H3PO4 has three acidic protons with the following Ka values:


Ka1 = 7.1 x 10^â3

Ka2 = 6.3 x 10^â8

Ka3 = 4.5 x 10^â13


If you have this acid in a solution with a pH=1.5 what is the predominate form of the compound in solution?

Answer:

Transmission means light waves bending when it enters a different medium

Explanation:

To react with 0.784 g of silver, you will need 0.00843 L or 8.4 mL of 1.15 M HNO₃(aq).

To solve this problem, we need to use stoichiometry and dimensional analysis. First, we need to convert the mass of silver given in grams to moles by dividing it by its molar mass:

0.784 g Ag / 107.87 g/mol Ag = 0.00725 mol Ag

According to the balanced chemical equation, 4 moles of HNO₃ react with 3 moles of Ag. So we can set up a proportion:

4 mol HNO₃ / 3 mol Ag = x mol HNO₃ / 0.00725 mol Ag

Solving for x, we get:

x = 4/3 * 0.00725 mol HNO₃ = 0.00967 mol HNO₃

Now we can use the molarity of the nitric acid solution given to calculate the volume of solution needed:

Molarity = moles of solute/liters of solution

1.15 M = 0.00967 mol HNO₃ / V liters HNO₃

Solving for V, we get:

V = 0.00967 mol HNO₃ / 1.15 M = 0.0084 L HNO₃

Finally, we can convert the volume from liters to milliliters:

0.0084 L HNO₃ * 1000 mL/L = 8.4 mL HNO₃

Therefore, 8.4 mL of 1.15 M HNO₃ solution is required to react with 0.784 g of silver.

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Answer:

He has a deep respect for the horse,so he treats him with care

Answer:

It's C

Explanation:

Good luck on the test.

Answer: Number of atoms: 1.82 x 10^21

Explanation:

To calculate the number of atoms present in the sample of gold, we can use the equation:

E = Nhf

Where:

E is the total energy emitted by the sample,

N is the number of atoms,

h is the Planck's constant (approximately 6.626 x 10^-34 J·s),

f is the frequency of each photon.

We are given the total energy emitted by the sample as 12.2 kJ, which we need to convert to joules:

12.2 kJ = 12.2 x 10^3 J

The frequency of each photon is related to the threshold frequency by the equation:

f = threshold frequency

Substituting the given values:

f = 1.20 x 10^15 Hz

Now we can rearrange the equation E = Nhf to solve for N:

N = E / (hf)

Substituting the values:

N = (12.2 x 10^3 J) / ((6.626 x 10^-34 J·s) * (1.20 x 10^15 Hz))

Performing the calculation:

N ≈ 1.82 x 10^21

Therefore, the number of atoms present in the sample is approximately 1.82 x 10^21.

Answer:smaller larger smaller smaller larger

Explanation:

Just took the test on edge

Answer:

smaller

larger

smaller

smaller

larger

Explanation:

on edge

Answer:

ion- ion> H - bonding > dipole > dipole> london dispersion

The ratio of radioactive atoms to other kinds of atoms changes over time. Hence, option C is correct.

In the process of radioactive decay the unstable atom nuclei of the parent nucleus break down and split so as to release the daughter atoms or nuclei along with the release of energy in the form of heat. Thus as the decay process proceeds the concentration of the parent atom decreases but the concentration of the daughter atom increases.

Radioactive atoms can be used to date materials because the radioactive decay occurs at a known rate, and the density of fission tracks for the amount of uranium within a mineral grain can be used to determine its age.

Hence, option C is correct.

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Answer:

1-T

2-F

3-T

4-T

Explanation:

big brain

Answer:

234

Explanation:

Answer:

0.07 g/s.

Explanation:

From the question given above, the following data were obtained:

Mass lost = 9.85 g

Time taken = 2 min 30 s

Mean rate =?

Next, we shall convert 2 min 30 s to seconds (s). This can be obtained as follow:

1 min = 60 s

Thus,

2 min = 2 × 60 = 120 s

Therefore,

2 min 30 s = 120 s + 30 s = 150 s

Finally, we shall determine the mean rate of the reaction. This can be obtained as illustrated below:

Mass lost = 9.85 g

Time taken = 150 s

Mean rate =?

Mean rate = mass lost / time taken

Mean rate = 9.85 / 150

Mean rate = 0.07 g/s

Therefore, the mean rate of the reaction is 0.07 g/s

One tightens and the other relaxes to make the bones move. Hence, option A is correct.

A muscle is a group of muscle tissues which contract together to produce a force. A muscle consists of fibres of muscle cells surrounded by protective tissue, bundled together with many more fibres, all surrounded by thick protective tissue.

Muscles work in pairs, when one muscle shortens the opposite muscle lengthens e.g. the biceps shortens to bend the elbow at the same time its opposite muscle, the triceps, lengthens to allow the movement to occur. Good working between pairs of muscles allows for smooth controlled movement.

One tightens and the other relaxes to make the bones move. Hence, option A is correct.

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\(2 \text{ KClO}_3 \to 2 \text{ KCl}+3\text{ O}_2\)

a)

\(2 \text{ mols of KClO}_3 \equiv 3 \text{ mols of O}_2\)

\(19 \text{ mols of KClO}_3 \equiv 3\cdot 9,5 \text{ mols of O}_2\)

\(\boxed{19 \text{ mols of KClO}_3 \equiv 28,5 \text{ mols of O}_2}\)

b)

\(2 \text{ mols of KClO}_3 \equiv 2 \text{ mols of KCl}\)

\(62 \text{ mol of KClO}_3 \equiv 62 \text{ mol of KCl}\)

Using the atomic mass given in the periodic table:

\(62\cdot(39+35,5+16\cdot3) \text{ g of KClO}_3 \equiv 62 \text{ mol of KCl}\)

\(62\cdot122,5 \text{ g of KClO}_3 \equiv 62 \text{ mol of KCl}\)

\(7595 \text{ g of KClO}_3 \equiv 62 \text{ mol of KCl}\)

\(\boxed{7,595 \text{ kg of KClO}_3 \equiv 62 \text{ mol of KCl}}\)

c)

\(2 \text{ KCl}+3\text{ O}_2\to 2 \text{ KClO}_3\)

\(3 \text{ mols of O}_2 \equiv 2 \text{ mols of KCl}\)

Using the atomic mass given in the periodic table:

\(3\cdot(2\cdot 16) \text{ g of O}_2 \equiv 2\cdot(39+35,5) \text{ g of KCl}\)

\(96\text{ g of O}_2 \equiv 149\text{ g of KCl}\)

\(\dfrac{39}{149}\cdot 96\text{ g of O}_2 \equiv \dfrac{39}{149}\cdot 149\text{ g of KCl}\)

\(\boxed{25,13\text{ g of O}_2 \equiv 39\text{ g of KCl}}\)

This result is an aproximation.

Explanation:

What type of floor. You have uploaded no image

The main reservoirs of the carbon cycle are the atmosphere, oceans, land (including vegetation and soils), and fossil fuels. In these reservoirs, carbon exists in both inorganic and organic forms.

The inorganic carbon cycle involves the exchange of carbon dioxide (CO2) between the atmosphere and oceans through processes like photosynthesis and respiration.

Organic carbon, on the other hand, is found in living organisms, dead organic matter, and soil organic matter. It is cycled through processes such as decomposition and consumption by organisms. The interactions between the inorganic and organic carbon cycles occur primarily in the biosphere, where photosynthesis converts inorganic carbon into organic carbon compounds. While inorganic carbon is primarily in the form of CO2, organic carbon is present in complex organic molecules. Both forms of carbon play crucial roles in energy transfer, nutrient cycling, and climate regulation.

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The method used to separate a mixture of ethyl alcohol and water is distillation. Thus option (d) is true.

Distillation is defined as a process involving the conversion of liquid into vapor that is subsequently condensed back into liquid form.

It is a widely used method for separating the mixture based on difference in conditions required to change the phase of components.

Some of the types of distillation are:

Thus, the method used to separate a mixture of ethyl alcohol and water is distillation. Thus option (d) is true.

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Your question is incomplete, but most probably your complete question was

The apparatus in Image A above is used to separate a mixture of ethyl alcohol and water. The mixture is heated in the flask on the left and the ethyl alcohol drips into the flask on the right after condensing in the cooling tube in the middle. Which method was used to separate the mixture?

a. chromatography

b .filtration

c .sorting

d distillation

The amount of concentrated solution needed is (0.286 M)(65 mL) / C M, and the amount of water needed is 65 mL minus the volume of the concentrated solution.

To calculate the molarity of Kool Aid desired, we need to determine the number of moles of Kool Aid powder and sugar in the package. Since the molecular formula for sugar is C12H22O11, we can calculate its molar mass as follows:

Molar mass of C12H22O11 = (12 * 12.01) + (22 * 1.01) + (11 * 16.00)

= 144.12 + 22.22 + 176.00

= 342.34 g/mol

Given that the package contains 4.25 grams of Kool Aid powder, we can calculate the number of moles of Kool Aid powder using its molar mass:

Number of moles of Kool Aid powder = Mass / Molar mass

= 4.25 g / 342.34 g/mol

≈ 0.0124 mol

Similarly, for the sugar, which has a molar mass of 342.34 g/mol, we can calculate the number of moles of sugar using its mass:

Number of moles of sugar = Mass / Molar mass

= 192.00 g / 342.34 g/mol

≈ 0.5612 mol

Now, to calculate the molarity of the desired Kool Aid solution, we need to determine the volume of water. Given that 1.06 quarts is equal to 1 liter, and we have 2.00 quarts of water, we can convert it to liters as follows:

Volume of water = 2.00 quarts * (1.06 liters / 1 quart)

= 2.12 liters

To find the molarity, we use the formula:

Molarity (M) = Number of moles / Volume (in liters)

Molarity of Kool Aid desired = (0.0124 mol + 0.5612 mol) / 2.12 L

≈ 0.286 M

To prepare 65 mL of the desired molarity, we can use dilution calculations. We need to determine the volume of concentrated solution and the volume of water needed.

Let's assume the concentration of the concentrated Kool Aid solution is C M. Using the dilution formula:

(C1)(V1) = (C2)(V2)where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration, and V2 is the final volume.

Given that C1 = C M and V1 = V mL, and we want to prepare a final volume of 65 mL (V2 = 65 mL) with a final concentration of 0.286 M (C2 = 0.286 M), we can rearrange the formula to solve for the volume of the concentrated solution:

(C M)(V mL) = (0.286 M)(65 mL)

V mL = (0.286 M)(65 mL) / C M

So, the amount of concentrated solution needed is (0.286 M)(65 mL) / C M, and the amount of water needed is 65 mL minus the volume of the concentrated solution.

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Arrhenius :

acid: a compound that releases H⁺ ions in water

base: a compound that releases OH⁻ ions in water

H2S Arrhenius acid

RbOH Arrhenius base.

Mg(OH)2  Arrhenius base.

H3PO4 Arrhenius acid

A chemical equation is said to be balanced when the number of atoms of each element on both sides of the equation are the same.

According to this question, a reaction occured between ammonia gas and oxygen gas to produce nitrogen gas and water.

Based on the equation, 4 moles of ammonia requires 3 moles of oxygen gas to react.

This means that 3.53 moles of ammonia will require 3.53 × ¾ = 2.65 moles of oxygen gas.

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Answer:

Chemists use a solution called Universal Indicator to identify acids and bases. ... The Universal Indicator Color Guide shows that Universal Indicator turns red when it is added to a strong acid, it turns purple when it is added to a strong base, and it turns a yellowish-green when it is added to a neutral solution.

Explanation:

Answer:

Phenolphthalein

Explanation:

Answer:

Distance cover = 8 km

Explanation:

Given:

Speed of runner = 4 km/h

Time taken = 2 hour

Find:

Distance cover

Computation:

Distance = Speed x Time

Distance cover = Speed of runner x Time taken

Distance cover = 4 x 2

Distance cover = 8 km

Answer:

[Zn(C₂H₃O₂)₂] = 1.85M (3 sig-figs accurate to 0.01 Molar)

Explanation:

Concentration is defined as amount of solute in a specified volume of solution. That is, Concentration = mass of solute/volume of solution (solution = solute + solvent). When concentration is in terms of Molar values the essential relationship is Molarity(M) = moles solute / volume of solution in liters.

For this problem => first, convert mass of Zn(C₂H₃O₂)₂ into moles and then the volume of solution into liters. Take ratio of moles/volume of solution (L).

=> Molar Concentration = moles of Zn(C₂H₃O₂)₂ / Liters of solution

moles of Zn(C₂H₃O₂)₂ = 85.0 grams Zn(C₂H₃O₂)₂ / formula weight of Zn(C₂H₃O₂)₂  =  85.0g/183.5g·mole⁻¹ = 0.463 mole Zn(C₂H₃O₂)₂.

Volume of solution in Liters = 250ml / 1000ml/L = 0.250 liters

Molarity of  Zn(C₂H₃O₂)₂ solution = 0.463 mole Zn(C₂H₃O₂)₂  /0.250 liters of solution = 1.85 Molar in Zn(C₂H₃O₂)₂

_____________

Note: The symbiology convention for 'molar solution concentration' is to place brackets around the molecular formula. That is, [Zn(C₂H₃O₂)₂] = 1.85M

Answer:

Dissolving is when the solute breaks up from a larger crystal of molecules into much smaller groups or individual molecules. This break up is caused by coming into contact with the solvent. In the case of salt water, the water molecules break off salt molecules from the larger crystal lattice.

Explanation:

Answer:

Gases can dissolve in water. The dissolving of a gas in water depends on the interaction between the molecules of the gas and the water molecules. The amount of gas that can be dissolved in water depends on the temperature of the water. More gas can dissolve in cold water than in hot water.

Explanation:

Organic compounds are characterized by covalent bonds and molecular solids. Therefore, the correct option is 3.

Covalent bonds are formed when atoms share electrons to achieve a stable electron configuration. In organic compounds, carbon atoms are usually bonded to other carbon atoms and to hydrogen atoms, forming a variety of functional groups. These functional groups give organic compounds their unique properties and reactivity.
Molecular solids are formed when molecules are held together by intermolecular forces, such as van der Waals forces, hydrogen bonds, and dipole-dipole interactions. Organic compounds typically have low melting and boiling points due to the weak intermolecular forces between the molecules. However, there are exceptions to this general rule, such as polymers, which can have high melting and boiling points due to their long, chain-like structures.
In contrast, ionic bonds and ionic solids are characteristic of inorganic compounds, which typically involve the transfer of electrons between atoms to form ions. Ionic solids are held together by strong electrostatic forces between ions of opposite charges, resulting in high melting and boiling points. In summary, covalent bonds and molecular solids are the characteristic bonds and solids of organic compounds.

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Answer:

1 answer

Explanation:

The mass of HClO₄ required to produce the desired pH in a 0.600 L solution can be calculated using the Henderson-Hasselbalch equation and the molecular weight of HClO₄.

The Henderson-Hasselbalch equation relates the pH of a solution to the acid dissociation constant (pKa) and the ratio of the concentrations of the acid (HA) and its conjugate base (A-). For HClO₄, pKa is approximately -7.2. Therefore, [A-]/[HA] can be solved for using the rearranged Henderson-Hasselbalch equation: [A-]/[HA] = 10^(pH - pKa).

For example, to obtain a solution with pH = 1.0, [A-]/[HA] = 10^(1.0 - (-7.2)) = 7.94 x 10^8. Assuming that the total volume of the solution is 0.600 L, and that the desired concentration of ClO4- is equal to the concentration of HClO₄, which is equal to [HA], then [HA] = 0.600 L / (1 + 7.94 x 10^8) = 7.54 x 10^-10 M. The mass of HClO₄ required to produce this concentration can be calculated using the molecular weight of HClO₄: 7.54 x 10^-10 mol/L x 100.46 g/mol = 7.57 x 10^-8 g, or 0.0757 mg.

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0.3 agarose is needed to prepare a 1 % agarose gel with 30 ml total volume .

We know that ,  a 1 % agarose gel in 100 ml  can be prepared by adding 1 g of agarose in 100 ml of water.(solvent).

1 % agarose gel in 100 ml of solvent  = 1 gram of agarose

Therefore , 1 % agarose gel in 30 ml can be prepared from ,

1 % agarose gel in 30 ml of solvent =  \(\frac{1}{100}\) × 30 gram of agarose

                                                            = \(\frac{30}{100}\) g of agarose

                                                            = 0.3 g of agarose

Therefore , the amount of agarose required to prepare 1 % agarose gel with 30 ml total volume  is 0.3 g

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To prepare a 1% agarose gel with a total volume of 30 ml, you will need 0.3 grams of agarose.

To calculate how many grams of agarose you will need to prepare a 1% agarose gel with a 30 ml total volume, you can use the formula:

Agarose mass (g) = 1% x Total volume (ml)

Plugging in the values, the calculation becomes:

Agarose mass (g) = 1% x 30 ml = 0.01 x 30 = 0.3 g

Therefore, you will need 0.3 grams of agarose to prepare the 1% agarose gel with a total volume of 30 ml.

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Answer:

First, we can find the partial pressure of carbon dioxide in the scuba tank by subtracting the sum of partial pressures of oxygen and nitrogen from the total pressure:

partial pressure of CO2 = total pressure - partial pressure of O2 - partial pressure of N2

partial pressure of CO2 = 3.33 atm - 1.20 atm - (unknown partial pressure of N2)

partial pressure of CO2 = 2.13 atm - (unknown partial pressure of N2)

Since the enhanced mixture only contains oxygen and nitrogen, the sum of their partial pressures should equal the total pressure:

partial pressure of O2 + partial pressure of N2 = total pressure

1.20 atm + partial pressure of N2 = 3.33 atm

partial pressure of N2 = 3.33 atm - 1.20 atm

partial pressure of N2 = 2.13 atm

Now we can substitute this value into the equation we found for the partial pressure of CO2:

partial pressure of CO2 = 2.13 atm - partial pressure of N2

partial pressure of CO2 = 2.13 atm - 0.77 atm

partial pressure of CO2 = 1.36 atm

Therefore, the partial pressure of nitrogen in the scuba tank is 0.77 atm.

Explanation: