Graph the compound inequality on the number line

Step-by-step explanation:

Based on the information given in the diagram, we know that AABD and ACAD are similar triangles, which means their corresponding sides are proportional.

Let's denote the length of AD as x. According to the similarity of the triangles, we can set up the following proportion:

AB/AC = AD/AD

Since AD is common to both triangles and has a length of x, the proportion simplifies to:

AB/AC = 1

We are given that AB = 12, so we can substitute that value into the proportion:

12/AC = 1

To solve for AC, we can cross-multiply:

12 = AC

Therefore, the value of x in the figure is 12.

The difference between the 2 in the tens place and 2 to its left column in the given number 2,222.222 is 180.

According to the number system, a number can be written in its expanded form according to their pace value in the chart.

2,222.222 can be written as 2×1000+2×100+2×10+2X1+2×1/10+2×1/100+2×1/1000

The place value of 2 in the tens place in given number 2,222.222 = 20

The place value of 2 in its left column in the given number 2,222.22  = 200

Difference between the place of 2 in tens place and 2 in its left column

= 200 - 20

= 180

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Answer:

B. Distributive Property

Step-by-step explanation:

The equation for the distributive property is

ab+ac = a(b+c)

We, see it similar to statement 6, so it is the correct answer

Answer:

Line s

Step-by-step explanation:

They are the same distance apart, so this makes them parallel.

By the definition of parallel lines, the line r is parallel to line s.

Arrangement of reference lines or curves used to identify the location of points in space is called as Coordinate System.

We have to find the line which is parallel to line r.

Parallel lines are the lines that do not intersect or meet each other at any point in a plane.

They are always parallel and are at equidistant from each other.

Parallel lines are non-intersecting lines.

We can also say Parallel lines meet at infinity.

As we observe the figure line s is parallel to line r and it is equidistant from r.

Hence, line s is parallel to line r.

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Answer:

S represents sasha and B represents brother.

Equation is s = b + 4

11

13

16

24

Step-by-step explanation:

Let s represent Sasha

Let b represent brother

Answer:

When B is 7, S is 3.

When B is 9, S is 5.

When S is 20, B is 24.

When S is 28, B is 32.

The five factors influencing classification decisions for geographic data mapping are scale, purpose, data availability, technology, and stakeholder input.



Here are five key factors:

1. Scale: The scale at which the map will be produced plays a crucial role in classification decisions. Different features and attributes may be emphasized or generalized based on the map's scale.

2. Purpose: The intended purpose of the map, such as navigation, land use planning, or environmental analysis, affects classification decisions. Each purpose may require different levels of detail and categorization.

3. Data Availability: The availability and quality of data influence classification decisions. Depending on the data sources and their accuracy, certain features may be classified differently or excluded altogether.

4. Technology: The tools and technology used for classification, such as remote sensing or GIS software, impact the decision-making process. Different algorithms and methods can lead to variations in classification outcomes.

5. Stakeholder Input: Stakeholder requirements and preferences can influence classification decisions. Input from users, experts, and decision-makers helps ensure that the map meets their specific needs and expectations.

Therefore, The five factors influencing classification decisions for geographic data mapping are scale, purpose, data availability, technology, and stakeholder input.

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Answer:

it is A

Step-by-step explanation:

Answer:

The amount of the markup is $3.70

Step-by-step explanation:

Independent variable t is time given to read story, dependent variable y is test scores, relationship modeled as y = f(t).

What is variable ?

variable, In algebra, a symbol (usually a letter) standing in for an unknown numerical value in an equation. Commonly used variables include x and y (real-number unknowns), z (complex-number unknowns), t (time), r (radius), and s (arc length).

Let's denote the amount of time given to read the story as t. The independent variable t has three levels: t = 10 minutes, t = 15 minutes, and t = 20 minutes.

The dependent variable y is the test scores on the content of the story. The purpose of the study is to determine the relationship between the independent variable t and the dependent variable y.

The problem can be mathematically represented as:

y = f(t)

where f is a function that represents the relationship between the independent variable t and the dependent variable y.

Independent variable t is time given to read story, dependent variable y is test scores, relationship modeled as y = f(t).

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Independent variable t is time given to read story, dependent variable y is test scores, relationship modeled as y = f(t).

variable, In algebra, a symbol (usually a letter) standing in for an unknown numerical value in an equation. Commonly used variables include x and y (real-number unknowns), z (complex-number unknowns), t (time), r (radius), and s (arc length).

Let's denote the amount of time given to read the story as t. The independent variable t has three levels: t = 10 minutes, t = 15 minutes, and t = 20 minutes.

The dependent variable y is the test scores on the content of the story. The purpose of the study is to determine the relationship between the independent variable t and the dependent variable y.

The problem can be mathematically represented as:

y = f(t)

where f is a function that represents the relationship between the independent variable t and the dependent variable y.

Independent variable t is time given to read story, dependent variable y is test scores, relationship modeled as y = f(t).

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Answer:

AC = 8 cm,

AD = 3 cm and ∠ACB = ∠CDA

From figure,

∠CDA = 90°

∴ ∠ACB = ∠CDA = 90°

In right angled ∆ADC,

AC2 = AD2 + CD2

⇒ (8)2 = (3)2 + (CD)2

CD2 = 64 – 9 = 55

⇒ CD = √55 cm

In ∆CDB and ADC.

∠BDC = ∠AD [each 90°]

∠DBC = ∠DCA [each equal to 90°-∠A]

∴ ∠CDB ∼ ∆ADC

Then,

Answer:

Step-by-step explanation:

The calculated t-value for the independent samples t-test (-1.709) is within the range of the critical t-value at α = 0.05 and df = 55. Therefore, we fail to reject the null hypothesis, indicating no significant difference in anxiety levels between bullies and victims.

To determine the exact answer, we can perform a two-sample t-test to compare the means of the bully group and the victim group. The formula for the t-test statistic is:

t = (x₁ - x₂) / √((s₁² / n1) + (s₂² / n₂))

Where

x₁ and x₂ are the sample means of the bully group and victim group, respectively.

s₁ and s₂ are the sample standard deviations of the bully group and victim group, respectively.

n₁ and n₂ are the sample sizes of the bully group and victim group, respectively.

Given the following data:

Bully group: n₁ = 30, x₁ = 21.5, s₁ = 10

Victim group: n₂ = 27, x₂ = 25.8, s2 = 9

Let's calculate the t-test statistic:

t = (21.5 - 25.8) / √((10² / 30) + (9² / 27))

Calculating the values within the square root

t = (21.5 - 25.8) / √((100 / 30) + (81 / 27))

= (21.5 - 25.8) / √(3.333 + 3)

Now, evaluating the square root and simplifying further:

t = (21.5 - 25.8) / √(6.333)

= (21.5 - 25.8) / 2.516

Finally, computing the numerator and denominator:

t = -4.3 / 2.516

≈ -1.709

Therefore, the exact value of the t-test statistic is approximately -1.709.

To compare the calculated t-value (-1.709) with the critical t-value at a significance level of α = 0.05 with a two-tailed test, we need to determine the degrees of freedom (df) first.

The degrees of freedom (df) for the independent samples t-test is given by the formula:

df = n₁ + n₂ - 2

In this case, n₁ = 30 (number of bullies) and n2 = 27 (number of victims). Therefore:

df = 30 + 27 - 2

df = 55

Next, we need to find the critical t-value from the t-distribution table or a statistical software for a two-tailed test at α = 0.05 and df = 55.

For a two-tailed test at α = 0.05 and df = 55, the critical t-value is approximately ±2.004.

Since the calculated t-value (-1.709) is within the range of the critical t-value (-2.004 to 2.004), we fail to reject the null hypothesis. This means that there is not enough evidence to conclude that there is a significant difference in anxiety levels between bullies and victims.

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Answer:

las vidas una carnival

Step-by-step explanation:

Answer:

About 6.4 hours.

Step-by-step explanation:

We are given the function:
\(\displaystyle B(h) = 1425e^{0.15h}\)

Which measures the population of bacteria B after h hours.

We want to determine the number of hours it will take for the population to reach 3700 bacteria.

Thus, substitute 3700 for B and solve for h:

\(\displaystyle \begin{aligned} (3700) & = 1425e^{0.15h} \\ \\ e^{0.15h} & = \frac{3700}{1425} \end{aligned}\)

Take the natural log of both sides. This cancels the e on the left-hand side:
\(\displaystyle \begin{aligned} \ln\left(e^{0.15h}\right) & = \ln\frac{3700}{1425} \\ \\ 0.15h & = \ln\frac{3700}{1425} \\ \\ h &= \frac{\ln\dfrac{3700}{1425}}{0.15} \\ \\ & \approx 6.4\text{ hours} \end{aligned}\)

In conclusion, it will take about 6.4 hours for the population of the bacteria to reach 3700.

Answer:

275

Step-by-step explanation:

x-35=240

x=240+35

x=275

Answer:

x=9.717

y=18.275

Step-by-step explanation:

First solve for x and then use x to help you solve for y

Harry’s Fish Fry orders cooking oil every 10 days. The lead time is six days. The usage of cooking oil at Harry's Fish Fry is normally distributed with an average of 15 gallons/day and a standard deviation of 3 gallons/day.

Harry's wants a 95% service level.Assuming a normal distribution for usage of cooking oil at Harry's Fish Fry, the service level can be found using the formula; z = (x - µ)/σ where x is the demand, µ is the average demand and σ is the standard deviation of demand.

The z value can be looked up in the z-table to find the probability.The service level is the probability of the lead time demand not exceeding the order point.

Therefore, the order point can be calculated using the formula; Order point = Lead time demand + safety stock.  

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Answer:

l hope this is helpful to you

Answer:

a) 4.47

b) 4.47 g

Step-by-step explanation:

The masses of the birds are given as;

The mass of the robin =76.58 grams.

The mass of the blue jay = 81.05 grams.

Difference in the masses of the birds is : 81.05 - 76.58 =4.47

Difference in masses of the two birds is grams is : 81.05g - 76.58g =4.47g

Answer:

y ≤ 1/3x - 4

Step-by-step explanation:

it could not be options 3 or 4 because the y-intercept is -4, not +4

I picked a point in the shaded area to see which inequality, the first or the second, would make it true; the point I used was (3, -4)

1st option:  y ≥ 1/3x - 4        Is this true? -4 ≥ 1/3(3)  No, -4 is not GE 1

2nd option: y ≤ 1/3x - 4        Is this true? -4 ≤ 1/3(3)  Yes, -4 is LE 1  

The Laplace domain equation X(s) is found to be X(s) = (s + 2)/(s^2 + 5s + 6). The time domain equation x(t) can be obtained by applying the inverse Laplace transform to X(s), resulting in x(t) = e^(-t) - e^(-2t).

Given the Laplace domain equation X(s), we need to substitute the given parameters and find its expression in terms of s. The equation provided is X(s) = (s + 2)/(s^2 + 5s + 6).

To obtain the time domain equation x(t), we need to apply the inverse Laplace transform to X(s). The inverse Laplace transform of X(s) will give us x(t) in terms of t.

Applying the inverse Laplace transform to X(s) involves finding the inverse transform of each term separately. The inverse Laplace transform of (s + 2) is simply 1, representing the unit step function. The inverse Laplace transform of (s^2 + 5s + 6) is e^(-t) - e^(-2t), which can be obtained through partial fraction decomposition.

Therefore, the time domain equation x(t) is given by x(t) = e^(-t) - e^(-2t), where t represents time.

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The measure of angle D in is 19° which is option (A)

To measure D, recall that sum of the angles in a triangle is 180°. We have two angles in triangle BCD, so we can find the third angle as follows:

m∠BCD + m∠CBD + m∠DCB = 180°

46° + m∠CBD + 90° = 180° (since angle DCB is a right angle)

m∠CBD = 44°

Now, we can use the fact that the sum of the angles in triangle CDE is 180° to find the measure of angle D:

m∠CDE + m∠DCE + m∠ECD = 180°

m∠CDE + 71° + 90° = 180° (since angle ECD is a right angle)

m∠CDE = 19°

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The position function of the object moving along the straight line is s(t) = -0.01t³ + 7t, and the velocity function is v(t) = -0.03t² + 7.

The position and velocity of an object moving along a straight line with the given acceleration, initial velocity, and initial position, we can use the equations of motion.

Given: a(t) = -0.06t (acceleration) v(0) = 7 (initial velocity) s(0) = 0 (initial position)

To find the velocity function v(t), we integrate the acceleration function a(t) with respect to time

v(t) = ∫ a(t) dt

Integrating -0.06t with respect to t gives us

v(t) = -0.03t² + C

Using the initial condition v(0) = 7, we can substitute t = 0 and v = 7 into the velocity equation to solve for the constant C

7 = -0.03(0)² + C

C = 7

So the velocity function becomes

v(t) = -0.03t² + 7

To find the position function s(t), we integrate the velocity function v(t) with respect to time

s(t) = ∫ v(t) dt

Integrating -0.03t² + 7 with respect to t gives us

s(t) = -0.01t² + 7t + D

Using the initial condition s(0) = 0, we can substitute t = 0 and s = 0 into the position equation to solve for the constant D

0 = -0.01(0)³ + 7(0) + D

D = 0

So the position function becomes

s(t) = -0.01t³ + 7t

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Step-by-step explanation:

\(\longrightarrow \tt { SI = \dfrac{PRT}{100} } \\ \)

\(\longrightarrow \tt { 250 = \dfrac{P \times 12\cfrac{1}{2} \times 4}{100} } \\ \)

\(\longrightarrow \tt { 250 = \dfrac{P \times \cfrac{25}{2} \times 4}{100} } \\ \)

\(\longrightarrow \tt { 250 = \dfrac{P \times 25 \times 2}{100} } \\ \)

\(\longrightarrow \tt { 250 = \dfrac{P \times 50}{100} } \\ \)

\(\longrightarrow \tt { 250 \times 100 = P \times 50} \\ \)

\(\longrightarrow \tt { 25000 = P \times 50} \\ \)

\(\longrightarrow \tt { \dfrac{25000}{50} = P } \\ \)

\(\longrightarrow \underline{\boxed{ \green{ \tt { \$ \; 500 = P }}}} \\ \)

Therefore principal is $500.

Let the total number of balls be x.

→ Red balls + Blue balls + Yellow balls = Total number of balls

\(\longrightarrow \tt{ \dfrac{2}{7}x + \dfrac{3}{5}x + 36 = x} \\ \)

\(\longrightarrow \tt{ \dfrac{10x + 21x + 1260}{35} = x} \\ \)

\(\longrightarrow \tt{ \dfrac{31x + 1260}{35} = x} \\ \)

\(\longrightarrow \tt{ 31x + 1260= 35x} \\ \)

\(\longrightarrow \tt{ 1260= 35x-31x} \\ \)

\(\longrightarrow \tt{ 1260= 4x} \\ \)

\(\longrightarrow \tt{ \dfrac{1260 }{4}= x} \\ \)

\(\longrightarrow \underline{\boxed{ \tt { 315 = x }}} \\ \)

Total number of balls is 315.

A/Q,

3/5 of the balls are blue.

\(\longrightarrow \tt{ Balls_{(Blue)} =\dfrac{3 }{5}x} \\ \)

\(\longrightarrow \tt{ Balls_{(Blue)} =\dfrac{3 }{5}(315)} \\ \)

\(\longrightarrow \tt{ Balls_{(Blue)} = 3(63)} \\ \)

\(\longrightarrow \underline{\boxed{ \green {\tt { Balls_{(Blue)} = 189 }}}} \\ \)

Answer:

Step I: Simplify the operations inside grouping symbols. Step II: Simplify the powers. Step III: Solve multiplication and division from left to right. Step IV: Solve addition and subtraction from left to right.

There are 45 games played in a season of the youth soccer league with 10 teams.

In a youth soccer league with 10 teams, each team will play against every other team exactly once.

To determine the number of games played in a season, we can use the combination formula, which calculates the number of ways to choose 2 teams from a set of 10 teams. Each combination represents a unique game.

The formula for combinations, also known as the binomial coefficient, is:

C(n, r) = n! / (r! * (n - r)!)

where n is the total number of items and r is the number of items to be chosen.

In this case, we have 10 teams, and we need to choose 2 teams for each game.

Using the combination formula, we can calculate the number of games played as:

C(10, 2) = 10! / (2! * (10 - 2)!)

= 10! / (2! * 8!)

= (10 * 9) / (2 * 1)

= 45

Therefore, 45 games are played in a season.

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