HELP PLEASE! IM DUMB AND DONT HAVE MUCH TIME :( SPENDING 18 POINTS ON THIS

HELP PLEASE! IM DUMB AND DONT HAVE MUCH TIME :( SPENDING 18 POINTS ON THIS

Answers

Answer 1

Answer:

The correct choice is the one on the bottom right.


Related Questions

the marijority of the population in the United states _________.
A. French
B.spanish
C.English
D.native languages​

Answers

it should be C english :)

Let P(t) be a population at time t. A simple population model supposes the rate of growth of the population is proportional to the population (a) Express the last sentence in the language of calculus. (b) Solve for P(t) in the equation you found in part (a) (c) Suppose the net birthrate of the population is .1, and the initial population is 100. (i) Find the population at time t 10.(ii) Find when the population is 1000.

Answers

Answer:

\((a) \dfrac{dP}{dt} =k P(t)\\(b)P(t)=Ce^{kt}\)

(c)\(P(10)\approx 272\)

(ii)\(P(1000)\approx 26.88 \times 10^{44}\\\)

Step-by-step explanation:

(a)The rate of growth of the population is proportional to the population, this is written as:

\(\dfrac{dP}{dt} \propto P(t)\\$Introducing our proportionality constant, k\\ \dfrac{dP}{dt} =k P(t)\)

(b)

\(\dfrac{dP(t)}{P(t)} =k dt\\$Take the integral of both sides\\\int \dfrac{dP(t)}{P(t)} =\int k dt\\\ln P(t)=kt+C, $C a constant of integration\\Take the exponential of both sides\\e^{\ln P(t)}=e^{kt+C}\\P(t)=e^{kt}\cdot e^C $, (Since e^C$ is a constant, we then have:)\\P(t)=Ce^{kt}\)

(c)

Suppose the net birthrate of the population is .1, and the initial population is 100.

k=0.1

P(0)=100

Substitution into P(t) gives:

\(100=Ce^{kX0}\)

C=100

Therefore:

\(P(t)=100e^{0.1t}\)

(i)When t=10

\(P(10)=100e^{0.1 \times 10}\\=271.8\\\approx 272\)

(ii)When t=1000

\(P(1000)=100e^{0.1 \times 1000}\\=26.88 \times 10^{44}\\\)

33. The population of Canada, y (in millions), can be approximated by the relation y=
0.146x + 31, where x represents the number of years since 2000.
a. Approximate the population of Canada in the year 2006.
b. In what year did the population of Canada reach approximately 32,752,000?

Answers

Answer:x=6573/500,x=13(73/500

Step-by-step explanation:

It will takes 12 years to reach approximately 32,752,000.

What is Equation?

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides. LHS = RHS is a common mathematical formula.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given:

y = 0.146x + 31

where x represents the number of years since 2000.

a) The population of Canada in the year 2006

x= 6

y= 0.146 x 6 + 31

y = 31.876

b) The population of Canada reach approximately 32,752,000 in

y = 32.752

0.146x + 31= 32.752

0.146x = 1.752

x= 1.752/0.146

x= 12

Hence, it will takes 12 years to reach approximately 32,752,000.

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Evaluate: xy+2x^2, if x=0.1 and y=9.8

Answers

Answer: 1

Step-by-step explanation:

\((0.1)(9.8)+2(0.1)^2\\0.98+0.02=1\)

Try Photomath! I always use the app for evaluating

Multiply.

17.22(−2.4)

Enter your answer in the box.

Answers

Answer:

-41.328

Step-by-step explanation:

Answer:

-41.328

Step-by-step explanation:

Addition multiplied by subtraction gets you subtraction. +-=-

so now, ()= multiplication

so now all you have to do is 17.22 times 2.4 which gets us 41.328

then, add the negative sign which gives you -41.328

yw :)

This is just a question I had.
If Denny (random name) left to another country and he left the Tuesday of this week (June 20) and he left for a month, what day would he be back on? I though July 18 but I’m not sure. Pls help?

Answers

Answer:

Step-by-step explanation:

Well, since the length of a month can vary in the number of days, this answer can also vary.

For example, February is only 28 days long, while December is 31 days long.

That being said, the average length of all 12 months is 30.436875 days, so if Denny left to another country on June 20th, he would most likely be back   July 19th of July 20th.

I hope this helps!

Solve for j I will give brainlest anwser
(h-4) / j = k

Answers

Answer:

j=h-4/k    this is the answer if you are solving for j

Step-by-step explanation:

Solve for x
4( 3x - 5) = -2(-x + 8) - 6x

Answers

Answer:

Step-by-step explanation:

12x - 20 = 2x  -16 - 6x

12x - 20 = -4x - 16

16x - 20 = -4x

20x = 20

x = 1

Find all values of x that are NOT in the domain of f

Find all values of x that are NOT in the domain of f

Answers

Answer:

……….

Step-by-step explanation:

Factorise the following expressions

x^2 + 9x + 20

Answers

Answer:

(x+4) (x+5)

Step-by-step explanation:

we look for what we add together to give 9 and what we multiply to give 20

and that's 4 and 5

so the answer is x+4 and x+ 5

Answer:

Refer to the attachment.

Hope it helps ⚜

Factorise the following expressions x^2 + 9x + 20

5x-3(-5y+6x) +4y i need help please

Answers

To simplify the expression \(\displaystyle\sf 5x-3(-5y+6x)+4y\), we can follow the order of operations, which involves simplifying the expressions within parentheses, applying the distributive property, and combining like terms.

Using \(\displaystyle\sf \) tags for formatting, the expression becomes:

\(\displaystyle\sf 5x-3(-5y+6x)+4y\)

First, we simplify the expression within the parentheses:

\(\displaystyle\sf 5x-3(-5y+6x)+4y\)

\(\displaystyle\sf 5x+15y-18x+4y\)

Next, we can combine the like terms:

\(\displaystyle\sf 5x-18x+15y+4y\)

\(\displaystyle\sf -13x+19y\)

Therefore, the simplified expression is \(\displaystyle\sf -13x+19y\).

\(\huge{\mathfrak{\colorbox{black}{\textcolor{lime}{I\:hope\:this\:helps\:!\:\:}}}}\)

♥️ \(\large{\underline{\textcolor{red}{\mathcal{SUMIT\:\:ROY\:\:(:\:\:}}}}\)

Ronald made some chili with 1/2 of a can of black beans and 7/10 of a can of pinto beans.
How many cans of beans did Ronald use in all?
Write your answer as a fraction or as a whole or mixed nunver.
Submit
cans

Answers

Total of 3/5 can of black beans and  pinto beans used in preparing the chili by Ronald.

Explain about the fraction of the number?

An element of a whole is a fraction. The number is represented mathematically as a quotient, where the numerator and denominator are split. Both are integers in a simple fraction. A fraction appears in the numerator either denominator of a complex fraction.

Fraction of beans used by Ronald to make chili.

black beans = 1/2  can

pinto beans = 7/10 can

Thus,

total beans = 1/2  can + 7/10 can

total beans = (1/2 + 7/10) can

Simplifying:

total beans = (5*1 + 7)/ 2*10  can

total beans = 12/20 can

total beans = 3/5 can

Thus, total of 3/5 can of black beans and  pinto beans used in preparing the chili by Ronald.

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show that, given one nth root of z, the others are obtained by multiplying it by the nth roots of unity. (z is complex number)

Answers

It is proven that the other nth roots of z can be found by multiplying the initial one by the nth roots of unity.

A complex number satisfying the equation \(z^{n-1} = 0\) is known as the nth root of unity. There are about n nth roots of a unit, according to the fundamental theorem of algebra. We know that,\(1=e^{2\pi i}\). Then, the nth root is written as \(\omega=e^{2\pi i/n}\).

The integer of powers of this root between 0 and n-1 provides the other nth roots. Then, the roots are \(1, \omega, \omega^2 ,\cdots \cdots, \omega^{(n-1)}\). Now, factorize the equation \(z^{(n-1)} = 0\) we get the required identity as, \(z^{(n-1)} = (z- 1)(z^{(n-1)}+ z^{(n-2)} + \cdots \cdots+ z + 1) = 0\).  

This indicates that the equation \(1+\omega+ \omega^2+\cdots \cdots+ \omega^{(n-1)}\) is true for all nth roots of unity other than 1.

Roots of unity also have the great quality of being periodic, which results from the fact that n = 1. It is equal to a power of that power mod n if the power is bigger than n.

When ω is a third root of unity, \(\omega^5 + \omega^4 + 1 = \omega^2 + \omega + 1 = 0\).

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27. What is the reflection image of (5, –3) across the y-axis? (–5, 3) (–5, –3) (–3, 5) (5, 3)

Answers

The search results are unrelated to the question of finding the reflection image of (5, -3) across the y-axis. To find the reflection image of a point across the y-axis, we need to change the sign of the x-coordinate of the point. Therefore, the reflection image of (5, -3) across the y-axis is (-5, -3).

What is the value of u?

What is the value of u?

Answers

Answer:

66-26 = 40

Step-by-step explanation:

u = 40 degrees

what is six hundred eighty and fourteen thousandths written in standard form?

Answers

Answer:618.014

Step-by-step explanation: It may look like hundredths which is where must people mess up but it is instead thousandths.

The farmer's market sells fruit baskets. Each basket contains 12 apples and 4 pears. Use a to represent the cost of each apple and p for the cost of each pear.
a) Write an EXPRESSION that represents the cost of 12 apples
b) Write an EXPRESSION that represents the cost of 4 pears
c) Write an EXPRESSION that represents the TOTAL COST of one basket

Answers

Answer:

a) a x 12

b) p x 4

c) (a x 12) + (p x 4)

Step-by-step explanation:

These are the answers because:

1) Since a is representing the cost of each apple, we have to multiply the a with 12.

2) Since p is representing the cost of each pear, we have to multiply the p with 4.

3) Finally, for c, each basket contains 12 apples and 4 pears. Therefore, we just use our eautions from before and add them which will give you the total cost of one basket.

Hope this helps! :D

The points (0,0), (3, 3), and (0,6) are three vertices of a square. What are the coordinates of the fourth vertex of the square?
O B. (2,3)
O A. (0, 3)
OD. (4,3)
O C. (3, 3)

Answers

The coordinates of the fourth square is 4,3

Answer:

Step-by-step explanation:

let 4th vertex be (x,y)

midpoint of diagonal is same.

\(\frac{0+0}{2} =\frac{3+x}{2}\\\\3+x=0\\ x=-3\\\frac{0+6}{2} = \frac{3+y}{2} \\3+y=0+6\\y=6-3\\=3\)

so 4th vertex is (-3,3)

Finn feeds his puppy 1/2 of a cup of food 3 times per day Finn has 4 1/2 cups of food left how many days will it take to use all the food?

Answers

Answer: There are 3 days until all the food is gone.

Step-by-step explanation:

If you take 1 1/2 x 3 = 1 1/2  and then take 4 1/2 and divide that by the 1 1/2 you got, You will then get your answer which is 3. Looks like he might wanna get more dog food within 3 days.

Answer:

3 days

Step-by-step explanation:

we first turn 4 1/2 into its decimal 4.5 then divide it by 1/2 or .5 and get 9. we then take 9 and divide it by 3 for the amount of times a day the puppy gets fed. after that step we have out answer of 3 days.

Sophia, Oliva, Ava, Mia, and Isabella are going to drive together to a nearby theme park. The car they are using has 5 seats: 1 driver seat, 1 front passenger seat, and 3 back passenger seats. Sophia and Olivia are the only ones who know how to drive the car. How many possible seating arrangements are there?

Answers

Answer: 48 arrangements

Step-by-step explanation:

Total persons = 5

Total seats = 5

Total arrangements

= 2 * 4!

= 2 * (4 * 3 * 2)

= 2 * 24

= 48


what is the range of ordered pairs shown in the graph?

I WILL MARK BRAINLIEST

what is the range of ordered pairs shown in the graph? I WILL MARK BRAINLIEST

Answers

The set that represents the range of the function given is -

{-2, 0, 3, 5}

What is range of a function?

The range of a function is the complete set of all possible resulting values of the dependent variable (y), after we have substituted the domain.

Given is a graph as shown in the image.

For the given graph, the set of {y} coordinates represent the range of the function. So, the set that represents the range of the function given is -

{-2, 0, 3, 5}

Therefore, the set that represents the range of the function given is -

{-2, 0, 3, 5}

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Which ones right ????

Which ones right ????

Answers

The student made an error in option (d) the range is {y<0}.

PLzzz help me!! Stuck with this equation

PLzzz help me!! Stuck with this equation

Answers

Answer:

f(2) = 15

for f(x) = 4, x = 6

Step-by-step explanation:

f(2) means f(x) for x = 2.

in the table for x = 2 we see f(x) = 15.

the second question : f(x) = 4

so, where in the table do we find f(x) = 4 ? ah, for x = 6 do we find f(x) = 4.

For the functions f(x) = 7x + 4 , h(x) =10/x− 3 and g(x) = 3x − 2
Evaluate
g(4)
h{g(4)}
f-1 (11)

Answers

Answer:

g(4) = 10

f⁻¹(11) = 1

h{g(4)} =

if h(x) = (10/x) – 3 = 7

if h(x) = 10/(x – 3) = 10/7

____________

f⁻¹(x) = (x - 4) / 7

write equation that represents the balance hanger above 6x+15=4x+20 unit 1

Answers

Answer:

x = 5/2

Step-by-step explanation:

6x+15=4x+20

Collect like terms

6x - 4x = 20 - 15

2x = 5

x = 5 / 2

Hi I just need the sum for this :) (Sum is the answer)
4(2x + 3) ÷ 5y = ?

Answers

Answer:

23

Step-by-step explanation:

Use the given conditions to write an equation for the line in the indicated form.
Passing through (2, 2) and perpendicular to the line whose equation is y = 4x + 7;
point-slope form
A)y=-4x-10
B)y-2=-1/4(x-2)
C)y-2=1/4(x+2)
D)y-2=1/4(x-2)

Answers

Answer:

B) y - 2 = (-1/4)(x - 2)

Step-by-step explanation:

Start with the equation of the given line: y = 4x + 7.

Determine the slope of the given line, which is 4.

Since the perpendicular line has a negative reciprocal slope, the perpendicular line's slope is -1/4.

Use the point-slope form of a linear equation: y - y₁ = m(x - x₁), where (x₁, y₁) is the given point and m is the slope.

Substitute the values x₁ = 2 and y₁ = 2 into the point-slope equation: y - 2 = (-1/4)(x - 2).

Simplify by distributing -1/4 to (x - 2): y - 2 = (-1/4)x + 1/2.

Add 2 to both sides to isolate y: y = (-1/4)x + 1/2 + 2.

Simplify further: y = (-1/4)x + 5/2.

The equation in point-slope form for the line passing through (2, 2) and perpendicular to y = 4x + 7 is y - 2 = (-1/4)(x - 2), which matches option B.

A production process is known to produce a particular item in such a way that 5 percent of these are defective. If two items are randomly selected as they come off the production line, what is the probability that both are defective (assuming that they are independent)

Answers

Answer:

0.0025 = 0.25% probability that both are defective

Step-by-step explanation:

For each item, there are only two possible outcomes. Either they are defective, or they are not. Items are independent of each other. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

\(P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}\)

In which \(C_{n,x}\) is the number of different combinations of x objects from a set of n elements, given by the following formula.

\(C_{n,x} = \frac{n!}{x!(n-x)!}\)

And p is the probability of X happening.

5 percent of these are defective.

This means that \(p = 0.05\)

If two items are randomly selected as they come off the production line, what is the probability that both are defective

This is P(X = 2) when n = 2. So

\(P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}\)

\(P(X = 2) = C_{2,2}.(0.05)^{2}.(0.95)^{0} = 0.0025\)

0.0025 = 0.25% probability that both are defective

Simplifying Algebraic Expressions

-16 (14+18p)

Please show your work!

Answers

Answer:

= -288p - 224

Step-by-step explanation:

-16 (14 + 18p)

= (-16*14) + (-16*18p)

= -224 - 288p

= -288p - 224

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Question Content Area
Service Department Charges and Activity Bases

Middler Corporation, a manufacturer of electronics and communications systems, uses a service department charge system to charge profit centers with Computing and Communications Services (CCS) service department costs. The following table identifies an abbreviated list of service categories and activity bases used by the CCS department. The table also includes some assumed cost and activity base quantity information for each service for October.

CCS Service
Category
Activity Base
Budgeted Cost Budgeted Activity
Base Quantity
Help desk Number of calls $160,000 3,200
Network center Number of devices monitored 735,000 9,800
Electronic mail Number of user accounts 100,000 10,000
Smartphone support Number of smartphones issued 124,600 8,900
One of the profit centers for Middler Corporation is the Communication Systems (COMM) sector. Assume the following information for the COMM sector:

• The sector has 5,200 employees, of whom 25% are office employees.

• All the office employees have been issued a smartphone, and 96% of them have a computer on the network.

• One hundred percent of the employees with a computer also have an e-mail account.

• The average number of help desk calls for October was 1.5 calls per individual with a computer.

• There are 600 additional printers, servers, and peripherals on the network beyond the personal computers.

a. Determine the service charge rate for the four CCS service categories for October.

CCS Service Category Service Charge Rate
Help desk $fill in the blank 1

Per call
Network center $fill in the blank 3

Per device monitored
Electronic mail $fill in the blank 5

Per user or e-mail account
Smartphone support $fill in the blank 7

Per smartphone issued
b. Determine the charges to the COMM sector for the four CCS service categories for October.

October charges to the COMM sector
Help desk charge $fill in the blank 9
Network center charge $fill in the blank 10
Electronic mail charge $fill in the blank 11
Smartphone support charge $fill in the blank 12
Feedback Area
Feedback
a. Divide the budgeted cost by the budgeted activity base quantity for each category.

b. Determine the Help desk charge by multiplying the rate from (a) by the number of employees times the percentage of office employees times the percentage with a computer times the number of calls. Follow a similar process for each of the other three categories.

Learning Objective 3.

Answers

The service charge rate are: Help desks $50 per call, Network center $75 per device monitored, Electronic mail $10 per user or per e-mail account, Local voice support $14 per phone extension.

Service charge rate

a. Service charge rate

Service charge rate=Budgeted cost/ Budgeted activity base quantity

Help desks:

Service charge rate=$160,000/3,200 calls

Service charge rate=$50 per call

Network center:

Service charge rate=$735,000/9,800 devices

Service charge rate=$75 per device monitored

Electronic mail:

Service charge rate=$100,000/10,000 accounts

Service charge rate=$10 per user or per e-mail account

Local voice support:

Service charge rate=$124,600/8,900 phone extensions

Service charge rate=$14 per phone extension

b.  Help desk charge

Help desk charge =(Number of employees times × Percentage of office employees× Percentage with a computer ×Number of calls)× Service charge rate

Help desk charge:

(5,200 employee×25%×96%×1.5)× $50 per call

=$93,600

Network center charge:

[(5,200 employee×25%×96%)+ 600]× $75 per device

=$138,600

Electronic mail:

(5,200 employee×25%×96%×100)×$10 per user or per e-mail account

=$12,480

Local voice support:

(5,200 employee×25%)× $14 per phone extension

=$18,200

Therefore the service charge rate are: Help desks $50 per call, Network center $75 per device monitored, Electronic mail $10 per user or per e-mail account, Local voice support $14 per phone extension.

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