how do I add odd number fractions for example 5/9 and 3/5?​

Answer:

Step-by-step explanation:

From the given information:

Null and alternative hypothesis is:

\(\mathbf{H_o: \text{The die is not loaded i.e. six numbbers are equally alike}}\)

\(\mathbf{H_a: \text{The die is loaded i.e. six numbbers are not equally alike}}\)

Numbers   Observed         Expected            (O - E)    (O-E)^2     (O-E)^2/E

                 Frequency (O)   Frequency (E)  

1                  31                             30                   1             1               0.03

2                 34                            30                   4             16            0.53

3                 26                            30                  -4            16             0.53

4                 16                             30                  -14           196           6.53

5                 32                            30                    2            4               0.13

6                 41                             30                    11            121            4.03

Total          180                                                 \(X^2= \sum (\dfrac{O-E}{E})^2=11.78\)

degree of freedom = n - 1

= 6 - 1

= 5

Critical value at \(X^2_{0.05/2,5} =11.07\)

Since the calculated \(X^2 \ is \ > X^2_{0.025/5}\) , then we reject \(H_o\)

Conclusion: Accept the alternative hypothesis.

The information provided gives sufficient evidence for us to conclude that the given die is loaded.

The number of pounds of strawberries sold and the number of pounds of grapes sold is 32 and 20 respectively.

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side. It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Given that the selling price of strawberries each pound = $2.50,

The selling price of grapes each pound = $2

The total earning = $160

Let x is the no of a pound of strawberries and y is the no of a pound of grapes sold, then equation will be,

x = y + 12 and 2.50x + 2y= 160

Solve the equation by substitution method;

x = 32 and  y = 20

Therefore, the number of pounds of strawberries sold is 32

the number of pounds of grapes sold is 20.

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Answer:

The answer I got was: (0.4,0)

The expression arcctg(tg(x)) simplifies to arcctg(tan(x)).

To simplify the expression arcctg(tg(x)), we can apply trigonometric identities and properties.

The function arcctg(x) is the inverse cotangent function, which is the angle whose cotangent is x. Similarly, tg(x) represents the tangent function.

First, let's simplify the expression inside the arcctg function, which is tg(x):

tg(x) = sin(x) / cos(x)

Now, we can substitute this value into the original expression:

arcctg(tg(x)) = arcctg(sin(x) / cos(x))

Using the property of inverse trigonometric functions, we can rewrite this as:

arcctg(sin(x) / cos(x)) = arcctg(1 / tan(x))

Now, we can simplify further using the identity:

1 / tan(x) = cot(x)

Therefore:

arcctg(1 / tan(x)) = arcctg(cot(x))

Using another identity, we know that the cotangent function is the reciprocal of the tangent function:

cot(x) = 1 / tan(x)

Therefore, we can simplify the expression to:

arcctg(cot(x)) = arcctg(1 / tan(x)) = arcctg(tan(x))

Finally, we arrive at the simplified expression:

arcctg(tg(x)) = arcctg(tan(x))

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n⁴ - 2n³ - 23n² + 24n + 144 is the standard form of given zeroes.

What is a linear equation in mathematics?

A linear equation is an algebraic equation of the form y=mx+b. m is the slope and b is the y-intercept. The above is sometimes called a "linear equation in two variables" where y and x are variables.

                              A linear equation is an equation that raises a variable to the first power. ax+b = 0 is an example of a 1 variable. x is a variable and a and b are real numbers.  

Roots : -3(mult . 2), 4(mult.2)

the function is given as

     f(n) = (n + 3)² (n - 4)²

         = (n + 3) (n + 3 ) ( n - 4 ) ( n - 4)

        = (n² + 6n + 9) (n² - 8n + 16 )

        = n⁴ - 8n³ + 16n² + 6n³ - 48n² + 96n + 9n² - 72n + 1

collecting like term,

    f(n) = n⁴ - 2n³ - 23n² + 24n + 144

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The integer values that make the statement true are x = -3, -2, -1, 1, 2, 3

We have,

We can start by multiplying both sides of the inequality by -3x to get rid of the denominators:

-3/x < -x/3

Multiplying by -3x on both sides.

-9 < -x²

Rearranging.

x² < 9

Taking the square root of both sides.

|x| < 3

This means that x can take any integer value between -3 and 3, excluding 0.

Thus,

The integer values are x = -3, -2, -1, 1, 2, 3

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DF is the ⊥ bisector of GE

The area of the Region bounded by y = √x, y = 2-x², and y = -√2x is $\frac{32}{15}$.

To find the area of the region bounded by y = √x, y = 2-x², and y = -√2x, we need to graph the equations and determine the points of intersection. Then we can integrate to find the area.

Firstly, we'll graph the equations and find the points of intersection:

y = √xy = 2-x²y = -√2xGraph of y = √x, y = 2-x², and y = -√2xWe need to solve for the points of intersection, so we'll set the equations equal to each other and solve for x:√x = 2-x²√x + x² - 2 = 0Let's substitute u = x² + 1:√x + u - 3 = 0√x = 3 - u

(Note: Since we squared both sides, we have to check if the solution is valid.)u = -2x²u + x² + 1 = 0 (substituting back in for u

)Factoring gives us:u = (1, -2)We can then solve for x and y:x = ±1, y = 1y = 2 - 1 = 1, x = 0y = -√2x = -√2, x = 2y = 0, x = 0Graph of y = √x, y = 2-x², and y = -√2x with points of intersection to find the area, we need to integrate.

The area is bounded by the x-values -1 to 2, so we'll integrate with respect to x:$$\int_{-1}^0 (2 - x^2) - \sqrt{x} \ dx + \int_0^1 \sqrt{x} - \sqrt{2x} \ dx$$

We can then simplify and integrate:$$\left[\frac{2x^3}{3} - \frac{2x^{5/2}}{5/2} + \frac{4}{3}x^{3/2}\right]_{-1}^0 + \left[\frac{2x^{3/2}}{3} - \frac{4x^{3/2}}{3}\right]_0^1$$$$= \frac{4}{3} + \frac{4}{3} - \frac{4}{15} + \frac{4}{3} - \frac{4}{3}$$$$= \frac{32}{15}$$

Therefore, the area of the region bounded by y = √x, y = 2-x², and y = -√2x is $\frac{32}{15}$.

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In the context of this problem all the solutions to the polynomial equation is correct because they all make sense.

The given polynomial equation  can be expressed as ;

x³ + 6x² - 40x = 192 and the given solutions can be written as ; x = -8, x = -4, and x = 6

We can test if the solution is the best for the given euation because this will help us to know if these valueas are the solution for the equation

x = -8

[(-8)³ + 6(-8)² - 40(-8)]

= 192

[-512 + 384 + 320]

= 192

x = -4,

[(-4)³ + 6(-4)² - 40(-4)]

[-64 + 96 + 160 ]

= 192

x = 6

[(6)³ + 6(6)² - 40(6) ]

216 + 216 - 240

= 192

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Answer:

Step-by-step explanation:

A,B

x = –8

x = –4

False.

2x10^6 you move the decimal point 6 places to the right. ( add 6 zeros after the 2)

2x 10^6 = 2,000,000

The next term in the sequence is 98. None of the given options (60, 81, 90, 101) match the expected next term. None of the option is correct.

To find the pattern in the sequence 1, 1, 3, 8, 19, 41, we can examine the differences between consecutive terms:

1 1 3 8 19 41

0 2 5 11 22

Looking at the differences, we can observe that each subsequent difference is obtained by adding consecutive odd numbers: 2, 3, 4, 5, etc. This suggests that the original sequence may be related to square numbers.

Let's check if the differences between consecutive terms are square numbers:

2 = 1²

5 = 2² + 1²

11 = 3² + 2²

22 = 4² + 3²

Based on this pattern, we can make a reasonable assumption that the next difference should be 5² + 4² = 41 + 16 = 57. Adding this difference to the last term of the sequence (41), we get the next term:

41 + 57 = 98

Therefore, the next term in the sequence is 98. None of the given options (60, 81, 90, 101) match the expected next term.

Hence, none of the given options accurately continue the pattern of the sequence. It's important to note that patterns in sequences can sometimes have multiple possible interpretations, and it's always essential to consider alternative patterns or extend the sequence further to confirm the pattern.

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Answer:

A

Step-by-step explanation:

Trust me it's correct.

You are solving for the system of equations.

Answer: The most typical symmetric histogram or dot plot has the highest vertical column in the center. This shape is often referred to as being a "normal curve" (or normal distribution). ... Skewed Right (positively skewed) - fewer data plots are found to the right of the graph (toward the larger numeric values).

Answer:

a = 2

Step-by-step explanation:

2a + 6 + 6a - 3 = 19

Next, combine like terms:

8a + 3 = 19

Subtract 3 from both sides:

8a = 16

Finally, divide both sides by 8:

a = 2

Therefore, a is equal to 2.

Answer:

60/2.5 = 24 cm

Step-by-step explanation:

if you are satisfied with the results then plz make me genius

Answer:

The answer is 24 inches.

Step-by-step explanation:

Given:

1 inch = 2.5 cm

or, 1 cm = 1/2.5 inch............... eqn (i)

Now,

Wideness of envelope = 60 cm

= 60 (1/2.5) inches [From eqn (i)]

= 60/2.5 inches

= 24 inches Ans

Answer:

65/100 = 13/20

Step-by-step explanation:

To change this decimal into a fraction, we can put it over 100 since the 5 is in the hundredths. We get 65/100. We can simplify this by dividing by 5. The final simplified answer is 13/20.

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We have proven that △ABD ≅ △CBD based on the given information and the SAS congruence criterion.

To prove that △ABD ≅ △CBD, we can use the SAS (Side-Angle-Side) congruence criterion.

Given:

∠BDA ≅ ∠BDC (Both are right angles)

D is the midpoint of AC¯¯¯¯¯

AB¯¯¯¯¯ ≅ BC¯¯¯¯¯

BD¯¯¯¯¯ bisects ∠B

Proof:

Since D is the midpoint of AC¯¯¯¯¯, we have AD ≅ CD by the definition of a midpoint.

AB¯¯¯¯¯ ≅ BC¯¯¯¯¯ (Given)

BD¯¯¯¯¯ is a common side for both triangles.

∠BDA ≅ ∠BDC (Given)

To apply the SAS congruence criterion, we need to show that one pair of corresponding sides and the included angle are congruent in both triangles.

AD ≅ CD (Side) - This is true as D is the midpoint of AC¯¯¯¯¯.

∠BDA ≅ ∠BDC (Included Angle) - Both are right angles.

By the SAS congruence criterion, we can conclude that △ABD ≅ △CBD.

Therefore, we have proven that △ABD ≅ △CBD based on the given information and the SAS congruence criterion.

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Answer:

188.5

Step-by-step explanation:

13 times 4.50 is 188.5 and theres 13,000

a.  The equation for the exponential distribution of waiting times f(x) = 0.4\(e^{(-0.4x)}\). b. The likelihood that a customer waits less than 2 minutes is 0.393 or 39.3%. c.  the probability of waiting between 2 and 4 minutes is 0.329 or 32.9%. d.  the probability of waiting more than 5 minutes is \(e^{(-2)}\) or approximately 0.135 or 13.5%.

a. The equation for the exponential distribution of waiting times is given by:

f(x) = λ\(e^{(-λx)}\)

where λ is the rate parameter. In this case, the average waiting time is 2.5 minutes, so we can use λ = 1/2.5 = 0.4. Thus, the equation becomes:

f(x) = 0.4\(e^{(-0.4x)}\)

To graph the equation, we can plot it on a coordinate system with the x-axis representing the waiting time in minutes and the y-axis representing the probability density. The mean waiting time is equal to 1/λ, which is 2.5 minutes in this case. We can locate this point on the graph by drawing a vertical line at x = 2.5 and finding the corresponding point on the y-axis, which will be the maximum point of the curve.

b. To find the likelihood that a customer waits less than 2 minutes to check out, we need to find the cumulative distribution function (CDF) of the waiting time. The CDF is given by:

F(x) = 1 - \(e^{(-λx)}\)

Substituting λ = 0.4 and x = 2, we get:

F(2) = 1 - \(e^{(-0.42*2)}\) = 0.393

Thus, the likelihood that a customer waits less than 2 minutes is 0.393 or 39.3%.

c. To find the probability of waiting between 2 and 4 minutes, we need to subtract the probabilities of waiting less than 2 minutes and waiting more than 4 minutes from 1. Using the CDF, we can find these probabilities as follows:

P(2 ≤ x ≤ 4) = F(4) - F(2)

= (1 - \(e^{(-0.44)}\)) - (1 - \(e^{(-0.42)}\))

= \(e^{(-0.8)}\) - \(e^{(-0.4)}\)

= 0.329

Thus, the probability of waiting between 2 and 4 minutes is 0.329 or 32.9%.

d. To find the probability of waiting more than 5 minutes to check out, we can use the CDF as follows:

P(x > 5) = 1 - F(5)

= 1 - (1 - \(e^{(-0.45*5)}\))

= \(e^{(-2)}\)

Thus, the probability of waiting more than 5 minutes is \(e^{(-2)}\) or approximately 0.135 or 13.5%.

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Answer:

17

Step-by-step explanation:

STUDY HARD GUYS I NEED HW HELP

Option (b) is the correct answer: Perpendicular segments.

Perpendicular rays, perpendicular segments, perpendicular lines, and parallel lines are important concepts in geometry that describe the relationship between lines and line segments.

1. Perpendicular Rays: Perpendicular rays are two rays that intersect at point and form a right angle (90 degrees) at the point of intersection. The rays extend indefinitely in opposite directions from the point of intersection.

2. Perpendicular Segments: Perpendicular segments are line segments that intersect at a right angle. They share a common endpoint but do not extend indefinitely like rays. The right angle is formed at the point of intersection.

3. Perpendicular Lines: Perpendicular lines are lines that intersect at a right angle. They continue indefinitely in opposite directions and form four right angles at the point of intersection. Perpendicular lines are often denoted by a symbol ⊥.

4. Parallel Lines: Parallel lines are lines that never intersect. They remain equidistant from each other at all points. Parallel lines have the same slope and do not converge or diverge. In Euclidean geometry, parallel lines are denoted by a double vertical line symbol (||).

Understanding these concepts is fundamental in geometry as they help define angles, shapes, and spatial relationships. The properties of perpendicular and parallel lines play a crucial role in various geometric theorems and applications.

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Answer:

associative, distributive, commutative

Step-by-step explanation:

Commutative is something just flipped around so the 3rd equation would be commutative. Associative is something with the same numbers but asked in a different way so 1st would be associative. Distributive is breaking the equation down and apart to make it easier to complete so the 2nd would be distributive.

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The algebraic expression "difference of 4 and a number" where the number is letter x is represented as 4 - x.

Algebra is an elementary branch of mathematics that deals with the numbers and the basic mathematics operations of addition, subtraction, division and multiplication. Algebraic expression involves arithmetic where the use of unknown quantities along with numbers.

From the question, we have the mathematical statement "difference of 4 and a number" and the number is "a number" is represented with the letter x.

the word difference in mathematics implies Subtraction (-)

Therefore, the mathematical statement "difference of 4 and a number" is represented as 4 - x.

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Answer:

Grogg's dad is 22

Step-by-step explanation:

Let D = dad's current age

Let g = Grogg's current age

6(d - 7) = g - 7 → 6d - 42 = g - 7 → 6d -35 = g

4(d - 3) = g - 3 → 4d -12 = g - 3 → 4d -9 = g

Set the two equations equal to each other and solve for d

6d - 35 = 4d - 9  Subtract 4d from both sides

2d -35 = -9  Add 35 to both sides

2d = 44  Divide both sides by 2

d = 22

Helping in the name of Jesus.

Answer:

Step-by-step explanation:

d = current dad age

g = current grogg age

d-7 = 6(g-7)

d-3 = 4(g-3)

Let's solve the first equation first:

Add 7 to both sides: d - 7 +7 = 6g - 42 + 7 so d = 6g - 35

Substitude d = 6g - 35 for d in d - 3 = 4g - 12

(6g-35)-3 = 4g-12 = 6g-38 = 4g-12

Subtract 4g from both sides: 2g - 38 = -12

Add 38 to both sides: 2g = 26

Easy: g = 13

And now substitude g in for any equations.

d-3 = 52-12

d = 43

The maximum budget for equipment and costumes is \(4.85x - $450\).

Let us assume the number of seats available is "x".

Let us represent cost of equipment and costumes with C

The total revenue from ticket sales would be 4.85x.

From 4.85x, the committee wants to have $450 remaining, so we can set up an equation.

The equation will be \(4.85x - 450 = C\)

So, to get maximum budget for equipment and costumes, we need to maximize the cost of equipment and costumes. This occurs when the cost is equal to the left side of the equation above.

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Answer:

d)

Step-by-step explanation:

İnşallah tutar iyi dersler Gold bye

Answer:

cevap 108 tamam sorun harika bir soru