graph the line with the equations y=−x−2?

Answer:

=√29

Distance between (4,7) and (2,2) :   =√29

Steps:

Compute the distance between (ˣ1,y1) , (ˣ2,y2) :  √ (₂-ˣ1) ² + (y₂-y₁)²

The distance between (4,7) and (2,2) is

= √ ( 2-4) ² + (2-7)²

√ ( 2-4) ² + (2-7) ² =√29

=√29

Please mark brainliest

Hope this helps.

Answer:

empeñemos eluden los emigró del fr¡¿&¿=£/€"=4=£64÷^£/:£=17

The correct answer is:

a = 43%

b = 88%

To determine the values of a and b in the relative frequency table, we need to analyze the information provided in the Venn diagram and the given table.

From the Venn diagram, we can gather the following information:

The circle labeled "satellite" has a value of 55.

The circle labeled "cable" has a value of 75.

The overlap between the two circles is labeled as 12.

Using this information, we can complete the table:

First column - "Satellite":

Entries: Satellite, Not satellite, Total

Total: 55 (as given in the Venn diagram)

Second column - "Cable":

Entries: Blank, 51%, Blank

To find the value for the "Cable" entry, we need to subtract the overlap (12) from the total number of cable users (75).

Cable: 75 - 12 = 63

Therefore, the entry becomes: Blank, 51%, Blank

Third column - "Not Cable":

Entries: a, b, Blank

To find the value for "a," we subtract the overlap (12) from the total number of satellite users (55).

a: 55 - 12 = 43

To find the value for "b," we subtract the overlap (12) from the total number of households (100).

b: 100 - 12 = 88

Therefore, the entries become: 43, 88, Blank

Fourth column - "Total":

Entries: Blank, Blank, 100%

The total number of households is given as 100% (as stated in the question).

Therefore, the values of a and b in the relative frequency table are:

a = 43% (rounded to the nearest percent)

b = 88% (rounded to the nearest percent)

Hence, the correct answer is:

a = 43%

b = 88%

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Answer:

7

Step-by-step explanation:

\(a^{m}*a^{n}=a^{m+n}\\\\\\\dfrac{a^{m}}{a^{n}}=a^{m-n}\\\\\\\dfrac{7^{8}*7^{3}*7^{4}}{7^{9}*7^{5}}=\dfrac{7^{8+3+4}}{7^{9+5}}\\\\=\dfrac{7^{15}}{7^{14}}\\\\\\=7^{15-14}=7^{1}\\\\= 7\)

Answer:

7^1

Step-by-step explanation:

since all the bases are same, we're going to use the law (a^m × a^n = a^m+n)

8+3+4= 15, hence, it's 7^15

we'll apply the same law for the denominator, 9+5= 14, so we'll get 7^15 ÷ 7^14

next we're gonna use the law (a^m ÷ a^n = a^m-n where m>n)

15-14 = 1

so our final answer is 7^1

Domain - the set of possible x-coordinates of a function.

Range - the set of possible y-coordinates of a function.

Domain is:

Range is:

This is not a function as it fails the vertical line test.

Domain is:

Range is:

This is not a function as it fails the vertical line test.

Answer:

30.a)  Domain:  [-6, 6]

30.b)  Range:  [-3, 7]

30.c)  Function:  No

31.a)  Domain:  [-2, 2]

31.b)  Range:  [-6, 6]

31.c)  Function:  No

Step-by-step explanation:

Definitions

Interval notation

The domain is the set of all possible input values (x-values).

The range is the set of all possible output values (y-values).

The graph is a conic section (ellipse) and therefore it is not a function.

The smallest x-value is x = -6 and the greatest x-value is x = 6.

The smallest y-value is y = -3 and the greatest y-value is y = 7.

Therefore, the domain and range in interval notation are:

The graph is a not a function as almost all the inputs (x-values) are related to more than one output (y-value).

From inspection of the graph, the endpoints of the continuous line are:

Both endpoints are closed circles, so the values are included in the domain and range.

The smallest x-value is x = -2 and the greatest x-value is x = 2.  

Therefore, the domain in interval notation is:

The smallest y-value is y = -6 and the greatest y-value is y = 6.  

Therefore, the range in interval notation is:

The graph is a not a function as not all inputs (x-values) are related to one output (y-value).

The 2 : 5 scaled version of the deck Sam plans to build and the dimensions of the original deck indicates;

Part A; Base length of the new deck = 7.2 feet

Height of the new deck = 2.8 feet

Part B; The area of the original deck is 63 square feet

The area of the new deck is 10.08 square feet

Part C; The ratio of the areas is the square of the scale factor

A scale factor is a number or factor that is used to enlarge or reduce the dimensions a shape or size of a figure.

The base length of the triangular deck = 18 feet

The height of the triangular deck = 7 feet

The scale factor for the scaled version Sam intends to build = 2 : 5

Part A; The dimensions of the new deck are;

Base length of the new deck using the the 2 : 5 ratio is; (2/5) × 18 = 7.2 feet

The height of the new deck = (2/5) × 7 = 2.8 feet

Part B; The area of the original deck = (1/2) × 18 × 7 = 63 square feet

Area of the new dec = (1/2) × 7.2 × 2.8 = 10.08 square feet

Part C; The ratio of the areas is; 10.08/63

Ratio of the area = 10.08/63 = 4/25 = 4 : 25

The scale factor is; 2 : 5

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Answer:

I hope this helps!

Answer:

B. 2

Step-by-step explanation:

1) all the perpendicular lines are: y=x+C, where C - number;

2) in order to calculate C: to substitute (2;4) into the equation y=x+C:

4=2+C; ⇒ C=2;

3) finally, the required equation is: y=x+2.

The answer is B. 2.

Answer:

In Geometry, we have several undefined terms: point, line and plane. From these three undefined terms, all other terms in Geometry can be defined. In Geometry, we define a point as a location and no size. ... And the third undefined term is the line.

Step-by-step explanation:

probably b and some c 1000

Answer:

-10 and 8?

Step-by-step explanation:

The area of the square with a side length of 3.1 meters is 9.61 square meters.

To find the area of a square, we need to multiply the length of one side by itself. In this case, the square has a side length of 3.1 m.

Area of a square = side length × side length

Substituting the given side length into the formula:

Area = 3.1 m × 3.1 m

To perform the calculation:

Area = 9.61 m²

It's worth noting that when calculating the area, we are working with squared units. In this case, the side length is in meters, so the area is expressed in square meters (m²). The area represents the amount of space enclosed within the square.

Remember, to find the area of any square, you simply need to multiply the length of one side by itself.

The area of the square with a side length of 3.1 meters is 9.61 square meters.

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Answer:

yes

Step-by-step explanation:

Answer:

i hope this helps  :)

Step-by-step explanation:

Grouped, 19546576 is 19,546,576. We underline through the millions place and mark the next digit. 19,546,576

Because the marked digit is 5, we increase 19 by 1 and replace all digits to the right with zeros: 20,000,000.

Thus 19,546,576 rounded to the nearest million is 20,000,000.

Answer:

43 million

43000000

Step-by-step explanation:

7 rounds up

The biconditional statement is: A rectangle is a parallelogram with four right angles if and only if a parallelogram has four right angles.

The term "if and only if" or biconditional statement refers to a compound statement composed of two conditional statements connected by a logical operator.

This definition is commonly utilized to describe the characteristics of a rectangle when it comes  to its correlation with a parallelogram. The opening section of the biconditional statement is comprised of a conditional statement indicating that a rectangle is defined as a parallelogram featuring four right angles.

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Write this definition as a biconditional statement.

A rectangle is a parallelogram with four right angles.

Answer:

The total number of students is > 160.

The percent as a part-to-whole ratio is StartFraction 10 Over 100 EndFraction.

There are 1,600 students in the school.

Step-by-step explanation:

got is correct

Answer:

2,3,5 for eg. 2020

Step-by-step explanation:

The symbols which correctly relates the two numbers are :

We could relate the two given numbers 100 and 20 on the basis of magnitude and equality.

100 is greater than 20, 100> 20

100 is greater than or equal to 20 , 100 ≥ 20

100 is not equal to 20 , 100≠20

Therefore, the symbols which relates the numbers are :

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Answer:

-5x + 8y = -21

3x - 4y = 15

8y = 5x - 21

y = 5/8x - 21/8

3x - 4y = 15

-4y = -3x + 15

y = 3/4x - 15/4

5/8x - 21/8 = 3/4x - 15/4

-1/8x = -9/8x

x = 9

3x - 4y = 15

3(9) - 4y = 15

27 - 4y = 15

-4y = -12

y = 3

(9, 3)

Answer:

  (9, 3)

Step-by-step explanation:

My favorite way to solve equations like this is using a graphing calculator. For Desmos, one only needs to type the equations into the input column, click on one of them, and highlight the point of intersection to see the coordinates there.

__

The usual ways to solve these are by substitution or elimination. Another way they can be solved is using Cramer's rule, which provides a formula for the solution based on the coefficients.

  ax +by = c

  dx +ey = g

__

  x = (bg -ec)/(bd -ea) . . . . . . note the crossing pattern of the values in the products

  y = (cd -ga)/(bd -ea) . . . . . . the denominator is the same as above

__

Using these formulas, we get ...

  x = (8(15) -(-4)(-21))/(8(3) -(-4)(-5)) = (120 -84)/(24 -20) = 36/4 = 9

  y = (-21(3) -15(-5))/4 = (-63 +75)/4 = 12/4 = 3

The solution is (x, y) = (9, 3).

Doing the same by elimination involves the same amount of math and a lot more writing.

Answer:

j=13.5

Step-by-step explanation:

The area of the composite figure is 122.24 units².

The composite figure consist of a rectangle and two semi circles. Therefore, the area of the composite figure is the sum of the area of the individua shapes.

Hence,

area of the composite figure = area of the rectangle + 2(area of semi circle)

Therefore,

area of the composite figure = 9 × 8 + 2(1 / 2 πr²)

area of the composite figure = 72 + πr²

where

r = 8 / 2 = 4 units

Therefore,

area of the composite figure = 72 + 3.14 × 4²

area of the composite figure = 72 + 3.14 × 16

area of the composite figure = 72 + 50.24

area of the composite figure = 122.24 units²

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instantaneous rate of change of the search length 0.1667 seconds per

We need to take the derivative of the function S(n) with respect to n and evaluate it at n=12 in order to determine the instantaneous rate of change of the search length for a set of 12 articles.

Taking the derivative of S(n) with respect to n using the chain rule, we get:

S'(n) = 1.6 * (1/(0.8n)) * 0.8 = 2/n

Evaluating this expression at n=12, we get:

S'(12) = 2/12 = 0.1667 seconds per article

This indicates that the search time will increase by approximately 0.1667 seconds per article if the set contains 12 articles by one unit. Alternately, the search time per article will decrease by approximately 0.1667 seconds if the set's number of articles decreases by one unit from 12.

Therefore, the units for the instantaneous rate of change are "seconds per article", indicating the change in search time for each additional or fewer article in the set.

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The total area of the regions between the curves is 4.5 square units

The graph is attached

From the question, we have the following parameters that can be used in our computation:

y = x² - 6x + 9 and y = x - 1

With the use of graphs, the curves intersect at

x = 2 and x = 5

So, the area of the regions between the curves is

Area = ∫x² - 6x + 9 - x + 1

This gives

Area = ∫x² - 7x + 10

Integrate

Area =  x³/3 - 7x²/2 + 10x

Recall that x = 2 and x = 5

So, we have

Area = [2³/3 - 7(2)²/2 + 10(2)] - [5³/3 - 7(5)²/2 + 10(5)]

Evaluate

Area = 4.5

Hence, the total area of the regions between the curves is 4.5 square units

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Answer:six more than the quotient of a number and 5 is equal to 4

n/5 +6 =4

subtract 6 from each side

n/5 = -2

multiply by 5 on each side

n = -10

Step-by-step explanation:

the three friends spent L.120.00, L.240.00, and L.360.00, respectively.

How to solve the problem?

Let's denote the amount that Alicia spends as "x". According to the problem statement, we know that Juan spends twice as much as Alicia, which means he spends 2x. Similarly, we know that Ana spends three times as much as Alicia, which means she spends 3x.

We also know that the three friends together have spent L.720.00. So, we can set up an equation to represent this:

x + 2x + 3x = 720

Simplifying this equation, we get:

6x = 720

Dividing both sides by 6, we get:

x = 120

So, Alicia spent L.120.00, Juan spent twice as much as Alicia, which is L.240.00, and Ana spent three times as much as Alicia, which is L.360.00.

Therefore, the three friends spent L.120.00, L.240.00, and L.360.00, respectively.

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so we have a point at -2-i or -2 - 1i, that means that both "x" and "y" are negative, the only occurs in the III Quadrant, so hmmm let's find the modulus and angle θ

\(\stackrel{a}{-2}\stackrel{b}{-1i}\hspace{5em} \begin{cases} r=\sqrt{(-2)^2 + (-1)^2}\\ \qquad \sqrt{5}\\ \theta =tan^{-1}\left( \frac{-1}{-2} \right)\\[1em] \qquad \approx 206.57^o \end{cases} \\\\\\ \stackrel{\textit{let's keep in mind that}}{\sqrt[3]{\sqrt{5}}\implies \left( 5^{\frac{1}{2}} \right)^{\frac{1}{3}}}\implies 5^{\frac{1}{6}}\implies \sqrt[6]{5} \\\\[-0.35em] ~\dotfill\)

\(\sqrt[n]{z}=\sqrt[n]{r}\left[ \cos\left( \cfrac{\theta+2\pi k}{n} \right) +i\sin\left( \cfrac{\theta+2\pi k}{n} \right)\right]\quad \begin{array}{llll} k\ roots\\ 0,1,2,3,... \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}\)

\(\boxed{k=0}\hspace{5em} \sqrt[ 3 ]{\sqrt{5}} \left[ \cos\left( \cfrac{ 206.57^o + 360^o( 0 )}{3} \right) +i \sin\left( \cfrac{ 206.57^o + 360^o( 0 )}{3} \right)\right] \\\\\\ \sqrt[ 6 ]{5} \left[ \cos\left( \cfrac{ 206.57^o }{3} \right) +i \sin\left( \cfrac{ 206.57^o }{3} \right)\right] \\\\\\ \sqrt[6]{5}\left[ \cos(68.86^o) +i \sin(68.86^o)\right] ~~ \approx ~~ 0.47~~ + ~~1.22i \\\\[-0.35em] ~\dotfill\)

\(\boxed{k=1}\hspace{5em} \sqrt[ 6 ]{5} \left[ \cos\left( \cfrac{ 206.57^o + 360^o( 1 )}{3} \right) +i \sin\left( \cfrac{ 206.57^o + 360^o( 1 )}{3} \right)\right] \\\\\\ \sqrt[ 6 ]{5} \left[ \cos\left( \cfrac{ 566.57^o }{3} \right) +i \sin\left( \cfrac{ 566.57^o }{3} \right)\right] \\\\\\ \sqrt[ 6 ]{5} \left[ \cos(188.86^o) +i \sin(188.86^o)\right] ~~ \approx ~~ -1.29~~ - ~~0.20i \\\\[-0.35em] ~\dotfill\)

\(\boxed{k=2}\hspace{5em} \sqrt[ 6 ]{5} \left[ \cos\left( \cfrac{ 206.57^o + 360^o( 2 )}{3} \right) +i \sin\left( \cfrac{ 206.57^o + 360^o( 2 )}{3} \right)\right] \\\\\\ \sqrt[ 6 ]{5} \left[ \cos\left( \cfrac{ 926.57^o }{3} \right) +i \sin\left( \cfrac{ 926.57^o }{3} \right)\right] \\\\\\ \sqrt[ 6 ]{5} \left[ \cos(308.86^o) +i \sin(308.86^o)\right] ~~ \approx ~~ 0.82~~ - ~~1.02i\)

just a quick clarification, notice that if we get the inverse tangent of (-1 / -2) the angle we get will be in the range of ±π/2, that's because that is the range inverse tangent is restricted to, however, our terminal point on the complex plane is on the III Quadrant, not the 1st one, so we use the reference angle on the III Quadrant, and that is about 206.57°.

Answer:

The circle graph does not represent a function because it doesn't pass the vertical line test.

Step-by-step explanation: