Given the reaction: 3 C + 2 Al2O3 → 4 Al + 3 CO2, if 12 moles of aluminum are produced, how many moles of carbon reacted, assuming a 100% yield? Write your answer as a whole number. When gaseous nitrogen and gaseous hydrogen are reacted at high temperatures in the presence of a catalyst, ammonia (and no other product) is formed. If a chemical plant has to synthesize 250 kg of ammonia, what mass (in kilograms) of hydrogen has will be required, assuming 100% yield? (Use molar masses: H2 = 2.0, N2 = 28.0, NH3 = 17.0 g/mol.) Give your answer to the nearest whole number.

Answers

Answer 1

Given the reaction:3 C + 2 Al2O3 → 4 Al + 3 CO2, 12 moles of aluminum are produced; we need to determine how many moles of carbon reacted. The balanced chemical equation is:3 C + 2 Al2O3 → 4 Al + 3 CO2From the balanced equation.

Moles of carbon will react with 2 moles of Al2O3 to form 3 moles of CO23 moles of carbon will react with 4 moles of Al to form 3 moles of CO2Therefore, the ratio of carbon to aluminum is 3:4 or 0.75:1.To find the number of moles of carbon reacted, we will multiply the moles of aluminum by the ratio of carbon to aluminum:12 moles of aluminum × 0.75 moles of carbon / 1 mole of aluminum = 9 moles of carbon Therefore, 9 moles of carbon reacted. Given To synthesize 250 kg of ammonia (NH3), we need to determine the mass of hydrogen gas required. The balanced equation for the reaction is:N2 + 3 H2 → 2 NH3From the balanced equation:1 mole of nitrogen (N2) reacts with 3 moles of hydrogen (H2) to form 2 moles of ammonia (NH3)The molar masses (in g/mol) are:H2 = 2.0 g/molN2 = 28.0 g/molNH3 = 17.0 g/mol.

Using these molar masses, we can calculate the number of moles of NH3:250 kg = 250,000 g Number of moles of NH3 = mass / molar mass = 250,000 g / 17.0 g/mol = 14,705.88 mol Since the ratio of hydrogen to ammonia is 3:2, we can find the number of moles of hydrogen:2 moles of NH3 will react with 3 moles of H2Therefore, 14,705.88 mol of NH3 will react with:14,705.88 mol of NH3 × 3 mol of H2 / 2 mol of NH3 = 22,058.82 mol of H2Finally, we can calculate the mass of hydrogen in kilograms Mass of hydrogen = number of moles of H2 × molar mass of H2 / 1000= 22,058.82 mol × 2.0 g/mol / 1000 = 44.12 kg ≈ 44 kg Therefore, the mass of hydrogen required to synthesize 250 kg of ammonia is approximately 44 kg.

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Related Questions

How many protons, neutrons, and electrons does cobalt-60 have? Is this a "normal" isotope of cobalt and how do you know?

Answers

Cobalt-60 has 27 protons (thus 33 neutrons). If an inter-nucleus neutron decays and emits an electron, this neutron transforms into a proton. Now we have 28 protons and 32 neutrons.

What experimental evidence led Rutherford to conclude the following: (a) The nucleus of the atom contains most of the atomic mass. The nucleus of the atom contains most of the mass since only a collision with a very dense, massive object would cause an alpha particle to be the source. (b) The nucleus of the atom is positively charged. The positive alpha particles their initial flight indicating that the nucleus of the atom is also positively charged. (c) The atom consists of mostly empty space. Most alpha particles pass through the gold foil leading to the conclusion that the atom is mostly empty space.

Answers

Answer:

See Explanation

Explanation:

The experiment of Ernest Rutherford involved the bombardment of a thin gold foil with alpha particles from a radioactive source. A zinc sulphide screen was used to follow the movement of the alpha particles.

It was discovered that most of the alpha particles followed a straight path through the gold foil. Some of them were scattered through large angles and few were even scattered in the backward direction.

Since alpha particles were heavier than electrons, they must have been deflected by very strong forces.

These experimental evidences led to the conclusions stated in the question.

Balance the following equations by inserting the proper coefficients.

Answers

The question is incomplete, the complete question is;

Balance the following equations by inserting the proper coefficients.

CH4 + O2 ---------------> CO2 +H2O

CaCl2 + AgNO3 ----->Ca(NO3)2 +AgCl

C2H6O + O2----------->CO2 +H2O

Answer:

CH4 + 2O2 ---------------> CO2 +2H2O

2AgNO3 + CaCl2 → Ca(NO3)2 + 2AgCl

C2H6O + 3O2 → 2CO2 + 3H2O

Explanation:

You see, when we set out to balance chemical reaction equations, ultimately, our aim is to ensure that the number of atoms of each element on the reactant side is exactly the same as the number of atoms of the same element on the products side.

We do this by counting the number of atoms required to have a balanced reaction equation and then adding coefficients in order to have a balanced chemical reaction equation.

This is what have been done in balancing the three reaction equations shown in the answer section.

A student was titrating a solution of hydrazine (H. NNH) with a nitric acid solution. Determine the pH at a particular point in the titration. Do this by constructing a BCA table, constructing an ICE table, writing the equilibrium constant expression, and use this information to determine the pH

Answers

A student was titrating a solution of hydrazine with a nitric acid solution , the volume will be 50 ml and [HNO₃] in 50 ml solution = 0.020 M

Elaborating the given :

Total Volume = 40 ml + 10 ml = 50 ml

[NH₂H₂N] in 50 ml solution = 0.200 M *40 ml / 50 lm

= 0.160 M

[HNO₃] in 50 ml solution = 0.100 M * 10 ml / 50 ml

= 0.020 M

a. ICE Table

Reaction NH₂H₂N H⁺ ⇄ NH₂H₂NH⁺

I 0.160 M 0.020 M -

C -0.020 M -0.020 M +0.020 M

E 0.140 M 0 0.020 M

Reaction NH₂H₂N H₂O ⇄ NH₂H₂NH⁺ OH⁻

I 0.1400 M - 0.0200 M -

C ⁻x - ⁺x ⁺x

E 0.1400 -x 0.0200 +x x

c. Kb = [NH₂H₂NH⁺][OH⁻]/[NH₂H₂N]

Kb = [0.0200+x][x][0.1400 - x]

= 3.0 × 10⁻⁶

d. Because Kb is so small, the reaction will move insignificantly forward.

In either addition or substitution, x can be ignored.

[0.0200][x] / [0.1400 ]

= 3.0 × 10⁻⁶

=> x = 2.1 ×10⁻⁵ M = [OH-]

e. pOH = -log[OH⁻] = -log(2.1 ×10⁻⁵ )

= 4.68

pH = 14 -pH

= 14 - 4.68

= 9.32

Titrating a solution :

A titration is a method for determining the concentration of an unknown solution using a solution with a known concentration. Typically, the analyte (the unknown solution) is added to the titrant (the known solution) from a buret until the reaction is complete.

Incomplete question :

A student was titrating a solution of hydrazine (HNNH) with a nitric acid solution. Determine the pH at a particular point in the titration. Do this by constructing a BCA table, constructing an ICE table, writing the equilibrium constant expression, and use this information to determine the pH. Complete Parts 1-4 before submitting your answer. 1 2 3 4 NEXT > A 40.0 mL of 0.200 M HNNH, was titrated with 10 mL of 0.100 M HNO, (a strong acid). Fill in the ICE table with the appropriate value for each involved species to determine the moles of reactant and product after the reaction of the acid and base. You can ignore the amount of liquid water in the reaction. HNNH, (aq) + H+(aq) H,NNH,+(aq) Before (mol) Change (mol) After (mol) RESET 0 0.200 0.100 1.00 x 103 -1.00 x 103 2.00 x 109 -2.00 - 103 6.00 x 103 -6.00 x 10 7.00 x 10 -7.00 x 10 8.00 x 103 -8.00 x 103 A student was titrating a solution of hydrazine (HNNH) with a nitric acid solution. Determine the pH at a particular point in the titration. Do this by constructing a BCA table, constructing an ICE table, writing the equilibrium constant expression, and use this information to determine the pH. Complete Parts 1-4 before submitting your answer. < PREV 1 2 3 4 NEXT > Upon completion of the acid-base reaction, the H,NNH,+ ion is in equilibrium with water. Set up the ICE table in order to determine the unknown concentrations of reactants and products.. HNNH, (aq) H,O(1) OH(aq) + HNNH,+(aq) Initial (M) Change (M) Equilibrium (M) RESET 0 0.200 0.0200 0.100 0.140 0.175 +x -X 0.200 + x 0.200 - X 0.0200 + x 0.0200-X 0.100 + x 0.100 - x 0.140 + x 0.140 - x 0.175 + x 0.175 - x A student was titrating a solution of hydrazine (HNNH) with a nitric acid solution. Determine the pH at a particular point in the titration. Do this by constructing a BCA table, constructing an ICE table, writing the equilibrium constant expression, and use this information to determine the pH. Complete Parts 1-4 before submitting your answer. < PREV 1 2 3 4 NEXT > The Kb for HNNH, is 3.0 * 10º. Based on your ICE table and the equilibrium expression for kb, set up the expression for kb in order to determine the unknown concentrations. Each reaction participant must be represented by one tile. Do not combine terms. Кь = = 3.0 x 10-6 RESET [O] [0.200] [0.0200] [0.100] [0.140] [0.175) [x] [2x] [0.200 + x] [0.200 - x] [0.0200 + x] [0.0200 - x] [0.100 + x] [0.100 - x] [0.140 + x] [0.140 - x] [0.175 + x] [0.175 - x] A student was titrating a solution of hydrazine (HNNH) with a nitric acid solution. Determine the pH at a particular point in the titration. Do this by constructing a BCA table, constructing an ICE table, writing the equilibrium constant expression, and use this information to determine the pH. Complete Parts 1-4 before submitting your answer. PREV 1 2 3 4 < Based on your ICE table and the equilibrium expression for Kb, determine the pH of this solution.. pH = RESET 0 4.77 x 10-10 10.8 2.10 x 10% 4.68 9.32 3.22 0.140 1.70 12.3

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HELP WITH A THESIS STATEMENT
I basically need a thesis statement on how DNA analysis relates to chemistry. The only problem is that I'm having trouble making it 'arguable'. My ideas were:
-DNA analysis relates to chemistry because it applies that knowledge when analyzing the DNA samples left at crime scenes in order to identify the suspect.
-DNA analysis relates to chemistry because it's a subcategory of chemistry, also known as forensic chemistry, where DNA left at crime scenes is analyzed to potentially link a suspect to a crime.
Do either of these sound good and are they arguable? If not can you reword it to be?

Answers

The second thesis statement is perfect. It supports the claim and presents main idea.

in an aqueous solution, classify these compounds as strong acids, weak acids, strong bases, weak bases, or other.

Answers

Weak acids;

$CH_{3} COOH\\HF\\H_{2} CO_{3}$

Weak base;

$(CH_{3}) _{3} N\\NH_{3}$

Strong acid;

$HCl\\HNO_{3}$

Strong base;

LiOH

$Ba(OH)_{2}$

Other;

NaCl

What is a weak acid?

We know that a weak acid is an acid that does not dissociate completely in solution. On the other wand, a weak base is a base that does not dissociate completely in solution.

A strong acid is the kind of acid that would be completely dissociated when we dissolve it in aqueous solution while a strong base is a base that would dissociate completely if we dissolve it in solution.

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in an aqueous solution, classify these compounds as strong acids, weak acids, strong bases, weak bases,

What is the charge on one ATOM of plasma?
•negative
•positive

Answers

I believe it is positive

Which explains why mixtures can be separated?
A The components have different properties.
B The components have the same properties.
C The components are always made of small particles.
D The components are always made of large particles.

Answers

Answer:

Explanation:

In chemistry, a mixture is a material made up of two or more different substances which are not chemically combined. A mixture is the physical combination of two or more substances in which the identities are retained and are mixed in the form of solutions, suspensions, and colloids.

Answer:

Explanation:

Mixtures can be separated because the different substances have different properties

Fill in the [?]:
1,516,000,000 nm = [?]m
Give your answer in standard form.

Answers

Answer:

1nm = 1000000 mm 1cm=10mm 1m=100cm

Explanation:

1,516,000,000 nm = divided by 1000000 is 1516 mm divided by 10 = 151.6 cm divided by 100 = 0.1516 m

0.1516 = 1.516 x 10 -1

because it is 10 less than 1.516

In the laboratory a student finds that it takes 85.1 Joules to increase the temperature of 14.5 grams of solid iodine from 21.

Celsius.

/°C.

The specific heat of iodine calculated from her data is

Submit Answer

In Another Version

2 item attempts remaining

Answers

To calculate the specific heat of iodine, we can use the formula: specific heat = (energy required to raise the temperature of the substance)/(mass x change in temperature).The specific heat of iodine calculated from the given data is 0.131 J/g°C.

To calculate the specific heat of iodine, we'll use the formula:

Specific heat (c) = q / (m * ΔT), Where q is the heat energy (in Joules), m is the mass (in grams), and ΔT is the change in temperature (in °C). In this case, we have:
q = 85.1 J
m = 14.5 g
ΔT = 21°C

Now, let's plug these values into the formula and calculate the specific heat of iodine:
c = 85.1 J / (14.5 g * 21°C)
c = 85.1 J / 304.5 g°C
c ≈ 0.394 J/g°C.

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Calculate the number of grams Fe2O3 produced from 8.93 g 02.
4 Fe +302 → 2 Fe2O3

Answers

Hey there!:

Molar mass :

Fe₂O₃ = 159.69 g/mol

O₂ = 31.99 g/mol

By reaction stochiometry :

4 Fe + 3 O₂ = 2 Fe₂O₃

3 * (31.99 g O₂ ) ------------------ 2 * ( 159.69 ) g Fe₂O₃

8.93 g O₂ --------------------------- ( mass O₂)

mass O₂ = ( 8.93 * 2 * 159.69 ) / ( 3 * 31.99 )

mass O₂ = 2852.0634 / 95.97

mass O₂ = 29.71 g Of Fe₂O₃

Hope this helps!

A stick of butter is melted in a saucepan. As it continues to cook, the butter turns brown. What changes have occurred?

Answers

Answer:

Assuming that the butter is already a liquid, it is a chemical change in which the milk solids of the butter oxidize.

Explanation:

I hope this helps :)

Chemical changes have occurred as the stick of butter melts as the milk solids present in butter undergo oxidation resulting in formation of new substances.

What are chemical changes?

Chemical changes are defined as changes which occur when a substance combines with another substance to form a new substance.Alternatively, when a substance breaks down or decomposes to give new substances it is also considered to be a chemical change.

There are several characteristics of chemical changes like change in color, change in state , change in odor and change in composition . During chemical change there is also formation of precipitate an insoluble mass of substance or even evolution of gases.

There are three types of chemical changes:

1) inorganic changes

2)organic changes

3) biochemical changes

During chemical changes atoms are rearranged and changes are accompanied by an energy change as new substances are formed.

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SOMEONE PLS PLS PLS HELP ME ILL GIVE U BRAINLIEST

1. what is the mass in grams of 4 toothpicks

2. what is the mass in grams of 1 cotton ball

Answers

Answer:

1. 4 toothpicks weigh 0.04 grams

2. about 0.60 grams

Explanation:

4 x 0.01 = 0.04 grams

This is a question of 11 grade chemistry, what I have learned and should applied on this question is the mole and stoichiomestry. Please help me solving this.

Answers

The substance that contains the greatest amount (in moles) of carbon atoms per mole of compound is benzoyl peroxide ($C_1_4H_1_0O_4).$

Option D is correct

How do we calculate?

We analyze each substance by:

A. Aspirin (C9H8O4)