HELP ME ASAP THANK YOU !!

Answer:

Step-by-step explanation:

\(\dfrac{3+x}3=\dfrac{20}5\\\\3+x = 4\cdot3\\\\x=12-3 \\\\x= 9\)                               \(\dfrac{4+y}4=\dfrac{20}5\\\\4+y= 4\cdot4\\\\y=16-4 \\\\y=12\)

\(\dfrac{3+x+u}3=\dfrac{60}5\\\\3+9+u=12\cdot3\\\\u=36-12 \\\\u=24\)                      \(\dfrac{4+y+v}4=\dfrac{60}5\\\\4+12+v=12\cdot4\\\\v=48-16 \\\\v=32\)

Answer:

3

Step-by-step explanation:

Answer:

Im pretty sure the guy above me is right

Step-by-step explanation:

Answer:

284.72

Step-by-step explanation:

Multiply 0.76 x 190. you get 144.4. then you add what she makes so add 140.32 to get your answer of 284.72 :)

Remember to thank and mark brainiest if this helped!

Answer:

1) T = 0.76m + 140.32

2) $284.72

Step-by-step explanation:

→ Substitute m as 190

(0.76 × 190) + 140.32

→ Simplify

$284.72

Answer:

B

Step-by-step explanation:

A is Standard Intercept Form

B is Point Slope Form

The rest are used for other problems I'm unsure of

The system capacity is 2 units per minute, the bottleneck stage is Stage A, and the utilization of Stage 3 is 100%.

A line process has three processing stages with the characteristics given below:

Stage A B C Unit processing time(minutes) 1 2 3 Number of machines 1 1 2 Machine availability 90% 100% 100% Process yield at stage 100% 100% 100%

To determine the system capacity and the bottleneck stage and utilization of Stage 3:

The system capacity is calculated by the product of the processing capacity of each stage:

1 x 1 x 2 = 2 units per minute

The bottleneck stage is the stage with the lowest capacity and it is Stage A. Therefore, Stage A has the lowest capacity and determines the system capacity.The utilization of Stage 3 can be calculated as the processing time per unit divided by the available time per unit:

Process time per unit = 1 + 2 + 3 = 6 minutes per unit

Available time per unit = 90% x 100% x 100% = 0.9 x 1 x 1 = 0.9 minutes per unit

The utilization of Stage 3 is, therefore, (6/0.9) x 100% = 666.67%.

However, utilization cannot be greater than 100%, so the actual utilization of Stage 3 is 100%.

Hence, the system capacity is 2 units per minute, the bottleneck stage is Stage A, and the utilization of Stage 3 is 100%.

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Answer:

steps below

Step-by-step explanation:

cot 10° * cot 20° * cot 70° * cot 80° * cot 45°

= (cos 10°/sin 10°)*(cos 20°/sin 20°)*(cos 70°/sin 70°)*(cos 80°/sin 80°)* (1)

= (cos 10°*cos 80°)(cos 20°*cos 70°) / (sin 10°*sin 80°)(sin 20°*sin 70°)

= (1/2*(cos60°+cos90°)*1/2(cos50°+cos90°))/(1/2*(cos60°-cos90°)*1/2(cos50°-cos90°))    ... cos90° = 0     cos60° = 1/2

= (1/8*cos50°) / (1/8*cos50°)

= 1

Answer:

36 minutes

Step-by-step explanation:

100 boxes in 3 hours is a rate. It is how fast you are working in boxes per hour 100/3 boxesperhour.

But 3 doesn't go into 100 very neatly and its going to make all kinds of ugly fractions or decimals. But lets look at minutes. 3 hours is 3 × 60 minutes (bc there's 60 minutes in an hour) So you loaded 100 boxes in 180 minutes. That's 100/180 boxes per minute.

100/180 = 10/18

10/18 means 10 boxes in 18 minutes.

So times 2 on the top and the bottom gives you 20/36.

20/36 means 20 boxes in 36 minutes.

This is your answer. It will take 36 minutes to load 20 more boxes.

Answer:

open circle

Step-by-step explanation:

the open circle does not include the number. this is what you want because the solution is not equal to the number

The derivative (or jacobian) matrix, DF(x), of the nonlinear system x′=f(x) given by x'1=ax, x'2=bx2+c(x2)^3, where a,b, and c are constants, is [a 0; 0 2bx+3cx^2].

To find the derivative (or jacobian) matrix, DF(x), of the nonlinear system x′=f(x):

We first need to find the partial derivatives of each equation with respect to each variable.

For the first equation, x'1=ax,

the partial derivative with respect to x1 is a, and the partial derivative with respect to x2 is 0.

For the second equation, x'2=bx2+c(x2)^3,

the partial derivative with respect to x1 is 0, and the partial derivative with respect to x2 is 2bx + 3cx^2.

Putting these partial derivatives into a matrix, we get:

DF(x) =
[a     0]
[0    2bx+3cx^2]

Therefore, the derivative (or jacobian) matrix, DF(x), of the nonlinear system x′=f(x) given by x'1=ax, x'2=bx2+c(x2)^3, where a,b, and c are constants, is [a 0; 0 2bx+3cx^2].

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Answer:

There are 240 students in the school

Step-by-step explanation:

Givens

55% of the total number of students in a school are girls.

Equation

55/100 * x = 132

Solution

Multiply both sides of the equation  by 100

55/100x * 100  = 132 * 100

55x = 13200                          Divide by 55

55x/55  = 13200/55

x = 240

According to the question we have  the correct answer is option 2, with a volume of 1664 cubic units.

The volume of the solid lying under the circular paraboloid z = x^2 + y^2 and above the rectangle R = (-4, 4] x [-6, 6] can be found using a double integral. First, set up the integral with respect to x and y over the given rectangular region:

Volume = ∬(x^2 + y^2) dA

To evaluate this integral, we will use the limits of integration for x from -4 to 4, and for y from -6 to 6:

Volume = ∫(from -4 to 4) ∫(from -6 to 6) (x^2 + y^2) dy dx

Now, integrate with respect to y:

Volume = ∫(from -4 to 4) [(y^3)/3 + y*(x^2)](from -6 to 6) dx

Evaluate the integral at the limits of integration for y:

Volume = ∫(from -4 to 4) [72 + 12x^2] dx

Next, integrate with respect to x:

Volume = [(4x^3)/3 + 4x*(72)](from -4 to 4)

Evaluate the integral at the limits of integration for x:

Volume = 1664

Therefore, the correct answer is option 2, with a volume of 1664 cubic units.

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The absolute and local extreme values of the given function f(x) = x^3 - 2x^(2/3) on the interval [−8, 8] is 11.79.

To find the absolute extrema and local extrema of a function on a closed interval, we need to evaluate the function at the critical points and the endpoints of the interval.
First, we need to find the derivative of the function:

f'(x) = 3x^2 - (4/3)x^(-1/3)

Setting f'(x) equal to zero, we get:

3x^2 - (4/3)x^(-1/3) = 0

Multiplying both sides by 3x^(1/3), we get:

9x^(5/3) - 4 = 0

Solving for x, we get:

x = (4/9)^(3/5) ≈ 0.733

Next, we need to evaluate f(x) at the critical point and the endpoints of the interval:

f(-8) ≈ -410.38
f(8) ≈ 410.38
f(0.733) ≈ 11.79

Therefore, the absolute maximum value of f(x) on the interval [-8, 8] is approximately 410.38, and it occurs at x = 8. The absolute minimum value of f(x) on the interval is approximately -410.38, and it occurs at x = -8.

To find the local extrema, we need to evaluate the second derivative of the function:

f''(x) = 6x + (4/9)x^(-4/3)

At the critical point x = 0.733, we have:

f''(0.733) ≈ 7.28

Since f''(0.733) is positive, this means that f(x) has a local minimum at x = 0.733.

Therefore, the local minimum value of f(x) on the interval [-8, 8] is approximately 11.79, and it occurs at x = 0.733.

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Answer:

The common ratio is -2

Next three terms are 18, -36, and 72

Step-by-step explanation:

The common ratio is -2 since each consecutive term is being multiplied by -2

The next three terms are -9(-2) = 18, 18(-2) = -36, and -36(-2) = 72

Answer:

A -0.5

B 4.5, -2.25, 1.125

Step-by-step explanation:

A: 72× -0.5= -36

-36× -0.5= 18

18× -0.5= -9

B multiple everything by -0.5

The addition of the expression \((-8-\frac{1}{4}p )+(\frac{5}{8}p-7 )\) is \(-15+\frac{3}{8}p\)

A linear expression is an algebraic statement where each term is either a constant or a variable raised to the first power.

Therefore, let's add the given linear expression as follows:

Hence,

\((-8-\frac{1}{4}p )+(\frac{5}{8}p-7 )\)

Hence, let's open the brackets of the expression as follows

\(-8-\frac{1}{4}p +\frac{5}{8}p-7\)

Combine like terms as follows;

\(-8-7-\frac{1}{4}p +\frac{5}{8}p\)

\(-15+\frac{-2p+5p}{8}\)

\(-15+\frac{3}{8}p\)

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The probability of drawing a red marble is 0.5

Probability is a way to determine how likely something is to happen. Many things are difficult to forecast with absolute confidence. Using it, we can only make predictions about how probable an event is to happen, or its chance of happening. Probability can range from 0 to 1, with 0 denoting an impossibility and 1 denoting a certainty.

Probability of an event=\(\frac{Number of Favourable outcomes}{Total number of outcomes}\)

In this problem, a single marble is drawn from a box of 36 marbles: 18 red and 18 green. We are told that five draws have to be done. The event is  independent of the others. The probability of drawing a red marble will always be the same in this situation. Since every marble is equally likely to be drawn, the probability of drawing red is

P(R)=\(\frac{Number of Favourable outcomes}{Total number of outcomes}\)

Here the favorable outcome is number of red balls and the total number of outcomes is total number of balls

=18/(18+18)

=18/36

=1/2

=0.5

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-6 = 3x - 6y

4x = 4 + 5y

ok

x = (4 + 5y)/4

Substitution

-6 = 3[(4 + 5y)/4] - 6y

-6 = [12 + 15y]/4 - 6y

-6 + 6y = [12 + 15y]/4

-24 + 24y = 12 + 15y

24y - 15y = 12 + 24

9y = 36

y = 36/9

y = 4

x = (4 + 5(4))/4

x = [4 + 20)/4

x = 24/4

x = 6

Solution x = 6, y = 4

Answer:

x < -1/2

Step-by-step explanation:

x - 8 > 5x

-8 > 5x -x

-8 > 4x

Divide through by 8

-1/2 > x or x < -1/2.

That is ofcourse if I interpreted the first part correctly.

Answer:

Step-by-step explanation:

If its a square all the sides are equal so therefor if it took up ten inches of the plate the length is 10 by 10 so 100 because the equation for length is base times height.

Answer:

answer is 2

Step-by-step explanation:

as you know the speed is calculated by dividing the distance travelled by time spent (s=d/t)

so we can write this as d/t=100

when u make d as the subject u get d=100t

Answer:

119,318

Step-by-step explanation:

Answer:

Step-by-step explanation:

espera y termino y te ayudo vale que me falta poco

Answer:

-56

Step-by-step explanation:

Equation: (4 * +1) (2 * -7)

Simplify: (4 * 1)(2 * - 7)

Multiply: (4)(-14)

Answer: -56

I hope this helps, have a nice day :D

Answer:

Step-by-step explanation:

,,,,,,,,,,,,,,,,,,,,,,,,,,,,,

Using trigonometric relations, we will see that:

sin(θ ) = -0.8

For any point (x, y), the angle between the positive x-axis and the ray that connects the origin with the point (x, y) is:

θ = Atan(y/x)

In this case, the point is (3, -4), then the angle is:

θ = Atan(-4/3) = -53.13°

Then the sine of theta is:

sin(θ  = -53.13°) = -0.8

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If quadrilateral JKLM were in third quadrant then the coordinates will be (-1,0),(-4,-1),(-4,-2)(-1,-2)

Given Quadrilateral JKLM is in fourth quadrant and coordinates (1,0),(4,-1),(4,-2)(1,-2)

We know that the coordinates of x used to negative in third quadrant and positive in fourth quadrant. Coordinates of y used to negative in third and fourth quadrant.

So in order to change the coordinates from fourth to third we need to change the coordinates of x axis to negative and the coordinates will be :

Coordinates of J will change from (1,0) to (-1,0)

Coordinates of  K will change from(4,-1) to (-4,-1)

Coordinates of L will change from (4,-2) to (-4,-2)

Coordinates of M will change from (1,-2) to (-1,-2).

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The length of the line segment is given by the distance equation

D = 7.2 units

The distance of a line between 2 points is always positive and given by the formula

Let the first point be A ( x₁ , y₁ ) and the second point be B ( x₂ , y₂ )

The distance between A and B is D , and the distance D is

Distance D = √ ( x₂ - x₁ )² + ( y₂ - y₁ )²

Given data ,

Let the distance of the line segment between two points be D

Now , the equation will be

Let the first point be represented as P ( 1 , 6 )

Let the second point be represented as Q ( 7 , 2 )

Now , distance between P and Q is D , and the distance D is

Distance D = √ ( x₂ - x₁ )² + ( y₂ - y₁ )²

D = √ ( 1 - 7 )² + ( 6 - 2 )²

On simplifying the equation , we get

D = √ ( -6 )² + ( 4 )²

D = √ ( 36 + 16 )

D = √ 52

D = 7.2 units

Hence , the distance is 7.2 units

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The total mass of the lamina is 32π units, the moment about the x-axis is (32/5), the moment about the y-axis is 0, the center of mass is (0, 1/(5π)), and the moment of inertia about the origin is (64/7)π.

To find the total mass, we need to integrate the density function over the given region

m = ∬ρ(x,y) dA

where ρ(x,y) = 2(x^2+y^2) and the region is x^2+y^2 ≤ 16 in the first quadrant. Using polar coordinates, we have

m = \(\int\limits^0_\(pi /2\) \(\int\limits^0_4\) 2r^2 r dr dθ

= 2 \(\int\limits^0_\(pi /2\) [r^4/2]₀^4 dθ

= 2 \(\int\limits^0_\(pi /2\) 32 dθ

= 32π

So the total mass is 32π.

To find the moment about the x-axis, we need to integrate the product of the density function and the distance from the x-axis

Mx = ∬ρ(x,y) y dA

Using polar coordinates, we have

Mx = \(\int\limits^0_\(pi /2\)\(\int\limits^0_4\)2r^4 sinθ dr dθ

= 2\(\int\limits^0_\(pi /2\) [r^5/5]₀^4 sinθ dθ

= (32/5) \(\int\limits^0_\(pi /2\) sinθ dθ

= (32/5)

So the moment about the x-axis is (32/5).

To find the moment about the y-axis, we need to integrate the product of the density function and the distance from the y-axis

My = ∬ρ(x,y) x dA

Using polar coordinates, we have

My =\(\int\limits^0_\(pi /2\) \(\int\limits^0_4\) 2r^4 cosθ dr dθ

= 2 \(\int\limits^0_\(pi /2\) [r^5/5]₀^4 cosθ dθ

= 0

Since the region is symmetric with respect to the y-axis, the moment about the y-axis is zero.

To find the center of mass (X, Y), we need to use the following formulas

X = (My)/m

Y = (Mx)/m

From part B, Mx = (32/5), and from part A, m = 32π. Therefore:

Y = (Mx)/m = (32/5)/(32π) = 1/(5π)

From part C, My = 0. Therefore, X = 0. So the center of mass is located at (0, 1/(5π)).

To find the moment of inertia about the origin, we need to integrate the product of the density function and the distance squared from the origin

I = ∬ρ(x,y) (x^2+y^2) dA

Using polar coordinates, we have

I = \(\int\limits^0_\(pi /2\) \(\int\limits^0_4\) 2r^4 r^2 dr dθ

= 2\(\int\limits^0_\(pi /2\) [r^7/7]₀^4 dθ

= (128/7) ∫₀^(π/2) dθ

= (64/7)π

So the moment of inertia about the origin is (64/7)π.

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