Hallar la altura de una asta bandera, si un estudiante la observa desde un punto a, con un ángulo de 30° y entre el estudiante y la asta hay una distancia de 10m.

The probability of rolling a number greater tan 2 on the blue cube and an odd number on the green cube is 1/3.

Here we roll two number cubes (each of these with 6 outcomes, {1, 2, 3, 4, 5, 6})

We want to find the probability of:

Getting a number greater than 2 on the blue cube and an odd number on the green cube.

First, there are 4 numbers greater than 2 (3, 4, 5, 6)on the blue cube, and 6 outcomes in total, then the probability is:

P = 4/6

For the green dice, there are 3 odd numbers:

1, 3, and 5

And there are a total of 6 outcomes, then the probability is:

Q = 3/6

The joint probability (for events) is

J = P*Q

J = (4/6)*(3/6)

J = (2/3)*(1/2)

J = 1/3

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Answer:

acute angle

Step-by-step explanation:

acute = less than 90 degrees

right = exactly 90 degrees

obtuse = more than 90 degrees

90 divided by 2 = 45

45 is less than 90 so acute angle

1/2 of a right angle is called an acute angle. The correct answer would be an option (D).

When two lines intersect at a location, vertical angles are generated. They are always equal to each other.

An angle with a measure of 1/2(90°) : 45°

As per the given question, the required solution would be as:

Straight: An angle with a measure of exactly 180° is considered straight. 45° is not a straight angle.

Obtuse: An angle with a measure greater than 90° and less than 180° is considered obtuse. 45° is not an obtuse angle.

Acute: An angle with a measure less than 90° is considered acute. 45° is an acute angle.

Thus, 1/2 of a right angle is called an acute angle.

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The solution to the equation 3 - 1/2d = 3/2d + 4 - d is d = -7

The expression is given as

3 - 1/2d = 3/2d + 4 - d.

Multiply through the expression by 2

So, we have

6 - d = 3d + 8 - 2d

Evaluate the like terms

6 - d = d + 8

Evaluate the like terms

2d = -14

Divide by 2

d = -7

Hence, the solution to the equation 3 - 1/2d = 3/2d + 4 - d is d = -7

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Answer:

Step-by-step explanation:

See attachment.

The change from x to (x-4) moved the function to the right by 4.  The - 5 moved it down by 5 (as measured from the crossover/inflection point.

The equation of the plane passing P(1,2,1) and is orthogonal to the two planes: x-y-z-10 = 0, x-2y + z-2=0 is 3x + 2y + z = 8.

We need a point b and a vector v along the line in order to characterize it. We might alternatively begin with the two points a and b and use the formula v = ab.
A point Q and a vector n perpendicular to the plane are required in order to describe a plane. Later on, we'll look at how to get n from various types of information, such as the positions of three points on a plane.

A plane is a flat, endlessly long, two-dimensional surface. A plane is a point with zero dimensions, a line with one dimension, and space with three dimensions in two dimensions. The picture below that is attached shows the answer.

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Question correction:

Find the equation of the plane passing P(1,2,1) and is orthogonal to the two planes: x-y-z-10 = 0, x-2y + z-2=0

Answer:

The length of the third piece of the ramp is;

D. 9.24 feet

Step-by-step explanation:

The given parameters are;

The height of the ramp = 8 feet

The angle between the piece that forms height and the base = 90°

The angle formed by the third piece connecting the height of the ramp to the furthest point and the 8 foot piece = 30°

Let 'y' represent the 8-foot piece forming the height, and let 'r' represent the third piece, by trigonometric ratio, we have;

\(cos(30^{\circ}) = \dfrac{y}{r}\)

Therefore, we get;

\(cos(30^{\circ}) = \dfrac{8}{r}\)

\(r = \dfrac{8 \ feet}{cos(30^{\circ})} = \dfrac{8 \ feet}{\dfrac{\sqrt{3} }{2} } = \dfrac{16 \cdot \sqrt{3} \ feet}{3} \approx 9.24 \ feet\)

The length of the third piece, r ≈ 9.24 feet

The reduced cost matrix for travelling salesperson problem in the given instance is shown below. The Travelling Salesperson Problem (TSP) is a classical combinatorial optimization issue that belongs to the category of NP-Hard problems.

This problem can be resolved using a branch and bound algorithm or by using dynamic programming.The reduced cost matrix for the given travelling salesperson problem instance The computation of the reduced cost matrix for travelling salesperson problem involves two steps: Identify the smallest element of each row and subtract the value from all the values in the row.

Identify the smallest element of each column and subtract the value from all the values in the column.In the given instance, the smallest element of each row is highlighted in bold. Therefore, after performing Step 1 the matrix becomes the matrix becomes Hence, the reduced cost matrix for the travelling salesperson problem is obtained.

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The ratio of the cooling time of Earth to the cooling time of the exoplanet is 16,777,216.

An exoplanet, also known as an extrasolar planet, is a planet that orbits a star other than the Sun, which is part of our solar system. An exoplanet is one of many planets that might exist in the universe outside of our solar system.

The ratio of the cooling time of Earth to the cooling time of the exoplanet can be determined using Stefan-Boltzmann's Law and Wien's Law.

We first need to use the Stefan-Boltzmann Law in order to calculate the cooling time.

σT⁴ = L/(16πR²)

σ(5780)⁴ = (3.846 × 10²⁶ W)/(16π(6.3781 × 10⁶)² m²)

Ratio of the exoplanet's radius to the Earth's radius:

re/rE = 8.00

Ratio of the exoplanet's mass to the Earth's mass:

me/mE = (re/re)³ = 8³ = 512 (since density is assumed to be the same for both planets)

Ratio of the exoplanet's luminosity to the Earth's luminosity:

Le/LE = (me/mE)(re/rE)² = 512(8)² = 32768

Ratio of the exoplanet's temperature to the Earth's temperature:

Te/TE = (Le/LE)¹∕⁴ = 32768¹∕⁴ = 32.0

The Wien Law can now be used to determine the ratio of the cooling times of the two planets.

(T/wavelength max)E = 2.898 × 10⁻³ m K(5780 K) = 1.68 × 10⁻⁸ m (using Earth as the comparison planet)

(T/wavelength max)e = 2.898 × 10⁻³ m K(Te)(8.00) = wavelength max (using the exoplanet)

Ratio of the wavelengths:

wavelength max,e/wavelength max,E = (Te/TE)(re/rE) = 32.0 × 8.00 = 256

Ratio of the cooling times:

cooling time,e/cooling time,E = (wavelength max,e/wavelength max,E)³ = 256³ = 16,777,216

Hence, the ratio of Earth's cooling time to the exoplanet's cooling time is 16,777,216.

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Answer: 105 couple tickets and 40 individual tickets

For this I will use the "Graphing Method"

     First, we need to set up two equations.

-> Let x be the number of couple tickets.

-> Let y be the number of individual tickets.

-> It is "2x" because a couple means two.

     $12x + $8y = $1,580

     2x + y = 250

     Next, we will graph this.

-> The point at which the two lines intersect is our solution.

-> See attached.

-> x = 105, so 105 couple tickets

-> y = 40, so 40 individual tickets

Have a nice day!

     I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly.

- Heather

Answer:

Step-by-step explanation:

Let's imagine if all the tickets were for individuals

The cost would be 250 x $8 = $2000
That is $420 higher than the actual cost.

The difference between a ticket for couples and a ticket for individuals is $4

Then, we can conclude that there are 420 : 4 = 105 couple tickets that were sold.

And, 40 individual tickets that were sold

The reason why we have 420:4 is because at the start, we assume every ticket was individuals. On the process, we replace one individual ticket by a couple ticket, keep replacing until the gap is exactly 420.

Hope this helps :)

Answer:

f(n) = 2 × \(3^{n-1}\)

Step-by-step explanation:

In order to write an explicit rule for a geometric function, you need to know the common ratio; you can find the common ratio by dividing two consecutive terms:

6 ÷ 2 = 3, 18 ÷ 6 = 3, 54 ÷ 18 = 3, etc..

Now you know the common ratio is 3. At this point you can write your explicit function following the rule f(n) = [1st term] × [common ratio]^(n-1):

f(n) = 2 × 3^(n-1)

The probability that 4 or more students score 85 percent or higher on the exam is 0.1209 or approximately 12.09 percent.

To solve this problem, we need to use the binomial distribution formula. We know that the probability of each student scoring 85 percent or higher on the exam is p = 0.2 (since 20 percent is equivalent to 85 percent or higher). We also know that n = 10 students took the exam.

Now we need to find the probability that 4 or more students score 85 percent or higher. We can use the binomial probability formula to calculate this:

P(X ≥ 4) = 1 - P(X < 4)

= 1 - (P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3))

= \(1 - [(10 choose 0) * 0.2^0 * (0.8)^10 + (10 choose 1) * 0.2^1 * (0.8)^9 + (10 choose 2) * 0.2^2 * (0.8)^8 + (10 choose 3) * 0.2^3 * (0.8)^7]\)
= 1 - (0.1074 + 0.2684 + 0.3020 + 0.2013)

= 0.1209

Therefore, the probability that 4 or more students score 85 percent or higher on the exam is 0.1209 or approximately 12.09 percent.

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The value of rate per toppings is, A = $ 0.50

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side. It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Given that;

The cost of 2 toppings = $ 3.99

The cost of 4 toppings = $ 4.99

Let the cost of the toppings be represented as A

Now , The equation will be;

The cost of 2 toppings = $ 3.99

So , 2A = 3.99  ..(1)

And, The cost of 4 toppings = $ 4.99

⇒ 4A = 4.99   .. (2)

Subtracting equation (1) from equation (2) , we get;

4A - 2A = 4.99 - 3.99

On simplifying the equation , we get

2A = 1.00

Divide by 2 on both sides of the equation , we get

A = $ 0.50

Therefore , The value of rate is, $0.50

Hence , The cost of one toppings = $ 0.50

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If Flyer Co. buys back 5102 shares of their $3 par value common stock for $17 per share. The amount debited to the treasury stock account to record the purchase would be $ 86,834.

To calculate the amount debited to the treasury stock account, we need to multiply the number of shares bought back by the price per share.

In this case, Flyer Co. buys back 5102 shares at $17 per share.

The amount debited to the treasury stock account is calculated as follows:

Amount = Number of shares bought back * Price per share

Amount = 5102 * $17

Amount = $86,834

Therefore, the amount debited to the treasury stock account to record the purchase would be $86,834.

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Answer:

(n + 1) (2n - 7)

Step-by-step explanation:

2n^2 - 5n - 7

AC= 2 * -7 = -14

                -7 + 2 = -5

      2n^2 - 7n      + 2n - 7

     1n(2n - 7)       1(2n - 7)

(n + 1) (2n - 7)

Answer:

-8n

Step-by-step explanation:

2n²-5n=-1n

-1n-7=-8n

Answer:

Symmetry is the property of an object to retain its shape even if it is turned or turned.

The three corporate logos are McDonald, Shell, Snapcaht

McDonald company logo is symmetrical and it is a reflective symmetry.

Shell logo is symmetrical and it is also reflective symmetry.

Snaphcat logo is symmetrical and it is also reflective symmetry.

Based on the calculations we have rejected the null hypothesis .

Given,

Standard deviation = $ 45

Random sample = 20

Now,

Part 1

Set the null hypothesis and alternative hypothesis,

\(H_{0} : u = 0\\ H_{0} : u > 606.40\)

Part 2

The value of z critical signifies 5% level of significance .

\(Z_{0.05} = 1.65\)

According to critical value if z after calculation is greater than or equal to 1.65 we reject the null hypothesis .

Part 3

The value of Z can be calculated by the formula,

Z = X - µ/σ/√n

Substitute the values ,

Z = 628.85 - 606.40/45/√20

Z = 1.93

Part 4

From the above calculation the value of Z is greater than the critical value .

Thus we reject the null hypothesis .

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Joe has $120 after all the trades, which is the entire amount.

Given that,

With $80, Joe opened a bank account. Then he took out $35, put in $115, and took out another $40.

To know how much balance left in his account after all the transactions in dollars;

Assume that,

Amount when account opened (x) = $80

Amount withdrawn (y) = $35

Amount deposited again (z) = $115

Amount withdrawn again (p) = $40

The total amount left after all the above transactions is;

A = x - y + z - p

  = 80 - 35 + 115 - 40

  = 195 - 75

A = $120

Therefore, the total amount left with Joe after all the transactions is $120.

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Answer:

y = 7x - 4

Step-by-step explanation:

To solve the equation of this line ( in point - slope form ) we would have to first identify the slope. If we are given the points ( 0, - 4 ) and ( 1, 3 ) then through the change in y / change in x, we can calculate the value of this slope. Take a look at the steps below;

\(( 0, - 4 ), ( 1, 3 )\\\\Slope = y2 - y1 / x2 - x1,\\\\Slope = - 4 - 3 / 0 - 1,\\Slope = - 7 / - 1\\Slope = 7 / 1\\\\Slope = 7\)

Now that we have the slope of this line, we have assume part of the equation of this line ( that passes through the points ( 0, - 4 ) and ( 1, 3 ) );

\(y = mx + b -\\m = slope, b = y - intercept\)

Plug in the value of slope for " m " in y = mx + b, and determine the y - intercept by plugging in x as 0 and y as - 4, given the point ( 0, - 4 );

\(- 4 = 7 * ( 0 ) + b,\\- 4 = 0 + b,\\b = - 4\)

From this information, we can say that the equation of this line is y = 7x - 4;

Solution, y = 7x - 4

Answer: its 130 degrees

Step-by-step explanation: if you reflect it over the line and translate it up a little to be on top of the other image it will be the same and have 130 degrees in the same spot

After computing a confidence interval, the user believes the results are meaningless because the width of the interval is too large, the best recommendation is c. Increase the sample size.

A confidence interval is a range of estimates for an unknown parameter in frequentist statistics. A confidence interval is calculated at a specific confidence level; the 95% confidence level is the most commonly used, but other levels, such as 90% or 99%, are also used.

Confidence intervals are used by statisticians to quantify uncertainty in a sample variable. A researcher, for example, may randomly select different samples from the same population and compute a confidence interval for each sample to determine how well it may represent the true value of the population variable. The resulting datasets are all unique, with some intervals containing the true population parameter and others not.

In this case, the sample size should be increased when the results are meaningless because the width of the interval is too large.

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Complete questions

After computing a confidence interval, the user believes the results are meaningless because the width of the interval is too large. Which one of the following is the best recommendation?

a. Increase the level of confidence for the interval

b. Decrease the sample size

c. Increase the sample size

d. Reduce the population variance

Answer: $96.25

Step-by-step explanation:

Take 89.75 divided by 100% = 0.8975

Then times 7.25% = $6.5

Total is 89.75 + 6.5 = $96.25

Step-by-step explanation:

parellogram

two opposite sides are equal

opposite angles add up to 180°

Answer

Fill the 5 gallon jug.

Pour the 5 gallon jug into the 3 gallon jug.

Empty the 3 gallon jug and pour the remaining 2 gallons in the 3 gallon jug.

Fill the 5 gallon jug and pour 1 gallon into the 3 gallon jug (remember it will only take one gallon)

Viola the remaining 5 gallon jug will have exactly 4 gallons remaining.

Answer:

use 4/5 of the 5 gallon jar or 1 and 1/3 of the 3 gallon jar

Step-by-step explanation:

Answer:

f = - \(\frac{g}{x-1}\)

Step-by-step explanation:

fx = f - g ( subtract f from both sides )

fx - f = - g ( factor out f from each term on the left side )

f(x - 1) = - g ( divide both sides by (x - 1) )

f = - \(\frac{g}{x-1}\)

Answer: y=3x+1

Step-by-step explanation:

Slope formula: m=(y2-y1)/(x2-x1)

m=(-5-(-2))/(-2-(-1))

m=(-5+2)/(-2+1)

m=(-3)/(-1)

m=3/1

m=3

y=mx+b

-2=3(-1)+b

-2=-3+b

b=1

y=3x+1

Answer:

The answer is B there's the steps ;))

There can be an infinite number of integer values of x possible.

The sum of the lengths of any two sides of a triangle must be greater than the length of the third side for it to be a valid triangle. So, for a triangle with side lengths 15, 47 and  \($\dfrac{x}{2}$\) the condition for the triangle to be valid is:

15 + 47 >\($\dfrac{x}{2}$\)

30 > \($\dfrac{x}{2}$\)

2\times30 > x

x > 60

Since xmust be an integer, the possible values of x are any integer greater than 60. Thus, there can be an infinite number of integer values of x possible.

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Answer:

here you go!!!

Step-by-step explanation:

the other answer might not fit your's

Step-by-step explanation:

so here's what I got