Guyton de Morveau, a French chemist, created a system for naming compounds that is still used today. For example, he said that a compound of zinc and chorine is called zinc chloride. Which of the
following is true about de Morveau's naming system?

A. The non-metallic atom is last.
B. The metallic atom is last.
C. The larger atom is first.
D. The smaller atom is first.

Presence of the substance in Air is O₃ < CO₂ < Ar < O₂ < N₂ is in this order.

O₃ is Ozone or trioxygen, CO₂ is Carbon dioxide, Ar is Argon, O₂ is Oxygen and N₂ is Nitrogen. An inorganic molecule having the chemical formula O 3 is ozone, often known as trioxygen. It is a gas that is a light blue color and smells strongly of sulfur. Atomic number 7 and the chemical symbol N belong to nitrogen. The lightest element in group 15, or the pnictogens, of the periodic table, nitrogen is a nonmetal. It is a common element in the universe and is regarded as the seventh most plentiful in the Milky Way and the Solar System. N2 is a diatomic gas that is colorless and odorless when two of the element's atoms join together at standard pressure and temperature. N2 is the most prevalent uncombined element and makes up around 78% of the Earth's atmosphere.

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The correct answer is (D) both mass and charge.

In all oxidation-reduction (redox) reactions, there is a conservation of both mass and charge. This principle is known as the law of conservation of mass and the law of conservation of charge. The law of conservation of mass states that matter cannot be created or destroyed in a chemical reaction. The total mass of the reactants must be equal to the total mass of the products. The law of conservation of charge states that the total electric charge of the reactants must be equal to the total electric charge of the products. During a redox reaction, electrons are transferred from one species to another, resulting in changes in oxidation states. However, the total charge of the system remains constant.

Therefore, in all oxidation-reduction reactions, there is a conservation of both mass and charge, the correct answer is  (D) both mass and charge.

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Answer: contact metamorphism

Explanation:

Contact metamorphism happens when a body of magma intrudes into the upper part of the crust. Heat is important in contact metamorphism, but pressure is not a key factor, so contact metamorphism produces non-foliated metamorphic rocks such as hornfels, marble, and quartzite.

Answer:

Explanation:

2H2O = H2 + O2

this ain't balanced because the value of hydrogen are not the same.

The cost associated with making one cold pack is $1.323.

From the table :

Ammonium chloride cost = $ 63 per Kg

To make an effective cold pack, 21. 0 g of ammonium chloride is required.

So,

cost for 21g  ammonium chloride =0.021 x 63 = $ 1.323.

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Answer:

\(C_{2}H_{8} O_{6}\)

Explanation:

Molecular formula can be calculated by finding the ratio of the molecular molar mass to the empirical molar mass, then multiplying the subscripts of the empirical molar mass by that ratio.

The empirical molar mass is 3(12.01) + 4(1.01) + 3(16.00) = 88.07

The molecular molar mass is 180g

180/88.07 = 2

So the molecular formula is \(C_{2}H_{8} O_{6}\)

Thomas Paine once said it is only error and not truth that shrinks from inquiry. He meant that the more you inquire about something, less error and mistakes come from it, and more truth will.

It means that you can not make a problem worse by inquiring about it but you can only lessen the error within it. Thomas Paine was likely referring to the idea that truth has nothing to fear from examination or investigation, whereas error does. In other words, if a belief or idea is true, it should be able to withstand scrutiny and examination. On the other hand, if a belief is based on error, it will crumble when subject to inquiry.

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The distribution of electrons in carbon and sodium atoms is 1s²2s²2p² and 1s²2s²2p⁶3s¹ respectively.

1s²2s²2p² is the distribution of electrons in carbon and 1s²2s²2p⁶3s¹ is the distribution of electrons in sodium.

The atomic number of Carbon is 6 and sodium is 11.

This indicates the presence of two electrons in the innermost orbital of carbon, further the next electrons are in the 2s orbital and next two electrons are in the orbital 2p in the carbon atom. So, we can write, the distribution of electrons is 1s²2s²2p².

However, In sodium atom, this indicates the presence of two electrons in the innermost orbital of carbon, further the next electrons are in the 2s orbital and next six electrons are in the orbital 2p and further one electron in the 3s orbital. So, we can write, the distribution of electrons is 1s²2s²2p⁶3s¹

The Electronic configuration is the distribution of electrons in the atom containing orbitals according to a basic principle.

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Answer:

1. 2.1 moles of Mg

2. 0.72 mole of Mg(OH)2

Explanation:

1. We'll begin by writing the balanced equation for the reaction. This is given below:

3Mg + 2AlBr3 —> 3MgBr2 + 2Al

From the balanced equation above, 3 moles of Mg reacted to produce 2 moles of Al.

Therefore, Xmol of Mg will react to produce 1.4 moles of Al i.e

Xmol of Mg = (3 x 1.4)/2

Xmol of Mg = 2.1 moles.

Therefore, 2.1 moles of Mg is required to 1.4 moles of Al.

2. We'll begin by calculating the number of mole in 26g of water, H2O.

This is illustrated below:

Molar mass of H2O = (2x1) + 16 = 18g/mol

Mass of H2O = 26g

Number of mole of H2O =?

Mole = Mass /Molar Mass

Number of mole of H2O = 26/18

Number of mole of H2O = 1.44 moles

Next, we shall write the balanced equation for the reaction. This is given below:

2HNO3 + Mg(OH)2 —> Mg(NO3)2 + 2H2O

Finally, we can obtain the number of mole of Mg(OH)2 used in the reaction as follow:

From the balanced equation above,

1 mole of Mg(OH)2 reacted to produce 2 mole of H2O.

Therefore, Xmol of Mg(OH)2 will react to produce 1.44 moles of H2O i.e

Xmol of Mg(OH)2 = (1 x 1.44)/2

Xmol of Mg(OH)2 = 0.72 mole.

Therefore, 0.72 mole of Mg(OH)2 was used in the reaction.

From the stoichiometry of the reaction, the mass of AgNO3 required is 340 Kg.

In the second step, 2 moles of AgI produces 1 mole of FeI2

In the third step, 2 moles of FeI2 produces 2 moles of I2

In the third step;

1000 moles of I2 is produced by 1000 moles of FeI2

2 moles of AgI produces 1 mole of FeI2

x moles of AgI produces 1000 moles of FeI2

x = 2 moles × 1000 moles/ 1 mole

x = 2000 moles

2000 moles of AgI is produced by 2000 moles of AgNO3

Mass of AgNO3 required = 2000 moles of AgNO3  × 170 g/mol = 340 Kg

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To draw the planes indicated by the Miller indices (121) and (212) in a unit cell of a cubic lattice, we follow these steps:

 To find the perpendicular distance between the origin and each plane, we can use the formula:

  Distance = sqrt((x-intercept)^2 + (y-intercept)^2 + (z-intercept)^2)

1. Determine the intercepts:

  For the Miller indices (hkl), the intercepts on the x, y, and z axes are determined by taking the reciprocals of the indices:

  Intercept on x-axis = 1/h

  Intercept on y-axis = 1/k

  Intercept on z-axis = 1/l

2. Scale the intercepts:

  Multiply the intercepts by the lattice constant parameter (a) to scale them to the appropriate size.

  Scaled intercept on x-axis = (1/h) * a

  Scaled intercept on y-axis = (1/k) * a

  Scaled intercept on z-axis = (1/l) * a

3. Draw the planes:

  Place the plane on each axis by drawing lines perpendicular to the axes at the scaled intercepts. The points where the lines intersect will determine the position of the plane in the unit cell.

4. Determine the perpendicular distance:

  To find the perpendicular distance between the origin and each plane, we can use the formula:

  Distance = sqrt((x-intercept)^2 + (y-intercept)^2 + (z-intercept)^2)

By following these steps, you can draw the planes and calculate the perpendicular distances between the origin and each of them in the given unit cell.

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Answer:

1+2 = 12

Explanation:

this is a math equation, not a chemical formula

a) The chemical reaction is a displacement reaction

b) The reason is position in the electrochemical series.

We know that a chemical reaction has to do with the combination of the reactants and the formation of the products. We have to look at the reaction so that we can bee able to decide the kind of reaction tat is taking place there.

We know that sodium is more electropositive than magnesium hence sodium would replace magnesium from a solution of its salt and what we would have there is a displacement reaction.

The reason while Al would react with copper II chloride but not magnesium chloride is that magnesium is higher than Al in the electronchemical series so it can not b able to displace it in solution. While Al is greater than Cu in the series hence it can displace it from its salt.

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Explanation:

\(C_{(s)} + O_{2(g)} \rightleftharpoons CO_{2(g)}\)

According to le ch-atelier's principle when a chemical reaction at equilibrium subjected to any stress, then the equilibrium shifts in that direction in which effect of stress is reduced.

When we would add more number of carbon in above reaction then rate of forward reaction will increase to attain the equilibrium again.

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Understanding alpha decay and the formation of daughter nuclides like lead-210 is an important part of nuclear physics and has many practical applications in science and technology.

Polonium-214 is a radioactive nuclide that undergoes alpha decay. In alpha decay, an atomic nucleus emits an alpha particle, which consists of two protons and two neutrons. This results in the nucleus losing two protons and two neutrons, and therefore changing into a different element. The daughter nuclide that forms as a result of alpha decay has a different atomic number and mass number than the parent nuclide.

In the case of polonium-214, the daughter nuclide that forms is lead-210. Lead-210 is also a radioactive nuclide, but it undergoes beta decay, in which a neutron is converted into a proton and an electron. This results in the nucleus gaining one proton and losing one neutron, which changes the element again.

The decay of polonium-214 to lead-210 is a natural process that occurs over time. Polonium-214 has a half-life of about 164 microseconds, which means that it takes that amount of time for half of the atoms in a sample to decay. This makes it a useful tool in scientific research and medical applications, but it can also be dangerous due to its radioactive properties.

Overall, understanding alpha decay and the formation of daughter nuclides like lead-210 is an important part of nuclear physics and has many practical applications in science and technology.

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The 'reabsorption' of HCO3 (bicarbonate) in the proximal tubule is dependent on the secretion of H+ (hydrogen ions).

Here's a step-by-step explanation:
1. In the proximal tubule, the reabsorption process starts with the secretion of H+ ions into the tubular lumen.
2. The secreted H+ ions combine with HCO3- ions present in the tubular fluid to form H2CO3 (carbonic acid).
3. H2CO3 then dissociates into H2O (water) and CO2 (carbon dioxide) in the presence of the enzyme carbonic anhydrase.
4. H2O and CO2 are reabsorbed back into the proximal tubule cells, where they combine to form H2CO3 again.
5. H2CO3 dissociates into H+ and HCO3- ions, and HCO3- is reabsorbed into the bloodstream.

So, the reabsorption of HCO3- in the proximal tubule is dependent on the secretion of H+ ions.

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The volume of the gas at a temperature of 405.0 K would be 607.5 mL. Making option D the right answer to the question.

What is the volume of the gas?

To find the volume of the gas, the equation to be used would have to be combine gas law.

Combine gas law as the name suggest uses the combination of Charles law which measures Volume against temperature, and Gay-Lussac's law which measures Pressure/Temperature, and Boyle's law  which measures pressure X volume where k is constant.

Using the combine law to find the volume, we have:

P₁V₁/T₁=P₂V₂/T₂

Where P₁ = initial pressure

           V₁ = initial volume

             T₁ = initial temperature

            P₂ = final  pressure

            V₂ = final  volume

            T₂ = final  temperature

P₁ = 2.25atm

V₁ = 450.0 mL

T₁ = 300 K

T₂ = 405.0 K

V₂ = ?

D) 607.5 mL

= [2.25(450)]÷300=[2.25(V₂]÷405

Making  V₂ the subject

 3.375=2.25 V₂ ÷ 405

V₂ = 3.375 x 405 ÷ 2.25

V₂ = 607.5 mL

In summary, a gas with an initial pressure of 2.25atm, an initial pressure of 450.0 mL and an initial temperature of 300 K would have a final volume of 607.5 mL if the temperature is increased to  405.0 K.

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Answer:

The change in entropy is negative; -ΔS

Explanation:

The entropy of a system measures the degree of randomness or energy dispersal of the system. The symbol for entropy is S.

For a given system, the change in entropy is symbolized as ΔS.

For an increase in entropy of a system, the final entropy must be greater than the initial entropy  i.e. Δfinal > Δinitial. Therefore ΔS > 0

For a decrease in entropy of a system, the final entropy must be less than the initial entropy  i.e. Δfinal < Δinitial. Therefore ΔS < 0 or ΔS is negative

A system with decreasing entropy may have a positive or negative free energy change, ΔG.

Also, a system with decreasing entropy may have a positive or negative enthalpy change, ΔH.

Answer:

I think it is b chromosomes are made of DNA. I'm not for sure tho sorry

The volume that is occupied by the gas is obtained as  56 L.

We know that from the Avogadro's law, the volume that can be occupied by one mole of a gas is obtained as 22.4 L. This implies that we have to find the number of moles in the 70 g of the CO and then obtain the corresponding volume by simple proportion.

Number of moles of CO = 70.0 g/28 g/mol

= 2.5 moles

If 1 mole of the gas occupies 22.4 L

2.5 moles of the gas occupies 2.5 * 22.4/1 mole

= 56 L

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Storing red blood cells (RBCs) requires proper preservation techniques to maintain their viability and functionality. One method is the high glycerol preservation method, which uses a high concentration of glycerol (40%) to protect the cells during storage. The temperature at which the RBCs are stored also plays a crucial role in determining their longevity.

Out of the options listed, the correct temperature for storing RBCs prepared with high glycerol preservation method is at 0°C or lower. At this temperature, the glycerol solution slows down cellular metabolism, preserving the viability and functionality of the RBCs for a longer period of time. Storing RBCs at 65°C or lower may damage the cells, rendering them unusable for transfusion. Similarly, storage at 20°C or lower may result in short-term preservation but is not ideal for long-term storage as it may cause a significant reduction in RBC viability. Storing RBCs at 10°C or lower may provide short-term preservation, but it may not be optimal for long-term storage as the low temperature may cause freezing of the cells, leading to irreversible damage.

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The pillar of sustainability broken by recycling electronics in India is environmental sustainability. Implementing a law that restricts electronics recycling to the US would not necessarily be the most effective solution, as it overlooks the complex global dynamics of electronic waste management.

Recycling electronics in India often involves improper disposal methods, such as burning or dismantling without proper safety measures. This leads to environmental pollution, including the release of hazardous substances into the air, soil, and water, thus violating the principle of environmental sustainability.

However, simply mandating that electronics can only be recycled in the US may not be the most optimal solution. Electronic waste is a global issue, and restricting recycling to a single country disregards the fact that electronic products are manufactured and consumed worldwide. A more comprehensive approach to addressing electronic waste would involve international cooperation, strict regulations, and monitoring of recycling practices to ensure they meet environmental standards.

Efforts should focus on improving recycling practices globally, including promoting responsible electronic waste management, developing sustainable recycling infrastructure in multiple countries, and encouraging the adoption of safe and environmentally friendly recycling practices. This approach would foster global sustainability and address the challenges associated with electronic waste disposal more effectively than a geographically limited restriction.

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Answer:

Number 2 is Direction

Explanation:

The old answer for number four was incorrect

I apologize for the inconvenience but I do not have an answer that fits in the lines for number 4

Answer:

19.6 g of N2

Explanation:

2 NH3 + 3 CuO g 3 Cu + N2 + 3 H2O

In the above equation how many grams of N2 can be made when 167 grams of CuO are consumed?

Round your answer to the nearest tenth. If you answer is a whole number like 4, report the answer as 4.0

Use the following molar masses. If you do not use these masses, the computer will mark your answer incorrect.:

Hydrogen

1

Nitrogen

14

Copper

63.5

Oxygen

16

first, we should rewrite the equation without using "g " for the yields sign

2 NH3 + 3 CuO ---------> 3 Cu + N2 + 3 H2O

next we need the molar mass of the compounds

CuO =63.5 + 16 = 79.5

N2 = 2 x 14 = 28

next , we see that 3 moles of CuO produce 1 mole of N2

167 g of CuO is 167/79.5 = 2,1 moles of CuO

since 3 moles produce 1 mole of N2

2,1 moles produce 2.1/3 = 0.7 moles of N2

1 mole of N2 is 28 gm

0.7 moles is 28x0.7 = 19.6 g of N2

Answer:

pOH = 8

Explanation:

There are many formulaes to go from pH to pOH. One of my favorites is this one:

pH+pOH=14  (Now this just becomes an algebra problem because you already know pH value)

6 + pOH = 14 (subtract 6 from both sides)

pOH= 8

Answer:

D

Explanation:

If we put pressure on a solid or a liquid, there is essentially no change in volume.

Matter are anything that is made up of atoms. The quantity of matter can be observed only on the basis of mass and volume calculation. Therefore, the incorrect statement is option D that is there is a large decrease in the volume of a solid metal when pressure is applied to it.

Matter is a substance that has some mass and can occupy some volume. The matter is mainly used in science. Matter can be solid, liquid or gas.

Matter is anything that is made up of atoms. Anything around us that can be physically seen and touched are matter. Ice, water and water vapors are example of matter. When we apply pressure on solid, then there is no change in volume of the solid matter.

Therefore, the incorrect statement is option D that is there is a large decrease in the volume of a solid metal when pressure is applied to it.

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Answer:

a) 2

b) 3

c) 5

d) 6

Explanation:

a. The empirical formula of a 5.000 g sample of an unknown insecticide made up of C, O, and Cl is C₄H₈Cl₂.

b. The molecular formula if the unknown’s molar mass is around 354 g/mol is C₈H₁₆Cl₄.

To determine the empirical formula of a 5.000 g sample of an unknown insecticide made up of C, O, and Cl, we are given:

First, let's calculate the number of moles of CO₂ and H₂O.

Now, calculate the moles of C, H and Cl atoms.

Now, let's determine the empirical formula. The empirical formula shows the simplest ratio of atoms in the compound.The empirical formula of the unknown insecticide is C₄H₈Cl₂.

To determine the molecular formula if the unknown’s molar mass is around 354 g/mol, we must calculate the empirical mass of C₄H₈Cl₂.

EM of C₄H₈Cl₂ = (4 × 12.01) + (8 × 1.01) + (2 × 35.45)

= 170.72 g/mol

Now, let's calculate the number of empirical units in 354 g/mol.

354 / 170.72

= 2.07 ≈ 2

So, the molecular formula of the unknown insecticide is twice the empirical formula. Therefore, the molecular formula is C₈H₁₆Cl₄.

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O2- Option B is correct

Explanations:

Calcium atom is a group 2 elements that gives out two electrons in order to form a stable configuration and a Ca2+ ion. These two electrons are transferred to an atom that required two electrons to complete its outer shell.

Since oxygen required 2 electron to attain its octet configuration, hence they can easily accepts the two electrons from calcium atoms to form CaO which is composed of Ca2+ and O2- ions in the ratio of one Ca2+ ion to one O2− ions.

It will take __6.4 years.___ years to double your money at a 11% rate of interest compounded annually.

Compounded interest is aa type of interest that allows investors to earn interest on both their initial principal and any interest earned. The compounding frequency refers to the number of times per year that interest is paid out or credited to an account. Annual compounding, which is once per year, is a common compounding frequency. To double your money in annual compounded interest, use the rule of 72, which says that 72 divided by the interest rate equals the number of years it takes to double your money. Using this formula, we have 72/11, which equals about 6.4 years. Thus, it will take approximately 6.4 years to double your money at an 11% rate of interest compounded annually.

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