How do the earths layers compare to other planets in the solar system?

The correct answer is c. friction loss develops much slower than change in velocity.

The second principle of friction loss states that as the velocity of a fluid increases, the friction loss within the system increases, but at a much slower rate compared to the change in velocity. In other words, the increase in friction loss is not directly proportional to the change in velocity. This principle is based on the fact that as the fluid moves faster, the pressure drop due to friction along the pipe walls increases, resulting in some energy loss. However, this energy loss is not as significant as the increase in velocity itself. Therefore, the friction loss develops much slower compared to the change in velocity.

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Answer:

an open circuit (A battery, bulb, wire,switch)

Explanation:

the battery supplies the power the wire carries the current from the battery to the bulb but the circuit is not completed if the switch is not connected (Switch )

Orchids have six petals arranged in a 3-2-1 arrangement.

Orchids have three sepals (one dorsal and two lateral) and three petals, but usually the middle petal, the labial, is distinct from the other petals. In most orchids, the flower rotates 180° during growth, so the lip is the lowest of the petals and points upwards. There are three sepals that are the outer petals. This is what you see when you look at an unopened bud. He also has three petals, but one of his orchid petals is specialized for the lip. Orchids always have three petals. Two are "normal" and the third is a highly specialized structure called a lip.

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Answer:

1. speed is the distance travelled by an object in unit time

2. velocity is the displacement of a body in in unit time

3. formula of speed =total distance (d)÷ total elapsed time

We have the next definitions

Distance It is all the way traveled by a mobile or moving body.

Displacement: It is a straight line distance from an initial position to a final position. This distance has direction therefore it is a vector

Therefore the statement that is not true is

Its displacement can be larger than its distance.

ANSWER

ETo determine the acceleration of the crate, we need to resolve the applied force into its horizontal and vertical components. The horizontal component of the force will contribute to the acceleration, while the vertical component will not affect the motion of the crate on a frictionless surface.
Given:
Mass of the crate (m) = 40 kg
Magnitude of the applied force (F) = 140 N
Angle of the force with the horizontal (θ) = 30°

To find the horizontal component of the force (F_horizontal), we can use trigonometry:
F_horizontal = F * cos(θ)
F_horizontal = 140 N * cos(30°)
F_horizontal = 140 N * √3/2
F_horizontal = 140 N * 0.866
F_horizontal ≈ 121.24 N
Since there is no friction or vertical forces acting on the crate, the horizontal component of the applied force will be responsible for the acceleration.
Using Newton's second law of motion, which states that the force applied to an object is equal to the mass of the object multiplied by its acceleration (F = m * a), we can calculate the acceleration (a).
a = F_horizontal / m
a = 121.24 N / 40 kg
a ≈ 3.03 m/s²
Therefore, the acceleration of the crate is approximately 3.03 m/s².

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Answer:

3 seconds

Explanation:

From the question above,

we can apply the first equation of motion which is,

a = (v-u)/t.................... Equation 1

Where a = acceleration. v = final velocity, u = initial velocity, t = time.

make t the subject of the equation

t = (v-u)/a.............. Equation 2

Given: a = -3 m/s²(decelerating), u = 9 m/s, v = 0 m/s (to stop)

substitute these values into equation 2

t = (0-9)/-3

t = -9/-3

t = 3 seconds

The correct terms that fills the box are;

(i) The incident ray

(ii) The normal

(iii) The reflected ray

(iv) The angle of incident

(v) The reflected angle

The terms of the ray diagram is illustrated as follows;

(i) This arrow indicates the incident ray, which is known as the incoming ray.

(ii) This arrow indicates the normal, a perpendicular line to the plane of incidence.

(iii) This arrow indicates the reflected ray; the out going arrow.

(iv) This the angle of incident or incident angle.

(v) This is the reflected angle or angle of reflection.

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Explanation:

The Sun is the center of the solar system. What is the Sun? Earth's Sun may seem different to us, but it is a star like all the other stars located outside the solar system.

A electric ring with a impedance of 6 ohms needs 9 volts to generate a power of 1.5 amps.

The electromotive force is measured in units known as volts, which express the electric strain or the charge difference between two sites. Voltage is represented by the writings V or E. The electromotive force between two places is measured in volts.

Ohm's Law can be used to fix this matter. As according Ohm's Law, the voltage (V) equals the current (I) times the resistance (R):

V = I * R

Inputting the values provided output:

V = 1.5 amps * 6 ohms

V = 9 volts

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False. A spring tide is characterized by a large tidal change, while a neap tide is characterized by a small tidal change.

Spring and neap tides are the result of the combined gravitational forces of the Moon and the Sun on the Earth's oceans. Spring tides occur twice a month, during the full moon and the new moon, when the gravitational pull of the Moon and the Sun are aligned. During spring tides, the high tides are higher and the low tides are lower, resulting in a larger tidal range. On the other hand, neap tides occur twice a month, during the first and third quarters of the Moon, when the gravitational pull of the Moon and the Sun are at right angles to each other. During neap tides, the high tides are lower and the low tides are higher, resulting in a smaller tidal range. Therefore, the statement is false. A spring tide is characterized by a larger tidal change, while a neap tide is characterized by a smaller tidal change.

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The focal length of an objective lens is directly related to its magnification power. The shorter the focal length, the higher the magnification. In this case, Lens D has a focal length of 17mm, which is the shortest among the four lenses provided. Therefore, Lens D would provide the highest magnification among the four lenses.

However, it is important to note that magnification alone is not the only factor to consider when choosing an objective lens. Other factors such as the numerical aperture, working distance, and resolution should also be taken into account. It is important to choose the right combination of factors for the specific application at hand.

In summary, Lens D would provide the highest magnification among the four lenses provided due to its short focal length of 17mm. But it is important to consider other factors in addition to magnification when selecting an objective lens for a specific application.

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A battery is connected to two capacitors shown below. the capacitors have air between the plates. The total charge coming out of the power supply: 8.16 × 10⁻⁹ C.

Capacitor 1 has a plate area of 1.5 cm² and an electric field between its plates of 2000 V/m and Capacitor 2 has a plate area of 0.7 cm² and an electric field of 1500 V/m.

Therefore, the total charge coming out of the power supply can be calculated by using the following formula:

Q = C × V,

where Q is the total charge coming out of the power supply.

C is the capacitance of the capacitors.

V is the voltage of the capacitors.

The capacitance of a parallel plate capacitor can be calculated by using the following formula:

C = εA/d,

where C is the capacitance of the capacitor.

ε is the permittivity of air.

A is the area of the capacitor plates.

d is the distance between the plates of the capacitor.

let's calculate the capacitance of the capacitors:

For capacitor 1:

ε = ε₀ = 8.85 × 10⁻¹² F/m²

A = 1.5 cm² = 1.5 × 10⁻⁴ m²d = ?

E = 2000 V/mQ = CV

C = εA/dC₁ = ε₀A/d

C₁ = ε₀A/E₁

C₁ = ε₀A/(V/d)

C₁ = (ε₀A/d) × V⁻¹

C₁ = ε₀A₁/E₁

C₁ = (8.85 × 10⁻¹² F/m²)(1.5 × 10⁻⁴ m²)/(2000 V/m)

C₁ = 6.63 × 10⁻¹⁰ F

For capacitor 2:

ε = ε₀ = 8.85 × 10⁻¹² F/m²

A = 0.7 cm² = 0.7 × 10⁻⁴ m²

d = E = 1500 V/m

Q = CV

C = εA/d

C₂ = ε₀A/d

C₂ = ε₀A/E₂

C₂ = (8.85 × 10⁻¹² F/m²)(0.7 × 10⁻⁴ m²)/(1500 V/m)

C₂ = 3.95 × 10⁻¹¹ F

Total charge coming out of the power supply: Q = C₁V + C₂VQ = (6.63 × 10⁻¹⁰ F)(12 V) + (3.95 × 10⁻¹¹ F)(12 V)Q = 8.16 × 10⁻⁹ C. Therefore, the total charge coming out of the power supply is 8.16 × 10⁻⁹ C.

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Answer:

Explanation:

Measurement of body temperature is an example of a variable that uses a continuous scale of measurement.

Continuous variables are those that can take on any value within a certain range, with no gaps or jumps. In the case of body temperature, it can be measured with a thermometer and can take on any value within a certain range, such as between 95 and 105 degrees Fahrenheit or between 35 and 40 degrees Celsius.

Continuous variables are typically measured using interval or ratio scales of measurement. An interval scale is one where equal intervals on the scale represent equal differences in the underlying variable, but there is no true zero point. In the case of body temperature, the Celsius and Fahrenheit scales are examples of interval scales. A temperature difference of one degree on these scales represents the same temperature difference anywhere on the scale, but a temperature of zero degrees does not represent the absence of temperature.

A ratio scale, on the other hand, has a true zero point, meaning that zero represents the absence of the variable being measured. Examples of ratio scales include measurements such as weight or height. While body temperature is not measured on a true ratio scale, it can be transformed into a ratio scale by using the Kelvin temperature scale, where absolute zero represents the complete absence of temperature.

Answer:

S = V0 t + 1/2 a t^2      net distance traveled

5.2 = a/2 * 25

a = 10.4 / 25 = ,416 m / s^2

F = m * a

m = F / a = 24 / .416 = 57.7 N

The strength of an electromagnet is directly proportional to the amount of current that passes through it. When the amount of current traveling through an electromagnet is increased, the strength of the electromagnetic field will increase.

The correct answer is the electromagnetic field will become stronger.

An electromagnet is a type of magnet in which the magnetic field is generated by an electric current. The magnetic field is produced when an electric current flows through a conductor. The strength of an electromagnet is directly proportional to the amount of current that passes through it, as well as the number of turns in the coil of the magnet wire, and the strength of the core material. Electromagnets are used in a variety of applications, including electric motors, relays, MRI machines, and particle accelerators. By changing the amount of current that passes through the electromagnet, it is possible to control the strength of the magnetic field that it produces. This is an important feature of electromagnets, as it allows them to be used in a wide range of applications.

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(b) negative charge

This is the answer

The magnitude of the gravitational force on one proton due to the other proton can be calculated using the equation for gravitational force: F = (G * m1 * m2) / r^2

Where F is the magnitude of the gravitational force, G is the gravitational constant (approximately 6.67430 x 10^-11 N*m^2/kg^2), m1 and m2 are the masses of the protons, and r is the distance between the protons.
The mass of a proton is approximately 1.67 x 10^-27 kg. Assuming the two protons are of equal mass, we can substitute this value into the equation:
F = (6.67430 x 10^-11 N*m^2/kg^2 * 1.67 x 10^-27 kg * 1.67 x 10^-27 kg) / r^2
Simplifying the equation:
F = (2.7933741 x 10^-54 N*m^2) / r^2
To calculate the magnitude of the gravitational force, we need the value of r, the distance between the protons.

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The magnitude of the gravitational field on the planet's surface is approximately 45.88 N/kg.

The magnitude of the gravitational field, g, on the planet's surface can be calculated using the equation:

g = G * (m / r^2)

where G is the gravitational constant (approximately 6.67430 x 10^-11 N m^2/kg^2), m is the mass of the planet, and r is the radius of the planet.

In this case, the mass of the planet is given as 3.10 x 10^24 kg, and the radius is given as 2.00 x 10^6 m.

Substituting these values into the equation, we get:

g = (6.67430 x 10^-11 N m^2/kg^2) * (3.10 x 10^24 kg) / (2.00 x 10^6 m)^2

Simplifying this calculation, we have:

g = 4.588 x 10^1 N/kg

Therefore, the magnitude of the gravitational field on the planet's surface is approximately 45.88 N/kg.

To understand the meaning of this value, we can say that for every kilogram of mass on the planet's surface, there is a gravitational force of 45.88 Newtons acting on it.

This force pulls objects towards the center of the planet. The larger the gravitational field, the stronger the force of gravity experienced.

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Answer:

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

\(a = \frac{f}{m} \\ \)

f is the force

m is the mass

From the question

f = 6000 N

m = 500 kg

We have

\(a = \frac{6000}{500} = \frac{60}{5} = 12 \\ \)

We have the final answer as

Hope this helps you

What does the shift in the period's relationship to its eccentricity reveal about the period's reliance on the eccentricity The duration is independent of eccentricity.

How is an ellipse's eccentricity determined?

Weirdness e = c/a if the focus's distance from the ellipse's center is "c" and the tip of the ellipse's distance from the central is "a." E = 1 b 2 a 2 is another formula to get the eccentricity of an ellipse. 

What does geometric eccentricity mean?

The term "eccentricity" is defined in terms of the fixed-point known as focus as well as the fixed-line known as the perpendicular line in the plane. The definition of eccentricity in geometry, the eccentricity formula, and the eccentric of several conic sections, including parabola, ellipse, and hyperbola, will all be covered in detail in this article along with worked-out examples.

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The train covers a distance of 100 meters in the given time.

To find the distance covered by the train in the given time, we can use the equations of motion.

S = ut + (1/2)at²

The equation S = ut + (1/2)at² is derived from the basic equations of motion. The first term (ut) represents the distance covered in the initial velocity u multiplied by time t. The second term (1/2)at² represents the distance covered due to the acceleration a during time t.

The initial velocity (u) of the train is 10 m/s, and the acceleration (a) is 4 m/s². We are given that this acceleration is attained after 5 seconds, so the time (t) is also 5 seconds. We need to find the distance covered (S).

Substituting the given values:

S = (10 m/s)(5 s) + (1/2)(4 m/s²)(5 s)²

S = 50 m + (1/2)(4 m/s²)(25 s²)

S = 50 m + 50 m

S = 100 m

It's important to note that the given problem assumes a constant acceleration throughout the entire time interval.

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Answer:

4 kg

Explanation:

because when you go the moon you lose 6 times your weight because of the gravitational pull

Answer:

16.3333333 newtons

Explanation:

on earth it would 98 newtons

Answer:

gravity...................

Answer:

Hope it help you