Given the following discrete probability mass function (f(x)): f(x) 1/4 1/8] 1/4 3/8 Find the following probabilities: a) P(x = 3) = b) P(x < 4) = c) P(x > 3) = d) P(2

Answer:

In picture

For 14, you can think of your own way to remember

Step-by-step explanation:

Answer:The answer is - 1.

Step-by-step explanation:

First I found how much the top equals.

0.3452 x 98.56 = 34.022912

Then, I found how much the bottom equaled.

0.06541 x 451 = 29.49991

Then I divided the top from the bottom. And the answer I got is below.

0.3452 x 98.56 / 0.06541 x 451 = 1.153322569

I HOPE THIS HELPED! :)

Answer : The incorrect step is, (A) step 1: -10 + 6x > 8

Step-by-step explanation :

The given expression is:

\(-4(\frac{5}{2}+\frac{3}{2}x)>8\)

Now solving this expression step by step.

First -4 distributed over parentheses.

\((-4\times \frac{5}{2})+(-4\times \frac{3}{2}x)>8\)

Now solving bracket term, we get:

\(-10-6x>8\)

Now taking like terms together, we get:

\(-6x>8+10\)

\(-6x>18\)

\(-x>3\)

Now multiplying this expression by (-1), we get:

\(x>-3\)

Thus, the incorrect step is, (A) step 1: -10 + 6x > 8

Answer:

A. Step 1: -10 + 6x > 8

Step-by-step explanation:

The correct way:

Step 1: Multiply both sides by \(-1\) (reverse the inequality)

\(\left(-4\left(\frac{5}{2}+\frac{3}{2}x\right)\right)\left(-1\right)<8\left(-1\right)\)

Step 2: Simplify

\(4\left(\frac{5}{2}+\frac{3}{2}x\right)<-8\)

Step 3: Divide both sides by 4

\(\frac{4\left(\frac{5}{2}+\frac{3}{2}x\right)}{4}<\frac{-8}{4}\)

Step 4: Simplify

\(\frac{5}{2}+\frac{3}{2}x<-2\)

Step 5: Subtract \(\frac{5}{2}\) from both sides

\(\frac{5}{2}+\frac{3}{2}x-\frac{5}{2}<-2-\frac{5}{2}\)

Step 6: Simplify

\(\frac{3}{2}x<-\frac{9}{2}\)

Step 7: Multiply both sides by 2

\(2\cdot \frac{3}{2}x<2\left(-\frac{9}{2}\right)\)

Step 8: Simplify

\(3x<-9\)

Step 9: Divide both sides by 3

\(\frac{3x}{3}<\frac{-9}{3}\)

Step 10: Simplify

\(x<-3\)

The assumption for linear regression analysis that is violated when the dependent variable is binary is the linearity of observed and predicted values. Binary variables only take on two values (0 or 1), and thus cannot be plotted on a linear regression line. Therefore, linear regression analysis is not appropriate for binary variables. Logistic regression is a more appropriate analysis method for binary variables.

Hi! If the dependent variable is binary and linear regression analysis is used, then the assumption for linear regression analysis that is violated is the "normality of error." This is because binary variables, which take only two values (e.g., 0 and 1), do not follow a continuous normal distribution, and thus, the errors in prediction are not likely to be normally distributed. Linear regression is designed for continuous dependent variables, so it's not ideal for analyzing binary outcomes.

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In solving simple probability questions, the calculations involved are usually straightforward. The key lies in identifying the applicable concepts and selecting the appropriate tools or formulas. Equally important is recognizing when these tools do not apply, enabling proper interpretation of data.

Understand the problem: Carefully read and comprehend the question to determine what information is given and what needs to be calculated. Identify the relevant concepts and tools that can be utilized.

Select the appropriate formula: Based on the problem statement and the involved concepts, choose the relevant formula or method to calculate the probability or confidence interval. Examples include the addition rule, multiplication rule, or Bayes' theorem.

Apply the given information: Substitute the known values into the formula, ensuring proper assignment and consistency of units.

Perform the calculations: Use mathematical operations to compute the desired probability or confidence interval. Take note of any special conditions or considerations mentioned in the problem.

Provide a clear answer: Express the result in a well-formatted manner. For probability questions, the answer may be a single value or a range, depending on the problem. Confidence interval questions require a properly formatted statement that includes the estimated parameter, range, and confidence level.

Validate and interpret the answer: Review the calculations for accuracy, and round the answer if necessary. Additionally, interpret the result within the context of the problem, providing explanations or conclusions as needed.

By practising with a variety of probability problems and confidence interval questions, you can improve your ability to identify relevant concepts and select the appropriate tools to solve them accurately. Furthermore, this practice will enhance your skills in recognizing when others may be misusing or misinterpreting data in real-world scenarios.

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im not sure but I think its D. 0.29 correct me if I’m wrong don’t trust my answer fully since I’m not for sure it’s d

If the price of 8.4 ounces of crackers is $2.42. Then $3.47 is the unit price

A unit of measurement is a definite magnitude of a quantity, defined and adopted by convention or by law, that is used as a standard for measurement of the same kind of quantity.

Given,

The price of 8.4 ounces of crackers is $2.42

We need to find the unit price.

We just need to divide eight point four ounces by two point four two.

8/2.42

3.47

Hence $3.47 is the unit price.

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Answer:

1 and 5

Step-by-step explanation:

So basically corresponding angles are the angles which lie on the same line of the transversal

And also one of them will be an interior angle and the other a exterior angle

Answer:

D

Step-by-step explanation:

Answer:

ABC≅DEF ASA POSTULATE

There must be two angles and one side of ABC congruent to DEF

Step-by-step explanation:

Answer:

BC=EF

Step-by-step explanation:

Process of elimination and I just took the test so trust me.

In both cases, the subject term (S) and the predicate term (P) are distributed, which means that the proposition makes a claim about the entire class of S and the entire class of P.

Traditional categorical logic, a proposition with both of its terms (subject and predicate) distributed is called a universal proposition.

Stronger claim than a particular proposition.

A universal proposition is a statement that applies to all members of a category or class.

Asserts that the subject term is either entirely included or entirely excluded from the predicate term.

There are two types of universal propositions:

Universal affirmative proposition (A): All S are P.

Universal negative proposition (E): No S are P.

"All mammals are warm-blooded" is a universal affirmative proposition (A) because it claims that the subject term (mammals) is entirely included in the predicate term (warm-blooded).

It distributes both terms and claims the most knowledge.

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There are a few different contexts in which the concept of continuity arises, and the specific conditions that must be satisfied for something to be considered continuous can vary depending on the context. Here are three common sets of conditions that are often used to define continuity:

In mathematics, a function is generally considered to be continuous if it satisfies the following three conditions:

In physics, a physical quantity is generally considered to be continuous if it can vary smoothly and continuously over a range of values, rather than taking on only discrete values.

In computer science, a function is generally considered to be continuous if it satisfies the following three conditions:

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There are a few different contexts in which the concept of continuity arises, and the specific conditions that must be satisfied for something to be considered continuous can vary depending on the context. Here are three common sets of conditions that are often used to define continuity:

In mathematics, a function is generally considered to be continuous if it satisfies the following three conditions:

In physics, a physical quantity is generally considered to be continuous if it can vary smoothly and continuously over a range of values, rather than taking on only discrete values.

In computer science, a function is generally considered to be continuous if it satisfies the following three conditions:

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The dimensions of the poster with the smallest area are = 64cm X 56cm where Width of the poster is 64 and Height of the poster is 56.

In order to establish a condition equation that represents the printed area's width (w) in terms of its height (h), we must first use what we know about the printed area.

Ap(w,h)=wh                   [Printed area]

Ap(w,h)=wh                  [ Substitute Ap(w,h)=1536]

1536=wh

w=1536h                      [width  ''w''  in terms of height ''h'' ]

The smallest surface area must be determined. We need to find out the area as a function of the variable h using the condition equation.

W=w+16                                              [ Width  of the rectangular poster ]

H=h+24                                                 [ Height  of the rectangular poster ]

Ar(w,h)=(w+16)(h+24)                        [Area of the rectangular poster ]

Ar(w,h)=(w+16)(h+24)

Put the value of W in terms of ‘h’ that we got above.

Ar(w)=(1536h+16)(h+24)

Ar(w)=36864h+16h+1920

Ar(w)=36864/w+16w+1920           (objective function)

Determine the domain of objective function

D={w∈R:w>0}                           [Domain of the Objective area function]

Ar(w)=36864/w+16w+1920

A′r(w)=−36864w2+16              [First derivative of the Objective area function]

A′r(w)=0                                     [critical point condition]

−36864/w2+16=0

16=36864/w2

w2=36864/16

w2=2304

w=±48

w=−48                       [w=−48∉D]

w=48                         [w=48∈D]

w=48                        [Critical point of the Objective area function ]

Applying sufficient condition for extremes (Second derivative test)

A′r(w)=−36864/w2+16

A′′r(w)=73728/w3[Second derivative of the Objective area function]

A′′r(48)=0.6                     [A′′r(48)>0]

w=48                                [Minimum point of the Objective area function ]

Calculate the dimensions of the rectangular poster with minimum area

w=48 Width of the print area

h=1536/48=32           (Height of the print area)

W=48+16=64             (Width of the rectangular poster)

H=32+24=56             (Height of the rectangular poster)

The dimensions of the poster with the smallest area are: ⟹64cm×56cm

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Answer:

I'm pretty sure it's the last one !

Step-by-step explanation:

Good luck on your quiz!!

Hope you have a good day

:)

Answer:

The midpoint is

Step-by-step explanation:

The midpoint M of two endpoints of a line segment can be found by using the formula

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

P(0, -2) and Q(5,3)

The midpoint is

We have the final answer as

Hope this helps you

Probability distribution is an assignment of probabilities to each distinct value of a discrete random variable or to each interval of values of a continuous random variable.

What is Probability ?

What is the probability of each value of a discrete random variable?

The probability P(x) that a discrete random variable X will take the value x in one trial of the experiment is connected to each possible value x of the variable.

Which is a discrete random variable?

What is the other name of mean of discrete random variable?

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Answer:

15x - 52

Step-by-step explanation:

Hi,

All you have to do is combine like terms. 4x + 11x is 15x. 9 + (-61) is simply -52.

Hope this helps :)

Answer:

15x-52

Step-by-step explanation:

Answer:

Parallel lines never intersect, but they must be in the same plane. The definition does not require the undefined term point, but it does require plane. Because they intersect, perpendicular lines must be coplanar; consequently, plane is not required in the definition.

Hope it helped u if yes mark me BRAINLIEST!

Tysm!

The probability of the selected coin showing heads is 0.77, or 77%.

Probability is the measure of the likelihood of an event occurring. In this scenario, we have three coins in a box, each with different properties.

To calculate the probability of an event occurring, we need to divide the number of favorable outcomes by the total number of possible outcomes. In this case, there are three possible coins we could select, each with a different probability of showing heads.

Now, we need to determine the total number of possible outcomes, which is simply the number of coins we have, which is three.

Next, we need to determine the number of favorable outcomes. For Coin 1, the probability of showing heads is 1 (since it has two heads). For Coin 2, the probability of showing heads is 0.5 (since it is a fair coin with equal probability of heads and tails). For Coin 3, the probability of showing heads is 0.8.

To calculate the probability of showing heads when we randomly select one of these coins, we need to weigh the probabilities of each coin being selected with their corresponding probabilities of showing heads.

Let's say that the probability of selecting each coin is equal (since we have no information to suggest otherwise). Then, the probability of selecting Coin 1 is 1/3, the probability of selecting Coin 2 is 1/3, and the probability of selecting Coin 3 is 1/3.

To calculate the overall probability of showing heads, we can use the following formula:

P(heads) = (P(Coin 1) * P(heads on Coin 1)) + (P(Coin 2) * P(heads on Coin 2)) + (P(Coin 3) * P(heads on Coin 3))

= (1/3 * 1) + (1/3 * 0.5) + (1/3 * 0.8)

= 0.77

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Using proportions, it is found that the mean time between arrivals is of 12 minutes.

The rule of three is:

5 trucks - 60 minutes

1 truck - x minutes

Applying cross multiplication:

\(5x = 60\)

\(x = \frac{60}{5}\)

\(x = 12\)

The mean time between arrivals is of 12 minutes.

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Answer: 40

Step-by-step explanation:

a) 16 students prefer burgers only.

b) 19 students prefer fries only.

c) 43 students prefer burgers or fries.

d) 0 students prefer neither burgers nor fries.

To find the number of students who prefer burgers only, we subtract the number of students who prefer both from the total number of students who prefer burgers:

a) Students who prefer burgers only = Total students who prefer burgers - Students who prefer both = 28 - 12

= 16

To find the number of students who prefer fries only, we subtract the number of students who prefer both from the total number of students who prefer fries:

b) Students who prefer fries only = Total students who prefer fries - Students who prefer both = 31 - 12

= 19

To find the number of students who prefer burgers or fries, we add the number of students who prefer burgers only, the number of students who prefer fries only, and the number of students who prefer both:

c) Students who prefer burgers or fries = Students who prefer burgers only + Students who prefer fries only + Students who prefer both

= 16 + 19 + 12

= 43

To find the number of students who prefer neither burgers nor fries, we subtract the total number of students who prefer burgers or fries from the total number of students:

d) Students who prefer neither burgers nor fries = Total students - Students who prefer burgers or fries = Total students - (Students who prefer burgers only + Students who prefer fries only + Students who prefer both) = Total students - 43

= Total students - 43

= 0

a) 16 students prefer burgers only.

b) 19 students prefer fries only.

c) 43 students prefer burgers or fries.

d) 0 students prefer neither burgers nor fries.

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The density value of 2.865 g/cm³ rounded to the nearest tenth is 2.9 g/cm³.

To round the density value of 2.865 g/cm³ to the nearest tenth, we look at the digit in the hundredth place, which is 6. Since 6 is greater than or equal to 5, we round up the digit in the tenths place, which is 6 in this case. The digit in the tenths place increases by 1, resulting in a rounded value of 2.9 g/cm³.

Rounding to the nearest tenth means that we are considering the value of the digit immediately to the right of the tenths place (hundredth place). If this digit is 5 or greater, we round up by increasing the digit in the tenths place by 1. If the digit is less than 5, we simply keep the digit in the tenths place as it is.

In the case of 2.865 g/cm³, the digit in the hundredth place is 6, so we round up the tenths digit to 9, resulting in a rounded value of 2.9 g/cm³.

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Answer: -3

Step-by-step explanation:

The set of integers is a set of numbers that includes all negative numbers, all positive numbers, and zero.

Examples of integers are -4, 7, 0, -17.

Note that 1/2 is not an integer, but rather a rational number.

So now that we know what integers are, we will answer our question.

Which number is an integer? -3, -4, 1, -5, 2, 4, 2/3

In fact, all of these are integers, except 2/3.

Answer:

D

Step-by-step explanation:

1.71

Answer:

True- She needs $3 more. She will not have enough money to buy everything. The cost is $28.

False- She has $3 left over.

Step-by-step explanation:

2 pounds of burgers for $3 each is $6

1 bag o bun equals $2

5 bags of chips for $4 each is $20

$20 + $6 +$2 = $28

She only had $25 to spent, so she doesn't have enough money and needs to 3 more dollars.

Answer:

Ionic Compound

Step-by-step explanation:

:D

Answer:

c

Step-by-step explanation:

-2 (9+32n) turns them both negative and makes them the numbers in said expression

Answer:

zero

Step-by-step explanation:

zero divided by any number is zero