Answer:
A Couple in a bicycle is usually generated by the gravitational force and the corresponding reaction forces of the floor. A couple is a force which encourages or prevents a body turning in motion.
The wheels help in the movement and motion of the bicycle from point A to B. The chain which connects different parts help in the rotation of the bicycle wheels through the movement of the pedals by the legs
a hockey puck is hit on a frozen lake and starts moving with a speed of 12.8 m/s. exactly 5.90 s later, its speed is 7.50 m/s. the acceleration of gravity is 9.81 m/s 2 how far does the puck travel during this 5.90 s interval? answer in units of m. answer in units of m.
The average velocity of the puck during the 5.90 s interval can be calculated as the average of the initial velocity and the final velocity:
Thus the velocity will be,
v_avg = (v_initial + v_final) / 2
= (12.8 + 7.5) / 2
= 10.15 m/s
The distance traveled by the puck during this interval can be calculated as:
d = v_avg * t = 10.15 * 5.90 = 59.87 m
This is the distance traveled by the puck in a straight line assuming that it does not experience any forces other than gravity.
However, since the acceleration of gravity is 9.81 m/s^2,
the puck will experience a downward acceleration due to gravity, causing its path to be a parabolic arc.
The exact distance traveled by the puck will depend on the exact path it takes, which is beyond the scope of the information provided.
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taking the potential energy to be zero at infinite separation, find the potential energy of a 47 kg object at the surface of the earth.
The potential energy of a 47 kg object at the surface of the Earth is approximately 2.94 x 10^9 J.
The equation U = mgh, where m is the object's mass, g is the acceleration brought on by gravity, and h is the height above the surface of the Earth, may be used to determine an object's potential energy at a particular height h above the Earth's surface. At the Earth's surface, h is equal to the radius of the planet, which is around 6.37 x 106 metres. About 9.81 m/s2 is the value of g at the Earth's surface. As a result, it is possible to compute the potential energy of a 47 kilogramme item at the Earth's surface using the formula U = (47 kg) x (9.81 m/s2) x (6.37 x 106 m) = 2.94 x 109 J. in 30 words.
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What does it mean for a hypothesis to be testable?
O A. It must be able to reject biased data.
O B. It must be supported by peer review.
O C. It must be able to be supported or refuted by data.
O D. It must be what the scientist is hoping is the result.
Answer:
The answer is C
Explanation:
Testable meaning experiments can be conducted to support or refute the hypothesis. This is done through data.
the stars antares and mima each have the same luminosity. antares is cooler than mima. which star is larger?
The Antares star must be larger than the Mima star.
Size of stars based on their propertiesThe star Antares, being cooler than Mima but having the same luminosity, indicates that it must be larger in size.
The luminosity of a star is closely related to its size and temperature. Cooler stars tend to be larger, while hotter stars are generally smaller.
Therefore, in this scenario, Antares being cooler suggests that it has a larger size compared to Mima, despite having the same luminosity.
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13.Suppose a ball of mass m is thrown vertically upward with an initial speed v, its speed decreases continuously till it becomes zero. Thereafter, the ball begins to fall downward and attains the speed u again before striking the ground. It implies that the magnitude of initial and final momentums of the ball are same. Yet, it is not an example of conservation of momentum. Explain why?
Answer:
Law of conservation of momentum is applicable to isolated system (no external force is applied).
In this case, the change in velocity is due to the gravitational force of earth.When the ball is thrown up, negative force of gravity is applied and so the speed becomes zero.After that due to gravitational force the ball falls down with same initial velocity.
wassup people of this wor;d
A 8.10-kg block is at rest on a horizontal floor. if you push horizontally on the 8.10-kg block with a force of 12.0 n, it just starts to move. what is the coefficient of static friction?
It just starts to move. The coefficient of static friction between the block and the floor is approximately 0.151.
N = (8.10 kg) (9.81 m/s^2) = 79.4 N
Now we can substitute these values into the formula for static friction:
f_s = μ_s N
12.0 N = μ_s (79.4 N)
Solving for μ_s, we get:
μ_s = 12.0 N / 79.4 N
μ_s = 0.151
Static friction is a force that arises between two surfaces that are in contact with each other but not in motion relative to each other. When an external force is applied to an object that is at rest, static friction opposes the force and prevents the object from moving.
This type of friction is the reason why you need to push a heavy object harder and harder until it starts moving. Once the object starts moving, the force required to keep it moving is reduced, and dynamic or kinetic friction takes over. The magnitude of the static friction force depends on the nature of the surfaces in contact, the normal force pressing the surfaces together, and the coefficient of static friction.
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why do people have symptoms in their bodys
Body works like a computer whenever there is any problem it warns you and those warnings are termed as symptoms. Of the body doesn't show symptoms we won't be able to detect the problem in our body.
What is the acceleration of a car making a turn in a circle with a 100m radius traveling at
17m/s?
Answer:
2.89 m/s²
Explanation:
From the question given above, the following data were obtained:
Radius (r) = 100 m
Velocity (v) = 17 m/s
Acceleration (a) =.?
The acceleration of a circular motion is defined by:
a = v²/r
Where:
a is the acceleration.
v is the velocity.
r is the radius.
With the above formula, we can obtain the acceleration of the car as follow:
Radius (r) = 100 m
Velocity (v) = 17 m/s
Acceleration (a) =.?
a = v²/r
a = 17²/ 100
a = 289/100
a = 2.89 m/s²
Therefore, the acceleration of the car is 2.89 m/s²
What is one piece of evidence that supported the heliocentric view but contradicted the geocentric one
One piece of evidence that supported the heliocentric view and contradicted the geocentric view was the observation of the phases of Venus.
Galileo Galilei observed that Venus went through a complete set of phases, ranging from a thin crescent to a nearly full disk. This observation directly contradicted the geocentric model, which could not account for the varying phases of Venus.
In the geocentric model, all celestial bodies were believed to revolve around the Earth. According to this view, Venus should always appear as a thin crescent, similar to the Moon, because it would be seen from Earth on the same side of the Sun. However, Galileo's telescopic observations revealed a different reality. He observed that Venus exhibited a complete set of phases, just like the Moon. These phases included a thin crescent, a half phase, and a nearly full disk.
This observation strongly supported the heliocentric model proposed by Nicolaus Copernicus, where Venus orbits the Sun. In the heliocentric model, as Venus orbits around the Sun, its position relative to Earth changes, causing the observed phases to vary. Galileo's observation of the changing phases of Venus provided concrete evidence contradicting the geocentric view and lending support to the heliocentric model. This evidence played a pivotal role in the scientific revolution and the acceptance of the heliocentric model of the solar system.
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A student is making some changes to a circuit he built. He connected a battery to a circuit that contained a light bulb. He decided to change the light bulb to a higher resistance, but he wanted to keep the current the same. What will he need to do?
A. Increase the voltage by adding a battery with greater volts.
B. It is impossible to change your resistance and keep the current the same.
C. Keep the same exact set up as he originally made.
D. Decrease the voltage by adding a bigger battery with more volts, so the current an flow the same.
Answer:
B
Explanation:
Makes more sense if you want to keep the current the same>
Answer:
a
Explanation:
thats what i put ithink its wrong tho
Science in the study of the natural world through. And.
A huge block of stone has a mass of 650kg and gains 70000j of gpe. how high has it been raised? (g = 10m/s2 )
What is the magnitude of the force a 1.5 x 10^6 C charge exerts on a 3.2 x 10^4 C charge located 1.5 m away?
The magnitude of the force a 1.5 x \(10^6\) C charge exerts on a 3.2 x \(10^4\)C charge located 1.5 m away is approximately 1.152 Newtons.
The magnitude of the force between two charges can be calculated using Coulomb's Law. Coulomb's Law states that the force between two charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.
Let's denote the first charge as Q₁ = 1.5 x \(10^{6}\) C and the second charge as Q₂ = 3.2 x \(10^{4}\) C. The distance between them is r = 1.5 m.
Applying Coulomb's Law, the equation becomes:
F = k * (Q₁ * Q₂) / r²
where k is the electrostatic constant, approximately equal to 9 x \(10^{9}\) N \(m^{2}/C^{2}\).
Substituting the given values into the equation, we have:
F =\((9 * 10^9 N m^2/C^2) * [(1.5 * 10^6 C) * (3.2 * 10^4 C)] / (1.5 m)^2\)
Simplifying this expression yields:
F ≈ 1.152 N
Therefore, the magnitude of the force between the two charges is approximately 1.152 Newtons.
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Which biome contains mostly coniferous trees and receives 35 to 100 cm of rain per year?
The question is incomplete as it does not have the options which are:
deciduous forest
taiga (boreal forest)
temperate rainforest
tropical rainforest
Answer:
Taiga (boreal forest)
Explanation:
A Biome refers to the habitat which is occupied by flora and fauna living in similar conditions. These biomes are distinguished based on many features like precipitation, temperature and many other physical factors.
In the given question, the biome which receives an annual rainfall of 35 to 100 cm annually and is mostly covered by the coniferous trees is known as "Taiga biome" which is also known as Boreal forest.
The Taiga biome is one of the largest terrestrial biomes which is present in Eurasia and North America. The biome is characterised by the conifers trees and therefore is also known as the Coniferous trees.
Thus, Taiga (boreal forest) is the correct answer.
Answer: Taiga(boreal forest)
Explanation:
a truck starts from rest and accelerates for 25 seconds to reach a velocity of 60m/s . calculate the rate of acceleration for the truck
Answer:
2.4m/s²
Explanation:
Given parameters:
Initial velocity = 0m/s
Time 25s
Final velocity = 60m/s
Unknown:
Acceleration = ?
Solution:
Acceleration is the rate of change of displacement
Acceleration = \(\frac{Final velocity - Initial velocity}{time}\)
Acceleration = \(\frac{60 - 0}{25}\) = 2.4m/s³
What type of friction must
these boaters overcome to
move their boat through the
water?
A. Static
B. Fluid
C. Sliding
Station A
? Arrival Time for P Wave
minu
? Arrival Time for 5 Wave
? S-P Lag Time (secs)
? Distance from Epicenter (km)
30
Station B
TIME(econd
Station B
? Arrival Time for P Wave
wwwwwwww
? Arrival Time for S Wave
? S-P Lag Time (secs)
? Distance from Epicenter (km)
30
TIME (second)
-Buon C
Station C
? Arrival Time for P Wave
10
призми мили
? Arrival Time for S Wave
? S-P Lag Time (secs)
100
300
200
Distance from Epicenter
? Distance from Epicenter (km)
90
TIME (second)
NOW: Use your information above to determine which earthquake these seismographs represent. Check the correct box!
90
2
8
8
*PART THREE:
MYSTERY EARTHQUAKE
/Mark the start of the P Wave AND S Wave
Find the Lag Time
Use the Lag Time Graph to determine each
Stations' distance to the epicenter.
Based on the Distances, choose which map
depicts your earthquake!
Graph
Lag time of S-wave behind P-wave
(seconds)
100 0
8
Nasme
8
A motorcycle of mass 100 kilograms travels around a flat, circular track of radius 10 meters with a constant speed of 20 meters per second. What force is required to keep the motorcycle moving in a circular path at this speed?
Answer:
100/10 = 10 , 10 × 10 = 100÷20 = 5
I'm pretty sure its wrong
The force required to keep the motorcycle moving in a circular path is equal to 2000 N.
What is centripetal acceleration?The centripetal force can be described as perpendicular to the velocity in a circular motion. If the objects change their speeds in a circular motion and acceleration is produced which is directed toward the center.
The mathematical expression for the centripetal acceleration used:
a = v²/r
Where 'r' is the circle's radius and a is the centripetal acceleration.
Given, the velocity of the motorcycle, v = 20 m/s
The radius of the track, r = 10m
The centripetal acceleration, a = (20)²/ 2×10 = 20 m/s²
The mass of the motorcycle, m = 100 Kg
The force required to produce this acceleration to keep the motorcycle moving in a circular path at this speed can be calculated as:
F = ma = 100 × 20 = 2000 N
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a 5.00-m-long ladder, weighing 200 n, rests against a smooth vertical wall with its base on a horizontal rough floor, a distance of 1.20 m away from the wall. the center of mass of the ladder is 2.50 m from its base, and the coefficient of static friction between the ladder and the floor is 0.200. how far up the ladder, measured along the ladder, can a 600-n person climb before the ladder begins to slip?
When a 5.00 m-long ladder, with all weighing of 200 n, rests among a smooth vertical type of wall, then the ladder, will be measured among the the height = 0.488 m.
If θ be the angle ladder makes with the plane
cos θ = 1.2 / 5
Tan θ = 4.04
Let the height a person of weight 600 N can climb be h from the ground .
Distance from the base point where ladder touches the floor = h / tanθ
= h / 4.04
Total reaction force = total downward force
R = 200 + 600
800 N
Frictional force = μ R
= .2 x 800
= 160 N
Taking moment of force about the point on the ladder where it touches the floor and balancing them
= 200 x 1.2 x .5 + 600 x h / tanθ = μ R x 1.2 / tanθ ( reaction at the top point of ladder where it touches the wall is R₁ and R₁ =μ R )
= 200 x 1.2 x .5 + 600 x h / tanθ = 160 x 1.2 / tanθ
120 - 600 h / 4.04 = 47.52
120 - 47.52 = 600 h / 4.04
72.48= 148.51 h
h = 0.488 m
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a sled is pulled along a flat road with a consistency velocity. The sled is being pulled by a rope that makes an angle of 25 degrees with the horizontal. The friction of a snow on the sled provides a force of 85 Newtons. What is the force being applied to the rope
The force being applied to the rope is 43.78 Newtons.
How do you determine the force applied?To find the force being applied to the rope, you can use the formula:
F = ma
where,
F is the force, m is the mass of the sled, and a is the acceleration of the sled. Since the sled is moving at a constant velocity, the acceleration is 0.
The force being applied to the sled by the rope can be broken down into two components:
a horizontal component and a vertical component.The horizontal component is the force being applied to the sled in the direction it is moving, and the vertical component is the force being applied to the sled in the direction perpendicular to the direction it is moving.
Apply trigonometry to find the horizontal and vertical components of the force being applied to the sled. The horizontal component is the force being applied to the sled in the direction it is moving, and the vertical component is the force being applied to the sled in the direction perpendicular to the direction it is moving.
So, the horizontal component of the force being applied to the sled is 85 * cos(25) = 72.67 Newtons. The vertical component of the force being applied to the sled is 85 * sin(25) = 42.78 Newtons.
Since the friction of the snow on the sled provides a force of 85 Newtons in the opposite direction of the direction the sled is moving, the total horizontal force being applied to the sled is 72.67 - 85 = -12.33 Newtons. This means that the force being applied to the rope in the direction it is being pulled is 12.33 Newtons.
The total vertical force being applied to the sled is 42.78 - 0 = 42.78 Newtons. This means that the force being applied to the rope in the direction perpendicular to the direction it is being pulled is 42.78 Newtons.
So, the total force being applied to the rope is the square root of the sum of the squares of the horizontal and vertical components of the force. This is equal to the square root of (12.33^2 + 42.78^2) = 43.78 Newtons.
Therefore, the correct answer is as given above
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of all the types of light the sun gives off, it emits the greatest amount of light at visible light wavelengths. if the sun were to cool off dramatically and as a result start giving off mainly light at wavelengths longer than visible light, how would the frequency, energy, and speed of this light given off by the sun also be different? explain your reasoning.
If the sun starts giving off mainly light at longer wavelengths than visible light, the frequency of light would decrease, and the energy of light would also decrease. This means that the light would have less energy than visible light. The speed of light, however, would remain constant, which is 299,792,458 meters per second.
The sun is a star, which is a giant ball of gas that produces light through nuclear fusion. Light is an electromagnetic wave that has a range of wavelengths and frequencies. The wavelengths of light are different and correspond to different colors. The visible light spectrum is the range of wavelengths that are visible to the human eye, and they are the colors that we see. If the sun were to cool off dramatically and as a result start giving off mainly light at wavelengths longer than visible light, the frequency, energy, and speed of this light given off by the sun would be different.
The frequency of light is the number of waves that pass a given point in a second, and it is measured in Hertz (Hz). The energy of light is directly proportional to its frequency. This means that if the frequency of light increases, its energy also increases. The speed of light is a constant and is measured as 299,792,458 meters per second. The frequency and energy of light would both drop if the sun began emitting light mostly at longer wavelengths than visible light.
The light would therefore be less energetic than visible light. Yet, the speed of light, which is 299,792,458 metres per second, would not change.
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FM radio stations use different frequencies. For
example, the radio station 93.3 has a
frequency of 93.3 Megahertz (MHz). Your
friend has the following four radio stations
preset on the stereo in her car. Which of these
stations would you expect to have the longest
wavelength? Explain your answer.
89.5 FM
92.5 FM
95.7 FM
101.5 FM
Answer:
89.5 Hz
Explanation:
The relationship between the frequency and the wavelength is given by the following formula:
\(\lambda = \frac{c}{f}\\\\\)
where,
f = frequency
c = speed of light
λ = wavelength
Since the speed of light is constant. Therefore the formula suggests an inverse relationship between the frequency and the wavelength. Hence, the station with the lowest frequency will have the longest wavelength.
Therefore, the answer is:
89.5 Hz
When a golf ball is hit, it travels at 41 meters per second. The mass of a golf ball is 0.045kg. Calculate the kinetic energy of the golf ball.
Answer:
75.645 J
Explanation:
The kinetic energy is related to the mass and velocity by the formula ...
KE = 1/2mv²
For the given mass of 0.045 kg, and velocity of 41 m/s, the kinetic energy is ...
KE = 1/2(0.045 kg)(41 m/s)² = 75.645 J
__
The unit of energy, joule, is a derived unit equal to 1 kg·m²/s².
A 969 n sky diver has opened his parachute to slow his descent to a constant speed the parachute applies 1,323 n of force. what deceleration does he experiences
Answer:
See below
Explanation:
Find mass of skydiver
F = mg
969 = m ( 9.81) so m = 98.8 kg
NET deccel force = 1323-969 = 354 N
F=ma
354 = 98.8 (a) = 3.58 m/s^2 decceleration
Microwaves travel at the speed of light, 300,000 km/s. What is the wavelength of a microwave received at 1000 gigahertz?
Answer:
3 x 10⁻⁴m
Explanation:
Given parameters:
Speed of light = 300000km/s
Frequency = 1000gigahz = 1000 x 10⁹Hz
Unknown:
Wavelength = ?
Solution:
To solve this problem, we use the expression below:
V = F ∧
V is the speed
F is the frequency
∧ is the wavelength
300000 = 1000 x 10⁹ x ∧
Wavelength = 3 x 10⁻⁷km = 3 x 10⁻⁴m
A ball is thrown horizontally from the top of a
building 110 m high. The ball strikes the ground
74 m horizontally from the point of release. What
is the speed of the ball just before it strikes the
ground?
Answer in units of m/s.
The speed of the ball just before it strikes the ground is 46.4 m/s
Motion Under Gravity
Motion under gravity is also known as vertical motion. The gravity act only on the vertical component of the velocity.
Given that a ball is thrown horizontally from the top of a building 110 m high. The ball strikes the ground 74 m horizontally from the point of release.
The time taken for the ball will be
h = ut + 1/2gt²
but u = 0
110 = 1/2 × 9.8 × t²
110 = 4.9t²
t² = 110 / 4.9
t² = 22.45
t = √22.45
t = 4.74 s
The speed of the ball just before it strikes the ground will be
v² = u² + 2gH
v² = 0 + 2 × 9.8 × 110
v² = 2156
v = √2156
v = 46.4 m/s
Therefore, the speed of the ball just before it strikes the ground is 46.4 m/s
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A wave has a frequency of 450 Hz and a wavelength of 0.52 m. What is the speed of the wave?
Answer:
Explanation:
ave speed is always (frequency) x (wavelength)
Speed = (450 /sec) x (0.52 m)
= 234 m/sec .
Define investigation to show its scientific meaning.
Answer:
the action of investigating something or someone; formal or systematic examination or research.
Explanation:
This definition is provided by Oxford Languages
12. There are 5280 ft in a mile. There are 1.61 km in a mile. If you travel 10,000ft, how many km did you travel?
a) 3.05km
b) 30.5km
c) 1.89km
d) 18.9km
1000m
d) 0.4m
Answer:
Below
Explanation:
10 000 ft / 5280 ft/mi * 1.61 km/ mi = 3.05 km
(see how the 'ft' and 'mi' cancel out and you are left with km??)
Answer:
a
Explanation:
10,000ft/1×1mi/5280ft×1.61km/mi=3.05km
Cross out the units with the target unit on the top. ft in the numerator cancels out with ft in the denominator, then mi in numerator cancels out with mi in denominator leaving km, your target.