given the formula p=mv what are the units of p

Answer: C. Bedrock structure and evolution of land surfaces.

Explanation:

Landscape has to do with the visible features of a particular area of land, and its landforms, and their integration with the both the man-made features and the natural features.

The characteristics best distinguish one landscape region from another include the bedrock structure and evolution of land surfaces.

Answer:

a

hydroelectric dams on the Columbia river

Explanation:

Answer:

-5.625 m/s^2

Explanation:

Use the kinematic equation \(v_{f}^{2} = v_{o}^{2} + 2ad\)

Substitute the values and solve for a.

0^2 = 75^2 + a 2 (500)

0 = 5625 + 1000a

-5625 = 1000a

-5.625 = a

Answer:

(This will depend on the type of fuel, I will assume that the fuel is petrol)

First, let's find the expected energy consumption in the US for the next 10 years.

We know that in one year, a person consumes 3.5*10^11 joules.

There are 310,000,00 people on the US

Then the total consumption in one year is:

310,000,000*3.5*10^11 joules = 1.085*10^20 J

In 10 years the consumption is 10 times the consumption of a single year, then the expected energy consumption in the US for the next 10 years is:

10*1.085*10^20 J = 1.085*10^21 J

Now let's find the mass of fuel required.

We know that a liter of petrol has 31,536,000 joules of energy,

And a liter of petrol weights 0.75 kg

To find the number of liters of petrol that we need, we need to find the quotient between the expected energy consumption in the next 10 years and the energy of a single liter of petrol, this is:

N = (1.085*10^20 J)/(31,536,000 j) = 3.44*10^13

We will need  3.44*10^13 liters of petrol.

And the total mass of petrol will be:

M = 3.44*10^13*0.75 kg = 2.58*10^13 kg of fuel.

The position of the center of mass of the Earth-Moon system is located 4,676 kilometers from the center of the Earth.

First, let us recall the formula for the center of mass, which is:

center of mass = (m1r1 + m2r2)/(m1 + m2)

where,

m1 and m2 are the masses of the two objects

r1 and r2 are their distances from the reference point

Earth: m1 = 5.97 x 10^24 kg,

r1 = 0 km

Moon: m2 = 7.35 x 10^22 kg,

r2 = 384,400 km (3.84 x 10^8 m)

We can ignore the radii of the two objects because they are negligible compared to their orbital radii. So the center of mass of the Earth-Moon system can be calculated as follows:

center of mass = (m1r1 + m2r2)/(m1 + m2)

= [(5.97 x 10^24 kg)(0 km) + (7.35 x 10^22 kg)(3.84 x 10^8 m)]/(5.97 x 10^24 kg + 7.35 x 10^22 kg)

= 4.67 x 10^6 m or 4,676 km from the center of the Earth

Therefore, the position of the center of mass of the Earth-Moon system is located 4,676 kilometers from the center of the Earth.

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A sequence diagram is a type of UML (Unified Modeling Language) diagram that shows the interactions between objects or components of a system as they occur in a chronological sequence.

It is a graphical representation of the interactions that take place between objects or components of a system, depicting the order of messages that are exchanged between them.

Sequence diagrams are used to visualize the flow of a system's functionality, as well as the communication and collaboration between the various components of the system. They are especially useful in understanding complex systems and identifying areas that may require improvement or optimization. Sequence diagrams are also often used to document and communicate the design of a system to stakeholders or development teams.

In summary, a sequence diagram shows the timing of interactions between objects or components of a system as they occur. It is a valuable tool in understanding and communicating the behavior and functionality of complex systems.

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1. The part that shows the body is accelerating is the first 2 hours (ABE). The acceleration is 20 Km/h²

2. The part that shows the body is coming to rest the last 2 hours (CDF)

3. The distance travelled in the first 2 hours is 40 Km

Acceleration is defined as the rate of change of velocity which time. It is expressed as

a = (v – u) / t

Where

From the diagram (ABE), we can see that the body starts from rest and attain a final velocity (40 Km/h) within the first 2 hours. This clearly indicates that the body is accelerating.

The acceleration can be obtained as followed:

a = (v – u) / t

a = (40 – 0) / 2

a = 20 Km/h²

From the diagram (CDF), we can see that the object velocity changes from 40 to 0 within the last 2 hours. This clearly indicates that the object caming to rest.

v² = u² + 2as

v² = 2as

s = v² / 2a

s = 40² / (2 × 20)

s = 40 Km

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If the flywheel's rotational velocity is constant and the force applied by the ant is strong enough, the ant will adhere to the wheel's rim without slipping.

In this case, the ant's tangential velocity will be the same as the wheel's tangential velocity, and the centripetal force acting on the ant will be supplied by the frictional force.Using F = ma, we know that a = v^2/r. We can then substitute the value for the angular velocity and wheel radius to get the centripetal acceleration.

The centripetal force on the ant is m*ac. This centripetal force is supplied by the ant's grip on the wheel. Since the ant can hold on to the wheel with a force much greater than its own weight, it is safe to assume that the force of the grip is greater than the centripetal force.

In conclusion, the force with which the ant must hold on to stay on the wheel at point III is equal to the centripetal force exerted on it, which is equal to its mass multiplied by its centripetal acceleration, which is equal to m*v^2/r.

The mass of the ant is given as 1 gram (0.001 kg), and the radius of the wheel is given as 0.4 m. The linear velocity v can be calculated using the formula v = ωr. Therefore, the force required to keep the ant on the wheel at point III is:F = m*v^2/rF = 0.001*[(2*2*3.14*0.4)^2]/0.4F = 9.92 N (approximately)

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Answer:

This is not a question-

Explanation:

Answer:

40n

Explanation:

test taken

The voltages across the resistor, capacitor, and inductor are 12.0 V, 23.4 V, and 40.2 V, respectively.

First, let's calculate the total impedance of the circuit, which is the total opposition to the flow of current:

Z = R + Xc + Xl

where R is the resistance, Xc is the capacitive reactance, and Xl is the inductive reactance.

R = 15.0 ohms (given)

Xc = 1/(2πfC) = 1/(2π(1400 Hz)(3.80 × 10^-6 F)) = 29.3 ohms

Xl = 2πfL = 2π(1400 Hz)(5.70 × 10^-3 H) = 50.3 ohms

Z = 15.0 + 29.3 + 50.3 = 94.6 ohms

Now, we can find the voltage across each component using the voltage divider rule:

V = IRX

where I is the current in the circuit, and RX is the resistance, capacitive reactance, or inductive reactance of the component.

To find the current, we can use Ohm's law:

V = IR

I = V/R = (12.0 V)/(15.0 ohms) = 0.8 A

Voltage across the resistor:

VR = IR = (0.8 A)(15.0 ohms) = 12.0 V

Voltage across the capacitor:

VC = IXc = (0.8 A)(29.3 ohms) = 23.4 V
Voltage across the inductor:

VL = IXl = (0.8 A)(50.3 ohms) = 40.2 V

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Answer:

Well if they playing a game like that

(a) The velocity of the ball after 7 seconds is approximately 68.6 m/s.

(b) The ball is traveling at a speed of approximately 95.4 m/s when it hits the ground.

To determine the velocity of the ball after 7 seconds and its speed when it hits the ground, we can use the equations of motion under constant acceleration.

(a) The initial velocity of the ball is zero since it is dropped from rest. The acceleration due to gravity is approximately \(9.8 m/s^2\) (assuming no air resistance). Using the equation v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time, we can calculate the velocity after 7 seconds:

\(v = 0 + (9.8 m/s^2) * 7 s = 68.6 m/s\)

Therefore, the velocity of the ball after 7 seconds is approximately 68.6 m/s.

(b) To find the speed of the ball when it hits the ground, we need to determine the time it takes for the ball to fall from a height of 450 m. We can use the equation \(s = ut + (1/2)at^2\), where s is the displacement, u is the initial velocity, a is the acceleration, and t is the time. Rearranging the equation, we have \(t^2 = (2s) / a\).

\(t^2 = (2 * 450 m) / (9.8 m/s^2) = 91.84 s^2\)

Taking the square root, t ≈ 9.59 s

Now, we can calculate the final velocity using the equation v = u + at:

\(v = 0 + (9.8 m/s^2) * 9.59 s ≈ 94.1 m/s\)

Hence, the ball is traveling at a speed of approximately 94.1 m/s when it hits the ground.

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Answer:

-3m+7m =  4m

Explanation:

As he walks south, he is going down 3m (-3m). Then he walks up 7m (+7m).

You subtract the final position from the initial position to get displacement.

7m - 3m = 4m

Answer:

c

Explanation:

Taking into account the Newton's second law, the acceleration of the 100 g mass is 50 m/s².

Newton's second law states that this force will change the speed of an object because the acceleration and/or direction will change.

So, Newton's second law defines the relationship between force and acceleration mathematically. This law says that the acceleration of an object is directly proportional to the sum of all the forces acting on it and inversely proportional to the mass of the object:

F= m×a

where:

In this case, you know:

Replacing in Newton's second law:

5 N= 0.1 kg× a

Solving:

a= 5 N÷ 0.1 kg

a= 50 m/s²

Finally, the acceleration is 50 m/s².

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When there are two currents flowing in opposite direction the magnetic field are moving in the same directions. When the currents flow in the same direction the magnetic field will be opposite, causing the wires to attract.

The term used to describe the sliding motion within the layers of an object is "shear."

Shear refers to the deformation that occurs when layers of a material slide or move in relation to each other, parallel to their planes. This type of motion can happen in various materials, including solids, fluids, and even gases.

In the context of solids, shear can occur when a force is applied parallel to a surface or when there is a difference in movement between adjacent layers.

This can lead to the layers sliding past one another, resulting in a shearing or shearing deformation. Shear can cause changes in shape, stress distribution, and material properties within the object.

Shear is an essential concept in fields such as materials science, engineering, and physics.

Understanding shear behavior is crucial for designing structures, analyzing material properties, and predicting the response of materials under different loads and conditions.

Various mathematical models and equations, such as the shear stress and shear strain relationship, are used to quantify and describe shear deformation in materials.

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0.017 is the probability that tab A won’t fit into slot B

Probability is related to possibility. Random event generation is the subject of this branch of mathematics. Values ​​range from 0 to 1. Probabilities are built into mathematics to predict the likelihood of certain events.

P(tab A won't fit into slot B) = P (A>B)

                                                = P( A-B > 0)

Given that, A ≈ N(30,0.5)   B ≈ N(32, 0.8)

Here,

E (A-B) = 30-32 = -2

V(A-B) = V(A) + V(B) = (0.5)² + (0,8)²

                                   = 0.89

SD (A-B) = \(\sqrt{0.89}\)

So, (A-B) ≈ N (-2, 0.9433)

P( A-B > 0) = 1 - P(A-B ≤ 0)

= 1 - P [(A - B +2 / 0.9433) ≤ (+2 / 0.9433)]

= 1 - P (Z₁ ≤ 2.12)

= 1 - 0.98300

= 0.017

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Answer:

yes

Explanation:

1.98×10 m/s

you can use a physics text

I remember but am not sure

3.00 × 10 m/s

I think you do 10 ×10 in 8 places for both them you do the rest

A. The average drift speed of the electrons in the wire is  1.19 x \(10^{-3}\)cm/s.

B. The time it would take an electron to travel 8.84 m is 7.43 x \(10^{5}\)sec

(A) To find the average drift speed of electrons in a wire, we can use the equation:

I = nAvq

Where:
I is the current in Amperes
n is the electron density in electrons per \(cm^{3}\)
A is the cross-sectional area of the wire in \(cm^{2}\)
v is the average drift velocity of electrons in cm/s
q is the charge of an electron, which is 1.6 x \(10^{-19}\) Coulombs

First, we need to find the cross-sectional area of the wire. The formula for the area of a circle is:

A = π\(r^{2}\)

Where:
A is the area of the circle
r is the radius of the circle

Given that the wire diameter is 1.63 mm, we can find the radius by dividing it by 2:

r = 1.63 mm / 2 = 0.815 mm = 0.0815 cm

Now, we can calculate the area:

A = \(π(0.0815 cm)^{2}\) = 0.0209 \(cm^{2}\)

Next, we can rearrange the equation to solve for v:

v = I / (nAq)

Given that the current is 20 A and the electron density is 8.47 x \(10^{24}\)electrons per \(cm^{3}\), we can substitute these values into the equation:

v = 20 A / (8.47 x \(10^{24}\) electrons per cm^3 * 0.0209 cm^2 * 1.6 x \(10^{-19}\) C)

Simplifying the expression:

v = 1.19 x \(10^{-3}\) cm/s

Therefore, the average drift speed of electrons in the 14 gauge wire carrying a maximum current of 20 A is approximately 1.19 x \(10^{-3}\) cm/s.

(B) To calculate the time it would take for an electron to travel a distance of 8.84 m, we can use the formula:

t = d / v

Where:
t is the time in seconds
d is the distance in meters
v is the average drift velocity of electrons in meters per second

Given that the distance is 8.84 m and the average drift velocity is 1.19 x 10^-3 cm/s, we need to convert the velocity to meters per second:

v = 1.19 x \(10^{-3}\) cm/s * 0.01 m/cm = 1.19 x \(10^{-5}\) m/s

Now, we can substitute the values into the formula:

t = 8.84 m / 1.19 x \(10^{-5}\)m/s

Simplifying the expression:

t = 7.43 x \(10^{5}\)s

Therefore, it would take approximately 7.43 x \(10^{5}\) seconds for an electron to travel a distance of 8.84 m.

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Formula for momentum is  45 kg* m/s = (9 kg) (5 m/s). The last option is the correct answer.

This can be defined as the product of the mass and velocity of an object. It is measured in  Kilograme meters per second, kgm/s.

momentum Ρ= mass*velocity

                    =m*v

m=9kg

v=5m/s

Ρ=m*v

45 kg* m/s  =9kg*5m/s

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Answer:

B

Explanation:

One object speeds up before it slows to a stop.

When reading this type of graph, we know that when the points are far apart, then the object is definitely moving quickly. Also again, we know that when the points are besides each other, then we say that the object is moving slow. When the distance that is between the points are changed, the velocity of the object subsequently changes too, and therefore, we say that the object is accelerated. When there are lots of points in one location, we will see that the object is not moving.

This then translates into that

The object(s) at the top begins to slow, eventually, it increases in its speed, going forward, it slows down again, before it finally halts. The object at the bottom on the other hand, starts fast, before slowing down.

then:

"One object speeds up before it slows to a stop "

The acceleration of the proton by using Coulomb's law is 2.806 m/s²

The acceleration of a proton can be defined by using coulombs force and centripetal acceleration. The value of coulomb force is

Fc = k.q1.q2 / d²

where Fc is coulomb force, k is Coulomb's constant, q is charge and d is distance.

Centrifugal force will also same as coulomb force, which can be determined as

F = m.a

where F is centrifugal force, m is mass and a is acceleration.

From the question above, we know that:

q1 = q2 = e = 1.602176634×10‾¹⁹ C

k = 8.988×10⁹ N⋅m²⋅C‾²

m = 1.673 x 10‾²⁴ kg

d = 7 x 10‾³ m

By combining these equations, we get

F = Fc

m.a = k.q1.q2 / d²

a = k.e² / m.d²

Substitute the parameter

a = 8.988×10⁹ . (1.6×10‾¹⁹)² / ( 1.673 x 10‾²⁴ . ( 7 x 10‾³ )² )

a = 2.806 m/s²

Hence, the acceleration of the proton by using Coulomb's law is 2.806 m/s²

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Answer:

Distance is 50m

Displacement is 0m

Explanation:

Distance is based on the amount of length you covered, regardless of where you end.

Displacement only considered where you started and where you ended, which is at the same spot in this case. Therefore, no displacement.

Answer:

To make it around the circle, the tension in the string must provide the necessary centripetal force to keep the ball moving in a circle. At the top of the circle, the tension in the string must provide all the force to keep the ball moving in a circle. At the bottom of the circle, the tension in the string must provide the centripetal force in addition to the force of gravity.

We can use the centripetal force formula to solve for the minimum velocity: F_c = m * a_c

where F_c is the centripetal force, m is the mass of the ball, and a_c is the centripetal acceleration.

At the top of the circle, the centripetal force is equal to the tension in the string: F_c = T

where T is the tension in the string.

At the bottom of the circle, the centripetal force is equal to the sum of the tension in the string and the force of gravity:

F_c = T + mg

where m is the mass of the ball, g is the acceleration due to gravity (9.8 m/s^2), and T is the tension in the string.

The centripetal acceleration is given by: a_c = v^2 / r

where v is the velocity of the ball and r is the radius of the circle.

Since the circle has a radius of 0.33 m, we can substitute this into the equation for a_c: a_c = v^2 / 0.33

Combining these equations, we get:

At the top of the circle: T = m * v^2 / 0.33

At the bottom of the circle: T + mg = m * v^2 / 0.33

We can solve for the minimum velocity by using these two equations to eliminate the tension in the string: m * v^2 / 0.33 + mg = m * v^2 / 0.33

Simplifying this equation, we get: v = sqrt(0.33 * g)

Plugging in the values, we get: v = sqrt(0.33 * 9.8) = 1.81 m/s

Therefore, the minimum velocity that the ball must have to make it around the circle is 1.81 m/s

Answer:

U = 66,150 J

Explanation:

Gravitational Potential Energy

Gravitational potential energy is the energy stored in an object because of its vertical position or height in a gravitational field.

It can be calculated with the equation:

U=m.g.h

Where m is the mass of the object, h is the height with respect to a fixed reference, and g is the acceleration of gravity or \(9.8\ m/s^2\).

The child of mass m=45 Kg is perched above a h=150 m ravine. His gravitational potential energy is:

\(U=45~Kg\cdot 9.8\ m/s^2\cdot 150\ m\)

U = 66,150 J

The cell boundary's net flux measures -0.887 \(Wb.m^{2}\) in both magnitude and direction (inward or outward).

Any impact that seems to flow through or move through a surface or substance is referred to as a magnetic flux. The following formulas are used to determine the size and direction (inward or outward) of the net flux through the cell boundary:

Ф = Q/ε, where:

Q is the net charge

ε is the permittivity of free space.

As per the question,

Φ = (-7.85 x 10⁻¹²)/ (8.85 x 10⁻¹²)

Φ = - 0.887 Wb.m²

The negative sign here indicates the outward flow of the flux. Magnetic flux is a measure of the strength of a magnetic field over a specific area, to put it simply. It has [\(ML^{2} T^{-2} A^{-1}\)], as the dimension of mass length squared per square of time and electric current.

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Complete question is:

The human nerve cells have a net negative charge and the material in the interior of the cell is a good conductor. if the cell has a net charge of - 7.85 pc, what are the magnitude and direction (inward or outward) of the net flux through the cell boundary.

Answer:

0.45m/s

Explanation:

Given parameters:

Distance = 1.8m

Time  = 4s

Unknown:

Speed of the car  = ?

Solution:

The speed of a body is the distance divided by the time.

       Speed  = \(\frac{distance}{time}\)  

So;

     Speed  = \(\frac{1.8}{4}\)   = 0.45m/s

The unit abbreviation that represents a measurement of force is C. N, which stands for Newton.

ewton is the force unit derived from the International System of Units (SI). It is named after Sir Isaac Newton, widely acknowledged as one of the most influential scientists of all time. The force required to accelerate a mass of one kilogram at a rate of one meter per second squared (m/s2) is referred to as one Newton.

Choice A, m/s, addresses an estimation of speed or speed (meters each second), while

choice B, m/s², addresses an estimation of speed increase (meters each second squared), which is connected with force, however not the unit of power itself.

Choice D, N/s, addresses an estimation of the pace of progress of power after some time, which is certainly not a generally involved unit in physical science.

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My primary mode of transportation is a car, and its energy efficiency is typically around 3 kW-hrs per 100 person-km.

As my primary mode of transportation, I rely on a car for commuting and traveling. While cars offer convenience and comfort, they are not the most energy-efficient option. On average, a car consumes approximately 3 kW-hrs of energy per 100 person-km. This energy consumption includes the fuel or electricity required to power the vehicle and accounts for the energy losses during the generation, distribution, and storage processes.

The energy efficiency of a car can vary depending on several factors, including the vehicle's make and model, driving conditions, and driving habits. Factors such as speed, acceleration, and braking can impact fuel consumption and efficiency. Additionally, the type of fuel or power source used by the car influences its energy efficiency. Electric vehicles (EVs) tend to have higher energy efficiency compared to traditional internal combustion engine (ICE) vehicles, as they convert a higher percentage of their energy into forward motion.

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