Hasan buys two kinds of cloth materials for school uniforms, shirt material that costs him ₹ 50 per metre and trousers material that costs him ₹ 90 per metre. For every 3 metres of the shirt material, he buys 2 metres of the trouser material. He sells the materials at 12% and 10% profit respectively. His total sale is ₹ 36,600. How much trouser material did he buy?

PLease i want it with step by step explanation

Hey there!

The answer to your question is the third option; \(5x-6\)

First, we'll start by simplifying your expression. Given:

\(3(x - 2)+2x\)

Distribute the \(3\):

\(3x-6+2x\)

Add \(3x\) and \(2x\):

\(5x-6\)

Therefore, the third option is correct.

Have a terrificly amazing day! :)

Answer:100

Step-by-step explanation:

Answer:

end

Step-by-step explanation:

Using for loop we can get the syntax in order to calculate this arithmetic series n is A = 0.9999.

An arithmetic collection is the sum of the phrases in an mathematics collection with a specific range of phrases. Following is a easy system for locating the sum: Formula 1: If S n represents the sum of an mathematics collection with phrases.

This system calls for the values of the primary and ultimate phrases and the range of phrases. Finite Sequence- Finite sequences have countable phrases and do now no longer cross as much as infinity. An instance of a finite mathematics collection is 2, 4, 6, 8. Infinite Sequence- Infinite arithmetic collection is the collection wherein phrases cross as much as infinity.

using while

A=0; n=1; while n<=10000     A=A+(1/(n*(n+1)));     n=n+1; end A

output

A =      0.9999

using  for loop

A=0; for n=1:10000     A=A+(1/(n*(n+1))); end A

output

A = 0.9999.

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Correct Question:

The following series can be written with a shorthand form of sigma notation (A). Use while syntax to calculate this arithmetic series:

1/(1x2) + 1/(2x3) + 1/(3x4) + ... + 1/(n x (n+1)) ......1

A = ∈ 1/(n x (n+1)); n=[1:10000]

Answer: The solution of x is 2.5

Step-by-step explanation: hope it helps:)

Answer: \(x=\frac{5}{2}\)  

Step-by-step explanation:

Simplify the expression:

\(-2x+14+10x=34\)

\(\left(-2x+10x\right)+14=34\)

\(8x+14=34\)

Group all constants on the right side of the equation:

\(8x+14-14=34-14\)

\(8x=34-14\)

\(8x=20\)

Isolate the x:

\(\frac{8x}{8}=\frac{20}{8}\)

\(x=\frac{20}{8}\)

\(x=\frac{5\cdot 4}{2\cdot 4}\)

\(x=\frac{5}{2}\)

The \(CORRECT\)answer to this solution is: \(x=\frac{5}{2}\)

\(calderonj4588~:)\)

Answer: D

Step-by-step explanation:

Zach won because 3 16/24 is less than 3 15/24. Then, 3.666666 is less than 3.625

Answer:

x is less than 46

x<46°

Step-by-step explanation:

............

Answer:

x² + 4xy + 4y²

Step-by-step explanation:

(x + 2y)² = (x + 2y)(x + 2y)

x(x + 2y) + 2y(x + 2y) ← distribute both parenthesis

= x² + 2xy + 2xy + 4y² ← collect like terms

= x² + 4xy + 4y²

Answer:

4x² - 2x + 1/4

Step-by-step explanation:

The perfect square trinomial formula states "the product is the first term squared plus twice the first term times the second term plus the second term squared" So applying this to the equation (2x - 1/2)² we have

(2x)² - 2(2x)(-1/2) + (1/2)². Then I simplified it which gives the final equation 4x² - 2x + 1/4.

Answer:

xz=255

Step-by-step explanation:

17 is prime so yz has to be 1*17

if that's the case xy=15*1

so 15*17=255

The appropriate p-value for the given test statistic and hypotheses is approximately 0.0253.

Tο determine the apprοpriate p-value fοr the given hypοthesis test, we need tο use the t-distributiοn and the t-statistic value οbtained.

Given:

Null hypοthesis (H0): μ = 130 (pοpulatiοn mean)

Alternative hypοthesis (HA): μ > 130 (pοpulatiοn mean)

T-statistic: t = 2.73

Degrees οf freedοm: df = 5

Tο calculate the p-value, we cοmpare the t-statistic tο the t-distributiοn.

Since the alternative hypοthesis is μ > 130, it is a οne-tailed test, and we are interested in the right tail οf the t-distributiοn.

Using a t-table οr a statistical sοftware, we can determine the p-value assοciated with the t-statistic and the degrees οf freedοm.

Fοr a t-statistic οf 2.73 with 5 degrees οf freedοm, the p-value is apprοximately 0.0257 (assuming a twο-tailed test).

Since we have a οne-tailed test, the apprοpriate p-value is half οf the twο-tailed p-value:

p-value = 0.0257 / 2 = 0.01285

Therefοre, the apprοpriate p-value fοr the given hypοthesis test is apprοximately 0.01285.

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The probability that the answerof the 1st question is correct is 1/15.

So, the probability of the correct answer:

Probability formula: P = Favourable events/Total events

Where total events are 15 and favorable event is 1.

Now calculate as follows:

Therefore, the probability that the answerof the 1st question is correct is 1/15.

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Answer:

AC line = DB line

Step-by-step explanation:

ac line is always larger that db line

Answer:

8

Step-by-step explanation:

Answer:

Ok to make this easier for us we should switch these equations into y=mx+b so that it's easier for us to identify the slope and y-intercept:

to switch into y=mx+b form do this:

3x-y=5

-y=5-3x

y=-5+3x

y=3x+(-5)

2y-15x=8

2y=8+15x

y=4+7 1/2x

y=7 1/2x+4

THe slope of any line in y=mx+b form is m. Therefore in this equation:

y=3x+(-5)     3 is the slope

The y intercept of any line is the +b:

y=7 1/2x+4 -therefore 4 in this equation is our y intercept.

Now we can construct our equation in y=mx+b then into standard form (Ax+By=C)

since 3 is our slope and 4 is our y intercept the equatuon is :

y=3x+4

NOw all we need to do is move this into standard form:

y=3x+4

-3x+y=4

-3x+y=4 is your final answer

-hope this helped

Step-by-step explanation:

Answer: \(\dfrac{1}{10}\)

Step-by-step explanation:

Given: In basket, we have

4 black socks, 7 pink socks, and 10 white socks.

Total socks = 4+7+10 = 21

Probability that first sock is pink = \(\dfrac{\text{Number of pinks socks}}{\text{Total}}=\dfrac{7}{21}=\dfrac13\)

Now basket has 6 pink socks left and total socks left= 20

Probability that second sock is pink =\(\dfrac{6}{20}=\dfrac{3}{10}\)

The probability that Allison will select 2 pink socks = \(\dfrac13\times\dfrac{3}{10}=\dfrac{1}{10}\)

Hence, the probability that Allison will select 2 pink socks = \(\dfrac{1}{10}\)

Answer: 0.03

Step-by-step explanation:

Answer:

0.03

Step-by-step explanation:

\(\frac{25}{10}\)×\(\frac{12}{1000}\)=

\(\frac{300}{10000}\)=0.03

Answer:

904.32 cubic units

Step-by-step explanation:

36x3.14x8=V

The graphs cross at x=-1 and x=1. Those are the solutions to to the equation

We know that, If two functions are equal then there solution is the intersection point of the curves.

When we determine the graph the intersection points are (0,2) and (1,1.25).

The values of x of the intersection points are the solutions of the system

Using a graphing tool, there are two intersection points and therefore the solutions are x = -1 and x [ 1.

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Answer:   y intercept = 4

The y intercept always occurs when x = 0. This is the location where the graph crosses the y axis. From the list of points, we see that (0,4) is the location of the y intercept. We can say the y intercept is 4.

To derive the least-squares fit for the model y = a1x + a2x^2 with a zero intercept, we need to minimize the sum of squared residuals. Let's denote the observed data points as (xi, yi) for i = 1 to n.

The objective is to find the values of a1 and a2 that minimize the following sum of squared residuals:

SSR = ∑(yi - (a1xi + a2xi^2))^2

To find the minimum, we differentiate SSR with respect to a1 and a2 separately and set the derivatives equal to zero.

Partial derivative with respect to a1:

∂SSR/∂a1 = -2∑(yi - (a1xi + a2xi^2))*xi = 0

Partial derivative with respect to a2:

∂SSR/∂a2 = -2∑(yi - (a1xi + a2xi^2))*xi^2 = 0

Expanding the above equations:

∑(yixi) - a1∑(xi^2) - a2∑(xi^3) = 0 ------ (1)

∑(yixi^2) - a1∑(xi^3) - a2∑(xi^4) = 0 ------ (2)

Now, let's solve these equations to find the values of a1 and a2.

From equation (1):

a1∑(xi^2) + a2∑(xi^3) = ∑(yi*xi) ------ (3)

From equation (2):

a1∑(xi^3) + a2∑(xi^4) = ∑(yi*xi^2) ------ (4)

We can express equations (3) and (4) in matrix form as:

| ∑(xi^2) ∑(xi^3) | | a1 | = | ∑(yixi) |

| ∑(xi^3) ∑(xi^4) | | a2 | = | ∑(yixi^2) |

Solving this system of linear equations will give us the values of a1 and a2.

Once a1 and a2 are determined, we have the least-squares fit of the model y = a1x + a2x^2 with a zero intercept.

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We have to put the triangular side as the base.

So, the height of the tent is signified by the red line, h.

Shown below:

The volume of the triangular prism is area of triangle x height

Let's find the area of the triangle, A_T:

The height is 10.

The volume is 280.

Substituting into the formula, let's sovle for "h". Shown below:

Answer:

a=π9² is the formula with the radius plugged in

radius is half

Answer:

243in^2

Step-by-step explanation:

18/2=9

3 x 9 x 9=243

Answer: Cost to distributer $3.38

Cost to retailer $4.73

Step-by-step explanation: First find 35 percent of $2.50

2.50 x 0.35 = 0.875 this is 35% of 2.50

Then add this amount to 2.50

2.50 + 0.875 = 3.375 or $3.38

Then to find the cost to the retailer repeat this process with 40%

3.38 x 0.40 = 1.352

1.352 + 3.38. = 4.732 or $4.73

In conclusion, the average rates of change for the given functions are:
1. 8
2. -32
3. 2
4. -12
5. 1
6. 12
7. -2
8. Calculation depends on the exact value of e.

To find the average rate of change for each function, we will use the formula: (f(x2) - f(x1)) / (x2 - x1).
1. For f(x) = x^2 + 2x between x = 0 and x = 6:
  - Plug in x = 6: f(6) = 6^2 + 2(6) = 36 + 12 = 48
  - Plug in x = 0: f(0) = 0^2 + 2(0) = 0
  - Average rate of change = (48 - 0) / (6 - 0) = 48 / 6 = 8
2. For f(x) = -4x^2 - 6 between x = 1 and x = 7:
  - Plug in x = 7: f(7) = -4(7)^2 - 6 = -196 - 6 = -202
  - Plug in x = 1: f(1) = -4(1)^2 - 6 = -4 - 6 = -10
  - Average rate of change = (-202 - (-10)) / (7 - 1) = -192 / 6 = -32
3. For f(x) = 2x^3 - 4x^2 + 6 between x = -1 and x = 2:
  - Plug in x = 2: f(2) = 2(2)^3 - 4(2)^2 + 6 = 16 - 16 + 6 = 6
  - Plug in x = -1: f(-1) = 2(-1)^3 - 4(-1)^2 + 6 = -2 - 4 + 6 = 0
  - Average rate of change = (6 - 0) / (2 - (-1)) = 6 / 3 = 2
4. For f(x) = -3x^3 + 2x^2 - 4x + 2 between x = 0 and x = 2:
  - Plug in x = 2: f(2) = -3(2)^3 + 2(2)^2 - 4(2) + 2 = -24 + 8 - 8 + 2 = -22
  - Plug in x = 0: f(0) = -3(0)^3 + 2(0)^2 - 4(0) + 2 = 2
  - Average rate of change = (-22 - 2) / (2 - 0) = -24 / 2 = -12
5. For f(x) = x between x = 1 and x = 9:
  - Average rate of change = (9 - 1) / (9 - 1) = 8 / 8 = 1
6. For f(x) = 3x - 2 between x = 2 and x = 6:
  - Average rate of change = (3(6) - 2) - (3(2) - 2) = 16 - 4 = 12
7. For f(x) = x - 1 between x = -2 and x = 0:
  - Average rate of change = ((-2) - 1) - (0 - 1) = -3 + 1 = -2
8. For f(x) = 0.4525e^(1.556x) between x = 4 and x = 4.5:
  - Average rate of change = (0.4525e^(1.556(4.5))) - (0.4525e^(1.556(4))) = 0.4525e^(7.002) - 0.4525e^(6.224) [calculations depend on the exact value of e]
In conclusion, the average rates of change for the given functions are:
1. 8
2. -32
3. 2
4. -12
5. 1
6. 12
7. -2
8. Calculation depends on the exact value of e.

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We can construct an interpolating polynomial for the given data points. By rewriting this polynomial equation as another equation that equals zero when Y is 2, we use root-finding methods to find X values.

To begin, we construct the interpolating polynomial using the given data points. The interpolated points for which Y = 2 are then plotted as black Xs, along with the original data points and the interpolating polynomial.The MATLAB code for constructing the polynomial and finding the X values for which Y = 2 is as follows:

```matlab

% Given data points

X = [0 1 -2 2 -1];

Y = [4 4 -6 1 0];

% Constructing the interpolating polynomial

poly = polyfit(X, Y, length(X)-1);

% Rewriting the polynomial equation as f(X) - 2 = 0

poly2 = poly - [2 zeros(1, length(X)-1)];

% Finding the roots of the equation f(X) - 2 = 0

X_roots = roots(poly2);

% Filter the X values within the range [-2, 2]

valid_X = X_roots(X_roots >= -2 & X_roots <= 2);

% Plotting the interpolating polynomial, data points, and reverse interpolated points

x_range = -2.2:0.2:2.2;

y_interpolated = polyval(poly, x_range);

plot(x_range, y_interpolated, 'r-', X, Y, 'bo', valid_X, 2*ones(size(valid_X)), 'kx');

```

The code first constructs the interpolating polynomial using `polyfit`, which fits a polynomial of degree `length(X)-1` to the data points. Then, we subtract 2 from the polynomial coefficients to rewrite the equation as `f(X) - 2 = 0`. The roots of this equation are obtained using `roots`, and we filter out the X values that fall within the range of [-2, 2]. Finally, we plot the interpolating polynomial as a smooth red line, the original data points as blue dots, and the reverse interpolated points for which Y = 2 as black Xs.

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Answer:

axis x=4 & vertex (4,1)

The number of surveyed nurses that were health club members or were smokers is 227.

Let the total number of nurses be 800 nurses

n(U) = 800

Let H be health club members, n(H) = 564

Let S be smokers, n(S) = 430

If 325 of the health club members were smokers, then n(HnS) = 325 members.

The number of surveyed nurses that were health club members or were smokers = 800 - [( 564 - 430) + (564-325)].

The number of surveyed nurses that were health club members or were smokers = 600 - (134+239) = 600 - 373 = 227

The number of surveyed nurses that were health club members or were smokers is 227.

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Using the empirical rule, we can estimate that approximately 97.5% of the students have GPAs that are greater than 1.66 at this university.

The empirical rule, also known as the 68-95-99.7 rule, states that for a normal distribution, approximately 68% of the data falls within one standard deviation of the mean, 95% falls within two standard deviations, and 99.7% falls within three standard deviations.

To apply this rule to the given scenario, we first need to calculate how many standard deviations away from the mean a GPA of 1.66 is.

Z = (X - μ) / σ

Where X is the GPA in question, μ is the mean (2.56), and σ is the standard deviation (0.45).

Z = (1.66 - 2.56) / 0.45 = -2

This tells us that a GPA of 1.66 is 2 standard deviations below the mean.

Now, using the empirical rule, we know that approximately 95% of the data falls within two standard deviations of the mean. Since a GPA of 1.66 is 2 standard deviations below the mean, we can conclude that only about 2.5% (half of the remaining 5%) of the students have a GPA lower than 1.66.

Therefore, the percentage of students who have GPAs that are greater than 1.66 would be approximately 97.5%.

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The equation for the velocity of the object if v =dy/dt is :

y = dy/dt = 2e-t( - sin3t + 3 cos3t)

Given data :

y = 2e^-t sin3t your mean is y = 2e-t * sin3t

If yes, you know the product rule is (u.v)' = u' v + uv'

in this case u = 2e-t and   v= sin3t

now u' = -2 e-t  and v' = 3 cos3t

y = dy/dt = -2 e-t * sin3t + 2e-t *3 cos3t

It is better you simplify! by factoring of 2e-t

y = dy/dt = 2e-t( - sin3t + 3 cos3t)

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