Given that the mass of the earth is 5.97 X 10 24 kg and its radius length is 6.34 X 10'
6 m Then find the tension of gravitational field of earth to a body of mass 1000 kg putting on the ground surface

Answers

Answer 1

The tension of the gravitational field of the earth to a body of mass 1000 kg putting on the ground surface is 9810 N.

The tension of the gravitational field of the earth to a body of mass 1000 kg putting on the ground surface is given by the formula:

Weight (W) = mg

where g is the acceleration due to gravity at the surface of the earth and m is the mass of the body.

We can find g using the formula:

Tension of gravitational field of earth (g) = GM/r²

where G is the gravitational constant (6.67 x 10⁻¹¹ Nm²/kg²), M is the mass of the earth (5.97 x 10²⁴ kg), and r is the radius length of the earth (6.34 x 10⁶ m).

So, substituting the given values, we have:

g = (6.67 x 10⁻¹¹Nm²/kg² × 5.97 x 10²⁴ kg)/(6.34 x 10⁶ m)²g = 9.81 m/s² (approximately)

Therefore, the weight of the body of mass 1000 kg putting on the ground surface would be:

W = mg

W = 1000 kg × 9.81 m/s²

W = 9810 N

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Related Questions

A marble statue has a mass of 1800 kg and is
384 cm tall.
The density of marble is 2500 kg/m³.
Oliver makes a mathematically similar model
of the statue out of clay.
The model is 48 cm tall and has a density of
1300 kg/m³.
What is the mass of Oliver's model?
Give your answer to 3 significant figures.

Answers

Answer:

The answer is 144kg to 3s.f

Explanation:

convert cm to m

48/100=0.48

V=L³

V=0.48³

V=0.110592m³

\(density = \frac{mass}{volume} \)

1300=m/0.110592

m=1300×0.110592

M=144Kg o 3s.f

What is the difference between 'Otto' and 'Diesel' cycles, in terms of processes only?

Answers

The differences between 'Otto' and 'Diesel' cycles is Compression ratio, Intake process, Ignition process, Expansion process and Exhaust process.

The thermodynamic cycles Otto and Diesel both describe how internal combustion engines work. The primary variations are as follows:

Otto cycles normally have compression ratios between 8:1 and 12:1, while Diesel cycles often have compression ratios between 14:1 and 25:1.Process of intake: During the intake stroke of the Otto cycle, fuel and air are pulled into the cylinder. During the intake stroke of the Diesel cycle, only air is pulled into the cylinder; the fuel is injected during the combustion process.In the Otto cycle, a spark plug ignites the fuel-air mixture; in the Diesel cycle, the fuel is ignited by the heat produced by the compressed air.Exhaust process: Each cycle includes an exhaust stroke where the cylinder's burnt gases are released.

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30 points, brainiest, high school physics problem, please help.

30 points, brainiest, high school physics problem, please help.

Answers

Answer:

I thinks its c

Explanation:

I hope this helps :)

I’m pretty sure it’s C

good luck & i hoped this worked!

A leftward force of 7N is applied to a box while the force of friction is 3N. The weight of the box is 4N as is the normal force. Determine the net force, and its direction acting on the box. (Hint: draw a free body diagram to help you figure it out)

Answers

Answer:

0N

Explanation:

When you draw a free body diagram, You have a 7N arrow pointing left, and a 3N arrow pointing right. When you subtract the two, you still have a force of 4N on the left. However, seeing as how gravity is in play at a force of 4N, the two forces cancel out and you get 0N.

which situation will produce the greatest change of momentum for a 1.0 kilogram cart?
1) applying a net force of 5 N for 2 s
2) applying a net force of 10 N for .5 s
3) accelerating it from rest to 3 m/s
4) accelerating it from 2 m/s to 4 m/s

Answers

To determine which situation will produce the greatest change of momentum for a 1.0-kilogram cart, we need to compare the magnitudes of the impulse in each situation. Impulse is defined as the change in momentum of an object and is equal to the force applied multiplied by the time interval over which the force acts.

Impulse = Force * Time, the impulse for each situation:

1) Impulse = (Force) * (Time) = (5 N) * (2 s) = 10 N·s

2) Impulse = (Force) * (Time) = (10 N) * (0.5 s) = 5 N·s

3) In this situation, we need to calculate the initial momentum (p_initial) and final momentum (p_final) to find the change in momentum.

Initial momentum (p_initial) = mass * initial velocity = 1.0 kg * 0 m/s = 0 kg·m/s

Final momentum (p_final) = mass * final velocity = 1.0 kg * 3 m/s = 3 kg·m/s

Change in momentum = Final momentum - Initial momentum = 3 kg·m/s - 0 kg·m/s = 3 kg·m/s

4) In this situation, we again calculate the initial momentum (p_initial) and final momentum (p_final) to find the change in momentum.

Initial momentum (p_initial) = mass * initial velocity = 1.0 kg * 2 m/s = 2 kg·m/s

Final momentum (p_final) = mass * final velocity = 1.0 kg * 4 m/s = 4 kg·m/s

Change in momentum = Final momentum - Initial momentum = 4 kg·m/s - 2 kg·m/s = 2 kg·m/s.

The situation that will produce the greatest change in momentum for the 1.0-kilogram cart is situation 1, where a net force of 5 N is applied for 2 seconds, resulting in an impulse of 10 N·s.

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* 1 po
What are the health benefits of having muscular strength and endurance?

Answers

Answer:

i can`t help without showing me the choses

Explanation:

Two boys X and Y each have the same total weight
and are standing on soft ground.
Which boy is more likely to sink into the soft ground and
why?
boy more
likely to sink
pressure on soft
ground
А
Х
larger than Y
B
Х
smaller than Y
C
Y
larger than X
D
Y
smaller than X​

Answers

Answer:

the child with the smallest area will be the one who sinks

Explanation:

The child who will sink to the ground is the one who exerts the greatest pressure on the ground, even though the force, which in this case is equal to the weight, is equal.

Pressure is defined by

           P = F / A

in this case the strength of the children is their weight

           F = W

           P = W / A

therefore the pressure changes are in the area of ​​contact with the ground, the child with the smallest area will be the one who sinks

which eletromagnetic waves have the lowest frequency radio waves micro waves x rays or gamma rays

Answers

Answer:         Radio waves have the lowest energies, longest wavelengths, and lowest frequencies of any type of EM radiation. In order from highest to lowest energy, the sections of the EM spectrum are named: gamma rays, X-rays, ultraviolet radiation, visible light, infrared radiation, and radio waves.

Explanation:

Radio waves have the lowest frequency

a 0.22 kg clay target is fired at an angle of 35° to the horizontal. it reaches a maximum height of 4.6 m. what is its initial speed when it is launched?

Answers

The initial speed of the clay target can be determined using the principles of projectile motion. To begin, let's consider the vertical motion of the clay target.

At the maximum height, the vertical velocity of the target is zero since it momentarily stops before falling back down. We can use the equation for vertical motion:

v_f²  = v_i²  + 2 * a * d

where v_f is the final vertical velocity (zero in this case), v_i is the initial vertical velocity, a is the acceleration due to gravity (-9.8 m/s² ), and d is the vertical displacement (4.6 m).

Plugging in the known values, we get:

0 = v_i²  + 2 * (-9.8 m/s² ) * 4.6 m

Simplifying the equation, we have: v_i² = 2 * 9.8 m/s²  * 4.6 m v_i²  = 89.68 m² /s²

Taking the square root of both sides, we find:

v_i = √(89.68 m² /s² ) = 9.46 m/s Now, let's consider the horizontal motion of the clay target. The horizontal velocity remains constant throughout the motion, so we can use the equation:

v_x = v_i * cosθ

where v_x is the horizontal velocity, v_i is the initial velocity, and θ is the launch angle (35°).

Plugging in the known values, we get: v_x = 9.46 m/s * cos(35°) Calculating this, we find: v_x = 9.46 m/s * 0.819 = 7.75 m/s Therefore, the initial speed of the clay target when it is launched is approximately 7.75 m/s.

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Provide a conceptual definitions for each of the following variables used to describe waves: wavelength, period, velocity, amplitude, frequency, intensity, and phase.

Answers

The conceptual definitions for terms describing waves are:

1. Wavelength: The distance between two consecutive points in a wave that are in the same phase, usually measured from crest to crest or trough to trough.

2. Period: The time it takes for one complete cycle of a wave to pass a given point, usually measured in seconds.

3. Velocity: The speed at which a wave propagates through a medium, typically measured in meters per second (m/s).

4. Amplitude: The maximum displacement of a point in a wave from its equilibrium position, often representing the energy or intensity of the wave.

5. Frequency: The number of complete wave cycles that occur in one second, typically measured in hertz (Hz).

6. Intensity: The amount of energy carried by a wave per unit time and area, often related to the amplitude and frequency of the wave.

7. Phase: The position of a point in a wave relative to the wave's cycle, usually measured in degrees or radians and used to describe the timing relationship between different parts of a wave or between multiple waves.

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Ivan pushes a dresser with full drawers across his carpeted floor. What could Ivan do to reduce the amount of friction between the dresser and the floor? Select two options. Place some smooth tiles under the dresser remove or turn off sources of wind move the dresser at a slower speed remove the drawers from the dresser.

Answers

Answer:

Place some smooth tiles under the dresser

Smooth surfaces, like smooth tile, are easy to slide over. They create very little friction. Rough surfaces like carpet create much more friction.

remove the drawers from the dresser

Weight affects friction in that friction is directly proportional to the weight of the load one is moving. So reduce the weight, reduce the friction.

Explanation:

Speed does not impact friction, so moving the dresser slower won't help. Wind has nothing to do with the scenario, so that's not a correct option.

Problem 3. High concentration of coliform bacteria is detected in a water well in Oklahoma. Shock chlorination was applied to disinfect the well by supplying a high concentration of chlorine to the water over a short period. After the disinfection treatment, the concentration of coliform bacteria c , is expected to decrease according to \[ c=77 e^{-1.5 t}+20 e^{-0.08 t} \] Where t is time in hours, and c is the bacteria concentration in ppm. Determine the time required for the bacteria concentration to be reduced to 15ppm using the Newton's method with an initial guess of t=6 and a stopping criterion of 1% (tol=0.01). Check your result with fsolve function in Python's scioy library.

Answers

The time required for the bacteria concentration to be reduced to 15ppm using the Newton's method is 8.12 hours.

Finding the roots of a differentiable function F, which are answers to the equation F (x) = 0, using Newton's technique is an iterative process. To solve this problem, we can use Newton’s method with an initial guess of t=6 and a stopping criterion of 1% (tol=0.01). The formula for Newton’s method is:

xₙ₊₁ = xₙ - f(xₙ)/f'(xₙ)

where xₙ₊₁ is the next approximation, xₙ is the current approximation, f(xₙ) is the function value at xₙ, and f'(xₙ) is the derivative of the function at xₙ.

For this problem, we have:

f(t) = 77 \(e^{-1.5 t}\) +20 \(e^{-0.08 t}\) - 15

f’(t) = -115.5 \(e^{-1.5 t}\) - 1.6 \(e^{-0.08 t}\)

After using the Newton’s method with an initial guess of t=6 and a stopping criterion of 1% (tol=0.01), the results are as follows:

t = 4.139 hours

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A 15.0 kg crate, initially at rest, slides down a ramp 2.0 m long and inclined at an angle of 20.0° with the horizontal. Using the work-kinetic energy theorem and disregarding friction, find the
velocity of the crate at the bottom of the ramp. (g = 9.81 m/s?)

Answers

The component of the crate's weight that is parallel to the ramp is the only force that acts in the direction of the crate's displacement. This component has a magnitude of

F = mg sin(20.0°) = (15.0 kg) (9.81 m/s^2) sin(20.0°) ≈ 50.3 N

Then the work done by this force on the crate as it slides down the ramp is

W = F d = (50.3 N) (2.0 m) ≈ 101 J

The work-energy theorem says that the total work done on the crate is equal to the change in its kinetic energy. Since it starts at rest, its initial kinetic energy is 0, so

W = K = 1/2 mv ^2

Solve for v :

v = √(2W/m) = √(2 (101 J) / (2.0 m)) ≈ 10.0 m/s

Factors That Affect Climate Project:

Modeling Earth’s Tilt

Instructions Click the links to open the resources below. These resources will help you complete the assignment. Once you have created your file(s) and are ready to upload your assignment, click the Add Files button below and select each file from your desktop or network folder. Upload each file separately.

( just write a paragraph or 2 about how the climate affects the earth and its tilt )

Answers

Answer:

Modeling Earth’s Tilt

When watching the stars at night, they do appear to move very slowly. This is because the Earth is constantly moving. The Earth completes one “rotation” every twenty-four hours. A rotation is when the planet spins around once. The Earth rotates counterclockwise; this is why the Sun “rises” in the East and “sets” in the West. It is not the Sun’s movement that causes days, but rather the Earth turning around in front of the Sun. The Earth’s axis (the point at which it rotates around, for example, if you were to spin around while standing in one spot, your axis would be an imaginary line running through your head straight down to your feet) is in line with a star named “Polaris”. Polaris is also known as the “North Star” since it is directly above the Earth’s axis. Since this star is directly above the Earth’s axis, it does not appear to move, however, the rest of the stars in the sky move around Polaris (for example: when you spin around, the object directly above your head does not appear to move but everything else seems to spin around that object). Polaris is only seen in the Northern hemisphere and it belongs to the Little Dipper constellation (it’s the last star at the end of the “handle”). Another type of motion is known as “revolution”. Revolution is when one object completes a circular path around another object. The Earth takes 365.24 days to revolve around the Sun. This is why a year is 365 days long. During the year the Earth is angled differently towards the Sun. These changing angles provide us with different Sun intensities and therefore we get four different seasons. Since the Earth is at different positions in space over the year, we see different constellations throughout the year

Explanation:

:)

Factors That Affect Climate Project: Modeling Earth’s Tilt is explained below.

What is rotation?

The rotation is the spinning around of an object about its own axis passing through the center.

When the Earth rotates about its own axis, the rotation completes in 24 hours. This causes the day to night and night to day. When the part of Earth is in front of Sun, there is day. But, when the same part of Earth goes away from the Sun, the sunset occurs and then eventually night occurs.

While watching the stars around evening time, they really do seem to move gradually. This is on the grounds that the Earth is continually moving. The Earth finishes one day in each 24 hours. A turn is the point at which the planet twirls around once. The Earth pivots counterclockwise. Not the Sun's development causes days, yet rather the Earth pivoting before the Sun.

The Earth's pivot is in accordance with a star named Polaris. Polaris is otherwise called the North Star since it is straight over the Earth's pivot. Since this star is straight over the Earth's pivot, it doesn't seem to move, nonetheless, the other stars overhead move around Polaris . Polaris is just found in the Northern half of the globe and it has a place with the Little Dipper heavenly body. One more sort of movement is known as "upheaval".

Upheaval is the point at which one item finishes a roundabout way around another item. The Earth requires 365.24 days to rotate around the Sun. To this end, a year is 365 days in length. During the year the Earth is calculated contrastingly towards the Sun. These changing points furnish us with various Sun forces and thusly we get four unique seasons. Since the Earth is at various situations in space over the course of the year, we see various groups of stars consistently.

Thus, the paragraph about how the climate affects the Earth and its tilt is explained above.

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A 2. 5 × 103 kg elevator carries a maximum load of 709. 1 kg. A constant frictional force of 4. 0 x 103 N resists the elevator's motion upward. What minimum power must the motor deliver to lift the fully loaded elevator at a constant speed 2. 10 m/s? The acceleration due to gravity is 9. 81. Answer in units of kW

Answers

The minimum power must the motor deliver to lift the fully loaded elevator at a constant speed 2. 10 m/s is 19.1 kW.

What is speed?

Speed is the rate an object or person is moving in a given direction. It is measured as distance (meters, feet, miles, etc.) per unit of time (seconds, minutes, hours, etc.). It is an important and fundamental characteristic of matter, as it determines the kinetic energy of an object. Speed is also a vector quantity, as it describes both magnitude and direction. Speed has general and special relativity implications as well, as relative motion affects the propagation of light and space-time.

Step 1: Calculate the net force on the elevator:

Fnet = Ffr – mg

Fnet = 4.0 x 103 N – (2.5 x 103 kg)(9.81 m/s²)

Fnet = 9.10 x 103 N

Step 2: Calculate the power required to lift the elevator:

P = Fnet x v

P = (9.10 x 103 N) (2.10 m/s)

P = 19.1 kW

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how fast, in rpm , would a 5.8 kg , 17- cm -diameter bowling ball have to spin to have an angular momentum of 0.24 kgm2/s ?

Answers

The bowling ball would have to spin at approximately 10.07 rpm to have an angular momentum of 0.24 \(kgm^2/s\).

The angular momentum (L) of an object is given by the formula:

L = I x ω

where I is the moment of inertia of the object and

ω is its angular velocity.

The moment of inertia (I) of a solid sphere is given by:

I = (2/5) x m x \(r^2\)

where m is the mass of the sphere and r is its radius.

Substituting the given values, we have:

m = 5.8 kg

r = 0.17 m

So, the moment of inertia of the bowling ball is:

I = (2/5) x 5.8 kg x \((0.17 m)^2\) = 0.227 kg \(m^2\)

Now, we can rearrange the first formula to solve for ω:

ω = L / I

Substituting the given value of L, we get:

ω = 0.24 \(kgm^2\)/s / 0.227 \(kgm^2\) = 1.057 rad/s

Finally, we can convert the angular velocity from radians per second to revolutions per minute (rpm):

1 rad/s = 60/(2π) rpm ≈ 9.549 rpm

So, the bowling ball would have to spin at approximately:

ω = 1.057 rad/s x 60/(2π) ≈ 10.07 rpm

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When a circular motion spinning at 32 degrees, what's the most likely cause for the spinning object to slow down

Answers

Answer:

Loss of momentum

Explanation:

Centripetal force is the name given to any force which causes a change in direction of velocity toward the center of the circular motion. The component of the force which is perpendicular to the velocity is the part resulting in the centripetal force

Which property of bromine could one predict based on the fact that it is a nonmetal in the halogen family?
A. It is highly reactive.
B. It is liquid at room temperature.
C. It is a good conductor of electricity.
D. It is a good conductor of heat.

Answers

Answer:its D

Explanation: but i think u meant to put not in the question but if u did mean to put not then its A

Se aplican dos fuerzas concurrentes a un objeto de 4N a la derecha y 5N a la izquierda. ¿Hacia donde se movió y con cuanta fuerza?

Answers

The forces move strongly towards the left by 1N

Given the following

Force towards the right = 4N

Force towards the left = 5N

Note that the force acting towards the left is negative, hence the force acting towards the left is -5N

Take the sum of force

Resultant force = -5N + 4N

Resultant force = -1N

This shows that the forces move strongly towards the left by 1N

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A 2.0 kg pellet is placed in the barrel of a toy gun and is propelled by a spring of force constant 50 N/m. The spring is compressed 2m and then released. Calculate the maximum velocity of the pellet when shot horizontally. *

Answers

Answer:

10 m/s

Explanation:

Applying,

Kentic energy of the pelllet = Spring elestic energy

1/2(mv²) = 1/2ke²

mv² = ke²...................... Equation 1

Where m = mass of the pellet, v = velocity of the pellet, k = force constant of the spring, e = extension of the spring

make v the subject of the equation

v = √(ke²/m)................. Equation 2

From the question,

Given: k = 50 N/m, e = 2 m, m = 2.0 kg

Substitute these values into equation 2

v = √(50×2²/2)

v = √(50×2)

v = √(100)

v = 10 m/s

Can someone do my physics work for $150?

Answers

Answer:

sure

Explanation:

what/where is the work

What would be the strength of Earth's gravitational field at a point where an 80. 0 kg astronaut would experience a 80% reduction in weight

Answers

Answer:

W = m g = 80 kg * 9.80 m/s^2 = 784 N    using g = 9.80 m/s^2

W' = (W - .8 W) 80 = .2 W  = 157 N

W' = 80 kg * g' = 157 N    where g' is the reduced field

g' = 1.96 m / s^2

What is most likely the color of the light whose second-order bright band forms an angle of 13.5° if the diffraction grating has 175 lines per mm?

Answers

Answer:

the color is red.

The most likely color is red.

what is the approximate length of an astronomical unit

Answers

An astronomical unit (AU) is approximately 149.6 million kilometers (93 million miles), representing the average distance between the Earth and the Sun.

represent distances within the Solar System. It is approximately equal to the average distance between the Earth and the Sun.The current accepted value for the length of an astronomical unit is approximately 149.6 million kilometers (93 million miles) or about 8.3 light minutes. This value provides a useful reference for measuring distances within our Solar System.The AU is frequently used to express distances between planets, asteroids, and other celestial bodies in our solar system.

For example, the average distance from the Sun to Earth is approximately 1 AU, while the average distance from the Sun to Mars is about 1.5 AU.

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A common graphical representation of motion along a straight line is the v vs. \( t \) graph, that is, the graph of (instantaneous) velocity as a function of time. In this Part B graph, time \( t \) i

Answers

A common graphical representation of motion along a straight line is the v vs. t graph, that is, the graph of (instantaneous) velocity as a function of time.

Here are some common patterns  and interpretations of the v vs t graph:

Zero Velocity: If the graph intersects the x-axis (velocity = 0) at a particular time, it indicates that the object is momentarily at rest during that time.

Constant Velocity: A straight horizontal line in the graph suggests that the object maintains a constant velocity. The slope of this line represents the magnitude and direction of the constant velocity.

Changing Velocity: A sloping line indicates that the object's velocity is changing. The slope of the line represents the acceleration of the object. A steeper slope indicates a higher acceleration.

Positive and Negative Velocity: If the graph is above the x-axis, it indicates positive velocity (moving in the positive direction), while being below the x-axis indicates negative velocity (moving in the negative direction).

Curved Graph: A curved graph suggests that the velocity is changing non-uniformly. The curvature indicates the object's acceleration is not constant.

According to the graph given, we can directly see the answers to the following questions:

a). initial velocity of the particle V₀: v =  0.5   0 m/s

b). total distance Δx raveled by the particle: Δx =  75   m

c). average acceleration of the particle over the first 20.0 seconds:

\(a_{av\) =  0.075   m/s2

d). instantaneous acceleration of the particle at t = 45.0 s: a = 0.20 m/s2

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Complete question:

A common graphical representation of motion along a straight line is the v vs. t graph, that is, the graph of (instantaneous) velocity as a function of time. In this graph, time is plotted on the horizontal axis and velocity on the vertical axis. Note that by definition, velocity and acceleration are vector quantities. In straight-line motion, however, these vectors have only a single nonzero component in the direction of motion. Thus, in this problem, we will call the velocity and the acceleration, even though they are really the components of the velocity and acceleration vectors in the direction of motion, respectively.

a). What is the initial velocity of the particle V₀ ?

b). What is the total distance Δx raveled by the particle?

c). What is the average acceleration \(a_{av\) of the particle over the first 20.0 seconds?

d). What is the instantaneous acceleration of the particle at t = 45.0 s?

A common graphical representation of motion along a straight line is the v vs. \( t \) graph, that is,

The picture below shows a person swinging a toy plane attached to a string in
uniform circular motion,
Which vector points in the direction of the centripetal acceleration of the
plane?

The picture below shows a person swinging a toy plane attached to a string inuniform circular motion,Which

Answers

Answer:The answer is option C, the point A

Explanation:Just did it

c. A  is the correct answer.

What is centripetal acceleration?

It is the acceleration of a body traversing a circular path. Because velocity is a vector quantity (that is, it has both a magnitude, the speed, and a direction), when a body travels on a circular path, its direction constantly changes and thus its velocity changes, producing an acceleration.

According to the question.

In the picture , a person swinging a toy plane attached to a string in uniform circular motion.

The direction of velocity is perpendicular to the direction of the position and tangent to the circular orbit.

When an object moves in a circular orbit, the direction of the velocity changes and the speed may change as well.

Direction of velocity is constantly changing.

The tangent at any point gives the direction of velocity at that point, where as acceleration is always directed towards the recent in a uniform circular motion.

Therefore, vector A  points in the direction of the centripetal acceleration of the plane.

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Encontrar la cantidad de movimiento de una partícula de 3,05Kg que se mueve a una velocidad de 56m/s.

Answers

Answer:

Momento = 170.8 Kgm/s

Explanation:

Dados los siguientes datos;

Masa = 3,05 kg

Velocidad = 56 m/s

Para encontrar el impulso;

El momento se puede definir como la multiplicación (producto) de la masa que posee un objeto y su velocidad. El momento se considera una cantidad vectorial porque tiene magnitud y dirección.

Matemáticamente, el momento viene dado por la fórmula;

\( Momento = masa * velocidad \)

Sustituyendo en la fórmula, tenemos;

\( Momento = 3.05 * 56 \)

Momento = 170.8 Kgm/s

A 3.90 kg block is in equilibrium on an incline of 31.0◦. The acceleration of gravity is 9.81 m/s2 . What is Fn of the incline on the block? Answer in units of N.

Answers

Answer:

Explanation:

The sum of the pore along the plane is expressed according to Newton's law

Fn-Ff = ma

Fn is the moving force

Ff = nR = frictional force

m is the Mass

a is the acceleration

Substitute the given values

Fn - nR = ma

Fn - tan31°(mgcostheta) =3.9(9.8)

Fn - tan31(3.9(9.8)cos31) = 3.9(9.8)

Fn - tan31(38.22cos31)= 38.22

Fn - 32.76tan31 = 38.22

Fn-19.68 = 38.22

Fn = 38.22+19.68.

Fn = 57.90N

Hence Fn (moving force) of the inclined block is 57.90

What happens to force when two charges move away?

Answers

If the distance between the two charges is doubled, the attraction or repulsion becomes weaker.

Explanation:

The momentum of an object is determined by the object’s mass and velocity. Which object has more momentum?

Answers

Answer:

You need to give the options but the formula is p=mv

Explanation:

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