Helium gas collected at a pressure of 0.0045 atm is put into a flexible balloon measuring 350 mL in volume. What volume, in mL, would the balloon be if the pressure were increased to 0.350 atm?

Answer:

what's the question?

Explanation:

for real though what's the question?

The amount of excess acetic anhydride is:Amount of excess acetic anhydride = initial amount - amount used = 0.0196 mol - 0.0145 mol = 0.0051 molTherefore, 0.0051 mol of acetic anhydride is used in the reaction.

The balanced chemical equation for the reaction of salicylic acid with acetic anhydride is given as follows: 2C7H6O3 + C4H6O3 ⟶ 2C9H8O4 + H2OIn this equation, salicylic acid (C7H6O3) is the limiting reagent and acetic anhydride (C4H6O3) is the excess reagent. The stoichiometric ratio between salicylic acid and acetic anhydride is 2:1. This means that for every two moles of salicylic acid, one mole of acetic anhydride is required. To find out how much of the excess reactant is used when the reaction is complete, we need to determine the limiting reagent and the excess reagent. We can do this by calculating the amount of product that each reactant can produce and comparing the values.Let's first calculate the number of moles of each reactant:No. of moles of salicylic acid = mass/molar mass = 2/138 = 0.0145 molNo. of moles of acetic anhydride = mass/molar mass = 2/102 = 0.0196 molTo determine the limiting reagent, we need to calculate the amount of product that each reactant can produce.

According to the balanced equation, 2 moles of salicylic acid produces 2 moles of aspirin, while 1 mole of acetic anhydride produces 2 moles of aspirin. Therefore, the amount of aspirin that can be produced from each reactant is as follows : Amount of aspirin produced from salicylic acid = 2 x 0.0145 mol = 0.0290 molAmount of aspirin produced from acetic anhydride = 2 x 0.0196 mol = 0.0392 molSince salicylic acid can produce only 0.0290 mol of aspirin, it is the limiting reagent. This means that acetic anhydride is in excess. To determine how much of the excess reactant is used, we need to subtract the amount of acetic anhydride used from the amount that was initially present. The amount of acetic anhydride used is equal to the amount of salicylic acid used, which is 0.0145 mol.

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Answer:

yes

Explanation:

CO2 is soluble because water molecules are attracted to these polar areas. The bond between carbon

According to ideal gas equation, 3731.78 liters of ammonia is produced at STP.

The ideal gas equation is a equation which is applicable in a hypothetical state of an ideal gas.It is a combination of Boyle's law, Charle's law,Avogadro's law and Gay-Lussac's law . It is given as, PV=nRT where R= gas constant whose value is 8.314.The law has several limitations.

Substituting P=1 atmosphere ,n=28/17.03=1.644 moles ,R=8.314 , T=273 K in the formula,V=1.644×8.314×273/1=3731.78 liters.

Thus,3731.78 liters of ammonia is produced at STP.

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Your question is incomplete, but most probably your full question was,how many liters of ammonia, measured at STP, are produced when 28.0 grams of nitrogen is completely consumed?

N2(g) + 3 H2(g) → 2 NH3(g)

A.

11.2

B.

44.8

C.

22.4

D.

5.60

E.

3731.38

Answer:

The process to use this knowledge is explained as below:

Explanation:

1. Farmer should use an indicator to check the pH value of the soil of the field of the farm.

2. If the field or the farm has alkali soil add acid to reduce the pH value.

3. If the soil of the farm is acidic for the crop add alkali to increase the pH value.

4. It will be a neutralization reaction and changes the pH value of the farm.

5. Weather/leeching into the surrounding soil/plant or animal waste will lead to a change in pH value over time.

6. The pH value will need to be regularly monitored and adjusted.

The correct stoichiometric ratio indicates the mole-to-mole ratio between nitrogen and hydrogen in the reaction.

To determine the amount of hydrogen that represents the correct stoichiometric ratio with 2.0 moles of nitrogen, we need to refer to the balanced chemical equation for the reaction between nitrogen and hydrogen.

Let's assume the balanced equation is:

N₂ + xH₂ → NH₃

In this equation, the coefficient 'x' represents the stoichiometric ratio between nitrogen and hydrogen. It indicates the number of moles of hydrogen required to react with one mole of nitrogen.

If 2.0 moles of nitrogen are available, we can use the stoichiometric ratio to calculate the corresponding amount of hydrogen. Since the stoichiometric ratio is not provided, we cannot provide an exact numerical answer. However, if the stoichiometric ratio is 3:1 (as is the case in the balanced equation above), then 2.0 moles of nitrogen would require 6.0 moles of hydrogen.

It is essential to have the specific stoichiometric ratio from the balanced equation or additional information to determine the precise amount of hydrogen. Without this information, we can only explain the concept of stoichiometry and the need for the stoichiometric ratio in determining reactant amounts.

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Answer:

yes

Explanation:

because density is determined by an objects mass and volume

The concentration of the sodium carbonate solution is 0.559 mol/dm³ and the concentration of the sodium carbonate solution is 59.2 g/dm³.

a) The concentration of the sodium carbonate solution in mol/dm³ is 0.559 mol/dm³.

To calculate the concentration of the sodium carbonate solution, we can use the balanced equation and the stoichiometry of the reaction. From the balanced equation, we can see that 2 moles of nitric acid react with 1 mole of sodium carbonate.

First, we need to calculate the number of moles of nitric acid used. Given the volume and concentration of the nitric acid solution:

Moles of HNO₃ = Concentration x Volume = 0.500 mol/dm³ x 27.9 cm³ ÷ 1000 cm³/dm³ = 0.01395 mol

Since 2 moles of nitric acid react with 1 mole of sodium carbonate, the number of moles of sodium carbonate used is also 0.01395 mol.

Now, we can calculate the concentration of the sodium carbonate solution:

Concentration of Na₂CO₃ = Moles of Na₂CO₃ / Volume = 0.01395 mol / 25.0 cm³ ÷ 1000 cm³/dm³ = 0.559 mol/dm³

Therefore, the concentration of the sodium carbonate solution is 0.559 mol/dm³.

b) The concentration of the sodium carbonate solution in g/dm³ is 20.2 g/dm³.

To calculate the concentration in g/dm³, we need to convert the concentration from mol/dm³ to g/dm³ using the molar mass of sodium carbonate.

Molar mass of Na₂CO₃ = 2 x (22.99 g/mol) + 12.01 g/mol + 3 x (16.00 g/mol) = 105.99 g/mol

Concentration in g/dm³ = Concentration in mol/dm³ x Molar mass = 0.559 mol/dm³ x 105.99 g/mol = 59.24 g/dm³

Rounding to three significant figures, the concentration of the sodium carbonate solution in g/dm³ is 59.2 g/dm³.

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Answer:

A calculator has an endifiite shape because all of its atoms are touching each other

The first occasion a Rh-negative patient receives Rh-positive blood, a transfusion reaction does not happen also because Rh-negative patient has not had time to develop antibodies against by the Rh-positive blood.

Some patients can have negative reactions towards the plasma they obtain after a donation, even when the right blood type is used. Some of the symptoms under these circumstances include hives and itching. Like other allergic reactions, this can be managed with medications. However, a professional should be sought if the reaction gets worse.

An acute immune hemolytic event, a very hazardous but unusual occurrence, can occur when the immune system rejects the directly injected red blood cells. The attack causes the discharge of a substance that damages the kidneys.

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Precipitates are insoluble ionic solid products of a reaction, formed when certain cations and anions combine in an aqueous solution. The determining factors of the formation of a precipitate can vary.

Answer:

The atoms are pulled together by attractive forces and become more organized.

Explanation:

According to the gas laws, the temperature is the measure of the average kinetic energy of the atoms of a molecule. State of change is primary driven by energy gain or loss. When molecules absorb energy, they transit into a phase in which their atoms are more mobile and move about more freely, staying relatively from, one from the other. When there is loss of energy, the molecules change into a less mobile state in which their atoms  move with lesser energy, and stay relatively closer to each other than they were.

During a the process in which atoms lose energy, its atoms are pulled together by the attractive force, and become more organised, since they now possess less kinetic energy.

Answer:

The answer is D: The atoms are pulled together by attractive forces and become more organized.

Explanation:  I just took the test and I got the answer write.

I hope this is right for you guys too!

The slope of the curves at equilibrium can be used to show that the rates of the forward and reverse reactions are the same at equilibrium because the slope of the curves is equal in magnitude but opposite in sign.

Equilibrium is a state of balance in which all forces operating on a system are equal and opposite. It is a state of dynamic balance between opposing forces, with no tendency to move toward a particular direction. It is a state of rest or balance due to the equal action of opposing forces. In economics, equilibrium refers to a situation in which the market price is stable, with no tendency to change due to the forces of supply and demand.

This indicates that the rates of the forward and reverse reactions are equal and that the system is at equilibrium.
At constant temperature, the pressure inside the container remains the same because the reaction occurs at equilibrium and therefore, the rate of the forward reaction is equal to the rate of the reverse reaction. As a result, the pressure inside the container does not change as the reaction occurs.

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Answer: They are all true

Explanation:

Helium is a noble gas and non oder and such

The type of attraction that results from the formation of weak momentary dipoles is dispersion (van der Waals) forces. These forces occur between nonpolar molecules or atoms and arise due to the temporary shifting of electrons in one atom or molecule, which then induces a temporary shift in electrons in another atom or molecule.

A dipole moment measures the separation of electrical charges in a molecule or compound. It is defined as the product of the magnitude of the charge on each end of the polar bond and the distance between them.

A temporary dipole moment is created due to the shifting of electrons within a molecule or atom. Electrons are constantly moving and randomly distributed within an atom or molecule. At any given moment, the electrons may be more heavily concentrated on one side of the molecule or atom, creating a temporary dipole moment.

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True, in combustion analysis, the carbon and hydrogen contents of a substance are determined from the \(CO_{2}\) and \(H_{2}O\), respectively, which are collected in the absorbers.

The combustion process involves combusting the substance in excess oxygen, converting carbon to \(CO_{2}\) and hydrogen to \(H_{2}O\). The produced \(CO_{2}\) and \(H_{2}O\) are then collected in the absorbers, and their masses are used to calculate the amount of carbon and hydrogen present in the original substance. The increase in weight of the absorbers can then be used to calculate the carbon and hydrogen contents of the original substance based on stoichiometric relationships. This method is commonly used in elemental analysis to determine the carbon and hydrogen contents of organic compounds.

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The capacity of stationary phases used in high performance liquid chromatography (HPLC) to distinguish between polar column and nonpolar chemicals can be used to classify them.

Extremely polar chemicals, which are difficult to separate under reversed-phase conditions, can be retained and separated successfully using hypercarb columns. This application has shown that: Polar chemical retention is good in hypercarb columns. The techniques created on Hypercarb columns are solid.

(We define a bond to be polar if there is a difference between the electronegativity of the atoms in the bond that is more than 0.4. The bond is effectively nonpolar if the difference in electronegativity is smaller than 0.4.) The molecule is nonpolar if there are no polar bonds.

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Answer: The amount of heat absorbed is 141.004 kJ.

Explanation:

In order to calculate the amount of heat released while converting given amount of steam (gaseous state) to ice (solid state), few processes are involved:

(1): \(H_2O (s) (-25^oC, 248K) \rightleftharpoons H_2O(s) (0^oC,273K)\)

(2): \(H_2O (s) (0^oC, 273K) \rightleftharpoons H_2O(l) (0^oC,273K)\)  

(3): \(H_2O (l) (0^oC, 273K) \rightleftharpoons H_2O(l) (100^oC,373K)\)

(4): \(H_2O (l) (100^oC, 373K) \rightleftharpoons H_2O(g) (100^oC,373K)\)

Calculating the heat absorbed for the process having the same temperature:

\(q=m\times \Delta H_{(f , v)}\)       ......(i)

where,

q is the amount of heat absorbed, m is the mass of sample and \(\Delta H_{(f , v)}\) is the enthalpy of fusion or vaporization

Calculating the heat released for the process having different temperature:

\(q=m\times C_{s,l}\times (T_2-T_1)\)      ......(ii)

where,

\(C_{s,l}\) = specific heat of solid or liquid

\(T_2\text{ and }T_1\) are final and initial temperatures respectively

We are given:

\(m=46g\\C=2.108J/g^oC\\T_2=0^oC\\T_1=-25^oC\)

Putting values in equation (i), we get:

\(q_1=46g\times 2.108J/g^oC\times (0-(-25))\\\\q_1=2424.2J\)

We are given:

\(m=46g\\\Delta H_{fusion}=334J/g\)

Putting values in equation (i), we get:

\(q_2=46g\times 334J/g\\\\q_2=15364J\)

We are given:

\(m=46g\\C=4.186J/g^oC\\T_2=100^oC\\T_1=0^oC\)

Putting values in equation (i), we get:

\(q_3=46g\times 4.186J/g^oC\times (100-0)\\\\q_3=19255.6J\)

We are given:

\(m=46g\\\Delta H_{vap}=2260J/g\)

Putting values in equation (i), we get:

\(q_4=46g\times 2260J/g\\\\q_4=103960J\)

Calculating the total amount of heat released:

\(Q=q_1+q_2+q_3+q_4\)

\(Q=[(2424.2)+(15364)+(19255.6)+(103960)]\)

\(Q=141003.8J=141.004kJ\)                  (Conversion factor: 1 kJ = 1000J)

Hence, the amount of heat absorbed is 141.004 kJ.

Answer: Copper and Zinc --> Copper Sulphate is possible

Explanation:

These rules described by specific cases of an ideal gas law, which states PV = nRT. When temperature rises, molecules become more energised, and lose their attraction to one another, causing pressure to fall.

As long as the volume remains constant, the pressure of a given quantity of petrol is precisely proportional towards its absolute temperature (Amontons' law). Under constant pressure, the volume of the a given gas is proportional to its exact temperature.

Now, let's review PV = nRT, our ideal petrol law. In this equation, P denotes pressure in atmospheres, V denotes volume in litres, n denotes moles of particles, T denotes temperature in Kelvin, and R denotes the ideal gas constant.

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A pharmacy technician performs all the following duties except answering phones and data entry. Option (d) is the correct answer

Pharmacy technicians work with a pharmacist in order to ensure the safety and health of the patients. Their duties involve locating, dispensing , packing , and labelling a prescribed medication for the patient which is further reviewed by a pharmacist to check accuracy before dispensing it  to the patient. They also help the pharmacists with taks related to administration. Some of their major roles and responsibilities include: Packaging and labeling of the prescribed medications, Preparation of compounded medications by using sterile as well as non-sterile processes, Processing of insurance claims, Tracking inventory, Operating automated machines for  dispensing, Repackaging bulk medications , Dispensing of medication to the patients acccording to the prescription.

Therefore, option (d) is correct.

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The five isomeric C6H14 alkanes can be represented by their condensed formulas and bond-line formulas. The condensed formulas are C6H14, C6H14, C6H14, C6H14, and C6H14 for n-hexane, 2-methylpentane, 3-methylpentane, 2,2-dimethylbutane, and 2,3-dimethylbutane, respectively. The bond-line formulas visually represent the carbon atoms and their connections using lines, with hydrogen atoms omitted. The isomers differ in the arrangement of carbon atoms and the presence and position of methyl (CH3) groups, leading to unique structures and physical properties.

The five isomers of C6H14 alkanes are n-hexane, 2-methylpentane, 3-methylpentane, 2,2-dimethylbutane, and 2,3-dimethylbutane. The condensed formulas for these isomers are C6H14, C6H14, C6H14, C6H14, and C6H14, respectively. In the condensed formulas, the number of carbon (C) atoms is indicated by the subscript 6, and the number of hydrogen (H) atoms is indicated by the subscript 14.

The bond-line formulas provide a visual representation of the carbon atoms and their connections in the molecule. In the bond-line formulas, carbon atoms are represented by vertices, and the bonds between them are represented by lines. Hydrogen atoms are omitted for simplicity. The isomers can be distinguished by the arrangement of carbon atoms and the presence and position of methyl (CH3) groups.

n-Hexane is a straight-chain alkane with six carbon atoms in a row. 2-Methylpentane has a branch consisting of a methyl group (CH3) attached to the second carbon atom of the pentane chain. 3-Methylpentane has a methyl group attached to the third carbon atom of the pentane chain. 2,2-Dimethylbutane has two methyl groups attached to the second carbon atom of the butane chain. Finally, 2,3-Dimethylbutane has one methyl group attached to the second carbon atom and another methyl group attached to the third carbon atom of the butane chain.

These isomers exhibit different physical properties due to their distinct structures. The arrangement of carbon atoms and the branching of methyl groups influence factors such as boiling points, melting points, and solubility. Understanding the structural isomerism of alkanes is important in organic chemistry as it impacts their reactivity and behavior in various chemical reactions.

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\(PbI_2\) ,  \(PbCO_3\)  and PbS are the ones that are significantly more soluble in acidic solutions than in pure water. The correct answer is option D) \(PbI_2\), PbS, and \(PbCO_3\) .

A slightly soluble salt is a salt that does not dissolve easily in water. In general, it's said to have solubility less than 0.1 mol/L.\(PbI_2\), PbS, and\(PbCO_3\)are all slightly soluble in water. When these salts are exposed to an acidic solution, they become more soluble. This is due to the fact that the acid ionizes in the water, creating \(H^+\)ions, which react with the salt, breaking down the bond and forming soluble lead ions.

As a result, \(PbI_2\), PbS, and \(PbCO_3\) become more soluble in acidic solutions than in pure water. As a result, option D is the correct option.\(PbI_2\), PbS, and \(PbCO_3\)should be significantly more soluble in acidic solutions than in pure water.

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The Earth's surface is not covered with the same materials ; however, some areas share similar materials.Several drilling sites have been dug in various regions of the planet to analyze the Earth's surface.

Each drilling site is unique, with differing characteristics and results. Despite these differences, all of the drilling sites analyzed offer scientists a more in-depth knowledge of the Earth's surface.In essence, the scientific drilling sites each had different lithologies, stratigraphies, and geologies. Each site had different types of rocks, depths, and ages, which led to varying drilling conditions, depths, and equipment used. Different types of equipment were also used to reach the depths required, which was a significant difference in each drilling site.The scientific drilling sites also had different purposes. Scientists had specific goals they wanted to achieve at each location. For example, the scientific drilling site in the Iceland region was focused on analyzing a unique layer of igneous rocks. The primary objective was to investigate the formation of the rock layer.The same materials were not found at each scientific drilling site.

Still, they had some similarities. They all provided geologists with vital information about the Earth's surface. The data provided from each drilling site was used to piece together the Earth's geologic history and how it has changed over time.

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Based on the balanced equation, if we have 0.08 moles of Iron (Fe), we can conclude that 0.08 moles of Hydrogen (H₂) will be formed as well.

First we need to balance the chemical equation for the reaction involving Iron (Fe) and Hydrogen (H).

The reaction will be between Fe and HCl (hydrochloric acid) to produce hydrogen gas (H₂) and iron chloride (FeCl₂):

Fe + 2HCl → FeCl₂ + H₂

From the balanced equation, we can see that for every 1 mole of Fe reacted, 1 mole of H₂ is formed. Therefore, if we have 0.08 moles of Fe, we can conclude that 0.08 moles of H₂ will be formed as well.

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Answer:

CO2

Explanation:

Answer:

Converting between matter

Explanation:

Chemical reactions can be the decomposition or synthesis of matter.