HELP ME PLEASE!!!!!!!!

The point prevalence of brilliance at the end of Week 1 is 0.08 or 8%.

The point prevalence of brilliance at the end of Week 2 is 0.17 or 17%.

The point prevalence of brilliance at the end of Week 3 is 0.33 or 33%.

Using person-weeks as denominator, the incidence of brilliance over the course of the 10-week course is 0.017 or 1.7%

In epidemiology context, brilliance can be calculated through calculating point prevalence, cumulative incidence, and incidence rate. The provided data table can be used to determine the point prevalence, incidence, and incidence rate of brilliance among PHE 450 students. So, the calculations of point prevalence, cumulative incidence, and incidence rate based on the provided data are as follows:

The point prevalence of brilliance at the end of Week 1 can be calculated by the following formula; Point prevalence = Total number of existing cases at a given time ÷ Total population at that time

Student #8 was the only existing case of brilliance at the beginning of Week 1, so the point prevalence of brilliance at the end of Week 1 is; Point prevalence = 1 ÷ 12 = 0.08 or 8%.

The point prevalence of brilliance at the end of Week 2 can be calculated by the following formula; Point prevalence = Total number of existing cases at a given time ÷ Total population at that time

Student #3 and Student #8 were existing cases of brilliance at the beginning of Week 2, so the point prevalence of brilliance at the end of Week 2 is; Point prevalence = 2 ÷ 12 = 0.17 or 17%.

The point prevalence of brilliance at the end of Week 3 can be calculated by the following formula; Point prevalence = Total number of existing cases at a given time ÷ Total population at that time

Student #3, #4, #6, and #8 were existing cases of brilliance at the beginning of Week 3, so the point prevalence of brilliance at the end of Week 3 is; Point prevalence = 4 ÷ 12 = 0.33 or 33%.

The incidence of brilliance can be calculated by the following formula; Incidence = Total number of new cases ÷ Total person-weeks of observation

Student #5 and Student #7 developed brilliance during the 10-week course, so the incidence of brilliance over the course of the 10-week course is; Incidence = 2 ÷ 120 = 0.017 or 1.7%.

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The completed table shows the products of each term. we get

       |  2z  |  -4

____________________

22²       | 44z² |

__________|______|______

3zy       | 6zy  | -12z

__________|______|______

-2y²      | -4y² | 8y²

To use the box method for multiplying the two expressions, let's create a table with the terms of each expression:

         |  2z  |  -4

____________________

22²       |

__________|______|______

3zy       |

__________|______|______

-2y²      |

Now, we will multiply each term from the first expression with each term from the second expression and fill in the table:

         |  2z  |  -4

____________________

22²       | 44z² |

__________|______|______

3zy       | 6zy  | -12z

__________|______|______

-2y²      | -4y² | 8y²

The completed table shows the products of each term.

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The expression equivalent to the 5ⁿ/2ⁿ will be (5/2)ⁿ , (2/5)⁻ⁿ ,  (2.5)ⁿ , 2⁻ⁿ/5⁻ⁿ.Options A, B, D, and F are correct.

An equation is a statement that two expressions, which include variables and/or numbers, are equal. In essence, equations are questions, and efforts to systematically find solutions to these questions have been the driving forces behind the creation of mathematics.

It is given that, the expression is, 5ⁿ/2ⁿ

The expression can be written in different ways as,

5/2)ⁿ

(2/5)⁻ⁿ

(2.5)ⁿ

2⁻ⁿ/5⁻ⁿ

Thus, the expression equivalent to the 5ⁿ/2ⁿ will be (5/2)ⁿ , (2/5)⁻ⁿ ,  (2.5)ⁿ, 2⁻ⁿ/5⁻ⁿ. Options A, B, D, and F are correct.

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Answer:

1.8.09

2.-6

Step-by-step explanation:

1. 11b=89

b=89/11

8.09

2. 13+k/3=11

k/3=11-13

k/3=-2

k=-2*3

=-6

Answer:

Number 2 is - 6

Step-by-step explanation:

2. 13 + k/3 = 11

We can start off my subtracting 13 in both sides.

-13 + 13 + k/3 = 11 - 13

k/3 = -2. now we have to multiply 3 in both sides

3 x k/3 = -2 x 3

k = -6

Hope this helps!!

Answer:

£289.20

Step-by-step explanation:

13:2 = x:16 or 13/2 = x/16

cross multiply: 208 = 2x

simplify: x = 104

16 blue tiles x £2.80 each = £44.80

104 white tiles x £2.35 each = £244.40

44.80 + 244.40 = £289.20

its the second oneee

The exponential model for the population can be written as P = 20000 * 1.171^t, where P is the population after t years, 1.171 is the growth factor per year (100% + 17.1%), and 20000 is the initial population.

This equation assumes that the population grows continuously at a constant rate of 17.1% per year. It is an example of exponential growth, which means that the population increases at an increasingly faster rate over time.

Using this model, we can predict the population size at any point in the future. For example, after 5 years, the population would be P = 20000 * 1.171^5 = 41,992 organisms. It is important to note that this model is based on certain assumptions, such as unlimited resources and a constant growth rate, which may not always hold true in real-world scenarios.

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Answer:

See below.

Step-by-step explanation:

The domain of a function is simply the span of x-values the graph will encompass.

And the range of a function is simply the span of y-values the graph will encompass.

Since the function is a quadratic, the domain is all real numbers. From the graph, the graph will continue to expand left and right. Therefore, the domain is all real numbers.

In interval notation, this is:

\((-\infty,\infty)\)

And in set notation, this is:

\(\{x|x\in\mathbb{R}\}\)

For the range, notice that the graph is going downwards. In other words, the graph has a maximum value. From the graph, we can see that this maximum value is at y=-4. The graph never reaches any value above -4. Therefore, our range is all numbers equal to or less than -4.

In interval notation, this is:

\((-\infty,-4]\)

We use brackets because we include the -4 in the solution set.

Also, note that we write the infinity first because the smallest number should be on the left. [-4, -∞) would not be correct.

And in set notation, this is:

\(\{y|y\in\mathbb{R},y\leq 4}\}\)

Answer:

The answer is C \(\sqrt{97}\).

Step-by-step explanation:

Use the pythagorean theorem. \(a^{2} + b^{2} = c^{2}\). With a and b corresponding to the legs of the triangle.

(L2) An inscribed circle is one that encompasses a polygon so that it passes by each of the polygon's vertices.

A circumcircle, not an inscribed circle, is a circle that encircles a polygon at each vertex. A circle that is enclosed within a polygon and intersects each side of the polygon exactly once is said to be inscribed. A circumcircle, on the other hand, is a circle that goes through every vertex of the polygon, with its center located at the point where the perpendicular bisectors of the polygon's sides converge. The greatest circle that can be drawn within a polygon is the circumcircle, while the largest circle that can be drawn inside a triangle is the inscribed circle.

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Step-by-step explanation:

equation for a gradient is

m=(y¹-y²)/(x¹-x²)

again the ¹&² are not powers

so (x¹,y¹) and (x²,y²) would be

(-1,6) and (4,-4) respectively

so the gradient would be

(6+4)/(-1-4)

=-2

so the ans is

2=(y¹-y²)/(x¹-x²)

y¹-y²=2(x¹-x²)

y-6=2(x+4)

Note that I put (x, y) into (x¹,y¹)

and (-1,6) into (x²,y²)

(x²,y²) can also be (4,-4), which would lead to the same answer, as theyre the dots on the SAME line

For question 8, try to follow my steps, and figure out the gradient of the graph first, so u can understand what u should do when u see these kinds of questions

Answer:

(-1,6) and (4,-4)= y - 6 = -2 × (x+1)

(-2,2) and (6,6)= y - 2 = 1/2 × (x+2)

Step-by-step explanation:

Because the point slope formula for equations is y - y = m (x - x1)

The 0 element for the permutation group defined over n objects is an identity permutation, which is a permutation that does not change the positions of any elements in a set.

This identity element is denoted by an empty permutation and is often referred to as the "do-nothing" permutation. In other words, it leaves the elements in the set unchanged. It is the base element of the permutation group, meaning that when it is combined with any other permutation, it does not change the result of the permutation.

This means that when it is combined with any other permutation, the end result is the same as the initial permutation.

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Answer:

1.   70

Step-by-step explanation:

2.  105

Answer:

A: 70.311 repeat

B: 105.53

Step-by-step explanation:

im not sure if im correct but hope this helps

\(answer = 6 + 2b\\ solution \\ length = 3 \: m \\ breadth = b \: m \\ perimeter \: of \: rectangle = 2(l + b) \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 2(3 + b) \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 2 \times 3 + 2 \times b \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 6 + 2b \\ hope \: it \: helps \\ good \: luck \: on \: your \: assignment\)

The perimeter of the rectangle is P = 6 + 2b, where b is the width.

Given data:

To find the perimeter of a rectangle, we add the lengths of all its sides. In this case, the rectangle is 3 meters long and b meters broad.

The perimeter is calculated as follows:

Perimeter = 2 × (length + breadth)

Given that the length is 3 meters and the breadth is b meters, substitute these values into the formula:

Perimeter = 2 × (3 + b)

Simplifying the expression,

Perimeter = 6 + 2b

Hence, the perimeter of the rectangle is 6 + 2b meters.

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The second derivative of w = 7z² eᶻ with respect to z is 14zeᶻ(z+1).

To find \(\frac{d²w}{dz²}\) for the function w = 7z² eᶻ, we need to take the second derivative of w with respect to z.

First, we find the first derivative of w with respect to z:

\(\frac{dw}{dz} = 14z^z\)

Then, we can take the second derivative of w with respect to z:

\(\frc{d²w}{dz²} = \frac{d}{dz}(\frac{dw}{dz)}\)

\(= \frac{d}{dz}(14ze^z)\)

= \(14e^z + 14z(e^z)'\) (using the product rule)

= \(14e^z + 14ze^z\)

Therefore, \(\frac{d²w}{dz²} = 14e^z + 14ze^z.\)

Substituting this result into d²w/dz² = ___ yields:

\(\frac{d²w}{dz²} = 14e^z + 14ze^z = 14z²e^z + 14ze^z = 14ze^z(z+1)\)

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Here is a general outline of how you can compare the populations using measures of center and variation:

Determine the measure of center for each population. The measure of the center could be the mean, median, or mode.

Determine the measure of variation for each population. The measure of variation could be the range, interquartile range (IQR), or standard deviation.

Compare the measures of the center for each population. If one population has a higher measure of center than the other, it means that the values in that population are generally larger than the values in the other population.

Compare the measures of variation for each population. If one population has a larger measure of variation than the other, it means that the values in that population are more spread out or diverse than the values in the other population.

To express the difference in the measures of the center as a multiple of the measure of variation, you would need to divide the difference in the measures of the center by the measure of variation. For example, if the mean goals scored per game for Team A is 2.5 and the mean for Team B is 3.0, the difference in the means is 0.5. If the standard deviation for Team A is 0.8 and the standard deviation for Team B is 0.7, the mean difference is 0.5 / 0.7 = 0.7142. This means that the difference in the means is approximately 0.7 times the measure of variation.

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The answers are:

\((a) \( \vec{a} \times \vec{b} = 7.0 \vec{i} + 42.0 \hat{j} - 43.0 \hat{k} \)(b) \( \vec{a} \cdot \vec{b} = 46.56 \)(c) \( (\vec{a}+\\)

\((a) To find the cross product of vectors \( \vec{a} \) and \( \vec{b} \), we can use the formula:\[ \vec{a} \times \vec{b} = (a_yb_z - a_zb_y) \vec{i} + (a_zb_x - a_xb_z) \hat{j} + (a_xb_y - a_yb_x) \hat{k} \]Substituting the values:\[ \vec{a} \times \vec{b} = (5.0 \cdot 1.4 - 8.6 \cdot 0) \vec{i} + (8.6 \cdot 5.0 - 4.6 \cdot 1.4) \hat{j} + (4.6 \cdot 0 - 5.0 \cdot 8.6) \hat{k} \]Simplifying the expression, we get:\[ \vec{a} \times \vec{b} = 7.0 \vec{i} + 42.0 \hat{j} - 43.0 \hat{k} \]\)

\((b) To find the dot product of vectors \( \vec{a} \) and \( \vec{b} \), we can use the formula:\[ \vec{a} \cdot \vec{b} = a_xb_x + a_yb_y + a_zb_z \]Substituting the values:\[ \vec{a} \cdot \vec{b} = (4.6 \cdot 8.6) + (5.0 \cdot 1.4) + (0 \cdot 0) \]Simplifying the expression, we get:\[ \vec{a} \cdot \vec{b} = 39.56 + 7.0 + 0 \]\[ \vec{a} \cdot \vec{b} = 46.56 \]\)

\((c) To find the dot product of \( (\vec{a}+\vec{b}) \) and \( (\vec{a}+\vec{b}) \), we can use the same formula as in part (b).Substituting the values:\[ (\vec{a}+\vec{b}) \cdot (\vec{a}+\vec{b}) = (4.6+8.6) \cdot (4.6+8.6) + (5.0+1.4) \cdot (5.0+1.4) + (0+0) \cdot (0+0) \]\)

\(Simplifying the expression, we get:\[ (\vec{a}+\vec{b}) \cdot (\vec{a}+\vec{b}) = 13.2 \cdot 13.2 + 6.4 \cdot 6.4 + 0 \]\[ (\vec{a}+\vec{b}) \cdot (\vec{a}+\vec{b}) = 174.24 + 40.96 + 0 \]\[ (\vec{a}+\vec{b}) \cdot (\vec{a}+\vec{b}) = 215.2 \]Therefore, the results are:(a) \( \vec{a} \times \vec{b} = 7.0 \vec{i} + 42.0 \hat{j} - 43.0 \hat{k} \)(b) \( \vec{a} \cdot \vec{b} = 46.56 \)(c) \( (\vec{a}+\\)

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Answer:

Step-by-step explanation:

G herbo trap house

for ever 12 elephants there is 11 lions

so it would be 12:11

Answer:

t is less than or equal to 10

Step-by-step explanation:

At most means less than or equal to. The boat costs 6 an hour, so, 6t. He has a $8 off coupon, so, 6t-8 is less than or equal to 52. Add 8 on both sides and then divide by 6 to isolate t. t is less than or equal to 10 hours.

Answer: this is the answer it is a screenshot of the graph

Answer:

1) Yes because the slope, 10x, is constant

2) Yes for every 1 hour of baby sitting $10 dollars is earned.

Consider Brainliest!

Answer:

$95,231 rounded to the nearest dollar

Step-by-step explanation:

5.8125/100 * $90,000 = $ 5231.25 increase

$5231.25 + $90,000 = $95,231.25

Round to the nearest dollar = $95,231

The area being measured will not match the Riemann sum. By employing ever smaller forms to divide the area more precisely, this mistake can be minimized. The sum approaches the area as the shapes become ever-smaller.

A specific type of approximation of an integral by a finite sum in mathematics is known as a Riemann sum. It bears the name of the German mathematician Bernhard Riemann from the nineteenth century. Approximating the area of functions or lines on a graph, as well as the length of curves and other approximations, is a highly typical use.

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An appropriate height range that would encompass approximately 95% of all people in the sample is from 64 inches to 76 inches.

In a study conducted in the United States, a random sample of individuals was measured for their heights.

The data revealed that the heights followed a normal distribution, with a mean of 70 inches and a standard deviation of 3 inches.

Based on this information, we can determine an appropriate height range that would encompass approximately 95% of all people in the sample.

To calculate the height range, we can utilize the properties of the normal distribution.

In a normal distribution, approximately 68% of the data falls within one standard deviation of the mean, 95% falls within two standard deviations, and 99.7% falls within three standard deviations.

In this case, with a standard deviation of 3 inches, approximately 95% of the data would fall within two standard deviations from the mean.

To find the height range, we need to determine the values that are two standard deviations above and below the mean.

Two standard deviations below the mean:

70 inches - (2 \(\times\) 3 inches) = 70 inches - 6 inches = 64 inches.

Two standard deviations above the mean:

70 inches + (2 \(\times\) 3 inches) = 70 inches + 6 inches = 76 inches

Therefore, an appropriate height range that would encompass approximately 95% of all people in the sample is from 64 inches to 76 inches.

It's important to note that this range is specific to the sample in the study and may not be applicable to the entire population.

Additionally, other factors such as age, gender, and ethnicity can influence height distributions.

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Question: In a study conducted in the United States, a random sample of individuals was measured for their heights. The heights were found to follow a normal distribution with a mean of 70 inches and a standard deviation of 3 inches. Based on this data, what would be an appropriate height range that would encompass approximately 95% of all people in the sample?

Answer:it’s -2

Step-by-step explanation:

Did on apex lol

Answer:

1/36

Step-by-step explanation:

Assuming the dice has 6 sides in total, we can set up a probability for each scenario.

The chances of the dice landing on 1 will be 1/6, since there are 6 total faces. Same goes for the second die and landing on 4.

Now that we have our 2 probabilities, we multiply them to get the final probability. 1/6 x 1/6 = 1/36.