How do you calculate the resultant velocity of the object in this image?

How Do You Calculate The Resultant Velocity Of The Object In This Image?

Answers

Answer 1

Answer:

the resultant velocity is Zero

Explanation:

by the rule of adding and subtracting factors, we know that; when the force acting on an object is from east & north we add and with forces acting from South & west we minus.

Therefore:

1) List the forces down:

the 100m/s acting west is (-) while

the other 100m/s is acting in easterly direction

so it is (+)

2) Add the forces:

-100+100=0

therefore the answer is 0m/s for the the resultant velocity

hope I'm right


Related Questions

Why is the speed of different sounds in a single medium remain the same though wavelength is different?

Answers

Answer:

I think it's because the refractive index of that medium is constant

Describe how to determine wether or not an atom is boron

Answers

Answer:

has 5 protons and the atomic numb is 5

Explanation:

atomic number = protons number

they're equal

Answer:An atom consists of a central nucleus that is surrounded by one or more negatively charged electrons. The nucleus is positively charged and contains one or more relatively heavy particles known as protons and neutrons.

Explanation:

Consider that each tick mark represents 1 mile on the vector grid, use the Gizmo to simulate the following scenario: Imagine that a hiker walked 6 mi SE and then 4 mi N. Find the sum of the vectors. Which of the following best describes the general direction that the blue line points?
a) south
b) west
c) east
d) cannot be determined from this information

Answers

Answer:

The best description of the general direction that the blue line points is East direction

Answer:

c. east

Explanation:

If it takes 35J to lift up an object to some height, then how much gravitational potential energy will that object have?

Answers

35j because if it takes so much to lift it’s that much pullin down

45. What is the wovelength of a 30. Hertz periodic
wave moving ol 60. meters per second?

a. 0.50m
c. m
b 20m
d 1800 m

Answers

The wavelength is 2m.

Hence, Option c) 2m is the correct answer

Given that;

Frequency; \(f = 30Hz\)

Speed; \(v = 60m/s\)

Wavelength; \(\lambda =\ ?\)

using the expression for the relations between wavelength, frequency and speed of wave:

\(\lambda = \frac{v}{f}\)

Where \(\lambda\) is wavelength, f is frequency and v is speed.

We substitute our given values into the equation

\(\lambda = \frac{60m/s}{30Hz}\\\\\lambda = \frac{60m/s}{30s^{-1}}\\\\\lambda = 2m\)

The wavelength is 2m.

Hence, Option c) 2m is the correct answer.

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The frequency of the moving wave is 30 Hz and if it is moving at the speed of 60 m/s then the wavelength will be equal to 2 m.

What is Wavelength?

The distance between two identical locations (adjacent crests) in successive cycles is known as the wavelength, and it is used to describe waveform signals that are transmitted over wires or into space. Typically, in wireless systems, this length is specified in meters (m), centimeters (cm), or millimeters (mm).

The wavelength is more frequently described in nanometers (nm), which are units of 10⁻⁹ m, or angstroms, which are units of 10⁻¹⁰ m, for infrared (IR), visible light (UV), and gamma radiation.

As per the provided given data in the question,

Frequency, f = 30 Hz

Speed, v = 60 m/s

Then, the wavelength of the moving wave will be,

λ = v/f

= 60/30

λ = 2 meters.

Therefore, the wavelength will be 2 meters.

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A student pushed a box 27.0 m across a smooth, horizontal floor using a constant force of 113 N. If the force was applied for 9.00 s, how much power was developed, to the nearest watt? Round your answer to the nearest whole number.

Answers

339 Watts

Nm/s=Watts.
113N * 27m / 9s
339 Watts

The power is a dependent parameter on work done for a given interval of time. The magnitude of power developed due to the applied force is 339 W.

What is power?

The rate of doing work is known as Power. Mathematically, the power is equal to the ratio of work and time interval.

Given data -

The distance covered by the box is, d = 27.0 m.

The magnitude of the constant force is, F = 113 N.

The time interval for the application of force is, t = 9.00 s.

The expression for the power developed is given as,

P = W/t

here, W is the work done and its value is, W = F × d.

Solving as,

P = F × d/t

Solving as,

P = 113 × 27.0/9.0

P = 339 W

Thus, we can conclude that the magnitude of power developed due to the applied force is 339 W.

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three forces act on an object. two of the forces are at an angle of to each other and have magnitudes 25 n and 12 n. the third is perpendicular to the plane of these two forces and has magnitude 4 n. calculate the magnitude of the force that would exactly counterbalance these three forces.

Answers

To calculate the magnitude of the force that would exactly counterbalance these three forces, we need to use the principle of vector addition. This involves combining the three forces vectorially to find the net force acting on the object.

First, we need to find the resultant of the two forces that are at an angle of 90 degrees to each other. This can be done using the Pythagorean theorem:

Resultant = √(25² + 12²) = √(625 + 144) = √769 = 27.74 N

Next, we need to find the net force acting on the object by adding the third force (4 N) to the resultant of the first two forces (27.74 N).

Net force = 4 N + 27.74 N = 31.74 N

Therefore, the magnitude of the force that would exactly counterbalance these three forces is 31.74 N.

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Why aren't other objects, like your pencil, drawn to you?

Answers

Let's say the force of gravity betwen you and the Earth (your "weight") is 100 pounds.

Then the force of gravity between you and a 10-pound bowling ball (sitting on the table 3-ft away from you) is about 0.000 000 049 of an ounce !

It's there, but it's too small for you to feel.

And it's not strong enough for the pencil or the bowling ball to jump up off the table, fly through the air, and stick to you.

a car moving at a steady 10 m/s on a level highway encounters a depression that has a circular cross-section with a radius of 30 m. the car maintains its speed as it drives through the depression. what is the normal force exerted by the seat of the car on a 60 kg passenger when the car is at the bottom of the depression?

Answers

To calculate the normal force exerted by the seat of the car on the passenger when the car is at the bottom of the depression, we need to consider the forces acting on the passenger.

At the bottom of the depression, the passenger experiences an inward net force directed towards the center of the circular path. This force is provided by the normal force exerted by the seat. To determine the normal force, we need to consider the centripetal force acting on the passenger.

The centripetal force can be calculated using the formula:

F_c = m * a_c

where F_c is the centripetal force, m is the mass of the passenger, and a_c is the centripetal acceleration.

The centripetal acceleration is given by:

a_c = v² / r

where v is the velocity of the car and r is the radius of the circular depression.

Given:

Velocity of the car (v) = 10 m/s

Radius of the depression (r) = 30 m

Mass of the passenger (m) = 60 kg

First, we calculate the centripetal acceleration:

a_c = (10 m/s)² / 30 m = 100 m²/s² / 30 m = 10/3 m/s²

Now, we can calculate the centripetal force:

F_c = (60 kg) * (10/3 m/s²) = 200 N

Since the normal force exerted by the seat is equal to the centripetal force, the normal force is 200 N. Therefore, the normal force exerted by the seat on the 60 kg passenger at the bottom of the depression is 200 N.

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initially, a pendulum swings through an arc of 3 feet. on each successive swing, the length of the arc is 0.7 of the previous arc. after 15 swings, what total length in feet will the pendulum have swung?

Answers

The total swing of the pendulum after 15 swings will be 9.951 feet.

For the 1st swing the length was = 3 feet

Now with each successive swing the distance becomes 0.7 times that of the previous swing distance.

So, the distance of the 2nd swing will be = 0.7 x 3 = (0.7)¹ x 3

Similarly,

the distance of the 3rd swing will be = (0.7)² x 3

So , the distance pattern for the 15th swing will be = (0.7)¹⁴ x 3

In order to calculate the total swing distance we add the swing distance of pendulum from 1st swing to 15th swing

Therefore ,

Total swing distance = 3 (   (0.7)⁰ + (0.7)¹  + _ _ _ _ _ _+  (0.7)¹⁴ )

Using the formula for Geometric progression sum , we have

Total swing distance = 3 x 3.317 =9.951 feet

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What is a situation where you can observe both kinetic and potential energy, shifting from one form to the other?

Answers

Answer:

when an object kept at some height and having some mass then ,when it falls down then shifting of energy takes place

An electron accelerates from 0 to 10 Ã 104 m/s in an electric field. Through what potential difference did the electron travel? The mass of an electron is 9. 11 Ã 10â31 kg, and its charge is â1. 60 Ã 10â19 C

Answers

According to the claim made, the electron moved across a potential difference of 2.84 * 10⁻² V.

Explain what the electric field is.

Each spot in space has an electric field associated with it when there is charge current in any form. The value of E, often known as the electric field strength, electric field intensity, or just the electric field, expresses the direction and intensity of the electromagnetic field.

Briefing:

Given;

Velocity, v = 10 * 10⁴ m/s = 10⁵ m/s

Potential difference, V = ?

Mass of electron = 9.11 * 10⁻³¹ kg

Charge of electron, q = 1.60 * 10⁻¹⁹C

The KE of an electron is the amount of energy in an electric field.

Thus, qV = 1/2mv²

Therefore, V = mv²/2q

Putting Values,

V = 9.11 * 10⁻³¹ * 10⁵ * 10⁵/2 * 1.6 * 10⁻¹⁹

= 9.11 * 10⁻²¹/3.2 * 10⁻¹⁹

V = 2.84 * 10⁻²

Thus, Potential difference is 2.84 * 10⁻² V

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Calculate the orbital period of a satellite circling the Earth at an altitude of 3500 km. Answer to the nearest minute. Show your work.​

Answers

The orbital period of the satellite circling the Earth at an altitude of 3500 km is 163 minutes

How do i determine the orbital period?

The orbital period for the satellite circling the Earth at an altitude of 3500 km can be obtained as follow:

Altitude = 3500 kmRadius of earth = 6400 KmSemi-major axis (a) = Radius + Altitude = 6400 + 3500 = 9900 Km = 9900 × 1000 = 9900000 mGravitational constant (G) = 6.67×10¯¹¹ Nm²/Kg²Mass of earth (M) = 5.987×10²⁴ KgOrbital period (T) = ?

T² = (4π² / GM) × a³

T² = [(4 × 3.14²) / (6.67×10¯¹¹ × 5.987×10²⁴)] × 9900000³

Take the square root of both sides

T = √[((4 × 3.14²) / (6.67×10¯¹¹ × 5.987×10²⁴)) × 9900000³]

T = 9789.15 s

Divide by 60 to express in minutes

T = 9789.15 / 60

T = 163 minutes

Thus, we can conclude that the orbital period of the satellite is 163 minutes

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help please i need to get this grade up​

help please i need to get this grade up

Answers

the ducks speed is 10m per second
60 divided by 6 is 10, so the answer you are looking for is 10 m.
Hope this helps you!

a frictionless pulley has the shape of a uniform solid disk of mass 5.00 kg and radius 11.0 cm . a 2.50 kg stone is attached to a very light wire that is wrapped around the rim of the pulley(figure 1), and the stone is released from rest. as it falls down, the wire unwinds without stretching or slipping, causing the pulley to rotate. how far must the stone fall so that the pulley has 5.40 j of kinetic energy?

Answers

Hence, for the pulley to have a kinetic energy of 5.40 J, the stone must descend a distance of around 0.56 metres.

The frictionless force of gravity acting on the stone is multiplied by the distance it falls in this instance to determine the work done on the system (stone + pulley): W = ΔK

where K is the change in kinetic energy of the item and W is the work done on it.

Fd + mgd = W

where m is the stone's mass, g is gravity's acceleration, and d is the stone's fall distance.

The system's change in kinetic energy equals the pulley's kinetic energy:

ΔK = (1/2)Iω^2

I = (1/2)MR^2

I = (1/2)(5.00 kg)(0.11 m)^2 = 0.03025 kg·m^2

d = 2πR

d = 2π(0.11 m) = 0.69 m

mgd = (1/2)Iω^2

(2.50 kg)(9.81)(0.69 m) = (1/2)(0.03025 kg·m^2)ω^2

ω = 5.00 rad/s

= (1/2)Iω^2 = 5.40 J

= (1/2)(0.03025 kg·m^2)(5.00 rad/s)^2 = 5.40 J

h = ΔPE/mg = (1/2)mv^2/mg = v^2/2g = (Iω^2/2mg)^2

h = (0.03025)(5.00 rad/s)^2 / (2)(2.50 kg)(9.81) ≈ 0.56 m

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A truck is driven at constant speed down the street.Do a pie chart for each position of the ball shown.

Answers

129 speed street nexus mark

An object is known to have balanced forces on it. Which of the following would be a true statement?

Answers

If an object has a balanced force on it, there is a possibility that the object may be in a position i.e. there is no change in speed and direction of the body.

If the forces acting on an object is balanced, it means that the net force acting on the body is zero.

According to Newton's law of motion, an object will continue in a state of motion in a straight line unless acted upon by an external force.

This external force might be a balanced or unbalanced force. Hence if an object has a balanced force on it, there is a possibility that the object may be in a position i.e. there is no change in speed and direction of the body.

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which statements accurately describe mechanical waves​

Answers

Answer:

Explanation:

so a mechanical wave transfers energy through a medium but unlike other waves that move through very long distances

the distance of the mechanical wave is different

Sandra is riding a water slide at her favorite water park. At the top of the slide,
she has 5,000 J of gravitational potential energy. After a few seconds, she has
1,928 J of gravitational potential energy. What is her kinetic energy at this point,
in J?

Answers

Answer:

3072J

Explanation:

At all points through her slide, it is important to reiterate that energy is always conserved.

Kinetic energy is the energy due to the motion of a body.

Potential energy is the energy due to the position of a body.

Based on the law of conservation of energy, energy is neither created nor destroyed but simply transformed from one form to another.

 So;

At all points:

           Total energy  = Potential energy + Kinetic energy

Since the initial energy  = 5000J which is the potential energy

This is the total energy within the system as the kinetic energy at this point is 0;

 After a few seconds, the potential energy is 1928J;

  Kinetic energy  = Total energy  - potential energy  = 5000J  - 1928J

  Kinetic energy  = 3072J

a 65 kg gymnast begins to prepare for his dismount from the high bar by increasing his angular velocity by a factor of 3. by what factor does the centripetal force change? (you may assume that r does not change)

Answers

The Centripetal force changes by a factor of 9.

A body is forced to follow a curved path by a centripetal force. It always moves in a direction that is the opposite of the body's motion and in the direction of the fixed point of the path's immediate center of curvature. "A force by which bodies are dragged or driven, or in any other manner tend, towards a point as to a center," was how Isaac Newton defined it. The centripetal force that causes astronomical orbits in Newtonian physics is provided by gravity.

The scenario in which a body moves uniformly fast along a circular path is one frequent example of centripetal force. In addition to moving along the radius, the centripetal force is also directed at right angles to the motion.

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how to increase current​

Answers

Answer:

So to increase current of the circuit what you can do is :

1. Use conductor of low resistivity, ¶.

2. Use conductor of small length.

3. Use thick wire.

4. Decrease the temperature of the circuit.

5. If operating temprature is high than use semiconductor, because it have negative temprature coefficient.

6. Minimise the circuit losses.

Answer:

by making dam into near the water resource

Terry is out with friends and sees a man who appears to be struggling with mental illness. He is ranting and waving his arms around in a very antagonistic way. He is getting more agitated and pulls out a knife and starts jabbing it like he is attacking someone. Should Terry call 9-1-1?

Answers

Yes, Terry should call 9-1-1 immediately because the man is mentally ill.

What should Terry do?

Based on the statement, if Terry is out with friends and sees a man who appears to be struggling with mental illness. And the man is ranting and waving his arms around in a very antagonistic way. He is also getting more agitated and pulls out a knife and starts jabbing it like he is attacking someone.

The man's behavior is dangerous and poses a potential threat to himself and others around him. The fact that he has pulled out a knife and is waving it in a threatening manner indicates that he may be a danger to himself or others.

In this situation, it is important to prioritize everyone's safety and call for emergency services to intervene and help the man.

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how do the energies of a flowing fluid and a fluid at rest compare? name the specific forms of energy associated with each case. (3 points)

Answers

The other response gave a description of the kinetic energy from flowing liquids. However, the energy or liquid at rest is not empty. the same concept as the potential energy underlying solids. Both can be converted into kinetic energy.

What precisely is kinetic energy?

An object's kinetic energy is the power it has as a result of motion. It is described as the effort required to move a mass-based body from rest to the indicated velocity. The body holds onto the kinetic energy it acquired during its acceleration, unless its speed changes.

Who made the discovery of kinetic energy?

The idea of kinetic energy was first proposed in 1849 by William Thompson, later known as Lord Kelvin. We now relate the idea of an object's kinetic energy with the quantity of one half of its mass multiplied by its velocity squared.

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A power station that is being started up for the first time generates 6120 MWh of energy over a 10 hour period. (i) If the rated power at full capacity is 660 MW, calculate how long it takes the power station to reach its full power output. (You may assume a constant increase in power from zero to full power) (ii) State what type of power station can be started up fastest and explain why the start-up times for other types of power station are slower. Explain briefly, how this is relevant to optimising the usage of windfarms. c) What is the Bremsstrahlung effect and how can it be avoided in shielding design? d) Sketch the electromagnetic field output from an antenna, describing in detail the two main regions in the output field.

Answers

(i)Therefore, it takes approximately 9.27 hours to reach its full power output.(ii)It is necessary to have quick-start power sources, this helps maintain a stable and reliable electricity supply even when wind speeds fluctuate.(c)The Bremsstrahlung effect needs to be considered to ensure proper radiation protection.(d) The near-field region is characterized by strong electric and magnetic fields while the far-field region represents the radiation zone.

(i) To calculate the time it takes for the power station to reach its full power output, we can use the formula:

Energy = Power × Time

Given that the power station generates 6120 MWh of energy over a 10-hour period and the rated power at full capacity is 660 MW, we can rearrange the formula to solve for time:

Time = Energy ÷ Power

Converting the energy to watt-hours (Wh):

Energy = 6120 MWh × 1,000,000 Wh/MWh = 6,120,000,000 Wh

Converting the power to watt-hours (Wh):

Power = 660 MW × 1,000,000 Wh/MW = 660,000,000 Wh

Now we can calculate the time:

Time = 6,120,000,000 Wh ÷ 660,000,000 Wh ≈ 9.27 hours

Therefore, it takes approximately 9.27 hours (or 9 hours and 16 minutes) for the power station to reach its full power output.

(ii) The type of power station that can be started up fastest is a gas-fired power station. Gas-fired power stations can reach full power output relatively quickly because they use natural gas combustion to produce energy.

In contrast, other types of power stations, such as coal-fired or nuclear power stations, have longer start-up times. Coal-fired power stations require time to heat up the boiler and generate steam, while nuclear power stations need to go through a complex series of procedures to ensure safe and controlled nuclear reactions.

This is relevant to optimizing the usage of windfarms because wind power is intermittent and dependent on the availability of wind. This helps maintain a stable and reliable electricity supply even when wind speeds fluctuate.

(c) The Bremsstrahlung effect is a phenomenon that occurs when charged particles, such as electrons, are decelerated or deflected by the electric fields of atomic nuclei or other charged particles. As a result, they emit electromagnetic radiation in the form of X-rays or gamma rays.

In shielding design, the Bremsstrahlung effect needs to be considered to ensure proper radiation protection. These materials effectively absorb and attenuate the emitted X-rays and gamma rays, reducing the exposure of individuals to harmful radiation.

(d) The electromagnetic field output from an antenna can be represented by two main regions:

Near-field region: This region is closest to the antenna and is also known as the reactive near-field. It extends from the antenna's surface up to a distance typically equal to one wavelength. In the near-field region, the electromagnetic field is characterized by strong electric and magnetic field components.

Far-field region: Also known as the radiating or the Fraunhofer region, this region extends beyond the near-field region.The electric and magnetic fields are perpendicular to each other and to the direction of propagation.  The far-field region is further divided into the "Fresnel region," which is closer to the antenna and has some characteristics of the near field, and the "Fraunhofer region," which is farther away and exhibits the properties of the far-field.

The transition between the near-field and the far-field regions is gradual and depends on the antenna's size and operating frequency. The size of the antenna and the distance from it determine the boundary between these regions.

In summary, the near-field region is characterized by strong electric and magnetic fields, while the far-field region represents the radiation zone where the energy is radiated away as electromagnetic waves.

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calculate the weight of a 4.3 kg bunny WITH PROOF/WORK

Answers

Answer:

can you be more specific? The answer is in the question. The bunny weighs 4.3 kg lol.

Explanation:

If you're looking for kg to lbs, then 4.3 kg is about 9.4lbs

Are three coefficients of expansion alpha bita and gamma universal constant?​

Answers

Answer:

As the temperature increases, the volume of the material also increases. This is known as thermal expansion. It can also be explained as the fractional change in the length or volume per unit change in the temperature.

The relation between alpha, beta, and gamma is given in the form of a ratio and the ratio is 1:2:3 and can be expressed as:

alpha=fracbeta2=fracgamma3

Following is the relation between the three:

L = L (1 + α.ΔT)

Where, α is the coefficient of linear expansion  

A = A (1 + β.ΔT)

Where, β is the coefficient of aerial expansion

V = V (1 + γ.ΔT)

Where, γ is the coefficient of cubical expansion  

V = V + γV.ΔT

V = V (1 + γ.ΔT)  

L3 = L3 (1 + α.ΔT)3

L3 = L3 (1 + 3α.ΔT + 3α2.ΔT2 + α3.ΔT3)

L3 = L3 (1 + 3α.ΔT)

Alpha, beta, and gamma are related to one another in the form of a ratio, and that ratio is 1:2:3, and yes they are universal constants.

What is expansion?

A substance's volume expands while its mass stays constant. Heating is typically the cause of expansion. When a substance is heated, the molecular bonds separating its particles weaken, the particles move more quickly, and the substance expands as a result.

Determine the relation as shown below,

L = L (1 + α × Δ T)

here, α is the coefficient of linear expansion  

A = A (1 + β × Δ T)

here, β is the coefficient of aerial expansion

V = V (1 + γ × Δ T)

here, γ is the coefficient of cubical expansion  

V = V + γ × V × Δ T

V = V (1 + γ × ΔT)  

L3 = L3 (1 + α × Δ T)3

L3 = L3 (1 + 3α × ΔT + 3α2 × ΔT2 + α3 × ΔT3)

L3 = L3 (1 + 3α × Δ T)

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you wash four loads of dishes with a single type of detergent using cold water in the first load, warm water in the second load, hot water in the third load, and room temperature water that has been neither heated nor cooled, in the fourth load. You then test the effects of the experiment by comparing how clean the dishes were in each load. Identify the control, dependent variable, and independent variable in the experiment.
please help me!?​

Answers

Answer:

The water temperature is independent, and the cleanliness of the dishes is dependent.

Explanation:

You can change the independent variable in an experiment, in this case it's the water temperature. The dependent variable is the outcome from the independent variable, in this case being the cleanliness of the dishes. You can't control the cleanliness, but you can control the water temperature.

Hope my explanation isn't too confusing, hope this helps.

what do you know about healthy relationship true or false​

Answers

Answer:

this question doesn't make sense

Explanation:

as the afterload is increased, how did the latency change

Answers

Latency increases as afterload increases because it takes the muscle more time to generate enough muscle tension to overcome the added resistance of the increased afterload.

The muscle needs to develop a greater force to shorten and lift the added load, resulting in a delay or lag time before the contraction begins. This delay is the latency, which increases as the afterload increases. Once the muscle tension is great enough to overcome the afterload, the muscle can then contract and move the load. This phenomenon is due to the properties of the muscle fibers and the amount of energy required to generate muscle tension, which increases with greater afterload.

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Sketch a position-time graph for a bear starting
1.2 m from a reference point, walking slowly
away at constant velocity for 3.0 s, stopping for
5.0 s, backing up at half the speed for 2.0 s, and
finally stopping​

Answers

Explanation:

hopefully that makes sense. the position doesn't change over the 5 seconds, meaning it's stopped but time still continues. then when the slope is negative this shows the bear's position becoming negative (backing up, changing direction).

Sketch a position-time graph for a bear starting1.2 m from a reference point, walking slowlyaway at constant
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