Hello! Please help me! I will give brainliest! An engineering company needs to solve a design problem.
It is designing a high-speed train to transport passengers
between Boston and Atlanta
Which statement is a constraint for this project?
A. The train must meet a strict set of safety guidelines.
B. The train must be able to operate during rainy weather.
C. The train must provide a smooth ride for passenger comfort.
D. The train design must be completed in 12 months

Answer:

\(1140\:\mathrm{J}\)

Explanation:

Work is given by \(W=F\Delta x\), where \(F\) is force and \(\Delta x\) is displacement.

Plugging in given values, we get:

\(W=95\:\mathrm{N}\cdot12\:\mathrm{m}=\fbox{$1140\:\mathrm{J}$}\).

The magnitude of Tom's acceleration is 0.585 m/s².

Acceleration is the rate of change of velocity with time.

The force applied by the Tom's sister is calculated by applying Newton's second law of motion as follows;

F = ma

F = 15 x 2.3

F = 34.5 N

The acceleration of Tom is calculated by applying Newton's third law of motion as follows;

\(F_{Tom} = -F_{little \ sister}\\\\F_{Tom} = - 34.5 \ N\)

\(a = \frac{F}{m} \\\\a = \frac{-34.5}{59} \\\\a = -0.585 \ m/s^2\\\\|a| = 0.585 \ m/s^2\)

Thus, the magnitude of Tom's acceleration is 0.585 m/s².

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Answer:

can you put on a clearer image this one is hard to see

The force required to pull the two hemispheres is 46622.72N

( Note: 1 millibar=100 N/m2. One atmosphere is 1013 millibar = 1.013×105 N/m2 ]

The contact area between the hemispheres is (pi x 0.400^2) = 0.5024m^2.

Pressure difference = (940 - 12)

= 928 millibars.

(928 x 100)

= 92,800N/m^2.

Therefore, the required force to pull the two hemispheres is

(92800 x 0.5024)

= 46622.72N.

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Explanation:

You want  N/m

 N = 66 * 9.81

 m = 2.3 x 10^-2 m

66* 9.81 / 2.3 x 10^-2  = 28150 =  28 000 N/m    to two S D

Plate boundaries represent the parts of the Earth's crust where plates come in contact with one another. There are three types of plate boundaries based on the movement and interaction of the plates involved. These are: Divergent Plate Boundaries, Convergent Plate Boundaries, and Transform Plate Boundaries.

Divergent Plate Boundaries
At divergent plate boundaries, two plates move away from each other as magma rises to the surface and creates new crustal material. Examples of divergent plate boundaries include the Mid-Atlantic Ridge, the East Pacific Rise, and the African Rift Valley.

Convergent Plate Boundaries
At convergent plate boundaries, two plates move toward each other and eventually collide. Depending on the type of plate involved, different types of interactions can occur. The three types of convergent plate boundaries are oceanic-continental, oceanic-oceanic, and continental-continental. An example of oceanic-continental convergence is the Pacific Northwest region of the United States. An example of oceanic-oceanic convergence is the Japanese Islands, and an example of continental-continental convergence is the Himalayas.

Transform Plate Boundaries
At transform plate boundaries, two plates move past each other in a horizontal direction. These boundaries are characterized by faults and earthquakes, such as the San Andreas Fault in California.

To create an illustration that represents each type of plate movement, you can draw a diagram that shows the direction of plate movement, the type of boundary, and any notable geological features associated with that type of boundary.

For example, a divergent plate boundary illustration could include a depiction of magma rising to the surface and creating new crustal material, while a transform plate boundary illustration could include a fault line and a depiction of the earthquakes that occur along that boundary.

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Answer:

Explanation:

Speed of electrical nerve signal = 33 m /s

Distance travelled = 1.3 m

time taken = distance / speed

= 1.3 / 33  

= .039 s

= 39 ms ( millisecond )  .

The work done in the spring is calculated to be 2.8 J

Hooke's law states that, the extension of a given material is directly proportional to the applied force as long as the elastic limit is not exceeded . First, we must bear in mind that the material must remain within the elastic limit for us to apply the Hooke's law in solving the problem.

Now;

From Hooke's law;

F = Ke

F = force applied

K = force constant

e = extension

F = W = mg =  2.50 - kg * 9.8 m/s^2 = 24.5 N

K = 24.5 N/ 2.76 * 10^-2

K = 888 N/m

e = F/K

F = W =  1.25 - kg * 9.8 m/s^2 = 12.25 N

e = 12.25 N/ 888 N/m = 0.014 m or 1.4 cm

Work done by an external agent = 1/2 Kx^2

= 0.5 * 888 * (8 * 10^-2)^2

= 2.8 J

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Determine the magnitude of B-A is 53.68

1.4

Magnitude is a term used to describe size or distance. We can relate the magnitude of the movement to the size and movement speed of the object. The magnitude of a thing or an amount is its size. A car moves at a faster pace than a motorcycle, just in terms of speed.

Magnitude is the relative size of an object (mathematics). The mathematical term for a vector's length or size is the norm. By using the symbol |v|, the magnitude of a vector formula can be utilized to determine the length of a given vector (let's say v). This amount is essentially the distance between the vector's beginning point and ending point.

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It is advisable that Jeff should begin to save about 5% of his income to serve as his retirement plan.

Retirement refers to such a time when one is no longer involved in actual work. It is important that a person ought to save up some money for use via a retirement plan.

It is advisable that Jeff should begin to save about 5% of his income to serve as his retirement plan since he still has many years of work ahead of him.

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Explanation:

We have,

Mass of a particle is 0.6 kg

Speed at A is 2 m/s

Kinetic energy at B is 7.5 J

(a) The kinetic energy at A is given by :

\(K_A=\dfrac{1}{2}mv^2\\\\K_A=\dfrac{1}{2}\times 0.6\times 2^2\\\\K_A=1.2\ J\)

(b) Kinetic energy at B is given by

\(K_B=\dfrac{1}{2}mV^2\\\\V=\sqrt{\dfrac{2K_B}{m}} \\\\V=\sqrt{\dfrac{2\times 7.5}{0.6}} \\\\V=5\ m/s\)

(c) The work done on the particle as it moves form A to B is given by work energy theorem as :

\(W=\dfrac{1}{2}m(V^2-v^2)\\\\W=\dfrac{1}{2}\times 0.6\times (5^2-2^2)\\\\W=6.3\ J\)

Answer:

40s

Explanation:

The current flowing over the 30 Ω resistor is 0.4 A.

To discover the current streaming over the 30 Ohm resistor, able to apply Ohm's Law, which states that the current (I) is break even with to the voltage (V) partitioned by the resistance (R). In this case, the voltage over the circuit is given as 9.0 V.

To calculate the full resistance of the circuit, we ought to consider the resistors in arrangement and parallel. The resistors with values of 40 Ω and 50 Ω are in serie.

Hence, the sum of their value (R_series )= 40 Ω + 50 Ω = 90 Ω. The 20 Ω and 10 Ω resistors are in parallel, hence, their resistance is represented as (1/R_parallel) = 1/20 Ω + 1/10 Ω = 1/10 Ω. Disentangling this expression gives R_parallel = 6.67 Ω.

Presently, ready to calculate the entire resistance of the circuit. The resistors with values of 30 Ω and 90 Ω (from the arrangement combination) are in parallel, so their identical resistance is given by 1/R_total = 1/30 Ω + 1/90 Ω = 1/22.5 Ω. Rearranging this expression gives R_total = 22.5 Ω.

At last, able to apply Ohm's Law to discover the current over the 30 Ω resistor. I = V / R_total = 9.0 V / 22.5 Ω ≈ 0.4 A.

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Answer:

Scientific thinking skills are very important for getting along in life. They allow you to analyse problems or situations you find yourself involved in that don't always have an easy or obvious answer. We all run into problems in relationships, at work, when learning new things, when seeking to advance our lives etc.

You must not be afraid to question authority, especially when they are wrong, you must think creatively, think out-of-the-box, overcome limits and most importantly accept criticism a part of life. These traits of a scientist will build a distinctive personality in an otherwise boring existence.

The accelaration of the edge of the rotor is linear acceleration.

Accelaration is the rate of the change of the velocity of an object with respect by time.

The electric motor is  spinning at a rate of 2695 Devolution Permanent. By two by over 60 is how this can be converted into reading persecond. The value is coming out at 282.08 ingredient per second. The areas of the model is 7.605 cm. The linear acceleration of the by  motor is what we have to l find. We have to find out of  the tangential acceleration that is given by the formula and omega squared R, if I substitute the values. This will be to 82.08 The  motor has a linear Acceleration.

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Answer:

A

 \(k = 0.11 \ m \)  beyond the goal  post

B

Given that the goal  was score against the Bruins it then means that the Flyer won the game with 2 points

Explanation:

From the question we are told that

  The amount of time left in the game is  \(t =  20 \ s\)

   The  amount of time the goal was defended  is  \(t_1  =  9 \  s\)

   The  time remaining when the shot was made is  \(t_2 =  1.25 \  s\)

     The  distance of the pluck from the goal is  \(d =  37 \  m\)

     The  initial  velocity of the pluck is \(u =  30 \  m/s\)

    The acceleration of the pluck is  \(a =  -0.50 \  m/s^2\)

Generally the distance travel at the remaining time is mathematically represented as

      \(D =  u *  t _2  +  \frac{1}{2}* a*  t_2\)

      \(D =  30 * 1.25  - \frac{1}{2}* 0.50* 1.25^2\)

       \(D =  37.11 \ m \)

So the position of the pluck when the game clock reaches zero is

        \(k = D - d\)

=>    \(k = 37.11 - 37\)

=>        \(k = 0.11 \ m \)  beyond the goal  post

Given that the goal  was score against the Bruins it then means that the Flyer won the game with 2 points

Answer: 100,000 Pa

Explanation:

\($$Applied Force $=200 \mathrm{~N}$ \\Area $=0.002 \mathrm{~m}^{2}$\\\\Pressure $=\frac{\text { Force }}{\text { Area }}$\\$=\frac{200}{0.002}$\\$=\frac{200}{2 \times 10^{-3}}$\\$=100,000 \mathrm{~Pa}$\)

a)

Objects moving under free fall have a constant acceleration g, which is the gravitational acceleration, directed downwards:

Since the balloon is descending at a speed of 2.52 m/s, the initial speed of the phone is 2.52 m/s. To find the speed after 4.00 seconds, use the formula that comes from the definition of acceleration:

Substitute the value for each parameter:

b)

From the reference frame of the balloon, the cellphone starts falling from rest, and accelerates with a constant acceleration g.

The equation that describes the distance traveled by an object that starts from rest and moves with constant acceleration g is:

Substitute the values of g and t to find how far is the cell phone below the balloon after 4 seconds:

c)

If the balloon is rising steadly at 2.52 m/s instead of descending, then the acceleration of the cellphone will be directed in the opposite direction of its initial speed. Then, the initial speed and the acceleration must have opposite signs. Considering the upward direction as positive, we have that the initial speed of the phone is 2.52 m/s and its acceleration is -g. Then:

The speed is the modulus of the velocity. Then, the speed of the phone after 4 seconds in this situation, would be 36.72 m/s.

On the other hand, in the reference frame of the rising balloon, the phone still starts moving at rest and accelerating uniformly towards the floor. The answer will be the same, and the phone will be 78.48 m below the balloon after 4 seconds.

Therefore, the answers with the correct amount of significant figures, are:

a)

b)

c)

Answer:

1st one,.

It changes the direction,

And satellite falls in earth infinity,

Its total workdone is zero

Answer:

It continuously changes the direction of the satellite.

Explanation:

our Welcome (; (:

Answer:

cos 0 = 1.

Fs = 7×8 = 56 J

Explanation:

Answer:

Earth-orbiting astronauts are weightless for the same reasons that riders of a free-falling amusement park ride or a free-falling elevator are weightless. They are weightless because there is no external contact force pushing or pulling upon their body. In each case, gravity is the only force acting upon their body.

Answer:

The maximum height to which water could be squirted with the hose is 13.380 meters.

Explanation:

A line of current of a fluid can be explained sufficiently by Bernoulli's Theorem. In this case, the system can be simplified due to neglectance of changes in absolute pressure. Water is squirted with an initial speed and reaches its maximum height, where final speed is zero. That is to say:

\(\frac{v_{1}^{2}}{2\cdot g} +z_{1} = \frac{v_{2}^{2}}{2\cdot g} +z_{2}\)

Where:

\(z_{1}\), \(z_{2}\) - Initial and final height of water, measured in meters.

\(g\) - Gravitational acceleration, measured in meters per square second.

\(v_{1}\), \(v_{2}\) - Initial and final speed of water, measured in meters per second.

If \(z_{1} = 0\,m\), \(v_{1} = 16.2\,\frac{m}{s}\), \(v_{2} = 0\,\frac{m}{s}\) and \(g = 9.807\,\frac{m}{s^{2}}\), then:

\(z_{2} = \frac{v_{1}^{2}-v_{2}^{2}}{2\cdot g} +z_{1}\)

\(z_{2} = \frac{\left(16.2\,\frac{m}{s} \right)^{2}-\left(0\,\frac{m}{s} \right)^{2}}{2\cdot \left(9.807\,\frac{m}{s^{2}} \right)} +0\,m\)

\(z_{2} = 13.380\,m\)

The maximum height to which water could be squirted with the hose is 13.380 meters.

Temperature of iron (Ti) = 415 °C Temperature of water (Tw) = 15.0 °CTemperature at equilibrium (Te) = 100 °CMass of water (m) = 0.625 kgMass of steam evaporated (ms) = 0.144 kgHeat lost by iron (Q1) = Heat gained by water (Q2) + Heat required to evaporate steam .

Heat lost by iron  = (mass of iron (m) x specific heat capacity of iron (c) x change in temperature of iron (ΔT1))Heat gained by water = (mass of water (m) x specific heat capacity of water (c) x change in temperature of water (ΔT2))Heat required to evaporate steam  = (mass of steam (ms) x specific latent heat of vaporization of water (L))Now, using the above formula we can calculate the mass of the iron block as:

Q3m x c x ΔT1 = m x c x ΔT2 + ms x L

Let's calculate the value of Q1 first.

Q1 = m x c x ΔT1m = Q1 / (c x ΔT1)

We know that

c = 450 J/kg °C and ΔT1 = Ti - Te = 415 - 100 = 315°CQ1 = m x c x ΔT1= m x 450 J/kg

°C x 315°C= 141750 m Jm = Q1 / (c x ΔT1)= 141750 / (450 x 315)= 1.002 kg

Now, let's calculate the value of Q3.Q3 = ms x L= 0.144 kg x 2.26 x 10^6 J/kg= 325440 J

Now, let's calculate the value of Q2

.Q2 = m x c x ΔT2m = (Q2 + Q3) / (c x ΔT2)

We know that ΔT2 = Te - Tw = 100 - 15 = 85°CQ2 = m x c x ΔT2= 0.625 kg x 4186 J/kg °C x 85°C= 276981.25 JNow, let's calculate the mass of the iron block.m =

(Q2 + Q3) / (c x ΔT2)= (276981.25 + 325440) / (450 x 85)= 1.003 kg

Hence, the mass of the iron block is 1.003 kg rounded off to 3 significant figures.

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The engineer should measure the radius of the ball bearings before the pivot has been used.

Given is that an engineer builds a model of a machine pivot. Instead of the two parts of the pivot directly touching one another, they have ball bearings between them.

As an indication of the amount of friction in the pivot, the engineer should measure the radius of the ball bearings before the pivot has been used.

Therefore, the engineer should measure the radius of the ball bearings before the pivot has been used.

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the frictional force on the broom has magnitude μ * m * g * cos(theta)

The frictional force on the broom can be determined using the equation:

F_friction = μ * F_norm

Where F_friction is the frictional force, μ is the coefficient of friction, and F_norm is the normal force. The normal force is equal to the force exerted on the broom perpendicular to the surface of the floor. Since the broom is being pushed across a horizontal surface, the normal force is equal to the force of gravity, which is equal to the mass of the broom (m) multiplied by the acceleration due to gravity (g).

F_norm = m * g

The force being applied to the broom is 7N and it is at angle theta with the horizontal. The component of this force perpendicular to the surface of the floor is the force that acts on the normal force.

F_norm = 7 * cos(theta)

Therefore,

F_friction = μ * m * g * cos(theta)

So, the frictional force on the broom has magnitude μ * m * g * cos(theta)

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If all conditions are ideal, you may harvest about five to 10 potatoes per plant for your gardening efforts. Yields are based on both the care your give your plants during the growing season and the variety of potatoes you choose to grow.

answer

7.5×10.000=75÷3=25

The required, it experiences a downward force due to gravity and a force due to air resistance.

Projectile motion is the movement of an entity projected into space. After the initial force that launches the object, it only experiences the force of gravity. The object is called a projectile, and its path is called its trajectory.

Here,

When throwing a ball vertically upward, there is a displacement of about 1.0 m from the initial position of the hand to the position where the ball leaves the hand. The mass of the ball is 0.80 kg and it reaches a maximum height of about 20 m above the initial position of the hand. While the ball is in the hand after it leaves, it experiences a downward force due to gravity and a force due to air resistance.

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