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Answer:

Option C is correct = ₈₅At²²⁰

Explanation:

Given radioactive decay shows the beta emission.

²²⁰₈₄Po    ₈₅At²²⁰  +  ⁰₋₁e ⁻

Beta radiations are result from the beta decay in which electron is ejected. The neutron inside of the nucleus converted into the proton an thus emit the electron which is called β particle.

Properties of beta radiations:

1) They can travel in air in few meter distance.

2) These radiations can penetrate into the human skin.

3) The mass of beta particle is smaller than the alpha particles.

4) The sheet of aluminium is used to block the beta radiation

¹⁴₆C → ¹⁴₇N + ⁰₋₁e ⁻

The beta radiations are emitted in this reaction. The one electron is ejected and neutron is converted into proton.

Answer:

i think it will be the first one

Explanation:

Answer:

A. the muscles in her leg relax and contract to move the bones (is the answer)

Explanation:

The only significant factors in determining the boiling points, in dispersion forces are Cl2, Ne, CCl4. Correct answer: letter A.

This is because these molecules do not form any significant intermolecular forces, such as hydrogen bonding or dipole-dipole interactions, so dispersion forces are the only significant factors in their boiling points.

Dispersion forces also known as London forces, are the weakest type of intermolecular forces. They are the forces of attraction between molecules due to the temporary, instantaneous dipoles that form as an electron in one atom is attracted to the nucleus of another atom.

These instantaneous dipoles induce dipoles in adjacent molecules, leading to attraction. Dispersion forces are responsible for the cohesion of nonpolar substances such as noble gases and hydrocarbons.

In which of the following groups of substances would dispersion forces be the only significant factors in determining boiling points?

I. Cl2

II. HF

III. Ne

IV. KNO2

V. CCl4

Group of options:

A. I, III, V

B. I, II, III

C. II, IV

D. III, IV, V

E. II, V

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Answer:

Na₂SO₄•(H₂O)₆.

Explanation:

The mass that is lost when the sample is heated is water.

Let's assume we have 100 g of the hydrate:

43 grams would be water (H₂O), while the rest (100-43=57) would be sodium sulfate anhydrous (Na₂SO₄).

We convert both those masses to moles, using their respective molar masses:

We can write those results as (Na₂SO₄)₀.₄₀•(H₂O)₂.₃₉. Now we just need to multiply those numbers so that they become integers.

If we multiply both coefficients by 5 we're left with (Na₂SO₄)₂•(H₂O)₁₂.

Simplify and thus the final answer is Na₂SO₄•(H₂O)₆.

Answer:

3.1g/mL

Explanation:

density = mass/volume

= 43.3/ 13.8

= 3.1g/mL

Answer:

68.4 liters

Explanation:

PV = nR T       R = gas constant = .082057  L atm / K-mole

                        n = 10      T = 27C = 300.15 K

3.6 V = 10 * .082057 * 300.15      solve for V = 68.4 liters

Answer:

B, adding an indicator to a solution to test its acidity

Explanation:

Answer:

B - Adding an indicator to a solution to test its acidity

Explanation:

Took the test

The term molefraction is an important method which is used to calculate the concentration of a solution. It is mainly employed to calculate the concentration of a binary solution. Here the molefraction is 1 / 5. The correct option are D, D and B.

Molefraction of any component of a solution is defined as the ratio of the number of moles of that component to the total number of moles of the solution. The sum of molefraction of solute and solvent is one.

Here the molefraction of nitrogen = Moles of nitrogen / Total number of moles

1. 'x' of 'N' = 2 / 5 + 3 + 2 = 0.2 or 1 / 5

2. Molefraction of Argon = 0.60 / 0.40 + 0.04 + 0.60 = 0.57

Partial pressure = Molefraction × Total pressure

0.57 × 6.3 = 3.59 atm

3. 20 cm³ mixture contains:

20 × 1 mole / 22400 m³ = 8.9286 × 10⁻⁴

1 mole occupies 22400 cm³

8.9286 × 10⁻⁴ × 22400 cm³ / 1 mole = 20 cm³

Thus the correct option are D, D and B.

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Answer:

C- THE LENGTH OF TIME REQUIRED FOR HALF OF A SAMPLE OF RADIOACTIVE MATERIAL TO DECAY

Answer:

molar mass of methane CH4

= C + 4 H  

= 12.0 + 4 x 1.008

= 12.0 +  4.032

= 16.042g/mol

7.31 x 10^25 molecules x             1 mole  CH4      = 121.43 moles

                                      6.02 x 10^23 CH4 molecules

121.43 moles CH4 are present.

Explanation:

not to certain if this is right or not.. but hope it helps!

Answer:

Transitional element are those elements which partially fill D and F subsells.

Answer:

an element having a d subshell that is partially filled with electrons, or an element that has the ability to form stable cations with an incompletely filled d orbital

Answer:

Other species will slowly die, because the species that eat snails and crayfish will not have anything to eat, then the thing that eats them will not have anything. This process will go on and on. So long story short populations will decrease, then off.

As per the given data, 1.6 grams of oxygen reacted in this experiment.

To calculate the amount of oxygen that reacted in the experiment, we need to determine the difference in the mass of X oxide (X,O) formed and the mass of X initially used.

Given:

Mass of X = 4.6 g

Mass of X oxide (X,O) = 6.2 g

To find the amount of oxygen that reacted:

Mass of oxygen = Mass of X oxide - Mass of X

= 6.2 g - 4.6 g

= 1.6 g

Therefore, 1.6 grams of oxygen reacted in this experiment.

Calculate the mass of 1 mole of X:

Given that the mass of X is 4.6 g, we can calculate the molar mass of X by dividing the mass by the number of moles:

Molar mass of X = Mass of X / Number of moles of X

Molar mass of X = 4.6 g / 0.1 mol

Molar mass of X = 46 g/mol

Therefore, the mass of 1 mole of X is 46 grams.

Thus, the answer is 46 grams.

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There are 576 different ways to choose a meal.

Promotional offers. A promotional offer is a specific proposition to clients that specifies a reward and patron behavioral standards for earning a reward. the recognition and trouble of the praise are captured thru a retail transaction, purchaser order, rebate claim, rebate redemption, or different patron interplay. a discount is a difference between the unique charge and the lower charge it's far being bought at. a proposal is a deal wherein a product is normally bought at a reduction.

Calculation:-

There are 8 appetizers, 12 entrees, and 6 desserts.

Number of choices =  8 × 12 × 6

                                =  576

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Answer:A

Explanation:

A.BREATHING THE PROCESS IN AIR IS EXCHANGED IN THE LUNGS

B.THE ACT SOWING SEEDS EVENLY

C.ITS WHEN NON DOMESTICATED ANIMALS

ARE EXTRACTED FROM THERE HABITATS

D.ITS A CELL THAT GIVES BLOOD IT'S RED

COLOUR

Answer:

metal cann't pass non metal can  pass through electicity

Explanation:

Q = Ksp = 1 × 10^(-12).

Substituting the values into the Nernst equation, we have:

0.799 V = E° - (RT/2F) * ln(1 × 10^(-12))

Now, solving for E°:

E° = 0.799 V + (RT/2F) * ln(1 × 10^(-12))

The value of R is the ideal gas constant, T is the temperature in Kelvin, and F is the Faraday constant.

To find the standard reduction potential at 25°C for the half-reaction Ag2CrO4(s) + 2e¯ → 2Ag(s) + CrO4²-(aq), we can use the Nernst equation, which relates the standard reduction potential (E°) to the equilibrium constant (K) and the reaction quotient (Q).

The Nernst equation is given as follows:

E = E° - (RT/nF) * ln(Q)

Given information:

Ksp = 1 × 10^(-12)

E = +0.799 V (standard reduction potential of Ag+ to Ag)

Since the reaction involves the dissolution of Ag2CrO4(s), the reaction quotient Q can be expressed as [Ag+]²/[CrO4²-].

Since the stoichiometry of the reaction is 2:1 for Ag2CrO4 to Ag+, we can say that [Ag+]² = Ksp.

Therefore, Q = Ksp = 1 × 10^(-12).

Substituting the values into the Nernst equation, we have:

0.799 V = E° - (RT/2F) * ln(1 × 10^(-12))

Now, solving for E°:

E° = 0.799 V + (RT/2F) * ln(1 × 10^(-12))

The value of R is the ideal gas constant, T is the temperature in Kelvin, and F is the Faraday constant.

Please note that without specific values for temperature (T) and the ideal gas constant (R), the exact standard reduction potential at 25°C cannot be determined.

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The percent composition of CuBr₂ is approximately 28.46% of Cu and 71.54% of Br.

To determine the percent composition of CuBr₂ (copper(II) bromide), we need to calculate the mass of each element in the compound and then divide it by the molar mass of the entire compound.

The molar mass of CuBr₂ can be calculated by adding up the atomic masses of copper (Cu) and bromine (Br) in the compound. The atomic masses of Cu and Br are approximately 63.55 g/mol and 79.90 g/mol, respectively.

Molar mass of CuBr₂ = (63.55 g/mol) + 2(79.90 g/mol) = 223.35 g/mol

Now, let's calculate the percent composition of each element in CuBr₂:

Percent composition of copper (Cu):

Mass of Cu = (63.55 g/mol) / 223.35 g/mol × 100% ≈ 28.46%

Percent composition of bromine (Br):

Mass of Br = 2(79.90 g/mol) / 223.35 g/mol × 100% ≈ 71.54%

Therefore, the percent composition of CuBr₂ is approximately:

- Copper (Cu): 28.46%

- Bromine (Br): 71.54%

These values represent the relative mass percentages of copper and bromine in the compound CuBr₂.

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Answer:

0.138 moles of oxygen are needed to combine with 0.276 moles of carbon.

Explanation:

Given data:

Moles of oxygen needed = ?

Moles of carbon present = 0.276 mol

Solution:

Chemical equation:

2C  + O₂      →        2CO

Now we will compare the moles of carbon with oxygen.

              C            :          O₂  

              2            :            1

             0.276     :        1/2×0.276  = 0.138 mol

Thus, 0.138 moles of oxygen are needed to combine with 0.276 moles of carbon.

Answer:

A full.

Explanation:

An electron needs to have a full octet do not need any more electrons. So the correct option is D.

The s and p electrons in the outermost shell are valence electrons. Core electrons are those found in the inner shell. Valence electrons are little subatomic particles that we come across as we examine and investigate an element's atom. We can trace the valence electrons and forecast the sorts of bonds with the aid of Lewis structures.

The majority of valence electrons are negatively charged particles, and they are all grouped in various orbitals or shells. Additionally, these electrons are in charge of how atoms interact with one another and create chemical bonds.

However, not every electron belongs to an atom. A chemical bond or molecule can only be created by the electrons that are found in the outermost shell. Valence electrons are the name given to this sort of electron.

Therefore the correct option is D.

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Answer:

A heterotroph is an organism that eats other plants or animals for energy and nutrients. The term stems from the Greek words hetero for “other” and trophe for “nourishment.”

When carbonate sediments are subjected to thermal or regional metamorphism, the CO2 cannot often escape and the carbonate minerals simply recrystallize; calcite and dolomite commonly form marble. Carbonate minerals can therefore be common in some metamorphic rocks.

Exactly 149.6J will raise the temperature of 10.0g of a metal from 25.0C. The specific heat capacity of the metal is 5.984 J/g°C.

The heat capacity of a sample of a substance divided by the mass of the sample yields the specific heat capacity (symbol c), also known as massic heat capacity. Informally, it is the quantity of heat that must be added to one unit of a substance's mass in order to raise its temperature by one unit. The specific heat capacity unit in the SI is the joule per kelvin per kilogram, or Jkg⁻¹K⁻¹. For instance, the specific heat capacity of water is 4184 J kg⁻¹K⁻¹, or the amount of energy needed to raise 1 kilogram of water by 1 K.

The specific heat capacity of the metal can be calculated using the equation Q = m × c ×ΔT.

Q = 149.6J

m = 10.0g

ΔT = (final Temperature - initial Temperature) = (25°C - 0°C) = 25°C

Plugging these values into the equation, we get:

149.6J = 10.0g × c ×25°C

Solving for c, we get:

c =  \(\frac{149.6J}{(10.0g *25C)}\)

c = 5.984 J/g°C

Therefore, the specific heat capacity of the metal is 5.984 J/g°C.

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