Heres an interesting math problem can yall solve it??

A pizza that has radius "z" and height "a" has volume of

Answer:

2/3

Step-by-step explanation:

There are 6 faces on a die

probability of rolling a 4 or less (there are 4 numbers) = 4/6 = 2/3

FRIENDLY REMINDER

Don't trust me.

I dont even know what I'm saying

To test if the 7th percentile is the same in two data sets from unknown distributions, you can use a non-parametric test called the Mann-Whitney U test or the Wilcoxon rank-sum test.

1. Mann-Whitney U test:

  - Rank all the data points from both data sets combined.

  - Calculate the sum of ranks for each data set separately.

  - Calculate the U statistic, which is the smaller of the two sums of ranks.

  - Determine the critical value of U from the table or use a statistical software.

  - Compare the calculated U value with the critical value to assess if the 7th percentile is the same.

2. Wilcoxon rank-sum test:

  - Rank all the data points from both data sets combined.

  - Calculate the sum of ranks for each data set separately.

  - Calculate the test statistic W, which is the sum of ranks for one data set.

  - Compute the expected value of W and the variance of W.

  - Calculate the z-score using the formula (W - expected value of W) / sqrt(variance of W).

  - Determine the critical value of the z-score from the table or use a statistical software.

  - Compare the calculated z-score with the critical value to assess if the 7th percentile is the same.

To test if the 7th percentile is the same in two data sets from unknown distributions, you can utilize the Mann-Whitney U test or the Wilcoxon rank-sum test. These non-parametric tests allow you to compare the distributions without making assumptions about their shape or parameters. By calculating the test statistics (U or W) and comparing them with critical values, you can determine if there is sufficient evidence to conclude that the 7th percentile differs between the two data sets. These tests are robust and appropriate when dealing with unknown distributions or when normality assumptions are violated.

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The order of a in (z/(pq))× is exactly (p-1)(q-1), as desired.

To prove that (z/(pq))× has order (p − 1)(q − 1), we need to show that the least positive integer n such that (z/(pq))×n = 1 is (p − 1)(q − 1).

First, let's define (z/(pq))× as the set of all integers a such that gcd(a,pq) = 1 (i.e., a is relatively prime to pq) and a mod pq is also relatively prime to pq.

Now, we know that the order of an element a in a group is the smallest positive integer n such that a^n = 1. Therefore, we need to find the order of an arbitrary element a in (z/(pq))×.

Let's assume that a is an arbitrary element in (z/(pq))×. Since gcd(a,pq) = 1, we know that a has a multiplicative inverse modulo pq, denoted by a^-1. Therefore, we can write:

a * a^-1 ≡ 1 (mod pq)

Now, let's consider the order of a. Since gcd(a,pq) = 1, we know that a^(p-1) is congruent to 1 modulo p by Fermat's Little Theorem. Similarly, we can show that a^(q-1) is congruent to 1 modulo q. Therefore, we have:

a^(p-1) ≡ 1 (mod p)
a^(q-1) ≡ 1 (mod q)

Now, we can use the Chinese Remainder Theorem to combine these congruences and get:

a^(p-1)(q-1) ≡ 1 (mod pq)

Therefore, we know that the order of a must divide (p-1)(q-1).

To show that the order of a is exactly (p-1)(q-1), we need to show that a^k is not congruent to 1 modulo pq for any positive integer k such that 1 ≤ k < (p-1)(q-1).

Assume for contradiction that there exists such a k. Then, we have:

a^k ≡ 1 (mod pq)

This means that a^k is a multiple of pq, which implies that gcd(a^k, pq) ≥ pq. However, since gcd(a,pq) = 1, we know that gcd(a^k, pq) = gcd(a,pq)^k = 1. This is a contradiction, and therefore our assumption must be false.

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The order of a in (z/(pq))× is exactly (p-1)(q-1), as desired.

To prove that (z/(pq))× has order (p − 1)(q − 1), we need to show that the least positive integer n such that (z/(pq))×n = 1 is (p − 1)(q − 1).

First, let's define (z/(pq))× as the set of all integers a such that gcd(a,pq) = 1 (i.e., a is relatively prime to pq) and a mod pq is also relatively prime to pq.

Now, we know that the order of an element a in a group is the smallest positive integer n such that a^n = 1. Therefore, we need to find the order of an arbitrary element a in (z/(pq))×.

Let's assume that a is an arbitrary element in (z/(pq))×. Since gcd(a,pq) = 1, we know that a has a multiplicative inverse modulo pq, denoted by a^-1. Therefore, we can write:

a * a^-1 ≡ 1 (mod pq)

Now, let's consider the order of a. Since gcd(a,pq) = 1, we know that a^(p-1) is congruent to 1 modulo p by Fermat's Little Theorem. Similarly, we can show that a^(q-1) is congruent to 1 modulo q. Therefore, we have:

a^(p-1) ≡ 1 (mod p)
a^(q-1) ≡ 1 (mod q)

Now, we can use the Chinese Remainder Theorem to combine these congruences and get:

a^(p-1)(q-1) ≡ 1 (mod pq)

Therefore, we know that the order of a must divide (p-1)(q-1).

To show that the order of a is exactly (p-1)(q-1), we need to show that a^k is not congruent to 1 modulo pq for any positive integer k such that 1 ≤ k < (p-1)(q-1).

Assume for contradiction that there exists such a k. Then, we have:

a^k ≡ 1 (mod pq)

This means that a^k is a multiple of pq, which implies that gcd(a^k, pq) ≥ pq. However, since gcd(a,pq) = 1, we know that gcd(a^k, pq) = gcd(a,pq)^k = 1. This is a contradiction, and therefore our assumption must be false.

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Answer:

what is the equation ? lmk

Answer: -3 or -$3.

Step-by-step explanation:

First, the set of integer numbers is the set of all the whole numbers (negatives, zero, and positives).

We want to write a $3 loss, now, the most important part here is that we have a loss, so we must represent this with a negative number.

Then we can write this as:

"An integer that represents a $3 loss"

is -3 or -$3 (if we want to also respect the units)

Answer:

p=19

Step-by-step explanation:

since the instructions say that (\(x^{13}\))(\(x^{6}\)) is equivalent to \(x^{p}\), we can make the equation:

(\(x^{13}\))(\(x^{6}\))=\(x^{p}\)

now, apply the laws of exponents; \(a^{m} * a^{n} =a^{m+n}\)

in that case, since we're multiplying x to the 13th power by x to the 6th, the result is \(x^{13+6}\), which is \(x^{19}\)

the equation now:

\(x^{19}\)=\(x^{p}\)

since the exponents are at the same base, we can solve the equation

19=p

so p is 19

hope this helps :)

Answer:

57671680x^9 y^2

Step-by-step explanation:

using combinatorics

Which of the following rational number is equal to 3,4?

31

9

Step-by-step explanation:

That's my opinion and I hope it helps^_^

The number of each type of shirt that Marcus bring to the fair is 80 long-sleeved T-shirts  and 120 short-sleeved T-shirts .

Let x =Number of long-sleeved T-shirts

Let y = Number of short-sleeved T-shirts

Hence,

x + y = 200

1/2x + 1/3y = 80

Using linear Combinations Method:

6[1/2x + 1/3y = 80]

x +y =200

3x + 2y =480

So,

-2(x +y = 200)

3x + 2y = 480

-2x -2y=-400

3x + 2y = 480

x            = 80 (Long sleeved)

Solve for y

80 + y =200

y = 200 -80

y = 120 (Short sleeved)

Therefore he brought  80 and 120  T-shirts .

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In cast iron, the mean number of inclusions per cubic mm is 2.5. We need to calculate the probability of at least one inclusion in one cubic mm, the probability of at most 10 inclusions in 4.0 cubic mm, and the expected number of inclusions in a part with a volume of I cubic cm.

a) To determine the probability of at least one inclusion in one cubic mm of cast iron, we can use the Poisson distribution. The Poisson distribution is appropriate for modeling the occurrence of rare events. In this case, the mean (λ) is given as 2.5. The probability of at least one inclusion is equal to 1 minus the probability of no inclusions. Using the Poisson distribution formula, we can calculate this probability.

b) To calculate the probability of at most 10 inclusions in 4.0 cubic mm of cast iron, we can again use the Poisson distribution. Now, the mean (λ) needs to be adjusted based on the volume. Since the mean is given per cubic mm, we need to multiply it by the volume to get the adjusted mean. The probability can then be calculated using the Poisson distribution formula.

c) The expected number of inclusions in a part with a volume of I cubic cm can be calculated by multiplying the mean (λ) by the volume (I). The expected value of a Poisson distribution is equal to its mean.

By performing these calculations, we can determine the probabilities and expected number of inclusions based on the given mean and volume.

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To find the value of x, we can equate the measures of angle DBE and angle CBE and solve for x. The measure of angle DBE is given as (0.1x - 35) and the measure of angle CBE is given as (0.3x - 38). By setting these two expressions equal to each other, we can solve for x.

1. We start by equating the measures of angle DBE and angle CBE: 0.1x - 35 = 0.3x - 38

2. To solve this equation, we need to isolate the variable x on one side. We can do this by rearranging the equation: 0.1x - 0.3x = -38 + 35

-0.2x = -3

3. Now, we divide both sides of the equation by -0.2 to solve for x: x = (-3) / (-0.2)

4. Simplifying further, we have: x = 15

5. Therefore, the value of x is 15.

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9514 1404 393

Answer:

  x = √2

Step-by-step explanation:

The side ratios in this special triangle are ...

  x/2 = 1/√2

Then ...

  x = 2/√2

  x = √2

Answer:

21 minutes

Step-by-step explanation:

The rate that she types is 15 words in a minute

315/15 =

21 or 21 minutes

Answer:  It will take Tracy 21 minutes to type 315 words

Step-by-step explanation:

Set up a proportional relationship to solve for the  number of minutes.

45 words  = 3 mins

315  words =  x mins.  

\(\frac{45}{315} = \frac{3}{x}\)      Cross multiply  

45x = 945    Divide both sides by 45

 x = 21  

The correct alternative hypothesis constructed in a binomial test is (a) H₁ :P < Q

From the question, we have the following parameters that can be used in our computation:

A. H₁ :P < Q

B. H₁: P - Q

C. H₁ : P = Q

D. H₁ : P ≤ Q

As a general rule of test of hypothesis, alternate hypothesis are represented using inequalities

This means that we make use of <, > or ≠

Hence, the correct alternative hypothesis is (a) H₁ :P < Q

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Question

Which of the following is the correct alternative hypothesis constructed in the binomial test?

A. H₁ :P < Q

B. H₁: P - Q

C. H₁ : P = Q

D. H₁ : P ≤ Q

Answer:

x=10

Step-by-step explanation:

Use pythagorean theorem, a^2+b^2=c^2

24^2 + b^2 = 26^2

576 + b = 676

676-576=100

\(\sqrt{x} 100\)=10

Answer:

x = 10

Step-by-step explanation:

Let b represent x.

Use the Pythagorean Theorem:

\(a^{2} + b^{2} = c^{2}\)

24² + b² = 26²

24² = 576

26² = 676

576 + b² = 676

Subtract 576 from both sides:

b² = 100

Square root of 100:

x = 10

I hope this helped you! If it did, please consider rating, pressing thanks, and marking as Brainliest. Have a great day! :)

Answer:

See below

Step-by-step explanation:

Example:

Let's pretend you were solving \(2^x=8\). If we take the logarithim of both sides, then we eliminate the base on the left side. So this would be \(log_2(2^x)=log_2(8)\). Then, you'll get your answer of \(x=3\).

Answer:

10 miles per hour I'm not sure tho just trying to help :)

Step-by-step explanation:

try to divide

Answer:

10

Step-by-step explanation:

600mph= 10miles/min

Answer:

32 cups

Step-by-step explanation:

To find the total number of cups, we have to convert the measures that are not in cups to cups and add

1 quart  = 4 cups

4 quarts = 4 x4 = 16 cups

1 pint = 2 cups

6 pints = 2 x 6 = 12 pints

total number of cups = 16 + 12 + 4 = 32 cups

Answer:

Step-by-step explanation:

the area of the hemisphere is  1/2 \(\pi\)\(r^{2}\)

the radius is 1/2 the diameter,

the diameter is also the hypotenuse of the isosceles triangle

\(d^{2}\) = \(4^{2}\)+\(4^{2}\)

\(d^{2}\) = 32

d =\(\sqrt{32}\)

r = 1/2\(\sqrt{32}\)

1/2\(\pi\)(1/2\(\sqrt{32}\))^2

1/2\(\pi\)(1/4*32)

(32/8 )*\(\pi\)

4\(\pi\) ( the entire upper hemisphere )

area of the triangle is  1/2* 4 *4 = 8

then the exact area of the parts of the circle would be

4\(\pi\) - 8    

The distance traveled in the first 5.2 seconds when the speed dropped from the rest as v(t) = 9.8t is equal to 132.496 meters.

'v' is the speed of the object in meter per second

't' is the time in seconds.

Speed dropped from rest 'v(t) = 9.8t '

Distance traveled in the first 5.2 seconds is equal to

= \(\int_{0}^{5.2}\)9.8t dt

= ( 9.8 / 2 )t² \(|_{0}^{5.2}\)

Substitute the lower and upper limit to get the required distance we have,

= 4.9 [ ( 5.2)² - 0² ]

= 4.9 × 27.04

= 132.496 meters

Therefore, the distance traveled for the given first 5.2 seconds is equal to 132.496 meters.

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The above question is incomplete, the complete question is:

Free fall the speed v of an object dropped from rest is given by v(t)=9.8t where v is meters per second and time 't' is in seconds.

(a) Express the distance traveled in the first 5.2 seconds as an integral.

Answer:

2 : 1

Explanation:

\(\sf area \ of \ sector: \dfrac{\theta}{360} \pi r^2\)

1st sector:

\(\sf \rightarrow area: \dfrac{80}{360} \pi (8)^2 = 44.68 \ cm^2\)

2nd sector:

\(\sf \rightarrow area: \dfrac{160}{360} \pi (4)^2 = 22.34 \ cm^2\)

Ratio of 1st sector to 2nd sector:

44.68 : 22.34

2 : 1

Answer:

l = 194999.45

Step-by-step explanation:

I'm going to assume that you meant 3.14 by 3,14.

336,765 = 3.14 × 0.55 × (l + 0.55)

336,765 ÷ (3.14 × 0.55) = l + 0.55

(336,765 ÷ (3.14 × 0.55)) - 0.55 = l

l = 194999.45

The HL postulate states that two triangles are congruent if the hypotenuse and leg of one right triangle are congruent with the hypotenuse and leg of another right triangle.

Hypotenuse Leg Theorem

hypotenuse theorem proof shows how a given set of right triangles is congruent when the corresponding hypotenuses and one leg are of equal length.

Statement:

Two triangles are congruent by the hypotenuse leg theorem if the hypotenuse and one leg of a right triangle are congruent with the hypotenuse and leg of another right triangle.

given: where ABC is an isosceles triangle, AB = AC, and AD is perpendicular to BC.

Proof : AD as altitude is perpendicular to BC and forms ADB and ADC as right triangles. AB and AC are the respective hypotenuses of these triangles and we know they are equal. Because AD = AD is common for both triangles.

That is, AB = AC and AD is common.

Therefore, the hypotenuse and pair of legs of the two right-angled triangles satisfy the definition of the HL theorem.

We know that angles B and C are equal (property of isosceles triangle).

We also know that the angles BAD and CAD are equal (AD bisects BC and BD equals CD).

Therefore, △ADB ≅ △ADC

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Answer:

2

Step-by-step explanation:

With the Hubble's constant H₀, the estimated age of the universe would be:

T = 8,332,452,617.49 years.

We know that the age of the universe is something near to the time the galaxies needed to reach their current distance:

T = D/V

And by Hubble's law, we know that:

V = H₀*D

Then we can write:

T = D/(H₀*D) = 1/H₀

So, we can say that the age of the universe is something near the inverse of Hubble's constant.

Then we have:

T = 1/(36 km/s*Mly) = (1/36)  s*Mly/km

Now we need to perform the correspondent change of units.

1 Mly = 1 million light-years

Such that:

1 ly = 9.461*10^12 km

Then 1 million light-years over km is equal to:

1 Mly/km = 1,000,000*(9.461*10^12 km)/km = 9.461*10^18

Then we can replace it:

T = (1/36) s*Mly/km = (1/36)*9.461*10^18 s

T = 2.628*10^17 s

This is the age in seconds, but we want it in years.

We know that:

1 year = 3.154*10^7 s

Then to change the units, we compute:

T = (2.628*10^17 s/3.154*10^7 s)* 1 yea

T = 8,332,452,617.49 years.

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The rule that describes the function is (c) Output = (0.5)(Input) + 1.5

The points on the coordinate plane are given as

(negative 1, 1), (1, 2), (3, 3), (5, 4)

Express as numbers

So, we have

(-1, 1), (1, 2), (3, 3), (5, 4)

Divide the input values by 2

So, we have

0.5(Input) => (-1/2, 1), (1/2, 2), (3/2, 3), (5/2, 4)

Add 1.5 to the input values

So, we have

0.5(Input) + 1.5 => (1, 1), (2, 2), (3, 3), (4, 4)

So, we have

Output = 0.5(Input) + 1.5

Hence, the equation is (c)Output = 0.5(Input) + 1.5

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Answer:

The Greatest Common Factor (GCF) for 70 and 98, notation CGF(70,98), is 14.

Step-by-step explanation: