Answer:
Explanation:
you can seperate mixtures by filtration, evaporation, distillation and chromatography.
Answer:
I think, i can separate the mixtures through
FiltrationMagnitizationeverpouration to drynessPLS FAST WILL GIVE BRAINLIEST Describe why atoms can be neutral when they contain charged subatomic particles.
Answer:
Atoms are neutral if they have the same number of charged protons and electrons, balancing positive and negative charges. As long as the numbers of electron and protons are the same, the charges will balance.
Which of the following is neutral?
(You may select more than one answer. Select all that apply.)
m atom
electron
O anion
O proton
cation
D neutron
Answer:
atoms and neutrons
Explanation:
electrons have a negative charge
protons have a positive charge
cations are positive ions
anions are negative ions
How would the pattern in the last question be different if the slit were 0.06mm wide instead of 0.02mm? Again assume that the slit is vertical.
If the slit were 0.06mm wide instead of 0.02mm, the pattern would likely exhibit wider interference fringes and a broader diffraction pattern.
How would changing the width of the slit to 0.06mm instead of 0.02mm affect the pattern observed?The width of the slit in a diffraction or interference experiment influences the characteristics of the resulting pattern. A narrower slit, such as 0.02mm, creates a more pronounced diffraction effect, leading to narrower interference fringes and a more focused pattern.
However, if the slit width is increased to 0.06mm, the interference fringes would become wider and the overall diffraction pattern would be broader.
A wider slit allows for a greater range of diffracted angles, leading to a broader spread of the diffracted light. This results in less distinct interference fringes and a less well-defined pattern.
The broader diffraction pattern may exhibit less contrast between the bright and dark regions, making it more difficult to discern fine details or precisely measure the location of interference maxima and minima.
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Which object has the most thermal energy?
A. A 10 kg rock at 10°C
B. A 6 kg rock at 15°C
C. A 10 kg rock at 15°C
D. A 6 kg rock at 10°C
Answer:
10 kg rock at 15 degrees
Explanation:
did test
Two asteroids with masses 3.45 x 103 kg and 6.06 x 104 kg are separated by
a distance of 7,200 m. What is the gravitational force between the asteroids?
Newton's law of gravitation is F gravity =
Gm) m2. The gravitational constant
Gis 6.67 x 10-11 N.m2/kg?
O A. 4.03 N
O B. 2.69 x 10-10 N
O C. 3.38 x 1032 N
O D. 1.93 x 10-6N
The gravitational force between the asteroids is 2.7 × 10^-10 N.
What is gravitation?
Newton's universal law of gravitation states that the force of attraction between any two bodies is inversely proportional to the square of the distance between them and directly proportional to the product of their masses.
Given that:
Two asteroids with masses 3.45 x 10^3 kg and 6.06 x 10^4 kg are separated by a distance of 7,200 m.
Hence, the gravitational force between the asteroids:
F = GmM/r²
= ( 6.67 x 10^-11 × 3.45 x 10^3 × 6.06 x 10^4)/( 7,200)² N
= 2.7 × 10^-10 N.
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Answer:
B 2.69 x 10-10 N
Explanation:
test right yes yes
if load is 10 kn, cross sectionl area is 2 square mm, contact area = 5 square mm. what will be bearing stress?
The bearing stress in this scenario is 2 kN/mm². To calculate the bearing stress, we need to use the formula:
Bearing Stress = Load / Contact Area
Substituting the given values:
Bearing Stress = 10 kn / 5 square mm
Bearing Stress = 2 N/mm^2
It is important to note that bearing stress is a measure of the force per unit area exerted on the contact surface between two components. In this case, the load is distributed over an area of 5 square mm, resulting in a bearing stress of 2 N/mm^2. It is important to ensure that the bearing stress is within the allowable limits to prevent failure or damage to the components.
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if "fair" weather were approaching, the pressure tendency would probably be ________.
The pressure tendency would likely be growing if "good" weather was on the horizon.
What kind of general weather can be anticipated when the pressure tendency is rising?The forecast calls for fair to good weather when the pressure tendency is rising. It is common to expect stormy or inclement weather while the pressure tendency is declining. Clouds and precipitation are linked to low pressure systems because warm air (which holds a lot of water vapour) rises because it is denser than the air above.
What kinds of wind patterns and climate are related to low pressure systems?High-pressure regions are linked to calmer winds and sunny sky, while low-pressure regions are frequently connected with unfavourable weather (such as gloomy, windy, with potential for rain or storms).
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magnitude F have a
resultant of the
same magnitude F.
The angle between
the two forces is:
45 degree
120 degree
150 degree
180 degree
Answer:
120°
Explanation:
Given forces with magnitude F and F
Applying the parallelogram law of vector
Where resultant is given as :
R = √(A^2 + B^2 + 2ABCos Ф
WHERE A and B are two forces with angle Ф
F =√(F^2 + F^2 + 2F * F Cos Ф
Square both sides
F^2 = F^2 + F^2 + 2F^2 CosФ
F^2 - 2F^2 = 2F^2 CosФ
- F^2 = 2F^2 Cos Ф
Divide both sides by 2F^2
- 1 / 2 = CosФ
Cosine(theta) = - 1/2
Ф = cosi^-1 (-1/2)
Ф = 120°
What electromotive force would cause 200 mA of current to flow through a 500ohm resistor? 250 V (B) 10kV 2. 5kV (D) 100 V
The electromotive force would cause 200 mA of current to flow through a 500ohm resistor is (D) 100 V.
The electromotive force that would cause 200 mA of current to flow through a 500 ohm resistor is 100 V. This can be determined using Ohm's law.Ohm's law states that the current through a conductor between two points is directly proportional to the voltage across the two points and inversely proportional to the resistance between them. Mathematically, Ohm's law is represented by the equation V = IR, where V is voltage, I is current, and R is resistance.To find the electromotive force, we can rearrange Ohm's law to be E = IR, where E is electromotive force. Substituting the given values, we have:E = (0.2 A)(500 Ω)E = 100 V .
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A turntable must spin at 33.3 rev/min (3.49 rad/s) to play an old-fashioned vinyl record. How much torque must the motor deliver if the turntable is to reach its final angular speed in 1.70 revolutions, starting from rest? The turntable is a uniform disk of diameter 30.5 cm and mass 0.220 kg.
ANSWER:
0.00145 J
STEP-BY-STEP EXPLANATION:
Using the rotational form of the kinematic equation to find α:
\(\omega^2_f=\omega^2_i+2\alpha\theta\)It started form rest:
\(\begin{gathered} \omega^{}_i=0\text{ rad/s} \\ \theta=1.7\text{ rev }=3.4\pi\text{rad} \end{gathered}\)Solving for α:
\(\begin{gathered} \alpha=\frac{\omega^2_f}{2\theta} \\ \alpha=\frac{3.49^2}{2\cdot3.4\pi} \\ \alpha=0.57rad/s^2 \end{gathered}\)The torque is given by the formula,
\(\begin{gathered} \tau=I\alpha \\ \text{for a uniform disk} \\ I=m\cdot\frac{r^2}{2},\text{ along the vertical a}\xi s\text{ in the center.} \\ \text{Therefore,} \\ \tau=m\cdot\frac{r^2}{2}\cdot\alpha,r=\frac{0.305}{2}=0.1525 \\ \text{ replacing} \\ \tau=0.22\cdot\frac{0.1525^2}{2}\cdot0.57 \\ \tau=0.00145\text{ J} \end{gathered}\)A 2kg rock is dropped from a height of 10m and hits the ground going 11m/s. How much work was done by air resistance as it fell?
Answer: 0.24 kg/m
Explanation: use k = ρ * A * C / 2 as the formulapart a find the gravitational potential energy of an 79 kg person standing atop mt. everest at an altitude of 8848 m. use sea level as the location for y=0.
The gravitational potential energy of a 79 kg person standing atop Mt. Everest at an altitude of 8,848 m is approximately 6.12 x 10^7 J.
The gravitational potential energy (GPE) of an object is given by the formula GPE = mgh, where m is the mass of the object, g is the acceleration due to gravity, and h is the height of the object above some reference point. In this case, we are given that the person has a mass of 79 kg and is standing atop Mt. Everest at an altitude of 8,848 m above sea level, which we can use as our reference point (i.e., y=0).
We can find the acceleration due to gravity at this altitude using the formula g' = (GM)/(r+h)^2, where G is the gravitational constant, M is the mass of the Earth, r is the radius of the Earth, and h is the height of the person above the Earth's surface. Plugging in the appropriate values, we get g' ≈ 9.760 m/s^2.
Using this value of g', we can now calculate the GPE of the person using the formula GPE = mgh. Plugging in the values we have, we get GPE ≈ (79 kg)(9.760 m/s^2)(8,848 m) ≈ 6.12 x 10^7 J. Therefore, the gravitational potential energy of the person is approximately 6.12 x 10^7 J.
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What do plasma cells produce ?
The engine of the car develops a driving force of 4000N. Air resistance also acts on the car, with a force of R. If the car has a mass of 1000kg, and is accelerating at 1.5m/s^2, calculate the magnitude of R.
Answer:
R = -2500N
Explanation:
Use formula ΣF = Ma. We can split the Net Force into two parts: Fe - Ff = Ma.
Fe is the force developed by the engine: 4000N
Ff (R) is the air resistance projected on the vehicle. This is the value we're looking for.
Mass: 1000kg
Acceleration: 1.5m/s^2
Next, just plug in the values and solve.
▪4000N - Ff = (1000kg)(1.5m/s^2)
▪Ff = 1500N - 4000N
▪Ff = -2500N
R = -2500N.
The air resistance acting on the car is R = -2500N.
A piano string vibrates with a
frequency of 262 Hz. If these sound
waves have a wavelength in the air of
1.30 m, what is the speed of sound?
Answer:
The speed of sound can be calculated using the formula:
speed of sound = frequency × wavelength
Substituting the given values:
speed of sound = 262 Hz × 1.30 m = 340.6 m/s
Therefore, the speed of sound in air is approximately 340.6 m/s.
If a hypothesis is.......
additional tests should be done to ensure accurate results.
a. correct
b.incorrect
c. unknown
d. inconclusive
Answer:
a correct
Explanation:
a hypothesis is a supposition made of a basis of limited evidence
what increases decreases and stays the same in the following table?
Volum of bubble increases
Mass of gas is same
Destiny of gas in buble wil be. It joins to air
Which of the following is an example of an opposing force?
A.Gravity pulling a ball down a hill
B.Wind blowing a leaf off of a tree
C.Gravity holding a rock still on the ground
D.Water pushing against someone as they wade through a pool
An experimenter exposed participants to different room temperatures to determine the effects on aggression. Aggression was the:
A. independent variable
B. dependent variable
C. control variable
D. confounding variable
An experimenter exposed participants to different room temperatures to determine the effects on aggression. Aggression was the dependent variable.
A variable is a characteristic, quality, or quantity that can take on different values.
In scientific research, variables are used to measure, analyze, and evaluate a phenomenon.
These can be continuous or discrete.
Variables are divided into two categories: independent variables and dependent variables.
An independent variable is a variable that does not depend on other variables, whereas a dependent variable is a variable that is dependent on other variables.
The independent variable is the variable that researchers manipulate or control, while the dependent variable is the variable that researchers measure or observe.
In scientific research, an independent variable is a variable that is manipulated, whereas a dependent variable is a variable that is observed.
An experimenter exposed participants to different room temperatures to determine the effects on aggression.
In this study, the independent variable is room temperature, while the dependent variable is aggression.
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Ranking Task: Understanding Curved Spacetime
Part C: The figures below show several different astronomical objects. Rank the objects based on the amount that spacetime is curved (relative to flat spacetime) very near the surface (or event horizon) of the objects, from least to greatest.
(1) Star, (2) Neutron star, (3) Black hole, (4) Singularity. This ranking is based on the increasing strength of gravitational effects and curvature of spacetime caused by these objects.
1. Star:
A star, such as our Sun, has a relatively weak gravitational field, resulting in minimal curvature of spacetime near its surface. While the presence of a star causes a slight bending of spacetime, the effect is significantly smaller compared to other astronomical objects.
2. Neutron star:
A neutron star is more massive and compact than a regular star, leading to a stronger gravitational field and curvature of spacetime near its surface. The intense gravitational forces and high density of a neutron star cause a significant curvature of spacetime, although it is less pronounced than that of a black hole.
3. Black hole:
A black hole is formed when a massive star collapses under its own gravity, creating an extremely dense object with an event horizon. The gravitational forces near a black hole are incredibly strong, resulting in a substantial curvature of spacetime. As objects approach the event horizon, the curvature becomes increasingly significant.
4. Singularity:
At the center of a black hole lies the singularity, a point of infinite density and gravitational pull. The curvature of spacetime near a singularity is immensely strong, and our current understanding of physics breaks down at this point. The singularity represents the most extreme curvature of spacetime within the black hole.
Therefore, ranking the astronomical objects based on the amount that spacetime is curved near their surfaces or event horizons, from least to greatest, we have: (1) Star, (2) Neutron star, (3) Black hole, (4) Singularity.
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Please help, I keep getting an answer that isn't an option.
A student does 6 J of work compressing a spring by 0.04 m. What is the spring constant of the spring?
(A) 150 N/m (B) 300 N/m (C) 3333 N/m (D) 7500 N/m
Answer:
D 7500
Explanation:
Energy is elastic potential energy
EPE=1/2 kx^2
6=1/2 k(0.04)^2
6=k (0.0016/2)
k = 6/0.0008 = 7500
Which refers to the rate of change in velocity? speed acceleration direction magnitude I need this answer i cant figure it out!!
Answer: Acceleration
Explanation: In this case its most likely acceleration as it has the definition of quick change in velocity. Therefore, the answer is acceleration.
Acceleration refers to the rate of the change in the velocity , therefore the correct answer is option B .
What is acceleration ?The rate of change of the velocity with respect to time is known as the acceleration of the object. Generally, the unit of acceleration is considered as meter/seconds².
As given in the problem statement we have to find out which terminology from the given list of options refers to the rate of change in velocity .
Speed refers to the rate of the change in the distance, while magnitude refers to the numerical quantity of any measured quantity .
The acceleration of any material = rate of the change of the velocity of the material
Thus , Acceleration refers to the rate of the change in the velocity, therefore the correct answer is option B.
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Where does the force come from that propels a rocket forward?
it is called the trust Answer:
Explanation:
(a) Find the typical speed of a conduction electron in copper, taking its kinetic energy as equal to the Fermi energy, 7.05eV .
The typical speed of a conduction electron in copper, taking its kinetic energy as equal to the Fermi energy, 7.05eV is 4.974 km/s.
The energy that an object has due to its motion or acceleration is called kinetic energy. When work is done to move an object from one place to another, the energy transferred to the object is stored as kinetic energy.
The kinetic energy of an object can be calculated using the formula:
Kinetic Energy (KE) = (1/2) * mass * velocity^2
Where:
KE is the kinetic energy of the object,
mass is the mass of the object, and
velocity is the speed of the object.
The kinetic energy of an object depends on its weight and speed. As the mass or speed of an object increases, its kinetic energy also increases. This means that an object with greater mass or higher speed will have more kinetic energy than an object with lower mass or speed. Kinetic energy is a scalar quantity with the SI unit Joule (J).
v= 3*10^5 under root 2*7.05/5.11*10^5
=4.974
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When using the lens equation, a negative value as the solution for d baseline i indicates that the image is
A. real
B. virtual
C. upright
D. inverted
When using the lens equation, a negative value as the solution for d baseline i indicates that the image is Virtual. The correct option is B.
What is reflection?When a light strikes on a shiny surface, it reflects back the light ray in the same medium. The phenomenon is called reflection and the ray is called the reflected ray.
From the Len's maker formula, e have
1/f = 1/u + 1/v
where f = radius of curvature /2
So, the negative value as the solution for d baseline i indicates that the image is Virtual.
Thus, the correct option is B.
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a ladybug sits 11.5 cm from the center of a turntable spinning at 33.33 rpm. the sun is shining horizontally through the window and the shadow of the ladybug can be seen traveling back and forth across the wall behind the turntable. what is the maximum velocity, in meters per second, of the shadow on the wall?
Thus, the maximum velocity of the shadow on the wall is 2(0.401 m/s) = 0.802 m/s or 2.38 m/s to two significant figures.
The problem involves a ladybug crawling on a turntable, and its shadow moving back and forth on a wall.
To determine the maximum speed of the shadow on the wall, we need to calculate the linear velocity of the ladybug as it moves on the turntable using the formula v = rω, where v is the linear velocity, r is the distance from the center of the turntable to the ladybug, and ω is the angular velocity of the turntable.
The distance from the center of the turntable to the ladybug is given, and we can calculate the angular velocity of the turntable using the formula ω = 2πf, where f is the frequency of the turntable in revolutions per minute (rpm).
Plugging in the values we know into the formula v = rω, we can determine the maximum speed of the shadow on the wall to be 0.802 m/s, taking into account the shadow's movement back and forth across the wall.
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An organ pipe closed at one end and open at the other has a length of 1.8 m.
Given,
The length of the pipe, L=1.8 m
Speed of the sound, v=340 m/s
To form the standing wave with the longest wavelength, the number of nodes of the thus formed standing wave should be equal to 1.
The wavelength of the standing wave created in a closed-end pipe is given by,
\(\lambda=\frac{4}{1}L\)On substituting the known values,
\(\begin{gathered} \lambda=\frac{4}{1}\times1.8 \\ =7.2\text{ m} \end{gathered}\)Thus the longest possible wavelength is 7.2 m
The frequency of this standing wave is given by,
\(f=\frac{v}{\lambda}\)On substituting the known values,
\(\begin{gathered} f=\frac{340}{7.2} \\ =47.22\text{ Hz} \end{gathered}\)Thus the frequency of this standing wave is 47.22 Hz.
A railway wagon of mass 100 kg is pulled with a force of 1000 N. what is its Acceleration ?
Solution,
Mass(m)= 100kgForce(F)= 1000NAcceleration (a)=?We know that,
\(f = ma \\ \frac{f}{m} = a \\ \frac{1000}{100} = a \\ 10 = a\)
Therefore,
Acceleration produced will be 10m/s².
a) A cell of dry air is moved vertically from its original position under adiabatic conditions. Depending on the temperature profile of the surrounding atmosphere, this gas cell can keep on moving in the same direction, or it may come back to its original position. Considering the temperature profile of the atmosphere, change of the air cell temperature as it moves up and down in the surrounding atmosphere, as well as relative densities of the air cell and atmosphere, explain why and when the atmosphere is considered to be convectively stable and convectively unstable. In answering this question, use diagrams of temperature change with altitude. (13 marks) b) Explain why the adiabatic lapse rate of dry air is different from the adiabatic lapse rate of wet saturated air. Show them both in a diagram. (5 marks) c) Wet unsaturated air rises from the ocean surface. The ambient lapse rate is higher than the adiabatic lapse rate for dry air. There is a temperature inversion layer at higher altitudes. Show in a schematic diagram how the temperature of the wet air changes with altitude, in comparison with the ambient temperature. Explain at what altitudes the cumulus clouds are formed and why. (7 marks)
The question addresses the stability of the atmosphere and the factors that determine convective stability or instability. It also explains the difference between the adiabatic lapse rate of dry air and wet saturated air.
a) The stability of the atmosphere is determined by the temperature profile and relative densities of the air cell and atmosphere. If the temperature of the surrounding atmosphere decreases with altitude at a rate greater than the adiabatic lapse rate of the air cell, the atmosphere is considered convectively stable.
In this case, the air cell will return to its original position. Conversely, if the temperature of the surrounding atmosphere decreases slower than the adiabatic lapse rate of the air cell, the atmosphere is convectively unstable. The air cell will continue moving in the same direction.
b) The adiabatic lapse rate refers to the rate at which temperature decreases with altitude for a parcel of air lifted or descending adiabatically (without exchanging heat with its surroundings). The adiabatic lapse rate of dry air is higher (around \(9.8^0C\) per kilometer) compared to the adiabatic lapse rate of wet saturated air (around 5°C per kilometer).
This difference arises because when water vapor condenses during the ascent of saturated air, latent heat is released, reducing the rate of temperature decrease. A diagram can illustrate the difference between the two lapse rates, showcasing their respective slopes.
c) When wet unsaturated air rises from the ocean surface, its temperature decreases at a rate equal to the dry adiabatic lapse rate. However, if the ambient lapse rate (temperature decrease with altitude) is higher than the adiabatic lapse rate for dry air, a temperature inversion layer forms at higher altitudes.
In this inversion layer, the temperature increases with altitude instead of decreasing. A schematic diagram can depict the temperature changes of the wet air in comparison to the ambient temperature, showing the inversion layer.
Cumulus clouds form at the altitude where the rising moist air reaches the level of the temperature inversion layer. These clouds are formed due to the condensation of water vapor as the air parcel cools to its dew point temperature.
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Convert 13.6g/cm3 into kg/m3
Answer:
0.000136kg/m3
Explanation:
13.6 / 1000 = 0.0136kg/cm3
0.0136 / 100 = 0.000136kg/m3