Hello, let me know if you can see this.

Answers

Answer 1

There is no correlation whatsoever

Related Questions

Draw a sketch of f(x)=x^2-5. Plot the point for the vertex, and label the coordinates as maximum or minimum, draw and write the equation for the axis of symmetryIn one sentence, describe the transformation of f(x)=x^2 you drew

Answers

Vertex: (0 ,-5) it is a minimun.

Axis of symmetry: x = 0

transformation of f(x) = x^2: translation 5 units down.

of the 8 friends sitting around the table at lunch, 6 brought their lunch from home. Which
grid represents the percent of the friends who brought their lunch from home?

Answers

You didn't provide any grid, but I can tell you how to turn fractions into percentages: just build the following proportion

$6\div 8=x\div 100$

and solve for $x$:

$x=\dfrac{600}{8}=75$

So, 75% of the friends brought their lunch from home.

A convex lens with focal length f centimeters will project the image of an object on a
point behind the lens. If an object is placed a distance of p centimeters from the lens,
then the distance q centimeters of the image from the lens is related to p and f by the
lens equation: 1/p+1/q=1/f
A. If the focal length of the convex lens is supposed to be 5 cm, and if the image is
formed 7 cm from the lens, find the distance from the lens to the object, p. (It’s not necessary to simplify your answer.)

B. Find an expression that gives q as a function of p, assuming that the focal length is a constant of 5 centimeters.

C. Sketch a graph of q as a function of p (i.e., q(p)), assuming that the focal length is a
constant of 5 centimeters. Show any important features of the graph.

D. Find limq(p) as p approaches infinity and limq(p) as p approaches 5from the positive side. What do these limits represent physically? What must
happen to the distance of the image and the object?

Answers

Answer:

A. Using the lens equation, 1/p + 1/q = 1/f, and substituting f = 5 cm and q = 7 cm, we can solve for p:

1/p + 1/7 = 1/5

Multiplying both sides by 35p, we get:

35 + 5p = 7p

Simplifying and rearranging, we get:

2p = 35

Therefore, the distance from the lens to the object, p, is:

p = 35/2 cm

B. Solving the lens equation, 1/p + 1/q = 1/f, for q, we get:

1/q = 1/f - 1/p

Substituting f = 5 cm, we get:

1/q = 1/5 - 1/p

Multiplying both sides by 5qp, we get:

5p = qp - 5q

Simplifying and rearranging, we get:

q = 5p / (p - 5)

Therefore, the expression that gives q as a function of p is:

q = 5p / (p - 5)

C. Here is a sketch of the graph of q(p):

The graph is a hyperbola with vertical asymptote at p = 5 and horizontal asymptote at q = 5. The image distance q is positive for object distances p greater than 5, which corresponds to a real image. The image distance q is negative for object distances p less than 5, which corresponds to a virtual image.

D. Taking the limit of q as p approaches infinity, we get:

lim q(p) = 5

This represents the horizontal asymptote of the graph. As the object distance becomes very large, the image distance approaches the focal length of the lens, which is 5 cm.

Taking the limit of q as p approaches 5 from the positive side, we get:

lim q(p) = -infinity

This represents the vertical asymptote of the graph. As the object distance approaches the focal length of the lens, the image distance becomes infinitely large, indicating that the lens is no longer able to form a real image.

In order for the lens to form a real image, the object distance p must be greater than the focal length f. When the object distance is less than the focal length, the lens forms a virtual image.

Find the quotient and express the answer in scientific notation. 302 ÷ (9.1 x 10^4 )

Answers

The quotient of 302 ÷ (9.1 x $10^4)$ in scientific notation is approximately 3.31868131868 x $10^1$

How to find the quotient

Dividing 302 by 9.1 gives:

302 ÷ 9.1 ≈ 33.1868131868

Now, to express this result in scientific notation, we need to move the decimal point to the appropriate position to create a number between 1 and 10. In this case, we move the decimal point two places to the left:

33.1868131868 ≈ 3.31868131868 x$10^1$

Therefore, the quotient of 302 ÷ (9.1 x $10^4$) in scientific notation is approximately 3.31868131868 x$10^1$

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3 a plus b equals 54, when b equals 9?

Answers

Answer:

3a+b= 54

3a+9=54

3a=54-9

3a=45

a=45/3

a= 15

Answer:

Step-by-step explanation:

3 a + b = 54

Given that b=9

We substitute b as 9 into the equation; 3 a + 9 = 54

3 a = 54 - 9

3 a = 45

Then, divide each side by 3 to get the value of a; 3 a /3 = 45 / 3

a = 45 / 3

a = 15

Find the slope between (-3,5) and (2,15).

Answers

Answer:

Step-by-step explanation:

use the formula for slope y2-y1 / x2-x1

(-3,5) (2,15)

15-5 / 2-(-3)

we know 15-5=10 and 2-(-3)=5

10/5 = 2

Answer:

Step-by-step explanation:

Slope is:

$\frac{rise}{run}= \frac{change.in.y}{change.in.x}$

("." in second fraction as it has multiply words)

We can plug our numbers in, and solve to find the slope:

- Coordinates are (x, y) -

$\frac{change.in.y}{change.in.x}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} = \frac{15-5}{2--3}= \frac{15-5}{2+3}=\frac{10}{5} =2$

So our slope is 2.

Hope this helps, have a nice day! :D

convert the decimal 0.085to a percent

Answers

Answer:

8.5%

Step-by-step explanation:

Answer:

8.5%

Step-by-step explanation:

0.085

1: Ignore the 0 and take the numbers that is 85

2: Add a percent

3: Answer is 8.5%

Hope this helps.

How to do a T-test step by step

Answers

1. Carry out the summation of the scores of both groups.
2.Calculate the mean of the scores of both groups.
3.Square each of the scores of the subjects of both groups (Group 12 and Group 22).
4.Based on the squared scores, make the sum of the scores of both groups (Group 12 and Group 22).
5.Then the equation of the Sum of Squares must be applied see formula
For this formula, use the SUMMARY OF THE SQUARE SCORES and the SUMMARY OF THE SIMPLE SCORES.
The procedure is carried out first with Group 1 and then with Group 2.
6.After obtaining the results of the SUMMARY OF THE SCORES TO THE SQUARE OF GROUP 1 and GROUP 2, we proceed to apply equation 1.
7.Finally, formula 3 is applied in this way, the elements are complete to identify the associated probability of the hypothesis contrast.
8. Then we are located in the table t, with the degrees of freedom and the value of t, with these two data we can locate what is the associated probability for the value of t obtained, and compare with the alpha of 0.05 (See SPSS Comparison ). Although it is also possible to compare the value of t obtained with the value of critical t, which appears in the table based on the alpha used in Psychology, which is 0.05 of this if the value of t obtained> critical t, is rejects the null hypothesis and if the value of t obtained

3 + 51 x 1/10 + 9 x 1/100

Answers

Answer:

5.49

Step-by-step explanation:

3+ 51= 54

54 x 1/10= 5.4 + 9 x 1/100

5.4 + 0.09=

5.49

Please help me solve this.

Answers

$\boxed{A}\\\\ U=5(2n+22)+2\left( n+\cfrac{3}{2} \right) \\\\\\ U=10n+110+2n+3 \implies U=12n+113 \\\\[-0.35em] ~\dotfill\\\\ \boxed{B}\hspace{5em}\textit{in 2009, that's 9 years after 2000, n = 9}\\\\ U(9)=12(9)+113\implies U(9)=221 ~~ millions$

A trucker wanted to track how long it took to reach Bismarck. When she started out, her clock
read 7:00AM. When she refueled, the clock read 8:00AM. After reaching Bismarck, the clock read
10:00AM. How many hours did it take this trucker to reach Bismarck?

Answers

Answer:

Below

Step-by-step explanation:

From 7 to 10 AM is THREE hours (if the times are all on the same day)

At a baseball game a vendor sold a combined total of 136 sodas and hotdogs. the number of soda sold was three times the number of the hotdogs sold. find the number of sodas in the number of hotdogs sold

Answers

Answer:

Step-by-step explanation:

Let's call the number of hotdogs sold "x". According to the problem, the number of sodas sold is three times the number of hotdogs sold, or 3x.

We know that the total number of sodas and hotdogs sold is 136. So we can set up an equation:

x + 3x = 136

Simplifying this equation, we get:

4x = 136

Dividing both sides by 4, we get:

x = 34

This means that 34 hotdogs were sold. To find the number of sodas sold, we can multiply the number of hotdogs sold by 3:

3x = 3(34) = 102

So, 102 sodas were sold.

Help!!!!!! I'll give you brainliest!!!

Answers

I would say

Balanced forces result in constant velocity: phase 3

Unbalanced force causes change in velocity: phase 4

The more unbalanced the forces are, the greater the changes in velocity is: phase 5

Hope this helps

What is the meaning of "$ \varphi (x,y)$ be $ y\wedge \phi (x)$ "?

$What is the meaning of "[tex] \varphi (x,y)[/tex] be [tex] y\wedge \phi (x)[/tex] "?$

Answers

The given passage provides a proof that the Separation Axioms follow from the Replacement Schema.

The proof involves introducing a set F and showing that {a: e X : O(x)} is equal to F (X) for every X. Therefore, the conclusion is that the Separation Axioms can be derived from the Replacement Schema.In the given passage, the author presents a proof that demonstrates a relationship between the Separation Axioms and the Replacement Schema.

The proof involves the introduction of a set F and establishes that the set {a: e X : O(x)} is equivalent to F (X) for any given set X. This implies that the conditions of the Separation Axioms can be satisfied by applying the Replacement Schema. Essentially, the author is showing that the Replacement Schema can be used to derive or prove the Separation Axioms. By providing this proof, the passage establishes a connection between these two concepts in set theory.

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6÷2+3×100000000000000000000000000000000000000000

Answers

Answer:

3E41

Step-by-step explanation:

hope it helps

Answer:

3e+40

Step-by-step explanation:

pls give me brainliest

Explain why, when you roll a normal dice, the probability of getting a 2 1/6?
.

Answers

Explanation/Answer:
You have a 1/6 chance of rolling a 2 because there are 6 sides on the dice.

7x+3 find x. I am confused I need help………………….

Answers

Dose it have what 7x + 3 is equal to
As this is incomplete

Is there more to this, I can’t really help you with this information

Asmaa is shopping for an infant car seat. She has a coupon for 20% off any purchase over $35
at a baby supply store in Manhattan. On a tax-free weekend, she finds a car seat priced at $130.
How much money does Asmaa's coupon save her?

Answers

Answer:

just find the persentage on a tax, then minus the orignal price.

Step-by-step explanation:

Answer:

$26

Step-by-step explanation:

thats 20% of 130

Before Valentine's Day, a store bought 58 boxes of chocolates. There were 65 chocolates in each box. How many chocolates did the store buy? chocolates

Answers

Answer:

The equation would be:

58 times 65

The answer:

3,770

Step-by-step explanation:

A company can produce 60 million chocolate candies within a 24-hour period.

Part A

Using this rate, create an equation to represent the number of chocolate candies,
c
, in millions, the company can produce in
h
hours.

Answers

Answer:

f(x)=60c * 24h

Step-by-step explanation:

Hope this helped!

A health club charges a one-time sign-up fee and a monthly membership fee. The
equation y = 28x + 50 represents what the health club charges. Find the rate of
change.

Answers

Answer:

The rate of change is 28.

Step-by-step explanation:

The equation is in slope-intercept form, y = mx + b, where m is the slope, and b is the y-intercept.

5.
Learning Task 4: Solve the following word problems.
1. Mr. Pablo bought a residential lot. The lot is in the shape of a trapezoid as shown in the illustration. What is the area of
the lot
12 m
10 m
20 m
2. Maria Ailyn bought a lot in a parallelogram shape. Its base is 24 meters and its height is 16 meters. What is the area of
ota

Answers

Answer:

160 m²

384 m²

Step-by-step explanation:

The area of a trapezium is given by :

A = 1/2(a + b)h

h = height ; a and b = lengths

From the diagram :

A = 1/2(12 + 20)10

A = 1/2(32)10

A = 16 * 10

A = 160 m²

2.)

Area of parallelogram = base * height

Base = 24 ; h = 16

A = 24 * 16

A = 384 m²

6. Journalise the following transactions
1. Bricks for Rs 60,000 and timber for Rs 35,000 purchased for
the construction of building. The payment was made by cheque.
2. Placed in fixed deposit account at bank by transfer from current
account Rs 13,000.
3. Appointed Mr. S.N. Rao as Accountant at Rs 300 p.m. and
Received Rs 1000 as security Deposit at 5% p.a. interest.
4. Sold goods to shruti for Rs 80,000 at 15% trade discount and
4% cash discount. Received 75% amount immediately through a
cheque.
5. Purchased goods from Richa for Rs 60,000 at 10% trade
discount and 5% cash discount. 60% amount paid by cheque
immediately.
6.
On 18th jan,Sold goods to shilpa at the list price of Rs 50,000
20% trade discount and 4% cash discount if the payment is made
within 7 days. 75% payment is received by cheque on Jan 23rd.
7. On 25th jan, sold goods to garima for Rs 1,00,000 allowed her
20% trade discount and 5% cash discount if the payment is made
within 15 days. She paid 1/4th of the amount by cheque on Feb 5th
and 60% of the remainder on 15th in cash.
8. Purchased land for Rs 2,00,000 and paid 1% as brokerage and
Rs 15,000 as registration charges on it. Entire payment is made by
cheque.
9. Goods worth Rs 25,000 and cash Rs 40,000 were taken away
by the proprietor for his personal use.
10. Sold goods costing Rs 1,20,000 to charu at a profit of 33% 3 %
on cost less 15% trade discount.
9
11. Paid rent of building Rs 60,000 by cheque. Half the building is
used by the proprietor for residential purpose.
12. Sold goods costing Rs 20,000 to sunil at a profit of 20% on
sales less 20% trade discount .
13. Purchased goods for Rs 1000 from nanda and supplied it to
helen for Rs 1300. Helen returned goods worth Rs 390, which in
turn were returned to nanda.
14. Received invoice at 10% trade discount from rohit and sons
and supplied these goods to madan, listed at Rs 3000.

Answers

1.Bricks and timber purchased for construction. (Debit: Bricks - Rs 60,000, Debit: Timber - Rs 35,000, Credit: Bank - Rs 95,000)

2.Transfer of Rs 13,000 to fixed deposit account. (Debit: Fixed Deposit - Rs 13,000, Credit: Current Account - Rs 13,000)

3.Appointment of Mr. S.N. Rao as Accountant. (Debit: Salary Expense - Rs 300, Debit: Security Deposit - Rs 1,000, Credit: Accountant - Rs 300)

4.Goods sold to Shruti with discounts. (Debit: Accounts Receivable - Shruti - Rs 80,000, Credit: Sales - Rs 80,000)

5.Goods purchased from Richa with discounts. (Debit: Purchases - Rs 60,000, Credit: Accounts Payable - Richa - Rs 60,000)

6.Goods sold to Shilpa with discounts and received payment. (Debit: Accounts Receivable - Shilpa - Rs 50,000, Credit: Sales - Rs 50,000)

7.Goods sold to Garima with discounts and received partial payment. (Debit: Accounts Receivable - Garima - Rs 1,00,000, Credit: Sales - Rs 1,00,000)

8.Purchase of land with additional charges. (Debit: Land - Rs 2,00,000, Debit: Brokerage Expense - Rs 2,000, Debit: Registration Charges - Rs 15,000, Credit: Bank - Rs 2,17,000)

9.Proprietor took goods and cash for personal use. (Debit: Proprietor's Drawings - Rs 65,000, Credit: Goods - Rs 25,000, Credit: Cash - Rs 40,000)

10.Goods sold to Charu with profit and discount. (Debit: Accounts Receivable - Charu - Rs 1,20,000, Credit: Sales - Rs 1,20,000)

11.Rent paid for the building. (Debit: Rent Expense - Rs 60,000, Credit: Bank - Rs 60,000)

12.Goods sold to Sunil with profit and discount. (Debit: Accounts Receivable - Sunil - Rs 24,000, Credit: Sales - Rs 24,000)

13.Purchased goods from Nanda and supplied to Helen. (Debit: Purchases - Rs 1,000, Debit: Accounts Payable - Nanda - Rs 1,000, Credit: Accounts Receivable - Helen - Rs 1,300, Credit: Sales - Rs 1,300)

14.Purchased goods from Rohit and Sons and supplied to Madan. (Debit: Purchases - Rs 2,700, Credit: Accounts Payable - Rohit and Sons - Rs 2,700, Debit: Accounts Receivable - Madan - Rs 3,000, Credit: Sales - Rs 3,000)

Here are the journal entries for the given transactions:

1. Bricks and timber purchased for construction:

Debit: Bricks (Asset) - Rs 60,000

Debit: Timber (Asset) - Rs 35,000

Credit: Bank (Liability) - Rs 95,000

2. Transfer to fixed deposit account:

Debit: Fixed Deposit (Asset) - Rs 13,000

Credit: Current Account (Asset) - Rs 13,000

3. Appointment of Mr. S.N. Rao as Accountant:

Debit: Salary Expense (Expense) - Rs 300

Debit: Security Deposit (Asset) - Rs 1,000

Credit: Accountant (Liability) - Rs 300

4. Goods sold to Shruti:

Debit: Accounts Receivable - Shruti (Asset) - Rs 80,000

Credit: Sales (Income) - Rs 80,000

5. Goods purchased from Richa:

Debit: Purchases (Expense) - Rs 60,000

Credit: Accounts Payable - Richa (Liability) - Rs 60,000

6. Goods sold to Shilpa:

Debit: Accounts Receivable - Shilpa (Asset) - Rs 50,000

Credit: Sales (Income) - Rs 50,000

7. Goods sold to Garima:

Debit: Accounts Receivable - Garima (Asset) - Rs 1,00,000

Credit: Sales (Income) - Rs 1,00,000

8.Purchase of land:

Debit: Land (Asset) - Rs 2,00,000

Debit: Brokerage Expense (Expense) - Rs 2,000

Debit: Registration Charges (Expense) - Rs 15,000

Credit: Bank (Liability) - Rs 2,17,000

9. Goods and cash taken away by proprietor:

Debit: Proprietor's Drawings (Equity) - Rs 65,000

Credit: Goods (Asset) - Rs 25,000

Credit: Cash (Asset) - Rs 40,000

10. Goods sold to Charu:

Debit: Accounts Receivable - Charu (Asset) - Rs 1,20,000

Credit: Sales (Income) - Rs 1,20,000

Credit: Cost of Goods Sold (Expense) - Rs 80,000

Credit: Profit on Sales (Income) - Rs 40,000

11. Rent paid for the building:

Debit: Rent Expense (Expense) - Rs 60,000

Credit: Bank (Liability) - Rs 60,000

12. Goods sold to Sunil:

Debit: Accounts Receivable - Sunil (Asset) - Rs 24,000

Credit: Sales (Income) - Rs 24,000

Credit: Cost of Goods Sold (Expense) - Rs 20,000

Credit: Profit on Sales (Income) - Rs 4,000

13. Goods purchased from Nanda and supplied to Helen:

Debit: Purchases (Expense) - Rs 1,000

Debit: Accounts Payable - Nanda (Liability) - Rs 1,000

Credit: Accounts Receivable - Helen (Asset) - Rs 1,300

Credit: Sales (Income) - Rs 1,300

14. Goods received from Rohit and Sons and supplied to Madan:

Debit: Purchases (Expense) - Rs 2,700 (after 10% trade discount)

Credit: Accounts Payable - Rohit and Sons (Liability) - Rs 2,700

Debit: Accounts Receivable - Madan (Asset) - Rs 3,000

Credit: Sales (Income) - Rs 3,000

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a health statistician wants to know if all pregnant women from three different counties have equal body fat composition. each county has 500 to 750 pregnant women at a given time. a random sample of n

Answers

The answer is 0.05 level, two tail test and n-2= 14 df, critical r=0.497

Given that,

If all pregnant women from three different counties have the same body fat composition, a health statistician is interested in knowing.

At any given time, there are 500–750 expectant mothers in each county. an sample size of n

Since absolute value of r is greater than critical value

There is a significant negative correlation between physical activiity and body fat.

When two variables are negatively correlated, it means that if one variable rises, the other tends to fall. Stronger links are represented by values near -1 or +1 than by values around zero. Spearman's and Pearson's Coefficients are contrasted.body fat.

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What is the cos A?Will give 15 points.

Answers

Answer:

Step-by-step explanation:

cos A = $\frac{\sqrt{8} }{3}$

I need help with slopes!

Answers

Answer:

the answer is 1/-4 rise over run my friend

Aaron wants to draw the development of a cylinder. Which method of development should he use?

A.
parallel line
B.
approximate
C.
triangulation
D.
radial line
E.
non-curved to non-curved triangulation

Answers

Answer:

The correct option is A. Parallel line.

Rumus suatu fungsi di nyatakan dengan f (x) = 2x + 5. Jika f(a) = 7, nilai a adalah

Answers

Step-by-step explanation:

As my previous answer got deleted for being wrong (in which it was right), I will answer again.

The answer is 1. Why? Just plug it into the equation. F(1) = 2(1) + 5 = 7.

This is proof that it is right, and that there are some corrupt admins on brainly.

How to get to this solution?

Well notice how we are given what f(a) is. It is 2a + 5. So plug this in for f(a).

If we do so, we get 2a + 5 = 7.

Solving this equation, we get a = 1.

Express the desired quantity as a definite integral and evaluate the integral using Theorem 2 .
Find the distance traveled by a train moving at 87 mph from 8:00 A.M. to 11:00 A.M.

Answers

Let t be the time elapsed in hours, starting at 8:00 A.M. So t = 0 at 8:00 A.M. and t = 3 at 11:00 A.M. The distance traveled by the train can be expressed as the definite integral of its velocity with respect to time:

distance = ∫(87 mph) dt from t = 0 to t = 3

Since mph is a unit of speed, we need to convert it to a unit of velocity (feet per second) in order to evaluate the integral:

87 mph = 87 miles/hour × 5280 feet/mile = 454840 feet/hour

distance = ∫(454840 ft/hr) dt from t = 0 to t = 3

distance = 454840 ft/hr * t from t = 0 to t = 3

distance = 454840 ft/hr * 3 hours

distance = 1364520 feet

So, the train travels a distance of 1364520 feet from 8:00 A.M. to 11:00 A.M.

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4)Does this shape belong in a group of shapes that have more than one pair of
perpendicular sides?
Use the drop-down menus to explain your answer.
4) Click the arrows to choose an answer from each menu.
The number of right angles in this shape is Choose....
meet at a right angle is Choose....
perpendicular sides in this shape. This shape
shapes that have more than one pair of perpendicular sides.
. Each pair of sides that
▾ of
in a group of
.There Choose...
Choose...

Answers

No, this shape does not belong in a group of shapes that have more than one pair of perpendicular sides.

Does the shape have > one pair of perpendicular sides?

In order to determine if the shape belongs to a group of shapes with more than one pair of perpendicular sides, we need to examine the number of right angles in the shape.

A right angle is a 90-degree angle, and shapes with perpendicular sides have right angles at their intersections. By counting the number of right angles in the shape, we can determine if it has more than one pair of perpendicular sides.

If the shape has only one right angle, then it does not have more than one pair of perpendicular sides. But if it has two or more right angles, then it would belong to the group of shapes that have more than one pair of perpendicular sides.