How can a unit of length such as millimeter of mercury (mmHg) be used as a unit of pressure, which has the dimensions of force per unit area?

The amount of copper obtained by the reaction depends on the amount of copper chloride reacted and the limiting reagent in the reaction.

Without information on the amounts of reactants used, it is not possible to calculate the amount of copper obtained by the reaction or compare it to the expected amount. However, if the reaction was carried out under controlled conditions and all reactants were used in the stoichiometric ratio, the amount of copper obtained should be the expected amount calculated based on the balanced chemical equation.

In order to calculate the expected amount of copper obtained, the amount of copper chloride reacted should be known, and the limiting reagent should be identified. The amount of copper obtained will be determined by the limiting reagent.

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The complete question is:

Calculate the amount of copper obtained by the reaction. Was it the amount you expected? Explain. ​

3CuCl2(aq) +2 Al (s) ----> 2AlCl3(aq) + 3Cu(s)

(A) R_r represents the rate of change of resistance with respect to the radius of the artery, r. The units of R_r are mmHg/mm. A negative value for R_r indicates that an increase in the radius of the artery will result in a decrease in resistance, meaning it becomes easier for blood to flow through the wider artery.

(b) The derivative is zero because the resistance with respect to the radius does not depend on the length of the artery.

(a) To calculate R_L (L, r), we differentiate the equation with respect to L while keeping r constant:

\(R_L(L, r) = d/dL (kL/r^4) = k/r^4\)

R_L represents the rate of change of resistance with respect to the length of the artery, L. The units of R_L are mmHg/cm. A positive value for R_L indicates that an increase in the length of the artery will result in an increase in resistance, meaning it becomes harder for blood to flow through the longer artery.

To calculate R_r (L, r), we differentiate the equation with respect to r while keeping L constant:

\(R_r(L, r) = d/dr (kL/r^4) = -4kL/r^5\)

R_r represents the rate of change of resistance with respect to the radius of the artery, r. The units of R_r are mmHg/mm. A negative value for R_r indicates that an increase in the radius of the artery will result in a decrease in resistance, meaning it becomes easier for blood to flow through the wider artery.

(b) To calculate R_rr (L, r), we differentiate R_r (L, r) with respect to r while keeping L constant:

\(R_rr(L, r) = d/dr (-4kL/r^5) = 20kL/r^6\)

R_rr represents the rate of change of R_r with respect to r. The units of R_rr are mmHg/mm^2. A positive value for R_rr indicates that as the radius of the artery increases, the rate of decrease in resistance increases. In other words, the wider the artery becomes, the easier it is for blood to flow through.

To calculate R_rL (L, r), we differentiate R_r (L, r) with respect to L while keeping r constant:

\(R_rL(L, r) = d/dL (-4kL/r^5) = 0\)

R_rL represents the rate of change of R_r with respect to L. The units of R_rL are mmHg/(cm·mm). The derivative is zero because the resistance with respect to the radius does not depend on the length of the artery. This implies that changes in the length of the artery do not affect the rate of change of resistance with respect to the radius.

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The root-mean-square speed of the molecules will be the highest in SF6 at 200°C. According to the kinetic-molecular theory, the root-mean-square speed of gas molecules is directly proportional to the square root of their absolute temperature and inversely proportional to the square root of their molar mass.

The formula for calculating the root-mean-square speed is:

vrms = √(3RT/M)

where:

vrms = root-mean-square speed

R = ideal gas constant

T = absolute temperature

M = molar mass of the gas

At a given temperature, gases with lower molar masses will have higher root-mean-square speeds. In this case, we are comparing gases at 200°C. Among the given options (O2, H2O, and SF6), SF6 has the highest molar mass. Therefore, according to the kinetic-molecular theory, the root-mean-square speed of SF6 molecules will be the highest at 200°C.

The root-mean-square speed of molecules is not the same for all gases at a given temperature. It depends on the molar mass of the gas. In this case, SF6 has the highest molar mass among the given options, so its molecules will have the highest root-mean-square speed at 200°C.

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So, the mass gained by the copper electrode is also 3.12 grams.

According to the law of conservation of mass, the mass lost by the zinc electrode during the operation of the cell must be equal to the mass gained by the copper electrode. Therefore, if the zinc electrode loses 3.12 grams of mass, the copper electrode must gain exactly the same amount of mass. The copper ions in the solution receive electrons at this electrode to produce copper metal, which then deposits on the electrode.

As a result, the copper electrode's mass grows as the reaction progresses.  The cathode is where reduction happens. The cathode is the electrode whose mass rose as a result. On the anode, oxidation takes place. The anode is the electrode whose mass has dropped as a result. As the Cu electrode gains mass, the Pb electrode's mass falls. The oxidation-reduction process takes place between active electrodes. Metal atoms in the electrode would lose mass if they oxidised and entered solution because metals produce cations.

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The potential ATP yield from complete oxidation of Stearic acid (18:0) is 129 ATP.

Stearic acid is an 18-carbon fatty acid and undergoes beta-oxidation to produce acetyl-CoA molecules. The complete oxidation of stearic acid yields 9 acetyl-CoA, 8 FADH₂, and 8 NADH molecules. These molecules then enter the electron transport chain to produce ATP.

The ATP yield from the complete oxidation of stearic acid can be calculated by first determining the number of ATP molecules generated from the oxidation of each molecule of NADH and FADH₂. The P/O ratio for NADH is 2.5 ATP and for FADH₂ is 1.5 ATP. The total ATP yield can then be calculated by multiplying the number of NADH and FADH₂ molecules by their respective P/O ratios and summing the results.

For stearic acid, the total number of NADH molecules produced is 8 x 1 = 8, and the total number of FADH₂ molecules produced is 8 x 2 = 16. Therefore, the total ATP yield is:(8 x 2.5) + (16 x 1.5) + (9 x 10) = 129 ATP.

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The conclusion about the rates of the rotting reaction from the table would be that the reaction occurs more quickly when the concentration of salt is higher—option B.

The rate of reaction, or reaction rate, is the time it takes for a reaction to occur. In other words, it is the time it takes for the reactants of a reaction to become products.

In this case, the reactant is the rope and the product is the rotten product of the rope. From the table, it took 10 years for the rope to decay in a lake. On the other hand, it took the same rope just 4 years to decay in an ocean.

The difference between the two water bodies is the presence of salt. The lake has almost zero salt while the conentration of salt in the ocean water is high.

Thus, the conclusion about the rate of rotting reaction would be that the reaction is hastened by the presence of salt in the ocean water.

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To solve this problem, we can use the ideal gas law, which relates pressure, volume, and temperature of a gas. The ideal gas law is given by:

PV = nRT

where P is the pressure of the gas, V is the volume of the gas, n is the number of moles of the gas, R is the ideal gas constant, and T is the temperature of the gas in Kelvin.

We can assume that the mass of the helium in the balloon remains constant, so the number of moles of helium also remains constant. Therefore, we can write:

P1V1/T1 = P2V2/T2

where P1, V1, and T1 are the initial pressure, volume, and temperature of the helium in the balloon, and P2, V2, and T2 are the final pressure, volume, and temperature of the helium at the higher altitude.

We are given:

P1 = 760 mmHg

V1 = 5.00 L

T1 = 20°C = 293 K

P2 = 76.0 mmHg

T2 = 50°C = 323 K

We can plug in these values and solve for V2:

P1V1/T1 = P2V2/T2

(760 mmHg)(5.00 L)/(293 K) = (76.0 mmHg)V2/(323 K)

V2 = (760 mmHg)(5.00 L)/(76.0 mmHg)(293 K/323 K)

V2 = 80.8 L

Therefore, the new volume of the balloon at the higher altitude is 80.8 L.

Answer:

molten

Explanation:

Lava is molten rock that breaks through the earth's surface

Lava is molten rock.

Lava is a molten rock flowing from volcano. It belongs to the category of igneous rocks.

Igneous rocks are one of the three main types of rocks, and are formed when molten material, either magma or lava, solidifies. These rocks are made up of a variety of minerals, and the cooling process determines their physical properties.

Depending on how quickly the molten material cools, the texture of the igneous rock can range from fine-grained to coarse-grained. Igneous rocks can be further classified based on the silica content, with the most common classifications being felsic, intermediate, mafic, and ultramafic.

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Bicarbonate (HCO3-) would be part of the explanation for taking bicarbonate (NaHCO3) for excess stomach acid.

When mixed with water, sodium bicarbonate dissociates into Na+ and HCO3-. Bicarbonate acts as a base that reacts with the acid in the stomach to neutralize it, causing carbon dioxide gas and water to be produced as by-products. This makes sodium bicarbonate an effective antacid for treating heartburn and other forms of acid reflux.The neutralization reaction can be written as follows:NaHCO3 + HCl → NaCl + CO2 + H2O

Where NaHCO3 is sodium bicarbonate, HCl is hydrochloric acid, NaCl is sodium chloride, CO2 is carbon dioxide, and H2O is water. Bicarbonate neutralizes the acid in the stomach, reducing symptoms of heartburn and other types of acid reflux.

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Answer:

Chloroform has a boiling point of 61.15 degrees Celsius and a vapor pressure of 9.5 kPa at 20 degrees Celsius. Glycerol, on the other hand, has a boiling point of 290 degrees Celsius and a vapor pressure of 0.0002 kPa at 20 degrees Celsius. Therefore, chloroform has a much lower boiling point and a much higher vapor pressure than glycerol. This means that chloroform is more volatile and evaporates more easily than glycerol.

Explanation:

Chloroform has a boiling point of 61.15 degrees Celsius and a vapor pressure of 9.5 kPa at 20 degrees Celsius. Glycerol, on the other hand, has a boiling point of 290 degrees Celsius and a vapor pressure of 0.0002 kPa at 20 degrees Celsius. Therefore, chloroform has a much lower boiling point and a much higher vapor pressure than glycerol. This means that chloroform is more volatile and evaporates more easily than glycerol.

Answer:

A) a new type of refrigerant that is less damaging to the environment is developed.  Applied development

B) a new element is synthesized in a particle accelerator.  Basic development.

C) a computer is redesigned to increase the speed of the computer. Technological development.

Explanation:

Answer:

Hey mate.....

This is your answer....

Explanation:

1. Evaporation

2. Liquid to solid

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Answer:

165.3 cm^3

Explanation: hope this is correct!!

P1 * V1 / T1 = P2 * V2 / T2

P1 = 84.6 kPa

V1 = 215 cm³

T1 = 23.5°C = 23.5 + 273 K = 296.5 K

At STP:

P2 = 101.3 kPa

V2 = ?

T2 = 273 K

The calculated molar mass of 32 g/mol is the same as the molar mass of oxygen. Thus, the gas is O2.

Let us determine the molar mass of this gas. We can begin with the density of the gas as follows:

Density = mass/volume
Density = 0.96 g/0.672 L

Density = 1.43 g/L

We know that at STP (standard temperature and pressure), temperature is 0°C and pressure is 1 atm. We can use these values to determine the molar volume of a gas, which is 22.4 L.

Molar volume = 22.4 L at STP
Thus,
1 mole of gas occupies 22.4 L at STP

We can determine the number of moles of the gas as follows:

Number of moles = volume/molar volume
Number of moles = 0.672 L/22.4 L/mol
Number of moles = 0.03 mol

The molar mass can be determined using the following formula:
molar mass = mass/number of moles
molar mass = 0.96 g/0.03 mol
molar mass = 32 g/mol

The calculated molar mass of the gas is 32 g/mol. Now let us compare this molar mass with the molar mass of the given gases.
Oxygen (O2) has a molar mass of 32 g/mol

The calculated molar mass of 32 g/mol is the same as the molar mass of oxygen. Therefore, the identity of the gas is O2.

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Answer:

February 12th.

Explanation:

Trust me.

The compound that will readily react with a solution of bromine consisting of 48% hydrobromic acid and 30% hydrogen peroxide is acetic acid.Hydrobromic acid is a solution of hydrogen bromide (HBr) in water.

It is a strong acid that can be used for several industrial purposes. Hydrogen peroxide is a reactive chemical with the chemical formula H2O2. When combined with hydrobromic acid, hydrogen peroxide forms a solution known as hydrobromic acid. Bromine is a non-metallic element that reacts with many compounds to form new substances.Acetic acid (CH3COOH) is a weak organic acid that is commonly found in vinegar and is used in the production of cellulose acetate.

When acetic acid is mixed with a solution of bromine containing 48% hydrobromic acid and 30% hydrogen peroxide, it reacts readily. This reaction will produce a new compound.The other three options (cyclohexane, dichloromethane, t-butyl alcohol, and cyclohexene) do not have any active functional groups such as an alcohol, carboxylic acid, or an unsaturated bond that can undergo halogenation or oxidation reactions. Therefore, they will not react with a solution of bromine consisting of 48% hydrobromic acid and 30% hydrogen peroxide.

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The rate of reaction increases, we need to consider the given reaction and orders of reactants A and B the rate of reaction increases by a factor of 50.

A + 2B -> Products
The reaction is first-order with respect to A and second-order with respect to B. Therefore, the rate law for the reaction can be written as:

Rate = k[A]^1[B]^2
Now, let's consider the changes in the concentrations of A and B:- Concentration of A doubles, so the new concentration of A is 2[A]. - Concentration of B increases 5 times, so the new concentration of B is 5[B].

Now we can find the new rate of reaction:
New Rate = k(2[A])^1(5[B])^2
To determine the factor by which the rate of reaction increases, we need to divide the new rate by the original rate:
Factor = (k(2[A])^1(5[B])^2) / (k[A]^1[B]^2)
By simplifying this expression, we get:
Factor = (2^1)(5^2)
Factor = 2 * 25 = 50
So, the rate of reaction increases by a factor of 50.

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Answer:

Molecule

Explanation:

Two or more atoms linked/bonded together is called a molecule.

The loss of two electrons causes the atom to have a net positive charge of two.

In order to reach the n=2 energy level and an octet of electrons in the outermost shell, oxygen, which has an electron configuration of (2, 6), must gain two electrons.

When an atom has an equal amount of protons and electrons, it also has an equal number of electric charges, both positive and negative (the electrons) (the protons). The atom is referred to as neutral since its overall electric charge is zero.

When electrons are added to or taken away from an object, an electrical charge is produced. An object acquires a negative charge when electrons are introduced to it because electrons have a negative charge. An object acquires a positive charge when its electrons are removed.

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A 25.0 mL sample of an HCl solution is titrated with a NaOH solution. The equivalence point is reached with of base. The concentration of HCl is 0.100M.

To find the concentration of HCl, we need to use the equation: M1V1 = M2V2, where M1 is the concentration of HCl, V1 is the volume of HCl used, M2 is the concentration of NaOH, and V2 is the volume of NaOH used at the equivalence point.
We know that the volume of NaOH used at the equivalence point is 25.0 mL, which is also the volume of HCl used. We also know that the concentration of NaOH is typically given in the problem.
Let's assume the concentration of NaOH is 0.100 M. Therefore, using the equation above:
M1V1 = M2V2
M1(25.0 mL) = (0.100 M)(25.0 mL)
M1 = (0.100 M)(25.0 mL) / (25.0 mL)
M1 = 0.100 M
So, the concentration of HCl is 0.100 M.

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The variables in the ideal gas constant has V as the unit of liters and T has the unit of Kelvin. Thus, option C is correct.

The gas constant in an ideal gas equation has been the value of the energy absorbed by 1 mole of an ideal gas at standard temperature and pressure.

The value of R has been dependent on the units of volume, temperature and pressure of the ideal gas.

The given value of R has been 0.0821 L.atm/mol.K

The unit in gas constant has been L (Liter) for volume (V).

The unit of pressure (P) has been atm.

The unit of temperature (T) has been Kelvin  (K).

Thus the gas law constant used by student has V has the unit of liters and T has the unit of Kelvin. Thus, option C is correct.

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Option D, NaCl(aq) + AgNO3(aq) → NaNO3(aq) + AgCl(s), is the balanced chemical equation that represents a single-replacement reaction.

What is Replacement Reaction?

In chemistry, a replacement reaction is a type of chemical reaction where one element replaces another in a compound. The general formula for a replacement reaction is:

A + BX → AX + B

where A and B are elements, and X is an anion that can combine with A and B. In this reaction, A replaces B in the compound BX, forming a new compound AX and releasing the element B as a free element. Replacement reactions can be of two types: single replacement reactions and double replacement reactions, depending on whether one or two elements are replaced in the reaction.

In this reaction, sodium (Na) replaces silver (Ag) in the compound AgNO3 to form NaNO3, and silver is released as a free element in the form of AgCl.

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The correct order of the four compounds in increasing Rf values on the TLC plate is: A. chlorobenzene, 1-chloro-4-nitrobenzene, 1-chloro-2,4-dinitrobenzene, 1-chloro-2,6-dinitrobenzene

In thin-layer chromatography (TLC), the Rf value (retention factor) is used to compare the migration of compounds on the plate. The Rf value is influenced by the polarity of the compound and the polarity of the solvent mixture. More polar compounds will have lower Rf values, while less polar compounds will have higher Rf values.

The solvent mixture used in this question is 8:1 hexanes/ethyl acetate, which is relatively non-polar.

1. Chlorobenzene is the least polar compound, as it only has a chlorine atom attached to the benzene ring.
2. 1-chloro-4-nitrobenzene has one nitro group, which increases its polarity compared to chlorobenzene.
3. 1-chloro-2,4-dinitrobenzene has two nitro groups, making it more polar than 1-chloro-4-nitrobenzene.
4. 1-chloro-2,6-dinitrobenzene also has two nitro groups, but the presence of the two nitro groups at the 2,6 positions makes it more polar than 1-chloro-2,4-dinitrobenzene.

As the Rf values increase with decreasing polarity, the correct order is A. chlorobenzene, 1-chloro-4-nitrobenzene, 1-chloro-2,4-dinitrobenzene, 1-chloro-2,6-dinitrobenzene.

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630g

Explanation:

firstly the equation has to be balanced. 2H2+o2>2H2o.

finding the mole of hydrogen?

mole = 70/2 which is equal to 35 mole of hydrogen.

35 mole of hydrogen is equal to the mole of water.

finding the mass of water=?

35=mass/18

mass= 35*18=630g of water

Answer: Hello  mister i dont now your question

Explanation:

Earth climate has stayed same thougout the past

Approximately 65.5 mL of 5.5 M NaOH is needed to prepare 300 mL of 1.2 M NaOH.

The dilution formula is used to calculate the concentration or volume of a solution after it has been diluted.

We can use the dilution formula to determine the volume of the 5.5 M NaOH needed to prepare 300 mL of 1.2 M NaOH:

C1V1 = C2V2

Where

Substituting the given values, we get:

(5.5 M) V1 = (1.2 M) (300 mL)

V1 = (1.2 M) (300 mL) / (5.5 M)

V1 ≈ 65.5 mL

Therefore, approximately 65.5 mL of 5.5 M NaOH is needed to prepare 300 mL of 1.2 M NaOH.

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ANSWER

option A and B

EXPLANATION

An increase in temperature will increase the average kinetic energy of the molecule, thereby increasing the frequency of collision.

The correct answer are option A and B