Help if you can please.​

Answer:

concentration = mol/volume = 4/2 = 2M

Answer:

1. A. 9 eggs

2. B. 5:3

3. C. Exactly 44 g

4. C. Mass and atoms only

5. D. 6.81 g of PH₃

6. C. 88.4%

7. B. O₂

8. D. 30.8 g CO₂

9. B.

10. B.

11. C. 99 g

12. D. mole ratio

13. C. Theoretical

14. A. 6.0 mol H₂O

15. D. 39.7 g CH₃OH

16. A. 650 g HgO

17. D. 8.8 mol H₂

18. B. 82.6%

Explanation:

1. The number of eggs it takes to make 1 cake = 3 eggs

The number of eggs it takes to make 3 × 1 = 3 cake = 3 × 3 = 9 eggs

Therefore, the correct option is;

A. 9 eggs

2. The given reaction is presented as follows;

C₃H₈(g) + 5O₂(g) → 3CO₂(g) + 4H₂O(l)

In the above reaction, we have;

Moles of , O₂, reacted = 5 moles

Moles of , CO₂, produced = 3 moles

The ratio of the of O₂ reacted to moles of CO₂ produced = 5 moles:3 moles

∴ The ratio of the of O₂ reacted to moles of CO₂ produced = 5:3

The correct option is;

B. 5:3

3. The reaction is presented as follows;

O₂ (g) + C(s) → CO₂ (g)

From the reaction, 1 mole (12 g) of carbon produces 1 mole of CO₂

The molar mass of CO₂ = The mass of 1 mole of CO₂ = 44.01 g/mol

Given that the reaction is completed, the mass of CO₂ produced = The mass of 1 mole of CO₂ ≈ 44 g

The correct option is;

C. Exactly 44 g

4. The given reaction is presented as follows;

N₂ + 3 F₂ → 2NF₃

The initial number of atom = 2 + 6 = 8

The final number of atom = 2 × 4   = 8

∴ The initial number of atom = The final number of atom

Therefore, the number of atoms is conserved;

The mass of the reactants ≈ 28 g/mol + 3 × 37.996806 g/mol ≈ 141.993612 g/mol ≈ 142 g/mol

The mass of the product ≈ 2 × 71 g.mol = 142 g/mol

∴ The mass is conserved

Moles of reactants = 1 + 3 = 4

Moles of products = 2

∴ The number of moles is not conserved

The correct option is

C. Mass and atoms only

5. The molar mass of P₄ = 123.895048 g/mol

One mole of P₄ (123.895048 g) produces four moles (4 × 34.00) of PH₃

6.20 g of P₄. will produce (4 × 34.00)/(123.895048) × 6.20 g ≈ 6.80576 g ≈ 6.81 g

The correct option is D. 6.81 g of PH₃

6. The percentage yield = ((The actual yield)/(The ideal yield)) × 100

The actual yield of silver = 38.1 g

The ideal yield of silver = 43.1 g

∴ The percentage yield = ((38.1 g)/(43.1 g)) × 100 = 88.3990719258% ≈ 88.4%

The percentage yield = 88.4%

The correct option is C. 88.4%

7. The given chemical equation is presented as follows;

CS₂ (g) + 3 O₂ (g) → CO₂ (g) + 2 SO₂ (g)

The number of moles in 192 g of O₂ = 192 g/(32 g/mol) = 6 moles

Given that 3 moles of O₂ reacts with 1 mole of CS₂ to produce 1 mole of CO₂ and 2 moles SO₂,  therefore 2 × 3 = 6 moles of O₂ will reacts with 2 × 1 = 2 moles of CS₂ to produce 2 moles of CO₂ and 4 moles SO₂

∴ The limiting reactant is;

B. O₂

8. The given chemical equation is presented as follows;

2 C₈H₁₈ (g) + 25 O₂ (g) → 16 CO₂ (g) + 18 H₂O (l)

The number of moles in 10 g of C₈H₁₈, n₁ = (10 g)/(114.26 g/mol)

The number of moles of CO₂ produced, n₂ = (10 g)/(114.26 g/mol) × 16/2 ≈ 0.7 moles

The mass of CO₂ produced, m ≈ 44.01 × n₂ ≈ 44.01 g/mol × 0.7 moles ≈ 30.807 grams ≈ 30.8 grams

The theoretical yield of CO₂ from completely burning 10.0 g of C₈H₁₈ ≈ 30.8 grams of CO₂

The correct option is D. 30.8 g CO₂

9. The correct option is B. The limiting reactants determine the maximum amount of product that can be formed

10. Option B, which has 3 atoms of each element combining to form a product with 1 atom of one element and 2 atoms of the other element

The correct option is B.

11. By the conservation of mass, we have;

The mass of the reactants = The mass of the products

Let 'x' represent the mass of zinc in the products of the reaction

Therefore, we have;

61 g of calcium + 207 g of zinc chloride = 169 g of calcium chloride + x g of Zinc

∴  x g = 61 g + 207 g - 169 g = 99 g

The mass of zinc in the products of the reaction, x g = 99 g

The correct option is;

C. 99 g

12. The quantity that must be used to convert from one chemical substance to another is the mole ratio

The correct option is D. mole ratio

13. The maximum mass of the product that could form in a reaction is called the theoretical yield, which is option C.

The correct option is C. Theoretical

14. 1 mole of O₂ produces 2 moles of water (H₂O), therefore;

3 × 1 = 3.0 moles of O₂ will produce 3 × 2 = 6 moles of H₂O

The correct option is

A. 6.0 mol H₂O

15. 2 mole × 2.02 g/mol = 4.04 g of H₂ (g) produces 32.05 g CH₃OH (l)

∴ 5 g of H₂ (g) will produce 32.05 g × 5/4.04 ≈ 39.6658416 g ≈ 39.7 g of CH₃OH

The correct option is;

D. 39.7 g CH₃OH

16. 2 (2 × 216.59 g = 433.18 g) moles of HgO produces 1 mole of O₂

1.5 mole of O₂ will be produced by 1.5 × 2 = 3 moles (3 × 216.59 g = 649.77 g ≈ 650 g) of HgO

The correct option is A 650 g HgO

17. 3 moles of H₂ produces 2 moles of NH₃

The number of moles of NH₃ in 100 g of NH₃, n = 100 g/(17.04 g/mol) = 5.868544 moles

The number of moles of H₂ that will produce 5.868544 moles of NH₃ = 3/2 × 5.868544 moles = 8.802816 moles ≈ 8.8 moles

Therefore, the correct option is;

D. 8.8 mol H₂

18. The theoretical yield of PbO = (223.2/331.2) × 9.90 g = 6.67173913 g

The percentage yield = (5.51 g)/(6.67173913 g) × 100 ≈ 82.6%

The correct option is option B 82.6%.

The power required by the "active Na⁺ pumping" system to produce this flow against the +25 mV potential difference is approximately 4 × 10⁻¹⁷ W.

To calculate the power required by the "active Na⁺ pumping" system, we need to consider the current (rate of ion movement) and the potential difference across the axon. Power is given by the equation:

Power = Current × Voltage

Given:

Current (I) = 5 × 10⁻⁷ mol/(m²·s)

Voltage (V) = +25 mV = +25 × 10⁻³ V (since 1 mV = 10⁻³ V)

To determine the power, we need to convert the current to amperes (A) and multiply it by the voltage:

I (in A) = Current × elementary charge (e)

e = 1.6 × 10⁻¹⁹ C (charge of an electron)

Now we can calculate the power:

Power = I × V

First, let's convert the current from mol/(m²·s) to A/m²:

I (in A/m²) = Current (in mol/(m²·s)) × Avogadro's number (Nₐ) / time (s)

Nₐ = 6.022 × 10²³ mol⁻¹ (Avogadro's number)

Now, we can calculate the power:

Power = I (in A/m²) × V (in V)

Note: We assume the axon is a cylinder with a circular cross-section.

Given:

Length of axon (L) = 10 cm = 0.1 m

Diameter of axon (d) = 20 μm = 20 × 10⁻⁶ m

To calculate the cross-sectional area (A) of the axon, we use the formula for the area of a circle:

A = π × (d/2)²

Now, we can calculate the power:

Power = I (in A/m²) × V (in V) × A (in m²)

Substituting the given values:

A = π × (20 × 10⁻⁶ / 2)² = π × 100 × 10⁻¹² m²

Power = (5 × 10⁻⁷ A/m²) × (25 × 10⁻³ V) × (π × 100 × 10⁻¹² m²)

Simplifying the expression:

Power ≈ 4 × 10⁻¹⁷ W

Rounding to one significant figure, the power required by the "active Na⁺ pumping" system to produce this flow against the +25 mV potential difference is approximately 4 × 10⁻¹⁷ W.

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The rate of diffusion of butane gas at the same temperature is approximately 240 m/s.

The rate of diffusion of a gas is directly proportional to its velocity at a given temperature. Therefore, we can use the ratio of the velocities of neon and butane gases to estimate the rate of diffusion of butane gas.

The molar mass of neon is 20.18 g/mol, and the molar mass of butane is 58.12 g/mol. Since both gases are at the same temperature, their velocities are proportional to the square root of the ratio of their molar masses:

\(\sqrt{(20.18 g/mol / 58.12 g/mol) }\)≈ 0.534

Therefore, we can estimate that the rate of diffusion of butane gas is about 0.534 times the velocity of neon gas. Multiplying the velocity of neon gas by this ratio, we get:

449 m/s x 0.534 ≈ 240 m/s

So, we can estimate that the rate of diffusion of butane gas at the same temperature is approximately 240 m/s.

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Answer: weathering due to freezing and thawing

Explanation:

The reason that caused these cracks to form is weathering due to freezing and thawing.

Weathering simply means the breaking down of rocks. In this situation, the boulder is freezed and thawed and due to this, as time progresses, it'll gradually be broken down. This is the reason why Mike saw the cracks even though there were no cracks the last time he went hiking.

Recrystallization of the chalcone before hydrogenation is important for several reasons.

Firstly, recrystallization helps to purify the chalcone by removing impurities such as unreacted starting materials, side products, or catalyst residues. Purifying the chalcone is crucial for obtaining accurate and consistent results in the subsequent hydrogenation reaction.

Secondly, recrystallization allows for the isolation of a single crystalline form of the chalcone, which is important for controlling the reaction conditions and achieving reproducible results. Different crystalline forms or crystal structures of the chalcone may have varying reactivity or accessibility to the reactants, potentially affecting the outcome of the hydrogenation reaction.

Furthermore, recrystallization helps to improve the overall yield and efficiency of the hydrogenation process. By removing impurities and obtaining a pure chalcone sample, the hydrogenation catalyst can work more effectively without interference from contaminants. This can result in higher conversion rates and selectivity towards the desired hydrogenation product.

Overall, recrystallization plays a crucial role in purifying and preparing the chalcone for the hydrogenation reaction, ensuring accurate results, reproducibility, and optimal reaction conditions.

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Option D, NaCl(aq) + AgNO3(aq) → NaNO3(aq) + AgCl(s), is the balanced chemical equation that represents a single-replacement reaction.

What is Replacement Reaction?

In chemistry, a replacement reaction is a type of chemical reaction where one element replaces another in a compound. The general formula for a replacement reaction is:

A + BX → AX + B

where A and B are elements, and X is an anion that can combine with A and B. In this reaction, A replaces B in the compound BX, forming a new compound AX and releasing the element B as a free element. Replacement reactions can be of two types: single replacement reactions and double replacement reactions, depending on whether one or two elements are replaced in the reaction.

In this reaction, sodium (Na) replaces silver (Ag) in the compound AgNO3 to form NaNO3, and silver is released as a free element in the form of AgCl.

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Answer:

The answer is SiO2

Explanation:

Because nonmetals are those who gain electrons and form ve ions

Answer:

d.

Explanation:

Answer:

D!

Explanation:

A is not true! When big meteors fall into the ocean, they cause mega-tsunamis I think, which does a lot of damage.

B, no, Uranus does too.

C, I think this is untrue, red wavelength and reflects the blue the blue!

D, is so true! A lot of reliable sources on this one!

Sorry if I did any wrong, I haven't learn chemistry in school yet.

The limiting reactant is potassium aluminum sulfate.

To determine the limiting reactant, we need to compare the amount of each reactant to the stoichiometry of the balanced chemical equation. The balanced equation for the reaction between ammonium hydroxide (NH4OH) and potassium aluminum sulfate (KAl(SO4)2) is:

2 NH4OH + KAl(SO4)2 -> Al(OH)3 + (NH4)2SO4 + K2SO4

From the equation, we can see that the stoichiometric ratio between ammonium hydroxide and potassium aluminum sulfate is 2:1. Therefore, we need twice as many moles of ammonium hydroxide as potassium aluminum sulfate.

To calculate the moles of each reactant, we use the formula:

moles = concentration (M) × volume (L)

For the ammonium hydroxide:

moles of NH4OH = 3.0 M × 0.100 L = 0.300 mol

For the potassium aluminum sulfate:

moles of KAl(SO4)2 = mass (g) / molar mass (g/mol)

moles of KAl(SO4)2 = 30.0 g / (39.1 g/mol + 26.98 g/mol + 2(32.1 g/mol) + 4(16.0 g/mol)) = 0.083 mol

Since the stoichiometric ratio is 2:1, the moles of ammonium hydroxide are in excess.

To determine the theoretical yield of aluminum hydroxide (Al(OH)3), we need to convert the moles of the limiting reactant (potassium aluminum sulfate) to moles of the product using the stoichiometry of the balanced equation. From the balanced equation, we can see that the stoichiometric ratio between potassium aluminum sulfate and aluminum hydroxide is 1:1.The moles of aluminum hydroxide produced will be the same as the moles of potassium aluminum sulfate used, which is 0.083 mol.

To calculate the theoretical yield in grams, we use the formula:

mass = moles × molar mass

The molar mass of aluminum hydroxide (Al(OH)3) is (26.98 g/mol + 3(16.0 g/mol)) = 78.0 g/mol.

The theoretical yield of aluminum hydroxide is:

mass = 0.083 mol × 78.0 g/mol = 6.474 g

Therefore, the theoretical yield of aluminum hydroxide is 6.474 grams.

Aluminum hydroxide is a precipitate, which means it forms solid particles when the reaction occurs. It can be collected on a filter paper using a filtration process. Filtration is a common method to separate solids from liquids. The reaction mixture can be poured through a filter paper funnel, and the solid aluminum hydroxide particles will be trapped on the filter paper while the liquid and soluble salts (such as ammonium sulfate and potassium sulfate) pass through.However, it's important to note that the success of the filtration process depends on the particle size and the nature of the solid precipitate. If the particles of aluminum hydroxide are too fine or colloidal in nature, they may pass through the filter paper and affect the efficiency of the filtration. In such cases, additional techniques like centrifugation or using a finer filter may be required to achieve better separation.

Overall, collecting aluminum hydroxide on a filter paper is a feasible method in this scenario, provided the precipitate is of the appropriate size and nature for filtration.

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Answer:

2:38

Explanation:

Answer:

2.58 good luck with everything

The secondary color green may be composed of more than one color while red, blue and yellow are single colors. If you take red and blue and mix those together, the color purple will be formed.

Though, the shade of purple will depend on the ratio and type of red and blue shade. Since purple is a secondary color. The 2 colors that make purple are primary in nature.

Primary colors (or primary colours) are sets of colors that can be combined to make a useful range of colors. The primary colors are those which cannot be created by mixing other colors in a given color space.

A secondary color is a color made by mixing of two primary colors in a given color space.

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Answer:

Salinity is a measure of the 'saltiness' of seawater, or more precisely the amount of dissolved matter within seawater.

Answer:

i dont no this one plz the question is hard

Answer:

False

Explanation:

There are other power plants that make serious hazards to public health such as smoke. I am 90% sure this is that answer double check me on that though❤️

Answer:

bestie this is like 6th grade stuff

Explanation:

Answer:

A

Explanation:

Determine the mass number for each of the isotopes, which is obtained by adding the number of protons and the number of neutrons. Hence, isotope A has a mass number of 1, isotope B has a mass number of 2, and isotope C has a mass number of 3. To determine the average atomic mass, we multiply the atomic mass of each isotope by its abundance. Hence, we obtain (0.99985 × 1 amu) + (0.00015 × 2 amu) + (0.00 × 3 amu) = 1.00 amu

B. methylcyclopentane

F. propane

G. n-pentane are the following molecules would a flame ionization detector (FID) be sensitive to after separation on a gas chromatography column.

flame ionization detector(FID) The most used detector in gas chromatography is the flame ionization detector . Since practically all organic molecules include carbon atoms (C), the FID is sensitive to and capable of identifying them. As nitrogen, the primary component of air, won't burn under these circumstances, and chromatography the technology is also insensitive to moisture and carbon dioxide, hydrocarbons in the environment can be found using flame ionization detector (FID).

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Answer:

Knowing your lab equipment and their names will aid in having a successful experiment and may help in correcting errors.

If you do not know your lab equipment, that will only result in having a lack of knowledge of the equipment or not knowing how to correct a mistake in an experiment.

Explanation:

Hope I helped.

Answer:

b:   Neither atoms will have a full valence shell

Explanation:

I think sooo

Answer:

B

Explanation:

Answer: 2 AgNO3(aq) + NiCl2(aq) ⇒ 2 AgCl(s) + Ni(NO3)2 (aq)

Explanation:

An example of a secondary pollutant is option (c)- photochemical oxidants.

Secondary pollutants are formed when primary pollutants react with each other or with other substances in the atmosphere. Photochemical oxidants, such as ozone, are created through reactions involving sunlight and primary pollutants like VOCs (volatile organic compounds) and nitrogen oxides.

Hence, an example of a secondary pollutant is option (c)- photochemical oxidants.

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Answer:

Ring is made up off copper.

Explanation:

Given data:

Mass of ring = 89.2 g

Volume of water = 10 mL

Volume of water + ring = 20 mL

Ring is made up of = ?

Solution:

Volume of ring = (Volume of water + ring) - Volume of water

Volume of ring = 20 mL - 10 mL

Volume of ring = 10 mL

Density:

Density = mass/volume     ( 1 mL = 1 cm³)

d = 89.2 g/  10cm³

d = 8.92 g/cm³

Thus, ring is made up off copper.

Given that

• T1 = 290K,

• T2 = 250K

• V1 = 1L

• V2=...?

We will use Charles's law formula to determine the resulting volume

V1 / T1 = V2 / T2.

→V2 = (V1*T2 )/T1

=1*250/290

=0.86 L

This is true because when temperature decreases , volume also decreases .

C = m V . The unit of concentration is typically given as g/mL because the solute mass is frequently given in grammes and the volume is frequently given in milliliters. However, there are a tone of other mass and volume unit combinations that are possible.

Given that a solution consists of both a solute and a solvent, its total volume is equal to the sum of the volumes of both the solute and the solvent it contains.

A solution's concentration is an indicator of how much solute has dissolved in a specific volume of solvent or solution. When there is a significant amount of dissolved solute in a solution, it is said to be concentrated. When a dissolved solute is present in a solution, it is said to be diluted.

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