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Question:

Select from the drop-down menus to correctly complete each statement

17.2 is 17.2 units to the ( drop-down 1 ) of zero on a number line. The opposite of 17.2 is 17.2 units to the ( drop-down 2 ) of zero on a number line.

The relation accepts reflexive, symmetry, and transitive.

Recall that a relation R is reflexive if the element (x, x) belongs to R for all elements X in the domain of R.

If (x, y) belongs to R, then follows that (y, x) must likewise belong to R, making the situation symmetric.

And it is transitive if (x, y) and (y, z) belongs to R necessarily implies that (x, z) belongs to R.

Given r is a relation on the set of all nonnegative integers R(a,b)

Reflexive - YES. A given number a will always have the same remainder when divided by 5.

Symmetric - YES. If a and b have the same remainder when divided by 5, then b and a are the same pair, so again they will have the same remainder.

Transitive - YES. If a and b as well as b and c have the same remainder when divided by 5, this is possible if both a and c also have the same remainder when divided by 5.

Therefore the relation accepts reflexive, symmetry, and transitive.

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Given:

Total number of marbles = 26

Number of blue marbles = 13

Number of red marbles = 10

Number of yellow marbles = 3

To find:

The probability of getting a blue marble then a red marble (without replacement).

Solution:

Total number of marbles = 26

Number of blue marbles = 13

Probability of getting a blue marble is first draw is:

\(P(Blue)=\dfrac{\text{Number of blue marbles}}{\text{Total number of marbles}}\)

\(P(Blue)=\dfrac{13}{26}\)

\(P(Blue)=\dfrac{1}{2}\)

After drawing 1 marble, the remaining number of marbles in the bag is 25.

Probability of getting a red marble is second draw is:

\(P(Red)=\dfrac{\text{Number of red marbles}}{\text{Remaining number of marbles}}\)

\(P(Red)=\dfrac{10}{25}\)

\(P(Red)=\dfrac{2}{5}\)

Now the probability of getting a blue marble then a red marble (without replacement) is:

\(P(\text{Blue then red})=P(Blue)\times P(Red)\)

\(P(\text{Blue then red})=\dfrac{1}{2}\times \dfrac{2}{5}\)

\(P(\text{Blue then red})=\dfrac{1}{5}\)

Therefore, the probability of getting a blue marble then a red marble (without replacement) is \(\dfrac{1}{5}\).

Part A

The equation is d = 50t

This is because the slope of 50 represents how many miles per day the butterflies cover (on average). The y intercept is 0 to indicate that 0 miles have been traveled initially.

You can think of this as the equation y = 50x

If t = 1, then d = 50t = 50*1 = 50 miles have been covered

If t = 2, then d = 50t = 50*2 = 100 miles have been covered

And so on.

==========================================================

Part B

You'll have these values in the bottom row (in the order presented): 50, 100, 150, 200, 250

You can plug in the values t = 1, t = 2, t = 3, t = 4 and t = 5 into d = 50t to find those answers in bold.

Or you could add on 50 each time to generate each new value. We start at 50 since t = 1 corresponds to d = 50.

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Part C

You can keep the pattern of 50,100,150, ... going until you reach 2500. Then note the t value that pairs with d = 2500

In my opinion, that's the slower method.

The quicker method is to plug d = 2500 into the equation for part A, and then solve for t.

d = 50t

2500 = 50t

50t = 2500

50t/50 = 2500/50 ....... divide both sides by 50

t = 50

It will take 50 days for the average distance traveled to be 2500 miles.

Answer:

Joel’s is the 28

Step-by-step explanation:

For the one is me cause Zyou KNOW ULTRA,,,!,,,,,,292

The property that should be used to continue simplifying the above equation is A-^1A = 1. So, correct option is C.

We can start with the equation AB = AC and multiply both sides by A^-1 on the left:

A^-1(AB) = A^-1(AC)

Using the associative property of matrix multiplication, we can simplify the left-hand side:

(A^-1A)B = (A^-1A)C

Using the fact that A^-1A = I (the identity matrix), we get:

IB = IC

Simplifying further using the fact that I times any matrix is that matrix itself, we obtain:

B = C

Therefore, the equivalent equation to AB = AC using A^-1 that simplifies to B = C is A^-1(AB) = A^-1(AC), and the property used to continue simplifying the equation is A^-1A = I.

The correct option is (C) A^-1A = 1, which is equivalent to A^-1A = I, since the identity matrix is denoted as 1 in some contexts.

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\(\cfrac{89.40~~ - ~~\stackrel{ \textit{minus the tax of each} }{0.50-0.50-0.50-0.50-0.50-0.50}}{6}\implies \cfrac{86.40}{6}\implies \stackrel{ each }{14.40}\)

Statements (b) and (D) can be concluded from the box plots.

From the box plots, we can see that Miguel's median number of text messages per day is around 35, while Shona's median is around 45. This means that Shona sent more text messages per day on average.

Statement (b) can be concluded because the box plot for Miguel shows that the upper quartile (75th percentile) is around 50, meaning that for approximately 25% of the days, he sent 50 or more text messages. Since this range extends to the maximum value of 70, it is likely that Miguel sent 50 or more text messages per day for approximately 15 days.

Statement (D) can be concluded because we can compare the interquartile ranges (IQRs) for both Miguel and Shona. The IQR for Miguel ranges from approximately 20 to 50, while the IQR for Shona ranges from approximately 35 to 55. This means that Shona sent more text messages than Miguel on at least the 50% of days that fall within her IQR. Therefore, we can conclude that the number of days on which Shona sent more text messages than Miguel is at least half of the total number of days.

Statement (E) cannot be concluded from the box plots, as there is no clear overlap or intersection between the two box plots. Therefore, we cannot determine whether there was a day on which Shona and Miguel each sent 25 text messages. Additionally, statement (C) cannot be concluded as there is no clear indication of the exact number of days on which Shona sent 40 text messages.

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1. Independent random samples arise when one random sample is split into groups differing by an observed feature is incorrect.

2. The margin of error of a confidence interval about the difference between the means of two populations is equal to half the width of the confidence interval.

1. Independent random samples arise when individuals in a sample are randomly assigned to experimental groups, data is recorded repeatedly on a random sample of individuals, or random samples are selected separately. The statement that one random sample is split into groups differing by an observed feature does not accurately describe independent random samples.

2. The margin of error in a confidence interval represents the range of values within which the true population parameter is likely to fall. It is calculated by taking half of the width of the confidence interval. Therefore, the correct answer is that the margin of error is equal to half the width of the confidence interval.

In summary, the incorrect statement is that independent random samples arise when one random sample is split into groups differing by an observed feature. The margin of error of a confidence interval about the difference between the means of two populations is equal to half the width of the confidence interval.

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Answer:

B i think

Step-by-step explanation:

A) The best point estimate of the population P is 0.5399

B) The value of margin of error E.≈ 0.0267 (Round to four decimal places as needed)

C) A confidence interval is 0.5132 < p < 0.5666

A) The best point estimate of the population proportion (P) is calculated by dividing the number of respondents who said "yes" (x) by the total number of respondents (n).

In this case,

P = x/n = 557/1032 = 0.5399 (rounded to four decimal places).

B) The margin of error (E) is calculated using the formula: E = z * sqrt(P*(1-P)/n), where z represents the z-score associated with the desired confidence level. For a 99% confidence level, the z-score is approximately 2.576.

Plugging in the values,

E = 2.576 * sqrt(0.5399*(1-0.5399)/1032)

≈ 0.0267 (rounded to four decimal places).

C) To construct a confidence interval, we add and subtract the margin of error (E) from the point estimate (P). Thus, the 99% confidence interval is approximately 0.5399 - 0.0267 < p < 0.5399 + 0.0267. Simplifying, the confidence interval is 0.5132 < p < 0.5666 (rounded to four decimal places).

In summary, the best point estimate of the population proportion is 0.5399, the margin of error is approximately 0.0267, and the 99% confidence interval is 0.5132 < p < 0.5666.

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Answer:

It would cost 3.47 cents for one ounce.

Hope it helps :)

Answer: 3.47

Step-by-step explanation: see the key word per and that tells you to divide 20 by 5.76 and get 3.47

 In the given game, if Carolyn removes the integer 2 on her first turn and $n=6$, we need to determine the sum of the numbers that Carolyn removes.

Let's analyze the game based on Carolyn's move. Since Carolyn removes the number 2 on her first turn, Paul must remove all the positive divisors of 2, which are 1 and 2. As a result, the remaining numbers are 3, 4, 5, and 6.
On Carolyn's second turn, she cannot remove 3 because it is a prime number. Similarly, she cannot remove 4 because it has only one positive divisor remaining (2), violating the game rules. Thus, Carolyn cannot remove any number on her second turn.
According to the game rules, Paul then removes the rest of the numbers, which are 3, 5, and 6.
Therefore, the sum of the numbers Carolyn removes is 2, as she only removes the integer 2 on her first turn.
To summarize, when Carolyn removes the integer 2 on her first turn and $n=6$, the sum of the numbers Carolyn removes is 2.

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the complete question is:

  Carolyn and Paul are playing a game starting with a list of the integers $1$ to $n.$ The rules of the game are: $\bullet$ Carolyn always has the first turn. $\bullet$ Carolyn and Paul alternate turns. $\bullet$ On each of her turns, Carolyn must remove one number from the list such that this number has at least one positive divisor other than itself remaining in the list. $\bullet$ On each of his turns, Paul must remove from the list all of the positive divisors of the number that Carolyn has just removed. $\bullet$ If Carolyn cannot remove any more numbers, then Paul removes the rest of the numbers. For example, if $n=6,$ a possible sequence of moves is shown in this chart: \begin{tabular}{|c|c|c|} \hline Player & Removed \# & \# remaining \\ \hline Carolyn & 4 & 1, 2, 3, 5, 6 \\ \hline Paul & 1, 2 & 3, 5, 6 \\ \hline Carolyn & 6 & 3, 5 \\ \hline Paul & 3 & 5 \\ \hline Carolyn & None & 5 \\ \hline Paul & 5 & None \\ \hline \end{tabular} Note that Carolyn can't remove $3$ or $5$ on her second turn, and can't remove any number on her third turn. In this example, the sum of the numbers removed by Carolyn is $4+6=10$ and the sum of the numbers removed by Paul is $1+2+3+5=11.$ Suppose that $n=6$ and Carolyn removes the integer $2$ on her first turn. Determine the sum of the numbers that Carolyn removes.

Answer:

The magnitude is sqrt((-4)^2 + (-9)^2) = 9.85. The angle is atan(-9/-4) = 180 deg + 66 deg = 246 deg = -114 deg.

Step-by-step explanation:

hope it help

Answer:

9.85

Step-by-step explanation:

|v|= √9²+(-4)²

=√81+16

=√97

|v|= 9.85

Answer:

(-1,-6)

Step-by-step explanation:

(-1,-6)

Multiply coordinates of mid point by 2

take away from point P

Answer:

this is a positive correlation

Step-by-step explanation:

it is going up so its positive

The polynomial function with leading coefficient of 3 and root -4, i, and 2 all with multiplicity of 1 is f(x) = 3(x+4)(x-i)(x+2)

The Leading coefficients are the numbers written in front of the variable with the largest exponent.

Roots of a polynomial refer to the values of a variable for which the given polynomial is equal to zero.

The multiplicity is the number of times a given factor appears in the factored form of the equation of a polynomial.

Therefore, the polynomial f(x) = 3(x+4)(x-i)(x+2) has a root -4 , 1 and -2.

The leading coefficient is 3. The multiplicity is all one.

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Answer:

d

Step-by-step explanation:

The third person owns 1/4 (or three twelfths) of the franchise.

To find the fraction of the franchise owned by the third person, we need to add the fractions owned by the first and second person and subtract it from the whole.

The first person owns 7/12 of the franchise, and the second person owns 1/6 of the franchise. To add these fractions, we need to find a common denominator. The common denominator for 12 and 6 is 12.

Converting the fractions to have a denominator of 12:

First person's ownership: (7/12) = (7 * 1/12) = 7/12

Second person's ownership: (1/6) = (1 * 2/12) = 2/12

Adding the fractions: (7/12) + (2/12) = 9/12

Now, we subtract the sum from the whole to find the third person's ownership. The whole is equal to 12/12.

Third person's ownership: (12/12) - (9/12) = 3/12

Simplifying the fraction, we get: 3/12 = 1/4

Therefore, the third person owns 1/4 (or three twelfths) of the franchise.

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Answer:

x^2 - 8x - 20

Step-by-step explanation:

(x - 10)(x + 2)

x^2 + 2x - 10x - 20

x^2 - 8x - 20

Please mark me the brainliest!?!

Answer:

6 to 7, A

Step-by-step explanation:

The slope of the tangent line to the polar curve r = 2 - sin(θ) at the point specified by θ = π/3 is -1/2.

To find the slope of the tangent line to the polar curve r = 2 - sin(θ) at the point specified by θ = π/3, we need to first find the derivative of r with respect to θ, and then evaluate it at θ = π/3.

Differentiating both sides of the polar equation with respect to θ, we get:

dr/dθ = d/dθ(2 - sinθ)

dr/dθ = -cosθ

So, the derivative of r with respect to θ is -cosθ.

Evaluating this derivative at θ = π/3, we get:

dr/dθ|θ=π/3 = -cos(π/3) = -1/2

Therefore, the slope of the tangent line to the polar curve r = 2 - sin(θ) at the point specified by θ = π/3 is -1/2.

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Answer:

(0,4) is the y-intercept and 3x is the slope

Answer:

\(x + 5y = 6\) is perpendicular to \(y = 5x + \frac{6}{5}\) and parallel to \(y = -\frac{1}{5}x + 2\\\)

Step-by-step explanation:

First, convert the equation to standard form so that y is isolated.

x + 5y = 6 --> x - 6 = -5y (divide both sides by -5) --> \(y = -\frac{1}{5}x + \frac{6}{5}\)

A perpendicular line will have a slope that is the opposite reciprocal of the original slope (meaning you flip the numerator and denominator then make it negative).

\(-\frac{1}{5}\) is perpendicular to \(-(\frac{-5}{1} )\) which simplifies to 5.

A parallel line will have the same slope, but the y-intercept will be different. It can be pretty much any number as long as the original slope is used in the new equation.

\(y = -\frac{1}{5}x + \frac{6}{5}\\\) is parallel to \(y = -\frac{1}{5}x + 2\\\) just like \(y = -\frac{1}{5}x - \frac{100}{23}\).

Answer:

Answer is C

Step-by-step explanation:

have a nice day!!

~ jassy

Answer:

The answer would be c

Step-by-step explanation:

The relation "is child of" on the set of all people is (a) reflexive, (b) irreflexive, (c) asymmetric, (d) antisymmetric, (e) symmetric, (f) transitive.

Let's determine each of these properties one by one.

(a) Reflexive property of the relation "is child of": The relation "is child of" cannot be reflexive. It is not possible for a person to be their own child. Thus, for any person "x", there does not exist any pair of "x" and "x" such that x is the child of x.

(b) Irreflexive property of the relation "is child of": The relation "is child of" can be irreflexive. It is not possible for a person to be their own child.

Thus, for any person "x", there does not exist any pair of "x" and "x" such that x is the child of x. Therefore, the relation "is child of" is irreflexive.

(c) Asymmetric property of the relation "is child of": The relation "is child of" can be asymmetric. If person "a" is a child of person "b", then "b" cannot be a child of "a". Thus, the relation "is child of" is asymmetric.

(d) Antisymmetric property of the relation "is child of": The relation "is child of" cannot be antisymmetric. If person "a" is a child of person "b", then it is possible that "b" is a child of person "a" (just not biologically). Thus, the relation "is child of" is not antisymmetric.

(e) Symmetric property of the relation "is child of": The relation "is child of" cannot be symmetric. If person "a" is a child of person "b", then it is not necessary that person "b" is the child of person "a". Thus, the relation "is child of" is not symmetric.

(f) Transitive property of the relation "is child of": The relation "is child of" can be transitive. If person "a" is a child of person "b", and person "b" is a child of person "c", then it follows that person "a" is a child of person "c". Therefore, the relation "is child of" is transitive.

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5y⁻³

= 5/y³

note :

a⁻ⁿ = 1/aⁿ

The 8-point Discrete Fourier Transform (DFT) of x[n] = 2cos²(nπ/4) is given by X[k] = [4, 0, 0, 0, 0, 0, 0, 0] for k = 0, 1, 2, 3, 4, 5, 6, 7.

The Discrete Fourier Transform (DFT) is used to transform a discrete-time sequence from the time domain to the frequency domain. To find the DFT of x[n] = 2cos²(nπ/4), we need to evaluate its spectrum at different frequencies.

The DFT formula for an N-point sequence x[n] is given by:

X[k] = Σ(x[n] * exp(-j2πkn/N)), for n = 0 to N-1

Here, N represents the number of points in the DFT and k is the frequency index.

Using the double-angle formula for cosine, we can express cos²(nπ/4) as (1 + cos(2nπ/4))/2.

Substituting this expression into the DFT formula, we have:

X[k] = Σ((2 * (1 + cos(2nπ/4))/2) * exp(-j2πkn/8)), for n = 0 to 7

Simplifying, we get:

X[k] = Σ((1 + cos(2nπ/4)) * exp(-j2πkn/8)), for n = 0 to 7

Using the identity exp(-j2πkn/8) = exp(-jπkn/4) for k = 0, 1, ..., 7, we can further simplify:

X[k] = Σ((1 + cos(2nπ/4)) * exp(-jπkn/4)), for n = 0 to 7

Notice that cos(2nπ/4) = cos(nπ/2), which takes on the values of 1, 0, -1, 0 for n = 0, 1, 2, 3, respectively.

Substituting these values, we find that X[k] = [4, 0, 0, 0, 0, 0, 0, 0] for k = 0, 1, 2, 3, 4, 5, 6, 7.

This means that the 8-point DFT of x[n] = 2cos²(nπ/4) has non-zero values only at the 0th frequency component (k = 0), while all other frequency components have zero amplitude.

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Answer:

Number of students= 820.64 = 821

Step-by-step explanation:

Giving the following information:

Current attendance= 950 students

Number of periods= 3 years

Decrease rate= 5%

To calculate the number of students in attendance in 3 years, we need to use the following formula:

Number of students= current attendance*(1+decrease rate)^(-n)

Number of students= 950*(1.05^-3)

Number of students= 820.64 = 821

Thus, there is a 71.95% chance that a randomly selected amateur player in the tournament is not in the top 40 golfers in the world.

The first step in solving this problem is to use the given information to calculate the proportion of players who are both amateurs and ranked in the top 40 golfers in the world.

Since being a top 40 golfer and being an amateur are mutually exclusive, the proportion we're interested in is the proportion of amateur players who are not in the top 40.

We know that 15% of players are in the top 40, so 85% of players are not. We also know that 67% of players are amateurs, so 33% of players are not. To find the proportion of amateur players who are not in the top 40, we can multiply these two proportions:

0.85 x 0.33 = 0.2805

So, 28.05% of players in the tournament are amateurs who are not in the top 40.

Now, we can use this proportion to answer the question of what the probability is of selecting an amateur player who is not in the top 40, given that the player is an amateur. This is simply the proportion we just calculated:

P(amateur and not top 40) = 0.2805

Therefore, the probability of selecting an amateur player who is in the top 40 is:

P(top 40 | amateur) = 1 - P(amateur and not top 40)
= 1 - 0.2805
= 0.7195 or 71.95%

In other words, there is a 71.95% chance that a randomly selected amateur player in the tournament is not in the top 40 golfers in the world.

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Answer:

yes i think you did

Step-by-step explanation: