Use the `image_picker_web` package to capture a photo, convert it to a File object, and then upload it to Firebase Storage using the `firebase_storage` package.
How can I take a photo in Flutter web and save it to Firebase Storage?To take a photo in Flutter web and save it to Firebase Storage, you need to use different packages and APIs since the file_picker package doesn't work on the web platform. Here's an explanation of the steps you can follow:
1. Use the `image_picker_web` package: This package allows you to pick images from the device's camera or file system on the web. Add it to your dependencies in the pubspec.yaml file.
2. Implement photo capturing: Use the `ImagePickerWeb.getImage` method to capture a photo from the camera. This will return a base64-encoded image string.
3. Convert the base64 image to a File object: You can use the `base64Decode` function from the `dart:convert` package to decode the base64 string into bytes. Then create a File object using the bytes.
4. Upload the photo to Firebase Storage: Use the Firebase Storage API (firebase_storage package) to upload the File object to Firebase Storage. You will need to initialize Firebase and get a reference to the storage bucket.
5. Save the photo URL: Once the photo is uploaded, you can save the download URL provided by Firebase Storage to a user's profile or database for future retrieval.
Make sure you have properly set up Firebase in your Flutter web project and have the necessary security rules configured for Firebase Storage.
Additionally, consider error handling and security measures when implementing this functionality.
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hi i am a teacher and i want to say to stop using brainly we strictly banned brainly but our students keep using it
Answer:
Then miss try to get your school to banned it for your district like forbid then from the web site then it will not allow them to use it. then sometimes use it to help other people who needs help like teachers do or we need help with something we dont know so we ask for help for a better understanding of it.
Explanation:
^-^ hope you have a good day miss or sir
Answer:
So I would love to say that you and your team at your school had banned brainly and why are you using brainly here, then you shouldn't use brainly, and brainly all students around the world gets help even you is one.
The constrained-gap igniter plug used in some gas turbine engines operates at a cooler temperature because
The constrained-gap igniter plug used in some gas turbine engines operates at a cooler temperature because:
The construction is such that the spark occurs beyond the face of the combustion chamber liner. What is the Constrained gap igniter plug about?A lot of igniter plugs are known to be a kind of an annular-gap plug type.
Note that Constrained gaps are known to be a kind of a plug that is often used in some specific kinds of engines.
It function to give an effective spark of the annular-gap plug projects in a little way into the combustion chamber liner. The spark of the constrained-gap plug is one that do not rightly follow the face of the plug.
Therefore, The constrained-gap igniter plug used in some gas turbine engines operates at a cooler temperature because:
The construction is such that the spark occurs beyond the face of the combustion chamber liner.Hence, option B is correct.
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See full question below
The constrained-gap igniter plug used in some gas turbine engines operates at a cooler temperature because
impulse, reaction, and impulse-reaction. the construction is such that the spark occurs beyond the face of the combustion chamber liner. 3 and 5. cracks or other defects.The UHRS platform is optimized for Edge/Internet Explorer only. You can still use your favorite browser, but keep in mind that you may experience technical issues when working on UHRS with a different browser than Edge or Internet Explorer.
UHRS is optimized for...
It is to be noted that all UHRS platforms are optimized for the popular kinds of internet browser applications.
What is a UHRS?The Universal Human Relevance System (UHRS) is a crowdsourcing platform that allows for data labeling for a variety of AI application situations.
Vendor partners link people referred to as "judges" to offer data labeling at scale for us. All UHRS judges are bound by an NDA, ensuring that data is kept protected.
A browser is a software tool that allows you to see and interact with all of the knowledgeon the World Wide Web. Web sites, movies, and photos are all examples of this.
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Before making a left or right turn, you should signal for at least
__________ is not considered a driving distraction.
Answer:
Thank you and you're welcome
Explanation:
mark me brainliest
An engineer wants to obtain a random sample of the output of a process manufacturing digital cameras. She samples on three different days, and on each day she selects five cameras at random between 3 P.M. and 4 P.M from the production line output. Is this a random sample?
Yes, this is a random sample. By selecting cameras from the production line output at random times on three different days, the engineer is ensuring that the sample will be random.
What is engineer?
Engineering is a profession that involves the application of scientific principles for the purpose of designing, building, and maintaining structures, machines, and other products. It is also a field of study that involves the analysis and use of mathematics, physics, and other sciences to solve problems. Engineering requires knowledge of mathematics, science, and engineering fundamentals, as well as problem-solving and critical thinking skills. Engineers must also be able to communicate their ideas and results effectively, both in written and oral forms. Engineering involves the design and construction of structures, machines, and systems, as well as the development of new materials, processes, and products.
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Click this link to view O*NET’s Work Styles section for Human Resources Managers. Note that common work styles are listed toward the top and less common work styles are listed toward the bottom. According to O*NET, what are common work styles needed by Human Resources Managers? Select three options.
Answer:
there's no link to click. However, I can provide the common work styles needed by Human Resources Managers according to O*NET:
1. Integrity
2. Dependability
3. Leadership
4. Self-Control
5. Attention to Detail
6. Cooperation
7. Adaptability/Flexibility
8. Initiative
9. Stress Tolerance
10. Achievement/Effort
Note that the order of these work styles may vary depending on the source and context.
Explanation:
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Build a Turing machine that enumerates the set of even length strings over {a},
To build a Turing machine that enumerates even length strings over {a}, design a machine that alternates between printing "aa" and moving right.
How can a Turing machine be designed to generate even length strings over {a}?To construct a Turing machine that enumerates even length strings over {a}, we can follow a simple approach. The machine needs to alternate between two actions: printing "aa" and moving right. Initially, the machine positions itself at the leftmost cell of the tape. It prints "aa" on the current cell and then moves the tape head one cell to the right.
It repeats this process until the desired even length strings are generated. By continuously printing "aa" and moving right, the machine will produce a sequence of even length strings consisting of only the symbol "a". This Turing machine systematically generates all possible even length strings over {a}.
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when a dielectric is added between two parallel plates, does the capacitance increase, decrease, or remain the same?
The capacitance of two parallel plates increases when a dielectric material is added between them. This is due to the dielectric material's ability to store electric charge and create an electric field between the plates.
The dielectric increases the capacitance because it decreases the electric field, thus allowing more charge to be stored on the plates. The amount of charge stored on the plates is directly proportional to the capacitance of the circuit. Therefore, when a dielectric material is added, the capacitance increases.
To summarise, when a dielectric is added between two parallel plates, the capacitance increases. This is because the dielectric material can store electric charge and decreases the electric field between the plates, thus allowing more charge to be stored and increasing the capacitance of the circuit.
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Force exerted by a muscle ( 35 points) In the problem below, you will model the forearm and hand as a rigid beam with a distributed load of
0.2lb
/in over 15 inches, with a pin at the clbow. The arm is holding apple soda in a pint glass, the total weight of the liquid and glass is
2lb
centered 2 inches out from the end of the hand. The glass is rigidly connected to the end of the forearm. Treat the biceps tendon as a rope/wire pulling on the forearm. (a) Draw a free body diagram of the pint glass with liquid. (6)
To draw a free body diagram of the pint glass with liquid, we need to identify all of the forces acting on the object and draw them as vectors. The forces acting on the pint glass with liquid are.
Weight: The weight of the pint glass with liquid is 2 lb, acting downwards. We can represent this force as a vector pointing downwards from the center of mass of the glass, which is located 2 inches out from the end of the hand.
Reaction force from the hand: The hand is in contact with the glass and exerts an equal and opposite force on the glass, upwards. We can represent this force as a vector pointing upwards from the center of mass of the glass.
Distributed load: The forearm and hand are modeled as a rigid beam with a distributed load of 0.2 lb/in over 15 inches. The pint glass is rigidly connected to the end of the forearm, so it also experiences this distributed load. We can represent this load as a vector pointing downwards from the end of the forearm.
Tension in biceps tendon: The biceps tendon is modeled as a rope/wire pulling on the forearm. This tension force is transmitted to the pint glass, causing it to rotate about the elbow. We can represent this force as a vector pointing upwards from the end of the forearm.
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It has been observed that a cylindrical rod with a diameter of 93 mm and a length of 204 mm increases in volume by 202 mm3 under the effect of axial normal force. Knowing that E = 181 GPa, ν=1/3, how many kN is the applied force P?
The applied force P on the cylindrical rod is 299.27 kN.
Given, Diameter (d) of the cylindrical rod = 93 mm
Length (l) of cylindrical rod = 204 mm
Increase in volume (ΔV) of cylindrical rod = 202 mm³
Elasticity or Young's modulus (E) = 181 GPa
Poisson's ratio (ν) = 1/3
Formula to calculate the force applied on the cylindrical rod is:
F = ΔV x E / [1-ν²] x [(d/l)²]
Where,
F = Force applied on cylindrical rod
ΔV = Increase in volume
E = Elasticity or Young's modulus
ν = Poisson's ratio of the cylindrical rod
d = Diameter of the cylindrical rod
l = Length of the cylindrical rod
Put all the given values in the above formula:
F = 202 x 181 / [1 - (1/3)²] x [(93/204)²]
F = 299266.44 N
F = 299.27 kN
Therefore, the applied force P on the cylindrical rod is 299.27 kN.
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The mass of a muon is 207 times the electron mass; the averagelifetime of muons at rest is 2.20 μs. In a certainexperiment, muons moving through a laboratory are measured to havean average lifetime of 6.85 μs. For the movingmuons, whatare (a)β(b)K,and (c)p (in MeV/c)?The rest energy of the electron is 0.511 MeV.
For moving muons in the given scenario, the values of β, K, and p are 0.824, (pc² / 104.977 MeV/c²), and √[(K + m0c²)²/c⁴ - m0²c²/c⁴] / c, respectively. These values are obtained through calculations using the provided data and relevant formulas.
The mass of a muon is 207 times the electron mass; the average lifetime of muons at rest is 2.20 μs. In a certain experiment, muons moving through a laboratory are measured to have an average lifetime of 6.85 μs.
The rest energy of the electron is 0.511 MeV. Formulas:Total energy of the particle: E = (m²c⁴ + p²c²)¹/², Where,
E = Total energy of the particle m = Rest mass of the particlec = Speed of light in vacuum p = Momentum of the particleβ = v/c, Where, β = Velocity of the particle/cK = Total Kinetic Energy of the particleK = E - mc²p = Momentum of the particle p = mvTo calculate the value of β for moving muons, we need to calculate the velocity of the muons. To calculate the velocity of the muons, we can use the concept of the lifetime of the muons. The average lifetime of muons at rest is 2.20 μs.
The moving muons have an average lifetime of 6.85 μs. The time dilation formula is given byt = t0 / (1 - β²)c², where,
t = Time interval between the decay of the muon measured in the laboratory.t0 = Proper time interval between the decay of the muon as measured in the muon's rest frame.c = Speed of light in vacuumβ = Velocity of the muon.Hence,t0 = t / (1 - β²)c²t0 = 2.20 μs / (1 - β²)c²t = 6.85 μs. From these two equations, we can calculate the value of β.6.85 μs / t0 = 6.85 μs / (2.20 μs / (1 - β²)c²)β² = 1 - (2.20 μs / 6.85 μs)β² = 0.679β = 0.824. Hence, the value of β is 0.824.
To calculate the value of K for moving muons, we need to calculate the total energy of the muons. The rest mass of the muon is given bym0 = 207 × 0.511 MeV/c²m0 = 104.977 MeV/c².
The total energy of the muon is given byE = (m²c⁴ + p²c²)¹/²E = (104.977 MeV/c²)²c⁴ + (pc)²K = E - m0c²K = [(104.977 MeV/c²)²c⁴ + (pc)²] - (104.977 MeV/c²)c²K = pc² / (104.977 MeV/c²). Hence, the value of K for moving muons is pc² / (104.977 MeV/c²).
To calculate the value of p for moving muons, we can use the value of K calculated in p = √(E²/c⁴ - m0²c²/c²) / cHere,E = (m²c⁴ + p²c²)¹/²E²/c⁴ = m²c⁴/c⁴ + p²p²c²/c⁴ = (K + m0c²)²/c⁴p = √[(K + m0c²)²/c⁴ - m0²c²/c⁴] / c. Hence, the value of p for moving muons is √[(K + m0c²)²/c⁴ - m0²c²/c⁴] / c.
Therefore, the values of β, K, and p are 0.824, (pc² / 104.977 MeV/c²), and √[(K + m0c²)²/c⁴ - m0²c²/c⁴] / c respectively.
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Python 5.18 lab
5.18 lab: adjust values in a list by normalizing when analyzing data sets, such as data for human heights or for human weights, a common step is to adjust the data. this adjustment can be done by normalizing to values between 0 and 1, or throwing away outliers.
for this program, adjust the values by dividing all values by the largest value. the input begins with an integer indicating the number of floating-point values that follow.
output each floating-point value with two digits after the decimal point, which can be achieved as follows:
print('{:.2f}'.format(your_value))
ex: if the input is:
5
30.0
50.0
10.0
100.0
65.0
the output is:
0.30
0.50
0.10
1.00
0.65
the 5 indicates that there are five floating-point values in the list, namely 30.0, 50.0, 10.0, 100.0, and 65.0. 100.0 is the largest value in the list, so each value is divided by 100.0.
In the given student question, Python 5.18 lab 0.50 refers to a Python exercise involving a list with five floating-point values. The list contains the following values: 30.0, 50.0, 10.0, 100.0, and 65.0. The largest value in this list is 100.0.
To solve this exercise, you need to divide each value in the list by the largest value, 100.0. This can be accomplished using a loop or list comprehension in Python. Here's an example of how you can perform this task using a list comprehension:
```python
values = [30.0, 50.0, 10.0, 100.0, 65.0]
largest_value = max(values)
normalized_values = [value / largest_value for value in values]
```
After executing this code, `normalized_values` will contain the result of dividing each element in the original list by the largest value, 100.0. The resulting list will be `[0.3, 0.5, 0.1, 1.0, 0.65]`.
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This agency develops standards for pressure vessels and pressure relief valves, as well as the design, welding, and materials that may be used in pipeline construction.
Select one:
a. American Petroleum Institute
b. American Society of Mechanical Engineers
c. American Gas Association
d. National Fire Protection Association
Answer:
b. American Society of Mechanical Engineers
Explanation:
The "American Society of Mechanical Engineers" (ASME) is an organization that ensures the development of engineering fields. It is an accreditation organization that ensures parties will comply to the ASME Boiler and Pressure Vessel Code or BPVC.
The BPVC is a standard being followed by ASME in order to regulate the different pressure vessels and valves. Such standard prevents boiler explosion incidents.
recall from the video that the field diameter for one objective lens can be used to calculate the field diameters of the other objective lenses of a parfocal microscope. using the diameter of the scanning field, calculate the approximate field diameters of the low power, high power, and oil immersion objectives. drag the correct measurements to complete the table.
The approximate field diameters of the low power, high power, and oil immersion objectives can be calculated using the diameter of the scanning field.
How to calculate the approximate field diameters of the different objectives of a parfocal microscope?To calculate the approximate field diameters of the low power, high power, and oil immersion objectives, we can use the concept of parfocality. Parfocality means that when one objective lens is in focus, the other objective lenses should also be nearly in focus.
The field diameter is defined as the diameter of the circular area visible through the microscope. Since the objective lenses are parfocal, the ratio of the field diameters is equal to the ratio of the objective lens magnifications.
Let's assume the diameter of the scanning field is D_scanning. If the magnification of the scanning objective lens is M_scanning, and the magnifications of the low power, high power, and oil immersion objective lenses are M_low, M_high, and M_oil, respectively, then we can calculate the approximate field diameters as follows:
D_low = (M_low / M_scanning) * D_scanning
D_high = (M_high / M_scanning) * D_scanning
D_oil = (M_oil / M_scanning) * D_scanning
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c) Also known as moral philosophy, Et hics is a branch of phil osophy which
seeks to address questions about morality; that is, about concepts like good and bad, right and wrong, justice, virtue, etc. There is quite a number of approaches to the study of ethical issues. With clear illustrations, compare and contrast Duty-based and Out come – based ethics
It should be noted that duty-based ethics is the intent of an action while outcome-based ethics means the outcome of an action.
What are ethics?It should be noted that ethics are the moral principles that govern a person's behaviour or the conducting of an activity.
Here, duty-based ethics are what people are talking about when they refer to the principle of the thing.
Also, duty-based ethics teaches that some acts are right or wrong based on how they're viewed in the society.
It should be noted that outcome-based ethics simply dictates that the decision to act in a particular way should be beneficial to the people and have a positive impact on them. In this case, the focus is on the result.
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You are a software developer for a Retail Point of Sale System Company. A client has made a request to upgrade the current system from command line interface to a graphic user interface. The client concerns on an effect to the current system with the change. The client does not want to lose any current data on the system. Provide recommendations and the change plan including the below requirements to the customer.
a. Create a requirement plan (what need to be done to support this upgrade)
b. Create a development plan (how to implement this upgrade with programming details explanation including technical details on this document)
c. Create testing plan (how to ensure that the new upgrade works without affecting current system and no data lost.)
Answer:
The recommendations to be provided for the customer and the change in plan before upgrade are: Check system requirements, Check the specifications, Problems that are existing and detected should be resolved before upgrade, Run a normal maintenance routines, Having backup plan
Explanation:
Solution
Command line interface is a way of working with a computer program where the user gives out commands to the program in a method called successive lines of text.
The Graphic user interface is a type of interface that enables users to interact with electronic devices through visual indicators. and graphical icons .
As a software developer, if a request comes to upgrade the system from CLI to GUI. Then, there are a number of necessary points which should be considered and also having a plan which is stated below:
First thing that should be carried is a feasibility study. We need to check whether the upgrade which is required by the client is feasible or not.
There can be a number of issues in the way like resource, technical constraints, budgetary constraints
So as a software developer, we need to examine each of them before Going further.
Check System Requirements: Think not only the system requirements, but also OS present configuration and any i software installed you use.
Check the specifications: The first thing is to check Specification. this is an important true requirement for upgrading, which is to guarantee your system meets the basic system requirements for running GUI
Existing problems should be detected and resolved: before upgrade. also, ensure that your system is not experiencing any major issues currently
Run Normal maintenance routines
Backup: To ensure the security of data, to prevent data loss and to avoid expensive recovery there is nothing that is not better than a backup.
The Golden rule or number one rule is Data backup.
Before upgrading any system, make sure that your personal, critical, ,irreplaceable data is safely backed up fully to an external device, like an external hard drive ,USB disk, DVD, etc.
Again, don't even try to attempt to upgrade before doing this important step. another way is creating a clone system or RAID (Redundant array of independent disks).
Then upgrade can begin. then in this particular order of upgrade,the remote secondary replica nodes first, then local secondary replica node is second , and the primary replica node third.
4. When the ESC system senses oversteer,
A) the brake at the inner rear or front wheel is applied to neutralize the oversteering
B) the brake at the outer corner rear or front wheel is applied to neutralize the oversteering
An OTR is selecting a wheelchair seating system for a child who has scoliosis secondary to spina bifida. Which feature should be considered FIRST for achieving optimal functional seating?
A. Width and placement of lateral trunk supports
B. Type and contour of the chair seat cushion
C. Position and stability of the pelvis in the chair
D. Configuration and attachment of chest harness
The first feature that should be considered for achieving optimal functional seating for a child who has scoliosis secondary to spina bifida is:
Option C. Position and stability of the pelvis in the chair.
Characteristics of a seat for a child with scoliosis secondary to spina bifida: The pelvis is the foundation of the seating system and provides a stable base for the trunk and extremities. Without proper positioning and stability of the pelvis, the child may have difficulty with functional activities and may experience discomfort or pain.
It is also important to consider the width and placement of lateral trunk supports (A), the type and contour of the chair seat cushion (B), and the configuration and attachment of chest harness (D) for optimal seating. However, these should be considered after the position and stability of the pelvis have been addressed.
In summary, the first feature to consider for achieving optimal functional seating for a child with scoliosis secondary to spina bifida is the position and stability of the pelvis in the chair.
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The flywheel has a diameter of 600 mm and rotates
with increasing speed about its z-axis shaft. If the
acceleration of point P on the rim of the flywheel is a=-3.02i-1.624j when ? = 60
The acceleration of point P on the rim of the flywheel is given as a=-3.02i-1.624j. To find the speed of the flywheel, we need to use the relationship between acceleration and angular velocity:
a = r * α
where r is the radius of the circle (which is half of the diameter), and α is the angular acceleration. Since the diameter of the flywheel is given as 600 mm, the radius is 300 mm or 0.3 m.
To find the angular acceleration, we can use the fact that the acceleration is given as a vector in the i-j plane. The component of acceleration in the direction perpendicular to the plane of rotation (i.e., in the k direction) must be zero, since the point is moving on a circle. Therefore:
a · k = 0
where · denotes the dot product. This means that the k-component of a is zero, or a = a_i + a_j, where a_i and a_j are the i- and j-components of a, respectively.
We can use this information to find the angular acceleration:
a = r * α
a_i = r * α * cos(θ)
a_j = r * α * sin(θ)
where θ is the angle between the radius vector and the i-axis (which is 60 degrees in this case). Substituting the given values:
-3.02i-1.624j = 0.3 * α * cos(60)i + 0.3 * α * sin(60)j
Simplifying and solving for α:
α = -10.067 rad/s^2
Now we can use the relationship between angular acceleration and angular velocity:
α = dw/dt
where w is the angular velocity. Integrating both sides:
w = ∫ α dt
Since the initial angular velocity is zero, we can integrate from t=0 to t=t_final:
w = ∫(0 to t_final) α dt
w = ∫(0 to t_final) -10.067 dt
w = -10.067 * t_final
We don't know the value of t_final, but we can use the fact that the point on the rim of the flywheel has traveled a distance equal to the circumference of the circle:
C = 2 * π * r
C = 2 * π * 0.3
C = 1.884 m
The time it takes to travel this distance is:
t_final = C / v
where v is the linear velocity of the point. To find v, we can use the fact that the point is moving on a circle, so its speed is equal to the product of its angular velocity and the radius:
v = r * w
Substituting the given values:
v = 0.3 * (-10.067 * t_final)
v = -3.02 * t_final
Setting this equal to the speed we need to travel the circumference:
-3.02 * t_final = 1.884
Solving for t_final:
t_final = -1.884 / 3.02
t_final = -0.624 sec
This is a negative time, which doesn't make physical sense. However, it indicates that we made an error somewhere in our calculations. Checking our work, we find that we made a mistake in the calculation of the angular acceleration:
α = -10.067 rad/s^2
should be:
α = -10.067 / 0.3
α = -33.56 rad/s^2
Using this value, we can repeat the calculation of the angular velocity:
w = ∫(0 to t_final) α dt
w = ∫(0 to t_final) -33.56 dt
w = -33.56 * t_final
Setting this equal to the speed we need to travel the circumference:
-0.3 * 33.56 * t_final = 1.884
Solving for t_final:
t_final = 0.177 sec
Finally, we can find the speed of the flywheel at this time:
v = r * w
v = 0.3 * (-33.56 * t_final)
v = -1.877 m/s
Note that the speed is negative, indicating that the point on the rim of the flywheel is moving in the opposite direction to the increasing rotation of the flywheel.
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Consider the flow of mercury (a liquid metal) in a tube. How will the hydrodynamic and thermal entry lengths compare if the flow is laminar
Answer:
Explanation:
Considering the flow of mercury in a tube:
When it comes to laminar flow of mercury, the thermal entry length is quite smaller than the hydrodynamic entry length.
Also, the hydrodynamic and thermal entry lengths which is given as DLhRe05.0= for the case of laminar flow. It should be noted however, that Pr << 1 for liquid metals, and thus making the thermal entry length is smaller than the hydrodynamic entry length in laminar flow, like I'd stated in the previous paragraph
QUICKK PLEASE WILL MARK BRAINIEST
When the pressure plate pushes down on the clutch disc, what initially happens?
Answer:
it gives pressure this makes it stay where it has to be and lock it
Explanation:
yan llng alam ko
A well-hydrated human body is made up of about _______ percent water.
Answer:
70%
Explanation:
the purpose behind the use of control charts is to distinguish:
The purpose behind the use of control charts is to distinguish between common cause variation and special cause variation in a process.
Common cause variation is a natural part of any process and is caused by random fluctuations in the system. Special cause variation, on the other hand, is caused by a specific event or factor that can be identified and addressed. Control charts help to monitor a process over time, by plotting data points on a graph, and determining if they fall within the expected range of variation.
If the data falls within the expected range, then the process is considered to be under control. If the data falls outside of the expected range, then there may be a special cause present that requires investigation and corrective action, control charts help to identify and distinguish between common cause and special cause variation, allowing for continuous improvement and quality control in a process.
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Some refrigerants contain CFCs
A) True
B) false
???????
Answer:
true ...............
Some refrigerants R11, R12, and R115 contain CFC. The statement is true.
What is chlorofluorocarbon?Chlorofluorocarbons (CFCs), as the name suggests, are compounds made of the atoms of fluorine, chlorine, and carbon. Because they are neither hazardous nor combustible, they have a variety of uses, including in refrigeration. Refrigeration is the process of maintaining the temperature of the required space cooler than that of an atmosphere.
As the public learned in 1974 that CFCs were alarmingly destroying the ozone layer, most CFCs were outlawed, and by 1995, their manufacture of them had virtually ended worldwide. CFCs were replaced with other products since they were no longer produced and the things they were used for required new products.
Therefore, some refrigerants R11, R12, and R115 contain CFC. The statement is true.
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A horizontal force P is applied to a 130 kN box resting on a 33 incline. The line of action of P passes through the center of gravity of the box. The box is 5m wide x 5m tall, and the coefficient of static friction between the box and the surface is u=0.15. Determine the smallest magnitude of the force P that will cause the box to slip or tip first. Specify what will happen first, slipping or tipping.
Answer:
SECTION LEARNING OBJECTIVES
By the end of this section, you will be able to do the following:
Distinguish between static friction and kinetic friction
Solve problems involving inclined planes
Section Key Terms
kinetic friction static friction
Static Friction and Kinetic Friction
Recall from the previous chapter that friction is a force that opposes motion, and is around us all the time. Friction allows us to move, which you have discovered if you have ever tried to walk on ice.
There are different types of friction—kinetic and static. Kinetic friction acts on an object in motion, while static friction acts on an object or system at rest. The maximum static friction is usually greater than the kinetic friction between the objects.
Imagine, for example, trying to slide a heavy crate across a concrete floor. You may push harder and harder on the crate and not move it at all. This means that the static friction responds to what you do—it increases to be equal to and in the opposite direction of your push. But if you finally push hard enough, the crate seems to slip suddenly and starts to move. Once in motion, it is easier to keep it in motion than it was to get it started because the kinetic friction force is less than the static friction force. If you were to add mass to the crate, (for example, by placing a box on top of it) you would need to push even harder to get it started and also to keep it moving. If, on the other hand, you oiled the concrete you would find it easier to get the crate started and keep it going.
Figure 5.33 shows how friction occurs at the interface between two objects. Magnifying these surfaces shows that they are rough on the microscopic level. So when you push to get an object moving (in this case, a crate), you must raise the object until it can skip along with just the tips of the surface hitting, break off the points, or do both. The harder the surfaces are pushed together (such as if another box is placed on the crate), the more force is needed to move them.
Cellular network towers are configured in such a way so that they avoid what type of problem?
Answer:
They are configured this way to avoid overlap issues.
Explanation:
most percussion instruments fall into the categories of idiophones and aerophones.
Most percussion instruments fall into the categories of idiophones and aerophones, let's discuss what they mean and their types.
The term "idiophone" is derived from two Greek words, "idio," which means "distinct," and "phone," which means "sound." An idiophone is a percussion instrument that creates sound by vibrating the entire instrument rather than a membrane, string, or stretched skin. Aerophones are musical instruments that produce sound primarily by vibrating a column of air within the instrument. They are further categorized into various subcategories based on the instrument's shape, size, and sound characteristics. Most percussion instruments are classified as either idiophones or aerophones, depending on the sound's origin or how the instrument produces sound. Most percussion instruments fall into the categories of idiophones and aerophones. This classification is based on how the instruments create sound. Let's discuss both types in detail. An idiophone is a percussion instrument that creates sound by vibrating the entire instrument rather than a membrane, string, or stretched skin. Some common examples of idiophones include triangles, bells, and xylophones. Aerophones are musical instruments that produce sound primarily by vibrating a column of air within the instrument. Some examples of aerophones include trumpets, flutes, and clarinets. To conclude, both idiophones and aerophones are important categories of percussion instruments. They differ in how they create sound, but both play a significant role in music and are widely used in various cultures worldwide.
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1. How many board feet in piece of Oak that is 1" thick 6" wide and 8' long?
Answer:
4
Explanation:
A "board foot" is 1/12 of a cubic foot. It is the volume of a board 1" thick and 1 foot square.
Here, the board is 1" thick, so the number of board feet is numerically equal to the number of square feet of area it has.
(1/2 ft)(8 ft) = 4 ft²
The number of board feet is 4.
Where does Burj Khalifa located? and how many meters?
Answer:
Burj Khalifa is located in dubai UAE at over 828m
Explanation:
828 metres
Answer:
The Burji Khalifa, known as the Burj Dubai prior to its inauguration in 2010, is a skyscraper in Dubai, United Arab Emirates. With a total hight of 829.8 m and a roof hight of 828 m, the Burji Khalifa has been the tallest structure and building in the world since its topping out in 2009.