Graph the image of the polygon after a reflection in the line y = -x .
A=(-3,2)
B=(1,-1)
C=(-2,-2)
D=(-4,-1)​

Given differential equation: y''-8y'+15y=0We are to determine the values of r for which the given differential equation has solutions of the form y=e^(rt).

We know that the characteristic equation is given by ar^2+br+c=0, where a,b and c are coefficients of the differential equation.

Now let's solve this using the characteristic equation.r^2 -8r+15=0Factor the quadratic equation(r-5)(r-3)=0 Therefore, r=5 or r=3 or r=0.

Thus, we obtain the following values of r for which the given differential equation has solutions of the form y=e^(rt):r={0,3,5}.So, the correct option is:r={0,3,5}.

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Answer:

g(x) = 8x -15

Step-by-step explanation:

g(x) = 8(x-2) +1

      = 8x -16 +1

      = 8x -15

Answer:

If you are asking if y = 4x is proportional, the answer is yes.  It is linear and it goes through the origin.

Step-by-step explanation:

3y = 5

6 = 2x + 2

x = 2, y = 5/3

2x - 2 = 2   ←

Answer:

y = - 4

Step-by-step explanation:

3y = 2x - 6 ................. (1)

4x + 3y = - 24 ........... (2)

(1)  ---->  (2)

4x + ( 2x - 6 ) = - 24

6x - 6 = - 24

x - 1 = - 4

x = - 3

3y = 2 ( - 3 ) - 6

3y = - 12

y = - 4

( - 3 , - 4 )

The error of closure (EC) is a measure of the accuracy of a closed loop leveling survey.

To calculate the error of closure, we need to subtract the sum of the foresight values from the sum of the backsight values. In this case, the sum of the backsight values is (7.85 ft + 3.55 ft + 4.51 ft + 5.01 ft) = 20.92 ft, and the sum of the foresight values is (5.57 ft + 3.87 ft + 5.15 ft + 6.11 ft) = 20.70 ft.

The error of closure (EC) can be obtained by subtracting the sum of the foresight values from the sum of the backsight values: EC = (sum of backsight values) - (sum of foresight values) = 20.92 ft - 20.70 ft = 0.22 ft.

Therefore, the correct answer is c) 0.22 ft, which represents the error of closure in this leveling survey.

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Answer:

it starts from 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, and so on. But all whole numbers are not natural numbers.

Answer:

160 packages in 4 minutes

Step-by-step explanation:

If this helped please mark brainliest

The measures in the circle given in the image above are calculated as:

1. m<PSQ = 130°;   2. m<AQS = 30°; 3. m(QR) = 100°; 4. m(PS) = 110°; 5. (RS) = 70°.

In order to find the measures in the circle shown, recall that according to the inscribed angle theorem, the measure of intercepted arc is equal to the central angle, but is twice the measure of the inscribed angle.

1. m<PSQ = m<PAQ

Substitute:

m<PSQ = 130°

2. Find m<PBQ:

m<PBQ = 1/2(m(PQ) + m(RS)) [based on the angles of intersecting chords theorem]

Substitute:

m<PBQ = 1/2(130 + 2(35))

m<PBQ = 100°

m<AQS = 180 - [m<BAQ + m<PBQ]

Substitute:

m<AQS = 180 - [(180 - 130) + 100]

m<AQS = 30°

3. m(QR) = m<QAR

Substitute:

m(QR) = 100°

4. m(PS) = 180 - m(RS)

Substitute:

m(PS) = 180 - 2(35)

m(PS) = 110°

5. m(RS) = 2(35)

m(RS) = 70°

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9514 1404 393

Answer:

  (1, 7)

Step-by-step explanation:

Fill in x=1 and do the arithmetic.

  h(1) = 4(1) +3 = 7

The coordinate pair is ...

  (x, h(x)) = (1, h(1)) = (1, 7)

The fraction of the total vote he should expect to get is 23/75.

A fraction is a mathematical unit used to represent a portion of a whole or a ratio of two integers. They are shown as the top number, or numerator, and the bottom number, or denominator, separated by a line. The denominator is the total number of pieces that make up the whole, whereas the numerator is the number of shares or parts.

For instance, you may write 3/8 for the portion of pizza you consumed if there were 8 pieces and you only ate 3. This indicates that you consumed three of the pizza's eight equally sized portions.

From the given table we can determine the total number of votes are:

13 + 9 + 10 + 8 + 10 + 14 + 5 + 6 = 75.

Now, Jamal received 13 + 10 = 23 votes.

Thus, the fraction of the total vote he should expect to get is 23/75.

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Therefore, the Taylor series for f centered at 7 is given by: \(f(x) = (-1)^n * n! * 2^n * (n-1) + (-1)^n * n! * 2^{(n-1)} * (n-1) * (n-2) * (x-7) + (-1)^n * n! * 2^{(n-1)} * (n-1) * (n-2) * (n-3) * (n-4) * (x-7)^2/2 + (-1)^n * n! * 2^{(n-1)} * (n-1) * (n-2) * (n-3) * (n-4) * (n-5) * (n-6) * (x-7)^3/6 + ...\)

To find the Taylor series for f centered at 7, we can use the formula for the Taylor series expansion:

\(f(x) = f(c) + f'(c)(x-c) + (f''(c)(x-c)^2)/2! + (f'''(c)(x-c)^3)/3! + ...\\f(x) = f(c) + f'(c)(x-c) + (f''(c)(x-c)^2)/2! + (f'''(c)(x-c)^3)/3! + ...\\f'(x) = -(-1)^n * n! * 2^{(n-1)} * (n-1) * (n-2) * (x-7)^{(n-3)}\\f''(x) = -(-1)^n * n! * 2^{(n-1)} * (n-1) * (n-2) * (n-3) * (n-4) * (x-7)^{(n-5)}\\f'''(x) = -(-1)^n * n! * 2^{(n-1)} * (n-1) * (n-2) * (n-3) * (n-4) * (n-5) * (n-6) * (x-7)^{(n-7)\)

Now let's evaluate these derivatives at x = 7:

\(f(7) = (-1)^n * n! * 2^n * (n-1)\\f'(7) = -(-1)^n * n! * 2^{(n-1)} * (n-1) * (n-2)\\f''(7) = (-1)^n * n! * 2^{(n-1)} * (n-1) * (n-2) * (n-3) * (n-4)\\f'''(7) = -(-1)^n * n! * 2^{(n-1)} * (n-1) * (n-2) * (n-3) * (n-4) * (n-5) * (n-6)\)

Now we can substitute these values into the Taylor series expansion formula:

\(f(x) = f(7) + f'(7)(x-7) + (f''(7)(x-7)^2)/2! + (f'''(7)(x-7)^3)/3! + ...\)

Simplifying further, we get:

\(f(x) = (-1)^n * n! * 2^n * (n-1) + (-1)^n * n! * 2^(n-1) * (n-1) * (n-2) * (x-7) + (-1)^n * n! * 2^(n-1) * (n-1) * (n-2) * (n-3) * (n-4) * (x-7)^2/2 + (-1)^n * n! * 2^{(n-1)} * (n-1) * (n-2) * (n-3) * (n-4) * (n-5) * (n-6) * (x-7)^3/6 + ...\)

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The value of the double integral of (2x + y) dA over the region D = {(x, y) | 1 ≤ y ≤ 2, y − 1 ≤ x ≤ 1} is 3.

1. Identify the region D: {(x, y) | 1 ≤ y ≤ 2, y − 1 ≤ x ≤ 1}.
2. Set up the double integral: ∬_D (2x + y) dA = ∫(1 to 2)∫(y-1 to 1) (2x + y) dxdy.
3. Integrate with respect to x: ∫(1 to 2) [x² + xy] (from y-1 to 1) dy.
4. Evaluate the antiderivative at the bounds: ∫(1 to 2) [(1+y) - (y²-y)] dy.
5. Simplify the integrand: ∫(1 to 2) (2 - y² + 2y) dy.
6. Integrate with respect to y: [(2y - (1/3)y³ + y³)] (from 1 to 2).
7. Evaluate the antiderivative at the bounds: [(4 - (8/3) + 8) - (2 - (1/3) + 1)] = 3.

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Brandon is currently 6 81 years old.

Let M be Michael's age and B be Brandon's age.

We are given that Michael is 3 33 times as old as Brandon. This means that M = 3 33 × B

We are also given that 18 1818 years ago, Michael was 9 99 times as old as Brandon. This means that M - 18 1818 = 9 99 × (B - 18 1818).

We can combine these two equations to solve for Brandon's current age:

3 33 × B = (9 99 × B) + 18 1818

2 66 × B = 18 1818

B = 18 1818 / 2 66 = 6 81.

Therefore, Brandon is currently 6 81 years old.

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The area of the triangle is increasing at a rate of 450sqrt(3) cm²/min.

What is the rate at which the area of an equilateral triangle is increasing?

To find the rate at which the area of the equilateral triangle is increasing, we first need to know the formula for the area  an equilateral triangle, which is:
of
Area = (sqrt(3)/4) x (side)²

where side is the length of one of the sides of the equilateral triangle.

We are given that the sides of the equilateral triangle are increasing at a rate of 10cm/min. This means that at any given time t, the length of each side is given by:

side = 30 + 10t

We want to find the rate at which the area of the triangle is increasing when the sides are 30cm long. This means that we need to evaluate the derivative of the area formula with respect to time t when side = 30. Taking the derivative of the area formula, we get:

dA/dt = (sqrt(3)/2) x side x (d(side)/dt)

Substituting side = 30 + 10t and d(side)/dt = 10, we get:

dA/dt = (sqrt(3)/2) x (30 + 10t) x 10

When t = 0 (i.e. when the sides are 30cm long), we get:

dA/dt = (sqrt(3)/2) x (30) x 10 = 450sqrt(3)

Therefore, when the sides of the equilateral triangle are increasing at a rate of 10cm/min and are 30cm long, the area of the triangle is increasing at a rate of 450sqrt(3) cm²/min.

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Answer:

Step-by-step explanation:When two triangles are congruent they will have exactly the same three sides and exactly the same three angles. The equal sides and angles may not be in the same position (if there is a turn or a flip), but they are there.

The probability of a typical driver who drives less than 10,000 miles per year having an accident in a year is 9.18%.

To calculate the probability of a driver who drives less than 10,000 miles per year having an accident, we can use the Z-score and the standard normal distribution.

First, we need to calculate the Z-score for a driver who drives less than 10,000 miles per year. The Z-score formula is:

Z = (X - μ) / σ

Where:

X is the value we want to calculate the Z-score for (10,000 miles per year),

μ is the mean (15,000 miles per year), and

σ is the standard deviation (3,750 miles per year).

Plugging in the values, we get:

Z = (10,000 - 15,000) / 3,750

Z = -1.333

Looking up the Z-score -1.333 in the standard normal distribution table, we find the probability to be approximately 0.0918 or 9.18%.

Therefore, the probability of a typical driver who drives less than 10,000 miles per year having an accident in a year is approximately 9.18%.

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Step-by-step explanation:

a rhombus is a parallelogram with 4 identical sides.

it has therefore two pairs of equal angles.

as any quadrilateral the sum of all interior angles is 360°.

(and yes, as add-on, the diagonals bisect each other at right angles).

so, one interior angle is 79°.

that means it has a twin that is also 79°.

together they have 79×2 = 158°.

that leaves

360 - 158 = 202°

for the other 2 angles (they must be equal too).

so, each of them has

202/2 = 101°

so, the other 3 angles are

79°, 101°, 101°

Answer:

1/15

Step-by-step explanation:

Multiply 1/5 by 3, therefore making this problem 3/15 - 2/15 = _. Subtract to get 1/15

Answer:

x = -6

hope this helps!

Answer:

the answer should be letter B your welcome ;)

Step-by-step explanation:

The 90% confidence interval is: (2.51, 3.22)

It is a boundary of values which is eventually to comprise a population value with a certain degree of confidence. It is usually shown as a percentage whereby a population means lies within the upper and lower limit of the provided confidence interval.

We have the following information :

The level of significance is calculated as:

\(\alpha =1-c\\\\\alpha =1-0.90\\\\\alpha =0.10\)

The degrees of freedom for the case is:

df = n - 1

df = 15 - 1

df = 14

The 90% confidence interval is calculated as:

=x(bar) ±\(t_\frac{\alpha }{2}\), df \(\frac{s}{\sqrt{n} }\)

= 2.86 ±\(t_\frac{0.10 }{2}\), 14 \(\frac{0.78}{\sqrt{15} }\)

= 2.86 ± 1.761 × \(\frac{0.78}{\sqrt{15} }\)

= 2.86 ± 0.3547

= (2.51, 3.22)

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Answer:

5 2/5 seems right to me

Step-by-step explanation:

filler filler filler

Based on the output (B) there is no basis for concluding that mean sales are different for the different days of the week.

According to the given table, There is no basis for concluding that mean sales are different for the different days of the week.

Therefore, based on the output (B) there is no basis for concluding that mean sales are different for the different days of the week.

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The complete question is given below:
A fast food chain operation is interested in determining whether the mean per customer purchase differs by day of the week. To test this, it has selected random samples of customers for each day of the week. The analysts then ran a one-way analysis of variance generating the following output:

Based upon this output, which of the following statements is true if the test is conducted at the 0.05 level of significance?

(A) Based on the p-value, the null hypothesis should be rejected since the p-value exceeds the alpha level.

(B) There is no basis for concluding that mean sales is different for the different days of the week.

(C) Based on the critical value, the null should be rejected.

(D) The experiment is conducted as an unbalanced design.

With a critical value of 1.96 and a margin of error of 0.022, the standard error is 0.011.

To find the standard error, we can use the formula for the margin of error, which is:
Margin of Error = Z* × Standard Error
Given that the margin of error is 0.022 and the critical value (Z*) is 1.96, we can rearrange the formula to find the standard error:
Standard Error = Margin of Error / Z*
Standard Error = 0.022 / 1.96
Standard Error = 0.011224
Rounded to three decimal points, the standard error is 0.011.

Given a confidence interval with a critical value of 1.96 and a margin of error of 0.022, the standard error is approximately 0.011.

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Answer:

j=$1.75/lb

t=$2.5/lb

Step-by-step explanation:

(1) 5t+6j=23

(2) 3t+2j=11, t=11/3 - 2j/3

sub t into (1):

5(11/3 - 2j/3) +6j = 23

55/3 -10j/3 +6j =23

8j/3=14/3

8j=14

j=7/4

sub j into t:

t=11/3 -2(7/4)/3

t=5/2

Answer:

hw could make 200 dollars in 4 weeks

Answer:

I think it's either 1/2 or 1/3.

This statement ''The proportion in the body of a normal distribution can never be less than 0.50.'' is false because the proportion in the body of a normal distribution can be less than 0.50, depending on the location of the mean and the spread of the distribution.

In fact, for a normal distribution with a mean of μ and standard deviation of σ, approximately 68% of the area under the curve falls within one standard deviation of the mean (i.e., between μ - σ and μ + σ), which means the proportion in the body of the distribution is about 0.68.

The remaining 32% is split evenly between the tails of the distribution, which means the proportion in each tail is about 0.16.

So, the proportion in the body of the distribution is greater than 0.50.

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The factor form of two possible trinomials representing the tiles are: (i) y = (x - 7) · (x + 1), (ii) y = (x + 7) · (x - 1).

In this problem we find a tile representing a trinomial, a quadratic equation of the form y = A · x² + B · x + C, where A, B, C are real coefficients. The number of blue squares indicates that A = 1, the number of yellow squares indicates that B = 6 and the number of green rectangles indicates that C = 7.

In addition, the quadratic equation can be factored in two ways if the following signs are included in the given coefficients:

A = 1, B = - 6, C = - 7

Standard form: y = x² - 6 · x - 7

Factor form: y = (x - 7) · (x + 1)

A = 1, B = 6, C = - 7

Standard form: y = x² + 6 · x - 7

Factor form: y = (x + 7) · (x - 1)

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