Hertz's and other physicists' breakthroughs in electromagnetic radiation helped pave the way for radio signal transmission.
Electromagnetic radiation refers to the energy that is transmitted through space in the form of electromagnetic waves, which include radio waves, microwaves, infrared radiation, visible light, ultraviolet radiation, X-rays, and gamma rays. In the late 19th century, Heinrich Hertz conducted experiments to demonstrate the existence of electromagnetic waves and their properties, which laid the foundation for the development of radio communication technology.
Hertz's experiments showed that electromagnetic waves could be generated by oscillating electric charges and that they could travel through space at the speed of light. This discovery paved the way for the development of radio communication technology, as it demonstrated the feasibility of transmitting signals wirelessly over long distances.
In the early 20th century, other physicists such as Guglielmo Marconi and Nikola Tesla built on Hertz's work and developed practical radio communication systems that enabled wireless transmission of audio signals over long distances. Today, radio communication technology is used in a wide range of applications, including broadcasting, telecommunications, and navigation.
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what is the density of the oil? [hint: pressures at points a and b are equal. why?] express your answer with the appropriate units.
The majority of oils have densities that fall within the 700–950 kg/m3 (kg/kg/m3) range. In oils, it is typically stated as +15°C or +20°C, in kilograms per square meter.
Explain density.Density Definition How closely a material gets packed together is determined by its density. It is described as the mass per volume. Density Symbol: D or Density formula: = m/V, where m is the object's mass and V is its volume.
What does density mean, for example?How compact & concentrated anything is is described by its density. Consider having two boxes, on large and one tiny. They each weigh the same, though. As a result, the small box does have a greater density than the huge box. Additionally, density reveals how crowded or concentrated something is.
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As a projectile falls, what happens to the components of velocity?
Question 25 options:
vertical velocity decreases in magnitude, horizontal velocity decreases
vertical velocity decreases in magnitude, horizontal velocity decreases
vertical velocity increases in magnitude, horizontal velocity stays the same
vertical velocity increases in magnitude, horizontal velocity increases
Answer:
Option (c).
Explanation:
An object when when projected at an angle, will have some horizontal velocity and vertical velocity such that,
\(v_x=v\cos\theta\ \text{and}\ v_y=v\sin\theta\)
\(\theta\) is the angle of projection
The horizontal component of the projectile remains the same because there is no horizontal motion. Vertical component changes at every point.
As a projectile falls, vertical velocity increases in magnitude, horizontal velocity stays the same .
As a projectile falls, The vertical velocity increases in magnitude and horizontal velocity stays the same as the components of velocity.
What is vertical velocity?acceleration caused by gravity always affects velocity in the vertical direction, it is a unique sort of velocity. This acceleration, which has a magnitude of around 10 meters/second/second, or 10 meters/second squared, directed downward, toward the center of the earth, affects any object that is hurled up, thrown down, or dropped in a vertical direction.
The thingswhich goess up must come down is a proverb that perfectly captures vertical velocity. Objects will fall back to the earth at a pace of around 10 meters per second every second due to the earth's gravity.
Therefore, As a projectile falls, The vertical velocity increases in magnitude, and horizontal velocity stays the same as the components of velocity.
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4. How has the development of integrated photonics helped increase network
speeds?
The development of integrated photonics has been a key factor in increasing network speeds by enabling the transmission of large amounts of data over optical fibers.
What are integrated photonics?photonics refers to the technology of creating optical devices and systems using semiconductor fabrication techniques, similar to those used in the production of electronic integrated circuits.
One of the most significant contributions of integrated photonics to increasing network speeds is the creation of photonic integrated circuits (PICs). PICs are made up of multiple optical components, such as lasers, modulators, and detectors, integrated onto a single chip. This integration enables faster and more efficient communication between the components, reducing signal loss and improving overall performance.
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a ball is kicked upward with an initial velocity of 56 feet per second. the ball's height, h (in feet), from the ground is modeled by h
The ball's height from the ground is 2.85 feet
Calculation and conceptV = 0
u= 56 feet/ second
h =?
h =\(\frac{u^2}{2g}\) = \(\frac{56}{2*9.8}\) = 2.85 feet
The concept of motion under gravity
When an object moves, it is said to be in motion under gravity since gravity has an impact on the object’s vertical motion.
GRAVITY is the force that pulls things downward. In actuality, gravity pulls objects toward the Earth’s center.
What is the motion under the gravity equation?Consequently, v=gt is the equation of motion.
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11. What kind of force did the levitating rings display? What does this say
about the magnetic domains of these objects? Record your evidence.
answer :
force is called the magnetic force of repulsion, and it happens when two magnets have the same poles (either both north or both south) and they push away from each other.
When all the domains in a material are aligned in the same direction, the material becomes strongly magnetized.
explanation :
magnetic domains in the rings were stable and strong enough to resist the force of gravity.
In the case of the levitating rings, the magnetic domains were aligned in such a way that they created a strong magnetic field, which allowed the rings to levitate in mid-air.
tiny regions within ferro magnetic material that have their own magnetic fields are called magnetic domains.
Magnetic domains in the rings refer to the tiny regions within the ring's ferro magnetic material that have their own magnetic fields.
two vectors have magnitudes 3 m and 4 m. their resultant has a magnitude of 1 m. the angle between the two vectors must be:
The angle between two vectors is found using the dot product of the vectors, so the angle between two vectors must be 90°
According to the question, two vectors of magnitudes 3 m and 4 m are given.
These two vectors' resultant has a magnitude of 1 m.
The angle between two vectors is calculated by using the dot product of the two vectors and dividing it by the product of the magnitudes of the two vectors.
Hence, the angle between the two vectors must be:cosθ= A . B/ |A||B| where A and B are the two given vectors.
Thus, the angle between two vectors is given bycosθ =1/ (3 × 4)cosθ = 1/12θ = cos−1(1/12)θ ≈ 84.3°Thus, the angle between two vectors is approximately 84.3°
Summary: Thus, the angle between two vectors is approximately 84.3°.
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0.0012 g is how many orders of magnitude smaller than 0.0012 kg?
Enter your answer as a number
There are three orders of magnitude difference between 0.0012 grams and 0.0012 kilograms.
What is magnitude?
The definition of magnitude is "how much of a quantity." In order to compare the speeds of an automobile and a bicycle, for example, the magnitude can be utilised. It can also be used to describe how far an object has travelled or how much an object weighs in terms of its magnitude. What then is magnitude in the field of physics? Magnitude is a term used in physics to describe an object's maximal size and direction. Scalar and vector quantities both use magnitude as a common factor. We are aware that scalar quantities are those that have just magnitude by definition. Those quantities with both magnitude and direction are considered vector quantities.
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A sprinter runs a 100 m dash in 12.0 s. She starts from rest with a constant acceleration ax for 2.0 s and then runs with constant speed for the remainder of the race.
the value of ax, given the data from the question is 4.55 m/s²
Data obtained from the questonFrom the question given above, the following data were obtained:
Total distance travelled = 100 mTotal time = 12 sTime for acceleration (t) = 2Acceleration (a) = ax =?How to determine the distance travelled in the first 2 sInitial velocity = 0 m/sAcceleration (a) = axTime (t) = 2 sDistance (s) for the first 2 s = ?s = ½at²
s = ½ × ax × 2²
s = 2ax
How to determine the velocity in the first 2 sAcceleration (a) = axTime for acceleration (t) = 2 sVelocity for the first 2 s (v) = ?v = at
v = ax × 2
v = 2ax
How to determine the value of axRemaining distance = velocity × remaining time
Remaining time = 12 - 2 = 10
Remaining distance = 2ax × 10
Remaining distance = 20ax
Total distance = Distance for first 2 s + Remainng distance
100 = 2ax + 20ax
100 = 22ax
Divide both sides by 22
ax = 100 / 22
ax = 4.55 m/s²
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The model above shows sunlight that is directly hitting one side of the earth during its winter season. Which sentence explains why this area is experiencing shorter hours of daylight
Answer:
During winter time the northern hemisphere leans away from the sun due to the rotation of earth and due to this change the sunlight is not direct on these areas instead it is spread and due to this the shadows are longer and the sunlight is not intense. The earths rotation around the sun causes the seasons to change and that is why we experience shorter hours of daytime.
Explanation:
During winter time the northern hemisphere leans away from the sun due to the rotation of earth and due to this change the sunlight is not direct on these areas instead it is spread and due to this the shadows are longer and the sunlight is not intense. The earths rotation around the sun causes the seasons to change and that is why we experience shorter hours of daytime.
Is the moon accelerating?
Answer:
The Earth's gravity keeps the Moon orbiting us. ... This means gravity makes the Moon accelerate all the time, even though its speed remains constant.
A 700 kg car makes a turn going at 30 m/s with radius of
curvature of 120 m. What is the force of friction between the car's tires and the road?
Answer:5250 N
Explanation: ig:iihoop.vince
The force of friction between the car's tires and the road is 5250 N
Centripetal force is the force that is perpendicular to an object moving in circular motion. It is given by:
F = mv²/r
where m is the mass of object, v is the velocity and r is the radius of circle.
Given that m = 700 kg, v = 30 m/s, r = 120 m, hence:
F = mv²/r = 700 * 30²/120 = 5250 N
The force of friction between the car's tires and the road is 5250 N
What would happen to the predominant protonation state and charge of the his and asp side chains if the ph were to change from 7.40 to 5.00?
The predominant protonation state and charge of the His and Asp side chain will be predominantly protonated and positively charged if both its p\(K_{a}\) values is more than 5.
We know that,
pH = p\(K_{a}\) + ( log [ \(A^{-1}\) ] / [ HA ] )
where,
[ \(A^{-1}\) ] represents deprotonated form
[ HA ] represents protonated form
Consider pH = p\(K_{a}\)
In this case,
[ \(A^{-1}\) ] / [ HA ] = 1
This means that protonated and deprotonated forms are equal.
This also means that as pH decreases, the acid's state will be predominantly protonated and its charge will be positive.
The relationship between pH and p\(K_{a}\) shown above is known as Henderson-Hasselbach equation
Therefore, the predominant protonation state and charge of the His and Asp side chain will be predominantly protonated and positively charged if both its p\(K_{a}\) values is more than 5.
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How can red giants be so bright when they are so cool
Answer:
The star's luminosity rises above its previous level. Because it is so cool, the surface will be red, and it will be much farther away from the center than it was during the earlier stages of star evolution. Despite its lower surface temperature, the red giant has a large surface area, which makes it very luminous.
The two regions of the electromagnetic spectrum where the Earth's atmosphere is transparent (radiation can get in) are visible light and: Group of answer choices
The two regions of the electromagnetic spectrum where the Earth's atmosphere is transparent are visible light and some radio waves.
What is electromagnetic spectrum?The electromagnetic spectrum consists of the range of all types of EM radiation. Radiation is packet of energy that travels and spreads out. It has radio waves, infrared waves, visible light waves, ultraviolet rays and microwaves.
They possess high energy even to penetrate deep within the material. The electromagnetic spectrum has longer wavelength and less frequency.
Thus, the two regions of the electromagnetic spectrum where the Earth's atmosphere is transparent are visible light and some radio waves.
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If a ball is given a push so that it has an initial velocity of 6 m/s down a certain inclined plane, then the distance it has rolled after t seconds is given by the following equation s(t) = 6t + 5t2 (a) Find the velocity after 2 seconds. m/s (b) How long does it take for the velocity to reach 40 m/s? (Round your answer to two decimal places.)
The velocity after 2 seconds is 26 m/s. It takes 11.50 seconds to reach a velocity of 40m/s.
Given the equation s(t) = 6t + 5t²
Let's find the velocity after 2 seconds.
(a) Velocity = (ds)/(dt)
Differentiating s(t) with respect to t, we get; ds(t) / dt = 6 + 10t
At t = 2,ds(t) / dt = 6 + 10t = 6 + 10(2) = 26m/s
Therefore, the velocity after 2 seconds is 26 m/s.
(b) We are to find how long it takes for the velocity to reach 40m/s. We know that the initial velocity of the ball, u = 6m/s. Acceleration = gsinθ = 9.81 x sin (angle of inclination) = 9.81 x 0.3 = 2.943 m/s²From the first equation of motion, v = u + at
We know v = 40m/s, u = 6m/s, a = 2.943m/s² and t is what we are to find, hence the equation becomes;40 = 6 + 2.943(t)t = (40 - 6) / 2.943t = 11.50s
Therefore, it takes 11.50 seconds to reach a velocity of 40m/s.
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Why is nuclear energy able to be used for practical purposes? the reactions are controlled to regulate energy output. the reactions are uncontrolled for maximum energy output. all of the products are fed back into the reaction to keep it going. all of the products are immediately removed to inhibit more reactions.
Nuclear energy is is used practically for many energy requirements because the reactions are controlled to regulate energy output
What is nuclear energy?Nuclear energy is the energy reaelesed during nuclear relations.
Nuclear energy is a clean form of energy which is available in enormous amounts.
Nuclear energy is is used practically for many energy requirements because the reactions are controlled to regulate energy output.
Therefore, the control of nuclear reactions make the use if nuclear energy possible.
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Answer: A or the reactions are controlled to regulate energy output.
Explanation: did it on edge!
What is the frequency of a mechanical wave that has a
velocity of 1.70 m/s and a wavelength æf 12.05 m?
Explanation:
v= (f) x ( lambda)
1.7 ms^-1/12.05 m = f =o.14 hz
Express
3sinωt+8cosωt
in the form
Rsin(ωt+α)
The expression 3sinωt + 8cosωt can be written in the form Rsin(ωt + α) as follows:
Rsin(ωt + α) = √(3² + 8²) sin(ωt + α)
In order to express 3sinωt + 8cosωt in the form Rsin(ωt + α), we need to find the values of R and α.
To determine the value of R, we can use the Pythagorean theorem, which states that for any right triangle, the square of the hypotenuse (R in this case) is equal to the sum of the squares of the other two sides (3 and 8 in this case). Therefore, R = √(3² + 8²) = √(9 + 64) = √73.
To find the value of α, we can use the trigonometric identity: cosα = 3/R, which implies α = cos⁻¹(3/R) = cos⁻¹(3/√73).
Now we have the values of R and α, so we can express 3sinωt + 8cosωt as Rsin(ωt + α), which becomes √73 sin(ωt + cos⁻¹(3/√73)).
In summary, the expression 3sinωt + 8cosωt can be written as √73 sin(ωt + cos⁻¹(3/√73)).
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What is the magnitude (size) and direction of the cumulative force acting on the car shown in the picture above?
A.
2500 N up
B.
30 N to the right
C.
30 N to the left
D.
2500 N down
The vertical forces cancel, so only the horizontal forces are included in the net force. If the right is positive and the left is negative, then
50 N + (-20 N) = 30 N
so the net force is (B) 30 N to the right.
Answer:
(B) 30 N to the right.
Explanation:
If a bicycle has an average acceleration of -0.44 m/s^2, and its initial forward velocity is 8.2 m/s, how long will it take the cyclist to bring the bicycle to a complete stop
Answer:
The value is \(t = 18.6 s\)
Explanation:
From the question we are told that
The average acceleration of the bicycle is \(v = -0.44 \ m/s^2\)
The initial forward velocity is \(u = 8.2 \ m/s\)
Generally from kinematic equations we have that
\(v = u + at\)
Here v is the final velocity of the bicycle and the value is v = 0 m/s
So
\(0 = 8.2 + (-0.44)t\)
=> t = 18.6 s
How do you find the rest mass (kg) of a 3.1 eV electron?
Answer:
Explanation:
The rest energy of any substance is defined by the Einstein's mass energy equivalence relation. Thus the rest mass of a electron is 9.11x10^-31 kg. The speed of light is 299,792,458 m/s. Thus multiplying the square of speed of light with the rest mass of electron gives the rest energy of the electron.
A bar of mass M and length L = 4 meters is pivoted on a fulcrum that is d = 1.8 meters away from the left end. Attached to the left end, a mass m = 5 kg hangs at rest and keeps the system in equilibrium. What is the mass of the bar?
The given problem can be exemplified in the following diagram:
The weight of the bar is concentrated in its center of mass which is located in the middle of the longitude of the bar. We can add the total torques at the point where the pivot touches the bar and we get:
\(\Sigma T=(5\operatorname{kg})(g)(1.8m)-(2m-1.8m)(Mg)\)Here we have used momentum counter-clockwise as positive. Since the system is in equilibrium the sum of the torques must be equal to zero:
\((5\operatorname{kg})(g)(1.8m)-(2m-1.8m)(Mg)=0\)Now we solve the operations, we will use for the acceleration of gravity 9.8 meters per second squared:
\(88.2Nm-1.96M=0\)Now we solve for the mass "M" first by subtracting 88.2Nm from both sides:
\(-1.96M=-88.2Nm\)Now we divide both sides by -1.96:
\(M=\frac{-88.2Nm}{1.96m\frac{m}{s^2}}\)Solving the operations we get:
\(M=45\operatorname{kg}\)Therefore, the mass of the bar is 45 kg.
a battery is connected to two capacitors shown below. the capacitors have air between the plates. capacitor 1 has a plate area of 1.5cm2 and an electric field between its plates of 2000v/m. capacitor 2 has a plate area of 0.7 cm2 and an electric field of 1500v/m. what is the total charge coming out of the power supply?
A battery is connected to two capacitors shown below. the capacitors have air between the plates. The total charge coming out of the power supply: 8.16 × 10⁻⁹ C.
Capacitor 1 has a plate area of 1.5 cm² and an electric field between its plates of 2000 V/m and Capacitor 2 has a plate area of 0.7 cm² and an electric field of 1500 V/m.
Therefore, the total charge coming out of the power supply can be calculated by using the following formula:
Q = C × V,
where Q is the total charge coming out of the power supply.
C is the capacitance of the capacitors.
V is the voltage of the capacitors.
The capacitance of a parallel plate capacitor can be calculated by using the following formula:
C = εA/d,
where C is the capacitance of the capacitor.
ε is the permittivity of air.
A is the area of the capacitor plates.
d is the distance between the plates of the capacitor.
let's calculate the capacitance of the capacitors:
For capacitor 1:
ε = ε₀ = 8.85 × 10⁻¹² F/m²
A = 1.5 cm² = 1.5 × 10⁻⁴ m²d = ?
E = 2000 V/mQ = CV
C = εA/dC₁ = ε₀A/d
C₁ = ε₀A/E₁
C₁ = ε₀A/(V/d)
C₁ = (ε₀A/d) × V⁻¹
C₁ = ε₀A₁/E₁
C₁ = (8.85 × 10⁻¹² F/m²)(1.5 × 10⁻⁴ m²)/(2000 V/m)
C₁ = 6.63 × 10⁻¹⁰ F
For capacitor 2:
ε = ε₀ = 8.85 × 10⁻¹² F/m²
A = 0.7 cm² = 0.7 × 10⁻⁴ m²
d = E = 1500 V/m
Q = CV
C = εA/d
C₂ = ε₀A/d
C₂ = ε₀A/E₂
C₂ = (8.85 × 10⁻¹² F/m²)(0.7 × 10⁻⁴ m²)/(1500 V/m)
C₂ = 3.95 × 10⁻¹¹ F
Total charge coming out of the power supply: Q = C₁V + C₂VQ = (6.63 × 10⁻¹⁰ F)(12 V) + (3.95 × 10⁻¹¹ F)(12 V)Q = 8.16 × 10⁻⁹ C. Therefore, the total charge coming out of the power supply is 8.16 × 10⁻⁹ C.
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If the car travels once around the 100 meters racetrack, what is its displacement?
Answer: 0
Explanation:
hope this helps!
if you add a vector with a magnitude of 1 to a vector of magnitude 2, what magnitudes are possible for the vector sum?
If you add a vector with a magnitude of 1 to a vector of magnitude 2, the possible magnitudes for the vector sum range from 1 to 3.
This is because of the triangle inequality theorem.The triangle inequality theorem states that the magnitude of the sum of two vectors is less than or equal to the sum of their magnitudes. In other words, if we have two vectors A and B, then the magnitude of their sum C is given by:
|C| ≤ |A| + |B|
If we have a vector of magnitude 1, we can call it vector A. If we have a vector of magnitude 2, we can call it vector B.
Then the magnitude of their sum, vector C, is given by:|C| = |A| + |B|.
Since |A| = 1 and |B| = 2, we can substitute those values into the equation: |C| = 1 + 2
|C| = 3
Therefore, the maximum magnitude of the vector sum is 3.
However, the minimum magnitude of the vector sum is found when the vectors are pointing in opposite directions.
In this case, the magnitude of the sum would be:
|C| = |B| - |A|
|C| = 2 - 1
|C| = 1.
Therefore, the possible magnitudes for the vector sum range from 1 to 3.
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a mass attached to a spring vibrates back and forth. at maximum displacement, which of the following values are zero
A mass attached to a spring vibrates back and forth. at maximum displacement.
At the maximum displacement of a mass attached to a spring, the velocity is zero, but the acceleration is not zero.
The maximum displacement is the amplitude of the motion, at which point the restoring force of the spring is at its maximum, and the potential energy is also at its maximum.
The kinetic energy of the system is zero at the maximum displacement. As the mass attached to the spring moves towards its equilibrium position, its kinetic energy increases and its potential energy decreases, until it reaches the equilibrium position where the kinetic energy is at its maximum, and the potential energy is zero. The acceleration is zero at the equilibrium position. As the mass continues to move past the equilibrium position, the potential energy increases, and the kinetic energy decreases until it reaches the maximum displacement again, and the cycle repeats.
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⦁ A body has weight 10 N. How much force is required to move it vertically upward with an acceleration of 3 ms-2?
Answer:
Force = 3.06 Newton.
Explanation:
Given the following data;
Weight = 10N
Acceleration = 3m/s²
To find the force required;
First of all, we would determine the mass of the body.
Weight = mass * acceleration due to gravity
We know that acceleration due to gravity is equal to 9.8m/s².
10 = mass * 9.8
Mass = 10/9.8
Mass = 1.02 kg
Now, we can find the force required by using the formula below;
Force = mass * acceleration
Force = 1.02 * 3
Force = 3.06 Newton.
How many moles are there in
200.00 g Na?
3.32107808 × 10^-22 moles
A current of 10 A moves through a circuit that contains multiple resistors in parallel. Which statement correctly describes the current through the resistors?
The current through all of the resistors will add up to 10 A.
The current through each resistor will be 10 A.
The current will be greatest through the resistor with the highest resistance.
The current will travel only through the resistor with the least resistance.
Answer:
The current through all of the resistors will add up to 10 A.
Explanation:
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What force is acting on the crate once it hits the flat part at the bottom of the ramp? What is the magnitude and direction of that force? (picture included for context)
Answer:
There will be a force of gravity and a normal force coming from the track itself.
Explanation:
Assuming this is a continuation of an earlier question [20398149], the crate starts at rest and is allowed to slide down the ramp with acceleration a = 2.35 m/s², so the block will have some speed as it reaches the bottom of the ramp and it will continue to slide some distance along the flat part.
If the flat part is made of the same material as the ramp, then in addition to its own weight and the normal force, the crate will also feel some friction that slows down its leftward slide.
• The crate's weight and the normal force act vertically, so that
∑ F = n - w = 0
n = w = mg = (100 kg) (9.8 m/s²) = 980 N
(where ∑ F = net force, n = magnitude of normal force, w = crate weight, m = crate mass, g = mag. of gravitational acceleration)
• The friction acts horizontally, so
∑ F = -f = m a
(where f = mag. of friction and a = crate acceleration)
The surface has a coefficient of kinetic friction of µ = 0.3, so
f = µ n = 0.3 (980 N) = 294 N
So at the bottom of the ramp, there are 3 forces exerted on the crate:
• its weight of 980 N pointing downward
• the normal force of the surface pushing upward on the crate, also of 980 N
• friction of 294 N, pointing to the right
and the two vertical forces cancel each other.