How can doing work on an object increase its kinetic energy?


What about its potential energy?

Answer:

f = 1.5 Hz

Explanation:

Given that,

18 waves pass by a person in 12 seconds.

We need to find the frequency of these water waves.

We know that,

Frequency = no. of waves per second

So,

\(f=\dfrac{18}{12}\\\\f=1.5\ Hz\)

So, the frequency of these water waves is equal to 1.5 Hz.

I am not entirely sure but I think it is:

The amount of heat absorbed by the engine from its heat-source reservoir is 107.692 kW.

In order to solve the given problem, let's start by calculating the Carnot coefficient of performance of the Carnot refrigerator.

The Carnot coefficient of performance of the Carnot refrigerator is given by the following relation:

\($$\omega_{Carnot} = \frac{T_0}{T_1 - T_0}$$\)

Where\(,$\omega_{Carnot}$\) = Coefficient of performance of the Carnot refrigerator

$$\omega_{Carnot} = \frac{T_0}{T_1 - T_0}$$\(

$$\omega_{Carnot} = \frac{T_0}{T_1 - T_0}$$\) = Temperature of the low temperature reservoir = 0 °C = 273 K

\($T_1$\) = Temperature of the high temperature reservoir

Let's substitute the given values in the above equation.

\($$0.6 \omega_{Carnot} = 0.6 \times \frac{273}{T_1 - 273}$$\)

\($$\implies T_1 - 273 = \frac{273}{0.6 \omega_{Carnot}}}$$\)

\($$\implies T_1 = 273 + \frac{273}{0.6 \omega_{Carnot}}}$$\)

\($$\implies T_1 = 455 K$$\)

Therefore, the temperature of the high temperature reservoir of the Carnot refrigerator is 455 K

.Now, let's calculate the thermal efficiency of the Carnot engine.

The thermal efficiency of the Carnot engine is given by the following relation:

\($$\eta_{Carnot} = 1 - \frac{T_0}{T_1}$$\)

Where,\($\eta_{Carnot}$\) = Thermal efficiency of the Carnot engine

\($T_0$\)= Temperature of the low temperature reservoir = 0 °C = 273 K

\($T_1$\) = Temperature of the high temperature reservoir

Let's substitute the given values in the above equation.

\($$0.6 \eta_{Carnot} = 0.6 \times \left(1 - \frac{273}{T_1}\right)$$\)

\($$\implies 0.6 \eta_{Carnot} = 0.6 - \frac{273}{T_1}$$\)

\($$\implies 0.6 \eta_{Carnot} = \frac{0.6T_1 - 273}{T_1}$$\)

\($$\implies 0.6 \eta_{Carnot} = \frac{0.6 \times 455 - 273}{455}$$\)

\($$\implies \eta_{Carnot} = 0.325$$\)

Therefore, the thermal efficiency of the Carnot engine is 0.325.

Now, let's calculate the amount of heat absorbed by the engine from its heat-source reservoir.

The rate at which the heat is extracted from the low temperature reservoir by the Carnot refrigerator is given as follows:

\($$Q_{extracted} = \omega_{Carnot} \times W = 0.6 \omega_{Carnot} \times 35 \ \text{kW} = 21 \ \text{kW}$$\)

Here, the work produced by the Carnot engine is used by the Carnot refrigerator in extraction of heat from a heat reservoir at 0 °C.

Now, the rate at which the engine delivers work to the surroundings is the rate at which the engine absorbs heat from its heat-source reservoir. This is given by the following relation:

\($$W = \eta_{Carnot} \times Q_{absorbed}$$\)

\($$\implies Q_{absorbed} = \frac{W}{\eta_{Carnot}}$$\)

\($$\implies Q_{absorbed} = \frac{W}{\eta_{Carnot}}$$\)

\($$\implies Q_{absorbed} = 107.692 \ \text{kW}$$\)

Therefore, the amount of heat absorbed by the engine from its heat-source reservoir is 107.692 kW.

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The acceleration of the elevator at this time was 2m/s² and the elevator was accelerating the upward direction.

The mass of the child standing on a spring scale in an elevator is 30 kg the elevator is showing a reading of 360 Newtons.

The reading note by the elevator is given by radiation,

W = M(g+a)

Where w is the reading of the spring scale,

M is the mass of the child,

g is the gravitational acceleration which is given to be 10m/s² and a is the acceleration of the elevator.

Putting values,

360 = 30(10+a)

12 = 10+a

a = 2m/s²

As you can see from the above result that the acceleration of the lift is 2m/s² and because it is positive it means that the elevator is accelerating in the upward direction.

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Answer:

True

Explanation:

idk

The nuclei of atoms might break apart in radioactivity due to the weak forces that bind protons and neutrons together in the nucleus. The nucleus of an atom contains positively charged protons and neutral neutrons, which are held together by strong nuclear forces.

In some cases, the number of neutrons in the nucleus is not sufficient to keep the protons bound together, leading to instability. The instability can cause the nucleus to undergo radioactive decay, which can involve the emission of particles or energy from the nucleus. For example, in alpha decay, a nucleus emits an alpha particle, which is composed of two protons and two neutrons. This results in the formation of a new nucleus with a lower atomic number. Similarly, in beta decay, a neutron in the nucleus is converted into a proton and an electron, which is then emitted from the nucleus. In gamma decay, a nucleus releases energy in the form of gamma rays.

In summary, the reason for the nuclei of atoms breaking apart in radioactivity is due to the instability of certain isotopes of elements, which have too many or too few neutrons for the number of protons they have. This instability can cause the nucleus to break apart, leading to radioactive decay.

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The total angular size of the retrograde loop of Mars along its longitudinal axis is approximately 180 degrees.

This means that the planet appears to move from east to west along its orbit instead of from west to east. The retrograde loop is visible when Mars reaches opposition, when it is directly opposite the Sun in the sky. During this time, it will appear to move backwards relative to the stars in the night sky.

Angular size refers to the apparent size of an object as seen from an observer on Earth. It is measured in terms of the angle subtended by the object at the observer's point of view. For example, the Moon has an angular size of approximately 0.5 degrees , while the Sun has an angular size of approximately 0.5 degrees.

Angular size is important in astronomy, as it can be used to calculate the distance to objects in the night sky.

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Answer:

692 g

Explanation:

La fórmula para encontrar la solución de una mezcla química es agregar el soluto y el solvente juntos. Esto significa

Solución = solvente + soluto

Solución = 670 g + 22 g

Solución = 692 g

es así de simple, y espero que lo entiendas

Answer:

your girl is very very very very very very very pretty

Answer:

very very pretty

Explanation:

B The Mustang, because it has the largest ratio of force to mass car is capable of the largest acceleration

On a dynamometer, engine torque is measured at constant speed. Powertrain The quantity necessary to accelerate the inertia of the spinning components reduces the actual torque provided to the drivetrain.

Standard automobile and truck engines generally provide 100 to 400 lb-ft of torque. The crankshaft of an engine is continually rotated (or twisted) by the pistons inside the engine as they reciprocate up and down on it.

Therefore, your automobile will accelerate faster the more torque it has. The ability of an engine to manage a load and produce a specific amount of power to rotate the engine on its axis is represented by torque, which is an essential component of producing power from a car's engine.

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What is the numeric value of the prefix "micro"?

a. 0.00001

c. 0.0001

d. 0.001

Answer:

See Explanation

Explanation:

Given

Cyclist 1:

\(Distance = 40km\)

\(Time = 2hr\)

\(Direction = East\)

Cyclist 2:

\(Distance = 10km\)

\(Time = 0.5hr\)

\(Direction = West\)

The question requires options. Since none is given,  I'll answer on a general term.

First, calculate the speed of both cyclists

\(Speed = \frac{Distance}{Time}\)

Cyclist 1:

\(Distance = 40km\)

\(Time = 2hr\)

\(Speed = \frac{40km}{2hr}\)

\(Speed = 20km/hr\)

Cyclist 2:

\(Distance = 10km\)

\(Time = 0.5hr\)

\(Speed = \frac{10km}{0.5hr}\)

\(Speed = 20km/hr\)

The following can be deduced from above:

A plan with a box and a whip. The range of the number line is 10 to 65. The box runs from 40 to 50, while the whiskers vary from 20 to 60. At 45 degrees, a line splits the box.

The box runs from 40 to 50, while the whiskers vary from 20 to 60. At 45 degrees, a line splits the box. How many data points are there between the two whiskers? 25% of the data is contained up to Q1. 25% of the data comes from Q3 to the maximum. Therefore, 50% of the data is spread across both whiskers. How Do I Use the Calculator for the Box and Whisker Plot? The box and whisker plot calculator should be used as follows: Step 2: To obtain the quartile value, press the "Calculate" button now.

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Answer: (15 & 45), (40 & 50), (45 & 60)

Correct Answer 100%! Pls, give me brainliest. Thank You!

Answer: There are seven main stores of energy: magnetic

internal (thermal)

chemical

kinetic

electrostatic

elastic potential

gravitational potential

Explanation: So you can have any of these

Answer:

that would be newtons.

Explanation:

I hope this helps

the oil drum traveled a distance of approximately 1.56 meters.

To find the distance that the oil drum traveled, we need to use the equation for average acceleration:

d = (vf^2 - vi^2) / 2a

where d is the distance traveled, vf is the final velocity, vi is the initial velocity, and a is the acceleration.

In this case, we are given that the final velocity is 3.0 m/s, the initial velocity is 0 m/s, and the acceleration is 520 N / 180 kg = 2.89 m/s^2. Substituting these values into the equation, we get:

d = (3.0^2 - 0^2) / 2 * 2.89

= 9 / 5.78

= 1.56 m

Therefore, the oil drum traveled a distance of approximately 1.56 meters.

Answer:

As the vibrations of the particles reach your ear, your ear drum receives the vibrations which the brain then interprets as sound. In the vacuum of space, there are no (or very, very few) particles to vibrate, so sound cannot travel through this medium.

Explanation:

Answer:

If you are traveling with a relativity constant velocity, then you will interpret your reference frame as being at rest. Since you are moving faster than the other train, the other train is moving backwards relative to you. Seeing the other train go past your window from front to rear makes it look like the train is going backwards

Explanation:

Given data:

* The mass of the student is m = 65 kg.

* The distance covered by the student is d = 100 m.

* The time taken by the student to cover the distance is t = 12 seconds.

Solution:

(a). The velocity of the student is,

Thus, the velocity of the student is 8.33 meters per second.

(b). The kinetic energy of the student is,

Thus, the kinetic energy of the student is 2255.14 J.

(c). The mechanical energy of the student is the energy acquired by the student during its motion.

Thus, the mechanical energy of the student is 2255.14 J.

Given :

Two forces act on a 6.00-kg object. One of the forces is 10.0 N.

Acceleration of object 2 m/s².

To Find :

The greatest possible magnitude of the other force.\

Solution :

Let, other force is f.

So, net force, F = 10 + f.

Now, acceleration is given by :

\(a=\dfrac{F}{mass}\\\\a= \dfrac{10+f}{6}\\\\\dfrac{10+f}{6}=2\\\\f = 12 - 10\\\\f = 2 \ N\)

Therefore, the greatest possible magnitude of the other force is 2 N.

Hence, this is the required solution.

Answer:

15

Explanation:

speed = distance/time

distance = 60 meters

time = 4 seconds

speed = 60/4= 15 ms-¹

Speed:-

Answer:

a) \(W_{Mercury}=92.5 N\)

b) \(W_{Mars}=92.8 N\)

c) \(W_{Saturn}=261.0 N\)

d) \(W_{Pluto}=15.5 N\)

Explanation:

First of all, we need to remember the value of gravity acceleration on each planet.

\(g_{Mer}=3.70 m/s^{2}\)

\(g_{Mar}=3.71 m/s^{2}\)

\(g_{Sat}=10.44 m/s^{2}\)

\(g_{Plt}=0.62 m/s^{2}\)

The definition of weigh is the product between the mass and the gravity acceleration, therefore we will have:

a) \(W_{Mercury}=25*3.70=92.5 N\)

b) \(W_{Mars}=25*3.71=92.8 N\)

c) \(W_{Saturn}=25*10.44=261.0 N\)

d) \(W_{Pluto}=25*0.62=15.5 N\)

I hope it helps you!

Answer:

19.6 m/s

Explanation:

Looking at the kinematics equations, we can find one with the necessary variables; vf= v0+ at

vf is the final velocity which we are solving for, and the equation tells us the initial velocity (v0) is zero. Because the stone is dropped, it is in free fall, so we know the acceleration is acceleration due to gravity, or 9.8 m/s^2.

Plugging it all in, we can solve for vf:

vf= 0 + (9.8)(2)

vf= 19.6 m/s

Yes, the statement 'Work done by a frictional force on an object is force exerted by friction multiplied by the displacement of the object in the direction of the frictional force. SI unit of work done by the frictional force is joules' is the correct definition of Work Done By Friction.

Work done by a frictional force on an object is a measure of the energy exerted by friction.

This energy is equal to the magnitude of the frictional force multiplied by the displacement of the object in the direction of the frictional force.

The SI unit of work done by the frictional force is the joule, which is a unit of energy. In other words, the work done by friction is the amount of energy expended by the frictional force on the object.

This definition applies to any object which experiences a frictional force.

Although a part of your question is missing, you might be referring to this question:

Is 'Work done by a frictional force on an object is force exerted by friction multiplied by the displacement of the object in the direction of the frictional force. SI unit of work done by the frictional force is joules' the correct definition of Work Done By Friction.

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The wavelength of the standing wave created in the string is 31.2 cm.

The speed of the transverse wave on a string will be given by:

v = sqrt(T/μ)

where T is tension in the string and μ is linear mass density of the string (mass per unit length). We can find the linear mass density of the string by dividing the mass of the string by its length:

μ = m/ℓ

where m is mass of the string and ℓ is its length.

Substituting the given values, we get:

μ = 13.1 g / 1.97 m = 6.64 × 10⁻³ kg/m

The frequency of the fourth harmonic of the string is given by:

f = 4v/λ

where λ is wavelength of the standing wave.

We can find v by using the formula for speed and the given values of T and μ:

v = sqrt(T/μ) = sqrt(9.51 N / 6.64 × 10⁻³ kg/m)

= 70.3 m/s

Substituting the values of v and f into the formula for wavelength, we get:

λ = 4v/f = 4(70.3 m/s) / f

So we just need to find the frequency of the fourth harmonic. The frequency of the nth harmonic of a string is given by:

f_n = nv/2ℓ

where n is the harmonic number and ℓ is the length of the string. So for the fourth harmonic, we have:

f_4 = 4v/2ℓ = 2v/ℓ = 2(70.3 m/s) / 1.97 m

= 142 Hz

Substituting this value into the formula for wavelength, we get:

λ = 4(70.3 m/s) / (142 Hz)

= 31.2 cm

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Answer:

the  kinetic energy the bat can give to a ball is 2,025 J.

Explanation:

Given;

mass of the bat, m = 2kg

velocity of the bat, v = 45 m/s

The kinetic energy the bat can give to a ball is calculated as;

\(K.E = \frac{1}{2} mv^2\\\\K.E = \frac{1}{2} \times \ 2 \ \times \ 45^2\\\\K.E = 2,025 \ J\)

Therefore, the  kinetic energy the bat can give to a ball is 2,025 J.

The volume of a sphere is given by the equation V = (4/3)πr^3, where r is the radius. To calculate the volume of a sphere with a radius of 131 pm in cubic meters, we need to convert the radius from picometers to meters.

1 picometer (pm) = 1 x 10^-12 meters
So, the radius in meters would be:
131 pm = 131 x 10^-12 meters
Now we can substitute the radius into the volume equation:
V = (4/3)π(131 x 10^-12)^3
V = (4/3)π(2.1971 x 10^-30)
V ≈ 3.622 x 10^-30 cubic meters
Therefore, the volume of the sphere with a radius of 131 pm is approximately 3.622 x 10^-30 cubic meters.
Let me know if you need further assistance.

The formula for the volume of a sphere is V = (4/3)πr^3,

where V is the volume and r is the radius.

We then performed the necessary calculations to find the volume of the sphere, which turned out to be approximately 3.622 x 10^-30 cubic meters.

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Answer:

Voltage V = 117.65 volts

the voltage across the light bulb's filament is 117.65 V

Explanation:

The power of a light bulb can be expressed with respect to voltage and current flow.

Power = voltage × current

P = VI

Making Voltage V the subject of formula;

V = P/I

Given;

Power P = 4.0W

Current I = 0.034A

Substituting the given values;

V = 4/0.034

V = 117.65 volts

Answer:

A. Her funding was from a source that could profit from the results.

Explanation:

GOT IT RIGHT

The average force exerted on the ball by the golf club is 490 N.

Thus,  F = p/t = 0.49 * 10³ N = 490 N.

Momentum is a metric for power and how challenging it is to stop an object. Zero momentum applies to any object that is not moving. tremendous, slow-moving objects have tremendous amounts of momentum.

A small, swiftly moving object also possesses a significant momentum. A bowling ball, for instance, has more momentum than a ping-pong ball if their velocities are equal.

This is because bowling balls are larger in mass than ping-pong balls.

Thus, The average force exerted on the ball by the golf club is 490 N.

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