4.016003 neutrons in Li-7 is: Mass of protons + Mass of neutrons = (3 x 1.007276) + (4.016003 x 1.008665) = 3.021828 + 4.029454 = 7.051282 u
Therefore, the mass defect in Li-7 is:
Mass defect = Actual mass - Calculated mass
= Atomic mass - Mass of protons and neutrons
= 7.016003 - 7.051282
= -0.035279 u
Nuclear Binding Energy per nucleon (BE/A) can be calculated using the formula:
BE/A = [Δm.c² / A]
where Δm is the mass defect and c is the speed of light which is 2.998 × 10⁸ m/s.
Substituting the values in the above formula:
BE/A = [(-0.035279) × (2.998 × 10⁸)² / 7]= 5.60553 × 10⁻¹² J/nuclide
Therefore, the mass defect of Li-7 is -0.035279 u and the nuclear binding energy per nucleon is 5.60553 × 10⁻¹² J/nuclide.
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What evidence did Mendeleev use to decide that the alkali metals should be in the same group?
The evidence that Mendeleev used to decide that the alkali metals should
be in the same group was because they exhibited the same properties.
Alkali metals are found in Group I together with Hydrogen and examples
include potassium, lithium etc and are the most electropositive sets of
elements.
All require the loss of one electron to attain an octet configuration which
makes them to be very reactive with other elements.
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An unknown substance with a mass of 5 grams releases 16.1 joules of energy when undergoing a temperature decrease of 7 degrees Celsius. What is the specific heat of that substance and what substance is it?
Answer:
0.46 J/g degrees C, Iron
Explanation:
16.1 J = 5 g x c x 7 degrees C
c = 16.1 / 5 x 7 = 0.46
Answer: 0.46 J/g degrees C, Iron
Give an example of how knowledge of physical properties of matter can be used in everyday life
Understanding physical properties of matter is essential in everyday life for a variety of purposes, from cooking to choosing materials.
Knowledge of physical properties of matter is extremely important in everyday life as it helps us understand the nature of substances we come into contact with. One example is the use of boiling points in cooking. Different substances have different boiling points which determine the temperature at which they boil. This information is crucial in determining cooking times and ensuring that food is cooked properly.
For instance, water boils at 100 degrees Celsius, while sugar syrup boils at a much higher temperature. If the wrong temperature is used, food may be undercooked or overcooked, leading to undesired outcomes. Knowledge of physical properties also helps in choosing the right materials for different purposes, such as choosing heat-resistant materials for cooking.
In conclusion, understanding physical properties of matter is essential in everyday life for a variety of purposes, from cooking to choosing materials.
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recalling that time is inversely proportional to rate, iif a reaction with an initial concentration of 0.100 m of reactant a took 50 s, and a second reaction in which 0.200 m of a took 25 s, what would be the order on a?
We are aware that a reaction's time need is inversely correlated with its rate, or that as the rate of the reaction rises, the reaction's time requirement falls.
We can express the rate law for a reaction involving products of form A as follows:
Rate = k[A]^n
where k is the rate constant and n is the order of the reaction with respect to A.
Given that the initial concentration of reactant A in the first reaction is 0.100 M and the time required for the reaction is 50 s, we can write:
50 s = 1 / (k * (0.100 M)^n)
Similarly, for the second reaction with an initial concentration of 0.200 M and a time of 25 s, we can write:
25 s = 1 / (k * (0.200 M)^n)
Dividing the two equations, we get:
50 s / 25 s = (0.100 M / 0.200 M)^n
Simplifying, we get:
0.5 = 0.5^n
Taking the logarithm of both sides, we get:
log(0.5) = n * log(0.5)
Solving for n, we get:
n = 1
Therefore, the order of the reaction with respect to A is 1.
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How does a scientist make two solutions with the same molarity?
O A. By dissolving the same number of moles of each substance in the
same volume of water
B. By dissolving the same number of grams of each substance in the
same volume of water
C. By dissolving the maximum amount of each substance in the
same volume of water
D. By dissolving 1 mole of each substance in enough water to make
sure dissolving is complete
Answer:
a
Explanation:
It's a duh
you are in a race to see who can dissolve 200 grams of sugar in 100 ml of water the fastest! select three (3) techniques that will make the solute dissolve faster so you can win the race!
two factor factor dependent Increased molecular activity accelerates up solubility at higher temperatures and Shaking or stirring helps the solution dissolve more quickly by increasing surface area contact.
To dissolve 200 grams of sugar in 100 ml of water faster, here are three techniques that you can use:
1. Increase the temperature of the water: Heating the water will increase the kinetic energy of the water molecules, making them move faster and collide with the sugar particles more frequently. This will result in faster dissolution of the sugar.
2. Stir the mixture: Stirring will help to increase the contact between the sugar particles and water molecules, which will speed up the dissolution process. The agitation caused by stirring will also help to break down any sugar clumps, making it easier for the sugar to dissolve.
3. Crush the sugar: Breaking the sugar into smaller particles will increase the surface area of the sugar that comes into contact with the water, making the dissolution process faster. You can use a mortar and pestle to crush the sugar into smaller pieces before adding it to the water.
By using these three techniques, you can dissolve the sugar in the water faster and potentially win the race!
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How many joules of heat are absorbed when 73 g water are heated from 30*C to 43*C? *
Answer:
3966.82 J
Explanation:
q=sm∆T
q=73×13×4.18
the specific heat for water is 4.18
Answer:
\(\boxed {\boxed {\sf 39,668.2 \ Joules}}\)
Explanation:
We are given the mass and change in temperature, so we must use this formula for heat energy:
\(q=mc \Delta T\)
The mass is 73 grams. Water's specific heat is 4.18 J/g × °C. Let's calculate the change in temperature
ΔT= final temperature - initial temperatureΔT= 43 °C - 30°C ΔT= 13 °CNow we know all the variables and can substitute them into the formula.
\(m= 73 \ g \\c= 4.18 \ J/g* \textdegree C \\\Delta T= 13 \ \textdegree C\)
\(q= (73 \ g )(4.18 \ J/g*\textdegree C)(13 \textdegree C)\)
Multiply the first numbers together. The grams will cancel.
\(q= 3051.4 \ J/\textdegree C (13 \textdegree C)\)
Multiply again. This time, the degrees Celsius cancel.
\(q= 39668.2 \ J\)
39,668.2 Joules of heat energy are absorbed.
CAN SOMEONE PLEASE HELP ME WITH THIS QUESTION
Wrong or inproper answer will be reported
The mass of unreacted zinc = 13 g
Further explanationThe reaction equation is the chemical formula of reactants and products
A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reactants and products
Reaction
\(\tt Zn+2HCl\Rightarrow ZnCl_2+H_2\)
mol ratio Zn : HCl = 1 : 2
mol of HCl\(\tt mol=V\times M\\\\mol=0.1~L(100~cm^3)\times 2~mol/L\\\\mol=0.2\)
mol of Zn\(\tt \dfrac{1}{2}\times 0.2=0.1~mol\)
the mass of reacted Zn :\(\tt 0.1\times 65=6.5~g\)
the mass of unreacted Zn\(\tt 19.5-6.5=\boxed{\bold{13~g}}\)
In a combustion reaction, ethanoic acid (CH3COOH) is burned in the presence of oxygen (O2). producing carbon dioxide (CO2) and water (H2O)
Classify each substance as either a reactant or product in the chemical reaction
a. ethanolc acid b. water c. carbon dioxide d. oxygen Reactants Products
In the chemical reaction the reactants are oxygen and ethanolc acid while the product are water and carbon dioxide.
In a chemical reaction, reactants are the substances that react with each other to form products.
Therefore, oxygen and ethanoic acid are reactants while carbon dioxide and water are products.In a combustion reaction, a substance is burned in the presence of oxygen, resulting in the release of heat and light.
During this reaction, the oxygen reacts with the substance to produce carbon dioxide and water. In the given reaction, ethanoic acid (CH3COOH) is burned in the presence of oxygen (O2), producing carbon dioxide (CO2) and water (H2O).
Thus, oxygen and ethanoic acid are reactants, while carbon dioxide and water are products.
The combustion reaction of ethanoic acid is shown as follows:
2CH3COOH + 3O2 = 2CO2 + 2H2O + heat and light
This means that for every two molecules of ethanoic acid and three molecules of oxygen that react, two molecules of carbon dioxide and two molecules of water are produced. The heat and light produced are also released.
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what is the molarity of a ch3cooh solution if 9.86ml of the solution is neutralized by 7.12ml of 1.14 m nahco3 soltuion
To determine the molarity of a CH3COOH solution, we can use the concept of stoichiometry and the volume and molarity information given for the neutralization reaction.
The balanced chemical equation for the reaction between CH3COOH (acetic acid) and NaHCO3 (sodium bicarbonate) is:
CH3COOH + NaHCO3 → CH3COONa + H2O + CO2
From the equation, we can see that the ratio between CH3COOH and NaHCO3 is 1:1. This means that one mole of CH3COOH reacts with one mole of NaHCO3.
First, let's calculate the number of moles of NaHCO3 used in the reaction:
moles of NaHCO3 = volume (in L) × molarity
= 7.12 ml × 0.00114 mol/ml
= 0.0081168 mol
Since the ratio of CH3COOH to NaHCO3 is 1:1, the number of moles of CH3COOH used in the reaction is also 0.0081168 mol.
Next, we can calculate the molarity of the CH3COOH solution:
molarity = moles/volume (in L)
= 0.0081168 mol / 0.00986 L
= 0.824 M
Therefore, the molarity of the CH3COOH solution is 0.824 M.
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A World Health Organization study of health in various countries reported that in Canada, systolic blood pressure readings have a mean of 121 and a standard deviation of 16 . A reading above 140 is considered to be high blood pressure. Complete parts a through d below. a. What is the z− score for a blood pressure reading of 140 ? z= (Round to two decimal places as needed.) b. If systolic blood pressure in Canada has a normal distribution, what proportion of Canadians suffers from high blood pressure? The proportion of Canadians with high blood pressure is (Round to four decimal places as needed.) c. What proportion of Canadians has systolic blood pressure in the range from 100 to 140 ? The proportion with systolic blood pressure between 100 and 140 is (Round to four decimal places as needed.) d. Find the 85 th percentile of blood pressure readings. The 85 th percentile of blood pressure readings is
The 85th percentile of blood pressure readings is approximately 137.64. a. To calculate the z-score for a blood pressure reading of 140, we can use the formula:
z = (x - μ) / σ
where x is the value (140 in this case), μ is the mean (121), and σ is the standard deviation (16).
Substituting the values into the formula:
z = (140 - 121) / 16
z ≈ 1.19 (rounded to two decimal places)
b. To find the proportion of Canadians with high blood pressure, we need to calculate the area under the normal distribution curve for values above 140. This can be done by finding the cumulative probability using the z-score.
Using a standard normal distribution table or a calculator, we can find that the cumulative probability corresponding to a z-score of 1.19 is approximately 0.881.
Therefore, the proportion of Canadians with high blood pressure is approximately 0.881 (rounded to four decimal places).
c. To find the proportion of Canadians with systolic blood pressure in the range from 100 to 140, we need to calculate the area under the normal distribution curve between these two values.
Using the z-scores corresponding to 100 and 140, we can find the cumulative probabilities for each value. The cumulative probability for a z-score of -1.25 (corresponding to 100) is approximately 0.105, and the cumulative probability for a z-score of 1.19 (corresponding to 140) is approximately 0.881 (as calculated in part b).
The proportion with systolic blood pressure between 100 and 140 is the difference between these two probabilities:
Proportion = 0.881 - 0.105 ≈ 0.776 (rounded to four decimal places)
d. The 85th percentile represents the value below which 85% of the blood pressure readings fall. To find the 85th percentile, we need to determine the z-score that corresponds to an area of 0.85 under the normal distribution curve.
Using a standard normal distribution table or a calculator, we can find that the z-score corresponding to an area of 0.85 is approximately 1.04.
To find the actual blood pressure reading at the 85th percentile, we can use the z-score formula:
x = μ + (z * σ)
Substituting the values:
x = 121 + (1.04 * 16)
x ≈ 137.64
Therefore, the 85th percentile of blood pressure readings is approximately 137.64.
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which of the following are essential components of a bomb calorimeter? all of these answers are correct. a thermometer a heavy, fine threaded system container a mechanical stirrer
A bomb calorimeter whose components have a heat capacity of 6.66 kJ/°C is filled with 986 g of water. (The amount of water is not constant from experiment to experiment. The heat capacity of the calorimeter is broken down into two parts: the water and the calorimeter components.) The initial temperature of the calorimeter contents is 21.48°C. A 1.104 g sample of benzoic acid (?Ecomb = -26.42 kJ/g) is combusted in the calorimeter. What is the final temperature of the calorimeter contents?
°C
The final temperature of the calorimeter contents is approximately 42.9824°C.
To calculate the final temperature of the calorimeter contents, we consider the heat absorbed by the water and the calorimeter components.
First, let's calculate the heat absorbed by the water:
q_water = m_water * C_water * ΔT_water
q_water = 986 g * 4.18 J/g°C * (T_final - 21.48°C)
Next, let's calculate the heat absorbed by the calorimeter components:
q_calorimeter = C_calorimeter * ΔT_calorimeter
q_calorimeter = 6.66 kJ/°C * (T_final - 21.48°C)
Since the total heat absorbed is the sum of the heat absorbed by the water and the calorimeter components:
q_total = q_water + q_calorimeter
Now we can equate the total heat absorbed to the heat released by the combustion of benzoic acid:
q_total = -26.42 kJ/g * 1.104 g
By setting these two equations equal to each other, we can solve for the final temperature (T_final). We have:
986 g * 4.18 J/g°C * (T_final - 21.48°C) + 6.66 kJ/°C * (T_final - 21.48°C) = -26.42 kJ/g * 1.104 g
Simplifying and solving the equation will give us the value of T_final, which represents the final temperature of the calorimeter contents.
986 g * 4.18 J/g°C * (T_final - 21.48°C) + 6.66 kJ/°C * (T_final - 21.48°C) = -26.42 kJ/g * 1.104 g
Simplifying the equation:
4122.68 * (T_final - 21.48) + 6.66 * (T_final - 21.48) = -29.15568
4122.68T_final - 88721.58 + 6.66T_final - 143.5028 = -29.15568
4133.34T_final - 88865.0828 = -29.15568
4133.34T_final = 88835.92712
T_final ≈ 21.48 + (88835.92712 / 4133.34)
T_final ≈ 21.48 + 21.5024
T_final ≈ 42.9824
Therefore, the final temperature of the calorimeter contents is approximately 42.9824°C.
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A flask that weighs 450 g is filled with 145 ml of benzene. The weight of the flask and benzene is found to be 754 g. From this information, calculate the density of the benzene.
Answer:
Density, \(d=2.09\ g/cm^3\)
Explanation:
Given that,
Mass of a flask is 450 g
Volume of benzene added to the flask is 145 mL or 145 cm³
The weight of the flask and benzene is found to be 754 g.
We need to find the density of the benzene.
Weight of benzene added = total weight of flask and benzene-mass of flask
m = 754 g - 450 g
m = 304 g
Density = mass/volume
So,
\(d=\dfrac{304\ g}{145\ cm^3}\\\\d=2.09\ g/cm^3\)
So, the density of the benzene is \(2.09\ g/cm^3\).
Nomex, a condensation copolymer used by firefighters because of its flame-resistant properties, is formed between isophthalic acid and m-aminoaniline
Draw the structure of the dimer. (Hint: Water is eliminated when the bond between the monomers forms. )
Draw the molecule by placing atoms on the grid and connecting them with bonds. Include all hydrogen atoms
The structure of the dimer of Nomex is as follows:
To draw the structure of the dimer, we first need to draw the structure of the two monomers, isophthalic acid and m-aminoaniline:
Next, we need to eliminate a water molecule from the two monomers to form the dimer. This is done by removing a hydrogen atom from the amino group of m-aminoaniline and a hydroxyl group from isophthalic acid:
Finally, we can connect the two monomers together to form the dimer of Nomex:
This is the structure of the dimer of Nomex, which is a condensation copolymer formed between isophthalic acid and m-aminoaniline.
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Patrick and SpongeBob love to blow bubbles! Patrick found some Super Bubble Soap at Sail-Mart. The ads
claim that Super Bubble Soap will produce bubbles that are twice as big as bubbles made with regular bubble
soap. Patrick and SpongeBob made up two samples of bubble solution One sample was made with 5 oz. of
Super Bubble Soap and 5 oz. of water, while the other was made with the same amount of water and 5 oz. of
regular bubble soap. Patrick and SpongeBob used their favorite bubble wands to blow 10 different bubbles and
did their best to measure the diameter of each one. The results are shown in the chart
Bubbles
(Diameter in centimeters)
Bubble Super Bubble
Regular Soap
1
15
10
2
10
5
3
12
16
4
18
14
5
22
11
6
13
12
7
16
11
8
18
15
9
15
15
10
12
6
What did the Super Bubble ads claim?
Answer:
heyyy I have the same question for my exam plsss help meee
Which horizon in a soil profile is known as topsoil? This rich, darker soil is alive with bacteria, algae, and fungi.Question 6 options:horizon Bhorizon Ohorizon Ahorizon C
Answer:
its horizon O
Explanation:
When the o is h is horizon O
Farmers use conservation practices such as crop rotation to insure that their crops are sustainable. Crop rotation is the process of moving crops to a new location to get the nutrients from the soil needed for that specific crop to grow. What conclusion can be drawn if farmers do not use soil conservation practices such as crop rotation?
A.
If farmers do not use soil conservation practices, the topsoil, which contains weathered rocks, will not be fertile to promote plant growth because of loss of nutrients from the soil.
B.
If farmers do not use soil conservation practices, the topsoil, which contains weathered rocks, will be fertile to promote plant growth because of the loss of nutrients from the soil.
C.
If farmers do not use soil conservation practices, the topsoil, which contains humus, will not be fertile to promote plant growth because of the loss of nutrients from the soil.
D.
If farmers do not use soil conservation practices, the topsoil, which contains humus, will be fertile to promote plant growth because of the loss of nutrients from the soil.
Answer:
C. If farmers do not use soil conservation practices, the topsoil, which contains humus, will not be fertile to promote plant growth because of the loss of nutrients from the soil.
Explanation:
The top soil is rich in humus and not weathered materials. It is not close to the bedrock. Rather, the topsoil is rich in organic matter and it is present as humus in the soil.
If crop rotation is not being practiced, the soil's nutrients would be highly depleted without replenishing them back. With crop rotation the top soil can be made more fertile when it is left uncultivated for a period of time. Instead of heavily relying on a single piece of land, crops can rotated on a timed basis so that soils will have enough time to restore their nutrients.How many electrons are in the valence shell of the sodium atom shown below?
Answer:
answer is one
Explanation:
valency is the amount of electrons on the last shell
why hydroxide an oxidation reaction??
Answer:
sorry I didn't know this one i did all the work and stuff and still couldn't get it sorry