Haseena bought 1 pencil box, 4 pencils and 4 notebooks from a store. She paid Rs. 95 in all. Some ink fell on the bill that she got from the store. So the price of 1 notebook cannot be seen from the bill.What is the price of the one notebook?

Renee can play 11 different games.

The most fundamental operations in arithmetic are addition, subtraction, multiplication, and division. However, arithmetic also includes more complex operations like manipulating percentages, square roots, exponentiation, logarithmic functions, and even trigonometric functions, which are analogous to logarithms. Other examples of more complex operations include exponentiation. Arithmetic expressions must be evaluated in accordance with the intended order of operations.

Given total amount Renee have = $60

Cost for entry in park = $25

The amount left with Renee = 60 - 25

The amount left with Renee =  $35

now cost for each game is $3

total no. of games can be played in $35 = \(\frac{ The amount left with Renee}{ cost for each game}\)

 35/3  = 11.667

Hence we only count integer digits which is 11; so  Renee can play 11 different games.

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Answer: 312=(2)(2)(2)(3)(13)

Step-by-step explanation:

312  |  2

156  |  2

78   |  2

39   |  3

13    | 13

Hence, 312=(2)(2)(2)(3)(13)

Considering the function f(x) = x(x-4), if the point (2+c, y) is on the graph of f(x), then the following point will also be on the graph of f(x): (2-c, y). Explanation: Since f(x) is symmetric with respect to the vertical line x = 2 (due to the fact that f(x) = x(x-4) = (x-2+2)(x-2) = (x-2)^2 - 2^2), if the point (2+c, y) is on the graph, then its symmetric counterpart, (2-c, y), will also be on the graph.

The definition of a function in mathematics can also be interpreted as a relation that connects each member of x in a set called the domain with a single value f(x) from a second set called the codomain.

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Answer:

Answer below!

Step-by-step explanation:

since y = -3x + 1, you can just plug those numbers in on the first equation.

6x + 2(-3x+1) = 2 (see how I replaced y into -3x + 1)

then distribute 2.

6x - 6x + 2 = 2, subtract 2 to both sides

6x - 6x = 0, combine x

0 = 0 (this means it has an infinite amount of solutions)

Answer: x-intercept is -1      y-intercept is 2

Step-by-step explanation: look for the intersection

To find a model for the revenue of Under Armour, we need to integrate the given rate of change equation with respect to time (t).

The given rate of change equation is:

\(\(\frac{dR}{dt} = 13.897t + 284.653\)\)

Integrating both sides of the equation with respect to t, we get:

\(\(\int dR = \int (13.897t + 284.653) dt\)\)

Integrating the right side of the equation, we have:

\(\(R = 6.9485t^2 + 284.653t + C\)\)

Here, C is the constant of integration.

To determine the constant of integration, we will use the given information that in 2008, the revenue for Under Armour was $725.2 million, which corresponds to \(\(t = 4\).\)

Substituting \(\(t = 4\)\) and \(\(R = 725.2\)\) into the revenue equation, we can solve for C:

\(\(725.2 = 6.9485(4^2) + 284.653(4) + C\)\)

Simplifying the equation:

\(\(725.2 = 111.176 + 1138.612 + C\)\)

\(\(725.2 = 1249.788 + C\)\)

Subtracting 1249.788 from both sides:

\(\(C = 725.2 - 1249.788\)\)

\(\(C = -524.588\)\)

Therefore, the model for the revenue of Under Armour is:

\(\(R = 6.9485t^2 + 284.653t - 524.588\)\)

This equation represents the revenue (in millions of dollars) of Under Armour as a function of time (in years), with \(\(t = 4\)\) corresponding to the year 2004.

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The answer is B) 3.250. It is important to note that the critical value depends on the level of significance (c) and the degrees of freedom (n-1).

To find the critical value, tc, for c = 0.99 and n = 10, we need to use the t-distribution table. Since we are dealing with a two-tailed test, we need to find the value that splits the distribution into two parts, each with an area of 0.005 (0.99/2 = 0.495, and 1 - 0.495 = 0.005). Looking at the table, we can see that for 9 degrees of freedom (n-1) and a probability of 0.005, the critical value is 3.250. Therefore, the answer is B) 3.250. It is important to note that the critical value depends on the level of significance (c) and the degrees of freedom (n-1). As the level of significance increases, the critical value increases as well. Similarly, as the degrees of freedom increase, the critical value decreases.

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Step-by-step explanation:

Simply graph the two equations....the intersection of the two graphs is the solution

Answer:

see below

Step-by-step explanation:

6 inches tall so h=6

base radius of 9 inches so base area = π r² =81π,

top & bottom together is 162π =508.7

lateral area = h* the circumference of the base = 2π*r*h =2π*9*6=108π =339.1

so lateral area is 54π= 169.6 smaller than top & bottom bases.

The value of the third expression \(\rm \dfrac{45}{n} + 7\) for n = 5 is 16 which is equivalent to 16.

The equivalent is the functions that are in different forms but are equal to the same value.

Given

The expressions are shown below.

\(\rm 1. \ \dfrac{25}{n} + 7\\\\2. \ 30 -3n\\\\3. \ 7+ \dfrac{45}{n}\\\\4. \ n^3 - 114\)

The expression is equivalent to 16 for n = 5.

1. For n = 5, the expression will be

\(\rm \dfrac{25}{n} + 7\\\\ \dfrac{25}{5} + 7\\\\5 + 7 \\12\)

The expression is not equivalent to 16.

2. For n = 5, the expression will be

\(\rm 30 - 3n\\30 - 3 * 5 \\30 - 15\\15\)

The expression is not equivalent to 16.

3. For n = 5, the expression will be

\(\rm \dfrac{45}{n} + 7\\\\ \dfrac{45}{5} + 7\\\\9 + 7 \\16\)

The expression is equivalent to 16.

4. For n = 5, the expression will be

\(\rm n^3 - 114 \\\\5^3 - 114 \\\\125 -114\\\\11\)

The expression is not equivalent to 16.

Thus, the third expression is equivalent to the 16.

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Answer:

The answer is C, \(7+\frac{45}{n}\)

Step-by-step explanation:

1. if n=5 then the expression would be rewritten as  \(7 + \frac{45}{5}\)

2. 45 divide 5 is 9.

Answer:

5.0

Step-by-step explanation:

Answer:it’s 0

Step-by-step explanation:

Answer:

C = 2πr, where C is the circumference, π is the mathematical constant pi (approx. 3.14), and r is the radius (9 inches). Therefore, the circumference of the basketball hoop is 2π(9) = 18π inches.

Step-by-step explanation:

In other words use C=2*pi*radius to find the circumference, here you are given the radius is 9 so when you plug that in it gives you a circumfrence of 18pi inches. Hope this helps!

The slope intercept form of a line which passes through the points (-2, 5) and (6, -4)  is  y = (-9/8)x + 11/4.

According to the question.

A line passes through the two points (-2, 5) and (6, -4).

As we know that, the slope intercept formula y = mx + b is used when you know the slope of the line to be examined and the point given is also the y intercept (0, b). In the formula, b represents the y value of the y intercept point.

So, the slope of the line = -4 -5/(6 + 2) = -9/8

And, the slope intercept form of a line which passes through the points (-2, 5) and (6, -4) is given by

y = (-9/8)x + b

Since, the line passes through (-2, 5) and (6, -4). So, both the points must statisfy the above equation.

⇒ 5 = (-9/8)(-2) + b

⇒ 5 = 9/4 + b

⇒ b = 5 - 9/4

⇒ b = (20 - 9)/4

⇒ b = 11/4

Therefore, the slope intercept form of a line which passes through the points (-2, 5) and (6, -4)  is  y = (-9/8)x + 11/4.

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Increasing the smoothing factor in Exponential Moving Average gives more weight to recent price values and makes the forecast more responsive to short-term movements.

When using Exponential Moving Average (EMA) as a forecasting method for stock price movements, the smoothing factor determines the weight assigned to past actual price values.

Increasing the value of the smoothing factor reduces the weight given to older price values and increases the weight given to more recent price values.

The formula for calculating EMA is as follows:

EMA(t) = \(\alpha \times Price(t) + (1 - \alpha ) \times EMA(t-1)\)

Here, α represents the smoothing factor, and Price(t) is the actual price at time t. The smoothing factor determines how quickly the weight of past prices decays as new prices are incorporated into the EMA calculation.

By increasing the value of the smoothing factor, the influence of older price values diminishes more rapidly. This means that the EMA will react more quickly to recent price movements, leading to a higher sensitivity to short-term changes. The EMA will closely track the recent price trends, making it more responsive to current market conditions.

However, it's important to note that increasing the smoothing factor excessively can also make the EMA more volatile and prone to noise, as it will react too quickly to short-term fluctuations and might overemphasize recent data at the expense of long-term trends.

In conclusion, increasing the smoothing factor in Exponential Moving Average gives more weight to recent price values and makes the forecast more responsive to short-term movements.

It can be beneficial when there is a need to capture and react quickly to the latest market trends. However, it should be used cautiously, as excessively high values may introduce more volatility and noise into the forecast.

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Answer: the three given points are the vertices of a triangle. solve the triangle, rounding lengths tot he nearest tenth and angle measures to the nearest degree A(0,0) B(-3,5) C(3,-2)

***

Plot given points to form a triangle with angle A at (0,0), B at (-3,5) and C at (3,-2).

Using distance formula:

AB=√(0+3)^2+(0-5)^2)=√(9+25)=√34

AC=√(0-3)^2+(0+2)^2)=√(9+4)=√13

BC=√(-3-3)^2+(5+2)^2)=√(36+49)=√85

..

Law of cosine: c^2=a^2+b^2-2abcosA

(BC)^2=(AB)^2+(AC)^2-2*AB*ACcosA

√85^2=34+13-2*√34*√13cosA

85=47-2√442cosA

38=-42cosA

cosx=-38/42

A=154.8˚

..

using law of sin:

BC/sin(154.8˚)=AC/sinB

sinB=AC*sin(154.8˚)/BC=0.1665

B=9.6˚

..

BC/sin(154.8˚)=AB/sinC

sinC=AB*sin(154.8˚)/BC=0.2693

C=15.6˚

Step-by-step explanation:

Answer:

11.1 times

Step-by-step explanation:

Answer:

11 times

Step-by-step explanation:

10, 20, 30, 40, 50, 60, 70, 80, 90, 100, 110

Answer: b

Step-by-step explanation: death normally last 9 min and birth 9 sec

The conditions for a function ( p: E \rightarrow \mathbb{R} ) to define a norm in the vector space ( E ) are as follows:

(i) Non-negativity: ( \forall x \in E, ) ( p(x) \geq 0 ). The norm of any vector is a non-negative value or zero.

(ii) Positive definiteness: ( p(x) = 0 ) if and only if ( x = 0 ). The only vector with a norm equal to zero is the zero vector.

(iii) Homogeneity: For any scalar ( \lambda ) and vector ( x ), ( p(\lambda x) = |\lambda| \cdot p(x) ). Scaling a vector multiplies its norm by the absolute value of the scalar.

(iv) Triangle inequality: ( \forall x, y \in E, ) ( p(x + y) \leq p(x) + p(y) ). The norm of the sum of two vectors is less than or equal to the sum of their individual norms.

These conditions define a norm in the vector space ( E ) over the field ( \mathbb{R} ) (or ( \mathbb{C} )).

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Note: The height of the room must be 3 m instead of 3 cm because 3 cm is too small and it cannot be the height of a room.

Given:

Perimeter of the floor of a room = 18 metre

Height of the room = 3 metre

To find:

The area of 4 walls of the room.

Solution:

We know that, the area of 4 walls of the room is the curved surface area of the cuboid room.

The curved surface area of the cuboid is

\(C.S.A.=2h(l+b)\)

Where, h is height, l is length and b is breadth.

Perimeter of the rectangular base is 2(l+b). So,

\(C.S.A.=\text{Perimeter of the base} \times h\)

Putting the given values, we get

\(C.S.A.=18\times 3\)

\(C.S.A.=54\)

Therefore, the area of 4 walls of the room is 54 sq. metres.

The probability that the sample average amount of time taken to fill out the form on each day is at most 11 minutes can be calculated using the normal distribution. The probability that the sample average amount of time taken on each day is at most 11 minutes is approximately 0.9432 * 0.8888 ≈ 0.8383

The problem states that the time taken by a randomly selected applicant to fill out the form follows a normal distribution with a mean of 9 minutes and a standard deviation of 2 minutes. Since the sample size is relatively large (5 individuals on one day and 6 individuals on another), we can use the Central Limit Theorem, which states that the sample mean will be approximately normally distributed regardless of the distribution of the individual observations.

To find the probability that the sample average time taken on each day is at most 11 minutes, we need to calculate the z-scores for each day's sample mean. The formula for the z-score is (x - μ) / (σ / √n), where x is the sample mean, μ is the population mean, σ is the population standard deviation, and n is the sample size.

For the first day with 5 individuals, the sample mean is still 9 minutes, and the standard deviation becomes σ / √n = 2 / √5. We calculate the z-score as (11 - 9) / (2 / √5) ≈ 1.5811.

For the second day with 6 individuals, the sample mean is again 9 minutes, but the standard deviation becomes σ / √n = 2 / √6. We calculate the z-score as (11 - 9) / (2 / √6) ≈ 1.2247.

Next, we need to find the probability of having a z-score less than or equal to the calculated z-scores. Using a standard normal distribution table or a calculator, we can find that the probability for a z-score of 1.5811 is approximately 0.9432, and the probability for a z-score of 1.2247 is approximately 0.8888.

Finally, we multiply these probabilities together since the events are independent (one day's result does not affect the other). Therefore, the probability that the sample average amount of time taken on each day is at most 11 minutes is approximately 0.9432 * 0.8888 ≈ 0.8383 (rounded to four decimal places).

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Report on Commonalities Among Three Chosen Regions

For this assignment, three regions of the world have been selected to identify commonalities among them. The chosen regions are North America, Europe, and East Asia. Through internet research, several commonalities have been identified that are shared among these regions. Below are five commonalities found:

Economic Development:

All three regions, North America, Europe, and East Asia, are characterized by significant economic development. They are home to some of the world's largest economies, such as the United States, Germany, China, and Japan. These regions exhibit high levels of industrialization, technological advancement, and trade activities. Their economies contribute significantly to global GDP and are major players in international commerce.

Technological Advancement:

Another commonality among these regions is their emphasis on technological advancement. They are known for their innovation, research and development, and technological infrastructure. Companies and industries in these regions are at the forefront of technological advancements in fields such as information technology, automotive manufacturing, aerospace, pharmaceuticals, and more.

Cultural Diversity:

North America, Europe, and East Asia are culturally diverse regions, with a rich tapestry of different ethnicities, languages, and traditions. Immigration and historical influences have contributed to the diversity seen in these regions. Each region has a unique blend of cultural practices, cuisines, art, music, and literature. This diversity creates vibrant multicultural societies and fosters an environment of cultural exchange and appreciation.

Democratic Governance:

A commonality shared among these regions is the prevalence of democratic governance systems. Many countries within these regions have democratic political systems, where citizens have the right to participate in the political process, elect representatives, and enjoy individual freedoms and rights. The principles of democracy, rule of law, and respect for human rights are important pillars in these regions.

Education and Research Excellence:

North America, Europe, and East Asia are known for their strong education systems and institutions of higher learning. These regions are home to prestigious universities, research centers, and educational initiatives that promote academic excellence. They attract students and scholars from around the world, offering a wide range of educational opportunities and contributing to advancements in various fields of study.

In conclusion, the regions of North America, Europe, and East Asia share several commonalities. These include economic development, technological advancement, cultural diversity, democratic governance, and education and research excellence. Despite their geographical and historical differences, these regions exhibit similar traits that contribute to their global significance and influence.

Answer:

For this assignment, three regions of the world have been selected to identify commonalities among them. The chosen regions are North America, Europe, and East Asia. Through internet research, several commonalities have been identified that are shared among these regions. Below are five commonalities found:

Economic Development:

All three regions, North America, Europe, and East Asia, are characterized by significant economic development. They are home to some of the world's largest economies, such as the United States, Germany, China, and Japan. These regions exhibit high levels of industrialization, technological advancement, and trade activities. Their economies contribute significantly to global GDP and are major players in international commerce.

Technological Advancement:

Another commonality among these regions is their emphasis on technological advancement. They are known for their innovation, research and development, and technological infrastructure. Companies and industries in these regions are at the forefront of technological advancements in fields such as information technology, automotive manufacturing, aerospace, pharmaceuticals, and more.

Cultural Diversity:

North America, Europe, and East Asia are culturally diverse regions, with a rich tapestry of different ethnicities, languages, and traditions. Immigration and historical influences have contributed to the diversity seen in these regions. Each region has a unique blend of cultural practices, cuisines, art, music, and literature. This diversity creates vibrant multicultural societies and fosters an environment of cultural exchange and appreciation.

Democratic Governance:

A commonality shared among these regions is the prevalence of democratic governance systems. Many countries within these regions have democratic political systems, where citizens have the right to participate in the political process, elect representatives, and enjoy individual freedoms and rights. The principles of democracy, rule of law, and respect for human rights are important pillars in these regions.

Education and Research Excellence:

North America, Europe, and East Asia are known for their strong education systems and institutions of higher learning. These regions are home to prestigious universities, research centers, and educational initiatives that promote academic excellence. They attract students and scholars from around the world, offering a wide range of educational opportunities and contributing to advancements in various fields of study.

In conclusion, the regions of North America, Europe, and East Asia share several commonalities. These include economic development, technological advancement, cultural diversity, democratic governance, and education and research excellence. Despite their geographical and historical differences, these regions exhibit similar traits that contribute to their global significance and influence.

Okay,

Im not going to do the project because you draw that but, ill give an online overview of ur "project."

To prove that the argument is valid using propositional logic, we can apply logical rules and deductions. Let's break down the argument step by step:

(A + B) ^ (C V -B) ^ (-D --> C) ^ A ^ D

We will represent the proposition as follows:

P: (A + B)

Q: (C V -B)

R: (-D --> C)

S: A

T: D

From the given premises, we can deduce the following:

P ^ Q (Conjunction Elimination)

P (Simplification)

Now, let's apply the rules of disjunction elimination:

P (S)

A + B (Simplification)

Next, let's apply the rule of disjunction introduction:

C V -B (S ^ Q)

Using disjunction elimination again, we have:

C (S ^ Q ^ R)

Finally, let's apply the rule of modus ponens:

-D (S ^ Q ^ R)

C (S ^ Q ^ R)

Since we have derived the conclusion C using valid logical rules and deductions, we can conclude that the argument is valid.

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The probability of landing in any yellow region is the area of the yellow region divided by the total area of the square, which is (π + 2) / 4. This is the exact probability.

To find the probability of landing in any yellow region of the square, we need to calculate the area of the yellow regions and divide it by the total area of the square.

Let's consider one of the quarters of the square, which is symmetrical. The yellow region consists of a quarter of a circle with radius 1 unit, and a right-angled triangle with sides of length 1 unit.

The area of the quarter circle is (1/4)π\(r^2\) = (1/4)π(\(1^2\)) = π/4.

The area of the right-angled triangle is (1/2) \(\times\)1 \(\times\)1 = 1/2.

Therefore, the total area of the yellow region in one-quarter of the square is (π/4) + (1/2) = (π + 2)/4.

Since the square has four identical quarters, the total area of the yellow region in the entire square is 4 \(\times\)[(π + 2)/4] = π + 2.

The probability of landing in any yellow region is the area of the yellow region divided by the total area of the square, which is (π + 2) / 4. This is the exact probability.

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The angle in the capital letter "L" measures 90°, making it a right angle.

A right angle is one that is exactly 90 degrees, or half of a straight angle. There is usually a quarter turn in it. The fundamental geometric forms, rectangle, and square, each have four angles that measure 90 degrees.

When two lines cross, and there is a 90-degree angle between them, the lines are said to be perpendicular. A few examples of 90-degree angles in real life include the angle between the hands of a clock at 3 o'clock, the angles between two neighboring sides of a rectangular door or window, etc.

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Answer:

$3.88

Step-by-step explanation:

Using simple mathematical operations, we know that we will require 1436 bricks to construct a brick wall.

A mathematical "operation" is the process of calculating a value utilizing operands and a math operator.

There are predefined rules associated with the math operator's symbol that must be applied to the supplied operands or numbers.

In mathematics, addition, subtraction, multiplication, division, and modular forms are the five basic operations.

So, we know that:

A brick wall's measurements are provided by:

14.5 feet in length

Size: 0.5 feet wide

5.5 feet tall

Brick dimensions are provided by:

6 inches in length

4-inch width

2 inches tall

The number of bricks must be determined:

Thus, the number of bricks is provided by:

Number of bricks = Volume of brick wall/Volume of brick

Number of bricks = 14.5 * 5.5 * 0.5 * 12 * 12 * 12/6 * 4 * 2

Number of bricks = 1435.5

Number of bricks = 1436

Therefore, using simple mathematical operations, we know that we will require 1436 bricks to construct a brick wall.

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