The percent yield, given that the theoretical yield is 73 grams and the actual yield is 62 grams, is 84.9%
How do I determine the percentage yield?Percentage yield is defined according to the following formula:
Percentage yield = (Actual yield / Theoretical yield) × 100
From the question given above, the following data were obtained:
Theoretical yield = 73 gramsActual yield = 62 gramsPercentage yield =?Using the above formula, we can obtain the percentage yield as shown below:
Percentage yield = (Actual yield / Theoretical yield) × 100
Percentage yield = (62 / 73) × 100
Percentage yield = 84.9%
Thus, from the above calculation, we can conclude that the percentage yield is 84.9%
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write the structural formula for 2-bromo-3-chloro-4,4-dimethylpentanal
Answer:
Br-CH2-CH(CH3)2-C(Cl)H-CH(CH3)2-CHO
Explanation:
The molecule has a total of 14 carbon atoms, 13 hydrogen atoms, and 1 bromine atom. The carbon atoms are arranged in a chain with a methyl group attached to the second carbon atom, a chlorine atom attached to the third carbon atom, and two methyl groups attached to the fourth carbon atom. The fifth carbon atom has a carbonyl group attached to it.
The molecule is an aldehyde, which means that it has a carbonyl group (C=O) at the end of the chain. The carbonyl group is polar, and the oxygen atom has a partial negative charge. The hydrogen atom has a partial positive charge. This polarity makes the aldehyde group susceptible to nucleophilic attack.
The bromine and chlorine atoms are both electrophilic, which means that they have a partial positive charge. This makes them susceptible to nucleophilic attack.
The methyl groups are non-polar and do not have any significant reactivity.
The molecule is a chiral molecule, which means that it has a mirror image that is not superimposable on itself. This is because the carbon atom with the carbonyl group is attached to four different groups.
The molecule is a liquid at room temperature and has a strong odor. It is used in a variety of products, including perfumes, flavorings, and plastics.
electronegativity for radon?
PLEASE HELP
the water cycle is continuous process by which ______ moves from Earth's surface to the atmosphere and back again. This cycle is driven by the energy from the ____ and the by the force of______.
Answer:
1-water 2-Sun 3-Gravity
A copper penny will sink in molten copper. What can you infer about the difference in distance between the molecules in a copper penny and in molten copper?
The molecules in a copper penny is closely packed and and has no space to move apart thus the material will be denser than that in the molten state. That's why the penny sink in the molten copper.
What is molten copper?Copper is a transition metal exhibiting all the metallic properties. The molten state of metals is the fluid state where the molecule are not strongly held by the metallic bonds.
Molten material is made by melting them and the liquid like state contains molecules with some space to move apart. Whereas, in solid state as in a copper penny, the molecules are closely packed and have no space to move apart.
An object will sink in a liquid if it is less dense than the liquid. Copper penny is denser than the molten copper because the molecules are densely packed and it will sink on to it.
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A runner runs for a distance of 350 yards and then runs for an additional 200 m. What is the total difference covered by the runner in meters?
2. If something is formed from nonliving things or the remains of things never
alive, it is said to be____?
a. dead
b. coal
c. inorganic
d. irrigation
Answer:
c. inorganic
Explanation:
inorganic has t do with non living things or things that have no carbon in them
what mass of glucose c6h12o6 would be required to prepare 5000 mL of a 0.215 M solution
Approximately 194.0 grams of glucose (C6H12O6) would be required to prepare a 5000 mL solution with a concentration of 0.215 M.
To determine the mass of glucose (C6H12O6) required to prepare a 0.215 M solution in 5000 mL, we need to use the formula:
Molarity (M) = moles of solute / volume of solution (in liters)
First, let's convert the volume of the solution from milliliters (mL) to liters (L):
5000 mL = 5000/1000 = 5 L
Now, we can rearrange the formula to solve for moles of solute:
moles of solute = Molarity (M) x volume of solution (L)
moles of solute = 0.215 M x 5 Lmoles of solute = 1.075 mol
Since glucose (C6H12O6) has a molar mass of approximately 180.16 g/mol, we can calculate the mass of glucose using the equation:
mass of solute = moles of solute x molar mass of solute
mass of glucose = 1.075 mol x 180.16 g/mol
mass of glucose = 194.0 g (rounded to three significant figures)
Therefore, approximately 194.0 grams of glucose (C6H12O6) would be required to prepare a 5000 mL solution with a concentration of 0.215 M. It's important to note that the molar mass of glucose used in this calculation may vary slightly depending on the level of precision required.
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please help me ASAAAAAAAAAAAP
Identify the Arrhenius acid and the Arrhenius base in this reaction.
H2SO4 + 2NaOH → Na2SO4 + 2H2O
Question 35 options:
Na2SO4(acid), 2H2O(base)
H2SO4(acid), NaOH(base)
NaOH(acid), Na2SO4(base)
H2SO4(acid), Na2SO4(base)
Answer:
H2SO4(acid), NaOH(base)
Explanation:
Which hydroxide is a weak base?
RbOH
CsOH
Sr(OH)2
NaOH
None of these choices are weak bases.
Answer:
NH4OH
Explanation:
NH4OH is a weak base because it partially dissociates into NH + and OH− ions in aqueous solutions and the amount of OH− ions produced is low.
PLSSSSS I NEED HELP MY AMPLIFY SIM WON’T WORK I DONT KNOW WHAT TO DO FOR AMPLIFY TAB 3.5.!! IM IN THE PURPLE GROUP !! The lead chemist wants you to determine what is happening to the freedom of movement of an object’s molecules when you smell something. Is it possible to smell a chocolate bar when it is a solid? Launch the Sim and investigate.
Use the Sim to determine if the molecules of a substance can be in two different phases at the same time.
Go through each substance and see if you can get it to exist in two phases at once.
Record as much evidence as you can in the table below.
When a chocolate bar is solid, it is able to smell it. It is also important to note that a substance 's molecules cannot be in two distinct phases at the a time.
Why is this the case ?In general, it is not possible for a the molecules of the chocolate to be in two distinct phases at the same time.
It must be noted that smelling a solid, such as a chocolate bar, however, mean the release of loose molecules from the solid, which may then move through the air and reach our olfactory receptors in our nose, allowing us to sense the fragrance.
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4. What is the volume, in liters, of a 3.00 mole sample of carbon dioxide at STP?
Answer:
One mole of ideal gas occupies 22.4L volume at STP
Explanation:
So., we treat carbon dioxide an ideal gas:
3 mol x 22.4L •Mol-¹ ≈? ?L
Find reaction type and products for each equation please. FIRST CORRECT ANSWERS GETS BRAINLIEST HELP!!!
Reactant: C3H8 + O2 = Product: CO2 + H2O
Reactant: Zn + HCI = Product: ZnCl₂
Reactant: KI + Pb(NO3)2 = Product: KNO3 and PbI2
Reactant: Mg(CIO3)2 = Product: MgCl2 and O2
Reactant: F2 + KBr = Product: KF and Br2
What are chemical reactions?Chemical reactions entail the conversion of one or more substances into novel species, thanks to the breaking and forging of chemical bonds.
Essentially, such transformations involve the reconfiguration of atoms and/or molecules, culminating in distinct chemical and physical attributes contrasting from those of the initial materials.
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the dimensions of a box are 4.5 cm wide by 5.750 cm long by 1.50 cm tall.
Answer:
38.8125
Explanation:
4.5 x 5.750 x 1.50 = 38.8125
Strontium hydroxide reacts with hydrobromic acid to produce Strontium bromide and
water.
Write and balance the chemical reaction above, use it for problems 1-4 below:
1. If 5.50 moles of strontium hydroxide were consumed, how much moles of water are
produced?
2. Find the mass of hydrobromic acid used to produce 7.50 moles water.
3. If 10.8 g of strontium hydroxide were used, how much moles of strontium bromide are
produced?
4. If 13.3 g of hydrobromic acid were consumed, find the mass of the water produced.
g Ions B and C react to form the complex BC. If 35.0 mL of 1.00 M B is combined with 35.0 mL of 1.00 M C, 0.00500 mol of BC is formed. Determine the equilibrium constant for this reaction.
Answer:
Kf = 0.389.
Explanation:
Hello there!
In this case, it turns out possible for us to solve this problem by firstly writing the equilibrium chemical equation and equilibrium expression for the formation of this complex:
\(B+C\rightleftharpoons BC\\\\Kf=\frac{[BC]}{[B][C]}\)
Thus, we firstly calculate the concentrations at equilibrium, knowing that the reaction extent in this case is 0.00500mol (same as the formed moles of BC):
\([B]=[C]=\frac{0.0350L*1.00mol/L-0.00500mol}{0.0700L} =0.429M\)
\([BC]=\frac{0.00500mol}{0.0700L} =0.0714M\)
And finally, the equilibrium constant:
\(Kf=\frac{0.0714}{[0.429][0.429]}\\\\Kf=0.389\)
Regards!
Silver chloride is virtually insoluble in water so that the reaction appears to go to completion. How many grams of solid NaCl must be added to 25.0 mL of 0.366 M AgNO3 solution to completely precipitate the silver
Answer:
0.535 g
Explanation:
The reaction that takes place is:
NaCl + AgNO₃ → AgCl + NaNO₃First we calculate how many AgNO₃ moles are there in 25.0 mL of a 0.366 M solution, using the definition of molarity:
Molarity = moles / litersmoles = Molarity * litersConverting 25.0 mL to L ⇒ 25.0 / 1000 = 0.025 L
moles = 0.366 M * 0.025 L = 0.00915 mol AgNO₃Then we convert AgNO₃ moles into NaCl moles:
0.00915 mol AgNO₃ * \(\frac{1molNaCl}{1molAgNO_3}\) = 0.00915 mol NaClFinally we convert NaCl moles into grams, using its molar mass:
0.00915 mol NaCl * 58.44 g/mol = 0.535 ghow old is Billie Eilish
Answer:
21
Explanation:
........................
Answer: 21
Explanation:
I can't understand this I need it done by 4:20
Answer:
well 6.3 times 10 is 63 and 6.7 times 10 is 67
Explanation:
What are the oxidant states of the atoms in a diatonic gas
Answer:
If it is elemental gas, the oxidation number is $$0$$.
Explanation:
The oxidation number of an atom in a chemical bond, is the charge left on the atom
How many grams of mercury (II) phosphite would I need to weigh to make 699.9mL of a 1.233e+00 M solution?
Answer
655.61 grams of mercury (II) phosphite.
Explanation
Given:
Volume, V = 699.9 mL = 0.6999 L
Molarity = 1.233e+00 M
What to find:
The grams of mercury (II) phosphite needed to make 699.9mL of a 1.233e+00 M solution.
Step-by-step solution:
Step 1: Calculate the number of moles of mercury (II) phosphite in 699.9mL of a 1.233e+00 M solution.
The moles can be known using the molarity formula:
\(\begin{gathered} Molarity=\frac{Moles}{Volume\text{ }in\text{ }L} \\ \\ Moles=Molarity\times Volume\text{ }in\text{ }L \\ \\ Moles=1.233\text{ }M\times0.6999L \\ \\ Moles=0.8629767\text{ }mol \end{gathered}\)Step 2: Convert the moles of mercury (II) phosphite needed to 699.9mL of a 1.233e+00 M solution to mass in grams.
Using the atomic masses of (Hg = 200.59, P = 30.97, O =15.999) from the periodic table.
The molar mass of mercury (II) phosphite (Hg3(PO3)2) = (3 x 200.59) + 2(30.97 + (3 x 15.999)) = 601.77 + 157.934 = 759.704 g/mol
Therefore, the mass of mercury (II) phosphite needed to 699.9mL of a 1.233e+00 M solution to mass in grams is:
\(\begin{gathered} Mass=Moles\times Molar\text{ }mass \\ \\ Mass=0.8629767\text{ }mol\times759.704\text{ }g\text{/}mol \\ \\ Mass=655.61\text{ }grams \end{gathered}\)Thus 655.61 grams of mercury (II) phosphite are needed to 699.9mL of a 1.233e+00 M solution.
How are radiation levels kept in balance?
Outgoing
Earth emits
Back toward the sun in the form of
Answer:
Explanation:We known that Earths energy machine is driven by sunlight which acts as fuel for this machine and to strike a balance between outgoing long wave radiation and short wave radiation there are many factors which are involved in this process.Sun emits this energy in the form of short wave radiation because of the huge energy it has and short wave radiation are higher in energy.Hence, they reach the earth surface mostly as visible and UV rays.After reaching the earths surface what happens with these rays is that they get absorbed by the clouds and other constituents of Earth.
Now, this energy needs to be emitted back in to space in order to balance out the energy budget of earth and that is why this energy is emitted back as long wave radiation which have less energy and also earth has less energy unlike the sun.Loss of this energy is essential as Earth looses most of its energy through this and results in cooling.But when this OLR decreases it should be a cause of concern for us.
This imbalance is caused by a wide range of different human induced activities which has a cumulative effect on the temperature of earth.These activities gives rise to a huge gain in the CO2 concentration which is why this word has gain so much popularity and a cause of widespread concern for us.At community level we contribute to this heating by increasing usage of personal automobiles rather than going for public transport , advancement in technology has greatly changed our lifestyles making it more simpler and easier but this demands more energy consumption.Landscape changes are one of the most important because its taking place at a faster rate.Most of the land being cleared off to built new houses which means clearing off the existing vegetation which leads to temperature rise.Setting up of Industry depending on its type can reduce the amount of OLR escaping the surface by introducing more amount of GHGs in to the atmosphere.
Its these small communities which add up to become the entire human population causing a massive damage and hence at community level if people realize and take necessary steps things will start to change.
The Ka of a monoprotic weak acid is 0.00469. What is the percent ionization of a 0.141 M solution of this acid?
Use quadratic equation.
The percent ionization of an acidic solution can be calculated from the H+ concentration. the percent ionization of the monoprotic acid of 0.141 M is 18.23 %.
What is percent ionization?Percent ionization of an acidic solution is the percent of H+ ions in the solution. Thus, mathematically, it is the ratio of H+ ion concentration to the concentration of solution multiplied by 100.
Let HA be the monoprotic acid when it ionizes, forming equal concentration of H+ and A- let it be x. Thus ionization constant can be written as follows:
Ka = [x]² /[HA]
0.00469 =[x]²/[0.141 M]
[X] = 0.025. = [H+]
Percentage ionization = (0.025 M / 0.141 M)× 100
= 18.23 %
Therefore percentage ionization of the acid is 18.23%.
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Give the formula of Plaster of Paris And some of its uses..
:))
A refrigerator uses_________________________ energy to move the_________________________ through the refrigerator pipes.
Answer:
thermal; coolant
Explanation:
A refrigerator transfers thermal energy from the cool air inside the refrigerator to the warm air in the kitchen. I hope this helps! ^-^
Based on periodic trends which atom has a larger ionization energy then calcium Ca?
Answer:
Gallium, Germanium, Arsenic, Selenium, Bromine and Krypton
Explanation:
Based on periodic trends, the atom that has a larger ionization energy than calcium are Gallium, Germanium, Arsenic, Selenium, Bromine and Krypton.
Across the period, the ionization energy increases from left to right.
Ionization energy is the energy required to remove the most loosely held electron within an atom. As you go from left to right, the ionization energy increases rapidly.The elements to the right of Ca will have a higher ionization energy compared to Ca.ANSWER QUICK!!!! GIVING BRAINIEST!!!
Answer:
B.
Explanation:
Can you give me brainliest? i need to rank up
Answer:
2nd One is correct
WILL GIVE 50 POINTS AND BRAINLIEST
Plate Tectonics Lab Report
Instructions: In the Plate Tectonics lab you will investigate the interactions between continental and oceanic plates at convergent, divergent, and transform boundaries around the globe. Record your observations in the lab report below. You will submit your completed report.
Name and Title:
Include your name, instructor's name, date, and name of lab.
Objective(s):
In your own words, what was the purpose of this lab?
Hypothesis:
In this section, please include the if/then statements you developed during your lab activity for each location on the map. These statements reflect your predicted outcomes for the experiment.
Location One: Select two events that you predict will be observed. If I explore two continental plates at a convergent boundary, then I will observe:
earthquakes
faults
ocean formation
mountains
volcanoes
island chains
seafloor spreading
Location Two: Select three events that you predict will be observed. If I explore two continental plates at a divergent boundary, then I will observe:
earthquakes
faults
ocean formation
mountains
volcanoes
island chains
seafloor spreading
Location Three: Select three events that you predict will be observed. If I explore two continental plates at a transform boundary, then I will observe:
earthquakes
faults
ocean formation
mountains
volcanoes
island chains
seafloor spreading
Location Four: Select two events that you predict will be observed. If I explore two oceanic plates at a convergent boundary, then I will observe:
earthquakes
faults
ocean formation
mountains
volcanoes
island chains
seafloor spreading
Location Five: Select three events that you predict will be observed. If I explore two oceanic plates at a divergent boundary, then I will observe:
earthquakes
faults
ocean formation
mountains
volcanoes
island chains
seafloor spreading
Location Six: Select two events that you predict will be observed. If I explore two oceanic plates at a transform boundary, then I will observe:
earthquakes
faults
ocean formation
mountains
volcanoes
island chains
seafloor spreading
Procedure:
The procedures are listed in your virtual lab. You do not need to repeat them here. Please be sure to identify the test variable (independent variable), outcome variable (dependent variable).
Reminder: Test variable = the item you are changing or manipulating; Outcome variable = the item you are measuring
Test variable (independent variable):
Outcome variable (dependent variable):
Data:
Record the data from each location below.
Location Name Boundary Type
(C=Convergent, D=Divergent, or T=Transform) Year Observed
(5, 10, or 20 million years) Geologic Events Observed
(earthquakes, faults, ocean formation, mountains, volcanoes, island chains, seafloor spreading)
Location One
Himalayas 5 Event 1-
20 Event 2-
Location Two
East Africa 5 Event 1-
10 Event 2-
20 Event 3-
Location Three
San Andreas fault zone 5 Event 1-
10 Event 2-
20 Event 3-
Location Four
Aleutian Islands 5 Event 1-
20 Event 2-
Location Five
Mid-Atlantic Ridge 5 Event 1-
10 Event 2-
20 Event 3-
Location Six
Alpine Fault 5 Event 1-
20 Event 2-
Conclusion:
Your conclusion will include a summary of the lab results and an interpretation of the results. Please write in complete sentences.
What types of geological events or changes occur at divergent plate boundaries?
What types of geological events or changes occur at convergent plate boundaries?
What types of geological events or changes occur at transform plate boundaries?
Explain how these geological processes and interactions have changed Earth's surface through the years. Be sure to use evidence to support your answer.
Answer:
here are what i have so far, im doing this right now
Explanation:
Plate Tectonics Lab Report
Instructions: In the Plate Tectonic lab you will investigate the interactions between continental and oceanic plates at convergent, divergent, and transform boundaries around the globe. Record your observations in the lab report below. Y
Objective(s):
To look at interactions between continental and oceanic plates, etc.
Hypothesis:
In this section, please include the if/then statements you developed during your lab activity for each location on the map. These statements reflect your predicted outcomes for the experiment.
Location One: Select three events that you predict will be observed. If I explore two continental plates at a convergent boundary, then I will observe:
• earthquakes
• mountains
• volcanoes
Location Two: Select three events that you predict will be observed. If explore two continental plates at a divergent boundary, then I will observe:
• ocean formation
• volcanoes
• seafloor spreading
you will submit your completed report
ps; you might want to change up the objective.
A geological event is a brief, spatially diverse, dynamic and ongoing occurrence in the history of the Earth.
What is geological event?A geological event is a brief, spatially diverse, dynamic (diachronous), and ongoing occurrence in the history of the Earth that aids in the modification of the Earth system and the production of geological strata. The concept of event stratigraphy initially came up as a way to identify, analyse, and correlate how significant physical and biological events have affected the overall stratigraphical record.
Israel's Dead Sea basin Holocene sediments contain seismic activity. This can be considered a record of a geological event, an earthquake, that altered the strata. Geological events can occur over timescales of order of magnitude, from just a few seconds through millions of years, as well as on a variety of spatial scales, from the local to the globe.
1. Volcanoes and minor earthquakes
2. Volcanoes, earthquakes and fold mountains.
3. Earthquakes and fold mountains.
4. Magma from volcanoes is filled with nutrients that makes land fertile.
Therefore, a geological event is a brief, spatially diverse, dynamic and ongoing occurrence in the history of the Earth.
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6. What pattern did you notice in valence electron configuration as you moved through
elements 3–18?
Answer:
The maximum number of valence electrons is 8
Explanation:
element 3 has 3 valence electrons. 7 has 5, and 10 has 8, as we increased the number of electrons in element 11, the number of valence electrons became 3, and the pattern went on, it cannot exceed 8.
The electron configuration of an atom depicts the arrangement of electrons scattered throughout the orbital shells and subshells.
What is period 3 group 18's electron configuration?According to the Periodic Table, P3- has the same electrical configuration as argon, the next Noble gas (Group 18) element, which is 2,8,8.The number of valence electrons in groups 1-2 and 13-18 increases by one from one element to the next across the periodic table's rows, or periods.Electron configurations include: Two trends or patterns should be obvious: For elements in the same Group, the number of valence shell electrons is constant. The number of valence electrons increases from left to right along a Periodic Table period.What substance has a three charge and 18 electrons?Looking at a periodic table or table of elements, we can see that phosphorus (symbol P) has an atomic number of 15.As a result, each atom has 15 protons. The alkali metals are composed of the chemical elements lithium (Li), sodium (Na), potassium (K), rubidium (Rb), caesium (Cs), and francium (Fr).To Learn more About electron configuration, Refer:
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How many molecules are present in 3dm^3 of nitrogen dioxide at r.t.p?
Answer:
At RTP (room temperature and pressure), one mole of any ideal gas occupies a volume of 24.45 dm³. Therefore, we can use the following steps to calculate the number of molecules of nitrogen dioxide in 3 dm³ at RTP:
Calculate the number of moles of nitrogen dioxide in 3 dm³ using the ideal gas law:
PV = nRT
Where:
P = pressure = 1 atm (at standard pressure)
V = volume = 3 dm³
n = number of moles (unknown)
R = gas constant = 0.0821 L atm/(mol K)
T = temperature = 298 K (at standard temperature)
n = PV/RT
n = (1 atm)(3 dm³)/(0.0821 L atm/(mol K) x 298 K)
n = 0.122 mol
Calculate the number of molecules of nitrogen dioxide in 0.122 mol using Avogadro's number:
1 mol of any substance contains 6.022 x 10^23 molecules (Avogadro's number)
Therefore, the number of molecules in 0.122 mol of nitrogen dioxide is:
6.022 x 10^23 molecules/mol x 0.122 mol = 7.35 x 10^22 molecules
Therefore, there are 7.35 x 10^22 molecules of nitrogen dioxide in 3 dm³ at RTP.
Explanation:
75.0 moles of Copper metal reacts with 70.0 moles of chlorine gas to produce copper (II) chloride.
Which reactant is the excess reactant?
Answer:
copper
Explanation:
First, write down the reaction and notice the ratio of moles of which the reactants react.
the equation (i'm too lazy to write states of matter and since it doesnt matter in this problem i'm not going to. it is balanced, however) is:
Cl2 + Cu -> CuCl2
as you can see, one mole of chlorine gas reacts with one mole of copper.
since we have 75 moles of copper but only 70 moles of chlorine gas, after everything has been reacted we would expect 5 moles of copper to be left over. so, copper is the the reactant which is in excess