!!HELP ASAP DUE TODAY!! I need help with this math problem.

Probability that that sum of the two dice outcomes is 6 is 5/36

What is probability?

We know,

Probability = Number of events / Total no. of favourable outcomes

If we through two dice then ,

Total number of favourable outcomes = 36

Here, we need the sum of the two outcomes is 6 is

(1, 5) , (2, 4), (3, 3), (4, 2), (5, 1)

So, the number of events = 5

P(of getting sum 6) = 5/ 36

Hence, Probability that that sum of the two dice outcomes is 6 is 5/36

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Answer:

Sin 3A = 1

cos 3A = 0

tan 3 A = undefined

Step-by-step explanation:

\(\sin A = \frac{1}{2} \\ \therefore \: \sin A = \sin \: 30 \degree.. \bigg( \because \: \sin \: 30 \degree = \frac{1}{2} \bigg) \\ \therefore \: A = 30 \degree \\ \\ now \\ \sin 3A =\sin (3 \times 30 \degree)= \sin \: 90 \degree = 1 \\ \\ \cos 3A =\cos (3 \times 30 \degree)= \cos \: 90 \degree = 0\\\\ \tan 3A =\tan (3 \times 30 \degree)= \tan \: 90 \degree = \infty \)

Answer:

enlargement ; 2

Step-by-step explanation:

dilation is change in the size of the figure.

in the given scenario, figure's size is increasing so dilation is called enlargement and scale factor must be greater than 1.

scale factor = dimension of new shape / dimension of original shape

let's calculate the difference in terms of boxes of both figures to calculate the scale factor,

scale factor = 6/3

thus, in the given dilation we have enlargement of 2

Answer:

n+7=21 -7

n=14

Step-by-step explanation:

prove me wrong

Answer:

area of circle = pi r²

3.14x 4²

3.14×16

50.24cm²

Answer:

its f and o

Step-by-step explanation:

Answer:

D

Step-by-step explanation:

Three problems would arise if the frequency of scrum was lowered to every two or three days.

(A) There may be missed opportunities to examine and amend the sprint backlog.

(B) The Sprint strategy deteriorates; barriers are raised and taken down more slowly.

(C) Too much time is spent updating the scrum board prior to meetings.

Scrum is a project management framework that was initially focused on software development, while it has now been applied to other areas such as research, sales, marketing, and cutting-edge technology.

It is intended for groups with ten or fewer members who divide their work into tasks that can be finished in sprints, which are time-boxed iterations that can be done in as little as one month and most frequently two weeks.

If the frequency was reduced to every two or three days, there would be three issues.

(A) The chances to review and modify the Sprint Backlog may be missed.

(B) The Sprint plan becomes imprecise; obstacles are raised and removed more slowly.

(C) Too much time is spent before meetings updating the scrum board.

Therefore, three problems would arise if the frequency was lowered to every two or three days.

(A) There may be missed opportunities to examine and amend the sprint backlog.

(B) The Sprint strategy deteriorates; barriers are raised and taken down more slowly.

(C) Too much time is spent updating the scrum board prior to meetings.

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Answer:students develop good habits when they are in elementary school.

Step-by-step explanation:

iready, I got it right away

The first track is 300 cm long, and the second track is 420 cm long based on distance calculations.

Assume that the first track is x cm long. The issue states that Alex's car covers 225 cm on the first track, or three-fourths of the whole track. With the aid of this knowledge, we can formulate the equation shown below:

3/4 * x = 225

We must multiply both sides of equation by 4/3 to get x:

x = 225 * 4/3 = 300

Hence, the first track is 300 cm long.

Let's similarly say that the second track is y cm long. The issue states that Alex's vehicle covers 315 cm, or three-fourths of the second track, when driving there. With the aid of this knowledge, we can formulate the equation shown below:

3/4 * y = 315

We can multiply both sides of the equation by 4/3 to find the answer for y: y = 315 * 4/3 = 420

Thus, the second track is 420 cm long based on distance calculations.

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A triangle whose sides are all equal is called an equilateral triangle and its area is given by A=\(\frac{\sqrt{3} }{4}\) \(x^{2}\), where x is the side of the triangle.

The area of a rectangle is found by using the formula

A=lw, where l is the length and w is the width.

The given figure can be split into two shapes: a rectangle and an equilateral triangle as shown in the diagram. Let l be the length of the rectangle.

Add all of the sides of the window and equate their result to 16. Then solve for l.

x + x + l + x + l = 16

3x + 2l = 16

2l = 16 - 3x

l = \(\frac{16-3x}{2}\)

The total area of the window will be the sum of the area of the equilateral triangle ABE and the area of rectangle BCDE.

A = \(\frac{\sqrt{3} }{4}\)\(x^{2}\) + lx

Subsitute  \(\frac{16-3x}{2}\) for l into the obtained equation and simplify.

A =\(\frac{\sqrt{3} }{4}\)\(x^{2}\) + ( \(\frac{16-3x}{2}\))x

A = \(\frac{\sqrt{3} }{4} x^{2}\) + 8x - \(\frac{3}{2} x^{2}\)

Differentiate the obtained equation with respect to x and equate the first derivative to 0 to calculate the critical point x .

\(\frac{dA}{dx}\) = \(\frac{\sqrt{3} }{4}\) (2x) + 8 - \(\frac{3}{2}\) (2x)

0 = \(\frac{\sqrt{3} }{2}\) x - 3x + 8

x (3 - \(\frac{\sqrt{3} }{2}\)) = 8

x = \(\frac{16}{6-\sqrt{3} }\)≈3.74887

Again, differentiate the equation

\(\frac{dA}{dx}\) = \(\frac{\sqrt{3} }{2}\)x - 3x + 8  with respect to x.

\(\frac{d^{2}A }{dx^{2} }\) = \(\frac{\sqrt{3} }{2}\) - 3

The value of the second derivative is \(\frac{\sqrt{3} }{2}\)−3, which is negative. This implies that the area will be maximum at the critical point.

Subsitute x = 3.74887 into the equation

l = \(\frac{16-3x}{2}\) and simplify

l = \(\frac{16-(3)(.74887)}{2}\) ≈ 2.3767

The maximum light will enter through the window when the triangular portion will have the side length of 3.74887 feet and the dimensions of the rectangular portion will be 3.74887-ft-by-2.3767-ft.

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An arithmetic sequence is a sequence of numbers in which each term after the first is obtained by adding a fixed number to the previous term

The first term of an arithmetic sequence is denoted by 'a₁', the second term by 'a₂', and so on.

Given that;

Un = a + (n - 1)d

U50 = 4 + (50 - 1) 2

U50 = 102

Then;

Un = ar^n-1

U10 = 1000(1/2)^9

U10 = 1.95

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Answer:

8

Step-by-step explanation:

(2 + x) (10) = 36 + 8x

20 + 10x = 36 + 8x

10x - 8x = 36 - 20

2x = 16

x = 8

The angle  of EBF is  6w -28°.

It is required to find the angle  of EBF.

In Plane Geometry, a figure which is formed by two rays or lines that shares a common endpoint is called an angle and corner whether constituting a projecting part or a partially enclosed space.

Given:

ABF = 8w - 6

ABE = 2(w + 11)

According to given question we have,

Angle EBF = ABF - ABE

Angle EBF = 8w - 6 - [2(w + 11)]

Angle EBF = 8w - 6 - [2w + 22]

Angle EBF = 8w - 6 - 2w - 22

Angle EBF = 6w -28°

Therefore, the angle  of EBF is  6w -28°.

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Answer:

60

Step-by-step explanation:

Complementary angles means that the angles add up to 90 degrees

So the complementary of 30 is 60

30+60=90

Let the other Complementary Angle be x,

We know that, Sum of Complementary Angles = 90°

therefore,

Answer:

So we rearrange the equation to R=I/PT

Then we substitute: R= 90/300(2)

Calculating the answer should be about 0.15

or I =15%

Step-by-step explanation:

Answer:

b

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

Got it right on Edge 2020

Given that AC is a diameter of the circle, we can conclude that triangle ABC is a right triangle, with AC being the hypotenuse. The area of the circle is not directly related to finding the lengths of BC or AB, so we will focus on the given information: AB = 16 units.

Using the Pythagorean theorem, we can find BC. The Pythagorean theorem states that in a right triangle, the square of the length of the hypotenuse (AC) is equal to the sum of the squares of the other two sides (AB and BC):

AC² = AB² + BC²

Substituting the given values, we have:

(AC)² = (AB)² + (BC)²

(AC)² = 16² + (BC)²

(AC)² = 256 + (BC)²

Now, we need to find the length of AC. Since AC is a diameter of the circle, the length of AC is equal to twice the radius of the circle.

AC = 2 * radius

To find the radius, we can use the formula for the area of a circle:

Area = π * radius²

Given that the area of the circle is 2897 units², we can solve for the radius:

2897 = π * radius²

radius² = 2897 / π

radius = √(2897 / π)

Now we have the length of AC, which is equal to twice the radius. We can substitute this value into the equation:

(2 * radius)² = 256 + (BC)²

4 * radius² = 256 + (BC)²

Substituting the value of radius, we have:

4 * (√(2897 / π))² = 256 + (BC)²

4 * (2897 / π) = 256 + (BC)²

Simplifying the equation gives:

(4 * 2897) / π = 256 + (BC)²

BC² = (4 * 2897) / π - 256

Now we can solve for BC by taking the square root of both sides:

BC = √((4 * 2897) / π - 256)

To find the measure of angle BC (mBC), we know that triangle ABC is a right triangle, so angle B will be 90 degrees.

In summary:

BC = √((4 * 2897) / π - 256)

mBC = 90 degrees

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Correct Question is:

Jenny walked 2 3/8 miles on Monday and 1 7/8 miles on Tuesday. How many miles did she walk on Monday and Tuesday all together? What number model would you use?

a. 2 3/8 - 1 7/8

b. 2 3/8 + 1 7/8

c. 23/8 + 17/8

d. none of these

Answer:

b. 2 3/8 + 1 7/8

Step-by-step explanation:

As the sum of both Monday and Tuesday miles are required therefore both fractions will be added up as mentioned in option B of the question.

remaining are wrong as both fractions cannot be subtracted, and option c is wrong because 2 (3/8) is not equals to 23/8 and 1 (7/8) is not equals to 17/8.

The root of this equation is determined to be approximately 0.567143.The root is found to be approximately -0.673253.

The Newton-Raphson method is an iterative numerical technique used to find the roots of equations. In the first equation, y = f(x) = e^x - x, the initial approximation x0 is set to 0. By applying the Newton-Raphson method, successive approximations of the root are calculated until convergence is achieved. The root of this equation is determined to be approximately 0.567143.

In the second equation, x^3 + 2x^2 + 6x + 3 = 0, the root is sought within the range (-1, 0). The Newton-Raphson method is employed again, starting with an initial approximation x0 of -1. Through iterative calculations, the root is found to be approximately -0.673253.

Both equations demonstrate the effectiveness of the Newton-Raphson method in finding roots within specific ranges by iteratively refining approximations until a satisfactory solution is obtained.

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Answer:

Let bags of pecans cost = x

Make an equation :

Bags of almonds cost = x + 3 (they said almonds cost 3 dollars more)

Total number of bags ordered: (3 bags pecans) + (5 bags of almonds)

Cost for pecans = 3x

Cost for almonds = 5(x + 3) = 5x + 15

Price of pecans + price of almonds = total cost

Solve for x:

3x + 5(x + 3) = 55 (remove brackets)

3x + 5x + 15 = 55 (add like terms)

8x + 15 = 55

8x + 15 - 15 = 55 - 15 (get rid of the 15)

8x = 40

8x/8 = 40/8

x = 5

bags pecans cost is $5

bags of almonds is $5+$3 = $8

Answer:

8/12, 11/16, 3/4, 4/8

Step-by-step explanation:

hope this helps

Answer:

Step-by-step explanation:

4x^2+4x+1

Explanation

By definition.

so

Let

hence

I hope this helps you

9514 1404 393

Answer:

Step-by-step explanation:

Three segments will form a triangle if the sum of the two shortest is greater than the longest. Here, we require ...

  10 + 10 > 18 . . . . . true, a triangle can be formed

__

Since two of the sides are the same length, the triangle will be isosceles.

Answer:

3/5

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(8-5)/(3-(-2))

m=3/(3+2)

m=3/5

The difference between the percentage of students enrolled in propel who had a GPA of 3.0 or greater and the percentage of students not enrolled in propel who had a GPA of 3.0 or greater is 12%.

There are 61 students enrolled in Propel who had a GPA of 3.0 or greater and 48 students enrolled in Propel who had a GPA of less than 3.0, so there are a total of 61 + 48 = 109 students enrolled in Propel.

The percentage of students enrolled in Propel who had a GPA of 3.0 or greater is 61 100% 109 × ≈ 55.96% or about 56%. There are 95 students who are not enrolled in Propel who had a GPA of 3.0 or greater and 123 students not enrolled in Propel who had a GPA of less than 3.0, so there are a total of 95 + 123 = 218 students who are not enrolled in Propel.

The percentage of students not enrolled in Propel who had a GPA of 3.0 or greater is 95 100% 218 × ≈ 43.58% or about 44%.

Therefore, the difference, to the nearest whole percent, between the percentage of students enrolled in Propel who had a GPA of 3.0 or greater and the percentage of students not enrolled in Propel who had a GPA of 3.0or greater is 56% − 44% = 12%.

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Answer:

It will take them 7.89 days