Halp me plass halp me

\(-7.8\left(-56\right)=436.8\)

\(-7.8\left(-1\right)=7.8\)

\(-7.8\cdot \:56=-436.8\)

\(-7.8\cdot \:5=-39\)

Evaluating the determinants of the submatrices:

det([[0, 3], [-6, 0]]) = 18

det([[5,

To find the inverse of matrix A, we need to calculate the determinant of A. If the determinant is non-zero, then A is invertible, and its inverse can be calculated using the formula:

A^(-1) = (1/det(A)) * adj(A)

Let's calculate the determinant and adjugate of matrix A:

A = [[3, 4, 3], [5, 0, 3], [10, -6, 0], [0, 0, -2/3]]

To calculate the determinant, we can use the cofactor expansion along the first row:

det(A) = 3 * (-1)^(1+1) * det([[0, 3], [-6, 0]]) - 4 * (-1)^(1+2) * det([[5, 3], [10, 0]]) + 3 * (-1)^(1+3) * det([[5, 0], [10, -6]])

Calculating the determinants of the submatrices:

det([[0, 3], [-6, 0]]) = (0 * 0) - (3 * -6) = 18

det([[5, 3], [10, 0]]) = (5 * 0) - (3 * 10) = -30

det([[5, 0], [10, -6]]) = (5 * -6) - (0 * 10) = -30

Plugging the determinants back into the formula for det(A):

det(A) = 3 * 18 - 4 * (-30) + 3 * 5 = 54 + 120 + 15 = 189

Since the determinant of A is non-zero (det(A) ≠ 0), A is invertible.

Next, let's calculate the adjugate of A. The adjugate is obtained by taking the transpose of the cofactor matrix of A. The cofactor matrix is obtained by calculating the determinant of each submatrix and multiplying it by (-1) raised to the power of the sum of the row and column indices:

Cofactor matrix C = [[(-1)^(1+1) * det([[0, 3], [-6, 0]]), (-1)^(1+2) * det([[5, 3], [10, 0]]), (-1)^(1+3) * det([[5, 0], [10, -6]])],

                   [(-1)^(2+1) * det([[4, 3], [10, 0]]), (-1)^(2+2) * det([[3, 3], [10, -6]]), (-1)^(2+3) * det([[3, 0], [10, -6]])],

                   [(-1)^(3+1) * det([[4, 3], [0, 3]]), (-1)^(3+2) * det([[3, 3], [5, 0]]), (-1)^(3+3) * det([[3, 0], [5, 0]])],

                   [(-1)^(4+1) * det([[4, 5], [0, 3]]), (-1)^(4+2) * det([[3, 5], [5, 0]]), (-1)^(4+3) * det([[3, 0], [5, -6]])]]

Evaluating the determinants of the submatrices:

det([[0, 3], [-6, 0]]) = 18

det([[5,

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The factored form of the expression is 4 x²(x + 2)(x + 4).

We are given that;

The quadratic expression = 4 x⁴+24 x³+32 x²

Now,

Factorization is the method of breaking a number into smaller numbers that multiplied together will give that original form.

To factor 4 x⁴+24 x³+32 x², we can first factor out the greatest common factor of the terms, which is 4 x²:

4 x²(x² + 6x + 8)

Then we can factor the quadratic expression inside the parentheses:

4 x²(x + 2)(x + 4)

Therefore, by factorization the answer will be 4 x²(x + 2)(x + 4).

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Answer:

lo siento, no lo sé

Estoy respondiendo por puntos

Step-by-step explanation:

lo siento por hacerte perder el tiempo

At t = 1.5 the height is 119 feet.

Distance is the measurement of an object from a specific point in the horizontal direction, and height is the measurement of an object in the vertical direction.

Without actually measuring the distances, heights, or angles, one of the principal applications of trigonometry is to determine the angles subtended by any object at a particular position, the height of the object, or both.

Given:

A window washer drops a tool from their platform 155 ft high.

and, polynomial =  -16t² + 155 tells us the height, in feet.

Now, the height after after t = 1.5 seconds.

h(t) = -16r² + 155

h(1.5) = -16t² + 155

h(1.5) = -16(1.5)² + 155

h(1.5) = -16(2.25) + 155

h(1.5) = -36 + 155

h(1.5) = 119 feet

Hence, the height is 119 feet.

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The equilibrium number of firms will be the smallest integer such that the price is 6 or higher. This occurs when n = 2. At this equilibrium, the price is P = 6, the output of each firm is y = 3/2, the industry's output is Y = 3, and the profit of each firm  = -2.

a) Supply curve of an individual firm

The price received by the individual firm will be P. Its demand curve is given by

D(p) = 20 - p.

Each firm chooses output to maximize its profit. Profit maximization occurs when the price is equal to the marginal cost. Mathematically,

P = MC(y)

4y = P

y = P/4

Thus the supply curve of the firm is y = P/4

b) The smallest price at which the product can be sold. The product can be sold at the minimum of the supply curve, which is y = 0, given P ≥ 0. Therefore the smallest price is P = 0.

c) Equilibrium price and output

Equilibrium occurs when each firm is producing at its profit-maximizing output given the output of other firms. Let the number of firms in the industry be n. The output of the industry is Y = ny. The industry supply curve is given by

S(P) = nP/4

The equilibrium price intersects the industry supply curve with the demand curve. Thus the equilibrium price satisfies

S(P) = Y

nP/4 = 20 - P

=> P = 80/(4 + n).

The equilibrium number of firms is the number that makes the industry supply curve equal to the demand curve. Thus

20 - P = nP/4

=> P = 80/(4 + n)

=> n = (80 - 20P)/P

= 20/P - 4.

Thus the equilibrium number of firms is a function of P and can range between 1 and infinity, but it must be an integer. The equilibrium output of each firm is given by

y = P/4 = 20/(4n + n²)

The equilibrium output of the industry is given by

Y = n

y = 5/P = (n² + 4n)/80.

d) Equilibrium number of firms with new demand curve D(p) = 21 - p.

The intersection of this curve with the marginal cost curve is at p = 21/5. This is greater than the minimum possible price of 0. Thus there is a positive profit to be earned in this industry, and new firms can enter the market.

e) Equilibrium price and output with new demand curve with the new demand curve D(p) = 21 - p, the industry supply curve and the equilibrium price are as given in part (d). The equilibrium output of each firm is given by y = P/4 = 21/20, and the equilibrium output of the industry is given by Y = 21/4.

f) Equilibrium number of firms, price, output, and profit with demand curve D(p) = 24 - p. This demand curve intersects the marginal cost curve at p = 6. The minimum possible price is P = 0. Thus there is a range of prices from 0 to 6 where firms can profit positively.

The equilibrium number of firms will be the smallest integer such that the price is 6 or higher. This occurs when n = 2. At this equilibrium, the price is P = 6, the output of each firm is y = 3/2, the output of the industry is Y = 3, and the profit of each firm is (6)(3/2) - (2)(2(3/2)² + 8) = -2.

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a. The price of the consol is approximately $133.33.

b. The new price of the consol would be $100. The price of the consol falls by 24.99% and the interest rate rises by 1%.

c. Your holding period return is approximately -49.99%.

a. The price of the consol can be calculated using the formula for the present value of a perpetuity:

Price = Annual Payment / Interest Rate

In this case, the annual payment is $4 and the interest rate is 3%. Substituting these values into the formula:

Price = $4 / 0.03 ≈ $133.33

Therefore, the price of the consol is approximately $133.33.

b. To calculate the new price of the consol if the interest rate rises to 4%, we use the same formula:

New Price = Annual Payment / New Interest Rate

Substituting the values, we get:

New Price = $4 / 0.04 = $100

The percentage change in the price of the consol can be calculated using the formula:

Percentage Change = (New Price - Old Price) / Old Price * 100

Substituting the values, we have:

Percentage Change in Price = ($100 - $133.33) / $133.33 * 100 ≈ -24.99%

The percentage change in the interest rate is simply the difference between the old and new interest rates:

Percentage Change in Interest Rate = (4% - 3%) = 1%

Comparing the two percentages, we can see that the price of the consol falls by approximately 24.99%, while the interest rate rises by 1%.

c. The holding period return can be calculated using the formula:

Holding Period Return = (Ending Value - Initial Value) / Initial Value * 100

The initial value is the purchase price of the consol, which is $133.33, and the ending value is the price of the consol after one year with an interest rate of 6%. Using the formula for the present value of a perpetuity, we can calculate the ending value:

Ending Value = Annual Payment / Interest Rate = $4 / 0.06 = $66.67

Substituting the values into the holding period return formula:

Holding Period Return = ($66.67 - $133.33) / $133.33 * 100 ≈ -49.99%

Therefore, the holding period return is approximately -49.99%.

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The required method typically employed is C) Experimental design.

The probability value is utilized as a measure of the merit of the parameter selection, and the parameter set with the highest likelihood is the best option given the available data.

Experimental design is typically employed when a researcher needs to estimate the likelihood of a certain outcome.

In an experimental design, the researcher manipulates one or more independent variables to determine the effect on a dependent variable, which is the outcome being studied.

The researcher can then use this information to make an estimate of the likelihood of the outcome under different conditions. This is the most commonly used method in the natural and social sciences to determine cause-and-effect relationships and make predictions about future outcomes.

Thus, Suitable option is C)Experimental design.

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Answer:

Step-by-step explanation:

"The capture-recapture of individually distinctive signature whistles has not been attempted before," says the paper's senior author Dr Tess Gridley, Co-Director of Sea Search and the Namibian Dolphin Project and a postdoctoral fellow in the Department of Botany and Zoology at SU. "The dolphins use these sounds throughout life and each has its own unique whistle. Therefore, by recording signature whistles over time and in different places we can calculate where animals are moving to and how many animals there are in a population."

Working with Dr Simon Elwen of Stellenbosch University, the Namibian Dolphin Project has been researching Namibia's resident bottlenose dolphins for the past 12 years, and built up a catalogue of more than 55 signature whistles dating back to 2009.

This particular study was led by Emma Longden, who began the project during her BSc (Hons) Marine Biology degree at the University of Plymouth. As an undergraduate, Emma completed an internship with the Namibia Dolphin Project for a month in 2016, and returned again in 2018 to complete work on the mark-recapture project.

She analysed more than 4000 hours of acoustic data from four hydrophones positioned along the coast south and north of Walvis Bay, Namibia, during the first six months of 2016.

All in all, they identified 204 acoustic encounters, 50 of which contained signature whistle types. From these encounters, 53 signature whistle types were identified; 40 were in an existing catalogue developed in 2014 for the Walvis Bay bottlenose dolphin population, and 13 were newly identified. Of the 53 signature whistle types identified, 43% were captured only once, whereas the majority (57%) were recaptured twice or more.

"One of the great things about bioacoustics is that you can leave a hydrophone in the water for weeks at a time and collect so much data without interfering with the lives of the animals you are studying," says Emma, whose work on the project was also supervised by Dr Clare Embling, Associate Professor of Marine Ecology at the University of Plymouth.

Dr Embling added: "This work is incredibly important as it allows us to track and count the number of dolphins in small vulnerable populations. It builds on our previous research looking at the impacts of noise on marine organisms and monitoring vulnerable marine mammal populations. It also showcases the fantastic level of research that our marine biology students are able to achieve, and the opportunities available to them through our partnerships with conservation organisations such as the Namibia Dolphin Project and the Ocean Giants Trust."

Future research includes the work undertaken by PhD student Sasha Dines from Stellenbosch University to further refine the technique to better understand the population of endangered humpback dolphins in South Africa. Another PhD student, Jack Fearey from the University of Cape Town, is continuing to conduct research along the Namibian Coast.

Answer:

I hope you have a great day and also to whoever sees this.

Others pls don't get mad that you didn't get to answer

Step-by-step explanation:

Answer:

y = 55x + 15

Step-by-step explanation:

i think this is it, but it might not be right

Answer:

no solution

Step-by-step explanation:

-5(-3x-2)-(x-3)=-4(4x+5)+13

-15x-10-x+5=-16x-20+13

-16x-5=-16x-7

-5=-7

The effective interest rate of the loan would be

In this case, we are given 4 options:

The formula of compounded interest rate is:

\(A = P (1+\frac{r}{n})^{nt}\)

Where:

A = amount, P = principal amount, r = interest rate, n = number of times interest rate compounded, t = time

Let’s assume the principal amount is $100 for 1 year

Loan L =

\(A = 100 (1+\frac{0.08254}{356})^{356x1}\)

A = $108.603

Loan M =

\(A = 100 (1+\frac{0.08474}{52})^{52x1}\)

A = $108.834

Loan N =

\(A = 100 (1+\frac{0.08533}{12})^{12x1}\)

A = $108.875

Loan O =

\(A = 100 (1+\frac{0.08604}{1})^{1x1}\)

A = $108.604

Therefore, the best effective interest rate for Craig is Loan L with nominal rate of 8.254% compounded daily.

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According to algebra, the square binomial (6 · x + 5 · y)² has the following equivalent expression: 36 · x² + 60 · x · y + 25 · y².

According to algebra, we find the case a square binomial, whose equivalent form is shown below by following rule:

(a + b)² = a² + 2 · a · b + b²

Where a, b are real coefficients.

If we know that a = 6 · x and b = 5 · y, then the equivalent form of the square binomial is:

First, write the entire expression:

(6 · x + 5 · y)²

Second, use power properties:

(6 · x)² + 2 · (6 · x) · (5 · y) + (5 · y)²

Third, perform associative and commutative properties:

6² · x² + (2 · 6 · 5) · (x · y) + 5² · y²

Fourth, multiply similar terms:

36 · x² + 60 · x · y + 25 · y²

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Answer: 32

Step-by-step explanation:

AD makes up a leg of triangle ABD, and since we know AB and BD, we can use pythagorean theorem to calculate AD.

\(a^{2} +b^{2} =c^{2}\), where AD is a, BD is b, and AB is c.

Rearranged and solved for a, we get AD = 32.

Let B be a nonstandard basis for a vector space V over a field F. If u = (u1, ..., un) is a vector in V with respect to the standard basis,

Then the vector x = (x1, ..., xn) in V with respect to the basis B can be found by solving the system of equations \(Bx = u\).Then the change of coordinates matrix from B to the standard basis is obtained by stacking the coordinate vectors for the basis B into a matrix,

i.e.\(, B = [b1 | b2 | ... | bn],\)

where bj is the jth basis vector in B. The inverse of B is then used to go from the B-coordinates of a vector to the standard coordinates of the same vector, i.e.,

\(u = Bx\)

implies that

\(x = B−1u.\)

Therefore, the change-of-coordinates matrix from B to the standard basis is B−1.Hence, the main answer to the given question can be found by simply finding the inverse of the matrix B, which will give us the change-of-coordinates matrix from B to the standard basis.

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Carla's behavior of putting in extra practices to become faster can be seen as an example of (Option A.) compensation. This is because she is trying to make up for her perceived lack of speed by working harder to become as fast as her teammates.

Carla's behavior of putting in extra practices to become faster can be seen as an example of compensation. This is because she is trying to make up for her perceived lack of speed by working harder to become as fast as her teammates.

By engaging in extra practices, Carla is attempting to compensate for her lack of speed and improve her performance. This is different from rationalization, which is the act of making excuses for one's behavior, or from regression, which is the act of reverting to a younger age in response to a stressful situation.

Finally, displacement is the act of redirecting one's emotions or anger onto another person or object.

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Answer:

C Subtraction property of equality

Step-by-step explanation:

You are subtracting 21 from both sides in step 3

Answer:

I would guess C

Step-by-step explanation:

I hope I'm correct, good luck.

There are 6 repeats in the product

So, according to question the repeats in the product can be find as:-

Primer amplified base pairs=130

These 130 base pairs are adjacent to 14 base pair repeats.

Let x, be the repeats in the product,

So, we will simply multiply 14 and x to get; 14*x=14x

Now this number will be added to our primer amplified base pair which is 130

The size of final product now is 14x+130=214

14x+130=214

14x=214-130

14x=84

x=6

So, the repeats in the product is 6

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Answer:

undefined

Step-by-step explanation:

the line has always the same x, so it is a vertical line

A vertical line has an undefined slope

Answer:

Skew (option d).

Step-by-step explanation:

Skew lines are the lines that do not intersect with each other. These lines exist in different planes and hence do not intersect each other and they are also not parallel. For skew lines to exist,  3 -d planes are required.

Here, the lines e and c are skew lines because they do not intersect each other and are lying on different panes. They are also skew line because the planes are co-planer,

Hence, the lines e and c are skew lines.

When lines are not parallel, and they do not intersect, such lines are said to be skewed.

Line AC and RS are skew.

From the diagram, we have two planes.

Line AC is on plane x, while line RS is on plane y

Plane x and plane y are not parallel;

So lines AC and RS are not parallel.

Also, both lines are not parallel.

Using the condition of skewness stated above, we can conclude that line AC and RS are skew.

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Al-Khwarizmi made significant contributions to the world of mathematics, particularly in the field of algebra. His major accomplishment was the development of algebra as an independent mathematical discipline.

Al-Khwarizmi, a Persian mathematician and scholar, wrote the book titled "Kitab al-Jabr wal-Muqabala," which laid the foundation for modern algebra. In this influential work, he introduced systematic methods for solving linear and quadratic equations. Al-Khwarizmi's algebraic techniques, including the use of variables and equations, greatly advanced mathematical understanding and problem-solving. His work also contributed to the development of algorithms and mathematical notation, such as the concept of the "zero" and the decimal system. Overall, al-Khwarizmi's contributions revolutionized mathematics and had a profound impact on subsequent generations of mathematicians and scientists.

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In determining a mean, the 90% C.I. is more accurate than the 95% C.I.

A confidence interval is the mean of your estimate plus or minus the range of that estimate's variability.

You can reasonably anticipate that if you repeat the test, your estimate will fall within these values.  In statistics , confidence is another name for probability

A statistician who declares that they have a 95% confidence level has basically seen one possible interval out of many possible ones, and 19 out of 20 of those intervals include the correct value of the parameter.

In determining a mean, the 90% C.I. is more accurate than the 95% C.I.

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The equation 6x + 7 = 2(3x + 5) + 9 has no solution.

Equations are mathematical statements containing two algebraic expressions on both sides of an 'equal to (=)' sign.

Let's solve the equation for variable x.

A variable is a number represented with letter in an equation. Therefore,

6x + 7 = 2(3x + 5) + 9

6x + 7  = 6x + 10 + 9

6x + 7 = 6x + 19

6x - 6x = 19 - 7

0x = 12

Therefore, the equation cannot be solved.

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Answer:

1/8

Step-by-step explanation:

Llyod used 1/4 chocolates to make 2/3 gallons of chocolate pudding

= 1/4 ÷ 2/3

= 1/4 × 3/2

= 3/8

Therefore the number of pounds needed to make 1/3 of the recipe can be calculated as follows.

= 3/8 × 1/3

= 3/24

= 1/8

Answer:

B) x=2

Step-by-step explanation:

6x+3=3(7-x)

6x+3=21-3x

9x+3=21

9x=18

x=2