help me PLEASEEEEEEEEE EE EE EE E

Answer:

the one you have selected is correct

Step-by-step explanation:

keeping in mind that a full pool means a WHOLE or namely 5/5 or 6/6 or for this case 4/4 is a whole, so

\(\begin{array}{ccll} gallons&quarters\\ \cline{1-2} 53.5&\frac{4}{4}\\[1em] x&\frac{3}{4} \end{array}\implies \cfrac{53.5}{x}~~ = ~~\cfrac{ ~~ \frac{4}{4}~~ }{\frac{3}{4}}\implies \cfrac{53.5}{x}~~ = ~~\cfrac{1}{ ~~ \frac{3}{4}~~ } \\\\\\ \cfrac{53.5}{x}=\cfrac{4}{3}\implies 53.5(3)=4x\implies \cfrac{53.5(3)}{4}=x\implies 40.1 \approx x\)

Answer:

14 people

Step-by-step explanation:

20% of 70 is 14, and 20% of the people gave crew b a high rating.

(hope this help :P)

Answer:

John has 4608.171 points

Step-by-step explanation:

4092.1 + 516.071 = 4608.171

Hope this helps

Have a nice day :)

Answer:

75 dollars.

Step-by-step explanation:

Each person costs 25 dollars and p=3 we just put this into a equation.

25 × 3 = 75

C = 75

The function with vertical asymptotes at x = -2 and x = 5 cannot be the option A because the given function has asymptotes and is not continuous on the vertical asymptotes x = -2 and x = 5.

Option B: f(x) = x² - 3x - 10. The equation can be factored as f(x) = (x - 5)(x + 2), which shows that it has vertical asymptotes at x = -2 and x = 5. The range of the function is all real numbers, so option B is a possible statement.

Option C: The domain of f(x) is {x | x ≠ -2, x ≠ -5, x ∈ R}. The given function has vertical asymptotes at x = -2 and x = 5, and its domain does not include x = -2 and x = 5. Therefore, option C is a possible statement.

Option D: The range of y = f(x) is {y | y ∈ R}. The given function has a horizontal asymptote at y = 0, which means the range of the function is all real numbers. So, option D is a possible statement.

Therefore, the answer is: Options B, C, and D are possible statements.

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Answer:

the answers are 10, 6 and -2

Answer:

11

Step-by-step explanation:

5+6 = 11

If the base of the exponent in an exponential growth function were 1, the function would become constant, with a fixed value of 1 regardless of the value of x.

In exponential growth functions, the base of the exponent represents the factor by which the function grows at each step. When the base is greater than 1, the function experiences exponential growth, with the values increasing rapidly over time. However, if the base of the exponent were 1, the function would change significantly.

When the base of the exponent is 1, the function becomes constant. This is because any number raised to the power of 1 remains unchanged. Therefore, if the base is 1, the exponential function will have a constant value and will not exhibit any growth or decay.

Mathematically, an exponential function with a base of 1 can be represented as:

f(x) = 1^x

No matter what value of x is used, the result will always be 1. For example, if we substitute different values for x, such as x = 2 or x = -3, we get:

f(2) = 1^2 = 1

f(-3) = 1^(-3) = 1

In both cases, the result is always 1.

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Solving a system of equations we can see that:

First, let's define the variables:

With the given information we can write 3 equations:

A = (3/4)*V

V = K - $18

A + V + K = $386.4

Then we need to solve a system of equations:

A = (3/4)*V

V = K - $18

A + V + K = $386.4

We can first replace the first equation into the third to get:

(3/4)*V + V + K = $386.4

And rewrite the second to get:

k = V + $18

And replace that in the other equation:

(3/4)*V + V + V + $18 = $386.4

Now we can solve this for V:

V*(1 + 1 + 3/4) = $386.4 - $18

V*(11/4) = $368.40

V = (4/11)*$368.40 = $133.96

Now that we know the value of V, we can replace it in:

K = V + $18 = $133.96 + $18 = $151.96

A = (3/4)*V = (3/4)*$133.96 = $100.47

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There is no Nash equilibrium in pure strategies because neither player has a strategy that maximizes their expected payoff.

(A) The modified payoff matrix for the matching pennies game with the updated losing payoffs is as follows:

         Player 2

         Heads (H)     Tails (T)

Player 1  +1, -1        -6, +6

Heads (H)

Tails (T) -10, +10      +1, -1

(B) The diagrams showing each player's pair of expected payoff lines and the other player's equilibrium decision probability are as follows:

Player 1's Expected Payoff Line:

H      T

Probability:  p1     1-p1

Expected Payoff:  p1(-6) + (1-p1)(+1)

Player 2's Expected Payoff Line:

H      T

Probability:  p2     1-p2

Expected Payoff:  p2(-10) + (1-p2)(+1)

The equilibrium decision probability for each player will be the value that maximizes their expected payoff. In this case, player 1 will choose heads (H) with probability p1* and player 2 will choose tails (T) with probability p2*.

(C) To calculate the numerical values of the Nash equilibrium probabilities (p1*, p2*), we need to find the values that maximize each player's expected payoff.

For player 1:

Expected Payoff = p1(-6) + (1-p1)(+1)

= -6p1 + 1 - p1 + p1

= -5p1 + 1

To maximize this expected payoff, we set the derivative equal to zero:

d/dp1 (-5p1 + 1) = -5 = 0

-5 = 0 (No solution)

For player 2:

Expected Payoff = p2(-10) + (1-p2)(+1)

= -10p2 + 1 + p2 - p2

= -9p2 + 1

To maximize this expected payoff, we set the derivative equal to zero:

d/dp2 (-9p2 + 1) = -9 = 0

-9 = 0 (No solution)

There is no Nash equilibrium in pure strategies because neither player has a strategy that maximizes their expected payoff.

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Answer:

36.5

Step-by-step explanation:

Answer:

292 divided by 8 is 36.5

However, 8 divided by 292  is 0.02739726027

Step-by-step explanation:

We know this by dividing, plus if you want to double check answers, go ogle is always there for you!

15

5x-2y=9......(1)

6x+ky=4......(2)

slope of eqn i= -5/-2

=5/2

slope of eqn ii = -6/k

since the line are perpendicular

5/2 * -6/k = -1

-30= -2k

k=15

The population of brazil is 5 times more than the population of Argentina

What is population?

The term "population" usually refers to the total number of people living in a particular area, such as a city or town, region, nation, continent, or the entire world. Governments frequently use censuses, a procedure for gathering, analysing, compiling, as well as publishing data regarding a population, to determine the size of a resident population inside their jurisdiction.

We are given that the population of argentine is \(4\)×\(10^7\)

And the population of brazil is \(2\)×\(10^8\)

Now we are asked to find How many times larger is the population of Brazil than the population of Argentina

Now Population of brazil can also be written as \(20\)×\(10^7\)

Now we take the ratio of population of brazil and population of argentine

We get,

\(\frac{20}{4}\)×\(\frac{10^7}{10^7}\)

=5

Hence, population of Brazil is 5 times larger than the population of Argentina

Hence the correct option is option c) 5
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It will take Joey's family approximately 21 months to save enough money, compounded monthly at a 5% interest rate, to finance their vacation trip to the amusement park.

To determine the time it will take to save enough money, we can use the formula for the future value of an ordinary annuity:

FV = P * [(1 + r)^n - 1] / r,

where FV is the future value, P is the monthly payment, r is the monthly interest rate, and n is the number of periods.

Given:

Desired future value (FV) = $5000,

Monthly payment (P) = $240,

Monthly interest rate (r) = 5% / 12 = 0.05 / 12 = 0.004167.

We need to solve for the number of periods (n) in the formula. Rearranging the formula, we have:

n = log(1 + (FV * r) / P) / log(1 + r),

where log denotes the logarithm with base 10.

Plugging in the given values, we get:

n = log(1 + ($5000 * 0.004167) / $240) / log(1 + 0.004167).

Using a calculator, we find that n is approximately 20.998, which rounds up to 21.

Therefore, it will take Joey's family approximately 21 months to save enough money, compounded monthly at a 5% interest rate, to finance their vacation trip to the amusement park.

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We need to find the characteristic polynomial, eigenvalues, and a basis for the eigenspace associated with each eigenvalue for the given matrix A.

To find the characteristic polynomial, we first need to find the determinant of the matrix (A - λI), where I is the identity matrix and λ is the eigenvalue. We have:

|\(\left[\begin{array}{ccc}1-\lambda&0&0\\-25&-2\-\lambda&24\\0&0&-1-\lambda\end{array}\right]\)

Expanding along the first row, we get:(1-λ)[(-2-λ)(-1-λ) - 0] - 0 - 0 = (1-λ)(λ^2 + 3λ + 2) = (1-λ)(λ+1)(λ+2). So the characteristic polynomial is (1-λ)(λ+1)(λ+2). To find the eigenvalues, we set the characteristic polynomial equal to zero and solve for λ. We get λ = 1, λ = -1, and λ = -2. Next, we need to find the eigenvectors for each eigenvalue. We first consider λ = 1. To find the eigenvectors, we need to solve the system of equations (A - λI)x = 0, which in this case is:

\(\left[\begin{array}{ccc}0&0&0\\-25&-3&24\\0&0&0\end{array}\right]\)

Solving this system, we get x1 = 0 and x2 = -8x3. So the eigenvectors associated with λ = 1 are of the form [0, -8t, t], where t is any nonzero real number. A basis for this eigenspace is {[0, -8, 1]T}. Similarly, for λ = -1, we get a basis for the eigenspace as {[0, -4, 1]T}. For λ = -2, we get a basis for the eigenspace as {[0, 0, 1]T}.So the characteristic polynomial is (1-λ)(λ+1)(λ+2), the eigenvalues are λ = 1, λ = -1, and λ = -2, and the corresponding eigenspaces have bases {[0, -8, 1]T}, {[0, -4, 1]T}, and {[0, 0, 1]T}, respectively.

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h = 15

just plug in the numbers for the corresponding letters and then solve to get h by itself

Answer:

i like the name omar

Step-by-step explanation:

it sounds different...

Answer:

2 * 10 + 6 * .1 + 5 * .01

Step-by-step explanation:

The limit of a function f(x) at x = 2 is always the value of the function at x= 2, that is f(2) - False.

Suppose f(x) is defined as x is near the number a (This means that f is defined on same open interval that contains a except possibly at a itself)

Then we write

\(\lim_{n \to \infty} f(x) =L\)

If we can make the f(x) arbitrary close to L (as close to L as possible) by taking x to be sufficiently close to a (on either side of the function) but not equal to a,

\(f(x) =\frac{x^2-4}{x-2}\)

Clearly this function is not defined at x =2 that is f(2) doesnot exist because it attains the form 0/0.

But it can be easily seen that the limit = 4

Thus the limit f(x) exists but the value of f(2) does not.

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For this case we have different effectiveness using two conditions the first one with to students who chose the professor as the chair of their doctoral committe and the second is associated to all students and we see a different effectiveness

This is a clear example of an error in the A)Data Gathering Phase

And the reason is because they introduce bias in the study just selecting students who select the professor as the chair of their doctoral committee, and it's very evident when they select all the students the real results change

By the calculations below, there are 20 groups of 1/5 in 4.

To find out how many groups of 1/5 are in 4, we can use the concept of division of fractions.

Recall that dividing by a fraction is the same as multiplying by its reciprocal. So, we can rewrite the problem as:

4 ÷ 1/5

To find the reciprocal of 1/5, we flip the fraction:

1/5 → 5/1

Now, we can rewrite the division problem as multiplication:

4 ÷ 1/5 = 4 × 5/1

Multiplying across gives:

4 × 5/1 = 20

Therefore, there are 20 groups of 1/5 in 4.

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Answer:

Congruent

ΔGHI = ΔLJK

Angle - Side - Angle (ASA)

Explanation:

Taking into account the diagram:

Angle G is congruent to angle L

Side GH is congruent to side LJ

Angle H is congruent to angle J

Then, we can use the property Angle - Side - Angle (ASA) to say that both triangles are congruent.

Therefore, the answers are:

Congruent

ΔGHI = ΔLJK

Angle - Side - Angle (ASA)

Answer: f(x) and g(x) both represent y of the equations

Step-by-step explanation: f(x) and  g(x) both represent the y of the equation for example f(x)=mx+b or g(x)+mx+b both would be to find y of that specific equation and that would also make them inverses because you could use the table to label the inverses on a graph.

Answer:

B, D

Step-by-step explanation:

This value represents the present worth below which the probability is 0.5, indicating a negative present worth.

To estimate the probability that the present worth is negative using the NORM.INV function in Excel,

we need to calculate the present worth of the project and then determine the corresponding probability using the normal distribution.

The present worth of the project can be calculated by finding the sum of the present values of the annual receipts over the 10-year period, minus the initial investment. The present value of each annual receipt can be calculated by discounting it back to the present using the minimum attractive rate of return (MARR).

Using the given information, the present value of the initial investment is $10,000. The present value of each annual receipt is calculated by dividing the expected return of $1,800 by \((1+MARR)^t\),

where t is the year. We then sum up these present values for each year.

We can use the NORM.INV function in Excel to estimate the probability of a negative present worth. The function requires the probability value, mean, and standard deviation as inputs.

Since we have a mean and standard deviation for the present worth,

we can calculate the corresponding probability of a negative present worth using NORM.INV.

This value represents the present worth below which the probability is 0.5. By using the NORM.INV function,

we can estimate the probability that the present worth is negative based on the given data and assumptions.

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