Have you ever swung an object tied to the end of a string in a circle? Do you remember that the faster you swung the object, the harder it was to hold?

Explanation:

rational

Step-by-step explanation:

The discriminant (d) of a quadratic equation ax^2 + bx + c = 0ax

2

+bx+c=0 is:

\boxed{\mathrm{d =} \ b^2 - 4ac}

d= b

2

−4ac

.

If:

• d > 0, then there are two real solutions

• d = 0, then there is a repeated real solution

• d < 0, then there is no real solution.

In this question, we are given the quadratic equation 3x^2 + 4x - 2 = 03x

2

+4x−2=0 . Therefore, the discriminant of the equation is:

b² - 4ac = (4)² - 4(3)(-2)

= 16 - (-24)rational

Step-by-step explanation:

The discriminant (d) of a quadratic equation ax^2 + bx + c = 0ax

2

+bx+c=0 is:

\boxed{\mathrm{d =} \ b^2 - 4ac}

d= b

2

−4ac

.

If:

• d > 0, then there are two real solutions

• d = 0, then there is a repeated real solution

• d < 0, then there is no real solution.

In this question, we are given the quadratic equation 3x^2 + 4x - 2 = 03x

2

+4x−2=0 . Therefore, the discriminant of the equation is:

b² - 4ac = (4)² - 4(3)(-2)

= 16 - (-24)

= 40

Since the discriminant, 40, is greater than zero, the quadratic equation has 2 rational solutions.

= 40

Since the discriminant, 40, is greater than zero, the quadratic equation has 2 rational solutions.

The time constant of a series RC or RL circuit is equal to the product of the resistance and the inductance of the circuit.

The time constant of an RC or RL circuit is a measure of how quickly the circuit will reach its steady-state voltage or current. It is calculated by multiplying the resistance and the inductance of the circuit. In this case, the resistance is 200 ohms and the inductance is 2mH, so the time constant is 400 seconds.

This means that it will take 400 seconds for the voltage or current in the circuit to reach its steady-state value.

In this case, the time constant is 400 seconds (2mH x 200 ohms = 400 seconds).).

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The frequency  is 6.67 kHz and the duty cycle is:16.67%.

​Given:

Pulse width=25

Period=150

Frequency:

Frequency=1/(150×10^-6)

Frequency=1/0.00015

Frequency=6.666 kHz

Frequency=6.67 kHz (Approximately)

Duty cycle:

Duty cycle=(25×10^-6)/ (150×10^-6)×100%

Duty cycle=16.67%

Therefore the frequency  is 6.67 kHz and the duty cycle is:16.67%.

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Answer:

  239 mL

Explanation:

The average of any set of data is the sum of the values, divided by their number.

  v = (240 +242 +235)/3 = 717/3 = 239 . . . mL

The average of the three measurements is 239 mL.

Fine grained of alkali igneous rocks cannot be used in cement because of the volume expansion caused by the Alkali-silica reaction, fine-grained igneous rocks cannot be used as aggregates in cement.

Extrusive igneous rocks have a fine-grained or aphanitic texture, with grains that are too small to see without a magnifying glass. The fine-grained texture suggests that the rapidly cooling lava did not have enough time to form large crystals. A petrographic microscope can be used to examine these tiny crystals.

The texture of an igneous rock (fine-grained vs coarse-grained) is determined by the rate at which the melt cools: slow cooling produces large crystals, while fast cooling produces small crystals.

The chemical reaction that occurs in both alkali cations and hydroxyl ions in the pore solution of hydrated cement paste and certain reactive silica phases present in concrete aggregates is known as the alkali-silica reaction (ASR).

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Explanation:

the resultant force =

\( \sqrt{} {x}^{2} + {y}^{2} \)

A resultant force is the single force and corresponding torque that are produced when adding vectors to a system of forces and torques acting on a rigid body.

R = A + B. Instance 2 To create the resulting vector, two vectors facing the opposite direction are subtracted from one another. Here, the vector B is pointing in the opposite direction of the vector A, and the resulting vector is called R.

A force system is a group of forces that interact at specific locations (may also include couples). Therefore, the collection of forces shown on any free body diagram is a force system. A group of forces is simply referred to as a force system.

Therefore, When an item is under the influence of two or more forces, the combined force can be calculated by adding up the separate forces.

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The proportion of wafers that exceed 0.2125 micrometers of photoresist thickness is approximately 0.583.

To calculate this proportion, we need to determine the area under the uniform distribution curve between 0.2125 and the upper limit of 0.2145. Since the distribution is uniform, the probability density function is constant over this interval.

Therefore, we can calculate the proportion by dividing the length of the interval between 0.2125 and 0.2145 by the total length of the distribution interval, which is 0.2145 - 0.2005. This gives us (0.2145 - 0.2125) / (0.2145 - 0.2005) = 0.583.

The mean of X, which represents the photoresist thickness, can be calculated by taking the average of the lower and upper limits of the distribution. Thus, the mean is (0.2005 + 0.2145) / 2 = 0.2075 micrometers.

The variance of X in a uniform distribution is calculated using the formula (\((b-a)^2\)) / 12, where a and b are the lower and upper limits, respectively. In this case, the variance is (\((0.2145 - 0.2005)^2)\) / 12 = 0.00001717 square micrometers.

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By using the boundary layer equation, the average heat transfer coefficient for the plate is equal to 4.87 W/m²k.

Given the following data:

Surface temperature = 15°C

Bulk temperature = 75°C

Side length of plate = 150 mm to m = 0.15 meter.

Since we have a quiescent room air and a uniform pole surface temperature, the film temperature is given by:

\(T_f=\frac{T_{s} + T_{\infty} }{2} \\\\T_f=\frac{15 + 75 }{2} \\\\T_f = 45\)

Film temperature = 45°C to K = 273 + 45 = 318 K.

For the coefficient of thermal expansion, we have:

\(\beta =\frac{1}{T_f} \\\\\beta =\frac{1}{318}\)

From table A-9, the properties of air at a pressure of 1 atm and temperature of 45°C are:

Next, we would solve for the Rayleigh number to enable us determine the heat transfer coefficient by using the boundary layer equations:

\(R_{aL}=\frac{g\beta \Delta T l^3}{v\alpha } \\\\R_{aL}=\frac{9.8 \;\times \;\frac{1}{318} \;\times \;(75-15) \;\times \;0.15^3 }{1.750 \times 10^{-5}\; \times \;2.416 \times 10^{-5} } \\\\R_{aL}=\frac{9.8\; \times 0.00315 \;\times \;60\; \times\; 0.003375 }{4.228 \times 10^{-10} }\\\\R_{aL}=1.48 \times 10^{7}\)

Also take note, g(Pr) is given by this equation:

\(g(P_r)=\frac{0.75P_r}{[0.609 \;+\;1.221\sqrt{P_r}\; +\;1.238P_r]^\frac{1}{4} } \\\\g(P_r)=\frac{0.75(0.7241)}{[0.609 \;+\;1.221\sqrt{0.7241}\; +\;1.238(0.7241)]^\frac{1}{4} }\\\\g(P_r)=\frac{0.543075}{[0.609 \;+\;1.221\sqrt{0.7241}\; +\;1.238(0.7241)]^\frac{1}{4} }\\\\g(P_r)=\frac{0.543075}{[2.5444]^\frac{1}{4} }\\\\g(P_r)=\frac{0.543075}{1.2630 }\)

g(Pr) = 0.430

For GrL, we have:

\(G_{rL}=\frac{R_{aL}}{P_r} \\\\G_{rL}=\frac{1.48 \times 10^7}{0.7241} \\\\G_{rL}=1.99 \times 10^7\)

Since the Rayleigh number is less than 10⁹, the flow is laminar and the condition is given by:

\(N_{uL}=\frac{h_{L}L}{k} = \frac{4}{3} (\frac{G_{rL}}{4} )^\frac{1}{4} g(P_r)\\\\h_{L}=\frac{0.02699}{0.15} \times [\frac{4}{3} \times (\frac{1.99 \times 10^7}{4} )^\frac{1}{4} ]\times 0.430\\\\h_{L}= 0.1799 \times 62.9705 \times 0.430\\\\h_{L}=4.87\;W/m^2k\)

Based on empirical correlation method, the average heat transfer coefficient for the plate is given by this equation:

\(N_{uL}=\frac{h_{L}L}{k} =0.68 + \frac{0.670 R_{aL}^\frac{1}{4}}{[1+(\frac{0.492}{P_r})^\frac{9}{16}]^\frac{4}{19} } \\\\h_{L}=\frac{0.02699}{0.15} \times ( 0.68 + \frac{0.670 (1.48 \times 10^7)^\frac{1}{4}}{[1+(\frac{0.492}{0.7241})^\frac{9}{16}]^\frac{4}{19} })\\\\h_{L}=4.87\;W/m^2k\)

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The elasticity of demand for oil when the price is $79 per barrel is approximately -0.052.

The elasticity of demand measures the responsiveness of quantity demanded to changes in price. In this case, the elasticity of demand is calculated by taking the derivative of the demand function with respect to price, and then multiplying it by the ratio of price to quantity.

To calculate the elasticity at a specific price, we need to differentiate the demand function with respect to price, which gives us -0.05 * 2,144,309 * p^(-0.05 - 1). Simplifying this expression gives us -107,215.45 * p^(-1.05).

Next, we multiply this expression by the ratio of price to quantity. At a price of $79 per barrel, we substitute p = 79 into the expression and divide it by the quantity consumed. This gives us (-107,215.45 * 79^(-1.05)) / (2,144,309 * 79^(-0.05)). Simplifying further, we find the elasticity to be approximately -0.052.

Interpreting this elasticity value, we can say that a 1% increase in the price of crude oil would result in a approximately 0.052% decrease in per capita consumption of crude oil in Country A in 2008. Similarly, a 1% decrease in price would lead to a 0.052% increase in per capita consumption. This indicates that the demand for oil in Country A is relatively inelastic, meaning that changes in price have a proportionately smaller impact on the quantity demanded.

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All of the aforementioned are used to pull a vehicle except: a bench.

A net force can be defined as the vector sum of all the forces that are acting on a physical object or body. This ultimately implies that, a net force is a single (one) force that substitutes the effect of all the forces acting on a physical object or body.

A force can be defined as a push or pull of an object or physical body, which typically results in a change of motion (acceleration), especially due to the interaction of the object with another.

Generally, the types of mechanical devices that can be to pull a vehicle include the following:

In conclusion, we can infer and logically deduce that all of the aforementioned are used to pull a vehicle except a bench.

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Answer:

Make sure both cars are in park or neutral with the parking brake engaged. This makes sure that all electrical functions (headlights, radios, etc.) are turned off.

When jump starting a car, make sure it is in the right distance of the cables to reach battery.

Thus, when jump-starting a car, always remember the cables are in the right position.

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Answer:

The energy in pneumatic power systems is easily transmitted to gases, which absorb the energy of the system and lower its efficiency.

Explanation:

I did it on edge and got it right.

Answer:

The energy in pneumatic power systems is easily transmitted to gases, which absorb the energy of the system and lower its efficiency

Thanks for points!!! :D

Answer:

a) \(L = 1.5\)

\(L_q = 0.9\)

\(W = \dfrac{1 }{8 } \, hour\)

\(W_q = \dfrac{3}{40 } \, hour\)

\(P = \dfrac{3}{5 }\)

b) The new backacter should be recommended

c) The additional backacter should not be deployed

Explanation:

a) The required parameters are;

L = The number of customers available

\(L = \dfrac{\lambda }{\mu -\lambda }\)

μ = Service rate

\(L_q\) = The number of customers waiting in line

\(L_q = p\times L\)

W = The time spent waiting including being served

\(W = \dfrac{1 }{\mu -\lambda }\)

\(W_q\) = The time spent waiting in line

\(W_q = P \times W\)

P = The system utilization

\(P = \dfrac{\lambda }{\mu }\)

From the information given;

λ = 12 trucks/hour

μ = 3 min/truck = 60/3 truck/hour = 20 truck/hour

Plugging in the above values, we have;

\(L = \dfrac{12 }{20 -12 } = \dfrac{12 }{8 } = 1.5\)

\(P = \dfrac{12 }{20 } = \dfrac{3}{5 }\)

\(L_q = \dfrac{3}{5 } \times \dfrac{3}{2 } = \dfrac{9}{10 } = 0.9\)

\(W = \dfrac{1 }{20 -12 } = \dfrac{1 }{8 } \ hour\)

\(W_q = \dfrac{3}{5 } \times \dfrac{1}{8 } = \dfrac{3}{40 } \, hour\)

(b) The service rate with the new backacter = 1.5 minutes/truck which is thus;

μ = 60/1.5 trucks/hour = 40 trucks/hour

\(P = \dfrac{12 }{40 } = \dfrac{3}{10}\)

\(W = \dfrac{1 }{40 -12 } = \dfrac{1 }{38 } \, hour\)

\(W_q = \dfrac{3}{10 } \times \dfrac{1}{38 } = \dfrac{3}{380 } \, hour\)

λ = 12 trucks/hour

Total cost = \(mC_s + \lambda WC_w\)

m = 1

\(C_s\) = GH¢ = 1300

\(C_w\) = 400

Total cost with the old backacter is given as follows;

\(1 \times 1000 + 12 \times \dfrac{1}{8} \times 400 = \$ 1,600.00\)

Total cost with the new backacter is given as follows;

\(1 \times 1300 + 12 \times \dfrac{1}{38} \times 400 = \$ 1,426.32\)

The new backacter will reduce the total costs, therefore, the new backacter is recommended.

c)

Here μ = 3 min/ 2 trucks = 2×60/3 truck/hour = 40 truck/hour

\(\therefore W = \dfrac{1 }{40 -12 } = \dfrac{1 }{38 } \, hour\)

Total cost with the one backacter is given as follows;

\(1 \times 1000 + 12 \times \dfrac{1}{8} \times 400 = \$ 1,600.00\)

Total cost with two backacters is given as follows;

\(2 \times 1000 + 12 \times \dfrac{1}{38} \times 400 = \$ 2,126.32\)

The additional backacter will increase the total costs, therefore, it should not be deployed.

Minimum speed signs are designed to ensure that drivers do not obstruct traffic flow by driving too slowly, especially on high-speed roads and highways.

The slowest speed at which an aircraft can maintain directional control on the ground or level flight in the air is known as the minimum speed. It is also known as the stall speed, meaning the speed at which the wings generate insufficient lift to keep the aircraft aloft. Weight, configuration, altitude, and weather conditions all have an impact on an aircraft's minimum speed. Pilots are taught to be aware of their aircraft's minimum speed and to take appropriate action to avoid stalling, which can result in loss of control and a potential crash. In aviation, the minimum speed is an important safety consideration.

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c

it could not be d it cover about all the lights u would have to have thick dirt can't be a way to little dirt u would have to just throw dirt on ur lights and b same thing to little amount of dirt

Answer:

building sewer

I hope this helps...

Please mark me Brainliest

The drainage piping between the building foundation and the sewer main or septic tank is known as the sewer lateral or building sewer.

The drainage piping between the building foundation and the sewer main or septic tank is commonly referred to as the "sewer lateral" or "building sewer." This piping system is responsible for carrying wastewater and sewage from individual buildings or structures to the main sewer line or septic tank.

The sewer lateral is typically a buried pipe that connects the building's plumbing system to the larger sewer infrastructure. It is designed to transport wastewater, including water from sinks, toilets, showers, and other sources, away from the building and into the public sewer system or on-site septic system for further treatment or disposal.

In urban areas with centralized sewage systems, the sewer lateral connects the building's plumbing to the municipal sewer main. The sewer main is the primary pipe that carries wastewater from multiple buildings and eventually leads to a wastewater treatment plant.

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Pipe lasers can be used for pipe alignment at distances up to several hundred feet. The exact maximum distance may vary depending on the specific model and manufacturer of the pipe laser.

Pipe lasers are specialized laser leveling devices designed for use in pipe installation and alignment. They project a highly visible laser beam that serves as a reference for aligning pipes with precision.

Pipe lasers are commonly used in construction projects involving the installation of underground pipes, such as sewer lines, drainage systems, or utility pipelines.

While pipe lasers are typically effective for alignment over relatively long distances, their range can be influenced by factors such as atmospheric conditions, ambient light, and the quality of the laser beam itself.

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To plot the bending stress profile, create a simple graph with y as the horizontal axis and sigma as the vertical axis. The values at A, B, C, and D can be indicated on the graph.

To compute the bending stress profile, we need to determine the maximum moment of inertia and the distance of the extreme fibers from the neutral axis.

Assuming that the cross-section is symmetric and uniform, we can determine the moment of inertia as follows:

I = 2[(1/2)(1)^3(0.125) + (1/2)(1)^3(0.125)] + (1)(1)(0.5)^3

I = 0.21875 in^4

The distance from the neutral axis to the extreme fibers is half of the height of the cross-section, which is 0.5 inches.

Using the bending stress formula:

sigma = M*y/I

where M is the applied moment, y is the distance from the neutral axis, and I is the moment of inertia.

Computing the bending stress at each point of interest:

At point A (y = 0.5 inches), sigma = (-50 kip-in)(0.5 in)/(0.21875 in^4) = -228.57 psi

At point B (y = 0.25 inches), sigma = (-50 kip-in)(0.25 in)/(0.21875 in^4) = -457.14 psi

At point C (y = 0 inches), sigma = (-50 kip-in)(0 in)/(0.21875 in^4) = 0 psi

At point D (y = -0.25 inches), sigma = (-50 kip-in)(-0.25 in)/(0.21875 in^4) = 457.14 psi

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Answer:

The time required to reduce the diameter of solid spherical ball from 2 cm to 0.50 cm = 61.60 hours

Explanation:

Given that:

The bulk gas temperature T = 347 K

The pressure = 1.0 atm

Molecular weight of naphthalene = 128 g/mole

density of the solid = 1.145 g/cm³

diffusivity in the air of coefficient = 8.19 × 10 ⁻⁶ m²/s

vapor pressure = 5.0 Torr (666 Pa)

The shape of the ball in this given study is spherical. So, the first step we need to carry out is to state the general differential equation for the mass transfer in the system of the spherical coordinates. After that , we will make use of simplified differential expression form of Fick's Flux. From there we'll determine the surface concentration (c) of the species and finally determine the material balance equation on the naphthalene which will be used in solving the time required to reduce the diameter from 2.0 cm to 0.50cm.      

THE DETAILED EXPLANATION OF WHAT WE JUST SAID CAN BE SEEN IN THE ATTACHED IMAGES BELOW.              

The statement that is not true of ISO 9000 is b. The American National Standards Institute guarantees continued ISO 9000 certification for all the ISO-certified American companies. Here's why:  ISO 9000 is a set of international standards for quality management and quality assurance.

It is designed to help companies achieve consistency in their products and services while also improving customer satisfaction. ISO 9000 is a five-part series of standards that includes ISO 9001, ISO 9002, ISO 9003, ISO 9004, and ISO 19011.

The ISO 9000 certification process involves an accredited third-party certification body reviewing a company's quality management system to ensure that it meets the requirements of the ISO 9001 standard. Once a company has been certified, the certification body will issue an ISO 9000 certificate that the company can use in its advertising and publications.

Continued ISO 9000 certification is not guaranteed. To maintain certification, a company must undergo regular surveillance audits to ensure that its quality management system continues to meet the requirements of the ISO 9001 standard. If a company fails to meet these requirements, it can lose its certification.

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Answer:

115 Ib/ft^3

Explanation:

To determine the maximum dry density in Ib/ft3 we have to calculate :

Bulk unit weight ( yb ) ; W / v

Dry unit weight ( yd. ) :  yb / ( 1 + w )

For every set of data given

assuming  v = 1/30 ft^3

calculating for the 3 data set ( maximum dry density )

weight of soil (W) = 4.40

moisture content (%) (w) = 15.0 = 0.15

Bulk unit weight (yb) = 4.40 / (1/30)  = 132 Ib/ft^3

Dry unit weight ( yd. ) = 132 / ( 1 + 0.15 ) = 114.702 Ib/ft^3

therefore after calculations the maximum dry density in Ib/ft^3 ≈ 115 Ib/ft^3

Employment growth is often used as a measure of economic expansion and a test for domestic economic health.

In this question all the choices were interlinked with each other therefore, the final answer is "Option d".

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Once the external shape and internal features of a part are represented by a combination of lines, further information is provided by Dimension.

In regards to geometry, the  three-dimensional shape is known to be one that can be said to be a form of solid figure or an object/shape that is of known to be made up of three dimensions which are length, width, and height.

Note that the three-dimensional shapes have height as well as thickness or depth.

Therefore, Once the external shape and internal features of a part are represented by a combination of lines, further information is provided by Dimension.

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(a) Newtonian approach to derive the equation of motion:

Using Newton's second law of motion, we can write the equation of motion for the spring-mass-damper system as:

m * d^2x/dt^2 + b * dx/dt + k * x = F(t)

Where:

m = mass of the system (1 kg)

b = damping coefficient (3 Ns/m)

k = spring constant (5 N/m)

x = displacement of the mass from its equilibrium position

F(t) = applied force (step input)

Taking Laplace transform on both sides, we have:

m * s^2 * X(s) + b * s * X(s) + k * X(s) = F(s)

Rearranging the equation, we get:

X(s) = F(s) / (m * s^2 + b * s + k)

(b) Changing the spring constant (k) to 5*k:

If the spring constant is increased to 5 times its original value, the system becomes stiffer. This change in the spring constant will result in a higher natural frequency of the system. The natural frequency (wn) is given by:

wn = sqrt(k / m)

By increasing k, the natural frequency of the system will increase, resulting in a faster oscillation and shorter period of the system's response.

(c) Keeping the spring constant (k) the same but increasing the damping constant (b) to 5*b:

Increasing the damping constant while keeping the spring constant the same will result in a higher damping ratio (ζ) for the system. The damping ratio is given by:

ζ = b / (2 * sqrt(k * m))

By increasing the damping constant, the system's response will be more overdamped. It will take longer for the system to reach its equilibrium position, resulting in a slower and smoother response.

(d) Model and Simulation in Engineering:

In summary, modeling is the creation of a simplified representation of a system, while simulation involves running the model to analyze system behavior. Simulation is a valuable tool in engineering as it allows for analysis, prediction, and optimization of complex systems, leading to improved designs and decision-making.

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There are basically five types of welding namely:

a)Gas Metal Arc Welding (GMAW/MIG)

b)Friction welding,

c)ELECTRON BEAM WELDING

d) LASER BEAM WELDING

e) RESISTANCE WELDING

What is welding?

Welding is a fabrication process in which two or more parts are joined together using of heat, pressure, or both to form a joint as the parts cool. materials to be welded include metals, thermoplastics, and wood.

Types of welding processes

a)Gas Metal Arc Welding (GMAW/MIG)

Used mainly for joining metals like stainless steel, nickel, copper alloys, aluminum, titanium, and cobalt.

b)Friction welding

This is a  technique used to join materials using mechanical friction. this can be used to join wood, steel, and aluminum.

c)ELECTRON BEAM WELDING

This process uses a mean of high-velocity electrons to combine materials this can be used to join thick sections in the aerospace, automotive, rail, and nuclear power industry.

d)LASER BEAM WELDING

this is used to combine pieces of metal or thermoplastics.

e) RESISTANCE WELDING

This is a process that joins metals by applying pressure and passing a current through them for a period of time.

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Answer:

Total number of pastries that will be made from at least \(3/8\) a pound of dough is \(8.\)

Explanation:

It is given that the line plot shows the weight of the dough for each pastry.

From the given box plot it is clear that,

Number of pastries with weight pound

Number of pastries with weight pound

Number of pastries with weight pound

We know that

We need to find the number of pastries that will be made from at least a pound of dough. It means the number of pastries whose weight is

Number of pastries with weight pound Number of pastries with weight pound

\(N=3+5\)

\(N=8\)

Therefore, the total number of pastries that will be made from at least a pound of dough is

It is the complete question,

Answer:

"Physical" would be the right approach.

Explanation:

So the answer here is just the perfect one.

It is false that a construction is considered a work of art because it has technological, environmental and social considerations.

A construction can be considered a work of art when its appearance and visual factor is characterized by beauty and differs from other constructions in its internal and external part. For example, the Burj Khalifa building located in Dubai is a work of art because its infrastructure is scaled and has very striking shapes for the public.

On the other hand, a self-sustaining house is not considered a work of art despite including technology to have environmental and social consideration. According to the above, it can be inferred that it is false that when a construction has a technological implementation for social and environmental considerations it is a work of art.

Note: This question is incomplete because there is some information missing. Here is the complete information:

Options

True

False

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