Answer:
X intercept is (-40,0) why intercept is (0,15)
Step-by-step explanation:
youyou will be able to tell this by looking at the graph and counting where the points are
Lisa charges $28 for 2 hours of swimming lessons, Tara charges $75 for 5 hours of swimming lessons. Who offers a better deal?
Answer:
Lisa
Step-by-step explanation:
Find the amount of money Lisa and Tara charge every hour.
Lisa's ratio is 28 : 2 hours
Divide both sides of the ratio by 2
Lisa charges 14 dollars per hour
Tara's ratio is 75:5 hours
Divide both sides of the ratio by 5
Tara charges 15 dollars per hour
Lisa charges 1 dollar less each hour, so Lisa offers a better deal.
Hope this helps :)
Have an awesome day!
Which is a solution to the system of inequalities? y > - 2x + 5 ; 3x - 4y ≤ - 24
Answer:
y > 2x+5 and y > 6+ 3z/4
Step-by-step explanation:
solve each inequality and then find the intersection
Answer:
y > - 2x
Step-by-step explanation:
Find the value of x in this equation. 180-5x=140180−5x=140
Answer: 8
Step-by-step explanation:
Using Euler's method, approximate y(0.4) for dy/dx = -3(x^2)y,
starting at (0,2) and using delta(x) = 0.1
(4) Using Euler's Method, approximate y(0.4) for x=-3xy, starting at (0, 2) and using Ax = 0.1 12 y dy dr ydy = -3r²dr
The approximate value of y(0.4) using Euler's method is approximately 1.9963.
To approximate the value of y(0.4) using Euler's method for the given differential equation dy/dx = -3(x^2)y, we can use the following steps:
1. Initialize the variables:
- Set the initial value of x as x0 = 0.
- Set the initial value of y as y0 = 2.
- Set the step size as Δx = 0.1.
- Set the target value of x as x_target = 0.4.
2. Iterate using Euler's method:
- Set x = x0 and y = y0.
- Calculate the slope at the current point: slope = -3(x^2)y.
- Update the values of x and y:
x = x + Δx
y = y + slope * Δx
- Repeat the above steps until x reaches the target value x_target.
3. Approximate y(0.4):
- After the iterations, the value of y at x = 0.4 will be the approximate solution.
Let's apply these steps:
Initialization:
x0 = 0
y0 = 2
Δx = 0.1
x_target = 0.4
Iteration using Euler's method:
x = 0, y = 2
slope = -3(0^2)(2) = 0
x = 0 + 0.1 = 0.1
y = 2 + 0 * 0.1 = 2
slope = -3(0.1^2)(2) = -0.006
x = 0.1 + 0.1 = 0.2
y = 2 + (-0.006) * 0.1 = 1.9994
Repeat the above steps until x reaches the target value:
slope = -3(0.2^2)(1.9994) = -0.02399
x = 0.2 + 0.1 = 0.3
y = 1.9994 + (-0.02399) * 0.1 = 1.9971
slope = -3(0.3^2)(1.9971) = -0.10773
x = 0.3 + 0.1 = 0.4
y = 1.9971 + (-0.10773) * 0.1 = 1.9963
Approximation:
The approximate value of y(0.4) using Euler's method is approximately 1.9963.
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-2/3y-3/4=5
What is the answer i need to show my work please
Answer:
y= -69/8 (negative 69 over 8)
Step-by-step explanation:
First, you have to simplify both sides of the equation:
\(-2/3y+ -3/4 =5\)
Second, add 3/4 to both sides:
-2/3y +-3/4 + 3/4=5 +3/4
-2/3y= 23/4
Next, multiply both sides by 3/(-2) (3 over -2)
(3/-2)*(-2/3y)= (3/-2) * (23/4)
y= -69/8
SOMEONE HELP ME PLEASE
9514 1404 393
Answer:
XY = 11
Step-by-step explanation:
XY = YZ
3x +2 = x +8
2x = 6 . . . . . . . . . subtract x+2
x = 3
XY = 3 +8 . . . . . . . . x +8 is the same as 3x+2
XY = 11
Answer:
\(\boxed {\boxed {\sf XY= 11}}\)
Step-by-step explanation:
We are asked to find the value of XY.
We know that Y is the midpoint of XZ. The midpoint of a line bisects the line or divides it into 2 equal parts. The point Y divides the line XZ into 2 parts : XY and YZ. Since Y is the midpoint, XY and YZ are equal.
\(XY= YZ\)
We know that XY is equal to 3x+2 and YZ is equal to x+8.
\(3x+2=x+8\)
Now we can solve for x by isolating the variable. Move all the terms with variables to one side and the constants to the other side. Subtract x from both sides of the equation.
\((3x-x) +2 = (x-x)+8\)
\(2x+2=8\)
Subtract 2 from both sides of the equation.
\(2x+(2-2)= (8-2)\)
\(2x=6\)
Divide both sides of the equation by 2.
\(2x/2= 6/2\)
\(x= 6/2 \\x=3\)
Now we know that x is equal to 3 and we can substitute it back into 3x+2 to solve for XY.
\(XY= 3x+2 \\XY=3(3) +2\\XY=9+2 \\XY=11\)
Raven purchases a new cell phone for $800 that depreciates annually. the value of her cell phone per year, x, can be modeled by the exponential function f(x) = 800(0.82)x. what is the range of this exponential function in terms of the context of the problem? [0, [infinity]) â„ (800, [infinity]) (0, 800]
The range for this function is (0,800].
What is a geometric progression?
It is a sequence of terms in which the succeeding term is can be found out by multiplying with a constant non zero value.
here the first term is 800 as it is the initial price. We can see that the common ratio is less than 1 which is 0.82, hence its a decreasing progression.
so the maximum value in range is 800
as x tends to infinity the equation tends to 0
hence the funtion apporaches 0
so the range will be (0,800]
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Using geometric progression, the range for this function is (0,800].
What is geometric progression?A mathematical sequence known as a geometric progression (GP) is one in which each following phrase is generated by multiplying each preceding term by a fixed integer, or "common ratio."
This progression is sometimes referred to as a pattern-following geometric sequence of numbers.
Here the first term is 800 as it is the initial price. We can see that the common ratio is less than 1 which is 0.82.
Hence it's a decreasing progression.
So, the maximum value in the range is 800.
As x tends to infinity the equation tends to 0.
Hence, the function approaches 0
So the range will be (0,800].
Therefore, using a geometric progression, the range for this function is (0,800].
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Capture-recapture studies are common in ecology. One form of the study is conducted as follows. Suppose we have a population of N deer in a study area. Initially n deer from this population are captured, marked so that they can be identified as having been captured, and returned to the population. After the deer are allowed to mix together, m deer are captured from the population and the number k of these deer having marks from the first capture is observed.
Required:
Assuming that the first and second captures can be considered random selections from the population and that no deer have either entered or left the study area during the sampling period, what is the probability of observing k marked deer in the second sample of m deer?
The probability of observing k marked deer in the second sample of m deer can be calculated using the hypergeometric distribution.
The probability of observing k marked deer in the second sample of m deer in a capture-recapture study can be calculated using the concept of hypergeometric distribution.
In this scenario, let's consider the following variables:
N = Total population size (number of deer)
n = Number of deer initially captured and marked
m = Number of deer captured in the second sample
k = Number of deer in the second sample that are marked from the first capture
The probability of observing k marked deer in the second sample can be calculated as the ratio of two combinations:
P(k marked in the second sample) = (Number of ways to choose k marked deer) * (Number of ways to choose (m - k) unmarked deer) / (Number of ways to choose m deer from the population)
The number of ways to choose k marked deer from the total n marked deer in the population is given by the combination formula:
Number of ways to choose k marked deer = C(n, k)
Similarly, the number of ways to choose (m - k) unmarked deer from the remaining (N - n) unmarked deer in the population is given by the combination formula:
Number of ways to choose (m - k) unmarked deer = C(N - n, m - k)
Lastly, the number of ways to choose m deer from the total N deer population is given by the combination formula:
Number of ways to choose m deer from the population = C(N, m)
Putting it all together, the probability of observing k marked deer in the second sample can be calculated as:
P(k marked in the second sample) = C(n, k) * C(N - n, m - k) / C(N, m)
This formula takes into account the random selection of deer in the two samples and assumes no change in the population size or migration during the sampling period.
It's important to note that this calculation assumes that the marking and recapture process does not affect the behavior or mortality of the deer. It also assumes that the marked deer mix randomly with the unmarked deer between the captures.
By using the appropriate combination formulas and plugging in the values of n, N, m, and k, you can calculate the probability of observing k marked deer in the second sample.
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Supposed a college class contains 61 students. 37 are sophomores, 26 are business majors and 10 are neither. A student is selected at random from the class. What is the probability that the student is both a sophomore and a business major?
The probability that a student is both a sophomore and a business major is 12/61.
The probability that a student is both a sophomore and a business major can be calculated by dividing the number of students who are both into the total number of students.
Let's denote the event of a student being a sophomore as A and the event of a student being a business major as B. We want to find the probability of both events occurring, denoted as P(A and B).
From the given information, we know that there are 61 students in total, with 37 being sophomores and 26 being business majors. We are also given that 10 students are neither sophomores nor business majors.
To find the probability of a student being both a sophomore and a business major, we need to determine the number of students who satisfy both conditions.
Since there are 61 students in total and 10 of them are neither sophomores nor business majors, the number of students who are both sophomores and business majors is 37 + 26 - 61 + 10 = 12.
Therefore, the probability of a student being both a sophomore and a business major is:
P(A and B) = Number of students who are both sophomores and business majors / Total number of students = 12 / 61.
Thus, the probability that a student is both a sophomore and a business major is 12/61.
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the ages (in years) of 10 infants and the numbers of hours each slept in a dayAge, x: 0.1, 0.2, 0.4, 0.7, 0.6, 0.9
The mean and median of the hours of sleep are 10.333 hours and 10.5 hours, respectively.
The ages (in years) of 10 infants and the numbers of hours each slept in a day are given below.
Age, x: 0.1, 0.2, 0.4, 0.7, 0.6, 0.9
Hours of sleep, y: 14, 12, 10, 8, 11, 7
We are to find the mean and median of hours of sleep.Let us first arrange the hours of sleep in increasing order.
7, 8, 10, 11, 12, 14
Mean is given by the formula \($\frac{\sum_{i=1}^{n} x_i}{n}$\)
Here, the sum of the observations is given by
7 + 8 + 10 + 11 + 12 + 14 = 62
Therefore, the mean of the hours of sleep is
\($\frac{62}{6}$\) = 10.333 hours
Now, the median can be calculated as follows:
Total number of observations, n = 6
Therefore, the median = \($\frac{(n+1)}{2}^{th}observation\)
=\(\frac{(6+1)}{2}^{th}$ observation\)
= 3.5th observation
Since there is no 3.
5th observation, the median is the mean of the 3rd and the 4th observation=
\($\frac{10 + 11}{2}$\)= 10.5 hours.
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6. There are only cars and trucks in the parking lot. Five out of every 13
vehicles are cars. If there are 143 vehicles in the parking lot, how many
are trucks?
Pls help me
Answer:
88 trucks
Step-by-step explanation:
Ratio of cars : vehicles = 5:13
Hence, the ratio of trucks : vehicles = 8:13
143/13 = 11
If the number of vehicles is 143,
we have to multiply both sides of the ratio by 11:
8*11 : 13* 11
88 : 143
Hence, there are 88 trucks for every 143 vehicles.
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Estimate the weight of the chips in the bag.
Answer:
Kale, 1 carrots, 4 sweet potatoes, 3, beets, 2
Step-by-step explanation:
um just round
P.S. Iready sucks
Answer:
Kale ; 1(oz)
Carrots; 4(oz)
Sweet Potatoes; 4(oz)
Beets; 2(oz)
Step-by-step explanation:
When rounding anything that is equal to or greater than 5 rounds up, anything that is less than 5 rounds down.Round to the nearest whole ounceVegetable | Weight(oz)Kale \ 1.35 ⇒ 1(oz)
Carrots \ 3.50 ⇒ 4(oz)
Sweet potatoes \ 3.81 ⇒ 4(oz)
Beets \ 2.29 ⇒ 2(oz)
Find the first two random numbers (to the fifth digit after the decimal point) using linear congruential generator with a=4, m=11 and b=0 and 23 as the seed
The first two random numbers are 4,5.using linear congruential generator with a=4, m=11 and b=0 and 23 as the seed
linear congruential generator
Xn= an-+b Lm
0d s = 25 , b=6, YM 11, 024
Q O o m) 4, Lu) = 4x2%U)
m= 4x4j = 5 y-5
the numbers are 4, 5.
4.O0000 5.000TO
A linear congruence generator is an algorithm that returns a sequence of pseudorandom numbers computed using discontinuous piecewise linear equations. This method is one of the oldest and best-known pseudorandom number generator algorithms.
The linear congruential generator (LCG) is a pseudorandom number generator (PRNG ) is a class of algorithms. Random number generation plays an important role in many applications, from cryptography to Monte Carlo methods.
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Evaluate the following integral to ∫ fx cos(x) (x − 2) dx.
The integral of the given function is (\(x^2\) sin(x) - 2x cos(x) + 2 sin(x)) + C.
To evaluate the integral ∫x cos(x) (x - 2) dx, we can expand the expression and then integrate it term by term.
Expanding the expression:
∫x cos(x) (x - 2) dx = ∫(\(x^2\) - 2x) cos(x) dx
Now, we can integrate term by term:
∫\(x^2\) cos(x) dx - ∫2x cos(x) dx
For the first term, we can use integration by parts. Let's choose u = \(x^2\) and dv = cos(x) dx.
Differentiating u, we get du = 2x dx.
Integrating dv, we get v = ∫cos(x) dx = sin(x).
Using integration by parts formula ∫u dv = uv - ∫v du, we have:
∫\(x^2\) cos(x) dx = \(x^2\)sin(x) - ∫2x sin(x) dx
Now, let's focus on the second term ∫2x sin(x) dx. We can again use integration by parts. Let's choose u = 2x and dv = sin(x) dx.
Differentiating u, we get du = 2 dx.
Integrating dv, we get v = -cos(x).
Using integration by parts, we have:
∫2x sin(x) dx = -2x cos(x) - ∫(-2 cos(x)) dx
= -2x cos(x) + 2 ∫cos(x) dx
= -2x cos(x) + 2 sin(x)
Bringing everything together, we have:
∫\(x^2\)cos(x) dx - ∫2x cos(x) dx = (\(x^2\)sin(x) - 2x cos(x) + 2 sin(x)) + C
Therefore, the evaluated integral is (\(x^2\)sin(x) - 2x cos(x) + 2 sin(x)) + C, where C is the constant of integration.
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Geometry help please. It’s due tomorrow
Points G, H, and I It seems to be the vertices of a triangle, forming the triangle GHI. Triangle GHI resembles triangle ABC.
What exactly is a triangle?A triangle is a three-sided polygon that is also known as the trigon. Every triangle has three sides and three angles, which might be different. In geometry, a triangle is a three-sided polygon with three edges and three vertices. The sum of a triangle's internal angles equals 180 degrees, which is its most important characteristic. This is known as a triangle's angle sum property.
Here,
Point G, H, I looks like the vertices of triangle making triangle GHI. Triangle GHI is similar to triangle ABC.
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Which measure is of an angle that is coterminal with a 425° angle?
425° – (1,000n)°, for any integer n
425° – (840n)°, for any integer n
425° + (960n)°, for any integer n
425° + (1,440n)°, for any integer n
The measure of angle that is coterminal with 425° is 425° + (1440n)°
What are coterminal angles?Coterminal angles are angles in multiples of the angles in standard positions examples(360°).
It is mostly gotten by adding 360° or multiples of 360 to the angle.
One of the unique behavior of coterminal angles is that their sine, cosine and tangent are equal.
Analysis:
From the options, the only one with an addition of 360 or multiples of 360 is 425 + 1440n
If we put n = 1, the coterminal angle gotten is 1865.
if we find the sine of 425°, we get 0.9063 which is same as the sine of 1865°.
In conclusion, the coterminal angle to 425° is 425° + (1440n)°.
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Answer:
B. 425° – (840n)°, for any integer n
A city currently has 128 streetlights. As part of a urban renewal program, the city council has decided to install 2 additional streetlights at the end of each week for the next 52 weeks.
Answer:
232
Step-by-step explanation:
52x2=104
128+104=232
The table below gives the distribution of milk
chocolate M&M's
Color
Brown
Red
Yellow
Green
Orange
Blue
Probability
0.13
0.13
0.14
0.16
0.20
0.24
If a candy is drawn at random, what is the probability
that it is not orange or red?
PLZ HELP!!!!!
Explanation:
The probability of picking red is 0.13
The probability of picking orange is 0.20
The probability of picking either of these is 0.13+0.20 = 0.33
So the probability of picking neither of them is 1 - 0.33 = 0.67
There's a 67% of this happening.
Answer:
0.34
Step-by-step explanation:
because the probability of red is 20 and the probability of orange is 14 20 + 14 is 34.
PLEASE HELP I DONT KNOW THE ANSWER!!!! A lot of points and brainliest if you tell me
Answer: r=1
Step-by-step explanation: r" is the correlation coefficient. It is always between -1 and 1, with -1 meaning the points are on a perfect straight line with negative slope, and r = 1 meaning the points are on a perfect straight line with positive slope.
just the linked questions, thanks . 8.4 similar triangles unit 8 practice a
The evaluation of the segment formed by the parallel lines using Thales Theorem also known as the triangle proportionality theorem are;
8. \(\overline {ST}\) is parallel to \(\overline{PR}\)
9. \(\overline{ST}\) is parallel to \(\overline{PR}\)
10. \(\overline{ST}\) is not parallel to \(\overline{PR}\)
11. x = 57.6
12. x = 25.8
13. x = 11
14. x = 10
15. x = 5
16. x = 17
What is Thales theorem?Thales Theorem also known as the triangle proportionality theorem states that a parallel line to a side of a triangle that intersects the other two sides of the triangle, divides the two sides in the same proportion.
8. The ratio of the sides the segment \(\overline{ST}\) divides the sides QR and QP of the triangle ΔPQR into are; 7/11.2 = 10/16 = 0.625
Therefore; according to the Thales theorem, \(\overline{ST}\) ║ \(\overline{PR}\)
9. The ratio of the sides the parallel side to the base divides the other two sides are;
33/41.8 = 15/19
45/(102 - 45) = 45/57 = 15/19
Therefore, \(\overline{ST}\) and \(\overline{PR}\) bisects \(\overline{QP}\) and \(\overline{QR}\) into equal proportions and therefore, \(\overline{ST}\) ║ \(\overline{PR}\)
10. The ratio of the sides the segment \(\overline{ST}\) bisects the other two sides are;
24/57 and 19/38
24/57 ≠ 19/38, therefore \(\overline{ST}\) ∦ \(\overline{PR}\)
Second part; To solve for x
11. x/30 = 48/25
x = (48/25) × 30 = 57.6
x = 57.6
12. x/34.4 = (49 - 28)/28
x = 34.4 × (49 - 28)/28 = 25.8
x = 25.8
13. (2·x + 6)/52.5 = 32/60
(2·x + 6) = 52.5 × (32/60)
x = (52.5 × (32/60)) - 6)/2 = 11
x = 11
14. (x - 3)/21 = (x - 1)/27
27·x - 27 × 3 = 21·x - 21
27·x - 81 = 21·x - 21
6·x = 60
x = 60 ÷ 6 = 10
x = 10
15. (35 - 20)/20 = (4·x - 2)/(7·x - 11)
15/20 = (4·x - 2)/(7·x - 11)
15 × (7·x - 11) = 20 × (4·x - 2)
105·x - 165 = 80·x - 40
105·x - 80·x = 165 - 40 = 125
25·x = 125
x = 125/25 = 5
x = 5
16. (x - 3)/35 = 4/(x - 7)
(x - 3) × (x - 7) = 35 × 4 = 140
x² - 10·x + 21 = 140
x² - 10·x - 119 = 0
(x - 17) × (x + 7) = 0
x = 17 or x = -7
Therefore, the possible value of x is 17
x = 17
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Multiply 2/3 by 42,and then multiply that product by 10
Answer:
280
Step-by-step explanation:
What is it?
??????????????????????
Answer:
c) 95 feet
Step-by-step explanation:
perimeter = πd
3.14*18=56.52 in
20 revolutions =56.52*20=1130 in =95 feet
If f(x)=10^x, then prove that f(a+b+c)=f(a).f(b).f(c)
Step-by-step explanation:
Given
f(x) = 10^x
Now
LHS
f(a + b + c)
= 10^ a + b + c
RHS
f(a) • f(b) • f(c)
= 10^a • 10^b • 10^ c
= 10 ^ a + b + c
Therefore LHS = RHS
Proved .
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A micrometer is smaller than a meter by a factor of
Answer:
12 inches
Step-by-step explanation:
if i where you and wherent sure i would go around brainly looking for the answer are go with my gut
Answer:
Step-by-step explanation: everyone
EMERGENCY HELP NEEDED!!! WILL MARK BRAINLIEST!!!!!
Given the graph below give the piecewise function.
Answer:
Step-by-step explanation:
It's hard to write the answer properly, but I'll give it a try (pretend the curly bracket { is extra long):
f(x) = { 2x + 1 if x ≥ 0
x² - 2 if x < 0
Martin needs to ship a box that weighs 12,000 grams. How should be move the decimal point to convert this number
to kilograms?
O 3 places to the left
O 3 places to the right
O 2 places to the left
O 2 places to the right
1. Which three lengths could be the lengths
of the sides of a triangle?
A. 12 cm, 5 cm, 17 cm
B. 10 cm, 15 cm, 24 cm
C. 9 cm, 22 cm, 11 cm
D. 21 cm, 7 cm, 6 cm
(Maneuvering the middle)
Answer:
B.
Step-by-step explanation:
A- 12 + 5 = 17 (Cannot be the same)
B- 10 + 15 = 25 (More than the 3rd side) ✅
C- 9 + 11 = 20 (Cannot be less than the 3rd side)
D- 7 + 6 = 13 (Cannot be less than the 3rd side)
if any particular experimental run involves the use of a single temperature, pressure, and catalyst, how many experimental runs are possible? runs (b) how many experimental runs are there that involve use of the lowest temperature and two lowest pressures? runs (c) suppose that four different experimental runs are to be made on the first day of experimentation. if the four are randomly selected from among all the possibilities, so that any group of four has the same probability of selection, what is the probability that a different catalyst is used on each run? (round your answer to four decimal places.)
The probability of using a different catalyst in each of the four experimental runs is C(n3, 4) / C(n1 * n2 * n3, 4) (rounded to 4 decimal places).
a) The number of experimental runs possible depends on the number of temperatures, pressures, and catalysts available for use.
b) The number of experimental runs involving the lowest temperature and two lowest pressures depends on the specific values of these factors and the number of options available for each.
c) The probability of using a different catalyst on each of the four experimental runs can be calculated as follows:
Let's assume that there are n different catalysts available for use.
The number of ways to select the first catalyst is n options.
The number of ways to select the second catalyst is (n-1) options since one of the options have already been used.
The number of ways to select the third catalyst is (n-2) options, and
The number of ways to select the fourth catalyst is (n-3) options.
The total number of ways to select 4 catalysts out of n is n! / (n-4)!
The probability of selecting a different catalyst for each run can be calculated as:
(n options * (n-1) options * (n-2) options * (n-3) options) / (n! / (n-4)!) = (n * (n-1) * (n-2) * (n-3)) / n!
Rounding the answer to 4 decimal places, the probability is (n * (n-1) * (n-2) * (n-3)) / n!.
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Please help with my math. I have a failing grade!
Answer:
B it's the only one with the negative sign
Step-by-step explanation:
Read this excerpt from Thomas Campbell’s ""Lord Ullin’s Daughter."" In what two ways is it a narrative poem?
Answer:
it contains charecter it contain setting ik i spelt wrong idc
Step-by-step explanation:
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