Helen put the soaked sandstone into a freezer for 24 hours . water in the spaces in the sandstone froze and expanded. what would happen to the sandstone as the water froze and expanded

Answers

Answer 1

As the water in the crevices of the sandstone freezes, the ice will expand and could cause the sandstone to break.

What is expansion?

The term expansion connotes an increase in volume. When water is converted into ice, the volume of the water increases hence it expands.

Therefore, as the water in the crevices of the sandstone freezes, the ice will expand and could cause the sandstone to break.

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Related Questions

an element that conducts thermal energy well and is easily shaped is a:____.

Answers

The element that conducts thermal energy well and is easily shaped is a metal. Their malleability and ductility allows for the creation of intricate shapes and structures.

Metals, such as copper, aluminum, iron, and silver, possess excellent thermal conductivity properties, allowing them to efficiently transfer heat. The high thermal conductivity of metals is due to the presence of free electrons that can easily move and transfer thermal energy.

Metals are also known for their malleability and ductility, which means they can be easily shaped and formed into various structures. This property is attributed to the metallic bonding present in metals, where the positive metal ions are surrounded by a "sea" of delocalized electrons, enabling the atoms to slide past each other when subjected to external forces.

These combined characteristics make metals ideal for applications that require effective heat transfer, such as in electrical wiring, heat sinks, cooking utensils, and industrial machinery. Additionally, their malleability allows for the creation of intricate shapes and structures, making metals highly versatile in various industries and applications.

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An object with a mass of 2.0 kg accelerates 2.0 m/s 2when an unknown force is applied to it. What is the amount of force?

Answers

Answer:

4 N

Explanation:

mass = 2 kg

acceleration = 2 m/s^2

Force = mass * acceleration

         = 2 *2

         = 4 N

If someone ran 100 meters in 20 seconds, then ran another 100 meters in 25
seconds, what would the runner’s average speed be over the whole 200 meters?
pls help!!!

Answers

I think the runner’s average speed would be 4.44/ 4.4 repeating.

Hold your index finger and middle fingers close to each other, leaving a small slit between them about 1 mm in width. Look through the slit into a source of light such as the window or lamp (NOT THE SUN). You will need to look with one eye up close to the slit. Why do the vertical black lines show up when your fingers are close together but not when they are far apart? Explain.

Answers

Answer:

I would say tunnel vision cause your only using one eye and if your looking through a tiny space your vision gets blury

Explanation:

A car starts from rest on a curve with a radius of 150 m and tangential acceleration of 1.3 m/s2 .Through what angle will the car have traveled when the magnitude of its total acceleration is 3.0 m/s2 ?

Answers

We can start by using the formula for tangential acceleration:

a_t = r * α

How to use tangential acceleration ?where a_t is the tangential acceleration, r is the radius of the curve, and α is the angular acceleration. Rearranging this equation, we get:

α = a_t / r = 1.3 m/s^2 / 150 m = 0.00867 rad/s^2

Next, we can use the formula for the magnitude of total acceleration:

a_total = √(a_t^2 + a_c^2)

where a_c is the centripetal acceleration. We can rearrange this equation to solve for a_c:

a_c = √(a_total^2 - a_t^2) = √(3.0^2 - 1.3^2) = 2.5 m/s^2

Now, we can use the formula for centripetal acceleration:

a_c = r * ω^2

where ω is the angular velocity. Rearranging this equation, we get:

ω = √(a_c / r) = √(2.5 m/s^2 / 150 m) = 0.1155 rad/s

Finally, we can use the formula for angular displacement:

θ= ω^2 * t / 2

where t is the time elapsed. Since the car starts from rest, we can use the formula for initial velocity and acceleration:

v_i = 0

a = a_t

to find the time it takes for the car to reach the required total acceleration of 3.0 m/s^2:

a = (v_f - v_i) / t

t = (v_f - v_i) / a

t = v_f / a

where v_f is the final velocity. Using the formula for final velocity and the fact that the car starts from rest, we get:

v_f^2 = 2 * a_t * θ

v_f = √(2 * a_t * θ)

t = √(2 * θ / a_t)

Substituting the values we have calculated, we get:

t = √(2 * θ / 1.3) = √(1.5385 * θ)

t = v_f / a = √(2 * a_t * θ) / a_t = √(2 * θ / 1.3)

Setting these two expressions for t equal to each other, we get:

√(1.5385 * θ) = √(2 * θ / 1.3)

Squaring both sides and solving for θ, we get:

θ = 4.89 radians

Therefore, the car will have traveled through an angle of 4.89 radians when the magnitude of its total acceleration is 3.0 m/s^2.

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Emily makes 0.250 kg of hot tea at 99.0 degrees Celsius. How much ice at 0.00 degrees Celsius must she add to the tea so that the mixture reaches a final temperature of 8.00 degrees Celsius? You may treat the tea as if it is water

Answers

Emily needs to add 0.108 kg of ice to the hot tea.

1. Determine the heat lost by the hot tea. We can use the formula: Q = m * c * ΔT, where Q is the heat energy, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature.

Q_lost = (0.250 kg) * (4186 J/kg·°C) * (99.0°C - 8.0°C)

2. Determine the heat gained by the ice as it melts and reaches the final temperature.

Q_gained = (m_ice) * (334000 J/kg) + (m_ice) * (4186 J/kg·°C) * (8.0°C)

3. Since the energy lost by the tea is equal to the energy gained by the ice, we can set up an equation:

Q_lost = Q_gained

4. Substitute the values and solve for m_ice, the mass of ice.

(0.250 kg) * (4186 J/kg·°C) * (99.0°C - 8.0°C) = (m_ice) * (334000 J/kg) + (m_ice) * (4186 J/kg·°C) * (8.0°C)

5. Simplify and solve the equation:

(0.250 kg) * (4186 J/kg·°C) * (91.0°C) = (m_ice) * (334000 J/kg) + (m_ice) * (4186 J/kg·°C) * (8.0°C)

(955085 J) = (m_ice) * (334000 J/kg) + (m_ice) * (33488 J)

(955085 J) = (m_ice) * (367488 J)

m_ice = (955085 J) / (367488 J)

m_ice ≈ 0.108 kg

Therefore, Emily needs to add approximately 0.108 kg of ice to the hot tea to reach a final temperature of 8.00 degrees Celsius.

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In which year did Canadian women win the right to vote in elections?

Answers

Canadian women won the right to vote in federal elections in the year 1918.

This was a significant moment in Canadian history as it marked a turning point in the fight for women's suffrage. Prior to this, women were not allowed to vote or participate in the political process. However, with the passing of the Canadian Elections Act, women over the age of 21 who were British subjects or wives of British subjects were granted the right to vote. This was a major victory for the suffragette movement in Canada and paved the way for greater gender equality in the country. Today, women's participation in elections and politics is encouraged and celebrated, and the right to vote is seen as a fundamental aspect of democratic societies.

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What is matter made of ? Will mark as brainliest to answer

Answers

Answer:

Explanation:

All matter is made up of atoms, which are turned up of protons, neutrons and electrons.

They bond together to make up matter

Answer:

Atoms

Explanation:

All matter is made up of atoms, which are in turn made up of protons, neutrons and electrons. Atomess come togetheer to forms molecules, which are the building blocks for all types of matter

Find the order of magnitude of the following physical quantities. (a) The mass of Earth’s atmosphere: (b) The mass of the Moon’s atmosphere: 25,000 kg; (c) The mass of Earth’s hydrosphere: (d) The mass of Earth: (e) The mass of the Moon: (f) The Earth–Moon distance (semimajor axis): (g)The mean Earth–Sun distance: (h) The equatorial radius of Earth: (i) The mass of an electron: (j) The mass of a proton: (k) The mass of the Sun:

Answers

Answer:

Book Cover for University Physics …

University Physics Volume 1

Samuel J. Ling, Jeff Sanny, William Moebs 1 Edition

Chapter 1, Problem 14

Question

Answered step-by-step

Find the order of magnitude of the following physical quantities. (a) The mass of Earth's atmosphere: (b) The mass of the Moon's atmos…

Find the order of magnitude of the following physical quantities. (a) The mass of Earth's atmosphere: (b) The mass of the Moon's atmosphere: (c) The mass of Earth's hydrosphere: (d) The mass of Earth: (e) The mass of the Moon: (f) The Earth-Moon distance (semimajor axis): The mean Earth-Sun distance: (h) The equatorial radius of Earth: (i) The mass of an electron: (j) The mass of a proton: (k) The mass of the Sun: .

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Transcript

So to find the order of magnitude of all these numbers, we're gonna first want to take the log based 10 of the number, and then, well around it's the nearest integer. And so, for part, A. If we take log based 10 of 5.1 times 10 to 18 find that's equal to 18.7 on the round that the nearest integer is going to be an order of magnitude of 19. And then we'll keep doing the same thing for B 25,000. Log 10 is 4.4, and that becomes just four for Part C, taking log based 10 of the value refined 21.1. And that's going to be an order of magnitude of 21 for D. If we take the log based 10 we find that it's equal to 24.8, which rounds to 25 then for E. We have long based 10 of the numbers, equal to 22.9, which rounds up to 23 for F. The log based 10 of this number is 8.6, which rounds up to nine. Fergie Log, based 10 is equal to 11.2, which rounds down to a new order magnitude of 11 for H. We have logged based 10 is 6.8, which rounds up to seven for I. We have loved based 10 equal to negative 30 0.0, and it's negative because the exponents is negative here. And so this is going to be an order of magnitude of negative 30. And then for Jay, we have log based tens equal to negative 26 0.8, which rounds to negative 27 as the order of magnitude. And then finally for K, we have logged based times equal to 30.3, which runs down to an order of magnitude of 30.

(a) The mass of Earth's atmosphere is ~10^19 kg;

(b) The mass of the Moon's atmosphere is 25,000 kg;

(c) The mass of Earth's hydrosphere is ~10^21 kg;

(d) The mass of Earth is ~10^24 kg;

(e) The mass of the Moon is ~10^22 kg;

(f) The Earth–Moon distance (semimajor axis) is ~10^8 m;

(g) The mean Earth–Sun distance is ~10^11 m;

(h) The equatorial radius of Earth is ~10^7 m;

(i) The mass of an electron is ~10^-31 kg;

(j) The mass of a proton is ~10^-27 kg; and

(k) The mass of the Sun is ~10^30 kg.

The orders of magnitude refer to powers of 10, which can be expressed in exponential notation. For example, the order of magnitude for the mass of the Earth's atmosphere is 10^19 kg, which can be written as 1.0 x 10^19 kg. The order of magnitude of a physical quantity indicates how large or small it is compared to other values.

For example, the mass of the Moon's atmosphere is much smaller than the mass of Earth's atmosphere. Similarly, the mass of the Earth is much larger than the mass of the Moon.

The order of magnitude of the Earth–Moon distance (semimajor axis) is much larger than the equatorial radius of Earth. The order of magnitude of the mass of an electron and proton are much smaller than the mass of the Sun.

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A train leaves the station and travels 21.62 km. The train had an average velocity of 36.0 m/s How much time passed in order for the train to travel the 22.62 km and what is the velocity of the train in mi/hr?

Answers

Answer:

See below

Explanation:

rate * time = distance

36 m/s  * t  = 21620 m      ( converted  km to m)

t = 600.56 seconds  = ~ 10 minutes    = 1/6 hr

21.62 km = 13.43 miles

13.43 miles / ( 1/6 hr ) = 80.6 mi/hr

It took 600.56 seconds for the train to travel 21.62 km, and its velocity is approximately 80.47 miles per hour.

Given:

Distance traveled (d) = 21.62 km = 21,620 m

Average velocity (v) = 36.0 m/s

The time it took for the train to travel 21.62 km and its velocity in miles per hour is:

Time (t) = Distance (d) ÷ Average Velocity (v)

The time (t) it took for the train to travel 21.62 km.

t = 21,620 ÷  36.0

t = 600.56 seconds

The velocity from m/s to mi/hr.

Velocity = 36.0 × 2.23694

Velocity = 80.47064 mi/hr

So, it took 600.56 seconds for the train to travel 21.62 km, and its velocity is approximately 80.47 miles per hour.

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A polymerization process is used to create a synthetic rubber material known as styrene butadiene copolymer. Explain the difference between a chemical formula and a chemical equation, using this copolymer as an example.

A polymerization process is used to create a synthetic rubber material known as styrene butadiene copolymer.

Answers

Answer:

the picture is so blured can you type it in comment i will wait:(

In the above 4 vectors, vector B has a magnitude of 61 . What is the +Y component of vector B ?

Answers

we can use the magnitude and components of the vector B to find its y-component. Let's consider B vector in standard position (starting at the origin). Its coordinates are (6, 4, 0).

The given vectors are:
a = (-3, -6, 2)
b = (6, 4, 0)
c = (-1, 2, -2)
d = (-2, 3, 4)
Here, the magnitude of vector B is 61. So, ||B|| = 61
Therefore, we have:
\(||B||² = (6)² + (4)² + (0)²\)
\(=> ||B||² = 36 + 16 + 0\)
\(=> ||B||² = 52\)
The formula to find the y-component of a vector is given by:
\($y$-component $= ||\vec{v}||\cdot\sin\theta$\)
where,\($||\vec{v}||$\) is the magnitude of vector \($\vec{v}$\) and \($\theta$\) is the angle that vector \($\vec{v}$\) makes with the positive\($x$-axis\).

Here, we can use the following equation to calculate the angle that vector B makes with the positive x-axis:
\($\tan\theta = \frac{y}{x}$\)
\(=> $\theta = \tan^{-1}\left(\frac{y}{x}\right)$\)
Thus, the angle made by the vector B with the positive x-axis is:
\($\theta = \tan^{-1}\left(\frac{4}{6}\right)$\)
\($\theta = \tan^{-1}\left(\frac{2}{3}\right)$\)
Hence, the y-component of vector B is given by:
\($y$-component $= ||\vec{B}||\cdot\sin\theta$\)
\($= 61 \cdot \sin(\tan^{-1}(2/3))$\)
\($= 61 \cdot \frac{2}{\sqrt{13^2+2^2}}$\)
\($= 61 \cdot \frac{2}{\sqrt{173}}$\)

Therefore, the +Y component of vector B is $\frac{122}{\sqrt{173}}$, which is approximately equal to 9.265 units (rounded to three decimal places).

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QUESTION: Is there a relationship between height and shoe size? Write a one sentence
summary of your graph.
J

Answers

Answer:

There is no particular relationship between the height and shoe size. But the shoe sizes in males is usually bigger than females. And the shoe size tends to get bigger when the person is taller.

Explanation:

2.0 in = ? mm ( 1in = 2.54 cm )

Answers

Answer:

50.8 mm

Explanation:

there are 10 mm in 1 cmmultiply 2.54 by 2 (5.08)multiply 5.08 by 10 (50.8)

Ans 50.8 mm

Explanation:

2 in = 5.08 cm

and 1 cm = 10 mm

mulitply  5.08*10 = 50.8 mm

GIVING BRAINLY, FOLLOW, STARS AND POINTS

Which of the following descriptions of these structures is accurate?
a. they are manufactured shell structures
b. they are manufactured mass structures
C. it's a manufactured shell structure

Answers

Answer:

Wheres. The. Pics. Of. The. Structures

Explanation:

Rahul wants to change the motion map shown so that it shows uniform circular motion. An illustration of a circle with four black dots on the top, bottom, left and right of the circle. Each dot has a vector toward the center of the circle of equal length and a vector tangent to the circle in a counterclockwise direction and of increasing length staring from the one on the right. What change should Rahul make? He should change the length of each vector that points toward the center so that it is the same length as the vector pointing tangent to the circle at that point. He should change the lengths of the vectors that point tangent to the circle so that each is the same length. He should change the direction of the vectors that are tangent to the circle so that each points away from the center of the circle. He should change the direction of the vectors that are tangent to the circle so that each points toward the center of the circle.

Answers

Rahul should change the lengths of the vectors that point tangent to the circle so that each is the same length.

Uniform Circular Motion:

A uniform circular motion is a motion in a circle where the tangential speed of the object is constant.

In the motion map:

The arrows pointing towards the center of the circle represent the centripetal acceleration, and their length represents the magnitude of the acceleration.The arrows pointing tangentially to the circle represent the tangential speed, and their length represents the magnitude of the speed.

In this motion map,  the length of the vectors pointing tangent to the circle is not constant: this means that the speed is not constant. In order to have a uniform circular motion, the speed must be constant, therefore the lengths of the vectors that point tangent to the circle must be the same.

Thus, we can conclude that Rahul should change the lengths of the vectors that point tangent to the circle so that each is the same length.

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What is angle between the vectors 2i -3j +K
and 3i +2j
?
a. 90°
C. 60°
b. 0°
d. 120°​

Answers

Answer:

the answer is B

Explanation:

edg 2020

Which process is the most scientifically plausible explanation for how the organisms released oxygen into Earth's atmosphere? Group of answer choices

Answers

Answer:

Photosynthesis

Explanation:

Studies about the time period of oxygen accumulation suggests that free oxygen was first produced by prokaryotic and then later by eukaryotic organisms in the ocean. These organisms carried out photosynthesis more efficiently, producing oxygen as a waste product.

The organism mainly responsible for this is known as cyanobacteria, or blue-green algae. These microbes conduct photosynthesis: using sunshine, water and carbon dioxide to produce carbohydrates and, oxygen.

A radio antennae picks up a radio wave with frequency 103.5 Hz. What is the frequency of the alternating signal in the antennae wiring?

Answers

The frequency of the alternating signal in the antennae wiring is 103.5 Hz.

What is resonant frequency?

Resonant frequency is the oscillation or vibration of a system at its natural frequency.

When the radio antennae picks up the radio wave, the natural frequency of the antennae must be the same as the frequency of the radio wave.

frequency of the antennae = frequency of the radio wave

Thus, the frequency of the alternating signal in the antennae wiring is 103.5 Hz.

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A scientist wants to measure the thickness of an aeroplane wing using ultrasound.
She has an electronic source and timer which generates a sound wave of wavelength 20 cm and frequency 29000 Hz
She places the device on the top surface of the wing. It takes 0.32 ms for the sound wave to travel to the bottom of the wing and reflect back to the receiver.

Calculate the thickness of the wing to two significant figures.

Answers

Answer:

High pitch means small wavelength, and the size of a musical instrument is directly related to the wavelengths of sound it produces. So a small instrument creates short-wavelength sounds. Similar arguments hold that a large instrument creates long-wavelength sounds.

Explanation:

6. A 55 kg skier is at the top of a slope, as shown in the illustration below. At the
initial point A, the skier is 10.0 m vertically above the final point B.
a. Set the zero level for gravitational potential energy at B, and find the gravitational
potential energy associated with the skier at A and at B. Then find the difference
in potential energy between these two points.
b. Repeat this problem with the zero level at point A
c. Repeat this problem with the zero level midway down the slope, at a height of 5.0
m.​

Answers

The question mentions an illustration that is not provided, but I can solve the problem anyway.

Answer:

Ua - Ub = 5,390 J regardless of the reference height

Explanation:

Gravitational Potential Energy

Gravitational potential energy is the energy stored in an object because of its vertical position or height in a gravitational field.

It can be calculated with the equation:

U=m.g.h

Where m is the mass of the object, h is the height with respect to a fixed reference, and g is the acceleration of gravity or \(9.8 m/s^2\).

The problem is about proving the difference in potential energy does not depend on the reference used to calculate them.

a. Let's set the zero level for gravitational potential energy at B, i.e., h=0 at B.

The m=55 kg skier is at the top of the slope (point A) at a height of h=10 m.

The gravitational potential energy Ua is:

Ua = 55 * 9.8 * 10 = 5,390 J

The gravitational potential energy Ub (h=0) is:

Ub = 55 * 9.8 * 0 = 0 J

The difference is:

Ua - Ub = 5,390 J - 0 J = 5,390 J

b. Now fix the zero level at point A (h=0).

The gravitational potential energy Ua (h=0) is:

Ua = 55 * 9.8 * 0 = 0 J

Point B is at a height h=-10 m since it's below the reference.

The gravitational potential energy Ub (h=-10) is:

Ub = 55 * 9.8 * (-10) = -5,390 J

The difference is:

Ua - Ub = 0 J - (-5,390 J) = 5,390 J

We get the same value.

c. Finally, fix the reference at the midpoint between A and B.

Point A is at a height h=5 m since it's 5 m above the reference.

The gravitational potential energy Ua is:

Ua = 55 * 9.8 * 5 = 2695 J

Point B is at a height h=-5 m since it's 5 m below the reference.

The gravitational potential energy Ub is:

Ub = 55 * 9.8 * (-5) = -2695 J

The difference is:

Ua - Ub = 2695 J - (-2695 J) = 5,390 J

Again, we get the same value.

Conclusion:

Ua - Ub = 5,390 J regardless of the reference height

Un alambre de 2m de longitud soporta una carga de 5400 N. El diámetro de la sección transversal es de 2 mm y el módulo de Young es de 4.2x1010 N/m2. Determine el alargamiento del alambre.

Answers

Hey there, hope you’re having a positive day. Can you try translate this into English please, unfortunately I do not understand your question as I don’t understand your language. No hate towards you happy Thanksgiving

If the string has a m value of 2.56 x 10-3 g/cm, what is the velocity of this wave?

Answers

Without the tension in the string (T), we cannot determine the velocity of the wave. The velocity of a wave can be calculated using the formula v = fλ, where v represents velocity.

f represents frequency, and λ represents wavelength. However, in the given question, we are only provided with the mass per unit length (m) of the string.


To determine the velocity of the wave, we need to use the formula v = √(T/μ), where T represents the tension in the string and μ represents the linear mass density of the string.


In this case, we are given the mass per unit length (m), which is equal to μ. Thus, μ = 2.56 x 10^-3 g/cm.


We also need to know the tension in the string (T) to calculate the velocity. Unfortunately, the tension is not provided in the question. Therefore, without this information, we cannot accurately calculate the velocity of the wave.

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A dipole is centered at the origin, with its axis along the axis, so that at locations on the axis, the electric field due to the dipole is given by E = (0, 1/4 pi epsilon_0 2qs/gamma^3, 0) v/m The charges making up the dipole are q_1 = +4 nC and q_2 = nC, and the dipole separation is s = 8 mm. What is the potential difference along a path starting at location p_1 = (0, 0.04, 0) m and ending at location P_2 = (0, 0.05, 0) m?

Answers

Answer:

Explanation:

Given that:

\(q_1 = + 4nC \\ \\ q_2 = -4nC \\ \\ q = 4nC\)

\(P_1 = (0,0.04,0) m\\\\ P_2 = (0,0.05,0) m\)

As \(q_1\) \(\text{is nearer to }\)\(P_1 \& P_2\) then \(q_2,q_1\) \(\text{is positive, Thus}\), \(E \limits^{\to}\)\(\text{ will be along the positive X-axis.}\)

Recall that:

\(E ^{\to} = \dfrac{-dV}{dr}\implies E_y = \dfrac{-dV}{dy} \\ \\ = \int^{P_2}_{P_1}dV = -\int \limits ^{(0.05)}_{(0.04)}E_y \ dy \\ \\ \implies (V_{P_2}}-V_{(P_1)}) = \dfrac{-2q_5}{4 \pi \varepsilon _o} \int \limits ^{(0.05)}_{(0.04)} \dfrac{dy}{y^3} \\ \\ \implies (V_{P_2}}-V_{(P_1)}) = \dfrac{-2q_5}{4 \pi \varepsilon _o} \Big[ \dfrac{-1}{2y^2} \Big]^{0.05}_{0.04} \\ \\ \implies (V_{P_2}}-V_{(P_1)}) = \dfrac{q_5}{4 \pi \varepsilon _o} \Big[\dfrac{1}{y^2}\Big] ^{0.05}_{0.04}\)

\(\\ \\ \implies (V_{P_2}}-V_{P_1}) = \dfrac{(4\times 10^{-9})(8\times 10^{-3})}{4 \pi (8.854 \times 10^{-12})} \Big [\dfrac{1}{(0.05)^2}-\dfrac{1}{(0.04)^2} \Big ]V \\ \\ (V_{P_2}}-V_{P_1}) = \mathbf{-64.71 \ volts}\)

how much electrical energy does a small heating coil use if it runs for 5 minutes using a 12 volt power supply that provides 2.5 amperes of current?

Answers

691.2 W electrical energy does a small heating coil use if it runs for 5 minutes using a 12-volt power supply that provides 2.5 amperes of current.

What is power?

Power refers to the rate at which a work is completed. It can also be defined as the total amount of energy expended in a given period of time. Power is measured in Watt (W).

What is energy?

It is the ability of a system to do work. It is measured Joule (J).

When the work done is said to be one joule?

Work done is said to be one joule when a 1 N of force is applied on an object, and the object moves by 1 m because of the force.

The formulae for power can be expressed as follows

P = \(V^{2}R\)

R = \(\frac{V}{I}\)

As per the question,

V = 12 V, I = 2.5 A

Therefore,

R = \(\frac{12}{2.5}\) = 4.8

Now,

P = 12 x 12 x 4.8 = 691.2 W

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Although frequently referred to a galvanized rigid conduit (GRC), the NEC® identifie thi wiring method a rigid metal conduit (RMC). Where trade ize 11/2 RMC i threaded (crewed wrenchtight) together between boxe or encloure, the maximum ditance permitted between trap (upport) i ___ feet. The ditance between the boxe for thi traight run of conduit i almot 200 feet

Answers

The National Electric Code (NEC) identifies rigid metal conduit (RMC) as a wiring method, even though it is often referred to as galvanized rigid conduit (GRC).

If 11/2 RMC is threaded (screwed wrench-tight) together between boxes or enclosures, the maximum distance allowed between supports is 130 feet. This straight run of the conduit is almost 200 feet, so it would require additional support to ensure proper electrical performance and safety.

When determining the proper support spacing for a straight run of conduit, it is important to consider factors such as the weight of the conduit, the conductors inside, and the number of bends in the conduit. Too few supports can create sagging and tension, which can damage the insulation of the conductors and potentially cause a short circuit.

Too many supports can be costly and difficult to install. Therefore, it is important to understand the proper support spacing requirements and follow the NEC guidelines.

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Write a statement that shows how the charge on an ion relates to the number of electrons transferred

Answers

Answer:

N = q / e    where q is the total charge on the ion and e = 1.6E-19 the charge on an electron or N = coulombs / (coulombs / electron)

3. A(n)______ is someone who travels to new places or does new things. A. explorer B. thrill C. expedition D. research

Answers

Answer:

explorer

Explanation:

Answer:

a) EXPLORER

Explanation:

An explorer is someone who travels to new places or does new things.

As altitude increases, the air pressure decreases. How do you think the lower pressure will affect the following?.

Answers

Answer:

A. Freezing point: Increase.

B. Melting point: Decrease

C. Boiling point:  Decrease​

Explanation:

As we go up in higher altitudes the air becomes on and less dense, hence the decrease in the water vapor content at such altitude leads to a decrease of boiling point.

Thus the air above is cool and much colder than at the ground surface. The vapor pressure is temperature-dependent and thus the melting point will decrease.

What energy transformation takes place when you push a pencil off your desk? A. Mechanical energy transforms into kinetic energy. B. Potential energy transforms into nuclear energy. C. Potential energy transforms into kinetic energy. D. Kinetic energy transforms into potential energy.​

Answers

When you push a pencil off your desk, the energy transformation that takes place is that potential energy transforms into kinetic energy.

The correct answer to the given question is option C.

Potential energy is the energy stored within an object because of its position or configuration.

In this scenario, the pencil has potential energy because of its elevated position on the desk. When the pencil is pushed off the desk, it begins to move, which means that it has kinetic energy. Kinetic energy is the energy of motion.

As the pencil falls off the desk, its potential energy is transformed into kinetic energy, which is the energy that results from its motion. The faster the pencil falls, the greater its kinetic energy will be because kinetic energy is directly proportional to the square of an object's velocity.

Therefore, when you push a pencil off your desk, the potential energy that it has because of its elevated position is transformed into kinetic energy as it falls towards the ground.

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