How did Kepler develop his second law of motion?(1 point)

a He made accurate measurements of the positions of all the planets over many years.


b He used a telescope to carefully follow and time the orbital motion of Mars.


c He compared data of planetary motion at different times along orbits.


d He invented a telescope that was strong enough to view all planets of the solar system along their orbits.

Answer:D

Explanation:

The experiment by Avery, MacLeod, and McCarty in 1944 with the r and s strains of streptococcus pneumonia demonstrate that DNA (rather than proteins) has the ability to change the properties of cells.

Oswald Avery, Colin MacLeod, or Maclyn McCarty issued the outcomes of an experiment in 1944 that showed DNA is responsible to feed bacterial differentiation (the conversion of a specific strain of microorganisms to another strain for a chemical substance) and thus is likely to be bacteria's genetic material.

Proteases, which digest proteins, did not remove the transforming principle, according to Avery and McCarty. Lipases, which break down lipids, did not work either. They discovered that the material that transformed the substance was high in nucleic acids, however, Ribonuclease which usually digests RNA did not render it inactive.

Griffith found transformation in bacteria. He discovered that when a lethal pneumococcal strain's dead strain (S-type) is mixed with a nonlethal strain (R-type), the nonlethal strain (R-type) becomes lethal.

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Answer: are being rapidly developed but traditional plant breeding programs are still the only method used to develop new plants

Explanation:

The correct option is B -Terrestrial insects−−uric acid.

The species that is incompatible with the main sort of nitrogenous waste it excretes is an insect that lives on land. The correct response for terrestrial insects is "uric acid," not "ammonia."

The primary nitrogenous waste excreted by terrestrial insects, such as insects and spiders, is uric acid. Uric acid is a somewhat insoluble waste product that requires less water for excretion in organisms living in dry or terrestrial settings.

Hence option B is correct.

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In glycolysis when glucose is converted to lactic acid. This is an example of fermentation.

Fermentation begins with glycolysis, but it does not involve the latter two stages of aerobic cellular respiration which is the Krebs cycle and oxidative phosphorylation. In lack of oxygen, pyruvate will undergo a process called fermentation. In the process the NADH+ H+ from glycolysis will be recycled back to NAD+ so that glycolysis can continue. In the process of glycolysis, NAD+ is reduced to form NADH+ H+ . The final product of glycolysis is pyruvic acid in aerobic condition. And forms lactic acid in anaerobic condition which is also termed as fermentation.

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Complete question- Glycolysis is the name given to a metabolic pathway occurring in many different cell types. It consists of 11 enzymatic steps that convert glucose to lactic acid. Glycolysis is an example of: A) aerobic metabolism. B) anabolic metabolism. C) a net reductive process. D) fermentation. E) oxidative phosphorylation.

the surface area of a figure in square units is the number of unit square it takes to cover entire surface without the gas or overlapse if three dimensional figure has + sides the sides called faces the surface area is the total of the area of the faces

TRUE. Generally, among mammals, species with shorter telomeres tend to have longer lifespans. Telomeres are protective caps on the ends of chromosomes, and their length is associated with cellular aging and longevity.

FALSE. The statement is incorrect. Telomeres, which are protective caps on the ends of chromosomes, tend to shorten with each cell division and are associated with cellular aging. Longer telomeres are typically found in species with longer lifespans, indicating better cellular health and longevity. Shortened telomeres, on the other hand, are linked to decreased cellular function, increased cellular senescence, and reduced lifespan. Therefore, among mammals, species with longer telomeres are more likely to have longer lives. Telomere length is influenced by various factors including genetics, lifestyle, and environmental factors, and it plays a role in the aging process and age-related diseases.

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Answer:

Magnesium was the limiting nutrient in an experiment where you have a culture of algae that is growing pretty well in its current medium.

Explanation:

Quality and quantity of nutrients, light, pH, turbulence, salinity or salt content, and temperature are the primary regulating parameters for algal growth. In an experiment where two cultures are grown separately, one with nitrogen supply and the other with magnesium supply, shows good cultural growth in the one magnesium was added. Thus, rather than nitrogen, magnesium is the limiting nutrient.

The majority of algae need at least 17 critical elements to develop. The availability of these nutrients in relation to algal demand determines the nutrient that restricts algal growth in a water body. The limiting nutrient in most water bodies is either phosphorus or nitrogen, but in other systems, trace elements like iron and molybdenum may also be a problem.

The excessive algal growth in water bodies is referred to as eutrophication.

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ALS is characterized by the progressive degeneration of motor nerve cells in the brain (upper motor neurons) and spinal cord (lower motor neurons).

ALS (amyotrophic lateral sclerosis) causes loss of muscle control. ALS is often called Lou Gehrig's disease, after the baseball player who was diagnosed with it. ALS has no cure. Causes of ALS: Theoretical mechanisms of neurodegeneration 1 Oxidative stress Defective glutamate metabolism Mitochondrial dysfunction. This neuronal death causes loss of brain volume and disruption of sodium, calcium, and potassium ion channels, which in turn alters neuronal conductance. The disorder is named for its underlying pathophysiology, and "amyotrophy" refers to the atrophy of muscle fibers, which are denervated as the corresponding anterior horn cells degenerate.

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Answer:

A. which organization published the source.

Explanation:

Answer:

Explanation:

Somatosensory cortex area of the brain receives information collected from mechanoreceptors. Option D is correct.

The somatosensory cortex is a region of the brain that receives information collected from mechanoreceptors. Mechanoreceptors are sensory receptors that respond to mechanical stimuli, such as touch, pressure, and vibration. The somatosensory cortex is located in the parietal lobe of the brain, and it is divided into two parts: the primary somatosensory cortex and the secondary somatosensory cortex.

The primary somatosensory cortex receives information from the skin, muscles, and joints. The secondary somatosensory cortex integrates this information and allows us to perceive the location, intensity, and quality of touch. The pons is a region of the brainstem that is involved in the coordination of movement and the regulation of sleep. The olfactory lobe is a region of the brain that is involved in the sense of smell. The medulla is a region of the brainstem that is involved in the control of breathing, heart rate, and blood pressure. Option D is correct.

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Explanation:

A gas can be converted into a liquid by increasing the pressure & decreasing temperature. So that the condensation occurs. You must also make the molecules closer so that it is a phase change from a gas to liquid. In liquids, the molecules are very near than that of gases.

Basal cell carcinoma initially affects cells of the stratum basale (also known as the basal layer) of the epidermis, which is the outermost layer of the skin.

The stratum basale is the deepest layer of the epidermis and is responsible for the continuous renewal of the skin.

Basal cell carcinoma is the most common type of skin cancer, and it arises from the abnormal growth of basal cells.

These cells are responsible for producing new skin cells and play a vital role in the maintenance and regeneration of the skin.

The tumor initially develops within the basal layer, characterized by the uncontrolled proliferation of basal cells. Over time, it can extend into the surrounding layers of the skin if left untreated.

Basal cell carcinoma usually appears as a slow-growing, pearly or waxy bump, often with visible blood vessels or a central depression.

Since basal cells are located in the stratum basale, basal cell carcinoma typically originates in this layer.

Early detection and prompt treatment are crucial for managing basal cell carcinoma and minimizing its potential for further growth and spread.

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Answer:A stunt person jumps off of a three story building into a dumpster full of cardboard and bubble wrap. When he entered the dumpster he was traveling at 22 m/s and he soon came to a complete stop.

If he underwent an impulse of −2134 N·s then what is his mass in kg?

Explanation:

According to the research, the correct answer is it has a very slow catalytic rate. The enzyme rubisco is thought to be inefficient due to its slow catalytic rate.

It is a chloroplast protein essential for atmospheric carbon dioxide  fixation and can be inhibited by oxygen due to its low substrate specificity and slow catalytic rate.

In this sense, this slow enzyme is exclusive of the green tissues of plants and of those organisms that carry out photosynthesis, being able to take 3 or 4 molecules of carbon dioxide for each one of oxygen, this makes it ineffective in addition to presenting a huge expense energetic.

Therefore, we can conclude that according to the research, Rubisco is an enzyme that acts as an initial catalyst but its catalytic activity is very slow.

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Answer:

Vegetation- riparian vegetation directly affects dissolved oxygen by releasing oxygen into the water during photosynthesis. It indirectly affects dissolved oxygen concentrations because vegetation shading a stream may decrease water temperatures, and as temperature decreases dissolved, oxygen increases.

a) 0 is the concentration of free enzyme.

b) 10^-9 M is the concentration of the ES complex.

- Km = 10^-6 M

- Initial substrate concentration [S] = 10^-3 M

- Initial enzyme concentration [E] = 10^-9 M

- kcat (catalytic rate constant) = 10 sec^-1

To find the concentration of free enzyme ([E]) at a steady state, we need to determine the amount of enzyme that is bound to the substrate (ES complex). At a steady state, the rate of formation of the ES complex equals the rate of its breakdown.

The rate of ES complex formation is given by k1 * [E] * [S], and the rate of ES complex breakdown is given by k-1 * [ES]. At steady state, these rates are equal:

k1 * [E] * [S] = k-1 * [ES]

Since k-1 = k2 (the rate constant for ES complex breakdown to form product), we can substitute k2 for k-1:

k1 * [E] * [S] = k2 * [ES]

At steady state, the concentration of the ES complex, [ES], is constant, so we can express it in terms of the total enzyme concentration [E]T and the concentration of free enzyme [E]:

[ES] = [E]T - [E]

Substituting this expression into the equation:

k1 * [E] * [S] = k2 * ([E]T - [E])

Plugging in the given values:

(10 sec^-1) * (10^-9 M) * (10^-3 M) = k2 * ([E]T - [E])

Simplifying the equation:

10^-11 = k2 * ([E]T - [E])

Since we are given kcat = k2 as 10 sec^-1:

10^-11 = 10 sec^-1 * ([E]T - [E])

Since we are in a steady state, we can assume that the concentration of the enzyme-substrate complex [ES] is negligible compared to the concentrations of [E] and [S]. Therefore, we can consider [E]T ≈ [E].

10^-11 ≈ 10 sec^-1 * ([E] - [E])

10^-11 ≈ 0

This implies that the concentration of free enzyme ([E]) at a steady state is approximately 0.

For part (b), the concentration of the ES complex can be calculated using the steady-state approximation:

[ES] = [E]T - [E]

[ES] = (10^-9 M) - 0

[ES] ≈ 10^-9 M

Therefore, the concentration of the ES complex at a steady state is approximately 10^-9 M.

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Answer:

I would think C

Explanation:

I came up with this answer through process of elimination:

A) It shows that they both come from the same speckled fish, so this cannot be the answer

B) I thought this was it, but the chart shows nothing about them having possibly lived in the same lake, only that they came from the same fish

C) The graph shows that they both originated from the same speckled fish

D) This can't be it, because the lakes are so close together

By looking at the hypothetic chart, it is clear that the fish in lake 1 and lake 2 are descended from a common ancestor. so, the correct option is C.

What is species?

A biological species is a group of organisms that can reproduce with one another in nature and produce fertile offspring.

When two lakes are close to one another, they can't be geographically separated. The fish in lake 1 and lake 2 do not evolve from different ancestors as both the species are looking very similar to each other.

Therefore, by looking at the hypothetic chart, it is clear that the fish in lake 1 and lake 2 are descended from a common ancestor.

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Answer:

Macronutrients

- Proteins

- Carbohydrates

- Fats

Micronutrients

- Calcium

- Vitamins

- Zinc

Explanation:

Got it right on my test. Have a good day!

Carbohydrates, proteins, and fats are the macronutrients, whereas vitamins, calcium, and zinc are the micronutrients.

Macronutrients and micronutrients are two very essential nutrients that are required for the growth and development of the body. Macronutrients are nutrients required in large quantities in the body for its growth and development, and to perform various other body functions. Carbohydrates, proteins, and fats are the three main macronutrients found.

Carbohydrates are building blocks of monosaccharides and provide energy to the body whereas proteins are building blocks of amino acids and are required to build and repair tissues in the body. Fats are also the building blocks of fatty acids and are important for protecting organs and providing energy too.

Micronutrients, on the other hand, are nutrients required in smaller amounts, and are essential part of the body. Micronutrients include vitamins and minerals such as calcium, iron, and zinc.

Therefore, carbohydrates, proteins, and fats are the macronutrients, whereas vitamins, calcium, and zinc are the micronutrients.

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We have that for the Question "Does she need to worry about this problem" it can be said that

From the question we are told

Marissa has had her entire thyroid gland removed because of a malignant tumor. She takes synthetic thyroid hormone to replace the thyroxine that her thyroid gland would have produced, but she is worried about her blood calcium. Does she need to worry about this problem

Generally normal thyroid feature is watched through the pituitary gland. The pituitary makes a hormone known as TSH that motives the thyroid gland to make thyroid hormone for the body.

the  hormone additionally promotes increase of the thyroid gland and likely of thyroid most cancers cells.

Levothyroxine (L-T four ) is one of the most typically given medications. It is given as both physiologic alternative remedy in sufferers with hypothyroidism or as interventional remedy to suppress thyroid-stimulating hormone secretion in sufferers with  thyroid cancer.

Therefore

if Mary is taking Calcium medication with thyroid hormone,she does not need to worry about this problem

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Try this class experiment to detect the presence of enzymes as they catalyse the decomposition of hydrogen peroxide

Enzymes are biological catalysts which increase the speed of a chemical reaction. They are large protein molecules and are very specific to certain reactions. Hydrogen peroxide decomposes slowly in light to produce oxygen and water. The enzyme catalase can speed up (catalyse) this reaction.

In this practical, students investigate the presence of enzymes in liver, potato and celery by detecting the oxygen gas produced when hydrogen peroxide decomposes. The experiment should take no more than 20–30 minutes.

Equipment

Apparatus

Eye protection

Conical flasks, 100 cm3, x3

Measuring cylinder, 25 cm3

Bunsen burner

Wooden splint

A bucket or bin for disposal of waste materials

Chemicals

Hydrogen peroxide solution, ‘5 volume’

Small pieces of the following (see note 4):

Liver

Potato

Celery

Health, safety and technical notes

Read our standard health and safety guidance.

Wear eye protection throughout. Students must be instructed NOT to taste or eat any of the foods used in the experiment.

Hydrogen peroxide solution, H2O2(aq) – see CLEAPSS Hazcard HC050 and CLEAPSS Recipe Book RB045. Hydrogen peroxide solution of ‘5 volume’ concentration is low hazard, but it will probably need to be prepared by dilution of a more concentrated solution which may be hazardous.

Only small samples of liver, potato and celery are required. These should be prepared for the lesson ready to be used by students. A disposal bin or bucket for used samples should be provided to avoid these being put down the sink.

Procedure

Measure 25 cm3 of hydrogen peroxide solution into each of three conical flasks.

At the same time, add a small piece of liver to the first flask, a small piece of potato to the second flask, and a small piece of celery to the third flask.

Hold a glowing splint in the neck of each flask.

Note the time taken before each glowing splint is relit by the evolved oxygen.

Dispose of all mixtures into the bucket or bin provided.

Teaching notes

Some vegetarian students may wish to opt out of handling liver samples, and this should be respected.

Before or after the experiment, the term enzyme will need to be introduced. The term may have been met previously in biological topics, but the notion that they act as catalysts and increase the rate of reactions may be new. Similarly their nature as large protein molecules whose catalytic activity can be very specific to certain chemical reactions may be unfamiliar. The name catalase for the enzyme present in all these foodstuffs can be introduced.

To show the similarity between enzymes and chemical catalysts, the teacher may wish to demonstrate (or ask the class to perform as part of the class experiment) the catalytic decomposition of hydrogen peroxide solution by manganese(IV) oxide (HARMFUL – see CLEAPSS Hazcard HC060).

If students have not performed the glowing splint test for oxygen for some time, they may need reminding of how to do so by a quick demonstration by the teacher.

Additional information

This is a resource from the Practical Chemistry project, developed by the Nuffield Foundation and the Royal Society of Chemistry. This collection of over 200 practical activities demonstrates a wide range of chemical concepts and processes. Each activity contains comprehensive information for teachers and technicians, including full technical notes and step-by-step procedures. Practical Chemistry activities accompany Practical Physics and Practical Biology.

It is important to prepare dilutions of a stock solution for several reasons:

Overall, preparing dilutions of a stock solutionis an important step in many scientific experiments and procedures, as it allows for more accurate, safe, and convenient handling of substances.

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Yes, It's true!

Explanation:

Material rising from the mantle reaches the surface at spreading centers.

A. True

B. False

Here is a summary of the short story "The Man to Send Rain Clouds" using the Somebody Wanted But So Then strategy:

Somebody: Teofilo, a respected elder in the Laguna Pueblo tribe, has died.

Wanted: His family and community want to honor him with a traditional funeral ceremony.

But: The priest, who is also a member of the community, refuses to participate in the ceremony because he believes it is pagan.

So: The family is forced to hold the funeral without the priest's blessing. They paint Teofilo's face with traditional symbols, offer him cornmeal and pollen, and pray for rain.

Then: The next day, it rains. The community is grateful to Teofilo for sending the rain, and they realize that they can still honor him even without the priest's blessing.

This story explores the conflict between traditional Pueblo beliefs and Christianity. It also shows how a community can come together to support each other during a time of loss.

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Mutations in sexually reproducing organisms must occur in the sex cells and not somatic cells in order to contribute to evolution.

Sex cells, also known as gametes, are the cells that are involved in sexual reproduction and carry the genetic information from the parents to their offspring. Somatic cells, on the other hand, make up the body tissues and organs of an organism. When a mutation occurs in a somatic cell, it only affects the individual organism and is not passed down to its offspring. However, when a mutation occurs in a sex cell, it can be passed down to the offspring and potentially become a part of the gene pool of a population.

Therefore, mutations in sex cells are important for the variation and evolution of a species. Somatic mutations do not contribute to the genetic diversity of a population and cannot lead to evolution.

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Answer:

Hey Dude...

Explanation:

This is ur answer....

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Answer:

The tertiary consumers.

Explanation:

The tertiary consumers will be the least available in the ecosystem.

Explanation:

the toxic chemical has different ingredients that makes it having a different reaction at the container