How are mechanical wave different from electromagnetic waves?

Given that,

Mass of a frog, m = 0.5 kg

The frog leaps pushing off of the rock with an acceleration of 5.0 m/s².

To find,

The magnitude of the net force exerted on the frog as it leaps.

Solution,

Let the net force exerted on the frog is given by the formula as follows :

F = ma

Putting the values of m and a to find F as follows :

F = 0.5 kg × 5 m/s²

F = 2.5 N

So, the magnitude of net force is 2.5 N.

The magnitude of the net force exerted on the frog as it leaps is 2.5 Newtons.

Hence, Option a) 2.5N is the correct answer.

Given the data in the question;

Force Exerted; \(F = ?\)

To determine the magnitude of the net force exerted on the frog as it leaps, we the expression from the Newton's Second law of motion:

\(F = m * a\)

Where m is mass and a is acceleration

We substitute our given values into the equation

\(F = 0.5kg * 5.0m/s^2\\\\F = 2.5kgm/s^2\\\\F= 2.5N\)

The magnitude of the net force exerted on the frog as it leaps is 2.5 Newtons.

Hence, Option a) 2.5N is the correct answer.  

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The technology that addresses a practical problem with sharing information is wireless device.

Technology is simply the application and organization of knowledge for practical purposes.

Technology has proven to make work more efficient and there is no overemphasis of its role in communication sector.

A wireless device is a technological device relating to communication without a wired connection, such as by radio waves.

Therefore, it can be said that the technology that addresses a practical problem with sharing information is wireless device.

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Answer:

Explanation:

Welcome to Pagasi b,  new recruit.  You will enjoy your new, fresh , home planet.  Your new home world is more relaxed than earth, days are longer by about quadruple, as are the nights.   Also seasons are also about 4 times  as long on Pagasi b. one year on Pagasi b is a bit over 4 years on earth.  You'll get great harvests and plenty of time to rest up during the mild, yet cool winters.  If the equatorial region is too warm for you during summer you can always travel north as the planet is at a 79 degree axis tilt , and will provide much cooler climes as you travel north for summers.  Have a great day, day, day, day   :P

A baseball is thrown vertically upward and feels no air resistance. As it is rising its momentum is not conserved, but its mechanical energy is conserved.

Momentum may be defined as a unique property of a moving body that the body has by virtue of its mass and motion and that is equal to the product of the body's mass and velocity.

According to the context of this question, as an object typically moves along the vertical direction, the gravitational potential energy, and the kinetic energy change. So, due to this, its momentum is not conserved, but its mechanical energy is conserved.

Therefore, a baseball is thrown vertically upward and feels no air resistance. As it is rising its momentum is not conserved, but its mechanical energy is conserved.

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Answer:

Technology is the application of scientific knowledge to the practical aims of human life or, as it is sometimes phrased, to the change and manipulation of the human environment.

Please Mark it as brainlist answer.

Density is defined as mass divided by volume. Therefore, in order to compare the densities of two objects, we need to know their masses as well as their volumes.

In this case, we are comparing two pieces of glass, one weighing 500 grams and the other weighing 50 grams. However, we do not have any information about their volumes.

Without knowing the volumes of the glass pieces, we cannot determine which one has a greater density. Density depends on both mass and volume, so we need information about both parameters to make a comparison.

Therefore, based on the given information, we cannot determine which of the two glass pieces has a greater density.

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Answer:

They're are Conditions .... (L00K D0WN.)

Explanation:

Conditions for equilibrium require that the sum of all external forces acting on the body is zero (first condition of equilibrium), and the sum of all external torques from external forces is zero (second condition of equilibrium). These two conditions must be simultaneously satisfied in equilibrium.

A&L Engineering, as an engineer, you've been tasked with evaluating the durability of three common materials used in the design of cell phone cases.

These materials include:Carbon FiberPolycarbonateTPUExplanation:Carbon fiber is a lightweight, durable, and corrosion-resistant composite material. It is often used in the aerospace, automotive, and sporting goods industries.Polycarbonate is a thermoplastic polymer that is strong, shatter-resistant, and lightweight. It is often used in the production of CDs, DVDs, and eyeglass lenses.

TPU (thermoplastic polyurethane) is a flexible, soft material that is abrasion-resistant and provides excellent impact protection. It is often used in the production of phone cases, as well as sporting equipment and medical devices.To evaluate the durability of these materials, you can conduct a series of tests to measure their resistance to impacts, scratches, and bending.

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The nucleus of an isotope is radioactive due to an imbalance between the number of protons and neutrons in the nucleus.

Stable nuclei have a balanced ratio of protons to neutrons, but when this balance is disrupted, the nucleus can become unstable and undergo radioactive decay.

The instability of a radioactive isotope's nucleus can be attributed to the strong nuclear force, which is the force that binds protons and neutrons together in the nucleus.

The rate of radioactive decay is measured by the half-life of the isotope, which is the amount of time it takes for half of the atoms in a sample of the isotope to decay.

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The number of turns needed on the secondary coil is 45. The transformer is a device that transfers electrical energy from one circuit to another through electromagnetic induction.

In order to determine the number of turns needed on the secondary coil of the transformer, we need to use the equation:

Vp/Vs = Np/Ns

Where Vp is the potential difference on the primary coil, Vs is the potential difference on the secondary coil, Np is the number of turns on the primary coil, and Ns is the number of turns on the secondary coil.

We know that Vp is 1.5V and Vs is 5.0V. We also know that Np is 150. So, we can rearrange the equation to solve for Ns:

Ns = (Vp/Vs) x Np

Ns = (1.5V/5.0V) x 150

Ns = 45

Therefore, the number of turns needed on the secondary coil is 45. The transformer is a device that transfers electrical energy from one circuit to another through electromagnetic induction. The voltage ratio between the primary and secondary coils is determined by the ratio of the number of turns in each coil.

In this case, we are given the input and output voltages and the number of turns on the primary coil, and we use this information to calculate the number of turns needed on the secondary coil.

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The final temperature of the mixture of 100g of water at 85ºC and 100g of ice at 0ºC  is c. 42.5ºC.

The final temperature of the water can be predicted using the principle of heat exchange. The heat lost by the water must be equal to the heat gained by the ice.

Let's denote the final temperature as T. We can set up the heat exchange equation:

Q_lost (by water) = Q_gained (by ice)

The specific heat capacity of water is 4.18 J/gºC, and for ice, it's 2.09 J/gºC. The heat of fusion for ice is 334 J/g.

Heat lost by water: mass_water x specific_heat_water x (initial_temperature_water - T)
Heat gained by ice: (mass_ice x specific_heat_ice x T) + (mass_ice x heat_of_fusion)

So, we have:

(100g x 4.18 J/gºC x (85ºC - T)) = (100g x 2.09 J/gºC x T) + (100g x 334 J/g)

After solving this equation, we get T ≈ 42.5ºC. Therefore, the correct answer is c. 42.5ºC.

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Therefore, the initial kinetic energy of the ball is approximately 10,587 J.

The initial kinetic energy of a 7.0 kg ball launched at 54 m/s at an angle of 67 degrees can be calculated as follows:

Step 1: Find the horizontal and vertical components of the velocity:

vx = v cos θ

vx = 54 cos 67°

vx = 21.9 m/s

vy = v sin θ

vy  = 54 sin 67°

vy  = 50.6 m/s

Step 2: Find the magnitude of the velocity:

|v| = √(vx² + vy²)

|v|= √(21.9² + 50.6²)

|v| = 55.4 m/s

Step 3: Calculate the initial kinetic energy of the ball:

KE = (1/2)mv²

KE = (1/2)(7.0 kg)(55.4 m/s)²

KE ≈ 10,587 J

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Answer:

The percentage uncertainty in his calculated value of density is \(\pm 0.713\,\%\).

Explanation:

We can estimate the absolute uncertainty by the definition of total differential. That is:

\(\Delta \rho \approx \frac{\partial \rho}{\partial m}\cdot \Delta m + \frac{\partial \rho}{\partial d}\cdot \Delta d + \frac{\partial \rho}{\partial l}\cdot \Delta l\) (1)

Where:

\(\frac{\partial \rho}{\partial m}\) - Partial derivative of the density with respect to mass, measured in \(\frac{1}{mm^{3}}\).

\(\frac{\partial \rho}{\partial d}\) - Partial derivative of the density with respect to diameter, measured in grams per cubic milimeter.

\(\frac{\partial \rho}{\partial l}\) - Partial derivative of the density with respect to length, measured in grams per cubic milimeter.

\(\Delta m\) - Mass uncertainty, measured in grams.

\(\Delta d\) - Diameter uncertainty, measured in milimeters.

\(\Delta l\) - Length uncertainty, measured in milimeters.

\(\Delta \rho\) - Density uncertainty, measured in grams per cubic milimeters.

Partial derivatives are, respectively:

\(\frac{\partial \rho}{\partial m} = \frac{4}{\pi\cdot d^{2}\cdot l}\) (2)

\(\frac{\partial \rho}{\partial d} = -\frac{8\cdot m}{\pi\cdot d^{3}\cdot l}\) (3)

\(\frac{\partial \rho}{\partial l} = - \frac{4\cdot m}{\pi\cdot d^{2}\cdot l^{2}}\) (4)

And we expand (1) as follows:

\(\Delta \rho \approx \frac{4\cdot \Delta m}{\pi\cdot d^{2}\cdot l} - \frac{8\cdot m\cdot \Delta d}{\pi\cdot d^{3}\cdot l}-\frac{4\cdot m\cdot \Delta l}{\pi\cdot d^{2}\cdot l^{2}}\)

\(\Delta \rho \approx \left(\frac{4}{\pi\cdot d^{2}\cdot l}\right)\cdot \left(\Delta m -\frac{m\cdot \Delta d}{d}-\frac{m \cdot \Delta l}{l} \right)\) (5)

If we know that \(d = 2\,mm\), \(l = 25\,mm\), \(m = 6.2\,g\), \(\Delta m = \pm 0.1\,g\), \(\Delta d = \pm 0.01\,mm\) and \(\Delta l = \pm 0.1\,mm\), then the absolute uncertainty is:

\(\Delta \rho \approx \pm\left[\frac{4}{\pi\cdot (2\,mm)^{2}\cdot (25\,mm)} \right]\cdot \left[(0.1\,g)-\frac{(6.2\,g)\cdot (0.01\,mm)}{2\,mm} -\frac{(6.2\,g)\cdot (0.1\,mm)}{25\,mm} \right]\)

\(\Delta \rho \approx \pm 5.628\times 10^{-4}\,\frac{g}{mm^{3}}\)

And the expected density is:

\(\rho = \frac{4\cdot m}{\pi\cdot d^{2}\cdot l}\) (6)

\(\rho = \frac{4\cdot (6.2\,g)}{\pi\cdot (2\,mm)^{2}\cdot (25\,mm)}\)

\(\rho \approx 78.941\times 10^{-3}\,\frac{g}{mm^{3}}\)

The percentage uncertainty in his calculated value of density is:

\(\%e = \frac{\Delta \rho}{\rho}\times 100\,\%\) (7)

If we know that \(\Delta \rho \approx \pm 5.628\times 10^{-4}\,\frac{g}{mm^{3}}\) and \(\rho \approx 78.941\times 10^{-3}\,\frac{g}{mm^{3}}\), then the percentage uncertainty is:

\(\%e = \frac{\pm 5.628\times 10^{-4}\,\frac{g}{mm^{3}} }{78.941\times 10^{-3}\,\frac{g}{mm^{3}} }\times 100\,\%\)

\(\%e = \pm 0.713\,\%\)

The percentage uncertainty in his calculated value of density is \(\pm 0.713\,\%\).

The pendulum is now swinging on Pluto.

Oscillation is the repetitive or periodic variation, usually over time, of a measurement about a central value or between two or more different states. Familiar examples of oscillations are swinging pendulums and alternating currents.

The oscillatory motion of a simple pendulum is defined as the periodic back-and-forth motion of the pendulum. The reciprocating motion of the bob starting at one end and returning to the same position is called a pendulum swing.

Oscillation is the repeated or periodic variation of a measurement about a central value  or between two or more different states, usually over time. Familiar examples of oscillations are swinging pendulums and alternating currents.

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Answer:

5.03×10¯⁷ N

Explanation:

From the question given above, the following data were obtained:

Mass of the person (M₁) = 55 Kg

Mass of the car (M₂) = 1234 Kg

Distance apart (r) = 3 m

Gravitational constant (G) = 6.673×10¯¹¹ Nm²/Kg²

Force (F) =?

The force between the person and his car can be obtained as follow:

F = GM₁M₂ / r²

F = 6.673×10¯¹¹ × 55 × 1234 / 3²

F = 6.673×10¯¹¹ × 67870/ 9

F = 5.03×10¯⁷ N

Thus, the force between the person and his car is 5.03×10¯⁷ N

Answer:

Increase height

Increase mass

The new length of the beam is therefore 30.2205 cm and the new volume of the glass beam is therefore 71.207 cm3.

Length is a measure of the size of something. It is usually measured in units of distance such as metres, kilometres, miles, yards, and feet. Length can also refer to the duration of time, such as seconds, minutes, hours, days, weeks, months, and years. Length can be used to describe the size of objects, including physical objects such as a car, a table, a book, or a room, as well as abstract objects such as a sentence, a piece of music, or a journey.

The increase in length of the glass beam due to an increase in temperature of 85.0°C can be calculated using the formula for linear expansion:

ΔL = L0*α*ΔT

where L0 is the original length of the beam, α is the coefficient of linear expansion, and ΔT is the change in temperature.

For this problem, L0 = 30.0 cm, α = 9.00 x 10-6/°C, and ΔT = 85.0°C. Substituting these values into the equation yields:

ΔL = 30.0 cm * (9.00 x 10-6/°C) * 85.0°C

= 2.205 x 10-3 cm = 0.2205 mm

The new length of the beam is therefore 30.2205 cm.

The new volume of the glass beam can be calculated using the formula for the volume of a cylinder:

V = πr2h

where r is the radius of the beam and h is the height (or length).

For this problem, r = 0.75 cm and h = 30.2205 cm. Substituting these values into the equation yields:

V = π(0.75 cm)2(30.2205 cm)

= 71.207 cm3

The new volume of the glass beam is therefore 71.207 cm3.

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The mass of the given will be 20kg.

By using formula,

force = mass x acceleration

mass = force / acceleration

mass = 400 N / 20m/s²

mass = 20 Kg

Acceleration is the rate at which an object's velocity with respect to time changes. They are vector quantities, accelerations. The direction of the net force acting on an object determines the direction of its acceleration.

Any process where the velocity changes is referred to as acceleration. There are only two ways to accelerate: changing your speed or changing your direction, or changing both. This is because the velocity is both a speed and a direction.

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Answer:

dV/dt = 40π

Step-by-step explanation:

We are told that The radius r(t) of the base of a cone is increasing at a rate of 10 meters per second. Thus;

dr/dt = 10 m

Height: h = 6 m

Volume of cone is given by the formula;

V = ⅓πr²h

dV/dr = ⅔πrh

We want to find the rate at which the volume is changing at radius of 1m.

Thus;

dV/dt = (dV/dr) × (dr/dt)

dV/dt = ⅔π(1 × 6) × (10)

dV/dt = 40π

Since the sphere is completely curved, the area of the curved surface is equal to the total area of the sphere. Additionally known as lateral surface area. Surface Area of a Sphere equals 4r2, where r is the sphere's radius.

A right circular cone is a cone whose axis is the line from its vertex to its circular base's midway. As a result, the radius of the base is "r" and the slant height is "l," giving the formula for the curved surface area of a right circular cone as rl.

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As per the given scenario, Ram will cross the river first.

Ram chooses the quickest route and crosses the river without turning. Ram and Hari can both swim in still water at the same speed, hence their respective speeds when crossing the river will be equivalent. Ram will be able to get to the opposing bank the fastest as a result.

Hari, on the other hand, is swimming upstream at an angle and is being dragged downstream by the water.

Hari's overall travel distance will increase due to the downstream current, however his effective speed will drop in comparison to the other bank. Hari will therefore take longer than Ram to get to the opposing bank.

Thus, Ram will cross the river first in this scenario.

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To find the activation energy for the reverse reaction, you can use the Arrhenius equation: Ea = -ln(k / (A * T)) * (R * T)

To find the activation energy for the reverse reaction, you can use the Arrhenius equation. The Arrhenius equation relates the rate constant of a reaction to the temperature and activation energy. The equation is as follows:

k = A * e^(-Ea/RT)

Where:

To find the activation energy for the reverse reaction, you need to know the rate constant and temperature values corresponding to the reverse reaction. Once you have these values, you can rearrange the equation to solve for the activation energy:

Ea = -ln(k / (A * T)) * (R * T)

By plugging in the values of the rate constant, pre-exponential factor, and temperature, you can calculate the activation energy for the reverse reaction.

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The activation energy for the reverse reaction can be found using the Arrhenius equation and experimental data.

To determine the activation energy for the reverse reaction, one can use the Arrhenius equation: k = A * e^(-Ea/RT), where k is the rate constant, A is the pre-exponential factor, Ea is the activation energy, R is the gas constant, and T is the temperature in Kelvin. By conducting experiments at different temperatures and measuring the rate constants, one can obtain a set of data points. By taking the natural logarithm of both sides of the Arrhenius equation and rearranging, a plot of ln(k) versus 1/T can be created. The slope of this plot will be equal to -Ea/R, allowing for the determination of the activation energy.

The activation energy for the reverse reaction can be determined by utilizing the Arrhenius equation and conducting experiments at different temperatures. By analyzing the resulting data and plotting ln(k) versus 1/T, the activation energy can be calculated from the slope of the plot. This method provides insights into the energy barrier required for the reverse reaction to occur and aids in understanding the reaction kinetics and thermodynamics involved.

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Answer:

A

Explanation:

it should be 70 times ten^-5

Answer:

A. 70 x 10^6m

Explanation:

The natural light display called aurora borealis is located in the northern

hemisphere.

There are two types of aurora which are called aurora borealis and aurora

australis. The aurora borealis is located in the Northern hemisphere while

the aurora australis is located in the Southern hemisphere.

They receive their energy through the interaction of charged particles

on the Sun and Earth to produce the light display. An example

of the interaction involves solar wind with atoms of the upper atmosphere.

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Answer:

northern and southern hemisphere

Explanation:

the magnitude of the average force of air resistance exerted on the object is approximately 1.05 N.

The magnitude of the average force of air resistance exerted on an object depends on various factors such as the shape, size, speed, and density of the object, as well as the density and viscosity of the air.

F = (1/2) * rho * Cd * A * v

we can estimate the density of air at sea level as 1.225 kg/m, and assume a drag coefficient of 0.5 for a spherical object.

F = (1/2) * rho * Cd * A * v

= (1/2) * 1.225 kg/m * 0.5 * pi * (0.1 m)* (8.50 m/s)

= 1.05 N (to two significant figures)

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Answer:

The value is \(v_t = 172 \ km/h\)

Explanation:

From the question we are told that

    The average speed for the first 12 hours is \(u = 185 km/h\)

    The average speed for the next 13 hours is  \(v = 160 \ km/h\)

Generally the total time taken is mathematically represented as

     \(t_t = 12 + 13\)

=> \(t_t = 25 \ h\)

The distance covered in the first movement is

          \(D = u * 12\)

         \(D = 185 * 12\)

        \(D = 2220 \ km\)

The distance covered in the first movement is

          \(d= v * 13\)

         \(d = 160 * 13\)

        \(d = 2080 \ km\)

The total distance traveled is  

       \(D_t = D + d\)

       \(D_t = 2220 +2080\)

      \(D_t = 4300 \ km\)

The average  of the whole journey is

      \(v_t = \frac{D_t}{t_t}\)

     \(v_t = \frac{4300}{25}\)

     \(v_t = \frac{4300}{25}\)

    \(v_t = 172 \ km/h\)

Answer:

980N

100kg

Explanation:

Weight is Mass * Gravity.

For question a, the object with a mass of 100 kg will have a weight of

100 * 9.8 = 980N

For question b, the mass of the object will stay the same, even if it is on the moon. Therefore it is 100kg.

(a). The weight of the object on the Earth is 980 N.

(b). The mass of the object on the moon is 100 kg.

The weight of the object on the earth has been considered to be affected by the Gravitational force as it has been acting on the object.

(a) The weight of the object on Earth can be given by:

Weight = mass \(\times\) Gravitational Force

Given, the mass of the object = 100 kg.

The gravitational force = 9.8N

Weight of the object = 100 \(\times\) 9.8 N

Weight of the object = 980 N

(b) The mass of the object has been independent of the gravitational force that has been acting on the object.

Thus, the mass of the object on earth = the mass of object on the moon.

The mass of the object on the moon = 100 kg.

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Answer:

-5Gm^2/r

Explanation:

You don't have the graph, but I know what question you are talking about. The answer is above.

The new gravitational potential energy of the three-sphere system will  be\(- \frac{5Gm^2}{r}\).

The energy that an item has due to its location in a gravitational field is known as gravitational potential energy.

For the sphere 1 we have to perform no work. Hence, the work done is zero.

\(\rm W_1 = 0\)

The mass m is to be brought to be infinity. Because there is potential at B due to mass m at A point .

\(\rm W_2 = \frac{-Gm}{r} \times m \\\\ W_2 =-\frac{Gm^2}{r}\)

The B2 m at C is brought to infinity. For we have to do work . The  gravitational potential energy for the mass 2 m is;

\(\rm W_3 = \frac{-Gm}{r} \times 2m\\\\ W_3 = \frac{-4Gm^2}{y} \\\\\)

The new gravitational potential energy of the three-sphere system will be;

\(\rm W =W_1+W_2+W_3 \\\\\rm W =-0-\frac{Gm}{r}-4\frac{-Gm^2}{r^2} \\\\ W=\-\frac{-5Gm^2}{r^2}\)

Hence,  the new gravitational potential energy of the three-sphere system will  be\(- \frac{5Gm^2}{r}\).

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