Answers
Answer: 325 adult tickets
Step-by-step explanation:
721 = (a+71) + a
721 = 2a + 71
2a = 650
a = 325
Related Questions
Which pair of triangles can be proven congruent by SAS?
Answers
Answer:
i don't know
Step-by-step explanation:
i am lower grade srry
A die is rolled twice. What is the probability of showing a 1 on the first roll and an even number on the secondroll? Write your answer as a reduced fraction or whole number.Your answer is :
Answers
The probability of the die showing any given output is 1/6.
Then, the probability of showing a 1 on the first turn is 1/6.
On the second turn, the probability of showing an even number is 1/2 because half of the output numbers are even.
To find the probability of showing a 1 on the first turn and an even number on the second turn, multiply the probabilities of each event:
\(\frac{1}{6}\times\frac{1}{2}=\frac{1}{12}\)Therefore, the probability of showin a 1 on the first roll and an even number in the second roll is 1/12.
Which of the two graphs below show an outlier in the distribution of the quantitative variable? a) Boxplot only b) Both Histogram and Boxplot c) Neither d) Histogram only
Answers
To determine which of the two graphs (Boxplot and Histogram) shows an outlier in the distribution of the quantitative variable, we need to understand the characteristics of outliers in each type of graph.
An outlier is a data point that significantly deviates from the rest of the data in a distribution. Here's how outliers are represented in Boxplots and Histograms:
a) Boxplot only: If an outlier exists in the distribution, it will be shown as a separate data point outside the whiskers (the lines extending from the box) in the Boxplot. The Boxplot provides a visual representation of the quartiles and any outliers present.
b) Both Histogram and Boxplot: If an outlier exists in the distribution, it may be evident in both the Histogram and the Boxplot. The Histogram shows the frequency or count of data points in each bin or interval, and an outlier can be observed as an extreme value far from the majority of the data. In addition, the Boxplot will display the outlier as mentioned above.
c) Neither: If there are no outliers in the distribution, neither the Histogram nor the Boxplot will show any data points or indicators outside the expected range. The data points will be distributed within the usual range of the distribution, and no extreme values will be present.
d) Histogram only: In some cases, an outlier may be noticeable in the Histogram but not explicitly shown as a separate data point in the Boxplot. This can happen when the outlier is not extreme enough to be considered as an outlier based on the specific criteria used to determine outliers in the Boxplot.
Without examining the actual graphs or having specific information about the data, it is not possible to determine with certainty which option (a, b, c, or d) is correct. To make a definitive determination, you would need to analyze the graphs and assess the presence of extreme values that deviate significantly from the majority of the data.
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Researchers are investigating the effectiveness of using a fungus to control the spread of an insect that destroys trees. The researchers will create four different concentrations of fungus mixtures: O milliliters per liter (ml/L), 1.25 ml/L, 2,5 ml/L, and 3.75 ml/L, An equal number of the insects will be placed into 20 individual containers. The group of insects in cach container will be sprayed with one of the four mixtures, and the researchers will record the number of insects that are still alive in each container one week after spraying (a) Identify the treatments, experimental units, and response variable of the experiment Treatments Experimental units: Response variable: (b) Does the experiment have a control group? Explain your answer, (c) Describe how the treatments can be randomly assigned to the experimental units so that each treatment has the same number of units.
Answers
(b) Yes, the experiment has a control group.
(c) The treatments can be randomly assigned to the experimental units by randomly selecting 20 containers and assigning each of the four treatments to 5 containers.
a) Treatments: Four different concentrations of fungus mixtures (0 ml/L, 1.25 ml/L, 2.5 ml/L, and 3.75 ml/L).
Experimental units: 20 individual containers with a group of insects.
Response variable: Number of insects that are still alive in each container one week after spraying.
(b) A control group is used to compare the results of the treatment group to a group that is not exposed to the treatment.
In this experiment, the control group can be the group of insects that are not exposed to any of the fungus mixtures.
c) The treatments can be randomly assigned to the experimental units by randomly selecting 20 containers and assigning each of the four treatments to 5 containers.
This way, each treatment has the same number of units and the assignment of treatments to units is random, which reduces the risk of bias in the experiment.
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Use the dot product to find v when v=(-2 -1)
a. -1 c. √5
b. -3 d. √3
Answers
Since you're only given the one vector, I assume you're supposed to find the magnitude of v, or ||v||, using the dot product.
We have
v • v = (-2, -1) • (-2, -1) = (-2)² + (-1)² = 5
so that
||v|| = √(v • v) = √(5)
and the answer is C.
Answer:
C
Step-by-step explanation:
just trust
What are the roots of the quadratic equation 0 = 2x² + 12x-14?
1,6, -7
2,12,-14
-7,1
-1,7
Answers
The roots of the quadratic equation 0 = 2x² + 12x-14 is (C) x=-7 and x=1.
What is a quadratic equation?Any equation in algebra that can be written in the standard form where x stands for an unknown value and a, b, and c stand for known values is said to be a quadratic equation.
In general, it is assumed that a > 0; equations with a = 0 are regarded as degenerate since they become linear or even simpler.
So, the roots of 0 = 2x² + 12x-14 are:
2x² + 12x-14 = 0
2x² + 14x - 2x -14
2x(x + 7) - 2(x + 7)
(2x - 2) (x + 7)
Now, use the zero product property as follows:
2x - 2 = 0
2x = 2
x = 2/2
x = 1
And
x + 7 = 0
x = -7
Therefore, the roots of the quadratic equation 0 = 2x² + 12x-14 is (C) x = -7 and x = 1.
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Correct question:
What are the roots of the quadratic equation 0 = 2x² + 12x-14?
a. 1,6, -7
b. 2,12,-14
c. -7,1
d. -1,7
This is a model of Mrs. Johnson's classroom. Find the area. Draw lines to break composed
figure into simpler figures. Show your work. PLS HELPPP
Answers
Answer: The area is 190,944. To make it simpler, they could do 47,736 feet per side.
Step-by-step explanation: You find area by multiplying all sides.
The speed of light is about 300,000,000 meters per
second. That's about 3 * 108 meters per second. The
speed of sound in dry air is about 3 * 102 meters per
second.
Which travels faster?
Speed of Sound in Dry Air
Speed of Light
3 x 102 m/s
3 x 108 m/s
Answers
Answer: it’s speed of light
Which equation represents the graph?
Answers
Answer:
y=75x
Step-by-step explanation:
Answer:
y = 75x
Step-by-step explanation:
In 4 months, it is at 300. In 9 months, it is at 675. An increase of 375 in 5 months. So you will multiply 75 x 5 to get 375 which is the exact amount.
rank the steps involved in transforming one couple to another couple in a parallel plane in the correct order.
Answers
To rank the steps involved in transforming one couple to another couple in a parallel plane, here is the correct order:
Identify the initial couple and the desired final couple.
Determine the translation vector that will move the initial couple to the desired final couple.
Translate the initial couple using the determined translation vector. This will shift the entire couple in the parallel plane.
Verify that the translation has successfully moved the initial couple to the desired final couple.
If necessary, make any additional adjustments or transformations to align the initial and final couples precisely in the parallel plane.
Confirm that the final couple is now in the desired position and orientation relative to the initial couple, maintaining the parallelism of the plane.
By following these steps in order, you can effectively transform one couple to another in a parallel plane.
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Stefan sells Jin a bicycle for $114 and a helmet for $18. The total cost for Jin is 110% of what Stefan spent originally to buy the bike and helmet. How much did Stefan spend originally? How much money did he make by selling the bicycle and helmet to Jin?
Stefan originally spent $
Answers
Answer:
$12
Step-by-step explanation:
given:
Stefan sells jin a bicycle for $114 and a helmet for $18.
we're gonna add to get the total cost 114 + 18 = $132
The total cost is 110% of what he spent originally to buy the bike and helmet.
divide 110% by 100 to get the answer in decimal which if you calculate is 1.1
now we're gonna make a simple equation and assume what Stefan spends originally is x
1.1 * x = 132
1.1x = 132
(now we want x to be alone so we can find its value so divide both sides by 1.1 (division is the opposite of multiplication if, for example, we have 1.1 - x 1.1 is positive so take it to the other side it'll be negative))
after dividing x=120
therefore, he originally spent $120
and to find how much money Stefan made we're gonna subtract 132-120 = $12
Stefan made $12
In order to apply the chi-square test of independence, we prefer to have:
a. at least 5 observed frequencies in each cell. b. not more than 5 observations in each cell.
c. at least 5 expected observations in each cell.
d. at least 5 percent of the observations in each cell.
Answers
At least 5 expected observations in each cell in order to apply the chi-square test of independence, we prefer to have at least 5 expected observations in each cell. The correct answer is c.
The chi-square test of independence is a statistical method used to determine whether two categorical variables are independent or associated with each other.
To apply this test, it is preferred to have at least 5 expected observations in each cell of the contingency table. The expected frequency is calculated based on the assumption of independence between the two variables.
If the expected frequency is less than 5 in any cell, the chi-square test may not be valid and alternative methods, such as Fisher's exact test, should be considered. Having a sufficient sample size can also improve the accuracy and reliability of the test results.
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In the test for equality of treatment means across four treatments (A, B, C and D), an ANOVA analysis was undertaken yielding a significant F statistic (at the 5% level of significance) based on the data obtained. The conclusion is thus to reject the null hypothesis (H0: that the population means are equal across the four treatments).
a) Explain why it is not appropriate to conduct multiple post hoc independent samples t tests on all possible pairs of treatments with α = 0.05 in each of the tests. (5 marks)
b) Given that H0 is rejected, outline an appropriate approach in conducting a post hoc analysis to identify where differences are present across the treatments. (5 marks)
Answers
(a) Conducting multiple post hoc independent samples t-tests on all possible pairs of treatments with α = 0.05 is not appropriate due to an inflated Type I error rate.
When conducting multiple tests, the likelihood of obtaining at least one false positive result increases, leading to an increased chance of incorrectly rejecting the null hypothesis.
(b) To appropriately identify where differences are present across the treatments after rejecting the null hypothesis, a post hoc analysis using a method such as Tukey's Honestly Significant Difference (HSD) test or the Bonferroni correction can be employed. These methods control the overall Type I error rate by adjusting the significance level for each individual comparison, allowing for valid inferences about specific
(a) Conducting multiple post hoc independent samples t-tests on all possible pairs of treatments without adjusting the significance level can lead to an inflated Type I error rate. When performing multiple tests, the probability of obtaining at least one false positive result increases. In this case, conducting multiple t-tests with α = 0.05 for each test would result in a cumulative probability of a Type I error greater than 0.05. This means that the overall chance of incorrectly rejecting the null hypothesis across all tests would be higher than the desired significance level.
(b) To address this issue and identify where differences are present across the treatments after rejecting the null hypothesis in an ANOVA analysis, post hoc tests can be employed. One commonly used method is Tukey's Honestly Significant Difference (HSD) test. This test compares all possible pairwise differences between treatment means and provides adjusted confidence intervals for each comparison. The intervals can be used to determine if the differences are statistically significant. Another approach is the Bonferroni correction, which adjusts the significance level for each individual comparison to control the overall Type I error rate. The adjusted significance level is divided by the number of comparisons being made, ensuring that the overall probability of a Type I error remains at the desired level.
In summary, conducting multiple post hoc independent samples t-tests on all possible pairs of treatments without adjusting the significance level would result in an inflated Type I error rate. To appropriately identify differences across treatments, post hoc analyses such as Tukey's HSD test or the Bonferroni correction can be employed, which control the overall Type I error rate and provide valid inferences about specific pairwise differences while maintaining the desired level of confidence.
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I really need help for this please help
Answers
Answer:
Step-by-step explanation:willits A
one ship is steaming on a path whose equation is y=x^2+1 and another is steaming on a path whose equations is x+y=-4. Is there danger of a collision
Answers
There is no danger of a collision, as the two paths will never met, due to the negative discriminant of the quadratic function.
What is the discriminant of a quadratic equation and how does it influence the solutions?A quadratic equation is modeled by the general equation presented as follows:
y = ax² + bx + c
The discriminant of the quadratic function is given by the equation as follows:
Δ = b² - 4ac.
The numeric value of the coefficient and the number of solutions of the quadratic equation are related as follows:
Δ > 0: two real solutions.Δ = 0: one real solution.Δ < 0: two complex solutions.The equations for this problem are given as follows:
y = x² + 1.x + y = -4.Replacing the first equation into the second, we have that:
x + x² + 1 = -4
x² + x + 5 = 0.
The coefficients are:
a = 1, b = 1, c = 5.
Hence the discriminant is of:
Δ = 1² - 4 x 1 x 5
Δ = -19.
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the lines that contain the altitudes of a triangle are
Answers
The altitudes of a triangle are the perpendicular lines drawn from each vertex of the triangle to the opposite side.
The altitudes of a triangle are special lines that are perpendicular to the sides of the triangle. They are drawn from each vertex of the triangle to the opposite side. These lines intersect the opposite side at right angles. The intersection point is called the orthocenter of the triangle. Each triangle has three altitudes, one from each vertex. The lengths of the altitudes can vary depending on the shape and size of the triangle.
The altitudes of a triangle are useful in many geometric calculations and constructions. They help determine the height of the triangle, which is important in finding the area of the triangle. The altitudes also play a role in proving geometric theorems and properties related to triangles.
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Which of the factors listed below determine the width of a confidence interval? Select all that apply.The chosen level of confidence.The population mean.The relative size of the sample mean.The size of the standard error.
Answers
The factors that determine the width of a confidence interval are: The chosen level of confidence, The population mean, The relative size of the sample mean, The size of the standard error.
The factors that determine the width of a confidence interval are:
The chosen level of confidence: The higher the level of confidence required, the wider the interval will be.
The size of the standard error: A larger standard error will result in a wider interval.
The size of the sample: A smaller sample size will result in a wider interval.
The population mean does not directly determine the width of a confidence interval, but it can affect the calculation of the standard error. The relative size of the sample mean is not a factor that determines the width of a confidence interval.
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The starting and finish lines for a yearly race in Columbia are 3 miles apart. How far apart are
the starting line and the finish line on a map with a scale of 2 inches : 1 mile?
inches
Answers
Complete the following similarity statement for the figure below.
Answers
Answer:
Triangle JKLM ~ Triangle STUV
the sum of two numbers is 41 . the sum of 3 times the larger and 8 times the smaller is 203 . find the numbers.
Answers
Answer:
The numbers are 16 and 25
Find an expression equivalent to the one shown below.
(8^3)^9 ÷ 8^27
A. 1
B. 8
C. 1/8^15
D. 1/8
Answers
Answer:
I believe it would be A. 1
Step-by-step explanation:
\((8^{3} )^{9}\) ÷ \(8^{27}\) = 1
hope this helps
help appreciated xx
:)
Answers
Answer:
13pts
Step-by-step explanation:
If you're asking how many pints 6 qt and 1 or is then I believe it is 13 pt
Find the values of x and y in parallelogram PQRS.
PT=y
TR=4x+1
QT=2y
TS=4x+14
Answers
The values of x and y in parallelogram PQRS are x = 3 and y = 7.
In a parallelogram, opposite sides are equal in length. Based on this property, we can set up equations using the given information to solve for the values of x and y.
Given:
PT = y
TR = 4x + 1
QT = 2y
TS = 4x + 14
Since opposite sides of a parallelogram are equal, we can set up the following equations:
PT = QS (opposite sides)
TR = SR (opposite sides)
Substituting the given values into these equations, we get:
y = 4x + 14 (equation 1)
2y = 4x + 1 (equation 2)
We now have a system of equations (equation 1 and equation 2) that we can solve to find the values of x and y.
To solve the system, we can use the method of substitution. From equation 2, we can express y in terms of x:
y = (4x + 1)/2
Substituting this expression for y into equation 1, we have:
(4x + 1)/2 = 4x + 14
Now, we can solve for x:
4x + 1 = 8x + 28
-4x = 27
x = -27/4
However, upon closer inspection, we realize that the values of x and y must be positive since they represent lengths. Therefore, we discard the negative value for x.
Let's solve for y using the positive value of x:
y = (4(3) + 1)/2
y = (12 + 1)/2
y = 13/2
Since we need whole numbers, let's convert y to a whole number by multiplying both the numerator and denominator by 2:
y = (13/2) * (2/2)
y = 26/4
y = 13/2
Therefore, the values of x and y in parallelogram PQRS are x = 3 and y = 7.
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help a girl out pls!!!!
Answers
Answer:
Your answer would be D!
Step-by-step explanation:
name the line ........
Answers
Answer:
Step-by-step explanation:
l is line. It has no beginning and end point.
AB is a ray. It has a beginning point and has no end point.
CD is a segment and it has both beginning and end point.
∠1 is an angle.
a, b are parallel lines and t is transversal.
Suppose that f(1) = 1, f(4) = 5, f '(1) = 3, f '(4) = 3, and f '' is continuous. find the value of 4 1 xf ''(x) dx.
Answers
Answer: b
Step-by-step explanation:
I think
please help me!! this is due already and late
Answers
2.) A . None
Answer:
C. Minimum value = 1/11, maximum value = √17E. Minimum value = -5, maximum value = -4Step-by-step explanation:
Question 1c(x) = √xThe domain is:
1/121 ≤ x ≤ 17The range is:
√1/121 ≤ √x ≤ √171/11 ≤ √x ≤ √17Correct choice is C
Minimum value = 1/11, maximum value = √17Question 2d(x) = ∛xThe domain is:
{x | x∈R, -125 ≤ x ≤ -64}The range is:
∛-125 ≤ ∛x ≤ ∛-64-5 ≤ ∛x ≤ -4Correct choice is E
Minimum value = -5, maximum value = -4Do you guys know the equation to solve it and the answer?
Answers
Answer: Sorry i can't see that brah
Step-by-step explanation: Thanks homie
If the forecast for two consecutive periods is 1,500 and 1,400 and the actual demand is 1,200 and 1,500 , then the mean absolute deviation is 1) 500 2) 700 3) 200 4) 100
Answers
200 is the mean absolute deviation. Therefore, choice three (200) is the right one.
How to calculate the mean absolute deviation
The absolute difference between the predicted and actual values must be determined, added together, and divided by the total number of periods.
Forecasted values are as follows: 1,500 and 1,400
Values in actuality: 1,200 and 1,500
Absolute differences:
|1,500 - 1,200| = 300
|1,400 - 1,500| = 100
Now, we calculate the MAD:
MAD = (300 + 100) / 2 = 400 / 2 = 200
Therefore, 200 is the mean absolute deviation. Therefore, choice three (200) is the right one.
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Brainliest goes to whoever answers correctly try to show work ONLY if you can also if you want more points answer my other questions
Answers
Answer:
Hi, there your answer will be C. y=33/2x+425
Step-by-step explanation:
I tired uploading the picture on how I got my answer, but it keep saying inaapriate words which I didn't even said anything bad, but yeah trust me the answer is right.