HELP for these 2 !!! it’s asking if it’s a function or not

18. An infant weighs 11 pounds which is equivalent to 4.98 kg. Using the 100/50/20 Rule, the required amount of fluid per day for an infant between 11-20 kg is 50 ml/kg/day. So, the required amount of fluid per day in ml is 4.98 kg x 50 ml/kg/day = 249 ml/day.

19. A child weighs 31lbs and 8 ozs which is equivalent to 14.21 kg. Using the 100/50/24 Rule, the required amount of fluid per day for a child over 20 kg is 20 ml/kg/day. So, the required amount of fluid per day in ml is 14.21 kg x 20 ml/kg/day = 284.2 ml/day.

If no oral fluids are consumed, the hourly IV flow rate to maintain proper hydration would be: 284.2 ml/day / 24 hours/day = 11.8 ml/hour.

The question is about fluid requirements for infants and children, and it is using the 100/50/20 Rule for Daily Fluid Requirements (DFR) to calculate the required amount of fluid per day for different weight ranges. The 100/50/20 Rule is a guideline used to determine the appropriate amount of fluid that infants and children should receive on a daily basis based on their weight. The rule states that for infants and children up to 10 kg, the recommended fluid intake is 100 ml/kg/day, for those between 11-20 kg it is 50 ml/kg/day, and for those over 20 kg it is 20 ml/kg/day.

The question also asking about the hourly IV flow rate to maintain proper hydration if no oral fluids are consumed.

This subject is part of pediatrics, more specifically in the field of fluid and electrolyte balance and management.

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The radius of the pool is 9.01 m.

Given,

In the question:

A circular pool is surrounded by a brick walkway 3 m wide.

The area of the walk- way is 198 m^2.

To find the Radius of the pool.

Now, According to the question:

"Area of the circle bounded by the outside edge of the walkway" minus "area of the pool" = "area of the walkway".

Let R = Radius of the pool

Area of the circle bounded by the outside edge of the walkway is:

\(\pi\)(R +3)^2

Area of the pool is:

\(\pi R^2\)

Now, Our equation is:;

\(\pi\)(R +3)^2 - \(\pi R^2\) = 198

\(\pi\)((R+3)^2 - \(R^2\)) = 198

Open the inner bracket :

\(\pi\)(\(R^2+6R+9-R^2\)) = 198

\(\pi\)(6R +9) = 198

6R+9 = 198/\(\pi\)

6R = 198/\(\pi\) - 9

R = (198/\(\pi\) - 9)/6

R = (198/(3.14) - 9)/6

R = (63.057 - 9)/6

R = 54.057/6

R = 9.01 meters

Hence, The radius of the pool is 9.01 m.

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First quartile is 14, IQR is 14, median is 19, third quartile is 28 and MAD is 7.

a. First quartile = 12 and d. Third quartile = 25 are not necessarily correct measures of quartiles for this dataset. To calculate the quartiles, we need to first order the data set and then find the value(s) that divide it into four equal parts. In this case, the sorted dataset is:

5, 10, 14, 17, 18, 20, 22, 25, 31, 43

The first quartile is the median of the lower half of the data: (5, 10, 14, 17, 18) and is 14.

b. IQR = 11 is not correct. The IQR (Interquartile Range) is the difference between the third quartile and the first quartile, which is 28-14=14 for this dataset.

c. Median = 19 is a correct measure of center.

d. The third quartile is the median of the upper half of the data: (22, 25, 31, 43) and is 28.

e. MAD = 7 is a correct measure of variation.

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Answer:

Hello,

Answer A

Step-by-step explanation:

\(a_1=-6\\\\a_2=a_1*(\dfrac{1}{4} )^1\\\\a_3=a_2*(\dfrac{1}{4} )^1=a_1*(\dfrac{1}{4} )^2\\\\\\\\a_n=a_1*(\dfrac{1}{4} )^{n-1}\\\\Answer\ A\\\)

Answer:

there is no additional information shown

The given manufacturing cost of a bicycle function C(x,y) is approximated as,

C(x,y) = 46x² + 37y² - 17xy + 58

Where x is the cost of materials and y is the cost of labor is 1.46

To find the following;

C_y(5, 3) ∂x/∂C (3,4)

Given,

C(x,y) = 46x² + 37y² - 17xy + 58

a) C_y(5,3)

To calculate C_y, we will differentiate C(x,y) partially w.r.t y.

So,  C_y = 74y - 17x

Now, substituting the given values,

y = 3,

x = 5,

we get

C_y(5, 3)

= 74(3) - 17(5)

= 222 - 85

= 137

Therefore,

C_y(5, 3) = 137.

b) ∂x/∂C (3,4)

To calculate ∂x/∂C, we will differentiate C(x,y) partially w.r.t x.

So,  ∂C/∂x = 92x - 17y

Here, we need to calculate ∂x/∂C (3, 4), so substituting the values in the above equation, we get

∂x/∂C

= 92(3) - 17(4)/[2(46)(3) - 17(4)]∂x/∂C

= 276 - 68/210 - 68∂x/∂C

= 208/142

Therefore,

∂x/∂C (3, 4)

= 208/142

= 1.46 (approx).

So, the values are:

C_y(5,3) = 137∂x/∂C (3,4)

= 1.46

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Answer:

\(\frac{3}{8}\)

\(2\times \frac{3}{8} = \frac{3}{4}\)

Step-by-step explanation:

According to the given scenario given that

if Ali uses \(\frac{3}{8}\)  of 2 pounds of clay for a game of 4 bowls

\(\frac{3}{8} (2) = \frac{6}{8} = \frac{3}{4}\)

here Ali will use the number of pounds of clay to create a game

\(2\times \frac{3}{8} = \frac{3}{4}\)

Now, we need to compute the number of pounds of clay that should be used in every bowl, we need to divide the prior outcome by 4 which is

\(\frac{2\times \frac{3}{8}}{4}\)

The height of the pile increasing when the pile is 6 ft high is approx 0.531 ft/min..

The volume of a cone V = (1/3)πr²h

Since we are given that h = 2r (where 2r is the diameter),

From h = 2r the value of r = h/2

Substitute the value of r in the formula of volume of cone

V = (1/3)π(h/2)²h

V = (1/3)π(h²/4)h

V = (1/12)πh³..................(1)

The rate of the volume change in time is given; it is 15 ft³/min.

Therefore

15 = dV/dt

15 = (dV/dh) · (dh/dt)

We can calculate dV/dh from the equation 1.

From the equation 1

dV/dh = (3/12)πh²

dV/dh = (1/4)πh²

Substitute the value

15 = (1/4)πh² · (dh/dt)

From the question h = 6 ft.

Substitute the value of h

15 = (1/4)π(6)² · (dh/dt)

15 = (1/4)π × 36 · (dh/dt)

15 = 9π · (dh/dt)

Divide by 9π on both side, we get

dh/dt = 15/9π

Substitute the π = 3.14

dh/dt = 15/(9 × 3.14)

dh/dt = 15/28.26

dh/dt = 0.531

At this moment, the height of the cone is increasing at the rate of 0.531 ft/min. (approximately)

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In ths case the answer is very simple .

We must analyze the options to find the solution.

All equations, except the last one, have a y-intercept term.

Therefore, the d equation would represent a linear proportional equation.

The answer is:

d) y = 2/5 x

The given function is f(x,y,λ) = 8xy − λ(5x + 6y − 2). The symbol λ is the Greek letter lambda.

To find the value of fx, we differentiate f(x,y,λ) with respect to x.

f(x,y,λ) = 8xy − λ(5x + 6y − 2)∂f/∂x = 8y − λ(5) = 8y − 5λ

Therefore, fx​ = 8y − 5λ

To find the value of fy​, we differentiate f(x,y,λ) with respect to y.

f(x,y,λ) = 8xy − λ(5x + 6y − 2)∂f/∂y = 8x − λ(6) = 8x − 6λ

Therefore, fy​ = 8x − 6λ

To find the value of fλ​, we differentiate f(x,y,λ) with respect to λ.

f(x,y,λ) = 8xy − λ(5x + 6y − 2)∂f/∂λ = − (5x + 6y − 2)

Therefore, fλ​ = 5x + 6y − 2

The given function is f(x,y,λ) = x² + y² − λ(4x + 9y − 19)

Find fx​,fy​, and fλ​.The symbol λ is the Greek letter lambda.

To find the value of fx, we differentiate f(x,y,λ) with respect to x.

f(x,y,λ) = x² + y² − λ(4x + 9y − 19)∂f/∂x = 2x − λ(4) = 2x − 4λ

Therefore, fx​ = 2x − 4λ

To find the value of fy​, we differentiate f(x,y,λ) with respect to y.

f(x,y,λ) = x² + y² − λ(4x + 9y − 19)∂f/∂y = 2y − λ(9) = 2y − 9λ

Therefore, fy​ = 2y − 9λ

To find the value of fλ​, we differentiate f(x,y,λ) with respect to λ.

f(x,y,λ) = x² + y² − λ(4x + 9y − 19)∂f/∂λ = − (4x + 9y − 19)

Therefore, fλ​ = 4x + 9y − 19.

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The symbol λ is the Greek letter lambda. f(x,y,λ) = 8xy−λ(5x+6y−2)

Given function is, f(x,y,λ) = 8xy − λ(5x + 6y − 2).

We are supposed to find fx​,fy​, and fλ​.

fx = ∂f/∂x = 8y - λ(5)

fy = ∂f/∂y = 8x - λ(6)

fλ = ∂f/∂λ = - (5x + 6y - 2)

Therefore, fx = 8y - 5λ

fy = 8x - 6λ

fλ = - (5x + 6y - 2)

Hence, fx = 8y - 5λ,

fy = 8x - 6λ, and

fλ = - (5x + 6y - 2).

The symbol λ is the Greek letter lambda. f(x,y,λ)=x2+y2−λ(4x+9y−19) ,

Second function is, f(x,y,λ) = x² + y² - λ(4x + 9y - 19).

We are supposed to find fx​,fy​, and fλ​.

fx = ∂f/∂x = 2x - λ(4)

fy = ∂f/∂y = 2y - λ(9)

fλ = ∂f/∂λ = - (4x + 9y - 19)

Therefore, fx = 2x - 4λ

fy = 2y - 9λ

fλ = - (4x + 9y - 19)

Hence, fx = 2x - 4λ,

fy = 2y - 9λ, and

fλ = - (4x + 9y - 19).

Therefore, fx​ for the first function is 8y - 5λ and for the second function is 2x - 4λ.

fy​ for the first function is 8x - 6λ and for the second function is 2y - 9λ.

fλ​ for the first function is - (5x + 6y - 2) and for the second function is - (4x + 9y - 19).

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The differentiation of the function y = sin(2 sin⁻¹x) is; dy/dx = d√(1 - y²)]/(√1 - x²)

1) We want to differentiate the function;

\(\frac{\sqrt{x + 1} + \sqrt{x - 1}}{\sqrt{x + 1} - \sqrt{x - 1} }\)

Differentiating this gives;

dy/dx = \(\frac{[(\frac{1}{2\sqrt{x + 1}} - \frac{1}{2\sqrt{x - 1}}) * \sqrt{x + 1} + \sqrt{x - 1}]}{(\sqrt{x + 1} - \sqrt{x - 1})^{2} }\)

That can be simplified to get;

dy/dx = \(\frac{\sqrt{x + 1} + \sqrt{x - 1} }{(x - 1)\sqrt{x + 1} + (-x - 1) \sqrt{x - 1}}\)

2) We want to differentiate the function;

y = sin(2 sin⁻¹x)

Differentiating the function gives;

dy/dx = [2cos(2 sin⁻¹x)]/√(1 - x²)

We know from trigonometric identity that;

cos²x = 1 - sin²x

Thus;

1 - sin²(2 sin⁻¹x) = cos²(2 sin⁻¹x)

But sin²(2 sin⁻¹x) = y²cos²(2 sin⁻¹x)

Thus; √(1 - y²) = cos(2 sin⁻¹x)

dy/dx = d√(1 - y²)]/(√1 - x²)

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The probability that a student's score is less than 81 points on the reading ability test is 0.9772. We would expect approximately 489 students to earn a score less than 81 points if 500 students took the reading ability test. The probability of randomly selecting 35 students (all from the same class) that have a sample mean reading ability test score between 66 and 68 is approximately 0.2190.

To find the probability that a student's score is less than 81 points, we need to standardize the score using the z-score formula:

z = (x - μ) / σ

where x is the student's score, μ is the mean score, and σ is the standard deviation. Plugging in the values, we get:

z = (81 - 65) / 8 = 2.00

Using a standard normal distribution table or calculator, we can find the probability of a z-score less than 2.00 to be approximately 0.9772. Therefore, the probability that a student's score is less than 81 points is 0.9772.

Since the distribution is normal, we can use the normal distribution to estimate the number of students who would earn a score less than 81. We can standardize the score of 81 using the z-score formula as above and use the standardized score to find the area under the normal distribution curve. Specifically, the area under the curve to the left of the standardized score represents the proportion of students who scored less than 81. We can then multiply this proportion by the total number of students (500) to estimate the number of students who would score less than 81.

z = (81 - 65) / 8 = 2.00

P(z < 2.00) = 0.9772

Number of students with score < 81 = 0.9772 x 500 = 489

Therefore, we would expect approximately 489 students to earn a score less than 81 points.

The distribution of the sample mean reading ability test scores is also normal with mean μ = 65 and standard deviation σ / sqrt(n) = 8 / sqrt(35) ≈ 1.35, where n is the sample size (number of students in the sample). To find the probability that the sample mean score is between 66 and 68, we can standardize using the z-score formula:

z1 = (66 - 65) / (8 / sqrt(35)) ≈ 0.70

z2 = (68 - 65) / (8 / sqrt(35)) ≈ 2.08

Using a standard normal distribution table or calculator, we can find the probability that a z-score is between 0.70 and 2.08 to be approximately 0.2190. Therefore, the probability of randomly selecting 35 students (all from the same class) that have a sample mean reading ability test score between 66 and 68 is approximately 0.2190.

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Answer:

0

0.054

0.405

0.45

0.54

8

Step-by-step explanation:

The displacement x(t) for overdamped oscillations is given by x(t) = (cosh βt + sin βt) [(A + B) cosh ωt + (A - B) sinh ωt].

The correct expression for the displacement x(t) in terms of hyperbolic functions is:

B. x(t) = (cosh βt + sin βt) [(A + B) cosh ωt + (A - B) sinh ωt]

To show this, let's start with the given expression x(t) = e^(-βt) [A e^(ωt) + B e^(-ωt)] and rewrite it in terms of hyperbolic functions.

Using the relationships e^y = cosh(y) + sinh(y) and e^(-y) = cosh(y) - sinh(y), we can rewrite the expression as:

x(t) = [cosh(βt) - sinh(βt)][A e^(ωt) + B e^(-ωt)]

= [cosh(βt) - sinh(βt)][(A e^(ωt) + B e^(-ωt)) / (cosh(ωt) + sinh(ωt))] * (cosh(ωt) + sinh(ωt))

Simplifying further:

x(t) = [cosh(βt) - sinh(βt)][A cosh(ωt) + B sinh(ωt) + A sinh(ωt) + B cosh(ωt)]

= (cosh(βt) - sinh(βt))[(A + B) cosh(ωt) + (A - B) sinh(ωt)]

Comparing this with the given options, we can see that the correct expression is:

B. x(t) = (cosh βt + sin βt) [(A + B) cosh ωt + (A - B) sinh ωt]

Therefore, option B is the correct answer.

The displacement x(t) for overdamped oscillations is given by x(t) = (cosh βt + sin βt) [(A + B) cosh ωt + (A - B) sinh ωt].

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The values of a, b, c are 152°, 28°, 152° respectively.

Angles around a point describes the sum of angles that can be arranged together so that they form a full turn.

The sum of angles at a point will give 360°.

This means that a + b + c + 28 = 360

c +28 = 180° ( angle on a straight line)

c = 180 -28

c = 152°

c = a( alternate angles are equal)

therefore the value of a = 152°

b = 28( alternate angles are equal)

therefore the value of b is 28

therefore the values of a, b, c are 152°, 28°, 152° respectively

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Answer:

\(\frac{-5}{9}\)

Step-by-step explanation:

The slope of two parallel lines is the same. As long as the y-intercept is different then, the lines are parallel. Therefore, if the slope of line b is \(\frac{-5}{9}\) then the slope of line c must also be \(\frac{-5}{9}\).

Answer:

1600 ml, 400 ml, 1200 ml

Step-by-step explanation:

Given ratios are: 4:1:3

Let the shares of the given ratios be 4x, x, 3x

\( \therefore \: 4x + x + 3x = 3200 \\ \\ \therefore \: 8x = 3200 \\ \\ \therefore \: x= \frac{ 3200}{8} \\ \\ \therefore \: x=400 \\ \\ \implies \\ 4x = 4 \times 400 = 1600 \\ \\ 3x = 3 \times 400 = 1200 \\ \\ \)

Let's simplify the expression step by step: Expand the squared term:

(x - 3y)² = (x - 3y)(x - 3y) = x² - 6xy + 9y²

Expand the second term:

3(x + y)(x − 4y) = 3(x² - 4xy + xy - 4y²) = 3(x² - 3xy - 4y²)

Expand the third term:

x(3x + 4y + 3) = 3x² + 4xy + 3x

Now, let's combine all the expanded terms:

(x - 3y)² + 3(x + y)(x − 4y) + x(3x + 4y + 3)

= x² - 6xy + 9y² + 3(x² - 3xy - 4y²) + 3x² + 4xy + 3x

Combining like terms:

= x² + 3x² + 3x² - 6xy - 3xy + 4xy + 9y² - 4y² + 3x

= 7x² - 5xy + 5y² + 3x

The simplified form of the expression is 7x² - 5xy + 5y² + 3x.

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Answer:

The picture that shows a proper reflection across the red dashed line is figure B

Explanation:

Given the figure in the attached image, we want to determine the picture that shows a proper reflection across the red line.

We can observe that for the figure A, the dimension of the preimage and the image are not the same. So, figure A does not show a proper reflection across the red dash line.

For figure B, the dimension and shape of the preimage is the the same as the image (they are congruent).

Therefore, The picture that shows a proper reflection across the red dashed line is figure B

Answer:p

=

2

,

−

8

7

Decimal Form:

p

=

2

,

−

1.

¯¯¯¯¯¯¯¯¯¯¯¯

142857

Mixed Number Form:

p

=

2

,

−

1

1

7

Step-by-step explanation:

Answer:

Try 17

Step-by-step explanation:

we will use the formula of tan(A+B)= (tanA+tanB)/(1-tanAtanB)

and tan(A-B)= (tanA-tanB)/(1+tanAtanB)

tan[(pie/4)+(x/2)]= [1+tan(x/2)]/[1-tan(x/2)] ......(1)

tan[(pie/4)-(x/2)]= [1-tan(x/2)]/[1+tan(x/2)]......(2)

now add the equation (1) and (2) which is LHS of question. So we get:

{[1+tan(x/2)]^2 + [1- tan(x/2)]^2}/1-tan^2(x/2)=2[1+tan^2(x/2)]/1-tan^2(x/2)= 2/cosx = 2secx =RHS

Hence proved.

Answer:

72 people.

Step-by-step explanation:

4 out of 10 is 40%. Now apply that to 180. 40% of 180 is 72. Hope this helps.

Answer:

3 1/2 is the closest

Step-by-step explanation:

Theres 3 that are full and 2/5

Answer:

its 3 1/2 or c

Step-by-step explanation:

Answer:

\(10 - 20x + 8x = - 19x + 52 \\ 10 - 52 = 20x - 19x \\ - 42 = x\)

The value of x is approximately 7.42857. let's solve for x in the equation: 2(5 - 10x) + 8x = -19x + 52

Step 1: Distribute the 2 on the left side of the equation:

10 - 20x + 8x = -19x + 52

Step 2: Combine like terms on the left side:

-20x + 8x = -12x

Step 3: Move -19x to the left side by adding 19x to both sides of the equation:

-12x + 19x = 7x

Step 4: Now, we have:

7x = 52

Step 5: To solve for x, divide both sides by 7:

x = 52 / 7

x ≈ 7.42857 (rounded to 5 decimal places)

So, the value of x is approximately 7.42857.

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Answer:

5x4=20

20x2=40

Step-by-step explanation:

Answer:

4 * 5 * 2 + 3 - 2 - 1

Step-by-step explanation:

remember pemdas

4 * 5 * 2 + 3 - 2 - 1 = 40

"Financial" as it is not an effectiveness MIS metric.

To determine which one is not an effectiveness MIS metric, we need to understand the purpose of these metrics. Effectiveness MIS metrics measure how well a system is achieving its intended goals and objectives.

Customer satisfaction is a common metric used to assess the effectiveness of a system. It measures how satisfied customers are with the product or service provided.

Conversion rates refer to the percentage of website visitors who complete a desired action, such as making a purchase. This metric is often used to assess the effectiveness of marketing efforts.

Financial metrics, such as revenue and profit, are crucial indicators of a system's effectiveness in generating financial returns.

Response time measures the speed at which a system responds to user requests, which is an important metric for evaluating system performance.

Therefore, based on the given options, "Financial" is not a type of effectiveness MIS metric. It is a separate category of metrics that focuses on financial performance rather than the overall effectiveness of a system.

In summary, the answer is "Financial" as it is not an effectiveness MIS metric.

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